what is the range of f(x)=-3'x-1​

Answer:

10 pounds of potatoes would cost $15.

Step-by-step explanation:

Set up proportion.

4/6=10/x

simplify 4/6 into 2/3,

2/3=10/x

cross product,

2*x=3*10

2x=30

x=30/2

x=15

lemme just add some to the great reply above,

\(\begin{array}{ccll} lbs&\$\\ \cline{1-2} 4&6\\ 10&x \end{array}\implies \cfrac{4}{10}=\cfrac{6}{x}\implies 4x = 60\implies x = \cfrac{60}{4}\implies x = 15\)

Answer:

hope this helps and have a great dayyyyyy

Answer:

less

Step-by-step explanation: 71.6 can also be seen as 71.60 therefore 71.63 is greater

Answer:

Less than.

Think of .6 as the tenths place to tens place.

.63 is 6 tenths and 3 hundredths, so 63.

Now ask yourself, "Is 63 greater than 60?"

And your answer is yes.

Answer:

620. 0.25 x 620 = 155

As the number of successful bit transmissions in a sequence of 10 bits sent over the internet. Then x follows a binomial distribution with parameters n=10 and p=0.5.

The binomial distribution models the number of successful outcomes in a fixed number of independent Bernoulli trials, where each trial has only two possible outcomes: success or failure. In this case, the number of trials is 10 (n=10) and the probability of success in each trial is 0.5 (p=0.5).

Since each bit transmitted over the internet can be considered a Bernoulli trial, it follows that the number of successful transmissions (x) follows a binomial distribution with parameters n=10 and p=0.5.

These properties make the binomial distribution a useful model for situations where the number of trials is fixed, each trial is independent, and each trial has only two possible outcomes.

In the example of sending bits over the internet, each bit transmission can be considered a Bernoulli trial, so the number of successful transmissions follows a binomial distribution.

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Answer:

The answer is -6.

Step-by-step explanation:

0^2 = 0

5(0) = 0

0+0-6=-6

Answer:

-2(6-3x)=-12+6x

Step-by-step explanation:

If you do the distributive property first and look at the other side of the = sign they are the same, which means that the answer would be x=x, which isn't a solution.

Answer:

I take it that we solve for x and y, so we have

3x + y = 4, so we have y = 4 - 3x

and plug that in to

8x + 2y = 10

8x - 6x + 8 = 10

so

2x = 2

x = 1

y = 4 - 3

y = 1

Answer:

r=c/21

Step-by-step explanation:

The solution of given system of equations is (1/5, 6).

What is system of equation?

A set or group of equations that you solve all at once is referred to as a "system" of equations. The simplest linear system is one with two equations and two variables. Linear equations are simpler than non-linear equations because they graph as straight lines.

Given equations : 5x+y=7

                             20x+2=y

We can solve it by using substitution method:

Now, we have 5x+y=7

it can be written as,

         y = 7 - 5x .... equation 1

Similarly, we have 20x+2=y

can be written as,

           y = 20x+2 ..... equation 2

Subtracting equation 1 from equation 2

we get,  20x+2 - ( 7 - 5x ) = 0

             20x + 5x + 2 - 7 = 0

             25x = 5

               x = 1/5

Putting x=1/5 in equation 1,

we get, y = 20 × 1/5 + 2

               = 4 +2

               = 6

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Using proportions, the property tax on a house with an assessed value of $762,000 is of $8,890.

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

The tax rate, as a proportion, is:

7280/624000 = 0.011667.

Hence, the property tax on a house with an assessed value of $762,000 is of:

0.011667 x 762,000 = $8,890.

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Answer:

B

Step-by-step explanation:

a function happens when there is exactly one output given for every input

Answer:

No.

Step-by-step explanation:

Insert the x and y, (-5 is x and 6 is y) into the equation. It should look like 4(-5)+3(6)=9. 4(-5)=-20 and 3(6)=18. -20+18=2 not 9.

(hope this helps :P)

Answer:

Nope

Step-by-step explanation:

Insert (-5,6) to the problem:

4(-5) + 3(6) = 9

-20 + 18 = 9

-2 = 9

(-5,6) is not the solution.

Answer:

Step-by-step explanation:

First we are going convert 6 hours to minutes and then seconds

1 hour= 60 mins

6 hours= 6 multiply by 60

           = 360 mins

1 min= 60 secs

360mins to seconds= 360 multiply by 60

                                  =21600

Answer:

x=8

Step-by-step explanation:

80=3x+2(5x-12)

80=3x+2(5x)+2(-12)

80=3x+10x-24

80=13x-24

104=13x

x=104/13

x=8

If this helps please mark as brainliest

Answer:

n = (-44/9) or \(-4 \frac{8}{9}\)

Step-by-step explanation:

n – 2 = 10n + 42

-n          - n

-2 = 9n + 42

-42        - 42

-44 = 9n

-44/9 = n

Answer:

Step-by-step explanation:

n-2= 10n+ 42

+2             +2

n     =    10n + 44

-10n     -10n

-9n = 44

/-9      /-9

n = -4.8

The probability of the event between two and five lines, inclusive, are in use is 0.85.

Probability can be defined as the ratio of the number of favourable outcomes to the total number of outcomes of an event.

Given that,

x         0         1         2       3        4         5         6

p(x)   0.12    0.18   0.20  0.20  0.20   0.07   0.03

a) At most three lines are in use

Here we need to find the probability for x≤3.

P(x≤3)=P(x=0)+P(x=1)+P(x=2)+P(x=3)

= 0.12+0.18+0.20+0.20

= 0.70

b) Fewer than three lines are in use

Here we need to find the probability for x<3.

P(x<3)=P(x=0)+P(x=1)+P(x=2)

= 0.12+0.18+0.20

= 0.50

c) At least three lines are in use

Here we need to find the probability for x≥3.

P(x≥3)=P(x=3)+P(x=4)+P(x=5)+P(x=6)

= 0.20+0.20+0.07+0.03

= 0.50

d) Between two and five lines, inclusive, are in use

Here we need to find the probability for 2≤x≤5.

P(2≤x≤5)= P(x=2)+P(x=3)+P(x=4)+P(x=5)

= 0.18+0.20+0.20+0.20+0.07

= 0.85

Therefore, the probability of the event between two and five lines, inclusive, are in use is 0.85.

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Answer:

Step-by-step explanation: To find the x let y=0

We substitute into the equation 3x+2y=15

3x+2 *0=15

3x=15

x=15/3=5

To find the y let x=0

we substitute into the equation x =0

3*0+2y=15

2y=15

y=15/2

Answer:

,,,,,,,,,,,,,,,,,,,,,,,

Answer:

-1 11/40

Step-by-step explanation:

-51/40 this is simplest form.

Step-by-step explanation:

Answer:

8/12

Step-by-step explanation:

Answer:

49 pieces

Step-by-step explanation:

1. convert 12.25m into cm (1225 cm)

2. divide 1225cm by 25 = 49

In golf, players use the concept of angles to evaluate their club head position and the angle of attack on the ball. By understanding the principles of geometric angles, golfers can adjust their swing and improve the accuracy and distance of their shots.

In basketball, players use the concept of spatial awareness to evaluate their positioning on the court. By understanding geometric concepts such as lines, angles and planes, they can improve their ability to move without the ball and find open spaces on the court.

In soccer, players use the concept of geometric shapes to evaluate their positioning on the field. By understanding the principles of triangles and circles, soccer players can improve their ability to move and pass the ball effectively, as well as to anticipate the movements of the opposing team.

Overall, the concepts of geometry, such as angles, spatial awareness, and geometric shapes, are essential for athletes in many sports to evaluate their positions and postures and improve their performance.

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Answer:

(x-1)(x+6)

Step-by-step explanation:

=> \(x^2+5x-6\)

Using mid-term break formula to find it's factors

=> \(x^2+6x-x-6\)

=> x(x+6)-1(x+6)

Taking x+6 common

=> (x-1)(x+6)

Answer:

Tennnnnnnnnnnnn.............

5th term of the sequence is -4

To find the 5th term in the sequence, we need to substitute n =  5 into the expression given

 \(a_5\) =  26- 6( 5)  

\(a_5\) =  26- 30

\(a_5\) = -4  

The formula given, an =  26- 6n, represents an  computation sequence with a common difference of-6.

This means that each term in the sequence is  attained by obtain 6 from the  former term.  

It's important to note that the formula is written in general form, meaning that it can be used to find any term in the sequence by simply plugging in the  matching value of  n.

 In this case, we were asked to find the 5th term, so we substituted n =  5 into the formula to get a5 = -4.

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A. The data is a random sample from the population of interest.

C. Individual observations can be considered independent.

B. The sampling distribution of is approximately normal.

What is the sampling distributions?

In statistics, the sampling distribution refers to the probability distribution of a statistic based on a random sample from a population. The sampling distribution is a theoretical concept that describes the distribution of values that the statistic would take across all possible samples of the same size from the population.

A and C are the conditions that have been met:

A. The data is a random sample from the population of interest.

C. Individual observations can be considered independent.

The condition that has not been met is:

B. The sampling distribution of is approximately normal.

Since the distribution of page lengths is skewed to the right with high outliers, the assumption of normality is not satisfied. Therefore, a t interval may not be appropriate for constructing a confidence interval for the mean page length. Alternative methods, such as a bootstrap or a nonparametric interval, may be more appropriate in this case.

Hence,

A. The data is a random sample from the population of interest.

C. Individual observations can be considered independent.

B. The sampling distribution of is approximately normal.

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The equation explaining the relationship between line segment AC and line segment A"C" is: y_A"C" = y_AC.

To determine the relationship between line segment AC and line segment A"C" in the given transformation, let's consider the properties of translation and dilation.

Translation:

A translation moves an object in a specific direction by a given distance. In this case, the translation (x + 0, y + 2) means that every point of the original triangle A'B'C' is shifted vertically upward by 2 units. So, A' becomes A" when shifted vertically by 2 units.

Dilation:

A dilation scales an object by a certain factor while keeping the same center of dilation. The scale factor of 2 means that every point is multiplied by 2 in both the x and y coordinates. Since the center of dilation is the origin (0, 0), the origin remains fixed.

Considering these transformations, we can deduce the following:

1. Translation: (x, y) ⟼ (x, y + 2)

2. Dilation: (x, y + 2) ⟼ (2x, 2(y + 2))

Applying the dilation to the translated point A", we get:

A" = (2x, 2(y + 2))

Now, we can determine the equation that relates line segment AC and line segment A"C" by comparing their coordinates:

The coordinates of A are (x, y), and the coordinates of C are (0, y) since it is a vertical line segment.

The coordinates of A" are (2x, 2(y + 2)), and the coordinates of C" are (0, 2(y + 2)).

The slope between A and C is given by:

m_AC = (y - (y + 2)) / (x - 0) = -2 / x

The slope between A" and C" is given by:

m_A"C" = (2(y + 2) - (2(y + 2))) / (2x - 0) = 0

Since the slope between A" and C" is zero, it indicates that line segment A"C" is a horizontal line. There is no change in the y-coordinate, implying that the y-value of A" and C" remains the same.

In other words, the y-coordinate of A"C" is equal to the y-coordinate of AC.

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The probable question may be:
Triangle A″B″C″ is formed using the translation (x + 0, y + 2) and the dilation by a scale factor of 2 from the origin. Which equation explains the relationship between line segment AC and line segment A"C"?

The simplification of the expressions in the question using the rules of indices are as follows;

1.) 6·e⁰ + (11·f)⁰ - 5/g⁰ = 2

2. (3⁻⁴ + 5⁻³)⁻¹ = \(49\frac{31}{206}\)

3. (3⁻⁴ + 5⁻³)⁻² = \(2415\frac{32685}{42436}\)

4.) \(\dfrac{-5\cdot \left(m^{-4}\cdot n^{-5} \right)^{-3}}{10\cdot c^{-5} \cdot d^6 \cdot e^{-8}}\) = \(\dfrac{c^5\cdot e^8}{2\cdot d^5}\)

5.)  \(\dfrac{-5\cdot \left(m^{-4}\cdot n^{-5}\right)^{-3 }}{7\cdot \left(p^{-6} \cdot q^8\right)^{-4}} =\dfrac{-5\cdot m^{12}\cdot n^{15}\cdot q^{32}}{7\cdot p^{24}}\)

An index or indices is the power by which a number or variable or expression raised.

1.) 6·e⁰ + (11·f)⁰ - 5/g⁰

6·e⁰ + (11·f)⁰ - 5/g⁰ = 6 × 1 + 1 - 5/1

6 × 1 + 1 - 5/1 = 6 + 1 - 5 = 2

Therefore;

6·e⁰ + (11·f)⁰ - 5/g⁰ = 2

2.) (3⁻⁴ + 5⁻³)⁻¹

(3⁻⁴ + 5⁻³)⁻¹ = (1/(3⁴) + 1/(5³))⁻¹ = 1/(1/(3⁴) + 1/(5³))

1/(1/(3⁴) + 1/(5³)) = 1/(1/81 + 1/125) = 1/((125 + 81)/(81×125))

1/((125 + 81)/(81×125)) = (81 × 125)/(125+81) = 10125/209

10125/206 = 49 + 31/206

(3⁻⁴ + 5⁻³)⁻¹ = \(49 \frac{31}{206}\)

3.) (3⁻⁴ + 5⁻³)⁻²

(3⁻⁴ + 5⁻³)⁻² = 1/((1/3⁴ + 1/5³)²)

1/((1/3⁴ + 1/5³)²) = 1/((1/81 + 1/125)²)

1/((1/81 + 1/125)²) = 1/(((125 + 81)/(81 × 125))²)

1/(((125 + 81)/(81 × 125))²) = 1/((206/10125)²)

1/((206/10125)²) = (10125)²/(206)² = 102515625/42436

102515625/42436 = 2415 32685/42436

(3⁻⁴ + 5⁻³)⁻² = \(2415\frac{32685}{42436}\)

4.)  \(\dfrac{5\cdot (2\cdot a^{-1}\cdot b^3)^0}{10\cdot c^{-5}\cdot d^6\cdot e^{-8}}\)

\(\dfrac{5\cdot (2\cdot a^{-1}\cdot b^3)^0}{10\cdot c^{-5}\cdot d^6\cdot e^{-8}} = \dfrac{5\times 1}{10\times \left(\frac{1}{c^5}\times d^6 \times \frac{1}{e^8} \right) }\)

\(\dfrac{5\times 1}{10\times \left(\frac{1}{c^5}\times d^6 \times \frac{1}{e^8} \right) } = \dfrac{5}{10\times \left(\frac{d^6}{c^5\times e^8} \right) }\)

\(\dfrac{5}{10\times \left(\frac{d^6}{c^5\times e^8} \right) } = \dfrac{1}{2\times \left(\frac{d^6}{c^5\times e^8} \right) }\)

\(\dfrac{1}{2\times \left(\frac{d^6}{c^5\times e^8} \right) } = \dfrac{c^5\times e^8}{2\cdot d^6}\)

\(\dfrac{5\cdot (2\cdot a^{-1}\cdot b^3)^0}{10\cdot c^{-5}\cdot d^6\cdot e^{-8}}= \dfrac{c^5\times e^8}{2\cdot d^6}\)

5.) \(\dfrac{-5\cdot \left(m^{-4}\cdot n^{-5} \right)^{-3}}{7\cdot \left(p^{-6}\cdot q^8\rright)^{-4}}\)

\(\dfrac{-5\cdot \left(m^{-4}\cdot n^{-5} \right)^{-3}}{7\cdot \left(p^{-6}\cdot q^8\right)^{-4}} =\dfrac{-5\cdot \dfrac{1}{\left(\frac{1}{m^{4}}\times \frac{1}{n^{5}} \right)^{3}} }{7\cdot \dfrac{1}{\left(\frac{1}{p^{6}}\times q^8\right)^{4}} }\)

\(\dfrac{-5\cdot \dfrac{1}{\left(\frac{1}{m^{4}}\times \frac{1}{n^{5}} \right)^{3}} }{7\cdot \dfrac{1}{\left(\frac{1}{p^{6}}\times q^8\right)^{4}} } = \dfrac{-5\cdot {\left(m^4\times n^5\right)^3} }{7\cdot \left( \dfrac{p^6}{q^8\right)^{4}} }\)

\(\dfrac{-5\cdot {\left(m^4\times n^5\right)^3} }{7\cdot \left( \dfrac{p^6}{q^8\right)^{4}} } = \dfrac{-5\cdot {\left(m^{12}\times n^{15}\right)} }{7} \times \left(\dfrac{q^8}{p^6}\right)^4 }\)

\(\dfrac{-5\cdot {\left(m^{12}\times n^{15}\right)} }{7} \times \left(\dfrac{q^8}{p^6}\right)^4 } = \dfrac{-5\cdot {\left(m^{12}\times n^{15}\right)} }{7} \times \left(\dfrac{q^{32}}{p^{24}}\right) }\)

\(\dfrac{-5\cdot {\left(m^{12}\times n^{15}\right)} }{7} \times \left(\dfrac{q^{32}}{p^{24}}\right) } = \dfrac{-5\times {m^{12}\times n^{15}\times q^{32}} }{7\times p^{24}}\)

\(\dfrac{-5\cdot \left(m^{-4}\cdot n^{-5} \right)^{-3}}{7\cdot \left(p^{-6}\cdot q^8\right)^{-4}} = \dfrac{-5\times {m^{12}\times n^{15}\times q^{32}} }{7\times p^{24}}\)

6.) (3·x⁻⁴·y⁻⁵·z⁻²)⁻²

(3·x⁻⁴·y⁻⁵·z⁻²)⁻² = \(3\cdot \left(\dfrac{1}{\left(\dfrac{1}{x^4} \cdot \dfrac{1}{y^5} \cdot \dfrac{1}{z^2} } \right)^2\right)\)

\(3\cdot \left(\dfrac{1}{\left(\dfrac{1}{x^4} \cdot \dfrac{1}{y^5} \cdot \dfrac{1}{z^2} } \right)^2\right) = 3\cdot \left(x^4\cdot y^5\cdot x^2\right)^2\)

3·(x⁴·y⁵·x²)² = 3·x⁸·y¹⁰·x⁴

Therefore;

(3·x⁻⁴·y⁻⁵·z⁻²)⁻² = 3·x⁸·y¹⁰·x⁴

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