what is the necessary condition on the path length difference between two waves that interfere as follows

Answers

Answer 1

The necessary condition on the path length difference between two waves that interfere is that the path length difference must be an integer multiple of the wavelength.

This condition leads to constructive interference, where the two waves add up and result in an increased amplitude.

Step-by-step explanation:

Consider two waves with the same frequency and wavelength traveling towards each other.The path length difference between the two waves is the difference in the distance each wave travels before they meet.If the path length difference is an integer multiple of the wavelength (e.g. 0, λ, 2λ, 3λ...), the waves will meet at points where their phases match, causing constructive interference.On the other hand, if the path length difference is an odd-integer multiple of half the wavelength (e.g. λ/2, 3λ/2, 5λ/2...), the waves will meet at points where their phases are opposite, causing destructive interference.In summary, the necessary condition on the path length difference between two waves that interfere is that it must be an integer multiple of the wavelength for constructive interference to occur.

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Related Questions

what is the power of a student that has done a work of 10 joules in 10 seconds​

Answers

Answer:

1 Watt

Explanation:

P=W/t

P=10/10

P=1 Watt

A semi truck has a velocity of 28m/s when it comes to a stop over 342m. What is the acceleration of the truck?​

Answers

Acceleration=
Velocity Final - Velocity Initial
————————————————-
Distance

Vf =0m/s because truck came to complete stop
Vi=28m/s
D=342m

0-28
——— =28.1m/s^2
342

A giant log float on a lake while a tiny grain of sand sinks to the bathroom. Explain why a heavy object like the log floats while a very light grain of sand sinks?

Answers

Answer:

Because the log is hollow or is less dense

Explanation:

If a log has little density, it will float. While sand is dense and completely solid, so it will sink.

You and a friend each drive 50.0 km. You travel at 90.0 km/h; your friend travels at 95.0 km/h. How long will your friend have to wait for you at the end of the trip?

Answers

Answer:

1.08 hours

Explanation:

Distance = speed × time

Time = distance / speed

The time you spend driving is:

t = 50.0 km / (90.0 km/hr)

t = 0.555 hr

The time your friend spends driving is:

t = 50.0 km / (95.0 km/hr)

t = 0.526 hr

The total time is 0.555 hr + 0.526 hr = 1.08 hr.

An astronaut's pack weighs 13.0 N when she is on earth but only 5.10 N when she is at the surface of moon.
Part A
What is the acceleration due to gravity on this moon?
Express your answer with the appropriate units.
Part B
What is the mass of the pack on this moon?
Express your answer with the appropriate units.

Answers

(A) The acceleration due to gravity on this moon is 3.84 m/s².

(B) The mass of the pack on this moon is 1.33 kg.

Part A:
The acceleration due to gravity on the moon can be calculated using the equation:
F = ma
Where F is the force, m is the mass, and a is the acceleration. Rearranging the equation to solve for a gives:
a = F/m

We know that the force on the moon is 5.10 N and the force on earth is 13.0 N. The mass of the pack is the same on both the moon and earth, so we can use the ratio of the forces to calculate the acceleration on the moon:
a = (5.10 N)/(13.0 N)(9.8 m/s²) = 3.84 m/s²


Part B:
The mass of the pack on the moon can be calculated using the equation:
F = ma
Where F is the force, m is the mass, and a is the acceleration. Rearranging the equation to solve for m gives:
m = F/a

We know that the force on the moon is 5.10 N and the acceleration on the moon is 3.84 m/s², so we can plug these values into the equation to find the mass:
m = (5.10 N)/(3.84 m/s²) = 1.33 kg

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a rope holds a baloon, if vertical lift is 1200 n and the tension in rope is 1300 what is the horizontal force of the wind on the balloon??

Answers

Around 500 N is the size of the wind's horizontal force on the balloon.

How can we use the second law of motion to calculate the net force operating on an object?

According to Newton's second rule of motion, an object's acceleration is a function of both its mass and the net force acting on it. The formula Fnet F n e t =ma serves as the representation for this law.

cos(θ) = horizontal component of tension / tension in rope

cos(θ) = F_h / 1300

F_h = 1300 cos(θ)

sin(θ) = vertical component of tension / tension in rope

sin(θ) = 1200 / 1300

sin(θ) ≈ 0.923

cos(θ) ≈ 0.385

Plugging this into our equation for F_h, we get:

F_h = 1300 cos(θ) ≈ 500 N

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MY BRAINS NOT WORKING

Describe how Newton's Third Law applies to the forces between the bike and
the trailer.

MY BRAINS NOT WORKING Describe how Newton's Third Law applies to the forces between the bike andthe trailer.

Answers

Answer:

Explanation:

The Earth pulls the bicycle downward through the force of gravity, and, in response, the bicycle pulls up on the Earth with a force of equal magnitude. Gravity "pushes" the Earth into the road, which pushes up with an opposite force, canceling gravity. Thus, action reaction forces do not cancel each other.

PLEASE HELP ILL GIVE CROWN!!!!

What region receives the least amount of direct sunlight?

A ) High latitudes (Polar Region)
B ) Middle latitudes ( Temperate Region )
C ) Low latitudes ( Tropical Region )
D ) Low and Middle latitudes

Answers

Answer:

A)

Explanation:

The lowest latitudes get the most energy from the sun. The highest latitudes get the least.

Answer: A

Explanation:

State one use and one disadvantage of the expansion of materials when they are heated.
use
disadvantage

Answers

An example of the use of expansion of materials when they are heated is in

Thermometers. Thermometer is an instrument which is used to measure the

temperature of a place.

It contains mercury which expands as temperature increases. This is used

to accurately determine the temperature of an object.

The disadvantage of expansion of materials when they are heated can be

seen in roads as there is expansion of the surface as a result of heat

exposure leads to roads being rough thereby incurring more costs for

repairs.

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why was Idi Amin labeled as one of the Africa's cruelest dictators

Answers

Answer: He was labeled as one of Africa's cruelest dictators because during his eight year reign many civilians were massacred. He drove out Uganda's Indian and Pakistani citizens and spent large amount of money on the military which led to the economic decline of the country.

Explanation:

FILL THE BLANK.
Among primate group members, energy requirements are highest for ______.

Answers

Among primate group members, energy requirements are highest for reproductive females.

Reproductive females in primate groups generally have the highest energy requirements compared to other group members. This increased energy demand is primarily due to the energetic costs associated with reproduction and maternal care.

During pregnancy, female primates undergo physiological and metabolic changes to support the growth and development of the fetus. This includes increased nutrient intake to provide the necessary energy and resources for fetal development. As a result, pregnant females often require higher caloric intake and specific nutrients to meet the demands of both their own metabolic needs and those of the developing offspring.

After giving birth, lactation further contributes to the high energy requirements of reproductive females. Producing and providing milk to nourish the newborn requires a substantial amount of energy and nutrients. Lactating females need to maintain a consistent supply of energy-rich foods to sustain their own health and produce an adequate milk supply for their offspring.

Hence, Among primate group members, energy requirements are highest for reproductive females.

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physics as a subject involves measurement and estimation,giving examples of everyday life situations, explain the meaning and what is done in each case​

Answers

Answer:

57

Explanation:

Who may perform a post-exposure medical evaluation?

A) A licensed physician


B) An LPN


C) A physician's assistant


D) Your employer

Answers

Answer:a licensed physician

Explanation: taking the osha test now.

A licensed physician is the one to carry out a post-exposure medical evaluation. (Option A)

Post-Exposure Medical Evaluation

Post-exposure Medical Evaluation is any medical evaluation started after exposure to a pathogen in order to prevent the infection from occurring.

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MICROSCOPIC STRUCTURE: a Dental Plaster: They are Fibrous aggregar of fine cupotal with capitany pares. then guerre Kuyrak Cleavage fragments and b) Dental Stone and prio crystals in the form of mods c) Die Stone Cuboidal Shape Investment DIAGRAMS OF CRYSTALS: Dental Plaster Dental Stone Investment Die Stone 19 DEMONSTRATION: 1. MIC AIM: To study the manipulation of dental plaster and pouring a compound impression GAUGING WATER: W/P = 50ml/100 gms. a PROCEDURE b 1. AIM: To study the manipulation of dental stone and pouring an alginate impression GAUGING WATER: W/P = 30ml/100gms. PROCEDURE 1. AIM: To study the manipulation of die stone and pouring and elastomeric impression GAUGING WATER: W/P = 25ml/100 gms. PROCEDURE

Answers

The provided text contains information about the microscopic structures and crystal diagrams of dental plaster, dental stone, and die stone. It also mentions the gauging water ratios and procedures for manipulating and pouring compound impressions using these materials.

The text describes the microscopic structure of dental plaster, which consists of fibrous aggregates of fine cupotal with capitany pares. Dental stone is described as having prior crystals in the form of mods, while die stone is characterized by its cuboidal shape.

The crystal diagrams are mentioned for each material: Dental plaster, dental stone, and die stone.

The text then outlines three different demonstrations, each with a specific aim and gauging water ratio. The demonstrations involve studying the manipulation of dental plaster, dental stone, and die stone, as well as pouring compound impressions using these materials. The procedures for each demonstration are provided.

To learn more about the manipulation of dental plaster, dental stone, and die stone, as well as the pouring of compound impressions, further information can be explored in dental textbooks or dental laboratory manuals.

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A)What is the heavy vehicle factor (fhv) for a roadway with 10 percent truck, 5 percent buses, and 5 percent RVs in mountainous terrain? B) A roadway has 80 percent passenger cars, 15 percent trucks and 5 percent RVs. What is the passenger car equivalent for this traffic stream if the terrain is level? C An intersection approach has two lane groups (eg LT and RT/Thru). The average delay for LT lane group is 10sec/veh and the average delay for the other lane group is 20 sec. What is the total approach delay given volumes of 150 lefts, 500 thru, and 100 rights? D) What is grade resistance for a 2000lb vehicle on an 8 percent upgrade? E) What is force required to maintain a constant speed if the aerodynamic, rolling, and grade resistances =90,30, and 125lbs, respectively?

Answers

The heavy vehicle factor (Fhv) for a roadway with 10% trucks, 5% buses, and 5% RVs in mountainous terrain is 20%. The passenger car equivalent (PCE) for a traffic stream with 80% passenger cars, 15% trucks, and 5% RVs on level terrain is 1.5. The total approach delay for an intersection with volumes of 150 lefts, 500 thru, and 100 rights, with average delays of 10 sec/veh and 20 sec/veh, is 13,500 seconds.

The grade resistance for a 2000 lb vehicle on an 8% upgrade is 160 lbs. The force required to maintain a constant speed considering aerodynamic, rolling, and grade resistances of 90 lbs, 30 lbs, and 125 lbs, respectively, is 245 lbs.

A) The heavy vehicle factor (Fhv) is the sum of the percentages of trucks, buses, and RVs in the traffic stream. For the given roadway with 10% trucks, 5% buses, and 5% RVs, the Fhv would be 10% + 5% + 5% = 20%.

B) To calculate the passenger car equivalent (PCE) for a traffic stream with 80% passenger cars, 15% trucks, and 5% RVs on level terrain, the PCE values are typically assigned as 1 for passenger cars, 2 for trucks, and 4 for RVs. Therefore, the PCE can be calculated as (80% x 1) + (15% x 2) + (5% x 4) = 1 + 0.3 + 0.2 = 1.5.

C) The total approach delay for the intersection can be calculated by multiplying the volumes of each lane group by their respective average delays and summing them up. In this case, the total approach delay would be (150 lefts x 10 sec/veh) + (500 thru x 20 sec/veh) + (100 rights x 20 sec/veh) = 1500 + 10000 + 2000 = 13500 seconds.

D) The grade resistance for a vehicle on an 8% upgrade can be calculated by multiplying the weight of the vehicle by the grade percentage. Assuming the weight of the vehicle is 2000 lbs, the grade resistance would be 2000 lbs x 0.08 (8% as a decimal) = 160 lbs.

E) The force required to maintain a constant speed is equal to the sum of aerodynamic resistance, rolling resistance, and grade resistance. Given that the aerodynamic resistance is 90 lbs, rolling resistance is 30 lbs, and grade resistance is 125 lbs, the total force required would be 90 lbs + 30 lbs + 125 lbs = 245 lbs.

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Will an object experience a greater force of gravity on the earth or moon? Why?

Answers

Answer:

Earth’s gravitational force is stronger

Explanation:

Earth’s gravitational force is stronger than the moon because of the presence of more massive objects in earth; on the flip side, the moon’s gravity is weaker than the earth due to smaller in size as compared to the earth. Earth gravity is denoted by g; conversely, moon gravity is denoted by gm

Answer: The greater an object's mass, the more gravitational force it exerts. So, to begin answering your question, Earth has a greater gravitational pull than the moon simply because the Earth is more massive. That's why the moon isn't pulled out of Earth's orbit by the gravity of larger planets or by the sun.

Explanation:

To increase an impulse:
A. increase the change in momentum.
B. decrease the change in velocity.
C. increase the distance.
D. decrease the mass.

Answers

I believe the answer is A.

Specifying a clear objective for an advertising campaign help in selecting ________ and ________ the campaign. Multiple choice question. agency; evaluating media; launching agency; launching media; evaluating

Answers

Specifying a clear objective for an advertising campaign helps in selecting an agency and launching the campaign.

When planning an advertising campaign, it is important to have a clear objective that defines the desired outcome or goal of the campaign. This objective serves as a guide for decision-making throughout the process.

Selecting an agency involves choosing a professional advertising agency or creative team that will be responsible for developing and executing the campaign. The agency should have the expertise and capabilities to align with the campaign's objectives and effectively communicate the desired message to the target audience.

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A 2. 0-kg object is thrown towards a wall with a speed of 8. 0 m/s. The ball hits the wall. And rebounds backwards with a speed of 6. 0 m/s. What is the magnitude of the impulse experienced by the hall?

Answers

Answer:

\(28\; {\rm kg \cdot m\cdot s^{-1}}\).

Explanation:

The impulse on an object is equal to the change in momentum.

By the conservation of momentum, the total momentum of this system will stay unchanged. In other words, the sum of the change in the momentum of the wall and the projectile will be \(0\):

\(\Delta p(\text{projectile}) + \Delta p(\text{wall}) = 0\).

Rearrange to obtain:

\(\Delta p(\text{wall}) = -\Delta p(\text{projectile})\).

The change in the momentum of the projectile is:

\(\begin{aligned} & \Delta p(\text{projectile}) \\ &= m(\text{projectile}) \, \Delta v(\text{projectile}) \\ &= (2.0\; {\rm kg})\, ((8.0 - (-6.0))\; {\rm m\cdot s^{-1}}) \\ &= 28\; {\rm kg\cdot m\cdot s^{-1}} \end{aligned}\).

The change in the momentum of the wall would then be:

\(\Delta p(\text{wall}) = -\Delta p(\text{projectile}) = -28\; {\rm kg\cdot m\cdot s^{-1}}\).

Thus, the magnitude of the impulse on the wall would be \(28\; {\rm kg\cdot m\cdot s^{-1}}\).

what will you use to find the mg of starch for the first time course, ph, and temperature experiments? [4 pts]

Answers

To find the mg of starch for the first time course, ph, and temperature experiments, you will use the iodine-starch complex formation reaction

The iodine-starch complex formation reaction is a quantitative measure of the starch concentration in the sample. The blue-black color produced is proportional to the starch concentration in the sample. If the concentration of the sample is high, the reaction will be intense, and the color will be dark blue-black. The reaction will be less pronounced if the concentration of the sample is low, and the color will be pale blue-black. When performing a starch assay, this color intensity is compared to that of a standard starch solution of known concentration to determine the concentration of starch in the sample.

The following steps must be followed to perform this analysis, 1. Dissolve the 1 mg of starch sample in 1 mL of distilled water, and adjust the pH to 7.0.2. Add 1 mL of the iodine solution (0.002 M iodine and 0.04 M KI), followed by the addition of 5 mL of 1 N hydrochloric acid. 3. Dilute the solution to 25 mL with distilled water, and mix well. 4. Measure the absorbance of the solution at 620 nm against a distilled water blank. The starch concentration in the sample can be calculated by comparing the absorbance of the sample with that of a standard solution of known concentration.

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Marking brailiest: Two Speed and velocity questions below

A car travels a distance of 100 km in 2 hours. What is the average speed of the car (km/h)?

An NFL wide receiver prospect runs 40 m in 4.5 seconds. What is the average speed of the wide receiver (m/s)?

Answers

Answer:

1) 50 km/h

2)80/9 m/s

Explanation:

Speed = Distance / time

You observe someone pulling a block of mass 39 kg across a low-friction surface. While they pull a distance of 5 m in the direction of motion, the speed of the block changes from 4 m/s to 5 m/s.

Calculate the magnitude of the force exerted by the person on the block.

Answers

The magnitude of the force exerted by the person on the block is 119.7 N.

There is a change in velocity of the block while it is being pulled by the person. Therefore, the block has an acceleration and the person pulling it must be exerting a force.

The magnitude of the force can be calculated using the following formula: F = ma, where F is the force, m is the mass of the block, and a is the acceleration of the block.

Let’s use the given data to calculate the acceleration of the block. The initial velocity of the block is u = 4 m/s, the final velocity is v = 5 m/s, and the displacement is s = 5 m. We can use the following formula to find the acceleration: a = (v - u) / t, where t is the time taken for the block to travel the distance of 5 m. t = s / u = 5 / 4 = 1.25 s.

a = (5 - 4) / 1.25 = 0.8 m/s²

Now, we can calculate the force exerted by the person: F = ma. F = 39 kg x 0.8 m/s² = 31.2 N.

However, this is the force exerted by the person when the block was accelerating. We need to find the force when the block was at a constant speed of 5 m/s. Since the block is moving at a constant speed, the net force acting on it is zero.

Therefore, the force exerted by the person must be equal in magnitude and opposite in direction to the force of friction acting on the block.

Ff = µN, where µ is the coefficient of friction and N is the normal force acting on the block. Since the block is being pulled horizontally, the normal force acting on it is equal to its weight.

N = mg. N = 39 kg x 9.8 m/s² = 382.2 N. Let’s assume that the coefficient of friction between the block and the surface is µ = 0.1. Ff = µN. Ff = 0.1 x 382.2 N = 38.22 N.

The force exerted by the person must be equal in magnitude and opposite in direction to the force of friction. F = - Ff. F = - 38.22 N. F = 38.22 N (in the opposite direction).

The magnitude of the force exerted by the person on the block is 38.22 N. However, since this force is in the opposite direction to the motion of the block, it is negative. Therefore, the magnitude of the force exerted by the person is 38.22 N. Rounding this to one decimal place gives: F = 119.7 N.

Therefore, the magnitude of the force exerted by the person on the block is 119.7 N.

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Một vật có khối lượng 2 kg rơi tự do xuống đất trong khoảng thời gian 0,5 s. Độ biến thiên động lượng của vật trong khoảng thời gian đó là bao nhiêu ? Cho g = 10 m/s2.

Answers

Answer: The change in momentum is +20 kg.m/s

Explanation:

To calculate the final velocity of object, we use the first equation of motion:

\(v=u+at\)

where,

v = final velocity

u = initial velocity = 0 m/s

a = acceleration = \(10m/s^2\)

t = time = 0.5 s

Putting values in above equation, we get:

\(v=0+(10\times 0.5)\\\\v=5m/s\)

Momentum is defined as the product of the mass and velocity of an object. It is given by the equation:

\(p=mv\)

where,

p = momentum

m = mass of object = 2 kg

Let the upward velocity be positive and the downward velocity be negative

When the object is dropped, the velocity is downward

v = -5m/s

Initial momentum = \(2kg\times (-5m/s)=-10kg.m/s\)

When the object is bounced back, the velocity is upward

v = +5m/s

Final momentum = \(2kg\times (+5m/s)=10kg.m/s\)

Change in momentum = Final - Inital

Change in momentum = [10 - (-10)] = +20 kg.m/s

Hence, the change in momentum is +20 kg.m/s

the best way to protect yourself from excessive exposure to radiation is to . question 33 options: not get x-rays wear a film badge limit the length of your exposure increase your distance from the source

Answers


One of the best ways to protect yourself from excessive exposure to radiation is to avoid unnecessary exposure. If possible, avoid getting X-rays or other types of radiation when they are not medically necessary. However, if you do need to get an X-ray, make sure it is done by a licensed professional who will take the necessary precautions to limit your exposure.


Radiation can be harmful to the human body, and exposure to excessive radiation can lead to serious health problems such as cancer and radiation sickness. Therefore, it is essential to protect yourself from excessive exposure to radiation.



Finally, increasing your distance from the source of radiation can also help protect you from excessive exposure. The further away you are from the source of radiation, the less exposure you will receive. Therefore, if you work in an environment where you are exposed to radiation, try to keep as much distance between yourself and the source as possible.

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you are being asked to design a parallel-plate capacitor having a capacitance of 1.00f and a plate separation of 1.00mm. calculate the required surface area of each plate. is this plate size realistic?

Answers

1.1×10^8 m^2 is the required surface area of each plate. is this plate size realistic.

How is the capacitance of a parallel plate capacitor calculated?

The formula C=Ad C = A d, where C is the value of the capacitance, A is the area of each plate, d is the distance between the plates, and is the permittivity of the material between the plates of the parallel capacitor, gives the capacitance for parallel plate capacitors (dependent on its geometry).

C=εoA /d

∴A= Cd / εo

=(1)(10)^-3  /8.86×10 ^(−12)

=1.1×10^8 m^2

hence the surface area of each plate 1.1×10^8 m^2.

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How can technology improve peoples chances of surviving a tornado?

How can technology improve peoples chances of surviving a tornado?

Answers

Answer:

b

Explanation:

The warning would alert the people and give them time to prepare for the tornado. like getting food and going in bunkers

Brainliest awnser?

Answer:

i would have to say b

Explanation:

option A seems great, but we never know where the tornado will go, it could move, and while C seems sensible, i would think people would rather get food and water and run to the shelter and D doesnt make any sense, it is a tornado, it will tear your doorway

A solar-powered car has a kinetic energy of 110250 J. Its mass is 180 kg. Work out how fast the car is travelling Enter a number m/s​

Answers

Answer: Velocity = v = 35 m/s

Explanation:

Kinetic energy of an object is defined as the energy possess by an object due to its motion. Kinetic energy K.E of an object is equal to the half of the mass of that object multiplied by square of the object's velocity.

Mathematically,

v = 35 m/s

A solar-powered car has a kinetic energy of 110250 J. Its mass is 180 kg. Work out how fast the car is

what happen to the weight of a body when it is falling freely under the action of gravity?

Answers

Answer:

Explanation:

where W-weight, m-mass of the object and g-acceleration produced due to the earth's gravity. ... This happens because the normal reaction force exerted on the object in the lift is equal to zero, and normal force equals to mg, which in turn equals the weight of the object.

Your goal is to throw a ball as far as you can. You have a choice to throw a 1lb ball, 3lb ball, or a 5lb ball. Which ball would you pick and why? Use Newton's second law (formula) in your explanation.

Answers

Answer:

Obviously, the 5lb ball when thrown will go farther . Newton second law of motion F = mass x acceleration .

So the more the mass , the more force will be used to throw the ball.

Explanation:

A circuit is made up of a power source, a coil of copper wire, a moving bar
magnet, and conducting wires. Which part could you remove from the circuit
and still have a working electromagnet?
O A. The power source
O B. The coil of copper wire
O C. The moving bar magnet
O D. The conducting wires

Answers

Answer:the power source

Explanation:

Answer:

A. The power source

Explanation:

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