What is the relationship between the kinetic energy of molecules in an object and the object's temperature? Responses As the kinetic energy of the molecules decreases, the temperature increases. The total kinetic energy of the molecules is not affected by a change in temperature. As the temperature increases, the kinetic energy of the molecules increases. The kinetic energy always increases whether the temperature increases or decreases.

Answer:

P Q

c) 30 10

Explanation:

P= 10m = 10 x 180 = 1800 N

work is done by the weightlifter in lifting the barbells :

A= Ph = 1800 x 1.95 = 3510 J

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Answer:

Work out the change in velocity for you given time.

Calculate the change in time for the period you are considering.

Divide the change in velocity by the change in time.

can increase the velocity of the object, decrease the velocity of the object, or change the direction of the velocity of the object.

Explanation:

hope this helped have a great day!

Answer:

here

Explanation:

dm me for answer

true

Explanation:

this is because melting point and boiling point decreases down the group because they are held together by attractions between positive nuclei and delocalised electrons

Answer:

(a) electrical energy or chemical energy

(b) sound energy, potential energy, light energy.

(c) Work (J) = Force (N) * Distance (m)

                   = 80 * 15

                   = 1200 Joules.

The absorption of energy occurs in endothermic reactions. The correct option is D.

The type of chemical reaction that results in the absorption of energy is endothermic. In an endothermic reaction, energy is absorbed from the surroundings, resulting in an increase in the internal energy of the system.

This means that the products of the reaction have more energy than the reactants, and the reaction requires an input of energy to proceed.

Examples of endothermic reactions include the reaction of baking soda and vinegar, the melting of ice, and the reaction of ammonium nitrate and water.

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While accelerating at a constant rate from 12.0 m/s to 18.0 m/s, a car moves over a distance of 60.0 m. The time taken by the car will be 4 seconds. the correct answer is option(c).

When acceleration is constant, the rate of change in velocity is also constant. In the absence of any acceleration, velocity remains constant. When acceleration is positive, velocity becomes more significant.

Let a denote acceleration, u denote initial velocity, v denote final velocity, and t denote time.

The equation of motion is stated as,

v = u + at

v² = u² + 2as

A car travels across a distance of 60.0 m while accelerating constantly from 12.0 m/s to 18.0 m/s.

Then the time taken by the car will be,

u = 12 m/s

v = 18 m/s

s = 60 m

Put these in the equation v² = u² + 2as.

18² = 12² + 2 x a x 60

a = 1.5

Then the time will be

18 = 12 + 1.5t

1.5t = 6

t = 4 seconds

Hence, the time taken is 4 s.

The complete question is:

While accelerating at a constant rate from 12.0 m/s to 18.0 m/s, a car moves over a distance of 60.0 m. How much time does it take?

1.00 s

2.50 s

4.00 s

4.50 s

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The change in length for a one-meter-long object subject to a 10-degree change in temperature would be on the order of a few millimeters, approximately 0.1 millimeters.

The change in length of an object due to a change in temperature is governed by its coefficient of linear expansion. This coefficient represents how much the length of the object changes per degree Celsius or Kelvin of temperature change. Different materials have different coefficients of linear expansion.

Assuming a linear relationship between the change in length (ΔL) and the change in temperature (ΔT), we can use the formula:

ΔL = αLΔT

where ΔL is the change in length, α is the coefficient of linear expansion, L is the original length of the object, and ΔT is the change in temperature.

For a one-meter-long object subjected to a 10-degree change in temperature, the value of α depends on the material of the object. However, as a general estimate, for most common materials, the coefficient of linear expansion is on the order of \(10^{-5}\) per degree Celsius.

Using this estimate, we can calculate the change in length:

ΔL ≈ \(10^{-5}\) per degree Celsius) * (1 meter) * (10 degrees)

= \(10^{-4}\) meters

≈ 0.1 millimeters

Therefore, the change in length for a one-meter-long object subject to a 10-degree change in temperature would be on the order of a few millimeters, approximately 0.1 millimeters.

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Answer:

Force = 3 Newton

Explanation:

Given the following data;

Mass = 200 g to kilograms = 200/1000 = 0.2 kg

Acceleration = 15 m/s²

To find the force;

Force = mass * acceleration

Force = 0.2 * 15

Force = 3 Newton

The value of the spring constant when the spring stores 96 joule of potential energy while stage to a distance of 5 cm is 76800 Nm.

The amount of energy stored in a spring is given by the formula,

E = 1/2Kx², access the elongation in the spring, K is the spring constant of the spring and if is the amount of energy that is stored while stretching the spring.

Now it is given to us that there is 96 joules of potential energy stored inside the spring when it is stretched by a distance of 5 cm. In order to find the spring constant of the spring we will put the given values in the mentioned formula,

96 = 1/2K(0.05)²

K = 2(96)/(0.05)²

K = 76800 Nm

So, the magnitude of the spring constant is found to be 76800Nm.

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Answer:

Density is the degree of compactness in an object.

Explanation:

S.I unit is kg/m3

Answer:

The mass of the paraffin is 70g

Explanation:

You have to subtract the mass of the empty beaker from that of the empty beaker and paraffin oil to get the mass of the paraffin oil

Answer:

Given,

Object distance, u=25cm

Focal length, f=20cm

From mirror formula

f

1

​

=

v

1

​

+

u

1

​

−20

1

​

=

v

1

​

−

25

1

​

⇒

v

1

​

=−

20

1

​

+

25

1

​

v=100cm

The image will be real, inverted magnified

Explanation:

Given,

Object distance, u=25cm

Focal length, f=20cm

From mirror formula

f

1

​

=

v

1

​

+

u

1

​

−20

1

​

=

v

1

​

−

25

1

​

⇒

v

1

​

=−

20

1

​

+

25

1

​

v=100cm

The image will be real, inverted magnified

Kinetic energy is energy of motion. If the object is sitting still, then it has no kinetic energy. It doesn't matter what its mass is, or how high the shelf is.

KE = 0

Answer:

Spring constant: approximately \(28\; {\rm N\cdot m^{-1}}\).

Unloaded length: approximately \(7.0\; {\rm cm}\).

(Assume that the weight of the spring is negligible, and that \(g = 9.81\; {\rm N\cdot kg^{-1}}\).)

Explanation:

Divide the tension \(F\) on the spring by the displacement \(x\) to find the spring constant. \(k\):

\(\begin{aligned}k &= \frac{F}{x}\end{aligned}\).

Let \(L_{0}\) denote the unloaded length of the spring (in meters.)

When the \(0.225\; {\rm kg}\) mass is on the spring, the tension on the spring would be \(m\, g = (0.225)\, (9.81) \; {\rm N} \approx 2.207\; {\rm N}\).

It is given that the length of the spring with this \(0.225\; {\rm kg}\) mass attached is \(L = 0.15\; {\rm m}\). Subtract the initial length of the spring \(L_{0}\) from the current length to find the displacement of the spring: \(x = L - L_{0} = 0.15 - L_{0}\).

Divide the tension on the spring by the displacement to find an expression for the spring constant:

\(\begin{aligned}k &= \frac{F}{x} \approx \frac{2.207}{0.15 - L_{0}}\end{aligned}\).

Similarly, when the \(1.85\; {\rm kg}\) object is on the spring, the tension on the spring would be \(m\, g = (1.85)\, (9.81) \; {\rm N} \approx 18.15\; {\rm N}\).

Subtract the initial length \(L_{0}\) from the current length \(L = 0.725\; {\rm m}\) to find the displacement: \(x = L - L_{0} = (0.725 - L_{0})\; {\rm m}\).

Divide the tension on the spring by the displacement to find another expression for the spring constant:

\(\begin{aligned}k &= \frac{F}{x} \approx \frac{18.15}{0.725 - L_{0}}\end{aligned}\).

Equate the two expressions for the spring constant \(k\) and solve for the unloaded length \(L_{0}\):

\(\begin{aligned}\frac{18.15}{0.725 - L_{0}} &= \frac{2.207}{0.15 - L_{0}}\end{aligned}\).

\((18.15)\, (0.15 - L_{0}) = (2.207)\, (0.725 - L_{0})\).

\(\begin{aligned} L_{0} &\approx \frac{(18.15)\, (0.15) - (0.725) (2.207)}{18.15 - 2.207}\; {\rm m} \\ &\approx 0.070\; {\rm m}\end{aligned}\).

Substitute \(L_{0}\) back into one of the two expressions for the spring constant \(k\) and evaluate:

\(\begin{aligned}k &\approx \frac{18.15}{0.725 - L_{0}} \\ &\approx \frac{18.15}{0.725 -0.070} \approx 28\; {\rm N\cdot m^{-1}} \end{aligned}\).

Apply unit conversion:

\(0.070\; {\rm m} = (0.070 \times 10^{2})\; {\rm cm} = 7.0\; {\rm cm}\).

In other words, the unloaded length of the spring would be approximately \(7.0\; {\rm cm}\).

The correct answer to part a) is, the force constant of the spring can be found using Hooke's Law and it is 3.83 N/m, and part b) is, the unloaded length of the spring is the same as the length when the 1.85 kg mass is hanging from it, which is 0.725 m.

Part (a) To find the force constant of the spring, we can use Hooke's Law, which states that the force exerted by a spring is equal to the spring constant multiplied by the displacement from equilibrium.

The equation for this is F = kx, where F is the force, k is the spring constant, and x is the displacement from equilibrium.

In this case, we can use the two given lengths and masses to find the displacement from equilibrium and the force exerted by the spring.

The displacement for the first mass is 0.15 m - 0.725 m = -0.575 m, and the force is 0.225 kg * 9.8 m/s^2 = 2.205 N. The displacement for the second mass is 0.725 m - 0.725 m = 0 m, and the force is 1.85 kg * 9.8 m/s^2 = 18.13 N.

We can then plug these values into the equation F = kx and solve for k:

2.205 N = k(-0.575 m)
k = -2.205 N / -0.575 m
k = 3.83 N/m

Therefore, the force constant of the spring is 3.83 N/m.

Part (b) To find the unloaded length of the spring, we can use the equation x = F/k, where x is the displacement from equilibrium, F is the force, and k is the spring constant.

Since the unloaded length of the spring is when the force is zero, we can plug in F = 0 and k = 3.83 N/m to solve for x:

x = 0 N / 3.83 N/m
x = 0 m

Since the displacement from equilibrium is zero, the unloaded length of the spring is the same as the length when the 1.85 kg mass is hanging from it, which is 0.725 m.

Therefore, the unloaded length of the spring is 0.725 m, or 72.5 cm.

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The point between the two charges where the electric field equal to zero is calculated to be 1.55 m.

The charge q₁ is given as 3 nc = 3 × 10⁻⁹ c

It is located at x₁ = 0.

The charge q₂ is given as 7.5 nc = 7.5 × 10⁻⁹ c

It is located at x₂ = 4 m.

Let us suppose that, electric field is zero at the point x, it is in between 0 and 4 m.

We know the formula for electric field as,

E = k q /r²

Let us equate the electric field at both the charges.

k q₁/x² = k q₂/(x₂ - x)²

q₁ (x₂ - x)² = q₂ x²

3 × 10⁻⁹× (4 - x)² = 7.5 × 10⁻⁹ × x²

3 × ( 16 + x² - 8x) = 7.5 ×x²

48 + 3x² - 24x = 7.5x²

4.5 x² + 24x - 48 = 0

The two values of x are,

x = 1.55, -6.883

The distance cannot be negative. So, the electric field at x = 1.55 m is said to be zero.

Thus, the required value of x is 1.55 m.

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48 m/s in terms of km/h is 720.8 km/h. In terms of m/min is 2880 m/min, in terms of km/s is 0.048 km/s and in terms of km/min is 2.88 km/min.

To solve this question, we need to understand some terms. The unit of velocity is measured in m/s. It can be expressed in different units of velocity.

1 km (kilometer) = 1000 meter

1 h (hour) = 3600 seconds

1 minutes = 60 seconds

To convert m/s into km/h,

48 m/s * 3600/1000 =  172.8 km/h

To convert m/s into m/min,

48 m/s * 60 = 2880 m/min

To convert m/s into km/s,

48 m/s ÷ 1000 = 0.048 km/s

To convert m/s into km/minutes,

48 m/s * 60 / 1000 = 2.88 km/min

Therefore, the 48 m/s expressed is 172.8 km/h, 2880 m/min, 0.048 km/s and 2.88 km/min.

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48 m/s is equivalent to  172.8 km/h, 2880 m/min, 0.048 km/s, and 2.88 km/minute.

To express 48 m/s in different units of velocity:

km/h (kilometers per hour):

To convert m/s to km/h, we can use the conversion factor of 3.6 since 1 m/s is equal to 3.6 km/h.

48 m/s * (3.6 km/h / 1 m/s) = 172.8 km/h

Therefore, 48 m/s is equivalent to 172.8 km/h.

m/min (meters per minute):

To convert m/s to m/min, we can use the conversion factor of 60 since there are 60 seconds in a minute.

48 m/s * (60 m/min / 1 s) = 2880 m/min

Therefore, 48 m/s is equivalent to 2880 m/min.

km/s (kilometers per second):

Since 1 kilometer is equal to 1000 meters, to convert m/s to km/s, we divide the value by 1000.

48 m/s / 1000 = 0.048 km/s

Therefore, 48 m/s is equivalent to 0.048 km/s.

km/minute (kilometers per minute):

To convert m/s to km/minute, we first need to convert m/s to km/s (as calculated in the previous step) and then multiply by 60 to convert seconds to minutes.

0.048 km/s * 60 = 2.88 km/minute

So, 48 m/s is equivalent to 2.88 km/minute.

Hence, 48 m/s is equivalent to approximately 172.8 km/h, 2880 m/min, 0.048 km/s, and 2.88 km/minute.

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Answer:

Explanation:

The formula for this is designed around the fact that momentum must be conserved:

\([(m_{ball1}*v_{ball1})+(m_{ball2}*v_{ball2})]_b=[(m_{ball1}+m_{ball2})v_{both}]_a\)

This is because they sitck together after they collide. Filling in:

[(3*10)+(5*2)] = [3 + 5]v and

30 + 10 = 8v so

40 = 8v and

v = 5

They are both moving east at a velocity of 5 m/s since they stuck together.

Explanation:

Here,

Mass=16,500kg.

speed=14 m/s.

we know that,

\(\tt{ p=m×v }\) ⠀

where,

p=momentum

m=mass

v=velocity

according to the question,

\(\tt{ momentum =mass×velocity }\) ⠀

\(\tt{ 16500×14 }\) ⠀

\(\tt{ 231000~kg.m/s }\) ⠀

so,

velocity of the car is 231000kg.m/s

Answer:

control group and experimental group

The distance between the crests of a wave with frequency 440Hz that moves through a string under a tension of 41N and with a linear density of 0.75g/m is approximately 1.496 meters.

To find the distance between the crests of the wave, we need to use the wave speed formula:

v = √(T/μ)

where v is the wave speed, T is the tension in the string, and μ is the linear density of the string.

First, we need to convert the linear density from grams per meter to kilograms per meter, since the unit of tension is Newtons:

μ = 0.75 g/m = 0.00075 kg/m

Next, we can plug in the values given in the problem:

v = √(41 N / 0.00075 kg/m) = 658.3 m/s

Now, we can use the frequency of the wave to find its wavelength:

λ = v/f

where λ is the wavelength and f is the frequency.

Again, we can plug in the values given:

λ = 658.3 m/s / 440 Hz = 1.496 m

Therefore, the distance between the crests of the wave is approximately 1.496 meters.

In summary, the distance between the crests of a wave with frequency 440Hz that moves through a string under a tension of 41N and with a linear density of 0.75g/m is approximately 1.496 meters.

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Answer:

C. Distance 90 feet Displacement 0 feet

Answer: Changing state from a liquid to a solid

Explanation: When liquid water loses thermal energy, it gets cold and undergoes freezing.

The speed of the object after 1 second and 2 seconds is 9.8 m/s and 19.6 m/s respectively.

The equation of motion to be used for calculation of velocity is -

v = u + at, where v and u are final and initial velocity, a is acceleration and t refers to time. Keep the value for each case to find the final velocity. The value of a will be acceleration due to gravity which is 9.8 m/s².

After 1 second

v = 0 + 9.8 × 1

v = 9.8 m/s.

After 2 seconds

v = 0 + 9.8 × 2

v = 19.6 m/s.

Hence, the required velocities are 9.8 and 19.6 m/s.

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The final intensity after passing through the stack of three polarizing filters is approximately 22.77 w/cm².

To solve this problem, we need to consider the effect of each polarizing filter on the intensity of the light.

1. The first filter reduces the intensity of the unpolarized light by a factor of cos²(0°), which is 1. Therefore, the intensity remains the same after passing through the first filter.

2. The second filter reduces the intensity of the light by a factor of cos²(25°). Since cos²(25°) is approximately 0.861, the intensity is reduced to 0.861 times the original intensity after passing through the second filter.

3. The third filter reduces the intensity of the light by a factor of cos²(64°). Since cos²(64°) is approximately 0.394, the intensity is further reduced to 0.394 times the intensity after passing through the second filter.

To find the final intensity, we multiply the intensities at each stage:

Final Intensity = Intensity after 1st filter × Intensity after 2nd filter × Intensity after 3rd filter
Final Intensity = 65.5 w/cm² × 1 × 0.861 × 0.394

Calculating this expression, we find that the final intensity after passing through the stack of three polarizing filters is approximately 22.77 w/cm².

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Answer:

Is always towards the center of the Earth

Explanation:

As a satellite moves around the Earth in a circular orbit, the direction of the force of gravity is always towards the center of the Earth. At an altitude of 100 km, you would be so high that you would see black sky and stars if you looked upwards.

Answer:

9 x 10 ^9 yrs    ( 9 billion years <=====older than Earth !)

Explanation:

.25 = 1.0 (1/2) ^n

.25 / 1.0 =   = (1/2 )^n

log .25 =  n log 1/2

n = 2 half lives

2 * 4.5 x 10^9 =   9 x 10 ^ 9 yrs

The current through the 2Ω resistor is 9.5A

The terminal voltage is 10.8 V

a) The voltage V across 8 Ω resistor is V = I*R = 8*0.5 = 4V

the current through 16Ω resistor is then I = V/R = 4/16 = 0.25 A

the current through 20Ω resistor is then I = current through 8Ω resistor + current through 16Ω resistor = 0.75 A

voltage across 20Ω is V = I*R = 0.75*20 = 15 V

the source voltage is Vs = V8 + V20 = 4+15 = 19 V

therefore the current through 2Ω resistor is

I = V/R = 19/2 = 9.5 A

b) The terminal voltage is

Vterminal = VR = I*R = 0.450*24 = 10.8 V

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The half-life of 40K is approximately 1.3 billion years. Given a ratio of 40Ar/40K as 3/1 in a granite sample, we can estimate the age of the sample by understanding the decay process.  Based on the given 40Ar/40K ratio, the age of the sample is approximately 650 million years.

Since the half-life of 40K is 1.3 billion years, this means that after each half-life, half of the 40K atoms will have decayed into 40Ar. Therefore, if the ratio of 40Ar/40K is 3/1, it suggests that three-quarters (or 75%) of the original 40K atoms have decayed into 40Ar.

To determine the age, we can calculate the number of half-lives that have occurred based on the remaining 25% of 40K. Since each half-life is 1.3 billion years, dividing the remaining 25% by 50% (half) gives us 0.5. Thus, the sample has undergone 0.5 half-lives.

Multiplying 0.5 by the half-life of 1.3 billion years gives us an estimated age of 0.65 billion years, or 650 million years, for the granite sample.

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Answer:

10-0÷2=5 that's the answer