What is the rate of return when 25 shares of Stock
A, purchased for $30/share, are sold for $825? The
commission on the sale is $6.
Rate of Return = [?] %
Give your answer as a percent rounded to the
nearest tenth.

Step-by-step explanation:

f(x) = y = -1/2 × sqrt(x + 3), x >= -3

-2y = sqrt(x + 3)

4y² = x + 3

x = 4y² - 3

and now we need to rename x to y and y to x to make it a "normal" function :

y = 4x² - 3

since in the original function x >= -3, this gave us y <=0.

and therefore (remember the x of the inverse function actually stands for the y of the original function) the limit for the inverse function is x <= 0.

so, again, the full answer is

f^-1(x) = 4x² - 3, x <= 0

Answer:

Step-by-step explanation:

3(x - 4) + 2(x + 5) = 3*x - 3*4  + 2*x + 2*5

                          = 3x - 12 + 2x + 10

                          = 3x + 2x  - 12 + 10   {Combine like terms}

                          = 5x - 2

Answer:

RM3,500

Step-by-step explanation:

Salary=RM375 per week

5% commission per week

If she target a minimum of RM 550.

Let x=minimum Sales

RM550=RM375 + 5% of x

RM550=RM375 + 0.05x

RM550 - RM375=0.05x

RM175=0.05x

Divide both sides by 0.05

RM175/0.05=0.05x/0.05

RM3,500=x

For Azila to earn a minimum of RM550 in a week, her salary will be RM375 plus 5% commission on the sales of RM3,500 value of product.

Check:

5% of RM3,500

=0.05*3,500

=RM175

Plus

Salary of RM375

RM175 + RM375=RM550

I think is rational but I'm not sure

Answer:

A. 1 in 6 jeans or 16.67% or \(\frac{1}{6}\)

B. 15

Step-by-step explanation:

B. \(\frac{1}{6} = \frac{x}{90}\)

If you have any questions feel free to ask in the comments

a)  The electrical potential V (center) at the center C of the circle due to the charges Q1 and Q2 is -2.30 V.

b) The total electrical potential at the point P due to charge Q1 and Q2 , located at a distance of 6.71 cm is -1.78V.

Given that:

Radius of the circle, r = 8.20cm

Charge distributed along one-quarter of the circumference of the circle,

Q1 = +4.20pC

Charge distributed along 3/4th of the circumference of the circle,

Q2 = 25.20pC

Distance of the point from the center, d = 6.71cm

The electric potential at infinity is. V = 0

Using the concept of potential at a point on a thin rod, we can obtain the individual potential due to each charge. The sum of these values ​​can now be used to obtain the desired potential value at the center and at the point, taking into account the distance to the point.

Formula:

The potential due to a point charge at a distance r from the point charge is determined by the equation V = \(\frac{1}{4\pi E_0} * \frac{q}{r}\)        ---------------- (1)

The potential due to the collection of point charges is determined by formula:

V = ∑\(\frac{1}{4\pi E_0} * \frac{q}{r}\)                 -------------------- (2)

(a) The potential VQ1 at the center C of the circle due to the charge Q1 is determined using equation (i) as:

\(V_Q_1 = \frac{1}{4\pi E_0} * \frac{Q_1}{R}\)              --------------------- (3)

Here, R is the radius of circle

The potential VQ1 at the center C of the circle due to the charge Q1 is determined using equation (i) as:

\(V_Q_1 = \frac{1}{4\pi E_0} * \frac{Q_2}{R}\)                 ----------------------- (4)

Now the potential V(center) at the center C of the circle due to charges Q1 and Q2 is the sum of the potential due to charge Q1 and the potential due to charge Q2. This is given using equations (a) and (b) in equation (ii) as:

    \(V_Center = \frac{1}{4\pi E_0} * \frac{Q_1}{R} + \frac{1}{4\pi E_0} * \frac{Q_2}{R}\)

⇒ \(V_Center = \frac{1}{4\pi E_0} *( \frac{Q_1}{R} + \frac{Q_2}{R})\)

⇒ 9.0 × 10⁹Nm²/C₂ (\(\frac{4.20*10^-12 C}{0.082m} +\frac{-25.2*10^-12C}{0.082m}\))

⇒ -2.30V

The electrical potential V (center) at the center C of the circle due to the charges Q1 and Q2 is -2.30 V.

(b) From the above figure the r between each charged particle and the point P is given as:

\(r = \sqrt{R^{2}+D^{2} }\)                    

In the figure above, r between each charged particle and point P is defined as: ="1662703245948 "

\(V_Q_1 = \frac{1}{4\pi E_0} * \frac{Q_1}{\sqrt{R^{2} + D^{2} } }\)                  ------------------ (5)

Again, the electric potential at point P due to charge Q2 is given using equation (i) as follows:
\(V_Q_1 = \frac{1}{4\pi E_0} * \frac{Q_2}{\sqrt{R^{2} + D^{2} } }\)                   -------------------- (6)

A The potential at point P due to charge Q2 is determined using equation (i): The potential of charge Q1 and the potential of charge Q2. This is given using equations (c) and (d) in equation (ii) as:

\(V_P = 9.0 * 10^9Nm^2/C^2 (\frac{4.20*10^-12C-6(4.20*10^-12C)}{\sqrt{(0.082m)^{2} + (0.082m)^{2} } })\)

= -1.78V

The total electrical potential at the point P due to charge Q1 and Q2 , located at a distance of 6.71 cm is -1.78V.

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The following specific topics are covered in 8th grade math:

-Mathematical operations

-Resolving equations with a single unknown

- One-variable linear equations

-Expressions in algebra

- square roots and squares

- Geometry

- Cube and cube root

-Data management

These are the headings that were previously mentioned. These subjects need to be investigated in depth going forward.

Algebraic expressions: What are they?

Using letters or alphabets to represent numbers without giving their exact quantities is the idea behind algebraic expressions. The fundamentals of algebra taught us how to express an unknown value using letters like x, y, and z. These letters are referred to here as variables.

What components make up one-variable linear equations?

One-variable linear equation is represented by the following equation:

A and B are two integers, and X is a variable, hence ax+b = 0. There is just one answer to this equation.

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Answer:

No

Step-by-step explanation:

The coordinates in an ordered pair are listed (x,y).  So, in (8,3)  The 8 is the x coordinate and the 3 is the y coordinate.  Plug those numbers into the equation and see if it makes a true statement.  If it does, then that point is on the line and it is a solution

y = 17x + 7

3 = 17(8) + 7

3 = 136 + 7

3 \(\neq\) 143, so this point is not a solution

Answer:

If this is the equation you meant to type (3x + 10 = 13x) then the answer is x = 1.

If this is the equation you meant to type (3x - 10 = 13x) then the answer is x = -1.

Answer:

ANSWER:C

Step-by-step explanation:

sana maka tulong

3+5=2+9

3x+5=2x+93x+5=2x+9

Solve

1

Subtract  

5

55

from both sides of the equation

3+5=2+9

3+5−5=2+9−5

2

Simplify

Subtract the numbers

Subtract the numbers

3=2+4

3

Subtract  

2

2x2x

from both sides of the equation

3=2+4

3−2=2+4−2

4

Simplify

Combine like terms

Multiply by 1

Combine like terms

=4

Solution

=4

Mary's HLV is $2,215,773.95.

Mary's HLV if she works until 70 is $1,611,008.23.

Mary's COE if she works until 75 is $5,130,372.40.

Mary's COE if she works until 70 is $2,985,308.60.

To calculate the Human Life Value insurance (HLV) of Mary, we need to determine the present value of her future income stream.

Annual after-tax earnings = $55,000 x (1 - 0.15) = $46,750

Total after-tax earnings over working life = $46,750 x (1 + 0.03)^(75-35) = $3,382,820.33

Total personal consumption = 27% x $3,382,820.33 = $914,073.89

Calculate Mary's HLV:

= $3,382,820.33 - (1 + 0.05)^(-1) x $914,073.89

= $2,215,773.95

Therefore, Mary's HLV is $2,215,773.95.

If Mary works until 70 total after-tax  = $46,750 x (1 + 0.03)^(70-35) = $2,124,182.09

Mary's HLV if she works until 70 is $1,611,008.23.

To calculate the Capitalization of Earnings (COE) method. Here's how we can calculate it:

Calculate Mary's expected earnings in her final year of work:

Expected earnings in final year = $55,000 x (1 + 0.03)^(75-35) = $256,518.62

Apply a capitalization rate to the expected earnings:

COE = expected earnings in final year / capitalization rate

= $256,518.62 / 0.05

= $5,130,372.40

Therefore, Mary's COE if she works until 75 is $5,130,372.40.

If Mary works until 70, her expected earnings in her final year of work would be:

Expected earnings in final year = $55,000 x (1 + 0.03)^(70-35) = $149,265.43

Mary's COE if she works until 70 is $2,985,308.60.

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To construct a histogram of the estimates and compare it to the above estimates, follow these steps:
1. Compile the data and organize it into groups or bins.
2. Assign each group a height or frequency, usually the number of occurrences in the group.
3. Represent each group by drawing a bar with the corresponding height.
4. Connect the tops of the bars to form a histogram.

Comparing the histogram to the above estimates, if the histogram is similar in shape and spread, then the estimates are consistent.

The best estimate of the random modifier without examining the value is the mode of the data, which is the value that occurs most often.

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The equations of the tangents to the curve are y = 3x - 6 and y = -3x + 30.

To find the equations of the tangents to the curve, we need to determine the slope of the tangent line at the given point of tangency.

The given curve is defined by the parametric equations x = 6t^2 - 2 and y = 4t^3 - 2.

We can eliminate the parameter t by expressing t in terms of x.

Rearranging the first equation, we have t^2 = (x + 2) / 6, and taking the square root of both sides, we get t = ±√((x + 2) / 6).

Substituting this value of t into the equation for y, we have y = 4(±√((x + 2) / 6))^3 - 2.

Simplifying this expression, we obtain y = ±(4/3)√((x + 2)^3 / 6) - 2.

Now, let's find the slopes of the tangents at the point (8, 6). We take the derivative of y with respect to x and evaluate it at x = 8.

Differentiating y with respect to x, we get dy/dx = ±(4/3)√(2(x + 2)^3 / 3)(1 / 2) = ±(2/3)√((x + 2)^3 / 3).

Evaluating the derivative at x = 8, we have dy/dx = ±(2/3)√((8 + 2)^3 / 3) = ±(2/3)√(10^3 / 3) = ±(2/3)√(1000/3) = ±20√10/3.

Since the slopes of the tangents are given by the derivative, the two possible slopes are ±20√10/3.

Now we can find the equations of the tangents using the point-slope form. Using the point (8, 6), we have:

y - 6 = (±20√10/3)(x - 8).

Simplifying these equations, we get:

y = 3x - 6 and y = -3x + 30.

Therefore, the equations of the tangents to the curve that pass through the point (8, 6) are y = 3x - 6 (the smaller slope) and y = -3x + 30 (the larger slope).

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Answer: 70

V = 15.14/3 = 5.14 = 70 (in³)

Step-by-step explanation:

Answer: Uhhh I think that the answer is b 70 in.

The slope of the line is given as -2/3.

We are also given the point (1, 1) in which this line passes through.

Before we can plot the graph of the line, we need to know the equation of the line first.

The values given are more than enough to find the equation of the line.

The formula used to get the equation of the line is given below:

Now, with this formula, let us find the equation of the line.

Thus, the equation of the line is:

Now, using a graph calculator, let us plot this equation.

After doing this, the following is the result:

Answer:

A crest is the highest point of a wave.

A trough is the lowest point of a wave.

Infrasound is sound below the limit that humans can hear, below 20 Hz.

Ultrasound is sound above the limit that humans can hear, above 20,000 Hz.

Based on the given distance and time, the speed of the runner is s(h) = 8h/√3.

Relationship between time, distance and speed:

The relationship of speed with distance and time is written as,

Speed = Distance x Time

Which describes the distance travelled divided by the time taken to cover the distance will results the speed.

Given,

Here we need to find the runner's speed when the distance a runner travels is represented by d(h) = 2√h and the associated time is t(h) = 3√/4h.

We know that the formula to calculate the speed is,

Speed = Distance / Time

Here we have the value of

distance = d(h) = 2√h

time = t(h) = √3/4h

Now, we have to apply the values on the formula, then we get,

Speed =  2√h / √3/4h

Therefore, the speed of the runner is 8h/√3.

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Answer:

=  229

Step-by-step explanation:

Step 1: Write down the binary number:

11100101

Step 2: Multiply each digit of the binary number by the corresponding power of two:

1x27 + 1x26 + 1x25 + 0x24 + 0x23 + 1x22 + 0x21 + 1x20

Step 3: Solve the powers:

1x128 + 1x64 + 1x32 + 0x16 + 0x8 + 1x4 + 0x2 + 1x1 = 128 + 64 + 32 + 0 + 0 + 4 + 0 + 1

Step 4: Add up the numbers written above:

128 + 64 + 32 + 0 + 0 + 4 + 0 + 1 = 229.

So, 229 is the decimal equivalent of the binary number 11100101.

The decimal value of 11100101.1 in binary representation is 229.5.

To convert a binary number to its decimal representation, we evaluate each digit in the binary number based on its place value. The rightmost digit has a place value of 2⁰, the second digit from the right has a place value of 2¹, and so on.

The place value of each digit is multiplied by its corresponding binary digit and the resulting products are summed together to obtain the decimal representation of the binary number.

For example, in the binary number 11100101.1, the rightmost digit is 1, which has a place value of 2⁰. So, the rightmost digit contributes 1 * 2⁰ = 1 to the decimal representation of the number. The next digit is 0, which has a place value of 2¹.

So, this digit contributes 0 * 2¹ = 0 to the decimal representation. This process is repeated for each digit in the binary number until the decimal representation is obtained.

In this case, the decimal representation of 11100101.1 is 229.5, which is calculated by summing up the contributions of each binary digit based on its place value.

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The next term in the given series is 21.

What is mathematical expression?

A mathematical expression is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

We are adding the previous term with the next term. By calculating we get the new next term. Then we repeat this process with the new term and calculate the next term. this is simple addition process.

Given,

1,1 2,3,5,8,13

1+0=1

1+1=2

2+1=3

3+2=5

5+3=8

8+5=13

13+8=21

Therefore, the next term in the given series is 21.

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Answer:

1 positive correlation

2 A

3 negative

Step-by-step explanation:

Hope this helps!:)

Answer is written down below

Answer:

3x^2z√2

/ 2y

Step-by-step explanation:

Simplify the radical by breaking the radicand up into a product of known factors, assuming positive real numbers.

Answer:

??????.

Step-by-step explanation:

????????????????

Answer:

look at the explanation

Step-by-step explanation:

A cylindrical container has a height of 14 inches and radius of 3.2 inches. It is filled with pasta, but there is 1.5 inches of space left at the top. How many cubic inches of pasta are in the container?

1. Given

h = 14 in

r = 3.2 in

space = 1.5

V pasta = πr² (h - space)

V pasta = π(3.2)² (14 - 1.5)

V pasta = 402.12 in³

Izzie has a muffin tin that holds 12 muffin cups. Each cup is cylindrical with a diameter of 3 inches and a height of 3.5 inches. Izzie has 544.28 cubic inches of batter. How many muffins can she bake?

2. Given

h = 3.5 in

d = 3 in

V batter = 544.28

V muffin = πd²h/4

V muffin = π(3)²(3.5)/4

V muffin = 24.74 in³

# of muffin = V batter/ V muffin

# of muffin = 544.28/ 24.74 = 22

so she can bake 22 muffins

A popsicle tray has 6 cone-shaped popsicle molds. Each popsicle mold has a diameter of 5.4 cm and a height of 12.9 cm. How many cubic centimeters will one tray hold?

3. Given

d = 5.4 cm

h = 12.9 cm

6 cone-shaped popsicles per tray

V popsicle = πd²h/12

V popsicle = π(5.4)²(12.9)/12

V popsicle = 98.48cm³

V popsicle per tray = (98.48cm³) (6)

V popsicle per tray = 590.88cm³

A cone has a volume of 1,230.88 units³ and a diameter of 14 units. How many units is the height of the cone? Use 3.14 for pi.

4. Given

V cone = 1,230.88 units³

d = 14 units

V cone = πd²h/12

h = 12V cone/πd²

h = 12(1230.88)/ (3.14) (14)²

h = 24 units

A cylinder has a volume of 7,598.8 units³ and a height of 5 units. How many units is the diameter of the cylinder? Use 3.14 for pi.

5. Given

V cylinder = 7,598.8 units³

h = 5 units

V cylinder = πd²h/4

d = √4V cylinder/πh

d = √4(7598.8)/3.14(5) = √1936

d = 44 units

Jana and Haiya are each filing a witch's hat in the shape of a cone with candy. Each hat has a radius of 3.4 inches and height of 12.5 inches. How many cubic inches of candy will both hats hold?

6. Given

r = 3.4 in

h = 12.5 in

V hat = πr²h/3

V hat = π(3.4)²(12.5)/3

V hat = 151.32 in³

V two-hats = 2(151.32 in³ )

V two-hats = 302.64 in³

George has 1 ½ containers of toothpaste in the shape of a cylinder. Each container has a diameter of 4 cm and a height of 15 cm. How many cubic centimeters of toothpaste does he have?

7. Given

d = 4 cm

h = 15 cm

V container = πd²h/4

V container = π(4)²(15)/4

V container = 188.496 cm³

V toothpaste = 1.5V container = 1.5(188.496 cm³)

V toothpaste = 282.74 cm³

A cone has a diameter of 16 units and a height of 11 units. How many cubic units is the volume of the cone?

8. Given

d = 16 units

h = 11 units

V cone = πd²h/12

V cone = π(16)²(11)/12

V cone = 737.23 units³

Answer:

subtract 10-7 which is 3 cookies

Answer:

he would do 10 - 7

Step-by-step explanation:

school is trash bro

Answer:

2

Step-by-step explanation:

First replace x with -1

f(-1)=2+(-1)

f(-1)=1

Now plug in 1

g(1)=3-1

3-1=2