What is the product of the following reaction?
(a) cyclohexane
(b) cyclohexene
(c) cyclohexanol
(d) 1,2-cyclohexanediol

Answer:

Explanation:

Branches or side chains are called alkyl radicals, they are named substituting the termination -ano for -yl or -il when it is part of a hydrocarbon.

Approximately 222.4 grams of oxygen reacted in the combustion process. To determine the amount of oxygen that reacted, we can use the balanced chemical equation for the combustion of hydrogen:

2H₂ + O₂ → 2H₂O

From the equation, we can see that 1 mole of oxygen reacts with 2 moles of hydrogen to produce 2 moles of water.

First, we need to convert the given masses of hydrogen and water into moles using their molar masses:

Molar mass of hydrogen (H₂) = 2 g/mol

Molar mass of water (H₂O) = 18 g/mol

Mass of hydrogen in moles = 27.8 g / 2 g/mol = 13.9 mol

Mass of water in moles = 249 g / 18 g/mol = 13.8 mol

Since the stoichiometry of the reaction tells us that 2 moles of hydrogen react with 1 mole of oxygen, we can calculate the moles of oxygen consumed as:

Moles of oxygen consumed = 13.9 mol / 2 = 6.95 mol

Finally, we can convert the moles of oxygen to grams using its molar mass:

Molar mass of oxygen (O₂) = 32 g/mol

Mass of oxygen consumed = 6.95 mol × 32 g/mol = 222.4 g

Therefore, approximately 222.4 grams of oxygen reacted in the combustion process.

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Answer:

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Answer:

Endothermic reaction.

Explanation:

The reactants have a lower energy than the products, so enegy was added to the system.  Ebdothermic reaction.  +ΔH.

Sucralose is present in the sample at a mass percent of 97.35 % and vitamin C at 2.65%

We can calculate the moles from osmotic pressure formula

Π = iMRT (Osmotic pressure) 

Van't Hoff factor i = 1

moles/volume = M

Now,

ππ= inVRT ——> (1)

R = 0.0821 L.atm.K.mol⁻¹

T = 301K

Volume = 28 ml, or 0.028 liters.

Next, using equation (1)

n = (π × 0.028 L) / (1× 0.0821 L.atmK⁻¹mol⁻¹× 301 K)

Mole = 0.00356 moles.

Given the quantity of samples and that sucralose has a mass of Y g and vitamin C has a mass of X g,

e = 1.371 g

X + Y = 1.371  g

Y = 1.371  g - X ----> (2)

The mass percent of vitamin c is 39.34 % and sucralose is 60.66 % in the sample.

Since vitamin C (VC) has a molecular mass of 176 g/mol while sucralose has a molecular weight of 398 g/mol. The sum of the moles of VC and sucralose is therefore the total amount of moles.

0.00356 moles = X/176 + (1.371 - X)/398

70,048(0.00356) = 398 X + 176(1.371 - X)

249.37 = 398 X +241.296 - 176 x

8.074 = 222x

X = 0.0364 gram (vit c)

Now, using eq (2);

Y =  1.371g - 0.0364 g

Y = 1.3346 gram (sucralose)

Thus, Vitamin C Mass Percentage is equal to 0.0364 g x 100 / 1.371g.

= 2.65%

Sucralose mass % =  1.3346g 100 / 1.371g

= 97.35 %

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The conclusion about the rates of the rotting reaction from the table would be that the reaction occurs more quickly when the concentration of salt is higher—option B.

The rate of reaction, or reaction rate, is the time it takes for a reaction to occur. In other words, it is the time it takes for the reactants of a reaction to become products.

In this case, the reactant is the rope and the product is the rotten product of the rope. From the table, it took 10 years for the rope to decay in a lake. On the other hand, it took the same rope just 4 years to decay in an ocean.

The difference between the two water bodies is the presence of salt. The lake has almost zero salt while the conentration of salt in the ocean water is high.

Thus, the conclusion about the rate of rotting reaction would be that the reaction is hastened by the presence of salt in the ocean water.

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Answer:

o sou imleyna leqro mueuto ajdairv  c aegra vamos loámas...i o

Explanationaer pgunta t:á incoplmeta

Answer:

non of them it is

halogen elements

Answer:

The answer is “They supported the use of radioactive elements for medical diagnostic purposes”.

Answer:

They supported the use of radioactive elements for medical diagnostic purposes.

Explanation:

(Its a recorded fact)

The carbon atoms are sp3 hybridized.

Hope this helps!

Answer:

Conduction

Explanation:

Conduction seems to be the mechanism whereby heat energy is transferred from adjacent molecules by interactions. In solids and liquids, where even the objects are near to each other, conduction happens more easily than in liquids, where even the molecules are farther separated.

Answer: 1. Endoplasmic Reticulum

Explanation:

it has passageways that carry proteins and other materials from one part of the cell to another

A Bronsted-Lowry acid is any species that may transfer a proton (H+) to another molecule. Any species that may take a proton from a different molecule is referred to as a Bronsted-Lowry base. Proton acceptors (PA) are Bronsted-Lowry bases, and proton donors (PD) are Bronsted-Lowry acids.

The connection it establishes between acids and bases is a crucial aspect of the Bronsted theory. There is a conjugate base for every Bronsted acid, and the opposite is true. A measure of an acid's strength is its Ka magnitude, while a measure of a base's strength is its conjugate base's Kb value.

The net-ionic equations of the following species which act as a Bronsted- Lowry acid are given as:

A. \(H_{3}O^{+} _{(aq)}\) ⇄ \(H^{+} _{(aq)} + H_{2} O_{(l)}\)

B. \(HCl_{(l)}\) ⇄ \(H^{+} _{(aq)} + Cl^{-} _{(aq)}\)

C. \(NH_{3(aq)}\) ⇄ \(H^{+}_{(aq)} + NH_{2} ^{-}\)

D. \(CH_{3}COOH_{(aq)}\) ⇄ \(H^{+} _{(aq)} + CH_{3}COO^{-}\)

E. \(NH_{4(aq)} ^{+}\) ⇄ \(H^{+}_{(aq)} + NH_{3} _{(aq)}\)

F. \(HSO_{4(aq)} ^{-}\) ⇄ \(H^{+} _{(aq)} + SO_{4}^{2-} _{(aq)}\)

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A double bond in a hydrocarbon chain of a fatty acid can influence the dispersion forces that can form between the hydrocarbon chains by decreasing the strength of the dispersion forces.

Dispersion forces, also known as van der Waals forces, are the weakest type of intermolecular forces that occur between molecules. These forces are caused by temporary dipoles that form when electrons in the molecules move around.

In a hydrocarbon chain with only single bonds, the chain is able to pack closely together, allowing for stronger dispersion forces between the chains. However, when there is a double bond present in the chain, it creates a kink or bend in the chain, preventing it from packing as closely with other chains. This decreases the strength of the dispersion forces between the chains.

Therefore, the presence of a double bond in the hydrocarbon chain of a fatty acid can decrease the strength of the dispersion forces between the chains, leading to weaker intermolecular forces and potentially different physical properties, such as a lower melting point.

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Dissolving sugar in water results in an increase in the entropy.

Hence, Option (D) is correct answer.

Measurement of randomness of a system is called entropy. It is an extensive property. It is a state function. Unit of entropy is JK⁻¹ mol⁻¹.

Now lets check all options one by one

Option (A): Freezing water

Freezing water decreases the entropy because here second law of thermodynamics does not violate.

So it is incorrect option

Option (B): Cooling water

Cooling water does not increases entropy because entropy increases when solid melts to give liquid.

So it is incorrect option

Option (C): Condensing water vapour

In Condensing water vapour the temperature of liquid phase decreases and thus kinetic energy decreases. The randomness will decrease and hence entropy will also decrease.

So it is incorrect option.

Option (D): Dissolving sugar in solute

In dissolving sugar in solute the solid dissociates to ions and  the randomness will increase and hence entropy will also increase.

So it is correct option

Thus from the above conclusion we can say that Dissolving sugar in water results in an increase in the entropy.

Hence, Option (D) is correct answer.

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Answer:

when we drink the milk the digestive system produce protease enzyme to break down the protein of milk.

The molarity (M) of a solution is 11.5 M that contains 0.75 moles of lithium fluoride, LiF in a 65 ml of solution.

Molarity (M) is defined as the number of moles of solute dissolved in 1L of solution. Molarity is also known as Molar concentration. The S.I Unit of Molarity is molar (M) or mol/L.

Molarity (M) = \(\frac{\text{Number of moles of solute}}{\text{Volume of solution (in liters)}}\)

From the above definition it is clear that the volume of solution is in liter. In question the volume of solution is given in ml.

So, convert 65 ml into l.

65 ml = \(\frac{65}{1000}\) = 0.065 l

Now, put the values in above formula, we get that

(M) = \(\frac{0.75}{0.065}\) = 11.5 M

Thus, the molarity of a solution is 11.5 M that contains 0.75 moles of lithium fluoride, LiF in a 65 ml of solution.

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Answer:

(i) In a bond amortization schedule, the book value represents the remaining amount of the bond principal that hasn't been paid off at a given point in time. When a bond is first issued, its book value equals its face value. As payments are made over the life of the bond, a portion of these payments reduces the book value. By the end of the bond's life, its book value will be zero, as the entire principal will have been paid off.

(ii) The formula for the book value B at time k, where k is the number of periods elapsed, is B = C + Cg - jan-kj.

Here:

- C is the redemption amount,

- g is the modified coupon rate per period,

- j is the yield rate per period, and

- a_n-kj is the present value of an annuity immediate with n - k periods at the yield rate j.

This formula states that the book value at any time k is the redemption amount plus the present value of the future coupon payments (Cg), minus the present value of the annuity that represents the repayments of the bond (jan-kj).

The amortized amount at time k is the change in the book value from time k-1 to time k, plus the coupon payment at time k. It represents the portion of the bond's principal (and interest) that has been repaid up to time k.

(iii) If K is defined as the present value of the redemption value C, according to the Makeham formula, (C-K) would represent the difference between the redemption value of the bond and its present value. This difference is the amount of interest that will accumulate over the life of the bond. In other words, (C-K) can be interpreted as the total interest that the bondholder will earn from holding the bond until redemption, assuming that all coupon payments are reinvested at the yield rate j.

Explanation:

To clean powder fouling, corrosion, and dirt from outside parts of the lower receiver and extension assembly, one should use the best quality cleaning materials and methods.

Powder fouling, corrosion, and dirt can accumulate on the outside parts of the lower receiver and extension assembly, making it hard to maintain the rifle. It is essential to clean the weapon regularly to maintain its efficiency and longevity.

The following cleaning materials are required for the cleaning process:

Cleaning solvent

Cleaning brush

Microfiber cloth

Lubricant

The best solvent to use when cleaning the rifle is a powder solvent. This is because it is specifically designed to remove fouling from firearms. It is also essential to use a cleaning brush made of brass, nylon, or synthetic material to avoid damaging the parts of the lower receiver and extension assembly.

Brass brushes are best for removing fouling, while nylon and synthetic brushes are gentle on the metal parts and help prevent corrosion. Avoid using a steel brush when cleaning the rifle since it may scratch or damage the surface of the metal.Lubricant is also essential in maintaining the rifle. It helps keep the moving parts smooth and minimizes friction between metal parts.

A high-quality lubricant should be used, and the excess should be wiped off with a microfiber cloth. To clean the weapon, apply the cleaning solvent onto the brush and scrub the outside parts of the lower receiver and extension assembly, then wipe it off with a microfiber cloth. Ensure the surface of the metal parts is dry before applying lubricant. Apply lubricant to moving parts of the weapon.

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Answer:

B. Cutting the supplies of oxygen

Ivan Pavlov is most known for demonstrating conditioned lreflex in dogs.

Conditioned reflex is a reflex action which has been conditioned to occur even without the stimulus which produces the reflex.

Ivan Pavlov is known to demonstrate conditioned reflex in dogs.

In his experiment, he trained dogs to salivate at the sound of a bell even if food which is the stimulus that produces salvation was not present.

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Answer:

A conditioned reflex is a reflex action that has been trained to occur even when the stimulus that causes the reflex is not present.

Ivan Pavlov is recognized for using dogs to illustrate conditioned reflexes.

He trained dogs to salivate at the sound of a bell even when food, the stimulus that induces salvation, was not present in his experiment.

Explanation:

The safety symbols which would be on an agar plate of bacteria culture are BSL1 or BSL2.

This is referred to as a method in which microbial organisms are multiplied by letting them reproduce in a predetermined culture medium such as nutrient agar etc under standard laboratory conditions based on the parameters involved.

BSL1 or BSL2 are both referred to as biosafety levels and they are known as set of established standards which must be followed in the safe handling of biological material which is therefore the reason why it was chosen as the correct choice.

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Answer: 300 goats want get food

Explanation:

Answer: B: Polarity

Explanation:

Answer:

It can be chemically separated if it is a compound. The gas carbon dioxide is a pure substance.

Explanation:

Carbon dioxide is a pure substance because it has a fixed composition no matter where it was taken. Each molecule of carbon dioxide will always have 1 carbon and 2 oxygens.

Answer:

28 g CO

Explanation:

First convert grams to moles.

1 mole C = 12.011 g (I'm just going to round to 12 for the sake of this problem)

12 g C • \(\frac{1 mol C}{12 g C}\) = 1 mol C

1 mol O = 15.996 g (I'm just going to round to 16)

16 g O • \(\frac{1 mol O}{16 g O}\) = 1 mol O

So the unbalanced equation is:

\(C + O_{2}\) -> \(CO\) (the oxygen has a 2 subscript because it is part of HONClBrIF meaning when not in a compound these elements appear in pairs - called diatomic elements)

The balanced equation is:

\(2 C + O_2\) -> \(2 CO\)

However, carbon is the limiting reactant in this equation and two moles cannot react because only 12 g (1 mole) are present. Therefore, use the equation

\(C + \frac{1}{2} O_2\) -> \(CO\).

1 mole of CO is formed, therefore 12 g + 16 g = 28 g CO.

Answer:

yes because on the left side 4 hydrogen in right side 4 hydrogen on the left side 2 oxygen in the right side 2 oxygen

Answer:

The Law of Conservation of Mass states that the mass of the system must remain constant over time as the system's mass cannot change because energy is not created nor destroyed. To tell if a chemical equation meets this law, check to see if the number of atoms is the same on both sides of the chemical equation.

Reactant Side:

Product Side:

Remember, when counting the atoms in a equation the subscript is the number that represents the quantity of that specific atom. Subscripts are numbers that come after a symbol and below. If an element does not have a subscript, then it is understood that the subscript is 1.  The coefficent represents the quantity of molecules, the coefficient multiplies everything in the formula.

Answer:

Explanation:

\(\mathrm {Hey, there!}\)

Let's solve your problem -

The answer to the question is 4.18 10^7.

Here is my clarification/explanation to support:

To convert a standard number to scientific notation, we have to move the decimal point up until we have a 1 digit number.

When we keep moving the decimal point, we get 4.18

Now, we will count the numbers after the 8 to get the 10 area.

There are five numbers after the 8, so we get 10^5.

Now, we will add 2 more to the 5, we get 10^7

Our answer will be: 4.18 10^7

\(\mathrm {Best, of, Luck!}\)