What is the momentum of a 5-kg bowling ball when at rest?

Answer:

C. A quantity with magnitude and a direction.

Explanation:

A vector can be defined as a quantity with magnitude and direction. Some examples of vector quantities are velocity, position, displacement, force, torque, acceleration.

For example, given the following data;

Time, t = 18.5secs

Final velocity = 78m/s

Initial velocity = 0

Substituting into the equation;

\(a = \frac{78 - 0}{18.5}\)

\(a = \frac{78}{18.5}\)

Acceleration, a = 4.22m/s²

Therefore, the acceleration of the object is 4.22m/s² due North.

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.

Mathematically, acceleration is given by the equation;

\(Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}\)

\(a = \frac{v - u}{t}\)

Where,

a is acceleration measured in \(ms^{-2}\)

v and u is final and initial velocity respectively, measured in \(ms^{-1}\)

t is time measured in seconds.

Answer:

C. A quantity with magnitude and a direction.

Explanation:

A physical Quantity, which has magnitude, direction and units But must follow the traingle law of vector addition

Answer:

Gas has the fastest moving particles. Liquid has the second fastest. Solid's particles cannot move.

Explanation:

Gas's molecules are spread apart and have space to move. Liquids have loosely held molecules. Solid's molecules don't move because they are tighly packed.

Answer:

67%

Explanation:

In the absence of external forces, the total momentum of the system before the collision is equal to the total momentum after the collision. Since the second ball is initially at rest, the total momentum before the collision is simply m*v.

After the collision, the two balls stick together and move with a common velocity, which can be calculated using conservation of momentum:

m*v + 0 = (m+2m) * v_final

Solving for v_final, we get:

v_final = v/3

The initial kinetic energy of the system is:

K_i = 0.5mv^2

The final kinetic energy of the system is:

K_f = 0.5*(3m)v_final^2 = 0.5(3m)(v^2/9) = 0.5m*v^2/3

The fraction of the initial kinetic energy lost on impact is:

( K_i - K_f ) / K_i = ( 1 - 1/3 ) = 2/3 = 0.67

Therefore, 67% of the initial kinetic energy is lost on impact.

The coordinates of the boat are (40,577 m, 15,752 m).

Let's calculate the (x, y) coordinates of the boat using the given information and the formulas mentioned earlier.

Given:

Speed of radio signal (v): 285400 m/ms

Distance between master station and secondary station (d): 40.50 km = 40,500 m

Measured time difference (t): 125 μs = 125 * 10^(-6) s

Distance from the vertex of the parabola (d1): 15.752 km = 15,752 m

First, let's find the time taken by the radio signal to travel from the master station to the secondary station:

t_total = d / v

t_total = 40,500 m / 285400 m/ms

t_total ≈ 0.1421 s

Next, we find the time taken by the radio signal to travel from the master station to the boat:

t_diff = t_total - t

t_diff = 0.1421 s - (125 * 10^(-6) s)

t_diff ≈ 0.142 s

Now, we can find the distance traveled by the radio signal from the master station to the boat:

d2 = t_diff * v

d2 = 0.142 s * 285400 m/ms

d2 ≈ 40,577 m

The (x, y) coordinates of the boat are (d2, d1), where d1 is the distance from the vertex of the parabola:

(x, y) = (40,577 m, 15,752 m)

Therefore, the coordinates of the boat are approximately (40,577 m, 15,752 m).

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From the calculation, the mass of the dummies head is 1647.44 Kg

We know that the momentum after collision is equal to the momentum before collision.

Mass of the headrest = 2005.6 kg

Initial velocity of the head rest = 4.524 m/s

Final velocity of the head rest =  4.487 m/s

Mass of the dummy = m

Initial velocity of the dummy = -1.005 m/s

Final velocity of the dummy = 9.965 m/s

Then;

(m *  -1.005) + (2005.6 * 4.524 ) = (2005.6 *   4.487) + (m * 9.965)

-1.005m + 9073.33 = 8999.13 + 9.965m

9073.33 - 8999.13  = 9.965m + 1.005m

18072.46 = 10.97m

m = 18072.46/ 10.97

m = 1647.44 Kg

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The correct answer for the given question for the distance that the piston on the right will move is 0.1 m option (A).

When an explosion occurs in the left piston, it exerts a force on the fluid, which in turn exerts an equal and opposite force on the right piston due to the enclosed volume.

The cross-sectional area of the left piston is 0.25 m², and assuming the force is uniformly distributed over the entire area, the force exerted by the left piston is given by F = P × A, where P is the pressure and A is the area.

Using the work-energy principle, the work done by the left piston is equal to the work done on the right piston. Therefore, the work done on the right piston is equal to the force exerted on it multiplied by the distance it moves.

The force exerted on the right piston can be calculated using the same formula as before (F = P × A), where the cross-sectional area A is 0.5 m².

Since the force exerted on the right piston is equal to the force exerted by the left piston, we can equate the two expressions for force and solve for the distance moved by the right piston.

Using the equation F_left = F_right, we have P_left × A_left = P_right × A_right.

Plugging in the given values, we get (P_left × 0.25) = (P_right × 0.5).

Since the pressure is the same throughout the fluid, P_left = P_right.

Simplifying the equation, we have 0.25 = (0.5 × A_right).

Solving for A_right, we get A_right = 0.25 / 0.5 = 0.5 m².

The distance moved by the right piston can be calculated using the work formula:

Work_right = Force_right × Distance_right.

Plugging in the values, we have (P_right × A_right) × Distance_right = (P_left × A_left) × Distance_left.

Since P_left = P_right, we can further simplify the equation:

A_right × Distance_right = A_left × Distance_left.

Plugging in the given values, we get (0.5 × Distance_right) = (0.25 × 0.2).

Solving for Distance_right, we have Distance_right = (0.25 × 0.2) / 0.5 = 0.1 m.

Hence, the correct answer is option A: 0.1 m.

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Answer:

Here

Explanation:

If an object has momentum, then it must also have mechanical energy. If an object does not have momentum, then it definitely does not have mechanical energy either. Object A has more momentum than object B. Therefore, object A will also have more kinetic energy.

Answer:

He can take the job at the fast food restaurant to make money in order to pursue his career in robotics it doesn't mean he can't pursue it just he needs to make money for it first.

Explanation:

Hope this helps!

Answer:

In their formation

Explanation:

igneous formed by cooling of magma

metamorphic formed from extreme temperatures and pressures

sedimentary formed from erosion and sedimentation

Answer:

An incandescent bulb use electrical energy

Explanation:

Answer:

a) Time = 2.67 s

b) Height = 35.0 m

Explanation:

a) The time of flight can be found using the following equation:

\( x_{f} = x_{0} + v_{0_{x}}t + \frac{1}{2}at^{2} \)   (1)

Where:

\( x_{f}\): is the final position in the horizontal direction = 80 m

\( x_{0}\): is the initial position in the horizontal direction = 0

\(v_{0_{x}}\): is the initial velocity in the horizontal direction = 30 m/s

a: is the acceleration in the horizontal direction = 0 (the stone is only accelerated by gravity)

t: is the time =?  

By entering the above values into equation (1) and solving for "t", we can find the time of flight of the stone:  

\( t = \frac{x_{f}}{v_{0}} = \frac{80 m}{30 m/s} = 2.67 s \)

b) The height of the hill is given by:

\( y_{f} = y_{0} + v_{0_{y}}t - \frac{1}{2}gt^{2} \)

Where:

\( y_{f}\): is the final position in the vertical direction = 0

\( y_{0}\): is the initial position in the vertical direction =?

\(v_{0_{y}}\): is the initial velocity in the vertical direction =0 (the stone is thrown horizontally)            

g: is the acceleration due to gravity = 9.81 m/s²

Hence, the height of the hill is:

\( y_{0} = \frac{1}{2}gt^{2} = \frac{1}{2}9.81 m/s^{2}*(2.67 s)^{2} = 35.0 m \)  

I hope it helps you!

Answer:

Electric potential energy

Explanation:

The Electric potential energy of a system is less than that carried out by electrostatic forces during the development of the system (as long as charges are initially cut infinitely).

The change in potential energy between an initial and final configuration  is equal to minus the work done by the electrostatic forces.

Differential stress forces constituents of the rock to become parallel to one another. B. Differential stress

Differential stress occurs when forces act on a rock in different directions and with different intensities. This type of stress causes the constituents of the rock to become parallel to one another, resulting in a preferred orientation of minerals known as foliation. Pressure, on the other hand, is a type of stress that acts equally in all directions and does not cause foliation. Strain refers to the deformation that occurs as a result of stress, and heat from a nearby pluton can cause metamorphism, but it does not necessarily cause the constituents of the rock to become parallel. Finally, starch is not related to this topic. In summary, differential stress is the key factor that leads to the development of foliation in rocks.
B. Differential stress

Differential stress is a type of force that causes constituents of a rock to become parallel to one another. This stress is typically a result of tectonic forces acting in different directions and magnitudes, causing deformation and realignment of mineral grains within the rock. This process can ultimately lead to changes in the rock's structure, orientation, and even its mineral composition. Differential stress is an essential factor in the formation of metamorphic rocks, as it influences the development of foliation or layering, which is characteristic of many metamorphic rocks. In summary, differential stress plays a crucial role in the deformation of rocks and the development of foliation in metamorphic rocks by causing the constituents of the rock to become parallel to one another.

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Answer:

Mechanical energy

Explanation:

Mechanical energy is needed for movement of objects. Muscles convert chemical energy provided by the rest of the body to allow movement.

Answer:

SI

Explanation:

Answer:

Given that

speed u=4*10^6 m/s

electric field E=4*10^3 N/c

distance b/w the plates d=2 cm

basing on the concept of the electrostatices

now we find the acceleration b/w the plates  to find the horizontal distance traveled by the electron when it hits the plate.

acceleration a=qE/m=\(1.6*10^{-19}*4*10^3/9.1*10^{-31} =0.7*10^{15}\)=\(7*10^{14}\) m/s

now we find the horizontal distance traveled by electrons hit the plates

horizontal distance

\(X=u[2y/a]^{1/2}\)

=\(4*10^6[2*2*10^{-2}/7*10^{14}]^{1/2}\)

=\(3*10^{-2}\)= 3 cm

At constant velocity, the crate would be in equilibrium, so that Newton's second law tells us

p + (-f ) = 0

where p and f denote the magnitudes of the added pushing force and friction force, respectively.

The friction force is proportional to the normal force by a factor of µ, the coefficient of friction. There's no vertical movement going on, so Newton's second law says

n + (-w) = 0

where n and w are the magnitude of the normal force and the weight of the crate, respectively.

Compute n :

n = w = (25 kg) (9.80 m/s²) = 245 N

Use this and µ = 0.45 to compute f :

f = µ n = 0.45 (245 N) = 110.25 N

Solve for p :

p + (-110.25 N) = 0

p = 110.25 N ≈ 110 N

The force i.e required to move the crate at a constant velocity across the floor is 110 N.

At the same velocity, the crate should be in equilibrium, so as per Newton's second law, the following formula should be used:

p + (-f ) = 0

p means the magnitudes of the added pushing force

f means the friction force

n = w = (25 kg) (9.80 m/s²) = 245 N

Now

force should be

= µ n

= 0.45 (245 N)

= 110.25 N

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Answer:b

Explanation:

A steel ball, a magnet, and a piece of paper are used in an activity by a pupil. The ball is under the influence of the magnet. Therefore, choice A is right.

When electric charges move, a phenomenon known as magnetism is produced. These tiny movements can occasionally be found inside a material known as magnets. Magnets and the magnetic fields created by moving electric charges can attract or repel other magnets, which can also change how other charged particles move.

Because they can support a magnetic field that lasts forever, some materials, like iron, are categorized as permanent magnets. These are the magnets that are typically encountered in day-to-day life. Other materials like iron, cobalt, and nickel can be briefly given a magnetic field when placed inside a stronger, bigger magnetic field, but they will eventually lose their magnetic qualities.

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Answer:

Explanation:

Centripetal acceleration's equation is:

\(a_c=\frac{v^2}{r}\) where v is the velocity of the object (moon II) and r is the radius. We have the radius, but we don't have the velocity, and we can't solve for acceleration until we do have it. Assuming moon II is a circle, or close enough to be called a circle, it has a circumference.

C = 2πr. If we can find the circumference of the circle, we can plug in the orbital period for the time, the circumference for the distance, and solve for velocity in d = rt. So let's do that and see what happens.

C = 2(3.14)(9.0 × 10⁷) and

C = d = 5.7 × 10⁸. Plugging in and solving for v:

\(5.7*10^8=v(3.0*10^5)\) and

v = 1.9 × 10³. That is the velocity we can use in the centripetal acceleration equation.

\(a_c=\frac{(1.9*10^3)^2}{9.0*10^7}\) and

\(a_c=.040\frac{m}{s^2}\)

These are fun!

Answer:

It is C the units and D

Explanation:

18.)C

19.)D

An external force exceeding the maximum static friction between the object and the surface is the likely reason for the object to start moving. This force could be from various sources.

The most likely reason the object begins to move is that a force is acting on it, overcoming the static friction between the object and the surface.

Static friction is the force that keeps the object at rest, but once the force acting on the object exceeds the maximum static friction, the object starts to move.

The force could come from various sources, such as an external push or pull, the force of gravity if the surface is inclined, or the force of air resistance if the object is moving through the air.

The coefficient of static friction between the object and the surface is also an important factor in determining the maximum static friction that can be exerted before the object starts to move.

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Answer:

A

Explanation:

Answer:

Distance divided by time

Explanation:

The function Ø(z) is Ø(z) = y + j(2x² + 2xy - y²), where x = 2x² + 2xy - y²

= x (x + y)² - 2xy

= (x + y)² - y² + x(x - y)

= 2x² + 2xy - y²

We are given that Ø (z) = y +jx represents

An the complex potential for electric field and

 x = 1 + (x /(x + y)² - 2xy)+ (x+y)(x-y).

To determine the function Ø(z), we need to find the value of x using the given expression.

Then, we can substitute the value of x in the given expression of Ø (z).

Let's simplify the expression of x: x = 1 + (x /(x + y)² - 2xy)+ (x+y)(x-y)x (x + y)² - 2xy x + y²

= (x + y)² - y² + (x+y)(x-y)x² + 2xy² + y²

= x² + 2xy + y² - y² + x² - y² + xy - xyx² + 3xy² - y²

= 2x² + 2xy - y²

Now, we can substitute the value of x in the given expression of Ø (z)Ø(z)

= y + jx

= y + j(2x² + 2xy - y²)

Therefore, the function Ø(z) is Ø(z) = y + j(2x² + 2xy - y²),

where x = 2x² + 2xy - y²

= x (x + y)² - 2xy

= (x + y)² - y² + x(x - y)

= 2x² + 2xy - y²

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The general manager target bonus plan includes financial incentives based on achieving specific performance goals.

The general manager target bonus plan is a type of incentive program that rewards managers for achieving specific performance goals. The plan typically includes financial incentives, such as bonuses or profit sharing, that are tied to the achievement of predetermined goals, such as revenue growth, cost reduction, or customer satisfaction.

The plan may also include other performance metrics, such as employee engagement or operational efficiency. By linking financial incentives to specific performance goals, the plan encourages managers to focus their efforts on areas that are critical to the success of the organization and helps align their interests with those of the company. Overall, the general manager target bonus plan is a key tool for motivating and rewarding managers and driving performance improvement within an organization.

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Answer:

potential energy is transformed into kinetic energy

Answer:

2n answer of 6

place it at the place of ?mark