What did the Constitutional Convention decide to do about the slave trade?(1 point)
Responses
It expanded it.
It expanded it.
It restricted it to slave states.
It restricted it to slave states.
It banned it.
It banned it.
It delayed taking action.
Turn the following word equation into a symbolic equation: aluminum reacts with hydrochloric acid to form aluminum chloride and hydrogen.
Equation is known to be balanced when the number of moles of element at the reactant is equal to that of product.
Aluminum = Al
Hydrochloric acid = HCl
The reaction formed by Aluminum and hydrochloric acid is expressed as:
\(Al+HCl\rightarrow AlCl_3+H_2\)The balanced form of the reaction will be expressed as:
\(2Al+6HCl\rightarrow2AlCl_3+3H_2\)Which of the following best describes the structure of a nucleic acid?
a
Carbon ring(s)
b
Globular or fibrous
c
Single or double helix
d
Hydrocarbon(s)
A constant electric current deposited 365 mg of Ag in 216 minutes from an aqueous Silver trioxonitrate (v). What is the Current?
The electric current is 0.025 A
Electric current refers back to the go with the flow of energy in an electronic circuit and to the amount of strength flowing through a circuit. it's far measured in amperes (A). the bigger the cost in amperes, the more energy is flowing within the circuit.
Ag+ + e¯ →Ag
1F deposits 107.87 g/mol (molecular mass) of silver
1F = 96500 C
Let, 107.87 g/mol needed = 96500 C
Number of coulombs required to deposit 0.3650 g of silver =(96500/107.87) 0.3650
Q = 326.5 C
According to Faraday’s law, Q = I x t
I = 326.5 C / (216 x 60 s) = 0.025 A
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what is it I need help
The system at equilibrium below is heated.
How does the system adjust to reestablish
equilibrium?
2SO₂(g) + O₂(g) ⇒ 2SO3(g) + 198 kJ
CuBr2 percent composition
The percent composition of CuBr₂ is approximately 28.46% of Cu and 71.54% of Br.
To determine the percent composition of CuBr₂ (copper(II) bromide), we need to calculate the mass of each element in the compound and then divide it by the molar mass of the entire compound.
The molar mass of CuBr₂ can be calculated by adding up the atomic masses of copper (Cu) and bromine (Br) in the compound. The atomic masses of Cu and Br are approximately 63.55 g/mol and 79.90 g/mol, respectively.
Molar mass of CuBr₂ = (63.55 g/mol) + 2(79.90 g/mol) = 223.35 g/mol
Now, let's calculate the percent composition of each element in CuBr₂:
Percent composition of copper (Cu):
Mass of Cu = (63.55 g/mol) / 223.35 g/mol × 100% ≈ 28.46%
Percent composition of bromine (Br):
Mass of Br = 2(79.90 g/mol) / 223.35 g/mol × 100% ≈ 71.54%
Therefore, the percent composition of CuBr₂ is approximately:
- Copper (Cu): 28.46%
- Bromine (Br): 71.54%
These values represent the relative mass percentages of copper and bromine in the compound CuBr₂.
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Why do you need microscope or hand lens to see the parts that make up-1
?matter
.a) Matter is made of parts that are very big
.b) Matter is made of parts that have no mass
.c) Matter is made of parts that are very small
Answer:
C: matter is made of parts that very small
What is the percent by mass of barium in BaCl₂?
The percent by mass of barium in BaCl₂ is 34.09%.
How to calculate percentage by mass?The percentage by mass of an element in a compound can be calculated by dividing the mass of the element in 1 mole of the compound by the compound's molar mass and multiply the result by 100.
Percentage by mass = mass of element/mass of compound × 100
According to this question, a compound with the chemical formula BaCl₂ can be calculated as follows:
Molar mass of barium chloride = 208.23 g/mol
Percent by mass of Cl = 71/208.23 × 100
Percent by mass of chlorine = 34.09%
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A compound accepts electrons from another substance to form a covalent bond. Which term best describes this
compound's behavior?
-Lewis acid
-Arrhenius base
-Bronsted-Lowry acid
-Bronsted-Lowry base
Answer:
A). Lewis Acid
Explanation:
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The term that best describes the compound that accepts electrons from another substance to form a covalent bond is Lewis acid.
What is Lewis acid?Lewis acid is a compound or ionic species which can accept an electron pair from a donor compound while a Lewis base is a compound such as the OH- ion, that can donate a pair of non-bonding electrons.
According to this question, a compound accepts electrons from another substance to form a covalent bond.
Therefore, the term that best describes the compound that accepts electrons from another substance to form a covalent bond is Lewis acid.
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50 POINTS!!! GOOD AND EXPERT ANSWER ONLY!!! DONT WRITE FAKE ANSWERS FOR POINTS OTHERWISE THEY WILL BE DELETED!!!
The cathode ray experiment indicated the existence of negatively charged particles in an atom. This experiment also disproved the part of Dalton's atomic model that claimed indivisibility of the atom. When the experiment was repeated using cathodes made of a different metal, each time the results were consistent. These discoveries of Thompson were later substantiated by Robert Millikan when he calculated the charge on an electron.
Use information from the passage to justify whether the characteristics of reliable scientific explanations are present in the development of the atomic theory.
The characteristics of scientific explanation are included in the development of the atomic theory.
What is the scientific method?The development of a scientific idea always follows the scientific method. The scientific method includes the proposition of a hypothesis, the confirmation or disapproval of the initial hypothesis, and experimentation.
Dalton's primary ideas were laid aside as stronger empirical evidence developed. J.J. Thomson's experiment has given the atomic model while the nucleus and electron were discovered by the experiments of Rutherford, Geiger, and Ernest Marsden.
Since there was experimentation at certain points to confirm or disprove the propositions, therefore, there was a deep involvement of the scientific method in the development of the atomic theory.
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Use the diagram below to answer question 13
13. A student walks from home to school,
on to a soccer field, then to an ice cream
shop, and finally home. Use grid distances
and directions to describe each leg of his
trip. What is the distance between the
student's home and the ice cream shop?
An ice cream shop is six units away from the student's home.
Just what is distance?Unaffected by direction, distance is an object's overall movement. Distance can be described as the amount of ground that an object has covered, regardless of its starting or ending points.
Student walks = Home to School + School to Soccer field + Soccer field to ice cream shop Student walks = B to C + C to D + D to E
Taken as 1 standard grid unit per city block
B to C = (0,2) (North)
C to D = (-3,0) (West)
D to E = (0,-1) ( South)
Student walks = distance in x + distance in y
Student walks = 6 unit ( 6 city blocks)
In order to get to the ice cream shop from home, the student must walk six units.
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-Convert 6.02 x 1020 formula units of MgCl₂ to mol of MgCl₂:
6.02 x \(10^{20\) formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.
To convert formula units of MgCl₂ to moles of MgCl₂, we need to use Avogadro's number, which relates the number of formula units to the number of moles.
Avogadro's number (NA) is approximately 6.022 x 10^23 formula units per mole.
Given that we have 6.02 x 10^20 formula units of MgCl₂, we can set up a conversion factor to convert to moles:
(6.02 x 10^20 formula units MgCl₂) * (1 mol MgCl₂ / (6.022 x 10^23 formula units MgCl₂))
The formula units of MgCl₂ cancel out, and we are left with moles of MgCl₂:
(6.02 x 10^20) * (1 mol / 6.022 x 10^23) = 0.1 mol
Therefore, 6.02 x 10^20 formula units of MgCl₂ is equal to 0.1 moles of MgCl₂.
It's important to note that this conversion assumes that each formula unit of MgCl₂ represents one mole of MgCl₂. This is based on the stoichiometry of the compound, where there is one mole of MgCl₂ for every one formula unit.
Additionally, this conversion is valid for any substance, not just MgCl₂, as long as you know the value of Avogadro's number and the number of formula units or particles you have.
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Determine the number of moles of air present in 1.35 L at 750 torr and 17.0°C. Which equation should you use? COMPLETE What is the number of moles present?
Answer:
0.0559 mol
Explanation:
Step 1: Given and required data
Volume of air (V): 1.35 LPressure of air (P): 750 torrTemperature (T): 17.0 °CIdeal gas constant (R): 0.0821 atm.L/mol.KStep 2: Convert "P" to atm
We will use the conversion factor 1 atm = 760 torr.
750 torr × 1 atm/760 torr = 0.987 atm
Step 3: Convert "T" to Kelvin
We will use the following expression.
K = °C + 273.15
K = 17.0 °C + 273.15 = 290.2 K
Step 4: Calculate the number of moles of air
If we assume air behaves as an ideal gas, we can calculate the moles (n) of air using the ideal gas equation.
P × V = n × R × T
n = P × V/R × T
n = 0.987 atm × 1.35 L/(0.0821 atm.L/mol.K) × 290.2 K = 0.0559 mol
Consider the reaction: CO (g) + 2 H2 (g) ⇌ CH3OH (g) where the Kp is 2.26 x 10^4 at 25°C. Calculate ΔGrxn for the reaction at 25°C under standard conditions.
The standard Gibbs free energy change of the reaction at 25°C is -18,262 J/mol.
What is energy?Energy is the ability to do work. It exists in many forms, such as kinetic energy (energy of motion), potential energy (stored energy), thermal energy (heat), chemical energy (energy stored in the bonds of molecules), electrical energy (energy carried by electrons), and nuclear energy (energy produced in the nucleus of an atom).
The reaction given is a reversible reaction and the given Kp value is at 25°C. Therefore, we can use the equation ΔG°rxn = -RT ln Kp to calculate the standard Gibbs free energy change of the reaction.
We know that R = 8.314 J/mol K and T = 298 K (25°C)
Therefore, ΔG°rxn = - 8.314 J/mol K x 298 K x ln (2.26 x 10⁴)
ΔG°rxn = -18,262 J/mol
Therefore, the standard Gibbs free energy change of the reaction at 25°C is -18,262 J/mol.
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if .654g of oxygen dissolves in 1.5L of water 1.65atm at what pressure would 1.35g in 1.5L of water dissolve
the pressure required for 1.35 g of oxygen to dissolve in 1.5 L of water is 3.56 atm.
The first step in solving this problem is to identify the relevant equation.
Henry's law is the formula that relates the pressure of a gas above a liquid to the concentration of the gas that dissolves in the liquid.
In mathematical terms, Henry's law can be expressed as follows:P = kH * Cwhere P is the pressure of the gas, kH is Henry's law constant, and C is the concentration of the gas in the liquid.
To solve the problem, we need to first determine the value of kH using the given data.
kH can be calculated using the following formula:kH = P / CSubstituting the values given in the problem into this formula, we get:kH = 1.65 atm / (0.654 g / 1.5 L) = 3.97 atm/(g/L).
Now that we have the value of kH, we can use Henry's law to calculate the pressure required for 1.35 g of oxygen to dissolve in 1.5 L of water.
To do this, we simply rearrange the formula to solve for P:P = kH * CSubstituting the values of kH and C into this formula, we get:P = 3.97 atm/(g/L) * (1.35 g / 1.5 L) = 3.56 atm
Therefore, the pressure required for 1.35 g of oxygen to dissolve in 1.5 L of water is 3.56 atm.
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Chemistry Help Please! Worth a lot of points!
1. Joseph Priestly was the first scientist to be able to prepare pure oxygen gas. He did this by heating mercuric oxide as shown in the reaction below. Answer the question related to the reaction.
2HgO(s) = 2Hg(l) + O2(g)
a.What volume of oxygen gas would be produced at STP through the decomposition of 5.36 grams of HgO? It is not collected over water!
b. What volume of oxygen gas would be produced at 23o and 0.975 atm by the decomposition of 5.36 grams of HgO?
c. What volume of oxygen gas would be collected over water at 23oC and 0.975 atm by the decomposition of 5.36 grams of HgO?
2. How many grams of water will form through the reaction of 550 mL of 2.5 M HCl and an excess amount of Ca(OH)2?
Ca(OH)2(aq) + 2HCl(aq) = CaCl2(aq) + 2H2O(l)
a. How many grams of calcium chloride will form if 250 mL of 2.0 M Ca(OH)2 reacts with 350 mL of 2.5 M HCl? Make sure to determine the limiting reagent!
3. Sam conducted an experiment where he reacted 5.0 grams of magnesium with an excess amount of oxygen gas to form magnesium oxide (MgO). When he conducted this in the lab, he obtained 8.06 grams of magnesium oxide.
a. Write and balance the chemical reaction.
b. Use stoichiometry to predict how many grams of magnesium oxide should form.
c. What is the theoretical yield?
d. What is the actual yield?
e. Calculate the percent yield.
4. Na(s) + Br2(L) = NaBr(s) (not balanced)
b.If 3.05 grams of sodium react with 10.0 grams of diatomic bromine, what is the excess reagent AND how many moles of excess reagent are present after the reaction?
c. How many grams of sodium bromide are formed?
Answer:
A.
1. a. 11.28L O2
b. 24.3L O2
c. 19.83L O2
2. a. 5.6 grams CaCl2
3. a. 2Mg + O2 = 2MgO
b. 8.06 grams MgO
c. 8.06 grams MgO
d. 8.06 grams MgO
e. 100%
4. a. 2Na + Br2 = 2NaBr
b. Excess reagent: Bromine; 0.5 moles
c. 10.6 grams NaBr
Which of the following is a characteristic of a scientific theory? A.it explains how nature works. B.it is based on a single experiment. C.it should not be possible to replicate it's results. D.it should not be possible to replicate it's observations.
Answer:
A. It explains how nature works.
Explanation:
A scientific theory is an explanation, based on a body of evidence, of how something works or will behave.
The other three answers contradict scientific theory. Theories should be based on many experiments, and you should be able to replicate the results and observations.
warm fronts appear on weather maps in areas of
Answer: A warm front is the transition area where a mass of warm air moves to replace a mass of cold air. On a weather map, a warm front is usually drawn using a solid red line with half circles pointing in the direction of the cold air that will be replaced. Warm fronts usually move from southwest to northeast. A warm front can initially bring some rain, followed by clear skies and warm temperatures.
Explanation: I got this from a website called SciJinks.gov. I hope that it answers your question and that this helps. Good luck!
Answer:
In case anyone wants both
Explanation:
Cold fronts appear on weather maps in areas of ( large temperature and air pressure decrease )
Warm fronts appear on weather maps in areas of ( temperature and air pressure increase )
How many O atoms are there in 1.51×10^23 molecules of trifluoroacetic acid, C2HF3O2?
Answer:
9.033 × 10²³ molec C₂HF₃O₂ x (2 O atoms / 1 molec C₂HF₃O₂) = 1.8066 x 10²⁴ O atoms
There are 3.01 × 10^23 atoms of oxygen in 1.51×10^23 molecules of trifluoroacetic acid, C2HF3O2.
The formula of trifluoroacetic acid is C2HF3O2
Number of moles of the trifluoroacetic acid(C2HF3O2)is given using the approach;
1 mole of the compound contains 6.02 × 10^23 molecules
x moles of the compound contains 1.51 × 10^23 molecules
x = 1.51 × 10^23 molecules × 1 mole /6.02 × 10^23 molecules
x = 0.25 moles of trifluoroacetic acid.
Now;
Number of O atoms in the sample = 0.25 × 2 × NA
Where; NA = Avogadro's number
Number of O atoms in the sample = 0.25 × 2 × 6.02 × 10^23 atoms
= 3.01 × 10^23 atoms
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Calculate the percent composition of Ca3P2
Answer:
Ca - 66%, P - 34%
Explanation:
So, this is the formula we can use to find the amount of each element:
Element count * Atomic mass = Mass
Plug in our elements for this:
Ca - 3*40.078=120.234
P - 2*30.973=61.946
Now, to find the percentage of mass, we must find total mass, and divide the two elements mass count by this total mass:
120.234+61.946=182.18
Now divide each element mass by the total mass:
Ca - 120.234/182.18=0.6599(Round to 0.65)
P - 61.946/182.18=0.34002(Round to 0.34)
Then multiply both numbers by 100 to get the percentage:
Ca - 65%
P - 34%
So these our your two answer!
Hope this helps!
The rate law for the reaction 3A --> 2B is rate = k[A] with a rate constant of 0.0447 hr-1.
What is the half-life of the reaction?
A) 0.0224 hr
B) 0.0645 hr
C) 15.5 hr
D) 22.4 hr
E) 44.7 hr
The half-life of the reaction is determined as 22.4 hr.
Half life of the reaction
The half life of the reaction is calculated as follows
rate of reaction, k = Δ[A]/3t = Δ[B]/2t
t = Δ[A]/3k = Δ[B]/2k
where;
k is rate constant = 0.0447/hrt = (3)/(3 x 0.0447) = (2)/(2 x 0.0447) = 22.4 hr
Thus, the half-life of the reaction is determined as 22.4 hr.
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What is the frequency of gamma radiation with energy of 6.96 x 10-14 J?
The frequency of gamma radiation is calculated to be = 1.11 *10^20 Hz.
What is gamma radiation?A gamma radiation is also known as gamma ray. It is a penetrating form of electromagnetic radiation arising from radioactive decay of atomic nuclei. It consists of shortest wavelength electromagnetic waves, even shorter than X-rays.
Gamma rays can pass through the human body completely and as they pass through, they cause ionizations that damage tissue and DNA.
As we know that E= hf
Hence, f= E/h
Given E= 6.96 x 10-14 J
And, Planck's constant, h = 6.626 *10^-34 m² kg/s
f = 6.96 * 10^-14J +/6.626 *10^-34
f = 1.11 *10^20 Hz
Hence, frequency of gamma radiation = 1.11 *10^20 Hz.
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FIST ONE TO AWNSER GETS BRAINLYIST AND 50 POINTS IF CORRECT HURRY!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1
Which question would be most important to ask in an interview related to the theme "winning requires sacrifice"?
A. How did your coaches and parents motivate you when you were down?
B. What activities did you have to give up in order to train eight hours every day?
C. Do you follow a special training diet, and can you share it with us?
D. Who is your personal hero, and have you ever met that person?
Answer:
B
Explanation:
Shows actual sacrifice in order to train and be the best.
Answer:
b
Explanation:
Which is a product of nuclear fusion?
A a nucleus that has a greater mass number than the starting materials
B two nuclei that are roughly half the mass of the starting materials
C a nucleus that has the same atomic number as the starting materials
D two nuclei that have greater atomic numbers than the starting materials
Answer:
A. a nucleus that has a greater mass number than the starting materials
Explanation:
The statement is "a nucleus that has a greater mass number than the starting materials."
What is nuclear fusion?Nuclear fusion occurs when two or more atomic nuclei unite to generate one or more new atomic nuclei and subatomic particles.
Two light nuclei fuse to form a single heavy nucleus in a fusion reaction. Because the overall mass of the resulting single nucleus is smaller than the mass of the two initial nuclei, the process releases energy.
Hence, the correct option is A
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Think about how you could design a robot to propel itself across an ice rink by applying the same principles that cause rockets to move. Describe what materials you would use and how the robot would work. What are some material limitations that you would need to consider for a robot moving on ice?
please help
Answer:
To design a robot that propels itself across an ice rink using the same principles as rockets, I would start by considering the materials that would be suitable for use on ice. Some materials that might work well for this purpose include plastic, rubber, and certain types of metal, such as aluminum or stainless steel.
Explanation:
The robot would work by using a propulsion system to generate a force that propels it forward. This could be achieved using a variety of methods, such as by using a jet engine or a rocket engine to produce a stream of hot gases that exits through a nozzle, creating a thrust force in the opposite direction.One material limitation to consider when designing a robot that moves on ice is the coefficient of friction between the robot's surface and the ice. A material with a low coefficient of friction, such as rubber or plastic, would be better suited for movement on ice, as it would provide less resistance and allow the robot to move more easily. In contrast, a material with a high coefficient of friction, such as steel, would be more difficult to move on ice, as it would generate more resistance and require more force to overcome.Other material limitations to consider when designing a robot for movement on ice might include the robot's weight and shape, as well as the overall stability and balance of the robot. It would also be important to consider the durability and wear resistance of the materials used, as the robot may need to withstand repeated movement on the ice over time.Answer:
Explanation:
Students learn about humankind’s search for life in outer space and how it connects to robotics and engineering. NASA is interested in sending exploratory missions to one of Jupiter’s moons, Europa, which requires a lot of preparatory research and development on Earth before it can happen. One robot currently being engineered as a proof of concept for a possible trip to explore Europa is the Icefin, which is an innovative robot that can explore under ice and in water, which are the believed conditions on Europa. This lesson provides students with intriguing information about far off (distance and time!) space missions and field robotics, and also sets up two associated robotics and arts integration activities to follow. The lesson can be used individually to provide new information to students, or as a precursor to the associated activities. A PowerPoint® presentation and worksheet are provided
15.0 L of an ideal gas at 298 K and 3.36 bar are heated to 350 K with a new pressure of 4.40 atm. What is the new volume in litres?
Answer:
13.3 L
Explanation:
Step 1: Given data
Initial pressure (P₁): 3.36 barInitial volume (V₁): 15.0 LInitial temperature (T₁): 298 KFinal pressure (P₂): 4.40 atmFinal volume (V₂): ?Final temperature (T₂): 350 KStep 2: Convert P₁ to atm
We will use the conversion factor 1 atm = 1.01325 bar.
3.36 bar × (1 atm / 1.01325 bar) = 3.32 atm
Step 3: Calculate V₂
We will use the combined gas law.
P₁ × V₁/T₁ = P₂ × V₂/T₂
V₂ = P₁ × V₁ × T₂/T₁ × P₂
V₂ = 3.32 atm × 15.0 L × 350 K/298 K × 4.40 atm
V₂ = 13.3 L
If the heat is added to an endothermic system, at equilibrium, the system will move to the _________ to regain equilibrium.
Answer:
At equilibrium, the system will move to the right to regain equilibrium
Hope Sergil
Check the Science and Interpreting Graphs
A group of students buit electromagnets using, wre, nails, and a 6V lentern battery. They decided design an
one set of investigations Use the graph to complete the organizer
nvestigation to test factors that they could chance to make a stronger electromagnet. The follow dete is from
Number of Wire Wraps and Magnetic Strength
Paperclips Magnet Picks Up
Independent Variable
Dependent Variable
12
10
8
6
4
Possible Research Question
What trends do you notice in the
data?
Write a claim based on this data
What evidence from the chart or
graph supports your claim?
25
vat
50
Number of Coils Wrapped Around
000
75
Answer:
Independent Variable: Number of Coils Wrapped Around
Dependent Variable: Number of Paperclips Magnet Picks Up
Possible Research Question: How does the number of wire wraps affect the strength of an electromagnet?
Trends noticed in the data: As the number of wire wraps (coils) around the nail increases, the magnetic strength of the electromagnet also increases. There is a positive correlation between the number of wire wraps and the number of paper clips the magnet picks up.
Claim based on the data: The magnetic strength of an electromagnet increases as the number of wire wraps (coils) around the nail increases.
Evidence from the chart or graph supporting the claim: The graph shows that as the number of wire wraps increases from 4 to 12, the number of paper clips the magnet picks up also increases from 6 to 25. This suggests a positive correlation between the two variables.
g 1. Write a balanced chemical equation, including physical state symbols, for the decomposition of solid sodium azide (NaN3) into solid sodium and gaseous dinitrogen.
Answer: A balanced chemical equation, including physical state symbols, for the decomposition of solid sodium azide (\(NaN_{3}\)) into solid sodium and gaseous dinitrogen is \(2NaN_{3}(s) \rightarrow 2Na(s) + 3N_{2}(g)\).
Explanation:
A chemical equation which contains same number of atoms on both reactant and product side is called a balanced chemical equation.
For example, \(NaN_{3}(s) \rightarrow Na(s) + N_{2}(g)\)
Here, number of atoms present on reactant side are as follows.
Na = 1N = 3Number of atoms present on product side are as follows.
Na = 1N = 2To balance this equation, multiply \(NaN_{3}\) by 2 on reactant side. Also, multiply Na by 2 and \(N_{2}\) by 3 on product side.
The equation will be rewritten as follows.
\(2NaN_{3}(s) \rightarrow 2Na(s) + 3N_{2}(g)\)
This equation contains same number of atoms on both reactant and product side. Hence, this equation is now balanced.
The symbols (s) and (g) depicts the physical state of substances present in the equation as solid and gas.
Thus, we can conclude that balanced chemical equation, including physical state symbols, for the decomposition of solid sodium azide (\(NaN_{3}\)) into solid sodium and gaseous dinitrogen is \(2NaN_{3}(s) \rightarrow 2Na(s) + 3N_{2}(g)\).