What is the surface area of a sphere with the given dimension? Express your answer to nearest hundredth. Use 3.14 for pi.
Radius = 5cm.
a. 982 sq. cm
C. 314 sq.cm
b. 1481.34 sq.cm
d. 628 sq. cm

Answer:

which principle prevents a brach from abusing  its power

Step-by-step explanation:

which principle prevents a brach from abusing  its power

Answer:

20x - 30 = 250

Step-by-step explanation:

20x - 30 = 250

20x = 280

x = 14

The slope of the linear equation of the entire data set is -720.98

1. Bring data in to excel sheet

2.Select both x and y variable and insert scatter plot chart. Select any data point in the chart and add trend line. In the format trend line option choose "Linear" and also select "Display an equation on chart" & "Display R-squared value on chart"

To find: What is the slope of the linear equation of the entire data set? Round to nearest hundredth.

Regression equation : y = -720.98x + 15,90,277.32

Slope = -720.98 (Round to nearest hundredth.)

Intercept = 15,90,277.32

So, the slope of the linear equation of the entire data set is -720.98

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Answer

From the origin, you would move left four and up 5

Answer:

See Explanation

Step-by-step explanation:

The question is incomplete, as a table or chart that shows the required data is not given.

To answer this, I will make use of the following frequency table

\(\begin{array}{cccccc}{Miles} & {1} & {1\frac{1}{2}} & {2} & {2\frac{1}{2}} & {3} \ \\ {Students} & {10} & {0} & {5} & {10} & {5} \ \end{array}\)

From the above table.

\(2\frac{1}{2}\ miles \to 10\ students\)

\(3\ miles \to 5\ students\)

So:

\(2\frac{1}{2}\ or\ 3\ miles = 10+5\)

\(2\frac{1}{2}\ or\ 3\ miles = 15\ students\\\)

From the above table.

\(1\ miles \to 10\ students\)

\(1\frac{1}{2}\ miles \to 0\ students\)

So:

\(1\frac{1}{2}\ or\ 1\ miles = 0+10\)

\(1\frac{1}{2}\ or\ 1\ miles = 10\ students\)

The difference (d) is then calculated by subtracting the number of students in both categories

\(d = 15\ students - 10\ students\)

\(d = 5\ students\)

The measure of the missing parts of the given triangle above would be given below as follows:

B = 36°

a = 32.4

To calculate the missing part of the triangle, the sine rule needs to be obeyed. That is :

a/sinA = b/sinB = c/sinC

where ;

a= ?

A= 65°

b= 21

B= 180-(79+65)

= 180-144 = 36°

Therefore;

a/sin65° = 21/sin36°

a = 21×0.9063/0.5878

= 19.0323/0.5878

= 32.4

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Answer:

To calculate how many standard deviations away from the mean an ACT score of 31 is, we need to use the formula:

z = (x - μ) / σ

Where:

x = ACT score of 31

μ = mean of ACT scores (28)

σ = standard deviation of ACT scores (2)

z = number of standard deviations away from the mean

Substituting the values, we get:

z = (31 - 28) / 2

z = 1.5

Therefore, an ACT score of 31 is 1.5 standard deviations away from the mean.

Answer:

\(the \: third \: answer \: is \: correct\)

The points  (2,6) (-4,-7) have a slope of 13/6 which satisfies the perpendicular condition option (B) is correct.

The ratio that y increase as x increases is the slope of a line. The slope of a line reflects how steep it is, but how much y increases as x increases. Anywhere on the line, the slope stays unchanged (the same).

\(\rm m =\dfrac{y_2-y_1}{x_2-x_1}\)

The question is incomplete.

The complete question is:

Line L has a slope of -6/13. The line through which of the following pair of points is perpendicular to L?

A) (6,-4) (-7,2)

B) (2,6) (-4,-7)

C) (6,9) (-4,-4)

D) (13,-4) (-7,2)

Line L slope m = -6/13

If two lines are perpendicular:

(m)(m') = -1

(-6/13)(m') = -1

m' = 13/6

From the points given finding the slope of every point:

A) (6,-4) (-7,2)

\(\rm m' =\dfrac{2+4}{-7-6}\)

m' = -6/13

B) (2,6) (-4,-7)

\(\rm m' =\dfrac{-7-6}{-4-2}\)

m' = 13/6

Thus, the points  (2,6) (-4,-7) have a slope of 13/6 which satisfy the perpendicular condition option (B) is correct.

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Answer:

(x-4)(x-3)

Step-by-step explanation:

x^2+12=7x  move the 7x to the other side

x^2-7x+12

(x-4)(x-3)

The stream velocity has no influence on the amount of dissolved load it contains. The amount of dissolved material depends on erosion and deposition carried out in the watercourse. These are affected by factors such as the slope of the land, the resistance of the material to erosion, the size of the sediments transported, etc.

Stream velocity plays an important role in the transport of sediments and dissolved loads in a watercourse. It affects the erosion and deposition processes that occur in the watercourse, which in turn affect the amount of sediment and dissolved load that is carried by the stream. For example, faster stream velocities can cause more erosion of the stream bed, leading to more material being carried in the water.

Sediment is any particulate matter that is transported by a fluid, and it can come in many different forms. The three main types of sediment are:

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Answer:

5x -4 ?

Step-by-step explanation:

Answer:

∠ JFK = 57°

Step-by-step explanation:

∠ JFK and ∠ GFH are vertically opposite and congruent , then

∠ JFK = ∠ GFH = 57°

The length of Stan's movie is 2 hours 25 minutes

The length of Talia's movie is 2 hours 55 minutes.

In order to determine the length of the movies, subtract the end time of the movie from the time the movie started.

Subtraction is the mathematical operation that is used to calculate the difference between two or more numbers. The sign that is used to represent subtraction is -.

Length of the movie = time the movie ended - time the movie started

Length of Stan's movie = 9:40 - 7:15 = 2 : 25 hours

Length of the Talia's movie = 10 : 10 - 7 : 15 = 2 : 55 hours

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Given:

The given endpoints are ( -2,10) and (-10, -12).

Required:

We need to find the midpoint of te given endpoints.

Explanation:

Consider the formua to find the midpoint.

Consider the points ( -2,10) and (-10, -12).

Final answer:

Answer:

A. they go on forever

Step-by-step explanation:

from the picture the lines will never meet

Answer:

ik the answer  but i wont help u hahaahahah

Step-by-step explanation:

i am evil

Since Jeff's balance was -$5 on Wednesday and he added $10 on Thursday before buying $4 worth of food, his balance at the end of Thursday would be $1.

We can show how to calculate his balance based on the information given.

Say Jeff's balance on Wednesday was -$5. This means he owed the cafeteria $5 for previous meals.

On Thursday, Jeff adds $10 to his account, so his balance becomes:

-$5 + $10 = $5

Now, Jeff buys $4 worth of food. This means his balance at the end of Thursday is:

$5 - $4 = $1

Therefore, if Jeff's balance was -$5 on Wednesday and he added $10 on Thursday before buying $4 worth of food, his balance at the end of Thursday would be $1.

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The complete question goes thus:

Jeff’s school allows students to carry a small negative balance for cafeteria lunch accounts. On Wednesday, Jeff discovers that his balance is -$5. Before lunch on Thursday, he adds $10 to his account and then buys $4 worth of food. What is his balance at the end of Thursday?

The frequency of a class is the number of data points that fall within the class is 1.

To determine the frequency of each class in the table shown, we must first divide the data points into the respective classes. The classes are 1003, 1062, 1063, 1122, 1123, 1182, 1183, 1242, 1243, 1302, 1303, and 1362.

For the class 1003, the frequency is 1, since there is only one data point (1003) in this class.

For the class 1062, the frequency is also 1 since there is only one data point (1062) in this class.

For the class 1063, the frequency is also 1 since there is only one data point (1063) in this class.

For the class 1122, the frequency is 1 since there is only one data point (1122) in this class.

For the class 1123, the frequency is 1 since there is only one data point (1123) in this class.

For the class 1182, the frequency is 1 since there is only one data point (1182) in this class.

For the class 1183, the frequency is 1 since there is only one data point (1183) in this class.

For the class 1242, the frequency is 1 since there is only one data point (1242) in this class.

For the class 1243, the frequency is 1 since there is only one data point (1243) in this class.

For the class 1302, the frequency is 1 since there is only one data point (1302) in this class.

For the class 1303, the frequency is 1 since there is only one data point (1303) in this class.

For the class 1362, the frequency is 1 since there is only one data point (1362) in this class.

Therefore, the frequency of each class in the table shown is 1.

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Answer:

pie * r^2 bro where r= 10mi

Answer: 4

Step-by-step explanation: a is three units away from o and a’ is 9 units away from o. you add 9+3 to get the total distance and divide that number by 3 to get the scale factor. 12/3=4

The scale factor for the given dilation is 3

Dilation is a transformation of an object which changes its size. if the dilated image is larger then it is called enlargement. If the dilated image is smaller it is called reduction.

If the dilation has the origin as the center of dilation, we can find points on the image formed by dilation by multiplying the coordinates of the original geometric object like triangle multiplying by the scale factor. For scale factor k, the transformation of the dilation is written as :  (x, y) → (k x, k y).

The scale factor ,k  = coordinate of image / coordinate of original

Given that Triangle ABC is dilated to create triangle A’B’C’ using point O as the center of dilation as shown in the figure

Scale Factor = coordinate of image / coordinate of original

                    = OA' / OA = 9/3 = 3

Therefore, the scale factor for the given dilation is 3.

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Answer: 3.5 miles

Step-by-step explanation:

C=2 √πA = 2 x √π x 1 = 3.5

Answer:

Step-by-step explanation:

\(x^2+y^2-8x+4y+4=0\\\\a)\\\\x^2-8x+y^2+4y+4=0\\\\x^2-2*x*4+(y^2+2*y*2+2^2)=0\\\\x^2-2*x*4+4^2+(y+2)^2=4^2\\\\(x-4)^2+(y+2)^2=4^2\\\)

Hence,

The radius of the circle is 4 units, coordinates of its centre are (4,-2).

\(b)\\\\y=0\\x^2+0^2-8x+4*0+4=0\\x^2-8x+4=0\\a=1\ \ \ \ b=-8\ \ \ \ c=4\\D=(-8)^2-4*1*4\\D=64-14\\D=48\\\sqrt{D}=\sqrt{48} \\ \sqrt{D}=\sqrt{16*3} \\\sqrt{D}=\sqrt{4^2*3} \\\sqrt{D}=4\sqrt{3} \\\displaystyle\\x=\frac{-(-8)б4\sqrt{3} }{2*1} \\\\x=\frac{8б4\sqrt{3} }{2} \\x_1=4-2\sqrt{3} \\x_2=4+2\sqrt{3}\)

\(c)\\\\A(6,2\sqrt{3}-2)\\ (x-4)^2+(y+2)^2=4^2\\(6-4)^2+(2\sqrt{3} -2+2)^2=16\\2^2+(2\sqrt{3} )^2=16\\4+2^2*(\sqrt{3})^2=16\\ 4+4*3=16\\4+12=16\\16\equiv16\)

\(d)\\A(6,2\sqrt{3}-2)}\\\sqrt{3} x+3y=\\\sqrt{3}(6)+3(2\sqrt{3} -2)=\\ 6\sqrt{3}+6\sqrt{3} -6=\\ 12\sqrt{3}-6\)

That would be central angels !

Please mark me, I'd like to get to virtuoso.

Answer:

Vertical Angles

Step-by-step explanation:

Answer:

Congruent angles

Step-by-step explanation:

These angles equal each other

The volume of the parallelepiped with sides given by vectors A, B and C is 13 cubic cm, which is the final answer.

The given vectors are:

A = [-4, 3, 2] cm, B = [2,1,3] cm and C= [1, 1, 4] cm

In order to calculate the volume of parallelepiped, we will use vector triple product equation:

Volume = A . (BXC)|, where BXC represents the cross product of vectors B and C.

Step-by-step solution:

We have, A = [-4, 3, 2] cm

B = [2,1,3] cm

C = [1, 1, 4] cm

Now, let's find BXC, using the cross product of vectors B and C.

BXC = | i    j     k|                    2      1     3                            1      1     4        | i    j     k |  = -i + 5j - 3k

Where, i, j, and k are the unit vectors along the x, y, and z-axes, respectively.

The volume of the parallelepiped is given by:

Volume = A . (BXC)|

Therefore, we have: Volume = A . (BXC)

\(Volume = [-4, 3, 2] . (-1, 5, -3)\\Volume = (-4 \times -1) + (3 \times 5) + (2 \times -3)\\Volume = 4 + 15 - 6\\Volume = 13\)

Therefore, the volume of the parallelepiped with sides given by vectors A, B and C is 13 cubic cm, which is the final answer.

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Answer:

If the product of two numbers is zero, there are two possibilities, namely;

1. One of the numbers is zero.

2. Both of the numbers are zero.

Step-by-step explanation:

As a rule in mathematics, when zero is used in multiplying any given whole number, the only result that would be obtained is zero.

Therefore,

1. If one of the numbers is zero, then the product of the two numbers is also zero. For example,

153, 000 * 0 = 0

2.  If both of the numbers are zero, then the product of the two numbers is zero. For example,

0 * 0 = 0.

So we can say that both can be true.

Answer:

D. none of the above

Step-by-step explanation:

If g(x)=8 is the only equation, then none of the answers are correct. The correct answer would have been 8 because 8=8.

Answer:

r^6

Step-by-step explanation:

In the laws of indices, it states that for division of indices of the same bases, there is a subtraction of indexes or powers.

For example, a^x/a^y = a^(x-y)

Therefore, r^9/r^3 = r^(9-3) = r^6