What is the solution, if any, to the inequality |3×| > 20?

The class width used for the frequency distribution is 6.

The class midpoint for the class 23-29 is 26.

The class midpoint for the class 30-36 is 33.

The class midpoint for the class 37-43 is 40.

To find the class width of the frequency distribution, we need to determine the range of each age class. The range is the difference between the upper and lower boundaries of each class. Looking at the table, we can see that the class boundaries are as follows:

23-29

30-36

37-43

For the class 23-29, the lower boundary is 23 and the upper boundary is 29. To find the class width, we subtract the lower boundary from the upper boundary:

Class width = 29 - 23 = 6

So, the class width for the frequency distribution is 6.

To find the class midpoint for each class, we take the average of the lower and upper boundaries of each class.

For the class 23-29:

Class midpoint = (23 + 29) / 2 = 52 / 2 = 26

For the class 30-36:

Class midpoint = (30 + 36) / 2 = 66 / 2 = 33

For the class 37-43:

Class midpoint = (37 + 43) / 2 = 80 / 2 = 40

So, the class midpoint for the class 23-29 is 26, for the class 30-36 is 33, and for the class 37-43 is 40.

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Answer:

x=3 y=-2

Step-by-step explanation:

Elimination would bring the equation to

3x=18

18/6 is 3

6-3y=12

-3y=6

y=-2

y= (-3x+6)2

For parallel lines, slopes are the same,

y = mx + c

Substitute the values,

3 = (-3/2)(-2) + c

3=3 + c,

c = 0

Thus, the equation is y= -3/2x

Hope it helps :)

Required correct options are having cereal for breakfast more often is associated with having more bowls to wash, owning more chickens is associated with having more eggs, none of them respectively.

The relationship that most likely reflects correlation but not causation is "Having cereal for breakfast more often is associated with having more bowls to wash." There is a correlation between eating cereal for breakfast and having more bowls to wash, but eating cereal does not cause the increase in dirty dishes.

The relationship that most likely reflects both correlation and causation is "Owning more chickens is associated with having more eggs." There is a clear causal relationship between owning chickens and having more eggs, as the chickens lay the eggs.

The relationships that are left are:

Frying eggs more often is associated with cooking bacon more often.

Owning more goats is associated with owning more sheep.

Owning more horses is associated with having a larger stable.

Eating hot dogs more often is associated with eating coleslaw more often.

Eating sandwiches more often is associated with eating bread more often.

Eating burgers more often is associated with eating french fries more often.

None of these relationships can be definitively classified as reflecting only correlation or both correlation and causation without additional information. However, some of them are more likely to reflect causation than others based on common sense and prior knowledge. For example, the relationship between frying eggs more often and cooking bacon more often is likely to reflect a causal relationship, as it makes sense that someone who frequently cooks eggs would also frequently cook bacon to go with them.

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Answer:

123.7 meters

Step-by-step explanation:

If you draw a diagram, this will be a rectangle and the line across cuts it into a right triangle, with a base of 120 and a height of 30. The need to know the length of the hypotenuse of the triangle, so we can use the pythagorean theorem.

30^2 + 120^2 = c^2

c=123.7

Notice that 25 p^2 - 144 is what is called a "difference of squares", because 25 = 5^2 , p^2 is the square of "p", and 144 is the same as 12^2

Then we use the factoring form for a difference of squares given by:

a^2 - b^2 = ( a - b) (a + b)

with in our case: a = 5 p, and b = 12

so we have:

25 p^2 - 144 = (5 p)^2 - (12)^2 = (5p - 12) (5 p + 12)

We need to factor the expression:

- 2 x^2 + 32

so we proceed to extract all common factors (this time there are only numerical factors: "2" is the only one .

2 (- x^2 + 16) = 2 (16 - x^2)

notice now that the expression in parenthesis is a "difference of squares" that can be factored using the factor form be used above. Then we end up with the following factors:

2 (4 - x) (4 + x)

since 16 = 4^2 and x^2 is the square of "x".

Answer:

there is no attachments but   The mean (average) of a data set is found by adding all numbers in the data set and then dividing by the number of values in the set. The median is the middle value when a data set is ordered from least to greatest. The mode is the number that occurs most often in a data set.

Step-by-step explanation:

The least restrictive assumption T2 + 0 and T3 # 0

What is structural model?

The items in the system and the static relationships that connect them make up the structural model. Packages or subsystems can be used to divide up groups of items. The structural model is described in object model diagrams. The code that is produced from object model diagrams is described in this section.

It looks like the question you provided contains multiple parts and is discussing the use of instrumental variables (IVs) in regression analysis.

An instrumental variable (IV) is a variable that is correlated with the independent variable in a regression model, but is not correlated with the error term. It is used to estimate the effect of the independent variable on the dependent variable, while controlling for omitted variables that may be correlated with both the independent and dependent variables.

In the question, y2 is the dependent variable, z1 is the endogenous explanatory variable (i.e., the independent variable that is correlated with the error term), and z2 and z3 are the exogenous explanatory variables that are excluded from the model. The reduced form equation for y2 is an equation that expresses y2 as a function of the exogenous explanatory variables and the error term.

The least restrictive assumption we need to impose on the T parameters in order for the instrument y5 to not be perfectly correlated with z1 is T2 + 0 and T3 # 0. This means that the effect of y5 on y2 must not be perfectly correlated with the effect of z1 on y2.

The least restrictive assumption T2 + 0 and T3 # 0

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Answer:

Answer is 9 feet = 9 fe 2t

w= 9fe 2t

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

Answer:

The length of the three sides \(5, \sqrt{58} , \sqrt{65}\)

The triangle is not a right triangle

Step-by-step explanation:

A = (3, 2) , B = ( 6, 9) , C = (10, 6)

Find the lengths using distance formula.

\(distance = \sqrt{(x_2 -x_1)^2 + (y_2 - y_1)^2}\)

\(AB = \sqrt{(6-3)^2 + (9-2)^2} = \sqrt{9 + 49 } = \sqrt{58}\)

\(BC = \sqrt{(10-6)^2 + (6-9)^2} = \sqrt{16 + 9} = \sqrt{25} = 5\)

\(AC = \sqrt{(3-10)^2+(2-6)^2} = \sqrt{49 + 16} = \sqrt{65}\)

Using Pythagoras theorem :

\((Longer \ side)^2 = sum \ of \ square \ of \ two \ other \ sides\)

Longest side is AC . So we will check if it satisfies Pythagoras theorem :

\(\sqrt{65} = \sqrt{58} + 5^2\\65 = 58 + 25\\\)

65 ≠ 58 + 25

So the sides does not satisfy Pythagoras theorem. Hence the triangle is not a right triangle.

a. The missing values of the logarithm expression is log₃(40).

b. The missing values of the logarithm expression is log₅(8).

c. The missing values of the logarithm expression is  log₂(1/25).

The missing values of the logarithm expression is calculated as follows;

(a). log₃5 + log₃8, the expression is simplified as follows;

log₃5 + log₃8 = log₃(5 x 8) = log₃(40)

(b). The log expression is simplified as;

log₅3 - log₅X = log₅3/8

log₅X = log₅8

X = 8

(c).  The log expression is simplified as;

-2log₂5 = log₂Y

log₂5⁻² = log₂Y

5⁻² = Y

1/25 = Y

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Answer:

Not sure what the question is but the equation would be

\(c^{2} = a^{2} + b^{2}\)

\(28^{2} = 20^{2} + b^{2}\)

and to find the missing side

784 = 400 + \(b^{2}\)

b= 19.6

The missing side would be 19.6

Answer:

19.6

Step-by-step explanation:

u see this is how the Pythagorean theorem works a^2 + b^2 = c^ i hope this helps have a great day bye please mark as brainliest :D

Solution:

Note that:

Using the equation (4x - 27 = 3x + 4), solve for x.

The measure of x is 31.

Solve for X ~

\( \bf4x - 27 = 3x + 4\)

\( \bf \: 4x - 3x = 4 + 27\)

\( \boxed{ \bf \: x = 31}\)

\( \tt \: ∠1 = 2x + 21 \\ \tt \: = 2 \times 31 + 21 \\ \tt \: ∠1= 83 \degree\)

\( \tt \: ∠2 = 4x + 27\\ \tt \: = 4\times 31 - 27 \\ \tt \: ∠2= 97 \degree\)

\( \tt \: ∠3 = 3x + 4 \\ \tt \: = 3\times 31 + 4 \\ \tt \: ∠3= 97 \degree\)

#7 is B, the trapezoid is reflected across the x axis

#8 is C, unlike D, answer C is still the same shape as triangle A. Answer A is just the same triangle in the same position, can't tell if it moved or not bc it never showed us. B is a reflection, it's flipped.

#9 is D, nothing has changed except it's position; it's been moved to the right

#10 is C, the points of the triangle are at different positions, and it didn't look like it flipped over the x or y axis, so it's reflection. It's also moved to the right, so translation

Hope this helped

Answer:

direct proof, proof by contradiction, and proof by induction.

The solution to the linear system is c = -6 and d = 3.

To solve the linear system using the elimination strategy, we can eliminate one variable by adding or subtracting the equations. Let's solve the first linear system:

(1) 12c + 28d = 12

(2) -20c + 16d = 168

To eliminate one variable, we can multiply equation (1) by 5 and equation (2) by 3, which will result in opposite coefficients for 'c'. This will allow us to eliminate 'c' when adding the equations together:

(1) 60c + 140d = 60

(2) -60c + 48d = 504

Now, we can add the equations:

(60c + 140d) + (-60c + 48d) = 60 + 504

188d = 564

d = 564/188

d = 3

Substituting the value of 'd' back into equation (1):

12c + 28(3) = 12

12c + 84 = 12

12c = 12 - 84

12c = -72

c = -72/12

c = -6

The solution to the linear system is c = -6 and d = 3.

Now let's analyze the second linear system:

(1) 7x - 3y = 43

(2) 7x - 3y = 13

By comparing the two equations, we can see that they have the same coefficients for both 'x' and 'y', and the constant terms on the right side are different. This means the lines represented by the equations are parallel and will never intersect.

The linear system has no solution.

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Answer: 45

Step-by-step explanation:

\(f(-5)=2(-5)^{2} -5\)

\(f(-5)= 2(25) -5\)

\(f(-5) = 50-5\)

\(f(-5) = 45\)

the length of side a is 91 ft (rounded to the nearest whole foot) and the length of side b is 132 ft (rounded to the nearest whole foot). The area of the triangle is approximately 6007 sq ft.

Given: The hypotenuse of the right triangle,

c = 159 ft; angle A = 34°

We know that, in a right-angled triangle:

\($$\sin\theta=\frac{\text{opposite}}\)

\({\text{hypotenuse}}$$$$\cos\theta=\frac{\text{adjacent}}\)

\({\text{hypotenuse}}$$\)

We know the value of the hypotenuse and angle A. Using trigonometric ratios, we can find the length of sides in the right triangle.We will use the following formulas:

\($$\sin\theta=\frac{\text{opposite}}\)

\({\text{hypotenuse}}$$$$\cos\theta=\frac{\text{adjacent}}\)

\({\text{hypotenuse}}$$$$\tan\theta=\frac{\text{opposite}}\)

\({\text{adjacent}}$$\) Length of side a is:

\($$\begin{aligned} \sin A &=\frac{a}{c}\\ a &=c \sin A\\ &= 159\sin 34°\\ &= 91.4 \text{ ft} \end{aligned}$$Length of side b is:$$\begin{aligned} \cos A &=\frac{b}{c}\\ b &=c \cos A\\ &= 159\cos 34°\\ &= 131.5 \text{ ft} \end{aligned}$$\)

Now, we have the values of all sides of the right triangle. We can calculate the area of the triangle by using the formula for the area of a right triangle:

\($$\text{Area} = \frac{1}{2}ab$$\)

Putting the values of a and b:

\($$\begin{aligned} \text{Area} &=\frac{1}{2}ab\\ &=\frac{1}{2}(91.4)(131.5)\\ &= 6006.55 \approx 6007 \text{ sq ft}\end{aligned}$$\)

Therefore, the length of side a is 91 ft (rounded to the nearest whole foot) and the length of side b is 132 ft (rounded to the nearest whole foot). The area of the triangle is approximately 6007 sq ft.

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Here we want to make a system of equations and solve it, in this way, we will see that there are 8 black sheep.

first, let's define the variables:

x = number of black sheep

y = number of white sheep.

We know that:

"there are 56 sheep"

Then we can write:

\(x + y = 56\)

We also know that there are 6 times as many white sheep than black sheep, this means that:

\(y = 6 \cdot x\)

Then we have a system of equations:

\(x + y = 56\)

\(y = 6\cdot x\)

To solve this we need to start by isolating one of the variables in one of the equations. Here, we can see that the variable y is already isolated in the second equation, so we can use that.

Now we can replace that variable in the other equation:

\(x + y = 56\)

\(x + 6\cdot x = 56\)

Now we can solve this for x, the number of black sheep:

\(7\cdot x = 56\\\\x = 56/7 = 8\)

There are 8 black sheep.

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Answer:

Check this explaination below

Step-by-step explanation:

Check the attached picture

(a) U is a subspace of L(V, W) (b) F is a linear map, and U is the null space of F. (c) The dimension of U is n - 1

The dimension of U is n - 1

(a) To demonstrate that U is a subspace of L(V, W), we must demonstrate that it meets the three subspace properties:

If T1 and T2 are in U, then T1 + T2 is in U as well, since if T1(v) = 0 and T2(v) = 0, then (T1 + T2)(v) = T1(v) + T2(v) = 0 + 0 = 0.

If T is in U and c is a scalar, then cT is in U, since if T(v) = 0, then (cT)(v) = c * T(v) = c * 0 = 0.

Containing the zero vector: Because 0(v) = 0, the zero transformation in L(V, W), indicated by 0, is in U.

As a result, U is a subspace of L. (V, W).

(b) To demonstrate that F is a linear map, we must demonstrate that it meets the following two properties:

Addition linearity: F(T1 + T2) = (T1 + T2)(v) = T1(v) + T2(v) = F(T1) + F(T2) (T2).

Homogeneity is defined as F(cT) = (cT)(v) = c * T(v) = c * F. (T).

As a result, F is a linear map. To demonstrate that U is the null space of F, we must first demonstrate that U is the set of all T in L(V, W) such that F(T) = 0. In other words, T(v) = 0.

(c) A basis for U can be used to calculate the dimension of U. Because U is a subspace of L(V, W), we may construct a basis for U by limiting a basis for L(V, W) to U. A basis for L(V, W) can be produced by designating as T1, T2,..., Tn the set of all transformations that send the standard basis vectors of V to the standard basis vectors of W. These transformations' constraints to U are T1, T2,..., Tn such that T1(v) = T2(v) =... = Tn(v) = 0. Because v = 0, T1, T2,..., Tn constitute a linearly independent set. As a result, dim(U) = n - 1.

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Answer:

it should give you the option right before you post the answer, what subjectand grade level

Step-by-step explanation:

Answer: The answer is D. the last option

Step-by-step explanation:

The correct answer is option d) The graph is the radical function, y = √x shifted right 1 unit and up 4 units.

The original function is y = √(x - 1) + 4, which represents a radical function.

This function involves taking the square root of the quantity (x - 1) and then adding 4 to the result.

By shifting the function right 1 unit, we are replacing x with (x - 1). This means that the graph will be shifted horizontally by 1 unit to the right compared to the standard square root function.

By shifting the function up 4 units, we are adding 4 to the output of the square root function.

This means that the graph will be shifted vertically by 4 units compared to the standard square root function.

Therefore, the graph of the function y = √(x - 1) + 4 is the radical function y = √x shifted right 1 unit and up 4 units.

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Answer:

  6x² -36x +48

Step-by-step explanation:

The terms in one factor are each multiplied by the terms in the other factor. The resulting partial products are then combined. (This works the same as for numerical "long" multiplication.)

  (2x -8)(3x -6) = 2x(3x -6) -8(3x -6)

  = 6x² -12x -24x +48 . . . . . . . form partial products

  = 6x² -36x +48 . . . . . . . collect terms

Answer:

6x² - 36x + 48

Step-by-step explanation:

(2x-8)*(3x-6) = 2x*3x + 2x* -6 + -8*3x + -8*-6

6x² - 12x - 24x + 48

6x² - 36x + 48 [Answer]

PLEASE RATE!! I hope this helps!!

if you have any questions comment below!!

(I have verified my answer using an online calculator)

The global maximum value of a differentiable function f(x) on a closed interval [a, b] must occur at a critical value or an endpoint is correct. Statement C.

The critical value is the value of x for which the double derivative of the function f(x) becomes zero.

When double derivative becomes zero, the graph of the function is neither increasing nor decreasing and hence, the the function attains either

a maxima or a minima.

Hence, he global maximum value of a differentiable function f(x) on a closed interval [a, b] must occur at a critical value or an endpoint.

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