what is the upper block's acceleration if the coefficient of kinetic friction between the block and the table is 0.14?

Answers

Answer 1

Answer:7.056 m/s²

Explanation: Resultant force = g - μmg

ma = g - μmg

a = g(1 - 2μ) / 2

a = 7.056 m/s²


Related Questions

If a steel nail is wrapped 8 times with an insulated copper wire and each wire end is attached to a 1.5 V battery, then we will be able to lift 2 large paper clips. We hypothesized that for every 8 additional coils, you will be able to pick up two additional paper clips. Choose the control group for the experiment.

A) the nail with 16 coils

B) the nail with no coils

C) the nail with 24 coils

D) the nail with 8 coils

Answers

Option D is the correct answer.

To demonstrate the hypothesis, the control experiment must be the nail with 8 coils.

What is control experiment?

A control experiment is the experiment that remains unchanged or unaffected by other variables.

A controlled experiment is simply an experiment in which all factors are held constant except for one: the independent variable.

For this given experiment, the number of paper clips lifted depends on the number of coils around the wire and voltage applied.

To demonstrate that for every 8 additional coils, you will be able to pick up two additional paper clips, we must have a control experiment, that is an experiment with which we will compare the out come.

This control experiment must be the nail with 8 coils.

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A car starts from rest and for 15.0 s its wheels has a constant linear acceleration of 0.800 m/s^2 to the right. What is the angle through which each wheel rotated in 20.0 s interval if the radius of the tires is 0.330 m?

Answers

237.375 rad. …………………

4. The earth exerts a gravitational force of 3.5 N on an object. What is the mass of
the object in kilograms? *

Answers

Answer:

I'm not sure

Explanation:

sorry I'm not smart that's why I have this app

Answer:

(3.5N)/(10) = 0.35

Explanation:

If the net force applied by the truck ramp in the previous question is -300,000 N, how far along the ramp will the truck move as it stops?

If the net force applied by the truck ramp in the previous question is -300,000 N, how far along the

Answers

The distance travelled by the truck before coming to a stop is 72.9 m.

What is the acceleration of the truck?

The acceleration of the truck is calculated by applying Newton's second law of motion as follows.

F = ma

a = F / m

where;

F is the net forcem is the mass

a = ( -300,000 ) / ( 60,000)

a = -5 m/s²

The distance travelled by the truck before coming to a stop is calculated as follows;

v² = u² + 2as

where;

v is the final velocity when the truck stops = 0u is the initial velocity of the trucks is the distance travelled

0 = u² + 2as

0 = (27²) + (2)(-5)(s)

= (27²) - 10s

10s = 27²

s = ( 27² ) / 10

s = 72.9 m

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#10. When the weightlifter in question #9 stands, his feet make contact with the floor over an area of 250 square centimeters. What is the area of contact between his feet and the floor in *square meters (picture of question 9 for reference)​

#10. When the weightlifter in question #9 stands, his feet make contact with the floor over an area of

Answers

The weight is 1372 N

How do we calculate the weight of an object on earth?

The weight of an object on Earth can be calculated by using the following formula:

Weight = Mass x Acceleration due to Gravity

Where:

Weight is measured in Newtons (N)

Mass is measured in kilograms (kg)

Acceleration due to Gravity is a constant value

Weight = mass * acceleration due to gravity

Weight = 140 Kg * 9.8

= 1372 N

To calculate the weight of an object on Earth, you need to know its mass.

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How will dropping a can from a higher or a lower elevation affect the impact it has on a clay ball?

Answers

When dropping it higher it will have a larger impact and dropping it lower will have a smaller impact.

Dropping a can from a higher elevation  affects greater impact compare to  dropping a can from a lower elevation.

What is potential energy?

Potential energy is a form of stored energy that is dependent on the relationship between different system components. When a spring is compressed or stretched, its potential energy increases.

If a steel ball is raised above the ground as opposed to falling to the ground, it has more potential energy. It is capable of performing more work when raised.

Potential energy is a system attribute, not a property of a single body or particle.

The potential energy of the can on higher elevation is greater than the potential energy of the can on  lower elevation. That is why, dropping a can from a higher elevation  affects greater impact compare to  dropping a can from a lower elevation.

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WILL GIVE BRAINLIEST HELP FASTWhat is the mass of Planet X? Note: The constant of universal gravity (G) equals 6.674 X 10-11 N·m²/kg?.
What is the centripetal acceleration of moon II? Note: The constant of universal gravity (G) equals 6.674 X 10-11 N·m²/kg?
0.069 m/s2
m
0.024 m/s2
0.081 m/s2
0.040 m/s2
0 0.19 m/s2

WILL GIVE BRAINLIEST HELP FASTWhat is the mass of Planet X? Note: The constant of universal gravity (G)

Answers

Answer:

Explanation:

Centripetal acceleration's equation is:

\(a_c=\frac{v^2}{r}\) where v is the velocity of the object (moon II) and r is the radius. We have the radius, but we don't have the velocity, and we can't solve for acceleration until we do have it. Assuming moon II is a circle, or close enough to be called a circle, it has a circumference.

C = 2πr. If we can find the circumference of the circle, we can plug in the orbital period for the time, the circumference for the distance, and solve for velocity in d = rt. So let's do that and see what happens.

C = 2(3.14)(9.0 × 10⁷) and

C = d = 5.7 × 10⁸. Plugging in and solving for v:

\(5.7*10^8=v(3.0*10^5)\) and

v = 1.9 × 10³. That is the velocity we can use in the centripetal acceleration equation.

\(a_c=\frac{(1.9*10^3)^2}{9.0*10^7}\) and

\(a_c=.040\frac{m}{s^2}\)

These are fun!

9.00 V is applied to a wire with aresistance of 52.0 2. At what distancefrom the wire is the imagnetic field2.22 x 10-8 T?

Answers

Answer:

1.56 m

Explanation:

First, we need to find the current in the wire, so we will use the following equation:

\(V=IR\)

Where V is the voltage, R is the resistance and I is the current. Replacing the values and solving for I, we get:

\(\begin{gathered} 9V=I(52\Omega) \\ \frac{9V}{52\Omega}=I \\ 0.17A=I \end{gathered}\)

So, the current is 0.17 A.

Now, the magnetic field generated by a wire with current I at a distance r is equal to:

\(B=\frac{\mu I}{2\pi r}\)

Where μ is 4π x 10^(-7). So, replacing the values and solving for r, we get:

\(\begin{gathered} (2.22\times10^{-8})=\frac{(4\pi\times10^{-7})(0.17)}{2\pi r} \\ (2.22\times10^{-8})r=\frac{(4\pi\times10^{-7})(0.17)}{2\pi r}\cdot r \\ (2.22\times10^{-8})r=\frac{4\pi\times10^{-7}(0.17)}{2\pi} \\ (2.22\times10^{-8})r=3.4\times10^{-8} \\ \frac{(2.22\times10^{-8})r}{2.22\times10^{-8}}=\frac{3.4\times10^{-8}}{2.22\times10^{-8}} \\ r=1.56\text{ m} \end{gathered}\)

Therefore, the distance is 1.56 m

The diagram below shows a 5.0-kilogram mass sliding 9.0 meters down an incline from a height of
2.0 meters in 3.0 seconds. The object gains 90. joules of kinetic energy while sliding.
How much work is done against friction as the mass slides the 9.0 meters?

Answers

The work done against friction as the mass slides is 8 J.

The given parameters:

sliding mass, m = 5.0 kgdistance traveled by the mass, s = 9.0 mheight of incline, h = 2.0 mtime of motion, t = 3.0 skinetic energy of the object, K.E = 90 J

The work done against friction as the mass slides can be determined by applying work-energy theorem.

\(\Delta E= W\\\\P.E - K.E = W\)

the change in mechanical energy of the sliding mass, is equal to energy lost to friction.

\(W = P.E - K.E\\\\W = mgh - K.E\\\\W = (5 \times 9.8 \times 2) - 90\\\\W = 98 - 90\\\\W = 8 \ J\)

Thus, the work done against friction as the mass slides is 8 J.

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A device consisting of two coil using electomagnetic effects to change the amount of current and voltage in a circuit is called a(n)

A inductor
B transformer
C transducer
D electromagnet

Answers

Answer:

B transformer

Answer:

it will be TRANSFORMER

Explanation:

TRANSFORMERS have step up (to increase voltage) and step down (to decrease the voltage ) . these features are acheived bcoz transformer has two coils arranged together.

Select the correct answer.
How do we define energy efficiency?
A.
the ratio of the actual output energy to the input energy
B.
the ratio of power gain to power loss
c.
the product of input power and output power
D.
the sumy potential and kinetic energy

Answers

D. The sumy potential and kinetic energy

The cosmic microwave background is: Group of answer choices redshifted in the direction of Earth's motion. redshifted in the direction of the Sun's motion. redshifted in the direction of the center of the Milky Way. blueshifted in the direction of Earth's motion.

Answers

The cosmic microwave background is redshifted in the direction of Earth's motion (option a).

The cosmic microwave background is a faint radiation that fills the entire universe and is believed to be the afterglow of the Big Bang.

It has been found to be redshifted, meaning that its wavelengths have been stretched, in the direction of Earth's motion.

This effect is caused by the Doppler shift, which is the change in frequency or wavelength of a wave when the source or observer is moving relative to the other.

The cosmic microwave background has been mapped in detail by satellites such as the Cosmic Background Explorer and the Planck satellite, providing important information about the early universe, the formation of galaxies, and the nature of dark matter and dark energy.

Thus, the correct choice is (a) redshifted in respect to how the Earth is moving.

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define about the laws of refraction .... 1st law and 2nd law in brief​

Answers

Answer:

1 law      the incident ray, the refracted ray and the normal at the point of incidence, all lie in the same plane

2 law     when light ray passes from denser medium to rarer medium it bends away from the normal

Explanation:




a predatory bird is chasing its prey at 15.3 m/s when it emits a 202 hz squawk. if


the prey is moving away from the predator at 13 m/s, what frequency will it hear if


the air temperature is 27 °c?

Answers

The prey will hear the predator's squawk at an approximate frequency of 219 Hz.

The Doppler effect formula for sound and consider the given information: the predator's speed (15.3 m/s), the prey's speed (13 m/s), the emitted frequency (202 Hz), and the air temperature (27 °C).

Step 1: Calculate the speed of sound in air at 27 °C. The formula is: v = 331.4 + 0.6 * T, where T is the temperature in Celsius.
v = 331.4 + 0.6 * 27 = 347.2 m/s

Step 2: Apply the Doppler effect formula for sound: f' = f * (v + vo) / (v + vs), where f' is the observed frequency, f is the emitted frequency, v is the speed of sound, vo is the speed of the observer (prey), and vs is the speed of the source (predator).

Note: Since the prey is moving away from the predator, vo is positive (13 m/s). The predator is also moving toward the prey, so vs is negative (-15.3 m/s).

Step 3: Substitute the given values into the Doppler effect formula.
f' = 202 * (347.2 + 13) / (347.2 - 15.3) = 202 * 360.2 / 331.9

Step 4: Calculate the observed frequency.
f' ≈ 219 Hz

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2. A person standing at
the edge of a seaside
cliff kicks a stone over
the edge with a speed of
18 m/s. The cliff is 52 m
above the water’s surface, as shown at right.
How long does it take
for the stone to fall to
the water? With what
speed does it strike the
water?

Answers

god is good man what can you say but its 18.66x30301=362728

Amount of heat required to raise temperature of 10gm water through 2 deg * C is​

Answers

The amount of heat required to raise the temperature of 10 g of water through 2°C is 83.68 Joules.

To determine the amount of heat required to raise the temperature of 10 g of water through 2°C, we will use the formula:Q = m × c × ΔT

Where Q is the amount of heat required, m is the mass of the substance being heated, c is the specific heat capacity of the substance, and ΔT is the change in temperature.

So, for 10 g of water, the mass (m) would be 10 g.

The specific heat capacity (c) of water is 4.184 J/(g°C), so we'll use that value.

And the change in temperature (ΔT) is 2°C.

Substituting these values into the formula, we get:Q = 10 g × 4.184 J/(g°C) × 2°CQ = 83.68 Joules

Therefore, the amount of heat required to raise the temperature of 10 g of water through 2°C is 83.68 Joules.

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A fish is 50.0 cm below the surface of a pond (index of refraction for water is 1.33). For a viewer directly above the fish, the fish appears to be placed
O 37.6 cm below the surface of the pond.
O 50.0 cm below the surface of the pond.
O 66.5 cm below the surface of the pond.
O None of the above is correct

Answers

The fish appears to be located 37.6 cm below the surface of the pond when viewed from directly above.The correct answer is: O 37.6 cm below the surface of the pond.

This is because when light travels from water (with an index of refraction of 1.33) to air (with an index of refraction of 1.00), it undergoes refraction. This means that the light bends as it passes through the surface, which causes objects to appear shifted from their actual position.

In this case, the fish is actually located 50.0 cm below the surface of the pond. However, when the light from the fish enters the air above the pond, it bends away from the normal (a line perpendicular to the surface of the water), causing the fish to appear higher up than it actually is. Using the formula for calculating the apparent depth of an object underwater:

apparent depth = real depth / index of refraction

We can calculate the apparent depth of the fish:

apparent depth = 50.0 cm / 1.33 = 37.6 cm

Therefore, the fish appears to be located 37.6 cm below the surface of the pond when viewed from directly above.

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If a gas and a liquid are both at the same temperature, the particles of gas have a higher average kinetic energy. True or false?

Answers

Answer:

True

Explanation:

The average kinetic energy is the measure of how freely the molecules of a substance moves relative to the other molecules within the substance. Gas and liquids are together termed fluids,  but the molecules of a gas naturally has more more average kinetic energy that that of a liquid, if they are kept at the same temperature. This explains why gases are easy to expand, and have to be confined by a container. So the particles of a gas has more kinetic energy that that of a liquid even if they are kept at the same temperature.

An airplane is flying at 80 kilometers per hour when a strong tail wind, traveling in the same direction at 5 kilometers per hour, hits the airplane. How can the net force acting on the airplane be calculated?


A. add the forces
B. subtract the forces
C. multiply the forces
D. divide the forces

Answers

Answer:

A.add the forces

Explanation:

since they're both going in the same direction then they should be added to get the total net force.

pls mark me brainliest

The net force acting on the airplane if, An airplane is flying at 80 kilometers per hour when a strong tailwind, traveling in the same direction at 5 kilometers per hour is 85 km/hr so, option A is correct.

What is force?

Force is the influence of either pull or pushes in the body. Basically, gravitation forces, nuclear forces, and friction forces are the types of forces.

For e.g. when the wall is hit by a hand then a force is exerted by the hand on the wall as well as the wall also exerts a force on the hand. There are different laws given to Newton to understand force.

Given:

An airplane is flying at 80 kilometers per hour when a strong tailwind, traveling in the same direction at 5 kilometers per hour,

Calculate the net force acting on the airplane as shown below,

The net force acting on the airplane = The velocity of the airplane + velocity of the wind  (As they both are in the same direction)

The net force acting on the airplane = 80 km / hr + 5 km / hr

The net force acting on the airplane = 85 km / hr

Thus, the net force acting on the airplane is added.

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HELP ME 20 POINTS!!!Assume that the average volume of an adult human body is one-tenth
cubic meter (0.10 m) and that there are two billion (2.0 x 109)
adults in the world.
a. What would be the total volume of all the adults in the world?
b. Compute the length of one edge of a cubic container that has a
volume equal to the volume of all the adults in the world.

Answers

a). (2.0 x 10^9) x (0.1) = 2.0 x 10^8 cubic meters

b). The edge of a cube with that volume is

(2.0 x 10^8) ^ 1/3 = about 585 metres

(about 0.36 of a mile)

==> I'm pretty sure there are actually more than 2 billion adults in the world, since the total population is well over 7 billion now.

Help please ASAP !! Thanks

Help please ASAP !! Thanks

Answers

Answer:

I think its C

Explanation:

calculate the ratio of the mass of an electron to its rest mass coi 2a when it is moving with a kinetic energy of20 mev. (rest mass i / of electron= 0.51mev)

Answers

The ratio of the mass of an electron to its rest mass when it is moving with a kinetic energy of 20 MeV can be calculated using the equation of special relativity and assuming that the speed of the electron is much less than the speed of light. The result is that the mass of the electron is 39.22 times its rest mass.

The ratio of the mass of an electron to its rest mass can be calculated from its kinetic energy using the equation of special relativity, which states that the total energy of an object is equal to its rest mass multiplied by the square of the speed of light, plus its kinetic energy.

The rest mass of an electron is 0.51 MeV, so its total energy is given by:

\(E\) = \(0.51 MeV*c^{2} + KE\)

Where c is the speed of light, and KE is its kinetic energy.

Since the kinetic energy of the electron is 20 MeV, we have:

\(E = (0.51 MeV) * (c²) + 20 MeV\)

And the total energy can be divided by the rest mass of the electron and the square of the speed of light to obtain the ratio of its mass to its rest mass:

 \(m/m0\) = \(\frac{E}{0.51 MeV * c^{2} }\)

\(m/m0\) = \(\frac{0.51 MeV*c^{2} + 20 MeV}{0.51 MeV }\)

We can simplify the calculation by assuming that the speed of the electron is much less than the speed of light, so that we can ignore the term (0.51 MeV * c^2).

In that case, we have:

\(m/m0\) = \(\frac{20MeV}{0.51MeV}\)

\(m/m0 = 39.22\)

So the ratio of the mass of an electron to its rest mass when it is moving with a kinetic energy of 20 MeV is 39.22.

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Which properties are characteristics of non metals

Answers

Non - Metals:

Non- metals are bad conductor of electricity ( except Graphite ).

Non- metals are also bad conductor of heats. ( except diamond )

Non - metal are neither malleable nor ductile. They are brittle.

Non-metal are not strong.

Non-metal are not sonorous.

Some terms:

★ Malleable: This means that metals can be beaten into thin sheets with hammer.

★ Ductile: This means that metals can be drawn into thin wires.

★ Brittle: This means that non-metal break into pieces on hammering.

★ Sonorous: This means capable of producing a ringing sound.


A boy pulls on a wagon with a force of 100 N [E]. The wagon pulls on the boy with a
force of
A). zero
B) less than 100 N [E]
C) 100 N [W]
D) Less then 100 N [W]
E) greater than 100 N [W]

Answers

The correct answer is F) 69 because it just is trust the expert which is me

Shown here is a portion of the activity table. Based
on the table, which activity burns the least amount
of calories per hour?
doing aerobics
O jogging
walking

Answers

Answer: The answer is walking. Hope it helps anybody :)

Explanation: The answer to the second question is glycogen and lipids.

Answer:

Walking

Explanation:

Took test

Un muelle se alarga 5 cm, cuando de él se cuelga una masa de 1000 gr. Colocamos después este muelle unido a una masa de 500 g sobre una mesa horizontal sin rozamiento. La masa se separa 3 cm de su posición de equilibrio y se deja vibrar sobre el eje horizontal. Calcular:
a) La fase inicial y la amplitud del movimiento.
b) La elongación y la velocidad en el instante t = 0,5 s
c) La velocidad angular
d) El periodo
e) la constante de recuperación del resorte;
f) El valor máximo de la velocidad.
g) la energía potencial en el punto de máxima deformación en horizontal;
h) La energía cinética cuando x = 2 cm;
i) La aceleración de la partícula 0,25 s después de iniciado el movimiento
j) la velocidad cuando el tiempo es de 1 seg

Answers

La expresión del movimiento armónico simple permite encontrar los resultados para las preguntas sobre el movimiento de la masa y el resorte son:  

     a) La fase inicial es cero y la amplitud es 0,05 m

     b)  La elongación y velocidad para el tiempo dado son:

          x =  -0,0445 m y  v = -0,0229 m/s

      c) La velocidad angular es:        w = 19,8 rad/s

      d) El  periodo vale   T = 0,317 s

      e) La constante de resorte es:      k = 196 N/m

      f)  La velocidad máximas es:     v= 0,99 m/s

     g) La energia potencial es:       Ep = 0,245 J

     h) La energía cinética es:     K = 0,2058 J

      i) La aceleración es:  a = -4,61 m/s²

      j) La velocidad es:  v= -0,806 m/s


.Movimiento armónico simple

El movimiento oscilatorio ocurre cuando hay un fuerza recuperadora en el sistema, si tea fuerza es proporcional al desplazamiento el movimiento se denomina armónico simple y es descrito por la expresión.

                       x= A cos (wt +Ф)

                       w² = k/m

Donde x es el desplazamiento, A la amplitud del movimiento, w la velocidad angular, t el tiempo, fi una constante de fase que se determina con los valores iniciales, k la constante del resorte y m la masa.

e) Indican el desplazamiento de x= 5 cm = 0,05 m para una masa de m= 1000 g = 1 kg.  Usemos la condición de equilibrio y la ley de Hooke para encontrar la constante del resorte.

                 W = F

                mg = k x

                 \(k = \frac{mg}{x}\)

Calculemos.

                 k = \(\frac{1 \ 19.8}{0.05}\)  

                 k = 196 N/m

c) indican la masa aplicada para el movimiento es m= 0,5 kg , podemos buscar la velocidad angular

                  w= \(\sqrt{ \frac{k}{m}}\)

                  w = \(\sqrt{ \frac{196}{0.5} }\)  

                  w = 19,8 rad/s

a) La fase y la mplitud.

La amplitud es la elongación máxima del movimiento  

            A = 0,05 m

para la fase usamos que el bloque se suelta, por lo cual el tiempo es cero t=0 ,desde la posición de máxima elongación v= 0, usemos la relación entre la posición y la velocidad.

            v= \(\frac{dx}{dt}\)

            v = -A w sin (wt +Ф)

            0 = - A w sin Ф

Por lo tanto fi debe ser cero, para que la función seno ea cero.

            Ф =0

b) Calculamos para t=0,5 s la elongación y la velocidad.

La ecuación del movimiento queda.

              x = A cos wt

               

Calculamos.

Recuerda que los ángulos están en radianes.

                x = 0,05 cos 19,8 0,5

                x =  -0,0445 m

La velocidad es:

                v = 0,05 19,8 sin 19,8 0,05

                v = -0,0229 m/s

d) La velocidad angular esta relacionada con el periodo.

            W = \(\frac{2\pi}{T}\)  

            T = \(\frac{2\pi}{w}\)  

             T = \(\frac{2\pi}{19.8}\)2pi/19,8

             T = 0,317 s

f) El valor máximo de la velocidad.

Este valor ocurre cuando la función seno vale 1

             v =Aw

             v= 0,05 19,8

              v= 0,99 m/s

g) La energía mecánica del sistema se mantiene constante porque no hay fuerzas de roce, por lo tanto en el punto de máxima elongación la energía es totalmente potencial.

             U = ½ k A²  

              U = ½ 196 0,05²  

             U = 0,245 J

h) la energía cinética para x=2 cm = 0,02 m

En todos los puntos la energía mecánica es la suma dela energía cinética mas la enriar potencial

            Em₀ = K + U

            K = Em₀ – U

            K = ½ k ( A² -x² )

            K = ½ 196 ( 0,05² – 0,02² )

            K = 0,2058 J

i)  La aceleracion y la velocidad están relacionadas

              a = \(\frac{dv}{dt}\)  

              a = - A w² cos wt

             a = - 0,05 19,8² cos 19,8t

              a = -19,6 cos 19,8 t

              a = - 19,8cos 19,8 0,25

              a = -4,61 m/s²  

j) La velocidad para t=1 s.

             v= - A w sin wt

             v = - 0,05 19,8 sin 19,8 1

             v= -0,806 m/s

En conclusión con la expresión del movimiento armónico simple podemos encontrar los resultados para las preguntas sobre el movimiento de la masa y el resorte son:

    a) La fase inicial es cero y la amplitud es 0,05 m

     b)  La elongación y velocidad para el tiempo dado son:

          x =  -0,0445 m y  v = -0,0229 m/s

      c) La velocidad angular es:        w = 19,8 rad/s

      d) El  periodo vale   T = 0,317 s

      e) La constante de resorte es:      k = 196 N/m

      f)  La velocidad máximas es:     v= 0,99 m/s

     g) La energia potencial es:       Ep = 0,245 J

     h) La energía cinética es:     K = 0,2058 J

      i) La aceleración es:  a = -4,61 m/s²

      j) La velocidad es:  v= -0,806 m/s

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According to the law of reflection, what is the angle of incidence?

It is the angle the incident ray makes with a line drawn perpendicular to the viewer.

It is the angle the incident ray makes with a line drawn perpendicular to the reflecting surface.

It is the angle the incident ray makes with a line drawn parallel to the reflecting surface.

Answers

the angle of incidence is always equal to the angle of reflection,

Explanation:

Important Information. When light is reflected from a surface, the angle of incidence is always equal to the angle of reflection, where both angles are measured from the path of the light to the normal to the surface at the point at which light strikes the surface. This equality is known as the law of reflection.

Answer:

It is the angle the incident ray makes with a line drawn perpendicular to the reflecting surface

Ou are approaching a railroad crossing with no warning devices and are unable to see 400 feet down the tracks in one direction. the speed limit is:______

Answers

In conclusion,it is advisable to approach such a crossing with caution, reduce your speed, and be prepared to stop. Safety should always be the top priority when encountering railroad crossings without warning devices.

The speed limit at a railroad crossing with no warning devices and limited visibility of 400 feet down the tracks in one direction is not explicitly stated.

However, it is important to note that in such situations, caution and attentiveness are key to ensure safety.
When approaching a railroad crossing without warning devices, it is crucial to reduce your speed and be prepared to stop. The lack of warning devices means that there might be a train approaching, and your ability to see down the tracks is limited to only 400 feet.

Therefore, reducing your speed allows you to have more time to react and make a safe decision.
In conclusion,it is advisable to approach such a crossing with caution, reduce your speed, and be prepared to stop. Safety should always be the top priority when encountering railroad crossings without warning devices.

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A pickup truck is capable of producing 515 Nm of torque. How much force does the engine produce if the force acts 0.25 m from the pivot point?

Answers

Answer:

257.5 N

Explanation:

the electric cell of internal resistance 0.5ohms delivers a current of 2 amperes when a resistance of 3 ohm is connected across it, find the electromotive force of the cell. Show all workings​

Answers

Answer:

7 volts

Explanation:

Applying,

E = IR+Ir................ Equation 1

Where E = electromotive force of the cell, I = current. R = External resistance, r = internal resistance.

From the question,

Given: I = 2 amperes, R = 3 ohm, r = 0.5 ohm

Substitute these values into equation 1

E = (2×3)+(2×0.5)

E = 6+1

E = 7 volts

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