What is the potential difference across the 40 ΩΩ resistor? Express your answer with the appropriate units.

Answers

Answer 1

Answer:

26volts

Explanation:

The question is incomplete. Here is the complete question

Suppose that E = 65 V.

What is the potential difference across the 40 Ω resistor? Express your answer with the appropriate units.

Using ohms law;

V = IR

V is the potential difference

I is the current

R is the resistance

First is to get the current in the 40Ω resistor

Since the resistors are connected I'm series, same current will flow in them.

Using:

I = E/Rt

Rt = 40+60

Rt = 100Ω

I = 65/100

I = 0.65A

Hence the current in 40Ω resistor is 0.65A

Next is to calculate the potential difference V across the 40Ω resistor

V = IR

V = 0.65(40)

V = 26Volts

Hence the potential difference across the 40Ω resistor is 26volts

What Is The Potential Difference Across The 40 Resistor? Express Your Answer With The Appropriate Units.

Related Questions

the government can encourage the production of goods that create positive externalities by creating?

Answers

The government can encourage the production of goods that create positive externalities by implementing policies and mechanisms such as subsidies, tax incentives, and regulations.

Positive externalities occur when the production or consumption of a good or service benefits society beyond the direct parties involved. These benefits can include improved public health, environmental sustainability, or increased social welfare. To encourage the production of goods with positive externalities, the government can take the following steps:

Subsidies: The government can provide financial support to producers of goods with positive externalities. Subsidies can offset production costs, making it more attractive for producers to supply these goods. By reducing the costs of production, subsidies can encourage higher output and more widespread availability of goods that benefit society.

Tax incentives: The government can offer tax incentives or tax breaks to businesses that produce goods with positive externalities. By reducing the tax burden on producers, it becomes economically advantageous for businesses to engage in activities that generate positive externalities. Tax incentives can stimulate investment, innovation, and production in areas that have positive spillover effects.

Regulations: The government can implement regulations and standards that require or promote the production of goods with positive externalities. For example, environmental regulations can encourage industries to adopt cleaner technologies and reduce pollution. By setting standards and enforcing regulations, the government can steer production towards goods that have positive impacts on society.

Public-Private Partnerships: The government can collaborate with private entities to promote the production of goods with positive externalities. Through partnerships, the government can provide resources, expertise, and incentives to businesses that are willing to produce goods that generate social benefits. This collaboration can help overcome barriers and create a conducive environment for the production of socially beneficial goods.

By employing these measures, the government can provide the necessary incentives and support for the production of goods that create positive externalities. These actions align the private interests of producers with the broader goals of societal welfare, fostering a more sustainable and socially responsible economy.

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Where is the near point of an eye for which a spectacle lens of power +2 D is prescribed for reading purpose?

Answers

The near point of a human eye is about a distance of 25 cm.

The closest distance that an object may be viewed clearly without straining is known as the near point of the eye.

This distance (the shortest at which a distinct image may be seen) is 25 cm for a typical human eye.

The closest point within the accommodation range of the eye at which an object may be positioned while still forming a focused picture on the retina is also referred to as the near point.

In order to focus on an item at the average near point distance, a person with hyperopia must have a near point that is further away than the typical near point for someone of their age.

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A vector has the components Ax=−31m and Ay=44m.
Express your answer to two significant figures and include appropriate units.
1.) What is the magnitude of this vector?
2.) What angle does this vector make with the positive x axis?

Answers

Magnitude of vector A is  51.4 m and the angle of vector A with positive x-axis θ is 127.1° .

The quantities which have direction as well as magnitude is known as vector quantities .

We are given that ,

Ax is vector component on x -axis=−31m

Ay is vector component on y -axis=44m

Therefore, the magnitude of the vectors \(A_{x}\) and \(A_{y}\) is \(A\) which is given as,

\(A = \sqrt{A_{x} ^{2} }+ {A_{y} ^{2} }\\A = \sqrt{{-31} ^{2} }+ {41 ^{2} }}\\A = 51.4m\)

Thus, the magnitude of vector A will be 51.4 m

Now calculating the angle(θ) of the vector which make on the positive x axis, is given by the formula,

θ' = \(tan^{-1}\frac{Ax}{Ay}\)

θ' = \(tan^{-1}\frac{-31}{44}\)

θ' = \(-59.9\)°

Thus, here vector A is lies in 2nd quadrant which is  x-component of vector A that is negative and y-component is positive. So that from this to get the angle of vector with positive x-axis,

θ = 180° - θ'

θ=180 °- 52.9°

θ= 127.1°

Hence from above solution, the angle of vector A with positive x-axis θ is 127.1°

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Explain the light detection technique of photovoltaic detection​

Answers

Answer:

Photovoltaic detection is a technique that converts light into electrical energy. It is a process that involves the use of a photovoltaic cell, which is made up of semiconductor materials, to generate an electric current when exposed to light.

The photovoltaic cell absorbs the photons of light, which then knock electrons out of their orbits, creating a flow of electricity. The amount of electricity produced is proportional to the intensity of the light. The photovoltaic cell is commonly used in solar panels to generate electricity from sunlight. The efficiency of the photovoltaic cell is dependent on several factors, including the type of semiconductor material used, the purity of the material, and the thickness of the cell.

The photovoltaic cell has many applications, including in solar power generation, telecommunications, and remote sensing. The technique of photovoltaic detection is an important area of research, as it has the potential to provide a clean and renewable source of energy that can help mitigate climate change.

Learn more about Photovoltaic detection

Ocean tides are caused by the ______________ pull of the _______ and the _______. The moon
has the __________ effect on the tides. When the Sun, moon and earth are in a straight line, we
have __________ tides. When the Sun, moon and earth are at right angles we have _________
tides. Spring tides are especially _________ tides while neap tides are especially _________
tides.

Answers

Ocean tides are caused by the gravitational pull of the Moon and the Sun. The moon has the strongest effect on the tides. When the Sun, Moon, and Earth are in a straight line, we have spring tides. When the Sun, Moon, and Earth are at right angles, we have neap tides. Spring tides are especially high tides while neap tides are especially low tides.

Ocean tides are caused by the gravitational pull of the moon and the sun on the Earth's oceans. The moon has a greater effect on tides than the sun because it is closer to the Earth.

When the Sun, moon, and Earth are in a straight line, we have higher high tides and lower low tides, which are called spring tides.

When the Sun, moon, and Earth are at right angles, we have less extreme tides, which are called neap tides.

Spring tides occur during a full moon and a new moon, while neap tides occur during a first quarter and a third quarter moon. Spring tides are especially strong tides because the gravitational pull of the moon and the sun are working together to pull the oceans in the same direction. Neap tides are weaker tides because the gravitational pull of the moon and the sun are working against each other, which leads to a lesser tidal range.

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______________________________

A Stone Is Dropped Into a Deep Water Well. The Sound of The Stone Hitting The Water Is Heard After 3.4 Seconds. Determine The Depth of The Water Well.

N.B. The Correct Answer Will Receive 30 Points & The Brainliest Title.
______________________________​

Answers

A Stone Is Dropped Into a Deep Water Well. The Sound of The Stone Hitting The Water Is Heard After 3.4 Seconds. then The Depth of The Water Well is 56.6 m.

In terms of physics, sound is a vibration that travels through a transmission medium like a gas, liquid, or solid as an acoustic wave. Sound is the receipt of these waves and the brain's perception of them in terms of human physiology and psychology. Only acoustic waves with frequencies between about 20 Hz and 20 kHz, or the audio frequency range, may cause a human to have an auditory sensation. These correspond to sound waves in air with an atmospheric pressure of 17 metres (56 ft) to 1.7 centimetres (0.67 in) in wavelength. Ultrasounds are sound waves with a frequency higher than 20 kHz that are inaudible to humans. Infrasound refers to sound frequencies below 20 Hz. Animals of different species have different hearing ranges. Acceleration of the stone is 9.8 m/s²

according to kinematics,

s = ut + 1/2 at²

s =  1/2 ×9.8×3.4²

s = 56.6 m

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A potato with a mass of 0.25kg is resting on a table. Calculate the force that the potato exerts on the Earth.

Answers

Answer:

F = 2.45 [N]

Explanation:

The force that the potato exerts on the Earth is equal to the product of the potato mass by gravitational acceleration.

\(F=m*g\)

where:

m = mass = 0.25 [kg]

g = gravity acceleration = 9.81 [m/s²]

\(F=0.25*9.81\\F=2.45[N]\)

A light elastic string, of natural length g metres and modulus mg N, has one end attached to a fed point O, and the other end attached to a particle of mass m kg. If the particle hangs in equilibrium vertically below O, what will the extension in the string be? Give your answer in metres to 1 decimal place.

The particle from the previous question is dropped from a point § metres directly below O and enters into simple harmonic motion centred on the equilibrium point once the string is under tension. If the equation of motion when under tension is › = -n?, where x is the displacement from the
equilibrium position, then find the constant n.

In the previous question, how long after it is dropped does the particle enter simple harmonic motion? Give your answer in seconds.

What is the amplitude of the simple harmonic motion in the previous two questions? Give your answer in metres to 2 decimal places.

How long does it take the particle in the previous three questions to come to instanteous rest for the first time? Give your answer in seconds to 2 decimal places.

A light elastic string, of natural length g metres and modulus mg N, has one end attached to a fed point

Answers

The extension in the string when the particle hangs in equilibrium is e = mg/k. The constant n in the equation of motion is n = (2π/T)²m. The time it takes for the particle to enter simple harmonic motion is t = √(2§/g).

To find the extension in the string when the particle hangs in equilibrium, we need to consider the forces acting on the particle. The weight of the particle is mg, acting vertically downward. The tension in the string exerts an equal and opposite force, mg, to balance the weight. Since the particle is in equilibrium, the total force acting on it is zero.When the particle is dropped from a point below O, it will stretch the string due to its weight. Let's denote the extension of the string as e. The tension in the string will now be greater than mg because it needs to support the weight of the particle and provide the necessary centripetal force for the simple harmonic motion.The extension in the string is given by Hooke's law: F = kx, where F is the force, k is the modulus of the string, and x is the extension. In this case, the force is the tension in the string, and the extension is e. Thus, we have mg = ke. Rearranging the equation, we get e = mg/k.

To find the constant n in the equation of motion, › = -n?, we can use the fact that the period of simple harmonic motion is given by T = 2π√(m/k), where m is the mass of the particle and k is the spring constant. Comparing this with the equation of motion, we see that ω² = n/m. Since ω = 2π/T, we can substitute ω in terms of T and solve for n: n = (2π/T)²m.

To determine when the particle enters simple harmonic motion, we need to find the time it takes for the string to reach its equilibrium position. Since the particle is dropped from a point § meters below O, it will accelerate towards the equilibrium position due to the tension in the string. The time taken for this free-fall motion can be calculated using the equation of motion for constant acceleration: § = ½gt². Solving for t, we get t = √(2§/g).The amplitude of the simple harmonic motion is equal to the maximum displacement from the equilibrium position. In this case, the maximum displacement is equal to the initial dropped distance, § meters.To determine the time it takes for the particle to come to instantaneous rest for the first time, we need to find the time period of the simple harmonic motion. The time period, T, is given by T = 2π√(m/k). To find the time it takes to come to rest, we need to consider half of the time period, T/2.The amplitude of the simple harmonic motion is equal to the initial dropped distance, § meters. The time it takes for the particle to come to instantaneous rest for the first time is T/2, where T is the time period of the simple harmonic motion.

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4. Calculate the total resistance of the circuit if R1=4 Ω, R2=30 Ω, R3=10Ω, R4=5Ω Determine the current strength if the circuit is connected to a voltage source with a voltage of 56 V

4. Calculate the total resistance of the circuit if R1=4 , R2=30 , R3=10, R4=5 Determine the current

Answers

The total resistance of the circuit is 49 Ω. The current strength in the circuit, when connected to a voltage source of 56 V, is approximately 1.14 A.

To calculate the total resistance of the circuit, we need to determine the equivalent resistance of the resistors connected in a series.

Given:

R1 = 4 Ω

R2 = 30 Ω

R3 = 10 Ω

R4 = 5 Ω

Calculate the equivalent resistance (RT) of R1 and R2, as they are connected in series:

RT1-2 = R1 + R2

RT1-2 = 4 Ω + 30 Ω

RT1-2 = 34 Ω

Calculate the equivalent resistance (RTotal) of RT1-2 and R3, as they are connected in parallel:

1/RTotal = 1/RT1-2 + 1/R3

1/RTotal = 1/34 Ω + 1/10 Ω

1/RTotal = (10 + 34) / (34 * 10) Ω

1/RTotal = 44 / 340 Ω

1/RTotal ≈ 0.1294 Ω

RTotal ≈ 1 / 0.1294 Ω

RTotal ≈ 7.74 Ω

Calculate the equivalent resistance (RTotalCircuit) of RTotal and R4, as they are connected in series:

RTotalCircuit = RTotal + R4

RTotalCircuit = 7.74 Ω + 5 Ω

RTotalCircuit ≈ 12.74 Ω

Therefore, the total resistance of the circuit is approximately 12.74 Ω.

To determine the current strength (I) when connected to a voltage source of 56 V, we can use Ohm's Law:

I = V / RTotalCircuit

I = 56 V / 12.74 Ω

I ≈ 4.39 A

Therefore, the current strength in the circuit, when connected to a voltage source of 56 V, is approximately 4.39 A (or 1.14 A, considering significant figures).

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how does mass relates to latent heat?​

Answers

The mass of a substance is not directly related to latent heat. Instead, latent heat is a parameter that describes the amount of energy required or released during a phase shift of a substance.

What is latent heat?​

Latent heat can be thought of as hidden energy that is supplied or extracted to change the state of a substance without changing its temperature or pressure.

Latent heat is energy released or absorbed, by a body or a thermodynamic system, during a constant-temperature process—typically a first-order phase transition.

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To accelerate, an object must

Answers

Answer:

be acted upon an object or person

Explanation:

hello what is momentum?

Answers

Answer:

Momentum is vector quantity and it is defined as the product of mass of the object and velocity of the object.

As it is a vector quantity it has both direction and magnitude, and momentum is written as

p = m × v

p = momentum

m = mass of the object

v = velocity

Two kinds of momentum are there and they are:

Linear MomentumAngular Momentum

Which of these statements best describes how energy is transferred when an object experiences friction?

A.friction changes mechanical energy to light energy

B.friction changes mechanical energy to heat energy

C. Friction changes mechanical energy to chemical energy

Answers

Answer: b hopefully this helps you with work

What types of memories are stored in the collective unconscious?

Answers

The types of memories that are stored in the collective unconscious include instinctive patterns and archetypes from ancestral heritage.

What is the collective unconscious?

The collective unconscious can be defined as  the part of the human mind  that contains distinct types of memories and also instinctive impulses in humans which may shape some of our behaviors regarding specific situations and also environmental contexts (e.g., during danger situations).

In conclusion, the types of memories that are stored in the collective unconscious include instinctive patterns and archetypes from ancestral heritage.

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If I do 140j work in 7 seconds, how much did I produce

Answers

you produce about 20 W

Explanation:

Determine the time in which the work will be done. Here, we can take t = 60 s . Power is equal to work divided by time. In this example, P = 9000 J / 60 s = 150 W(example)

Answer:

Explanation:

To determine the power (or rate of work) produced, we can use the formula:

Power = Work / Time

Where:

Work = 140 J (joules)

Time = 7 seconds

So, we can plug in the values into the formula:

Power = 140 J / 7 s = 20 W (watts)

So, you produced 20 watts of power in 7 seconds.

It's important to note that work and power are different physical quantities. Work represents the amount of energy transferred, while power represents the rate at which that energy is transferred.


A stone is dropped off of a 123 meter cliff and falls to the ground below. How long does it take for the stone to hit the ground

Answers

25.10 or 24.6m/s both answers are correct

Explanation:

firstly , divide the multiply with 2 and divide the result by acceleration due to gravity which is 9.8m/s or 10m/s

123*2=246

246/9.8 or 10

= 25.10 or 24.6m/s

Identify the energy levels from which the 410.2 nm emission line of the Balmer series of the
hydrogen atom originates, i.e., state the values of ninitial and nfinal. What is the frequency of the
radiation involved in the transition between these levels?

Answers

The energy level from which is emitted is n = 6

The frequency is\(7.3 * 10^14\) Hz

What is the energy level?

The Rydberg equation is a mathematical formula that relates the wavelengths of light emitted by an atom to the energy levels of its electrons.

Using the Rydberg equation;

1/λ= RH (1/\(n_{2}^2\) - 1/\(n_{1} ^2\))

1/\(410.2 * 10^-9\) = \(1.097 * 10^7\)(1/\(2^2\) - 1/  /\(n_{1} ^2\))

1/\(4.102 * 10^-7\) = \(1.097 * 10^7\)(1/4 - 1/\(n_{1} ^2\))

1/\(4.102 * 10^-7\) * 1/ \(1.097 * 10^7\) = (1/4 - 1/\(n_{1} ^2\))

0.22 = 0.25 -  1/\(n_{1} ^2\)

0.22 - 0.25 = -  1/\(n_{1} ^2\)

-0.03 = -  1//\(n_{1} ^2\)

\(n_{1}\) = 6

Using;

f = c/λ

\(3 * 10^8/4.102 * 10^-7 \\f = 7.3 * 10^14 Hz\)

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What is measurement???
knahi pani nepali ca jasto chaxenw​

Answers

Explanation:

The comparison of an unknown physical quantity with the known standard quantity is called measurement....

Here are some tho.....

1. Go to your room for 2 hours (you can do it longer to really feel the difference); 2. Keep your gadgets out of your reach, turn off any grid powered electrical devices and appliances; 3. Perform any activities that you loved aside from those that needed modern products of technology. 4. After the social experiment, write a minimum of 5 sentences essay on how does it feel to have no gadgets, appliances and anything that are products of modern technology. In your essay you must answer the question, Are we human using these technologies or are these technologies using us already?​

Answers

Answer:

You should probably try following the instructions and you will be able to find the answer to the question :>

Explanation:

but mostly the technology's using us

You know you can provide 600 W
of power to move large objects. You need to move a 60-kg
safe up to a storage loft, 18 m
above the floor.
Part A
With what average speed can you pull the safe straight up?

Answers

A. The average speed you can use to pull the safe is 1.02 m/s

B. The time needed to pull the safe up is 17.65 s

A. How do i determine the velocity?

First, we shall obtain the force. This is shown below:

Mass of safe (m) = 60 KgAcceleration due to gravity (g) = 9.8 m/s² Force (F) =?

F = mg

F = 60 × 9.8

F = 588 N

Finally, we shall obtain the average speed. Details below:

Power = 600 WForce = 588 NAverage speed =?

Power = force × average speed

600 = 588 × average speed

Divide both sides by 588

Average speed = 600 / 588

Average speed = 1.02 m/s

B. How do i determine the time?

The time needed to pull the safe up can be obtained as follow:

Average speed = 1.02 m/sTotal distance = 18 mTime = ?

Time = Total distance / average speed

Time = 18 / 1.02

Time = 17.65 s

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Complete question:

You know you can provide 600 W

of power to move large objects. You need to move a 60-kg

safe up to a storage loft, 18 m

above the floor.

Part A

With what average speed can you pull the safe straight up?

Part B

What is the time needed to pull the safe up?

Which statement indicates what the fossil record suggests about evolution on Earth?

Humans have only recently existed on Earth.
Organisms originally lived only on land.
Life on Earth started before water formed on Earth.
Multicellular life evolved before complex single-celled life.

Answers

The fossil record suggests that multicellular life evolved before complex single-celled life on Earth.

What does the fossil record suggest about the evolution of life on Earth?

The statement that suggests what the fossil record indicates about evolution on Earth is "Multicellular life evolved before complex single-celled life." The fossil record provides evidence that early life forms were single-celled, and over time, some of these organisms evolved into multicellular organisms.

This is supported by the appearance of fossils of multicellular organisms that are older than those of complex single-celled organisms. The other statements are not supported by the fossil record; humans have not existed on Earth for very long, life likely began in the oceans, and early life forms were single-celled.

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Question 1 of 10
A business must decide whether to open a new office in China. If it opens the
branch, it will increase its chances of selling a high volume of its products in
China. On the other hand, the business will have to spend a lot of money to
make the branch operational.
What would be an opportunity cost for the business if it chooses not to open
the new branch in China?
A. The business would lose the chance to make more money in
China.
B. The business would increase its marginal benefits on each
product it makes.

Answers

A. The opportunity cost for the business if it chooses not to open the new branch in China would be that the business would lose the chance to make more money in China.

Opportunity cost refers to the cost of the next best alternative that must be forgone in order to pursue a certain action. In this case, if the business chooses not to open the new branch in China, the opportunity cost would be the potential revenue and profits that could have been generated by selling products in China.

1.Can money by happiness?why and Why not?
2.Are you happy with the possession you have? Yes/No Why? ​

Answers

Answer:

Explanation:

1) No it can't

2)Yes I am

Answer:

yes it's can be, but Don't put money first

Which air pocket would you expect to cool down more at night?

Answers

Which air pocket would you expect to cool down more at night? 

Answer: The ocean air.

Why?

Because ocean water seems to cool faster at night which may cause the ocean air to cool down more at night.

Ocean water seems to cool faster at night which may cause the ocean air to cool down more at night.

What is Air pocket?

"Air pocket" is merely another term for ordinary turbulence. You might feel as if you're falling from the sky, but rest assured, if you flying commercially, you rarely gain or lose more than about twenty feet, especially if the plane is on autopilot.

The term "air pocket" comes from early aviation, a time when pilots flying open-cockpit biplanes took adventurous locals on a rides in their “flying machines.”

When the plane entered air that, instead of simply sitting there, was flowing slightly upward or slightly downward, the plane's path was altered slightly upward or slightly downward.  

Therefore, Ocean water seems to cool faster at night which may cause the ocean air to cool down more at night.

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Which are true of gamma radiation?
Check all that apply.
A. It has no charge.
B. It has a mass of 0.0005 amus.
C. It causes transmutation.
D. It usually occurs with other types of radioactive decay.

Answers

Answer:

B and D

Explanation:

Question 2 (1 point)
What happens to the number of waves when you change the light from green to red?
Increase
decrease
remain the same
there are zero waves

Answers

When you change the light from green to red, the number of waves remains the same.

Light waves behave similarly throughout the electromagnetic spectrum. Depending on the nature of the item and the light's wavelength, a light wave can be transmitted, reflected, absorbed, refracted, polarized, diffracted, or dispersed when it strikes a surface.

The number of waves doesn't vary when the light changes from green to red. The distance between each wave's consecutive peaks, or wavelength, determines the color of light. Red and green light both have waves with a set number of peaks and troughs per unit of time, despite green light having a shorter wavelength. As a result, the number of waves is unaffected by changing the colour of the light.

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The figure below shows a dipole. If the positive particle has a charge of 37.3 mC and the particles are 3.08 mm apart, what is the electric field at point A located 2.00 mm above the dipole's midpoint? (Express your answer in vector form.)

Answers

The electric field at point A located 2.00 mm above the dipole's midpoint is 5.287 X 10¹³ N/C.

Electric field of the positive particle

The electric field is calculated as follows;

E = kq/r²

where;

r is the distance between the chargesk is Coulomb's constantq is magnitude of the charge

midpoint of 3.08 m, x = 1.54 mm

r(1.54 mm, 2.00 mm)

|r| = √(1.54² + 2²)

|r| = 2.52 mm

E = (9 x 10⁹ x 37.3 x 10⁻³)/(2.52 x 10⁻³)²

E = 5.287 X 10¹³ N/C

Thus, the electric field at point A located 2.00 mm above the dipole's midpoint is 5.287 X 10¹³ N/C.

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Which statement best describes the primary difference between scientific investigation and technological design?
Scientific investigation is more time consuming than technological design.
Technological design is more expensive than scientific investigation.
Technological design involves background research, and scientific investigation does not require research.
Scientific investigation involves experiments, and technological design involves products.
Su

Answers

The statement best describes the primary difference between scientific investigation and technological design is Scientific investigation involves experiments, and technological design involves products. Option D

What are scientific investigation and technological design?

It can be said that both scientific investigation and technolgical design require problem-solving, creativity, and rigorous methods.

However, both of them have different objectives. While Scientific investigation seeks to expand knowledge and understanding of the natural world. Research involvs hypothesis testing and different experiments;

on the other hand, Technological design, wants to create or improve products, processes, or systems to meet specific needs or solve particular problems.

It can then be defined as the application of scientific knowledge for practical purposes.

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A 1400-N crate rests on the floor.
How much work is required to move it at constant speed 5.0 m
vertically.
Express your answer to two significant figures and include the appropriate units.

Answers

The work required to move the crate vertically at a constant speed of 5.0 m is approximately 7000 Joules (J).

To determine the work required to move the crate vertically, we need to calculate the gravitational potential energy change. The work done is equal to the change in potential energy.

The formula for gravitational potential energy is given by:

Potential energy = mass * acceleration due to gravity * height

In this case, the mass of the crate is not provided, but we can use the given weight of the crate to find the mass. Weight is equal to mass multiplied by the acceleration due to gravity (W = mg).

Given:

Weight of crate (W) = 1400 N

Acceleration due to gravity (g) = 9.8 m/s^2

Vertical distance (height) = 5.0 m

First, calculate the mass of the crate:

1400 N = m * 9.8 m/s^2

m = 1400 N / 9.8 m/s^2 ≈ 143 kg

Now we can calculate the work:

Work = Potential energy = mass * g * height

Work = 143 kg * 9.8 m/s^2 * 5.0 m ≈ 7000 J

Therefore, the work required to move the crate vertically at a constant speed of 5.0 m is approximately 7000 Joules (J).

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A balloon has a charge of -1.0 x 10-6 C and is held 0.97 m away from a steel tube. If the force between them is -5.5 N, what is the charge of the tube?

Answers

We can use Coulomb's Law to solve this problem:

F = k * (q1 * q2) / r^2

where:

F = -5.5 N

k = Coulomb's constant (9.0 x 10^9 N·m^2/C^2)

q1 = charge of the balloon (-1.0 x 10^-6 C)

q2 = charge of the steel tube= ?

r = distance between the balloon and the steel tube (0.97 m)

Plugging in the given values and solving for q2:

-5.5 N = (9.0 x 10^9 N·m^2/C^2) * (-1.0 x 10^-6 C) * q2 / (0.97 m)^2

Solving for q2, we get:

q2 = (-5.5 N) * (0.97 m)^2 / [(9.0 x 10^9 N·m^2/C^2) * (-1.0 x 10^-6 C)]

q2 ≈ -6.4 x 10^-6 C

Therefore, the charge of the steel tube is approximately -6.4 x 10^-6 C.

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