What is the remainder when (x3 1) is divided by (x2 â€"" x 1)? x 1 x 2 0.

Answer:

Starting at the origin (0, 0), go right 3 units, then down 7 units. You will end at (3, -7).

When drawing cabinets obliquely, we start with the front face of an object and draw the depths or sides at 45 degrees.

The object is depicted as having a cabinet oblique with half height and full depth. In a cabinet oblique drawing, the object's height is depicted at half scale while its depth is represented at full scale.

In doing so, a foreshortening effect is produced, giving the object a deeper than tall appearance. The drawing is normally displayed at a 45-degree angle, with the breadth of the object drawn to full scale.

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Answer:

Step-by-step explanation:

The graph of the straight line \(y = -\frac{1}{3}x -2\) is plotted. The graph is shown below.

A straight line is of the form y = mx + c, where m is the slope and c is the y-intercept.

To plot the given straight line \(y = -\frac{1}{3}x -2\), follow the following steps:

Step 1: Substitute x = 0 in the given equation to obtain the point where the line intersects the y-axis.

y = 0 - 2

y = -2

The point at the y-axis is (0, -2).

Step 2: Substitute y = 0 in the given equation to obtain the point where the line intersects the x-axis.

\(0 = -\frac{1}{3}x -2\\x = -6\)

The point at the x-axis is (-6, 0).

Step 3: Draw a straight line passing through both points.

Thus, the straight line \(y = -\frac{1}{3}x -2\) is plotted.

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Answer:

I think it is 0.51? (I am complety off aren't I/)

Step-by-step explanation:

Answer: -2a,-2b

Step-by-step explanation:

Therefore, the linear approximation estimates that f(1.9, 4.1) ≈ -144.7.

To find the linearization of the function f(x, y) = 96 - 3x^2 - 5y^2 at the point (2, 4), we need to calculate the partial derivatives with respect to x and y and evaluate them at the given point:

∂f/∂x = -6x, ∂f/∂y = -10y

Substituting x = 2 and y = 4 into these partial derivatives, we get:

∂f/∂x = -6(2) = -12, ∂f/∂y = -10(4) = -40

The linearization of the function f(x, y) at the point (2, 4) is given by:

L(x, y) = f(2, 4) + (∂f/∂x)(x - 2) + (∂f/∂y)(y - 4)

Substituting the values, we have:

L(x, y) = (96 - 3(2^2) - 5(4^2)) + (-12)(x - 2) + (-40)(y - 4)

Simplifying, we get:

L(x, y) = 40 - 12x - 40y

To estimate the value of f(1.9, 4.1) using the linear approximation, we substitute x = 1.9 and y = 4.1 into the linearization equation:

L(1.9, 4.1) = 40 - 12(1.9) - 40(4.1)

Calculating this expression, we find:

L(1.9, 4.1) ≈ -144.7

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The standard deviation of demand over the lead time is 23.72.

The demand over lead time is normally distributed with a mean of 80. The reorder point for a 95% service level is 119. To calculate the standard deviation of demand over the lead time, we need to use the following formula:

z = (x - μ) / σ, where z is the number of standard deviations from the mean, x is the reorder point for a 95% service level, μ is the mean of the distribution, and σ is the standard deviation of the distribution.

To solve for σ, we need to first find the z-score for a 95% service level, which can be obtained from the standard normal distribution table.

The z-score for a 95% service level is 1.645.

Substituting the given values in the formula, we get:

1.645 = (119 - 80) / σ

Solving for σ, we get:σ = (119 - 80) / 1.645

σ = 23.72

Therefore, the standard deviation of demand over the lead time is 23.72.

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Answer:

answer is the number 5

Step-by-step explanation:

First you square root 9 which is 3. Then u  3-1=  2.   then u times 2 by 6 which equals = 12. Then minus 7 from this number.    12-7=5            ur number is 5.

The answer to the given word problem is as follows. From the calculations: Johanna purchased

A word problem is a few phrases that describe a real-life scenario in which an issue must be solved using a mathematical computation.

The calculations is given as follows:

Step 1 -  First, let's define the variables to represent the unknowns.

Let p = number of pens

Let n = number of notebooks

Let h = number of highlighters

p + n + h = 17 ......................... 1  (purchased 17 items)

.5p + 4n + 1.5h = 41.5 ...................2 (total cost $41.50)

n = h+3  ................................3 (3 more notebooks than highlighters)

Step 2...............Solve for P in equation 1

P = 17 - n - h..................4

Recall that in equation 3,

n = h + 2

If we make n the subject of the expression, we have:

n = h+ 3

Substituting that into equation 4, we have

p = 17 - (h+3) - h
p = 17 -2h - 3 ..................5

Going back to equation 2, let's substitute n with h+3 and replace p with 17 -2h - 3

.5(17 -2h - 3) + 4 (h+3) + 1.5h = 41.5

To remove all decimals, we can multiply all with 10 to get:

5(170-20h -30) + 40(10h +30) + 15h = 415

Expand all brackets and we have:

850 - 100h - 150 + 400h + 1200 + 15h = 415

Collect like terms

-100h + 400h + 15h = 415-850+150-1200

315h = -1485

h = -1485/315

h = -4.71

Since a physical item cannot be negative, we utilize the absolute value which is:

h = 4.71

h \(\approx\) 5 highlighter

Recall that

n = h + 3

Hence

n = 5 +3 = 8 notebooks

Recall that

p + n + h = 17

Hence we have

p + 8 + 5 = 17

p = 17 -8 - 5

p = 17 - 13
P = 4 pens.

Hence Johanna purchased

4 pens, 8 notebooks and 5 highlighters.

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Answer:

94.2

Step-by-step explanation:

3*10=94.2

youre welcome

Answer:

261,7 in^3

Step-by-step explanation:

This time is a bit more difficult because we have to find the base area

Base area = radius^2 x π

in this case we have

5^2π = 25π = 78,5 in^2

now we can use the formula

(78,5 x 10) / 3 = 785/3 = 261,7 in^3

Answer: wow Ashley smh it’s Lorelei btw

Step-by-step explanation:

a. The initial size of the bacteria colony is 1 gram.

b. The growth rate for this bacteria colony is 25% per day.

c. The size of the bacteria colony after t days is given by the equation S(t) = 1 * e^(0.25t) grams.

d. To find when the colony size reaches 5 grams, we need to solve the equation 5 = 1 * e^(0.25t) for t. Taking the natural logarithm of both sides and rearranging, we get t = ln(5)/0.25 ≈ 8.7 days.

e. The doubling time for this colony is approximately 2.77 days, which is found by solving the equation 2 = 1 * e^(0.25t) for t. Taking the natural logarithm of both sides and rearranging, we get t = ln(2)/0.25 ≈ 2.77 days.

The law of uninhibited growth states that the growth rate of a population is proportional to its size, and there are no limiting factors that affect the growth. In this problem, the size of the bacteria colony is modeled using an exponential function, where the initial size of the colony is 1 gram and the growth rate is 25% per day.

To find the size of the colony after a certain number of days, we can substitute the given value of t into the equation S(t) = 1 * e^(0.25t). For example, after 5 days, the size of the colony is S(5) = 1 * e^(0.25*5) ≈ 2.28 grams.

To find when the colony size reaches a certain value, we need to solve the exponential equation S(t) = 1 * e^(0.25t) = A, where A is the desired size. Taking the natural logarithm of both sides and rearranging, we get t = ln(A)/0.25. For example, to find when the colony size reaches 5 grams, we solve the equation 5 = 1 * e^(0.25t) for t and get t = ln(5)/0.25 ≈ 8.7 days.

The doubling time is the time it takes for the population to double in size. In this case, we need to solve the exponential equation 2 = 1 * e^(0.25t) for t. Taking the natural logarithm of both sides and rearranging, we get t = ln(2)/0.25 ≈ 2.77 days.

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Answer: the answer is 8:1

Step-by-step explanation:

48:6/6

8:1

The probability that a randomly selected student majors in business or economics is 44.8%.

Let 'B' be the students of business.

P(B) = 35.1%

Let 'E' be the students of business.

P(E) = 12.3%

Thus,

P(E ∩ B) = 2.6%

P(E ∪ B) = probability for student majors in business or economics.

P(E ∪ B) = P(B) + P(E) - P(E ∩ B)

Put the values-

P(E ∪ B) = 35.1% + 12.3% -  2.6%

P(E ∪ B) = 44.8%

Thus, the probability that a randomly selected student majors in business or economics is 44.8%.

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The probability that 2 math majors and 2 computer science majors are chosen is 0.3778.

In a class of 18 students, there are 11 math majors and 7 computer science majors. Four students are randomly picked to prepare a demonstration on the use of a graphing calculator. Then the probability that 2 math majors and 2 computer science majors are chosen To solve the problem, we need to use combinations as the order in which the students are selected doesn't matter.                                                                                                                                      

The total number of ways of choosing 4 students out of 18 students is shown by :18C4 = (18 × 17 × 16 × 15) / (4 × 3 × 2 × 1) = 3060 The number of ways of choosing 2 math majors from 11 math majors is shown by :11C2 = (11 × 10) / (2 × 1) = 55 .The number of ways of choosing 2 computer science majors from 7 computer science majors is given by :7C2 = (7 × 6) / (2 × 1) = 21 Thus, the number of ways of choosing 2 math majors and 2 computer science majors out of 11 math majors and 7 computer science majors, respectively, is given by :55 × 21 = 1155 Therefore, the probability that 2 math majors and 2 computer science majors are chosen is :1155 / 3060 = 0.3778 (rounded to four decimal places)Thus, the probability that 2 math majors and 2 computer science majors are chosen is 0.3778.

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3060 possible groups of four students can be formed using a combination of math majors and computer science majors.

In a class of 18 students there are 11 math majors and 7 computer science majors. Four students are randomly picked to prepare a demonstration on the use of a graphing calculator.

We need to find out how many possible groups of four students can be formed using a combination of math majors and computer science majors.

We can apply the combination formula to find the number of possible combinations.

The combination formula is given as: C(n, r) = (n!)/(r!(n-r)!) Where, n is the total number of items available for selection, r is the number of items to be selected at a time C(n, r) is the number of possible combinations.

The number of math majors = 11

The number of computer science majors = 7

The total number of students = 18

We need to select a group of four students, therefore r = 4

The number of possible groups of four students can be formed using a combination of math majors and computer science majors is given by: C(18, 4) = (18!)/(4!(18-4)!)= (18 × 17 × 16 × 15)/(4 × 3 × 2 × 1) = 3060

Therefore, there are 3060 possible groups of four students that can be formed using a combination of math majors and computer science majors.

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Step-by-step explanation:

16.5 add all then divide

geologists unearth a sample of zircon that appears to be a closed system. they find 0.686 micro gram of 206 Pb for 1.000 micro gram of 238U present. approximately  3.7973 × 10⁹ years old is the sample.

The reciprocal of the time period during which the number of atoms in the radioactive element drops to almost A. 50% of its initial number is the decay constant.

According to the radioactive decay law, a nucleus's likelihood of decaying is a constant that is independent of time.

t1/2 of U₂₃₈ is 4.5 × 10⁹ years

moles of U₂₃₈ : (1 × 10⁻⁶ / 238) moles

moles of Pb₂₀₆ : (0.686 × 10⁻⁶ / 206) moles

Now, U₂₃₈ → Pb₂₀₆

As Pb₂₀₆ comes from U₂₃₈ hence,

moles of  U₂₃₈ decayed = moles of  Pb₂₀₆

                                        = (0.686 × 10⁻⁶ / 206) moles

Therefore, initial moles of U₂₃₈:

N₀ = [(1 × 10⁻⁶ / 238) + (0.686 × 10⁻⁶ / 206)] moles

and N = (1 × 10⁻⁶ / 238) moles

Now, λ (decay constant) = 0.693 / (t1/2)

                                        = 0.693 / ( 4.5 × 10⁹ years)

So,

t = 2.303 / λ × log (N₀ / N)

t = 2.303 / [0.693 / ( 4.5 × 10⁹ years)] × log [1 + (0.686/206)/(1/238)]

t = 14.95 × 10⁹ × 0.254

t = 3.7973 × 10⁹ years.

Thus, the sample is: 3.7973 × 10⁹ years old.

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(-x, -y, -z) the vector form (x, y, z) to the origin, in the direction of the greatest increase.

The quantity or amount of radiation contained in material or item, as measured by a temperature or sensed by touch and stated on a numerical scale.

The temperature T of a ball bearing is inverse to the length first from the origin, which we consider to be the center of the ball. The temperature at the exact location

(x, y, z) is a point on the sphere, the temperature at this point is given by

\(T(x,y,z)= \dfrac{k}{(x^2 +y^2+z^2)^{1/2}}\)

Where k is constant, then we have

T(1, 2, 2) = k/3 = 170

k = 510

So

\(T(x,y,z)= \dfrac{510}{(x^2 +y^2+z^2)^{1/2}}\)

Then we have

\(\rm \triangledown T = \left ( -\dfrac{510x}{(x^2 +y^2+z^2)^{1/2}}, -\dfrac{510y}{(x^2 +y^2+z^2)^{1/2}}, \dfrac{510z}{(x^2 +y^2+z^2)^{1/2}} \right )\\\\\\\triangledown T (1, 2, 2) = -\dfrac{510}{27} (1, 2, 2) =-\dfrac{170}{9} (1, 2, 2)\)

Then the direction will be from (1, 2, 2) to (4, 3, 5) will be (3, 1, 3)

So u = (3/√19, 1/√19, 3/√19)

Then we get

\(\rm \triangledown T \cdot u = \dfrac{-170}{9}(1, 2, 2) \cdot \left (\dfrac{3}{\sqrt{19}}, \dfrac{1}{\sqrt{19}}, \dfrac{3}{\sqrt{19}} \right )\\\\\\\triangledown T \cdot u = - \dfrac{170}{9\sqrt{19}} (3 + 2 + 6)\\\\\\\triangledown T \cdot u = -\dfrac{1870}{9\sqrt{19}}\)

The direction of the greatest inverse in the temperature is given by any vector parallel to and having the same direction \(\triangledown\)T. (-x, -y, -z) the vector form (x, y, z) to the origin, in the direction of the greatest increase.

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The weightage is given to the most recent values in the time series.

SES is a simple forecasting technique that is easy to implement and can be used with data that has a consistent trend. However, it is not well suited for data that is highly volatile or has a lot of noise.

One of the simplest forecasting techniques is single exponential smoothing (SES). It is a weighted average of past time-series values, where the weightage is given to the most recent values in the time series. This technique is easy to implement and can be used with data that has a consistent trend. However, it is not well suited for data that is highly volatile or has a lot of noise.

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To answer these questions, we need to use the formula for the uniform distribution, which is:
f(x) = 1/(b-a)
where a is the lower bound of the distribution and b is the upper bound.

a. To find the probability that a randomly selected videotape will be returned between 3 and 4 days late, we need to calculate the area under the curve between 3 and 4 on the x-axis. Since the uniform distribution is a rectangle, the area of the rectangle is equal to the height times the width. In this case, the height is f(x) = 1/(4-0) = 0.25 and the width is 4-3 = 1. Therefore, the probability is:
P(3 ≤ x ≤ 4) = height × width = 0.25 × 1 = 0.25
So the answer is 0.25.

b. To find the probability that a randomly selected videotape will be returned more than 1 day late, we need to calculate the area under the curve to the right of 1 on the x-axis. Since the distribution is uniform, the area to the right of 1 is equal to the width of the rectangle from 1 to 4, which is 4-1 = 3. Therefore, the probability is:
P(x > 1) = 3/(4-0) = 0.75

So the answer is 0.75.
In summary, the probability that a randomly selected videotape will be returned between 3 and 4 days late is 0.25, and the probability that a randomly selected videotape will be returned more than 1 day late is 0.75.

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Answer:

$12 per shirt

Step-by-step explanation:

$300/25=$12

Answer:

11.96 per shirt

Step-by-step explanation:

299/25 = 11.96 you do this instead of 300/25 because it says less than 300

Answer:

2.5

Step-by-step explanation:

Eric's demand for fish tacos increased by 50% when his income increased by 20%.

An income elasticity of demand greater than 1 indicates a normal good, while an income elasticity of demand less than 1 indicates an inferior good.

To calculate the income elasticity of demand for fish tacos, you need to divide the percentage change in the number of fish tacos demanded by the percentage change in income.

As per the question, the number of fish tacos demanded increased by 50% (15 - 10 = 5, and 5 / 10 = 0.5), and the income increased by 20% ($600 - $500 = $100, and $100 / $500 = 0.2).

So, the income elasticity of demand is 0.5 / 0.2 = 2.5.

This means that when Eric's income increased by 20%, the number of fish tacos he demanded increased by 50%.

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The area of the figure are as follows:

area of the figure = 4x + 4

area of the figure = 7d + 28

area of the figure = y² + 3y

The figures above are rectangle.

Therefore,

area of a rectangle = lw

where

Hence,

4. area of the figure = 4x + 4 × 1 = 4x + 4

5. area of the figure = 7d + 7 × 4 = 7d + 28

6. area of the figure = y² + 3 × y = y² + 3y

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Answer:

it is a

171 degrees

Step-by-step explanation:

Answer:

171

Step-by-step explanation:

Answer:

2 terms the terms are x and y

Answer:

Cry Shape Hearty

Step-by-step explanation:

Cry Shape Hearty

The expected number of classes a student will take in a given semester is 1.89

Expected value is defined as the predicted value of a variable, calculated as the sum of all possible values each multiplied by the probability of its occurrence.

Given :

x|  0       1        2       3      45  

p| 0.4 0.25  0.15  0.08  0.02

where x = number of classes

p = probability

The expected value of x, E(x) =Σ xp

E(x) = (0×0.4) + (1×0.25) + (2×0.25) + (3×0.08) + (45×0.02)

E(x) = 0 + 0.25 + 0.5 + 0.24 + 0.9

E(x) = 1.89

Therefore, the expected number is 1.89.

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The matrix A that represents the set W, consisting of vectors of the form [r, s, t] with real numbers, is constructed by organizing the coefficients of r, s, and t as the columns of A. The resulting matrix A is given by A = [0 0 2 48; s 2 1 0; 0 -5 1 0; 0 0 0 1]

Let's break down the construction of matrix A step by step.

Given that W is the set of all vectors of the form [r, s, t] where r, s, and t are real numbers, we want to find a matrix A such that the column space of A (Col(A)) represents W.

The matrix A will have as its columns the coefficients of r, s, and t in the given expression.

Column 1 of A: Coefficients of r

In the expression, we have 5sr + 3t, so the coefficient of r is s. Therefore, the first column of A will be [0, s, 0, 0] since there is no r term in the expression.

Column 2 of A: Coefficients of s and t

In the expression, we have 2sr - 5t. The coefficient of s is 2, and the coefficient of t is -5. Therefore, the second column of A will be [0, 2, -5, 0] with the corresponding coefficients.

Column 3 of A: Coefficients of r, s, and t

In the expression, we have 2r + s + t. The coefficients of r, s, and t are 2, 1, and 1, respectively. Therefore, the third column of A will be [2, 1, 1, 0] with the corresponding coefficients.

Column 4 of A: Coefficients of r and t

In the expression, we have 48r + t. The coefficient of r is 48, and the coefficient of t is 1. Therefore, the fourth column of A will be [48, 0, 0, 1] with the corresponding coefficients.

Putting it all together, the matrix A that represents W = Col(A) is:

A = [ 0 0 2 48 ]

[ s 2 1 0 ]

[ 0 -5 1 0 ]

[ 0 0 0 1 ]

Each column of A corresponds to the coefficients of r, s, and t in the given expression, forming the column space that represents the set W.

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Answer: All Real Numbers Are Solutions