What is the Mole fraction of Co2+ in a solution made up of 8 mL of 0.002 M solution of Co+ and 2 mL of 0.002 M solution of CN ?

Answer:

V₂ = 2509.62 cm³

Explanation:

Given data:

Initial volume = 1500 cm³

Initial temperature = -65°C (-65 + 273 = 208 K)

Final temperature = 75°C ( 75 +273 = 348 K)

Final volume = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 1500 cm³ × 348 K / 208 k

V₂ = 522000 cm³.K / 208 k

V₂ = 2509.62 cm³

The complete question is: Fill the blanks with appropriate coefficient number for the reaction equation- __AgNO3 + __Cu → __Ag + __Cu(NO3)2

Answer: The complete reaction equation is \(AgNO_{3} + Cu \rightarrow Ag + Cu(NO_{3})_{2}\)

Explanation:

A chemical equation which contains same number of atoms on both reactant and product side is called a balanced chemical equation.

For example, \(AgNO_{3} + Cu \rightarrow Ag + Cu(NO_{3})_{2}\)

Here, number of atoms present on reactant side is as follows.

Number of atoms present on product side is as follows.

To balance this equation, multiply \(AgNO_{3}\) by 2 on reactant side and multiply Ag by 2 on product side. Hence, the equation can be re-written as follows.

\(2AgNO_{3} + Cu \rightarrow 2Ag + Cu(NO_{3})_{2}\)

Now, the number of atoms present on reactant side are as follows.

Number of atoms present on product side are as follows.

Thus, we can conclude that the complete reaction equation is \(AgNO_{3} + Cu \rightarrow Ag + Cu(NO_{3})_{2}\).

Answer:

True

Explanation:

they are found on the crust

Answer:

crust

Explanation:

Answer:

D

Explanation: d

Answer:

547g

Hope i could help ;)

Answer:

plate drifting

Explanation:

Plate tectonics

Plate tectonics is the theory that Earth's land masses are in constant motion. The realization that Earth's land masses move was first proposed by Alfred Wegener, which he called continental drift.

Answer:

Plate drifting

Explanation:

Answer:0

Explanation: zero because it is the most stable form of oxygen in its standard state

Answer:

Consequently, what happens when gas obtained by heating slaked lime and ammonium chloride is passed through copper sulphate solution? The HCl in the gas mixture will form hydrochloric and the H+ will react with some of the NH3(aq), forming NH4^+, and with some of the SO4^2-, forming HSO4^-.

The gas obtained by heating Ammonium Chloride and slaked lime is passed through copper sulphate, deep blue solution will be formed.

The gas obtained by heating Ammonium Chloride and slaked lime is ammonia gas.

2NH₄Cl + Ca(OH)₂  ---> CaCl₂ + 2NH₃ + 2H₂O

Ammonia reacts with copper (II) ions to precipitate light blue copper hydroxide.

Ammonia causes the copper ion to go back into the solution as a deep blue ammonia complex.

However, in excess ammonia, the precipitate dissolves.

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Answer:

+27 66 514 3800

Explanation:

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Answer:

0.9401 mol H₂O

General Formulas and Concepts:

Chemistry - Atomic Structure

Explanation:

Step 1: Define

16.94 g H₂O

Step 2: Identify Conversions

Molar Mass of H - 1.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of H₂O - 2(1.01) + 16.00 = 18.02 g/mol

Step 3: Convert

\(16.94 \ g \ H_2O(\frac{1 \ mol \ H_2O}{18.02 \ g \ H_2O} )\) = 0.940067 mol H₂O

Step 4: Check

We are given 4 sig figs. Follow sig fig rules and round.

0.940067 mol H₂O ≈ 0.9401 mol H₂O

Answer:

D. 108g of water

Explanation:

16g CH4 produces 2(18)g of H20

1g CH4 produces \(\frac{36}{16}\)g of H2O

48g CH4 produces \(\frac{36}{16}\)×48

                                108g of H20

Answer:

D. 108g of water

Explanation:

The pH of the final solution is 3.09.

To solve this problem, we will use the Henderson-Hasselbalch equation, which relates the pH of a buffer solution to the pKa of the weak acid and the ratio of the concentrations of weak acid and its conjugate base;

pH = pKa + log([conjugate base]/[weak acid])

In this case, the weak acid is HF, and its conjugate base will be F⁻. The pKa of HF is given as 6.8 x 10⁻⁴. We are given the volumes and concentrations of the two solutions, so we can calculate the concentrations of HF and F⁻;

[HF] = 0.28 M x (38.9 ml / 78.7 ml) = 0.139 M

[F⁻] = 0.75 M x (39.8 ml / 78.7 ml) = 0.379 M

Now we can substitute these values into the Henderson-Hasselbalch equation;

pH = 6.8 x 10⁻⁴ + log(0.379/0.139)

= 3.09

Therefore, the pH of the final solution will be 3.09.

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The ion expected to have the largest crystal field splitting delta is [Os(CN)6]^3-.

Crystal field splitting (delta) refers to the energy difference between the d-orbitals in a transition metal complex due to the interaction between the metal ion and the surrounding ligands. The magnitude of delta depends on the nature of the ligands, with stronger field ligands causing larger splitting.
In this case, we have two types of ligands: H2O (aqua) and CN- (cyanide). CN- is a stronger field ligand compared to H2O, as it has a higher electron-donating ability. Consequently, complexes containing CN- will have a larger crystal field splitting. Among the given complexes, [Os(CN)6]^3- has the highest oxidation state and is surrounded by the strong field CN- ligands, leading to the largest crystal field splitting delta.

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Answer:

As you can see sodium = ionic and covalent bonds aka NA 2

and CO 3 also has those two bonds the other answers dont have both numbers (bonds) Na2 and CO3 is the only answer choice that has these bonds in simpler terms ( only answer with 2 numbers)

Explanation:

Answer:

Yes it is balanced.

Explanation:

See 1.ferrous or iron is 3 on both sides.

2. Oxygen is also 4 on both side

3. Same in hydrogen (8 on both sides).

Answer:

MgF₂

Explanation:

The correct answer is MgF₂, also known as magnesium fluoride.

This is because magnesium fluoride is an ionic compound, as there's a significant difference between the electronegativities of Mg and F.

Ionic compounds become good electricity conductors once they are dissolved in water.

The most common isotope of chromium contains 28 neutrons in addition to its 24 protons and 24 electrons. Chromium is a strong, shiny metal with a bluish hue under normal circumstances. Thus, option C is correct.

There are four naturally occurring isotopes of chromium, with relative abundances of 4.35%, 83.79%, 9.50%, and 2.36% for 50Cr, 52Cr, 53Cr, and 54Cr, respectively.

Numerous Chromium isotopes are employed in medical procedures. The radioisotope Cr-51, which is used to gauge blood volume and red blood cell survival, is created from Cr-50.

Studies on (adult) diabetes and chromium metabolism both use Cr-53 and Cr-54 as research tools.

Therefore, chromium isotope contain  24 protons and 28 neutrons.

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a) The concentration of the hydrogen ions is  1 * 10^-7 M

b) The concentration of the hydroxide ions is  1 * 10^-7 M

c) Ratio of the hydrogen to the hydroxide ion is 1:1

We know that the pH of the solution would have to do with ratio of the hydrogen ion and the hydroxide ions that we have in the solution. We know that the pH values that range from 0 -6 is acid, 7 is neutral and 8 - 14 is basic.

Then we have that;

Concentration of the hydrogen ion in the solution is obtain from the formula;

[H^+] = Antilog (-pH)

At pH 7 we have;

[H^+] = Antilog (-7)

= 1 * 10^-7 M

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Answer:

4 of each protons and electrons

Explanation:

since the atomic number is 4 it would contain both the same number of protons and electrons

Answer:

Explanation:

For the first row, only protons identify an element. For the second row, protons and neutrons affect mass. For the third row, protons and electrons affect charge.

Answer:

A few elements combine to make many compounds.

Explanation:

The heading of the reading is 'Few elements, many Compounds'. The reading has focused on the process involved in the formation of elements and compounds. In the Hawaiian Islands the elements are found in abundance. These elements combine together to form compounds. The mountains, greenery, rocks and living matter are made up of many elements and compounds. The elements present helps in forming various compounds.

Pollution refers the release of hazardous pollutants into the environment. These hazardous elements are referred to as contaminants. Pollutants may be naturally occurring, such as volcanic ash.

They may also be caused by human activities, such as factory runoff or waste. Pollutants have a negative impact on the quality of the air, water, as well as land.

Pollution refers the release of hazardous pollutants into the environment. These hazardous elements are referred to as contaminants. Pollutants may be naturally occurring, such as volcanic ash. They may also be caused by human activities, such as factory runoff or waste. Pollutants have a negative impact on the quality of both the air, water, as well as land.

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Answer:

\(\boxed{\small \sf \: Mass \: of \: H_2O =322.2 \: grams}\)

Explanation:

Given:

Mass of ferous (Fe) produced = 750 gram.

To find:

Mass of water produced= ?

Solution:

Molar mass of Fe is 55.84 gram/mol

Let's find out the number of moles of ferous produced.

\( \small \sf Number \: of \: moles = \frac{Given \: mass \: of \: substance }{Molar \: mass \: of \: substance} \)

Substituting the given data in above formula.

\( \small \sf Number \: of \: moles = \frac{750}{55.84} \)

\( \boxed{\small \sf Number \: of \: moles \: of \: Fe= 13.43 \: moles}\)

Now the given reaction is,

\(Fe_3O_4 + 4H_2 \rightarrow 3Fe + 4H_2O\)

now calculate the number of moles of H2O

\( \sf \: \frac{3}{4} = \frac{13.43}{x} \\ \sf x = \frac{13.43 \times 4}{3} \\ \sf x = 17.90 \: moles\)

\( \small \boxed{\sf number \: of \: moles \: of \: H_2O= 17.90 \: moles}\)

mass of one mole of H2O is 18 gram, so we can calculate mass of 17.90 moles.

\(\small \sf \: Mass \: of \: H_2O = 17.90 \times 18 \\ \boxed{\small \sf \: Mass \: of \: H_2O =322.2 \: grams}\)

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The standard free energy change and the equilibrium constant is  -1.75 x 10^5 J/mol and  6.67 x 10^31 respectively for the reaction.

We can calculate standard free-energy change ΔG° by using the following formula :

ΔG° = -nFE°

where ΔG° is the standard free energy change, n is the number of electrons transferred during the reaction, F is the Faraday constant which is (96,485 C/mol), and E° is the standard reduction potential.

Firstly we can split the equations in two halves to calculate the standard reduction potential of each equation  

Ag(s) → Ag+(aq) + e- E° = +0.80 V

O2(g) + 4 H+(aq) + 4 e- → 2 H2O(l) E° = +1.23 V

The net reaction is the sum of both the standard reduction potential of each equation  

4 Ag(s) + O2(g) + 4 H+(aq) → 4 Ag+(aq) + 2 H2O(l)

Applying the formula

ΔG° = -nFE°

ΔG° = -(4)(96,485 C/mol)(+0.80 V + 1.23 V)

ΔG° = -1.75 x 10^5 J/mol

Therefore the standard free-energy change ΔG° =  -1.75 x 10^5 J/mol

To calculate the equilibrium constant, K,  we can use the value from the standard free energy change using the following equation:

ΔG° = -RT ln K

in which R is the gas constant (8.314 J/mol·K), T is the temperature in Kelvin (298 K), and ln is the natural logarithm and the value of ΔG° from above

Applying the formula we get:

-1.75 x 10^5 J/mol = -(8.314 J/mol·K)(298 K) ln K

ln K = 72.99

K = e^72.99

K = 6.67 x 10^31

Therefore, the equilibrium constant for the reaction at 298 K is K = 6.67 x 10^31.

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The balanced chemical equation for the combustion reaction of the gaseous hydrocarbon fuel (CxH2x+2) with air can be written as CxH2x+2 + (2x + 1)O2 + 3.76N2 -> xCO2 + (x + 1)H2O + 3.76(2x + 1)N2. The fuel is determined to be methane (CH4).

The balanced chemical equation for the combustion reaction of the gaseous hydrocarbon fuel (CxH2x+2) with air can be written as:

CxH2x+2 + (2x + 1)O2 + 3.76N2 -> xCO2 + (x + 1)H2O + 3.76(2x + 1)N2.

Given the volumetric analysis of the products of combustion, we can determine the value of x in the hydrocarbon fuel. The percentage of carbon dioxide (CO2) corresponds to the carbon atoms in the fuel, so 9.45% CO2 implies x = 1. The fuel is therefore methane (CH4).

To calculate the air-fuel ratio, we compare the moles of air to the moles of fuel in the balanced equation. From the equation, we have (2x + 1) moles of oxygen (O2) and 3.76(2x + 1) moles of nitrogen (N2) for every 1 mole of fuel. Substituting x = 1, we find that the air-fuel ratio is 17.2 kg of air per kg of fuel.

To determine the heat transfer rate and combustion efficiency on a lower heating value (LHV) basis, we need to calculate the molar enthalpies of the reactants and products. Using standard molar enthalpies of formation, we can calculate the change in molar enthalpy for the combustion reaction. The heat transfer rate can be obtained by multiplying the change in molar enthalpy by the mass flow rate of the fuel. The combustion efficiency on an LHV basis can be calculated by dividing the actual heat transfer rate by the ideal heat transfer rate.

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Answer:

The letters, s, p, d, and f designate the shape of the orbital. (The shape is a consequence of the magnitude of the electron's angular momentum, resulting from its angular motion.) An s orbital is spherical with its centre at the nucleus.

There will be no effect of adding a small amount of strong acid to a buffer solution.

The conjugate base in the buffer eats the hydronium ion, turning it into water and the weak acid of the conjugate base when a strong acid (H3O+) is added to the buffer solution. This causes the amount of weak acid to increase and the amount of conjugate base to decrease.

A buffer solution is an aqueous mixture of a weak acid and either its conjugate base or base itself. When a modest amount of a strong acid or base is applied to it, the pH hardly changes at all.

A buffer is a substance that can withstand a pH change when acidic or basic substances are added.

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