What is the SI unit that is equal to 0.01 meters?

s = 40m - 4m = 36m

W = F × s

= 10N × 36m = 360J

W = Work (J)

F = Force / weight (N)

s = distance (m)

Work done in physics is the product of force and displacement. The displacement for the object is 36 m and force acts on it is 10 N. Then the work done is 360 J.

Work done is the dot product of force acting on a body and the resultant displacement. When a force applied on an object results in a displacement from its position, the force is said to be work done.

Work done is a vector quantity thus, characterised by a magnitude and direction.  The common unit of work done is joule.

Given that force applied on the weight = 10 N

displacement occurred = 40 m - 4 m = 36 m

Work done = F . ds

ds = 36 m and f = 10 N

Then W = 10 N × 36m

             = 360 J.

Therefore, the work is required to lift a 10-newton weight from 4.0 meters to 40 meters above the surface of Earth is 360 J.

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The average distance from mars to the sun if Mars had an orbital period of 1.88 years is 2.27 * \(10^{8}\) km

P² = a³

P = Orbital period

a = Average distance

P = 1.88 years

a³ = 1.88²

a³ = 3.53

a = 1.52 AU

a = 1.52 * 1.496 * \(10^{8}\) km

a = 2.27 * \(10^{8}\) km

The formula used to solve the given problem is derived from Kepler's third law of planetary motion. AU is the abbreviated from of Astronomical unit. 1 AU = 1.496 * \(10^{8}\) km

Therefore, the average distance from mars to the sun is 2.27 * \(10^{8}\) km

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Answer:

Unsaturated Solution: Less amount of salt in water, clear solution, no precipitation. Saturated Solution: The maximum amount of salt is dissolved in water, Colour of the solution slightly changes, but no precipitation. Supersaturated Solution: More salt is dissolved in water, Cloudy solution, precipitation is visible.

when Force (N) is 10.0 Length (m) is 0.60

when Force (N) is 8.0 Length (m) is 0.40

when Force (N) is 4.0 Length (m) is 0.20

when Force (N) is 4.0 Length (m) is 0.20

when Force (N) is 2.0 Length (m) is 0.10

chatgpt

49. To find the length of a pendulum that has a period of 2.3 seconds on the Moon, where the gravitational acceleration (g) is 1.6 N/kg, we can use the formula:

Period (T) = 2π√(Length (L) / g)

Substituting the given values:

2.3 = 2π√(L / 1.6)

To solve for L, we can rearrange the formula:

L = (2.3 / (2π))^2 * 1.6

L ≈ 0.781 meters (or 78.1 centimeters)

So, the pendulum must be approximately 0.781 meters (or 78.1 centimeters) long to have a period of 2.3 seconds on the Moon.

50. Ranking Task:

To rank the pendulums according to their periods, we need to consider both the length and mass of each pendulum.

Ranking from least to greatest period:

1. A: 10 cm long, mass = 0.25 kg

2. C: 20 cm long, mass = 0.25 kg

3. B: 10 cm long, mass = 0.35 kg

There is a tie between pendulums A and C, as they have the same length but different masses.

Based on Newton's first  and second law of motion most people would find it less painful to catch a flying baseball than a bowling ball flying at the same speed as the baseball because the mass of the baseball is smaller and will require smaller force to be stopped.

Newton's first law of motion first law of motion states that a body at rest or uniform motion in a straight line will continue in that path unless acted upon by an external force.

Newton's first law of motion is also called law of inertia because it depends on mass of the object.

An object with a greater mass will require greater force to be stopped or get moving.

Based on Newton's first law of motion most people would find it less painful to catch a flying baseball than a bowling ball flying at the same speed as the baseball because the mass of the baseball is smaller and will require smaller force to be stopped.

Also according to Newton's second law of motion, the force applied to an object is proportional to the product of mass and acceleration of the object. Thus, a baseball with smaller mass will require smaller force to be stopped.

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Answer:

Acceleration.

Explanation:

In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.

This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.

Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.

Mathematically, acceleration is given by the equation;

\(Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}\)

\(a = \frac{v - u}{t}\)

Where,

a is acceleration measured in \(ms^{-2}\)

v and u is final and initial velocity respectively, measured in \(ms^{-1}\)

t is time measured in seconds.

Hence, in a velocity-time graph, acceleration is represented by the slope, or steepness, of the graph line.

The final velocity of the 25.8 g marble after the collision is 16.15 cm/s.

The velocity of the 25.8 g marble after the collision is calculated as follows;

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

where;

The final velocity of the 25.8 g marble after the collision is calculated as;

( 25.8 x 21 ) + ( 12.4 x 13.8 ) = ( 12.4 x 23.9 ) + ( 25.8v )

712.92 = 296.36 + 25.8v

25.8v = 416.56

v = 416.56 / 25.8

v = 16.15 cm/s

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Answer:

A. gravitational force always true.

B, C and D could be true under the correct conditions

Answer:

Half

Explanation:

If the half life of an isotope is 20 years, then half of the original amount will  remain after 20 years has passed.

That's what "half-life" means.

Similarly, after ANOTHER 20 years, 1\4 of the original amount remains.

And after ANOTHER 20 years, 1\8 of the original amount remains.

And after ANOTHER 20 years, 1\16 of the original amount remains.

And after ANOTHER 20 years, 1\32 of the original amount remains.

And after ANOTHER 20 years, 1\64 of the original amount remains.

And after ANOTHER 20 years, 1\128 of the original amount remains.

1 km = 1000 m

1 hr = 3600 s

So, 18 km/hr = (18 * 1000) / (3600) m/s = 5 m/s

And 2 m/s^2 = 2 m/s^2

Now, we can use the formula for final velocity (v) when an object starts with an initial velocity (u) and accelerates at a constant rate (a) for a given time (t):

v = u + at

Plugging in the values, we get:

v = 5 + (2 * 5) m/s v = 15 m/s

To convert this back to km/hr, we use the inverse conversions: v = (15 * 3600) / (1000) km/hr v = 54 km/hr

Therefore, the car’s velocity in km/hr after 5 seconds is 54 km/hr.

Answer:

identify who they are as a person

Explanation:

Answer:

hey so this website called quiz-let helps you it will give u the answer for every question i use it sometimes when im confused on a test.

It takes 0 seconds for the catcher to stop the ball and the ball travels 0 meters before stopping.

To find the time it takes for the catcher to stop the ball, you can use the equation:

time = distance / velocity

In this case, the distance is zero (since the ball is stopped) and the velocity is 21.80 m/s. Plugging these values into the equation gives us:

time = 0 / 21.80

time = 0 s

So, it takes 0 seconds for the catcher to stop the ball.

To find the distance the ball travels before stopping, you can use the equation:

distance = 1/2 * acceleration * time^2

In this case, the acceleration is the force applied to the ball divided by the mass of the ball, or (-360 N) / (0.18 kg) = -2000 m/s^2. The time is the time it takes the ball to stop, which we just found to be 0 s. Plugging these values into the equation gives us:

distance = 1/2 * (-2000 m/s^2) * (0 s)^2

distance = 0 m

So, the ball travels 0 meters before stopping.

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Explanation:

Given: Required: solution:

k=25N/m PE ? PE= 1/2 × KX²

X= 5m 1/2 × (25)(5)²

= 312.5 J

The required choice is for both the lines are conductor and conductor.

A conductor is something that easily allows current to flow through it. As an example, consider metal or any other metal. An insulator is something that does not allow current to travel through it. Polyurethane is an example.

Here,
Inside each socket are two pairs of metal strips that are engineered to bend and flex but return to their original shape when pressure is released. Each pair of strips is linked to one of your power lines (either hot or ground).

When you insert the wall plug, springy brass fingers hold the plug prongs, allowing you to connect to your home's electrical system.

Thus, the required choice is for both the lines to be conductor and conductor.

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Newton's second law allows finding the result for the comparison of the rise and fall times of the block on the ramp is:

Newton's second law establishes a relationship between the net force, the masses and the acceleration of the bodies.  

         ∑ F = m a

Where the bold letters indicate vectors, F is the force, m the mass and the acceleration of the body.

The reference system is a coordinate system with respect to which the forces are drawn, in the attached we can see a free body diagram of the block going up and down the ramp, in this case the x axis is parallel to the ramp and the y axis it is perpendicular.

Let's use trigonometry to find the components of weight.

         sin θ = \(\frac{W_x}{W}\)  

         cos θ = \(\frac{W_y}{W}\)  

         Wₓ = W sin θ

          \(W_y\) = W cos θ

Let's write Newton's second law for each axis.

Case 1. block slides down.

x- axis

         Wₓ = ma

         mg sin θ = ma

         a = g sin θ

Case 2. block rises

X axis

         - Wₓ = m a

         - m gsin θ = a

          a = - g sin θ

We can see that the acceleration is the same in two two cases, if the block has the same initial speed, the rise and fall time is the same.

           y = v₀ t - ½ a t²

            y = ½ a t²

In conclusion using Newton's second law we can find the result for the comparison of the rise and fall times of the block on the ramp is:

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Answer:

The weight required to stretch a wire can be calculated using the formula:

W = (π/4) x d^2 x L x S

where:

d = diameter of the wire

L = length of the wire

S = stress applied to the wire

π = pi (3.14)

In this case, the wire has a diameter of 1.0 millimeters and a length of 1.0 meters. We want to stretch it by 3.0 millimeters, which means the stress applied to the wire is:

S = ΔL / L = 3.0 / 1000 = 0.003

Now we can plug in the values and calculate the weight required:

W = (π/4) x (1.0)^2 x 1.0 x 0.003

W = 0.0002355 kg or 0.2355 grams

Therefore, we need to add 0.2355 grams of weight to the free end of the wire to stretch it by 3.0 millimeters.

The answers are 1) The value of R2 is not relevant as it implies a downward force on the plank, 2) The reactions at C and D are 66.3 N and 90 N, respectively, and 3) The vertical force at B to lift the plank clear of D is 686.4 N. The reaction at C is zero, and the reaction at D is 61.4 kg.

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Answer:

The value  is \( |P| =  187.4 \ N\)

Explanation:

From the question we are told that

   The length of the first rope is  L  =  6 m

    The first rope lie on the x-axis

   The end point of the first rope is  A  

   Now the vector of  A will be \(\vec {OA}=  6i\)

   The point of the second rope on the wall is  B

   The coordinate for the point of the second rope on the wall is  (0,-1,2)

   The vector of B will be  \(\vec {OB} =  -j+2k\)

Now the coordinate of rope AB is mathematically represented as

    \(\vec {AB} =  \vec{OB} -\vec{OA}\)

=>   \(\vec {AB} =  -j+2k -6i\)

=>   \(\vec {AB} =  -6i -j+2k \)

Generally the magnitude of the rope AB is mathematically evaluated as

       \(|\vec{AB}| = \sqrt{(-6^2) +(-1)^2 + (2)^2}\)

       \(|\vec{AB}| = \sqrt{41} \ m \)

Generally the unit vector rope AB is mathematically evaluated as

       \(\vec r = \frac{\vec {AB}}{|\vec{AB}|}\)

=>     \(\vec r =  \frac{1}{\sqrt{41} } * [-6i -j+ 2k]\)

From the question we are told that there is a force acting at point A and the force is  

    \(F = 400 i - 200 j + 500 k\)

Generally the projected component of this force (in N) acting along the rope AB is mathematically represented as

         \( P =  \vec F \cdot  \vec r\)

=>      \(  P  = 400 i - 200 j + 500 k  \ * \  \frac{1}{\sqrt{41} } * [-6i -j+ 2k]\)

Note ( i . i = 1  ) , (j . j  = 1) , (k . k  = 1)

So    \(P =  \frac{1}{\sqrt{41} } [-400 * 6 + 200 * 1 + 500 *2]\)

=>   \(P =  -187.4 \ N\)

So the magnitude of the projected component of this force (in N) acting along the rope AB is  

    \( |P| =  187.4 \ N\)

Answer:

a) 14.76 psi

b) 15.59 psi

c) 15.68 psi

d) The solution method is reasonable

Explanation:

The formula for maximum pressure is given as using Bernoulli's Equation :

Pmax = p + 1/2ρV²

Where ρ = Density = 0.002376slug per cubic foot

p = Atmospheric pressure in pounds per cubic foot = 14.6959 pounds per square inch

Converting pounds per square inch to pounds per square foot

= 1 pounds per square inch = 144 pounds per square foot

14.6959 pounds per square inch =

14.6959 pounds per square inch × 144 pounds per square foot

= 2116.2096 pounds per square foot

V = Velocity of the flow = Speed limit.

(a) For safety, the pit lane speed limit is 60 mph. At this speed, what is the maximum pressure on his hand?

Our speed limit is 60 mph

We convert to ft/s

1 mph = 1.46667 ft/s

60 mph =

60 mph × 1.46667 ft/s = 88 ft/s

Pmax = p + 1/2ρV²

Pmax = 2116.2096 + (0.5 × 0.002376 × 88²)

Pmax = = 2125.409472 Ib/ft² =

Converting to psi.

= 2125.409472/144

= 14.759788 psi

≈ 14.76 psi

(b) Back on the race track, what is the maximum pressure when he is driving his IndyCar at 225 mph?

Our speed limit is 225 mph

We convert to ft/s

1 mph = 1.46667 ft/s

225 mph =

225 mph × 1.46667 ft/s = 330 ft/s

Pmax = p + 1/2ρV²

Pmax = 2116.2096 + (0.5 × 0.002376 × 330²)

Pmax = 2245.5828 Ib/ft² =

Converting to psi.

= 2245.5828/144

= 15.594325 psi

≈ 15.59 psi

(c) On the straightaways, the IndyCar reaches speeds in excess of 235 mph.

Our speed limit is 235 mph

We convert to ft/s

1 mph = 1.46667 ft/s

235 mph =

235 mph × 1.46667 ft/s = 344.667 ft/s

Pmax = p + 1/2ρV²

Pmax = 2116.2096 + (0.5 × 0.002376 × 344.667²)

Pmax = = 2257.338465 Ib/ft² =

Converting to psi.

= 2257.3384654/144

= 15.675961562 psi

≈ 15.68 psi

d) For this speed, is your solution method for parts (a and (b) reasonable? Explain.

It is important to note that: the value of 1 atmosphere = 14.696 psi

If we look at the solution above, we can see that the maximum pressure of the speeds in question a, b, c which are: 14.76 psi, 15.59 psi, 15.68 psi respectfully are just a little bit outside the range of 1 atmosphere.

Hence, this is not significant enough to cause damage or harm the hands of Tony Kanaan therefore, my solution method for parts (a and (b) reasonable is reasonable.

The amplitude of the graph is 4. Option D.

Amplitude refers to the maximum displacement or distance from the rest position of a vibrating object or wave. In other words, it measures the strength or intensity of the vibration or wave.

For sound waves, it determines the loudness of the sound, while for light waves, it affects the brightness of the light.

In the graph, the maximum amount of displacement of the wave is 4.

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The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.

The p-waves travel with a constant velocity of 7 km/s

The time can be calculated by using the formula

t = d / v

where

T1 =  10:05 a.m

d is the distance they take to travel from the epicenter

v is the speed of the p-waves

On average, the speed of p-waves is

v = 7 km/s

d = 5600 km (given)

Substituting the values in the formula;

t = d / v

t = 5600 ÷ 7

t = 800 seconds

Converting into minutes,

t = 800 ÷ 60

t = 13.3

≈ 13 mins

T1 -  13 mins = T2

10:05 - 13 mins = 9.52 am

It means the earthquake occurred prior 13 minutes, that is at 9.52 am.

Therefore, the earthquake occurred at 9.52 am.

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Answer:

Explanation:

In the microscopic world of quantum mechanics, particles don't behave like familiar everyday objects. They can exist in multiple states simultaneously and behave as both particles and waves. When we try to measure or observe a particle, we typically use light or other particles to interact with it. However, this interaction can disturb the particle's state. Imagine trying to measure the position of an electron using light. Light consists of photons, and when photons interact with the electron, they transfer energy to it. This energy exchange causes the electron's position and momentum to become uncertain. The more precisely we try to measure its position, the more uncertain its momentum becomes, and vice versa. This is known as the Heisenberg uncertainty principle.

So, the act of observing a particle disturbs its state because the interaction between the observer and the particle affects its properties. The very act of measurement or observation introduces a level of uncertainty and alters the particle's behavior. It's important to note that this behavior is specific to the quantum world and doesn't directly translate to the macroscopic world we experience in our daily lives. Quantum mechanics operates at extremely small scales and involves probabilities and uncertainties that are not typically noticeable in our macroscopic observations.

a. The free-body diagrams of the 8.0 kg box and the 2.0 kg mass is attached below.

bi) the acceleration of the system is 0.4 m/s^2

bii)  the tension in the string is 0.8 N.

Net force = ma

Net force = T - F_friction

where T is the tension force and F_friction is the frictional force.

Substituting the given values, we have:

T - F_friction = ma

T - 6.0 N = (8.0 kg + 2.0 kg) a (since the tension force acts on both masses)

T - 6.0 N = 10.0 kg a

(ii) To find the tension in the string, we can apply Newton's second law of motion to the 2.0 kg mass:

Net force = ma

where m is the mass of the mass and a is the acceleration of the system. The net force on the mass is the tension force:

Net force = T

Substituting the given values, we get:

T = ma

T = 2.0 kg x a

To solve for T, we need to find the acceleration of the system.

To find both a and T, we can use the equations we derived above and solve them simultaneously:

T - 6.0 N = 10.0 kg a (equation 1)

T = 2.0 kg x a (equation 2)

Substituting equation 2 into equation 1, we get:

2.0 kg x a - 6.0 N = 10.0 kg a

Solving for a, we get:

a = 0.4 m/s^2

Substituting a into equation 2, we get:

T = 2.0 kg x 0.4 m/s^2 = 0.8 N

Therefore, the acceleration of the system is 0.4 m/s^2 and the tension in the string is 0.8 N. of the system is 0.4 m/s^2 and the tension in the string is 0.8 N.

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Hooke's Law can be given as follows sometimes:

The restoring force of a spring is equal to the spring constant multiplied by the displacement from its normal position:

F = -kx

Where, F = Restoring force of a spring (Newtons, N)

k = Spring constant (N/m)

x = Displacement of the spring (m)

The negative sign relates to the direction of the applied force and by convention, the minus or negative sign is present in F = -kx. The restoring force F is directly proportional to the displacement (x), according to Hooke's law. When the spring is compressed, the displacement (x) is negative. It is zero when the spring is at its original length and positive when the spring is extended.

Practically, Hooke's Law is applicable only within a limited frame of reference, and through experimenting, this statement proves to be true. Because materials cannot be compressed beyond a certain size or expanded beyond a certain size without some permanent deformation or change of their original state.

The law only applies under some conditions such as a limited amount of force or deformation. Factually, many materials will noticeably deviate from Hooke's law even before those elastic limits are reached.

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when having the time and the velocity we can find the traveled distance by applying the formula:

so

Step 1

a)let

now, we need to convert the time ,from years into seconds, to do that, let's use equivalent fractions

b) now, replace in the formula

therefore, the answer is

I hope this helps you

Answer: The are both attempts to explain natural phenomena is what ima say.

Explanation: I hope this is right an di hope this helps.

Answer:

To convert nanometers (nm) to picometers (pm), you need to multiply the value by 1,000. Therefore, to convert 12 nanometers to picometers, you would perform the following calculation:

12 nm * 1,000 pm/nm = 12,000 pm

So, 12 nanometers is equal to 12,000 picometers.