What is the pseudoformula of ascorbic acid, given that ascorbic acid contains 3. 407 mol of carbon, 4. 53 mol of hydrogen, and 3. 406 mol of oxygen?.

Answer:

The major potential environmental impacts associated with mining and associated mineral processing operations are related to erosion-prone landscapes, soil and water quality, and air quality.

Explanation:

Plants were native to the mining site and making sure the soil is healthy are the examples of environmental concerns taking into account by a mining company when it created a reclamation plan for a mine site.

Land use may change as a result of mine exploration, construction, operation, and maintenance.

It may also have detrimental effects on the environment, such as deforestation, erosion, contamination of nearby streams and wetlands, alteration of soil profiles, increased noise levels, and dust.

Mining is a naturally invasive operation that can alter the landscape over a much wider region than the actual mining site.

Therefore, years after a mine closes, the impacts of this harm can still be felt, adding to greenhouse gas emissions, causing flora and fauna to die, and eroding the land and environment.

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Answer:

this

Explanation:

Molar mass also called Atomic mass is the atomic weight. You can find this on the periodic table.

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The answer would be

A. the mass in grams of one mole of a substance

The type of object that completely absorbs white light would be a black piece of paper. First option.

Black bodies are objects that completely absorb all the components of white light.

White light is a mixture of different colors of light, each with a different wavelength and frequency.

When white light strikes a black body, the black body absorbs a large fraction of all the different colors, regardless of their wavelength. This absorption causes the light to be transformed into thermal energy, which increases the temperature of the black body.

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Answer: 70 percent

About 97 percent of Earth's water is in the ocean.

The ocean covers more than 70 percent of the surface of our planet. It's hard to imagine, but about 97 percent of the Earth's water can be found in our ocean. Of the tiny percentage that's not in the ocean, about two percent is frozen up in glaciers and ice caps.

Hope this helps...... Stay safe and have a Merry Christmas!!!!!!!!!!! :D

Explanation:

Answer:

it is a result of hydrogen bonds present within water molecules.

Explanation:

when the water is transformed to ice at zero degrees Celsius, the water molecules are in crystal lattice in a structure that has a lot of empty space around each molecule.

Answer:

The answer in this question is show you made Sodium Hydroxide and Hydrogen Gas.In order to do the products of the reaction relate to the phenol red test and the splint test you need to show that you made Sodium Hydroxide and Hydrogen Gas. Show that you made Sodium Hydroxide and Hydrogen Gas so that the products of the reaction relate to the phenol red test and the splint test.

use dimensional analysis and set up your equation like so:

\(=220g\ x\ \frac{cm^3}{55g}\)

the unit grams would cancel which leaves the unit of cm³, which is the unit for volume in this case.

The volume of 220g of an object with a density of 55g/cm³ is 4 cm³.

Answer:

6.02*10^6 is ans

it mean (1)is correct

the value of pBa is approximately 1.66.

Volume of 0.1 M EDTA solution = 75.00 mL

Volume of 0.1 M Ba2+ solution = 50.00 mL

alpha(Y4+) = 0.30 (fraction of EDTA that forms the Y4- complex)

Kf = 7.59 × 10^7 (formation constant for BaY2- complex)

First, let's calculate the moles of EDTA and Ba2+ in the solutions:

Moles of EDTA = (Volume of EDTA solution in L) * (Concentration of EDTA)

= (75.00 mL / 1000 mL/L) * 0.1 M

= 0.0075 mol

Moles of Ba2+ = (Volume of Ba2+ solution in L) * (Concentration of Ba2+)

= (50.00 mL / 1000 mL/L) * 0.1 M

= 0.0050 mol

Next, we determine the moles of BaY2- complex formed by reacting Ba2+ with EDTA:

Moles of BaY2- = alpha(Y4+) * Moles of EDTA

= 0.30 * 0.0075 mol

= 0.00225 mol

Since the stoichiometric ratio between Ba2+ and BaY2- is 1:1, the concentration of Ba2+ remaining in solution is equal to the concentration of Ba2+ initially minus the moles of BaY2- formed:

Concentration of Ba2+ remaining = (Moles of Ba2+ - Moles of BaY2+) / (Total volume of solution in L)

= (0.0050 mol - 0.00225 mol) / (0.075 L + 0.050 L)

= 0.00275 mol / 0.125 L

= 0.022 M

Finally, we can calculate pBa by taking the negative logarithm (base 10) of the concentration of Ba2+ remaining:

pBa = -log10(Concentration of Ba2+ remaining)

= -log10(0.022)

≈ 1.66

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Answer:

5,73mol

Explanation:

N=n*Na

3.45*10^24=n*6.02*10^23

n=\(\frac{3.45*10^{24}}{6.02*10^{23}}\)

n=5,73mol

The presented statement states that 52.5 lbs. of salt had been consumed after 30 minutes.

Salts come in a variety of forms, such as a double salt, corrosive salt, or basic salt. A salt that forms when a potent acid and a feeble base interact is referred to as a "acidic salt."

There seem to be initially 100 gal with in tank. The amount of salt is 60 lbs. The tank has a salt content of 60/100, or 0.6 pounds per gal.

One pound per gallon of water is coming in.

Because the combination is continually varying, the concentration of the water that comes out is uncertain.

Each minute, the tank is dropping 1 gal. (3-2=1)

Utilize this information to configure three functions for volume, saturation, and salt content: V(t), S(t), and C(t).

V (t) = 100 - t

s (t) = 60 plus 2t - 3t * C (t)

C (t) = s(t)/V(t) = 60 + 2t - 3t * C(t)/ 100 - t

Solve for C with a little mathematics (t)

C (t) = 60 + 2t / 100 + 2t

Now, we are aware of the tank's salt content at all times.

Evaluate at t = 30

C (30) = 60 + 2(30)/100 - 2(30) = 120/160 = 3/4

s(30) = 60 + 2(30) - 3(30)(3/4) = 120 - 90(3/4) = 52.5

Consequently, 52.5 lbs of salt had been consumed within 30 minutes.

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d5 electron count can exhibit both high-spin and low-spin states in an octahedral complex

Electron is a free, open-source software framework developed and maintained by GitHub. This framework is designed to build desktop applications using web technologies rendered using a variant of the Chromium browser engine and a backend using the Node.js runtime environment.

Electrons are negatively charged subatomic particles that are free to (not) bond with atoms. Electrons bound to atoms are one of the three main types of particles within atoms. The other two are protons and neutrons. Electrons, protons, and neutrons together form the nucleus.

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Answer:

53.4%

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

N2 + 3H2 —> 2NH3

Next, we shall determine the mass of H2 that reacted and the mass of NH3 produced from the balanced equation. This is illustrated below:

Molar mass of H2 = 2 × 1.01 = 2.02 g/mol

Mass of H2 from the balanced equation = 3 × 2.02 = 6.06 g

Molar mass of NH3 = 14 + (3×1.01)

= 14 + 3.03

= 17.03 g/mol

Mass of NH3 from the balanced equation = 2 × 17.03 = 34.06 g

Summary:

From the balanced equation above,

6.06 g of H2 reacted to produce 34.06 g of NH3.

Next, the shall determine the theoretical yield of NH3. This can be obtained as follow:

From the balanced equation above,

6.06 g of H2 reacted to produce 34.06 g of NH3.

Therefore, 26.3 g of H2 will react to produce = (26.3 × 34.06)/6.06 = 147.82 g of NH3.

Thus, the theoretical yield of NH3 is 147.82 g

Finally, we shall determine the percentage yield of NH3. This is illustrated below:

Actual yield = 79 g

Theoretical yield = 147.82 g

Percentage yield =.?

Percentage yield = Actual yield /Theoretical yield × 100

Percentage yield = 79/147.82 × 100

Percentage yield of NH3 = 53.4%

Answer:

The answer is D(53.4%)

Explanation:

Just took test hopes this help

The equilibrium vapor pressure with respect to water (eow) is 259.9 Pa. assume that saturation vapor pressure is same as equilibrium vapor pressure.

Therefore, the RH at the frost point is  

RH = (eow / saturation vapor pressure) × 100

= (259.9 Pa / 259.9 Pa) × 100

= 100%

b) At T = -11 °C, we need to compare the equilibrium vapor pressure with respect to water (eow) and the equilibrium vapor pressure with respect to ice (coi) to determine if ice particles will form. From the given table, at T = -11 °C, the equilibrium vapor pressure with respect to water (eow) is 237.7 Pa, and the equilibrium vapor pressure with respect to ice (coi) is 165.3 Pa.

The air is supersaturated with respect to ice, and the presence of Kaolinite particles can provide surfaces for water droplets to condense onto, leading to the formation of ice particles.

c) At T = -12 °C, we compare the equilibrium vapor pressure with respect to water (eow) and the equilibrium vapor pressure with respect to ice (coi). From the given table, at T = -12 °C, the equilibrium vapor pressure with respect to water (eow) is 217.3 Pa, and the equilibrium vapor pressure with respect to ice (coi) is 181.2 Pa.

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Explanation:

obviously true the gravity of moon is 1/6th of the Earth

Answer:

Hello

please make sure that there is any group which is join with alkane

Based on Lana's diagram, the correct statement that explains the results of asexual reproduction is C. The offspring are genetically identical to the parent, because each offspring receives a complete copy of a single parent's chromosomes.

In the diagram, the parent cell divides into two identical daughter cells, each of which contains a complete copy of the parent cell's genetic material.

This type of reproduction, where a single parent produces offspring that are genetically identical to itself, is called asexual reproduction. It is the process by which many unicellular organisms, such as bacteria and some protists, reproduce.

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We collected the evidence that air has mass through balloon balance experiment . We also got the evidence that the Compressed air weighs more than atmospheric air.

All types of gases consist of a certain amount of mass depending upon its amount present in a particular substance or container .Gases are invisible to the human eye but we feel them through our skin because of the pressure they exhibit.

We can prove that the air has mass by performing a simple science experiment that is the balloon balance science experiment.

Take a simple balance machine and tie equal sized inflate balloons on either side of its lever. You will observe both the balloons hang at the same height from the ground. Now, blast any one of the inflated balloon through a syringe and observe that the lever on the deflated balloon side tilts and moves upwards. While the inflated balloon still goes down because it has air which reveals  mass. In this way we can prove that air has mass.

Or we can calculate mass of a gas through ideal gas equation   PV=nRT

Compressed air exhibits weight more than the surrounding air moving freely outside through balloon balance experiment. Let us see how much weight it reveals.

Compressed air weighs more than atmospheric air and hence a certain amount of compressed air weighs more than the same amount of regular gas.

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this question answer is true

Answer:

true

Explanation:

it's true....independent variable is what is changed by the experimenter

Answer:

A cloud occurs when evaporated water condenses into visible water or ice. The three factors required in forming a cloud include: moisture, condensation, and temperature.

Explanation:

To calculate the temperature needed to change 75 liters at 27°C to 105 liters, the information about the pressure is required. Please provide the constant pressure value for an accurate calculation.

To calculate the temperature needed to change the volume of a gas from 75 liters at 27°C to 105 liters while keeping the pressure constant, we need to use the ideal gas law. The ideal gas law states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature.

Since the pressure is constant throughout the experiment, we can rewrite the ideal gas law as V1/T1 = V2/T2, where V1 and T1 are the initial volume and temperature, and V2 and T2 are the final volume and temperature.

Plugging in the values, we have:

V1 = 75 liters

T1 = 27°C + 273.15 (converted to Kelvin)

V2 = 105 liters

T2 = ?

Using the equation V1/T1 = V2/T2, we can rearrange it to solve for T2:

T2 = (V2 * T1) / V1

Substituting the values, we can calculate the temperature T2 needed to change the volume from 75 liters at 27°C to 105 liters.

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If we add 25.6 g of an unknown molecular compound to the 0.250 kg of benzene, the molar mass of the unknown compound is 148.8 g/mol.

The Molality of the compound is given as :

ΔT = i Kf m

Where,

ΔT = freezing point depression = 3.54 °C

i =  Van't Hoff factor of the Benzene = 1

Kf =  constant of the freezing = 5.12 °C/m

m = molality = ?

m = ΔT / i Kf

m = 3.54 / 1 × 5.12

m = 0.69 mol

molality = moles / mass of benzene

moles = 0.172

The molar mass = mass / moles

The molar mass = 25.6 / 0.172

The molar mass = 148.8 g/mol

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Answer:

133.85 K

Explanation:

Initial pressure, P₁ = 635 torr

Initial temperature, T₁ = 67.0°C = 340 K

Final pressure, P₂ = 250 torr

We need to find the new temperature. The relation between temperature and pressure is given by :

\(\dfrac{P_1}{T_1}=\dfrac{P_2}{T_2}\\\\T_2=\dfrac{P_2T_1}{P_1}\\\\T_2=\dfrac{250\times 340}{635}\\\\T_2=133.85\ K\)

So, the new temperature is equal to 133.85 K.

Answer: A

Explanation:

Answer:

The answer is A

Explanation:

The risk assessment team, consisting of various members from different departments within the winery, conducted a comprehensive assessment of the potential risks associated with sulfur dioxide (SO2) and dimethyl dicarbonate (DMDC) operations.

Data was collected regarding the equipment, chemicals, procedures, training, incident history, and physical attributes of the workplace. The team also interviewed employees to gather their experiences, concerns, and suggestions.

After reviewing the collected information, the team identified the potential risks of fatalities or serious incidents related to workplace exposures of SO2 and DMDC. These risks were considered of utmost priority and required immediate control to ensure an acceptable level of safety. The consultant highlighted the importance of addressing these serious risks, as fatality and serious incident rates have not shown a decline and demand serious attention.

Factors contributing to the potential for environmental releases, explosions, and disasters were identified, including unusual and nonroutine work, nonproduction tasks, facility modification or construction activities, shutdowns and startups for repair and maintenance tasks, exposure to high-energy sources (such as electrical, steam, pneumatic, chemical), and situations transitioning from normal to abnormal (upsets).

Based on the assessment and the identified risks, it is crucial for the winery to implement effective control measures to minimize the potential for fatalities, serious incidents, and environmental disasters. These measures may include improving procedures, enhancing operator training, implementing stricter safety protocols, and ensuring proper handling and storage of chemicals.

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Answer:

The final velocity of the motorcycle is 64.7 m/s

Note: Since the value for the acceleration of the motorcycle is not clear, it is assumed to be 4.55 m/s² in the calculation

Explanation:

Using the equation of motion that contains all the given values in the question: v² = u² + 2as

where v is final velocity; u is initial velocity; a is acceleration; s is horizontal distance

v = ?, u = 0 (since the motorcycle starts from rest), a = 4.55 m/s², s = 460 m

v² = 0² + 2 * 4.55 * 460

v² = 4186

take square root of both sides

v = 64.7 m/s

Therefore, the final velocity of the motorcycle is 64.7 m/s

The automobile gasoline tank will hold 59.05 pounds of gasoline.

Given that the volume of the gasoline tank of the automobile is 19.0 gal. and the density of the gasoline is 0.737 g/mL. So, we need to calculate the number of pounds of gasoline the tank can hold.The relationship between volume and density is as follows;Density= Mass/ VolumeRearranging the equation gives; Mass= Density × VolumeSubstitute the given values in the above equation;Mass = 0.737 g/mL × 19.0 gal × 3.78541 L/galWe know that; 1 L = 1 dm³Thus,Mass = 0.737 g/mL × 19.0 gal × 3.78541 dm³/LMass = 53.70 kgThe given mass is in kg and we need to convert it into pounds;1 kg = 2.20462 poundsThus,Mass = 53.70 kg × 2.20462 pounds/kgMass = 118.4 pounds therefore, the automobile gasoline tank will hold 59.05 pounds of gasoline.

Given that the volume of the gasoline tank of the automobile is 19.0 gal. and the density of the gasoline is 0.737 g/mL. So, we need to calculate the number of pounds of gasoline the tank can hold.The relationship between volume and density is as follows;Density= Mass/ VolumeThe above equation can be rearranged as; Mass= Density × Volume Substitute the given values in the above equation;Mass = 0.737 g/mL × 19.0 gal × 3.78541 L/galMass = 53.70 kgThe given mass is in kg and we need to convert it into pounds;1 kg = 2.20462 poundsThus,Mass = 53.70 kg × 2.20462 pounds/kgMass = 118.4 pounds therefore, the automobile gasoline tank will hold 59.05 pounds of gasoline.

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