What is the probability of the spinner below landing on blue and rolling an even number on a 6-sided die?

Show work! If it’s correct I will give brainliest

What Is The Probability Of The Spinner Below Landing On Blue And Rolling An Even Number On A 6-sided

Answers

Answer 1

Answer:

1/6

Step-by-step explanation:

There is a 1/3 chance that you will get either a blue, red or green.
It is also a 1/2 chance that you will get an even number on a die.
1/3x1/2=1/6.

Therefore our answer is 1/6


Related Questions

A block of ice is in the shape of a rectangular prism. The ice block has a volume of 9,600 cubic inches. After being in a warm area, the size of the block is now 18 inches by 12 inches by 20 inches.

What is the difference between the volume of the ice block before and after it melted?

Answers

Answer:

5280 cubic inches

Step-by-step explanation:

V= l * w * h

V= 18 * 12 * 20

V= 4320 cubic inches

Then do the first measurement subtracted by the second one because it wants to know the difference.

9600 - 4320 = 5280 cubic inches

A Car can Travel 82 miles on 2 gallons of gasoline. How Far can it travel on 9 gallons?​

Answers

Answer:

369 miles

Step-by-step explanation:

82 miles =2 gallons

41 miles = 1 gallon

369 miles = 9 gallons

Answer:

369 miles

Step-by-step explanation:

Distance travelled in 1 gallon gasoline = 82 miles

So, distance travelled in 1 gallon gasoline

= distance travelled in 2 gallon gasoline/2

= 82 miles/2

= 41 miles

So, distance travelled in 9 gallons gasoline

= distance travelled in 1 gallon gasoline × 9

= 41 miles × 9

= 369 miles

Write a recursive formula for the nth term of the sequence 5,12,19,26,....

Answers

Thus, beginning with a 1 = 5, the formula a n = a n-1 + 7 can be used to recursively find the nth term of the sequence.

what is sequence ?

A sequence in mathematics is an ordered collection of numbers that is typically defined by a formula or rule. Every number in the series is referred to as a term, and its location within the sequence is referred to as its index. Depending on whether the list of terms stops or continues indefinitely, sequences can either be finite or infinite. By their patterns or uniformity, sequences can be categorised, and the study of sequences is crucial to many areas of mathematics, such as calculus, number theory, and combinatorics. Mathematical, geometrical, and Fibonacci sequences are a few examples of popular sequence types.

given

The sequence's terms are all different by 7 (i.e., 12 - 5 = 19 - 12 = 26 - 19 =... = 7).

The following is a definition of a recursive formula for the nth element of the sequence:

a 1 = 5 (the first term of the series is 5) (the first term of the sequence is 5)

For n > 1, each term is derived by adding 7 to the preceding term, so a n = a n-1 + 7.

Thus, beginning with a 1 = 5, the formula a n = a n-1 + 7 can be used to recursively find the nth term of the sequence. For instance, we have

a_2 = a_1 + 7 = 5 + 7 = 12

a_3 = a_2 + 7 = 12 + 7 = 19

a_4 = a_3 + 7 = 19 + 7 = 26

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company that ships glass for a glass manufacturer claimed that its shipping boxes are constructed so that no more than 8 percent of the boxes arrive with broken glass. The glass manufacturer believed the actual percent is greater than 8 percent. The manufacturer selected a random sample of boxes and recorded the proportion of boxes that arrived with broken glass. The manufacturer tested the hypotheses H, :p = 0.08 versus H, :p > 0.08 at the significance level of a = 0.01. The test yielded a p-value of 0.001. Assuming all conditions for inference were met, which of the following is the correct conclusion?А. The p-value is greater than a, and the null hypothesis is rejected. There is convincing evidence that the proportion of all boxes that contain broken glass is greater than 0.08.B. The p-value is greater than a, and the null hypothesis is rejected. There is not convincing evidence that the proportion of all boxes that contain broken glass is greater than 0.08.C. The p-value is greater than a, and the null hypothesis is not rejected. There is not convincing evidence that the proportion of all boxes that contain broken glass is greater than 0.08.D. The p-value is less than a, and the null hypothesis is rejected. There is convincing evidence that the proportion of all boxes that contain broken glass is greater than 0.08.E The p-value is less than a, and the null hypothesis is not rejected. There is not convincing evidence that the proportion of all boxes that contain broken glass is greater than 0.08.

Answers

The conclusion which is correct about given situation is D) The p-value (0.001) is less than the significance level (0.01), which means we reject the null hypothesis that the proportion of boxes with broken glass is equal to or less than 8%.

We have convincing evidence to suggest that the actual proportion of boxes with broken glass is greater than 8%. Therefore, we can conclude that the glass manufacturer's belief is supported by the sample data.

This conclusion is based on the fact that the p-value is less than the significance level, indicating that the observed data is unlikely to have occurred by chance alone assuming the null hypothesis is true.

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If the sum of an infinite geometric series is \( \frac{15625}{24} \) and the common ratio is \( \frac{1}{25} \), determine the first term. Select one: a. 625 b. 3125 c. 25 d. 125

Answers

The first term of the infinite geometric series is 625.Let's dive deeper into the explanation.

We are given that the sum of the infinite geometric series is \(\( \frac{15625}{24} \)\)and the common ratio is\(\( \frac{1}{25} \).\)The formula for the sum of an infinite geometric series is \(\( S = \frac{a}{1 - r} \)\), where \( a \) is the first term and \( r \) is the common ratio.
Substituting the given values into the formula, we have \(\( \frac{15625}{24} = \frac{a}{1 - \frac{1}{25}} \).\)To find the value of \( a \), we need to isolate it on one side of the equation.
To do this, we can simplify the denominator on the right-hand side.\(\( 1 - \frac{1}{25} = \frac{25}{25} - \frac{1}{25} = \frac{24}{25} \).\)
Now, we have \(\( \frac{15625}{24} = \frac{a}{\frac{24}{25}} \).\) To divide by a fraction, we multiply by its reciprocal. So, we can rewrite the equation as \( \frac{15625}{24} \times\(\frac{25}{24} = a \).\)
Simplifying the right-hand side of the equation, we get \(\( \frac{625}{1} = a \).\)Therefore, the first term of the infinite geometric series is 625.
In conclusion, the first term of the given infinite geometric series is 625, which corresponds to option (a).



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Lena is asked to write an explicit formula for the graphed geometric sequence. On a coordinate plane, 3 points are plotted. The points are (1, 1), (2, 2.5), (3, 6.25). What value, written as a decimal, should Lena use as the common ratio? 1.0 1.5 2.5

Answers

Answer:

Common Ratio = 2.5

Step-by-step explanation:

Given

Points: (1, 1), (2, 2.5), (3, 6.25)

Required

Determine the common ratio

The points can be rewritten as:

x --- f(x)

1 ---- 1

2 --- 2.5

3 ---- 6.25

The data under the x column are the domain of the function and in this case,  they are not needed;

To calculate common ration, Lena should use data in function f(x) column

Common ratio is calculated by dividing a term by the previous term;

Hence;

Common Ratio = 2.5/1 or 6.25/2.5

Common Ratio = 2.5 or 2.5

Notice that, the results are the same;

Hence, the usable common ratio is 2.5

Answer:

c

Step-by-step explanation:

edge2020

Art and his friends spent $62 at the movies. Admission tickets cost $12 apiece, and a bucket of popcorn costs $7. Which equation written in standard form represents the number of tickets bought, t, and the number of buckets of popcorn bought, p?

12p + 7t = 62
7p + 12t = 62
12p = 62 – 7t
7p = 62 – 12t

Answers

It would be the second one.. B

Four buses carrying 150 football fans from the same school arrive at a football stadium. The buses carry, respectively, 20, 45, 35, and 50 students. One of the fans is randomly selected. Let X denote the number of fans that were on the bus carrying the randomly selected person. One of the 4 bus drivers is also randomly selected. Let Y denote the fans of students on his bus. Compute E(X) and Var(X)

Answers

If 4 buses carrying 150 football fans from same school arrive at a football stadium, then the expected-value, "E(X)" is 41 and variance "Var(X)" is 99.

To find the expected value of X, we use the formula E(X) = ∑x P(X=x), where x is = possible values of X and P(X=x) = probability of X taking the value x.

Four buses have a total of 150 students, the probability that the randomly selected person is from a bus with x students is the proportion of students on that bus divided by the total number of students:

P(X=x) = (number of students on bus with x students)/(total number of students);

So, We have:

P(X=20) = 20/150 = 2/15

P(X=35) = 35/150 = 7/30

P(X=45) = 45/150 = 3/10

P(X=50) = 50/150 = 1/3

The expected-value of X is : E(X) = 20(2/15) + 35(7/30) + 45(3/10) + 50(1/3) = 41

To find the variance of X, we use the formula Var(X) = E(X²) - [E(X)]².

We already know E(X), so we need to find E(X²).

E(X²) = ∑ x² P(X=x);

So, We have:

E(X²) = 20²(2/15) + 35²(7/30) + 45²(3/10) + 50²(1/3) = 1780;

So, variance of X is : Var(X) = E(X²) - [E(X)]² = 1780 - 41² = 99.

Therefore, the expected value of X is 41 and the variance of X is 99.

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what are the equivalence classes of equivalance relation {(1, 1), (1, 4), (2, 2), (2, 5), (3, 3), (4,1), (4, 4), (5, 2), (5, 5)}?

Answers

The equivalence classes of the given equivalence relation are: {1, 4}, {2, 5}, and {3}. To determine the equivalence classes of the equivalence relation given by {(1, 1), (1, 4), (2, 2), (2, 5), (3, 3), (4,1), (4, 4), (5, 2), (5, 5)}, we need to identify all the pairs of elements that are related to each other.

Two elements are related if there is a pair (a, b) in the relation such that a is related to b. In this case, we can see that:

- 1 is related to 1 and 4
- 2 is related to 2 and 5
- 3 is related to 3
- 4 is related to 1 and 4
- 5 is related to 2 and 5

We can use these relationships to group the elements into equivalence classes. An equivalence class is a set of elements that are related to each other. In this case, we have the following equivalence classes:

- {[1, 4]}: This equivalence class contains the elements 1 and 4, which are related to each other.
- {[2, 5]}: This equivalence class contains the elements 2 and 5, which are related to each other.
- {[3]}: This equivalence class contains the element 3, which is related to itself.
- {[1, 4], [2, 5]}: This equivalence class contains the elements 1, 4, 2, and 5, which are all related to each other.
- {[1, 4], [2, 5], [3]}: This equivalence class contains all the elements, since they are all related to each other.

Each equivalence class contains elements that are related to each other, and no element in one equivalence class is related to any element in another equivalence class. These equivalence classes form a partition of the set of elements, since every element is contained in exactly one equivalence class.

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A random variable X has a normal distribution with mean 50 and variance of 10. Find the range of scores that lies
a. within two standard deviations from the mean
b. the lowest score which lies two standard deviations above the mean
c. the highest score which lies three standard
deviations below the mean.
handwritten pls, asap. will thumbs up if handwritten and correct

Answers

The range of scores that lies within two standard deviations from the mean is (43.68, 56.32), the lowest score which lies two standard deviations above the mean is 56.32, and the highest score which lies three standard deviations below the mean is 40.52.

The random variable X has a normal distribution with mean 50 and variance of 10. The standard deviation of X is the square root of the variance, which is √10 ≈ 3.16.

a. The range of scores that lies within two standard deviations from the mean is (50 - 2*3.16, 50 + 2*3.16) = (43.68, 56.32).

b. The lowest score which lies two standard deviations above the mean is 50 + 2*3.16 = 56.32.

c. The highest score which lies three standard deviations below the mean is 50 - 3*3.16 = 40.52.

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Tìm các giá trị của tham số m để hàm số đồng biến trên  .
1) 3 2 y x x m

Answers

Answer:

can you say it in english so i can help u

Step-by-step explanation:

difer from the true proportion by more than 2% ? A previous study indicates that the proportion of lefthanded sclontists is 9%. Round up to the nearest whicie number. Duestion 13 A. 1.218 B. 1,109 C. 14 D.767

Answers

The total number of samples will be 1109 .

Given ,

Margin of error 0.02

Here,

According to the formula,

\(Z_{\alpha /2} \sqrt{pq/n}\)

Here,

p = proportions of scientist that are left handed

p = 0.09

n = number of sample to be taken

Substitute the values,

\(Z_{0.01} \sqrt{0.09 * 0.91/n} = 0.02\\ 2.33 \sqrt{0.09 * 0.91/n} = 0.02\\\\\\\)

n ≈1109

Thus the number of samples to be taken will be approximately 1109 .

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which of the following features of the data displayed make the use of the bar graph less helpful for a comparison? responses the displayed spending is based on money for grassroots mobilization. the displayed spending is based on money for grassroots mobilization. the data would better fit a horizontal rather than a vertical presentation. the data would better fit a horizontal rather than a vertical presentation. the bar showing the spending for the chamber of commerce makes comparisons with the other groups more difficult. the bar showing the spending for the chamber of commerce makes comparisons with the other groups more difficult. the group or corporation that gave the most money between 1998 and 2014 is difficult to portray visually.

Answers

The bar showing the spending for the chamber of commerce makes comparisons with the other groups more difficult.

The structured presentation is a well known visual device for showing information and making correlations between various classifications or gatherings. Nonetheless, certain elements of the information can utilize a visual chart less supportive for correlations. For this situation, the bar showing the spending for the office of trade makes correlations with different gatherings more troublesome on the grounds that it is altogether bigger than different bars, which can make it harder to analyze the general sizes of different bars precisely.

Furthermore, the information would preferable fit a flat rather over an upward show, as this would consider a more clear representation of the information and more precise correlations between the various classifications.

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James paid 3.43 for 20 ml cleaning bottle. How much did he pay per millilitre?

estimate:

calculations:

Answers

Answer:

James is paying $0.17 per ml.

Step-by-step explanation:

To get this answer you divide the amount purchased by the amount spent: 3.43/20

This will give you 0.1715, which rounds down to 0.17 (which is 17 cents)

What is the distance between points A and E on the coordinate plane below? a : (4,3) e : (-5,3)​

Answers

Input Data :
Point 1
(
x
A
,
y
A
)
= (4, 3)
Point 2
(
x
B
,
y
B
)
= (3, -2)

Objective :
Find the distance between two given points on a line?

Formula :
Distance between two points =

(
x
B

x
A
)
2
+
(
y
B

y
A
)
2


Solution :
Distance between two points =

(
3

4
)
2
+
(

2

3
)
2

=

(

1
)
2
+
(

5
)
2

=

1
+
25

=

26
= 5.099
Distance between points (4, 3) and (3, -2) is 5.099

Question is in the images

Not all need to be used!

Question is in the imagesNot all need to be used!
Question is in the imagesNot all need to be used!

Answers

The two column proof is completed by

Statement                                            Justification

1. DE || KL                                        1. Given

2. < DFE ≅ < LF-K                            2. Vertical Angles Theorem

3. < DEF ≅ < LKF                            3. Alternate Interior Angles Theorem

4. Δ FDE ≅ Δ FLK                           4. AAS postulate

What is AAS postulate?

According to the AAS Postulate, triangles are congruent if two angles and the non-included side of one triangle are congruent with two angles and the non-included side of another triangle.

In the given problem the side is non included and the angels are congruent and hence completes the proof

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CAN SOMEONE PLEASE DO THE WORK FOR NUMBER 3 ILL MARK AS BRAINLIEST

CAN SOMEONE PLEASE DO THE WORK FOR NUMBER 3 ILL MARK AS BRAINLIEST

Answers

Answer:

I THINK its 1.5?

Answer:3/2

Step-by-step explanation:

hope this helps, LOOK AT THE PICTURE

CAN SOMEONE PLEASE DO THE WORK FOR NUMBER 3 ILL MARK AS BRAINLIEST

need help asap ! thanks

need help asap ! thanks

Answers

3.33 is the right answer
6 is the correct answer you have to combine like terms and take 16 out of the equation which leaves you with -6n=36 so if you change n to 6 it is 36

What is the perimeter of the figure below?*
2 in
9 in
2 in
11 in

Answers

Answer:24

Step-by-step explanation:

i think its right just try

si tardamos 20 minutos en recorrer una distancia a una velocidad de 40 km/h

1)cuanto tardaremos en recorrer dicha distancia si circulamos a 50 km/h
2) si la velocidad maxima en la zona es de 90 km/h a que porcentaje corresponden los 50 km/h?

porfa necesito el paso a paso :(

ya se q son inversas solo necesito el paso a paso

Answers

1) El vehículo tardará 14 minutos en recorrer la misma distancia a una rapidez de 50 kilómetros por hora.

2) La rapidez registrada equivale al 55.556 % de la velocidad máxima de la zona.

¿Cómo analizar móviles a rapidez constante?

1) En este problema tenemos el caso de un vehículo que se desplaza a rapidez constante. Aquí tenemos que la rapidez (v), en kilómetros por hora, es inversamente proporcional al tiempo invertido (t), en minutos.

[(40 km /h) / (50 km / h)] = t / 20 min

4 / 5 = t / 20

t = 80 / 5

t = 14 min

El vehículo tardará 14 minutos en recorrer la misma distancia a una rapidez de 50 kilómetros por hora.

2) El porcentaje correspondiente a la rapidez reportada se calcula mediante porcentajes:

r = [(50 km / h) / (90 km / h)] × 100 %

r = 55.556 %

La rapidez registrada equivale al 55.556 % de la velocidad máxima de la zona.

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Suppose that a researcher selects a sample of participants from a population. If the shape of the distribution in this population is negatively skewed, then what is the shape of the sampling distribution of sample variances

Answers

If the shape of the distribution in this population is negatively skewed, then the shape of the sampling distribution of sample variances is also negatively skewed.

The sampling distribution refers to the distribution of a statistic for all possible random samples drawn from the same population. The shape of the sampling distribution of the sample variance is related to the shape of the original population. The sample variance measures the amount of variation or dispersion within the sample.

The sampling distribution of sample variances is also known as the chi-square distribution. The distribution of sample variances approaches a chi-square distribution as the sample size increases. Therefore, if the shape of the distribution in this population is negatively skewed, the shape of the sampling distribution of sample variances is also negatively skewed.

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what is an equation of the line that passes through the point (6,8) and is perpendicular to a line with equation y

Answers

The equation of the line that passes through the point (6,8) and is perpendicular to a line is y = (-2/3)x + 12.

Given the equation, y= 3/2x + 5. Compare it with the general equation of the line,

y =  m₁   x + c₁

y= (3/2) x + 5

Therefore, the slope of the given line is m₁=(3/2).

Since it is needed to find the line that is perpendicular to y= 3/2x + 5, therefore, the slope of the two lines can be written as,

(Slope of line 1) × (Slope of line 2) = -1

m₁ × m₂ = -1

(3/2) × m₂ = -1

m₂ = -2/3

Now, the equation of the given line can be written as,

y = m₂x + c₂

y = (-2/3)x + c₂

Substitute the given coordinate in the above equation to get the value of y-intercept(c),

8 = (-2/3)6 + c₂

8 = -4 + c₂

c₂ = 8 + 4

c₂ = 12

Hence, the equation is y = (-2/3)x + 12.

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The complete question is:

What is an equation of the line that passes through the point (6, 8) and is perpendicular to a line with equation y=3/2x 5.

a certain statistic dˆ is being used to estimate a population parameter d. the expected value of dˆ is not equal to d. what property does dˆ exhibit?a. The sampling distribution of d hat is normal.b. The sampling distribution of d hat is binomial.c. The sampling distribution of d hat is uniform.d. d hat is unbiased.e. d hat is biased.

Answers

The right answer is: E, according to the Central Limit Theorem for proportionality. The statistic is inaccurate.

In probability theory, the central limit theorem establishes that, in many situations, when independent random variables are summed up, their properly normalized sum tends toward a normal distribution even if the original variables themselves are not normally distributed.

The Central Limit Theorem establishes that for a proportion p in a sample of size n:

The expected value is μ=р

The standard error is s=\(\sqrt{\frac{p(1-p)}{n} }\)

In this problem, the expected value is different of the expected of μ=р , hence, the statistic is biased, and the correct option is E.

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Clarie has $300 in an account. She decides she is going to take out half of what's left in there at the end of the month. (This is for geometric sequence, Math 1 btw and I gotta graph it)

Clarie has $300 in an account. She decides she is going to take out half of what's left in there at the

Answers

The expected money deposited in Clarie's account in next 12 months is listed below:

300 (Initial value)1507537.5018.759.384.692.341.170.590.290.140.07

How to derive and graph a geometric sequence

First, we must derive a formula that will generate the geometric sequence for the money remaining in Clarie's account:

\(c = c_{o}\cdot \left(1 + \frac{r}{100} \right)^{t}\)     (1)

Where:

\(c_{o}\) - Initial money deposited in Clarie's account.r - Decrease rate, in percentage.t - Number of periods, in months.

If we know that \(c_{o} = 300\) and r = - 50, then the money left for each month is shown in the image attached below.

Remark

The image quality is poor to the point of being very hard to read. However, it coincides with the complete statement, which is presented in the question.

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Clarie has $300 in an account. She decides she is going to take out half of what's left in there at the

Two angles form a linear pair. The measure of one angle is z and the measure of the other angle is 2.4 times z plus 10°. Find the measure of each angle.

Answers

Two angles form a linear pair.

so, the sum of the angles are 180

the measure of the angles are z and (2.4 * z + 10)

so,

z + (2.4 * z + 10) = 180

solve for z

so,

z + 2.4 * z + 10 = 180

3.4 z = 180 - 10

3.4 * z = 170

divide both sides by 3.4

so, z = 170/3.4 = 50

so, the angles are 50 and 130

Find the exact values of the six trigonometric functions functions of the angles 0 shown in the figure. Sin, cos, tan, csc, sec and cot (Use the pythagorean theorem to find the third side of the triangle)

Find the exact values of the six trigonometric functions functions of the angles 0 shown in the figure.

Answers

Answer:

\(undefined\)

Explanation:

Let x represent the length of the third side of the given triangle.

We can go ahead and determine the value of x using the Pythagorean theorem as seen below;

\(\begin{gathered} 41^2=x^2+40^2 \\ 1681=x^2+1600 \\ x^2=1681-1600 \\ x^2=81 \\ x=\sqrt[]{81} \\ x=9 \end{gathered}\)

So the length of the third side of the triangle is 9

We can now determine the value of sine theta as seen below;

\(\begin{gathered} \sin \theta=\frac{opposite\text{ side to angle }\theta\text{ }}{\text{hypotenuse}}=\frac{40}{41} \\ \therefore\sin \theta=\frac{40}{41} \end{gathered}\)

We can see that sine theta is 40/41

Let's determine the value of cosine theta as seen below;

\(\begin{gathered} \cos \theta=\frac{\text{adjacent side to angle }\theta}{\text{hypotenuse}}=\frac{9}{41} \\ \therefore\cos \theta=\frac{9}{41} \end{gathered}\)

So cosine theta is 9/41

Let's determine the value of tangent theta as seen below;

\(\begin{gathered} \tan \theta=\frac{opposite\text{ side to angle }\theta}{\text{adjacent side to angle }\theta}=\frac{40}{9} \\ \tan \theta=\frac{40}{9} \end{gathered}\)

So tangent theta is 40/9

Let's now determine the value of cosecant theta as seen below;

\(\begin{gathered} \csc \theta=\frac{1}{\sin\theta}=\frac{1}{\frac{40}{41}}=1\div\frac{40}{41}=1\times\frac{41}{40}=\frac{41}{40} \\ \therefore\csc \theta=\frac{41}{40} \end{gathered}\)

So the value of cosecant theta is 41/40

Let's determine the value of secant theta as seen below;

\(\begin{gathered} \sec \theta=\frac{1}{\cos\theta}=\frac{1}{\frac{9}{41}}=1\div\frac{9}{41}=1\times\frac{41}{9}=\frac{41}{9} \\ \therefore\sec \theta=\frac{41}{9} \end{gathered}\)

So the value of secant theta is 41/9

Let's determine the value of cotangent theta as seen below;

\(\begin{gathered} \cot x=\frac{1}{\tan x}=\frac{1}{\frac{40}{9}}=1\div\frac{40}{9}=1\times\frac{9}{40}=\frac{9}{40} \\ \cot x=\frac{9}{40} \end{gathered}\)

So the value of cotangent theta is 9/40

What percent of the forecasted high temperatures is greater than 52°F?​

Answers

The percent decrease in the high temperature from yesterday to today is 35%.

What is the percentage decrease?

To calculate the percent decrease in temperature from yesterday to today, we first need to calculate the actual decrease in temperature:

Actual decrease = Yesterday's high temperature - Today's high temperature

Actual decrease = 80°F - 52°F

Actual decrease = 28°F

The percent decrease can be calculated using the formula:

Percent decrease = (Actual decrease / Yesterday's high temperature) x 100%

Substituting the values, we get:

Percent decrease = (28°F / 80°F) x 100%

Percent decrease = 0.35 x 100%

Percent decrease = 35%

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The complete question is below:

Yesterday, the high temperature was 80 degrees Fahrenheit. Today,  the high temperature was 52°F. What is the percent decrease in the high temperatures from yesterday to today?

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Answers

Answer:

\(x^2+5x+4+\dfrac{3x-8}{x^2+5x-4}\)

Step-by-step explanation:

Long Division Method of dividing polynomialsDivide the first term of the dividend by the first term of the divisor and put that in the answer.Multiply the divisor by that answer, put that below the dividend and subtract to create a new polynomial.Repeat until no more division is possible.Write the solution as the quotient plus the remainder divided by the divisor.

The dividend is the polynomial which has to be divided.

The divisor is the expression by which the dividend is divided.

Given:

\(\textsf{Dividend:} \quad x^2+10x^3+25x^2+3x-24\)\(\textsf{Divisor:} \quad x^2+5x-4\)

Following the steps of long division, divide the given dividend by the divisor:

\(\large \begin{array}{r}x^2+5x+4\phantom{)}\\x^2+5x-4{\overline{\smash{\big)}\,x^4+10x^3+25x^2+3x-24\phantom{)}}}\\{-~\phantom{(}\underline{(x^4+\phantom{(}5x^3-\phantom{(}4x^2)\phantom{-b)))))))))}}\\5x^3+29x^2+3x-24\phantom{)}\\-~\phantom{()}\underline{(5x^3+25x^2-20x)\phantom{)))..}}\\4x^2+23x-24\phantom{)}\\-~\phantom{()}\underline{(4x^2+20x-16)\phantom{}}\\3x-8\phantom{)}\end{array}\)

The quotient q(x) is the result of the division.

\(q(x)=x^2+5x+4\)

The remainder r(x) is the part left over:

\(r(x)=3x-8\)

The solution is the quotient plus the remainder divided by the divisor:

\(\implies q(x)+\dfrac{r(x)}{b(x)}=\boxed{x^2+5x+4+\dfrac{3x-8}{x^2+5x-4}}\)

A shoemaker sold a pair of for $245.99 if the buyer a $300.00 bill, how much will the buyer receive in change?

*two decimal places don't forget your $ sign. Example: $50.00 NOT 50*

Answers

Answer:

$54.01

Step-by-step explanation:

All you have to do is $300.00-$245.99 .

It costs a company $20 per box to make pocket-sized stuffed animals. The company also has a fixed manufacturing cost of $2300. The owners are trying to calculate their cost for making boxes of animals.

Answers

there’s no question, but here’s the equation to use to solve.

y = 20x + 2300

y is the total cost, x is the amount of boxes made
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