What is the value of x to the nearest degree?

Answer:

676

Step-by-step explanation:

I think this is an arithmetic series, so

Sn = 26/2[2(1) + (26 - 1)2]

Sn = 13[2 + 50]

Sn = 13[52]

Sn = 676

Answer:

676

Step-by-step explanation:

A = 1

B = 3

C = 5

D = 7

...

Z = 51

              1   + 3    + 5   + 7    + 9 + 11  + 13  + 15  + 17  + 19 + 21 + 23 + 25

(+)       + 51 + 49 + 47 + 45 + 43 + 41 + 39 + 37 + 35 + 33 + 31 + 29 + 27

---------------------------------------------------------------------------------------------------

          52 + 52 + 52 + 52 + 52 + 52 + 52 + 52 + 52 + 52 + 52 + 52 + 52

13 * 52 = 676

Answer: 676

Answer:

300 new employees

Step-by-step explanation:

1:3

x + 3x = 1,200

4x = 1200

x = 300

Answer:

EF is the chord of K

hope it helped

Answer:

EF is the chord of K

Step-by-step explanation:

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The inequality expression given as -x/3 < 5 has a solution of x > -15

From the question, the inequality is given as

-x/3 < 5

The above inequality can be re-written as follows

-x/3 < 5

There is no constant to add or subtract in the expression

So, we start by multiplying both sides of the expression by a constant

Multiply both sides by 3

expression

-x < 15

Divide both sides by -1

So, we have the following representation

x > -15

Hence, the solution to the expression is x > -15

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Multiplication expression used is 16 ×\(\frac{5}{4}\).

A number that when multiplied by a number x results in the multiplicative identity, 1, is known as a multiplicative inverse or reciprocal, indicated by 1/x or x1. A fraction a/b has a multiplicative inverse of b/a. Divide 1 by the real number to obtain the multiplicative inverse of the number. When a number is multiplied by its original number, the multiplicative inverse of that number, or x-1, produces a value equal to 1. The multiplicative inverse of 2, for instance, is 2-1 since it fulfils the formula: 2 x 2-1

2 x \(\frac{1}{2}\)= 1. It is also known as a number's reciprocal.

Given Data

16 ÷ \(\frac{4}{5}\)

Reciprocating,

16 × \(\frac{5}{4}\)

Simplifying,

4(5)

20

Multiplication expression used is 16 ×\(\frac{5}{4}\)

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Answer:

Option B

Step-by-step explanation:

Given that two variables in the table as

                                           Total     Average

x              2   6   7   8   12       35          7

y             15  13   9   8    5        50         10

xy            30 78 63 64  60     295        59

(x-7)^2   25      1  0     1   25        52     10.4

(y-10)^2   25   9   1      4   25     64        12.8

Var x = 10.4 and std dev x = 3.225

Var Y = 12.8 and std dev Y = 3.578

Cov (xy) = E(xy)-E(x) E(Y)=59-70=-11

Correlation coefficient r

= Cov /sx sy = -11/(3.225)(3.578)=-0.9532

Round off to get

r=-0.953

Henceoption B is right.

I hope my answer helped! <3

Answer:

B and D

Step-by-step explanation:

Surveys are only tested with one group.

Answer:

D : 1 1/2

Step-by-step explanation:

150% converted into a decimal is 1.5, this is the same as 1 1/2, so the answer is D.

hope this helps :)

The 150% as a fraction in simplest form is D. 1 1/2

Multiplication is the mathematical operation that is used to determine the product of two or more numbers. If an event can occur in m different ways and if following it, a second event can occur in n different ways, then the two events in succession can occur in m × n different ways.

We have to write 150% as a fraction in simplest form.

So we put 150 over 100

That is (150/100)

Now multiply the top and the bottom by 10 to get rid of the decimal  as;

15/10

1.5 = 1 1/2

Hence, the fraction in simplest form is 1 1/2

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Mae Ling make $590 in a work week if she sold $4,500 worth of merchandise.

The given is:

We need to find how much she would earns in a work week

Mae Ling earns a weekly salary of $320

She earns a 6.0% commission on sales

She sold by $4,500 in that week

Add $320 to the product of 6.0% and $4,500

She made = 320 + (6.0% × 4,500)

6.0% = 6.0 ÷ 100 = 0.06

She made = 320 + (0.06 × 4,500)

She made = 320 + 270

She made = 590

She would make $590 in a work if she sold $4,500 worth of merchandise.

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Answer:

112

Step-by-step explanation:

the formula for area is length times width,so in this case 14×8 = the area

The property that should be used to continue simplifying the above equation is A-^1A = 1. So, correct option is C.

We can start with the equation AB = AC and multiply both sides by A^-1 on the left:

A^-1(AB) = A^-1(AC)

Using the associative property of matrix multiplication, we can simplify the left-hand side:

(A^-1A)B = (A^-1A)C

Using the fact that A^-1A = I (the identity matrix), we get:

IB = IC

Simplifying further using the fact that I times any matrix is that matrix itself, we obtain:

B = C

Therefore, the equivalent equation to AB = AC using A^-1 that simplifies to B = C is A^-1(AB) = A^-1(AC), and the property used to continue simplifying the equation is A^-1A = I.

The correct option is (C) A^-1A = 1, which is equivalent to A^-1A = I, since the identity matrix is denoted as 1 in some contexts.

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The price per share of BBQ Corp. after there has been a stock split, or post - split, is $24. 15

When there is a stock - split, then each of outstanding shares that a company has, is divided into a number of shares that is determined by the stock split ratio.

The price of the individual shares are also divided into the same ratio as the shares.

This means that the price per share for BBQ Corp. post - split is:

= Price per share before split / 3

= 72. 45 / 3

= $24. 15

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Vector a = (3, 2), then;

Also, vector b = (-5, 6), then;

Then, -3a + 2b = (-9, -6) + (-10, 12)

The answer is (-19,6)

Answer:

In this I have answered this problem.

Step-by-step explanation:

The proportion of similar triangles are

\( \frac{3}{4} = \frac{9}{r} \)

Solving for r

\( \frac{4}{3} = \frac{r}{9} \)

\( \frac{9 \times 4}{3} = r\)

\(12 = r\)

The condition number of a matrix A is defined as the product of the norm of A and the norm of the inverse of A, divided by the norm of the identity matrix. That is:

K(A) = ||A|| ||A^(-1)|| / ||I||

If K(A) is large, it means that small changes in the input to the matrix equation can cause large changes in the output, indicating that the problem is ill-conditioned.

In this case, we are given that K(A) = 5, and that A is a 2x2 matrix with entries a, 1, 0, and 0. That is:

A = [a 1; 0 0]

To find the value of a, we need to use the definition of the condition number and some properties of matrix norms. We have:

||A|| = max{||Ax|| / ||x|| : x != 0}

Since A is a 2x2 matrix, we can compute the norm using the formula:

||A|| = sqrt(max{eigenvalues of A^T A})

The eigenvalues of A^T A are a^2 and 1, so:

||A|| = sqrt(a^2 + 1)

Similarly, we have:

||A^(-1)|| = sqrt(max{eigenvalues of A^(-1) A^(-T)})

Since A is a diagonal matrix, its inverse is also diagonal, with entries 1/a, 0, 0, and 1. Therefore:

A^(-1) A^(-T) = [(1/a)^2 0; 0 0]

The eigenvalues of this matrix are (1/a)^2 and 0, so:

||A^(-1)|| = sqrt((1/a)^2) = 1/|a|

Finally, we have:

||I|| = max{||Ix|| / ||x|| : x != 0} = 1

Putting it all together, we get:

K(A) = ||A|| ||A^(-1)|| / ||I|| = (sqrt(a^2 + 1) / |a|) / 1 = sqrt(a^2 + 1) / |a| = 5

Squaring both sides and rearranging, we get:

a^2 + 1 = 25a^2

24a^2 = 1

a^2 = 1/24

a = ±sqrt(1/24) = ±0.204

Since a is required to be in the interval (0, 1), the only valid solution is a = 0.204 (rounded to three decimal places).

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∫_A^B ∫_B^C ∫_D^E (10%)(x^2 + y^2 + z^12) dz dr dθ.

This represents the full iterated integral for F_sav over the given solid cylinder.

(a) The iterated integral for F_sav with the given limits of integration is as follows:

∫∫∫_W (10%)(x^2 + y^2 + z^12) dz dr dθ,

where the limits of integration are A = 0, B = C = 0, D = 6, and E = -1.

(b) To evaluate the integral, we begin with the innermost integration with respect to z. Since z ranges from -1 to 6, the integral becomes:

∫∫_D^E (10%)(x^2 + y^2 + z^12) dz.

Next, we integrate with respect to r, where r represents the radial distance from the z-axis. As the solid cylinder is centered about the z-axis and has a base radius of 6, r ranges from 0 to 6. Thus, the integral becomes:

∫_B^C ∫_D^E (10%)(x^2 + y^2 + z^12) dz dr.

Finally, we integrate with respect to θ, where θ represents the angle around the z-axis. As the cylinder is symmetric about the z-axis, we integrate over a full circle, so θ ranges from 0 to 2π. Hence, the integral becomes:

∫_A^B ∫_B^C ∫_D^E (10%)(x^2 + y^2 + z^12) dz dr dθ.

This represents the full iterated integral for F_sav over the given solid cylinder.

The problem asks for the iterated integral of F_sav over the solid cylinder W. To evaluate this integral, we use the cylindrical coordinate system (r, θ, z) since the cylinder is centered about the z-axis. The function inside the integral is 10% times the sum of squares of x, y, and z^12. By integrating successively with respect to z, r, and θ, and setting appropriate limits of integration, we obtain the final iterated integral. The integration limits are determined based on the given dimensions of the cylinder.

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Answer:

13. 23 boat rides; 22 are full, and the first one has 301 passengers.

12. $11,067.50

In the exponential ab = c, there are certain conditions where there is no solution. Firstly, if c is negative, there is no solution because there is no real number that can be raised to any power to give a negative result.

Secondly, if b is negative and c is a fraction, there is no solution because the result of raising a negative number to a fractional power is not a real number. Thirdly, if a is a fraction and c is zero, there is no solution because any number raised to the power of zero is equal to one, and there is no fraction that can be equal to one. Lastly, if a is positive and b is a fraction, there is no solution because any number raised to a fractional power will always give a positive result. Therefore, these are the conditions where there is no solution in the exponential ab = c equation.

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Answer:

D

Step-by-step explanation:

I would have to assume its D since the starting point is (-7, 5) and the slope is 1/2, since it is a positive slope it would reach (13, 9)

A. x1, x2, x3, s1, s2 ≥ 0

B. New table au:

x1 x2 x3 s1 s2 RHS

x2 | 0 1 4/7 3/14 -1/14 1/2

s2 | 1 0 3/7 -1/14 3/14 3/2

Z | 0

a) Writing the problem in equation form and adding slack variables:

Maximize Z = 3x1 + 2x2 + x3

Subject to:

3x1 - 3x2 + 2x3 + s1 = 3

-x1 + 2x2 + x3 + s2 = 6

x1, x2, x3, s1, s2 ≥ 0

b) Solving the problem using the simplex method:

Step 1: Convert the problem into canonical form (standard form):

Maximize Z = 3x1 + 2x2 + x3 + 0s1 + 0s2

Subject to:

3x1 - 3x2 + 2x3 + s1 = 3

-x1 + 2x2 + x3 + s2 = 6

x1, x2, x3, s1, s2 ≥ 0

Step 2: Create the initial tableau:

x1 x2 x3 s1 s2 RHS

s1 | 3 -3 2 1 0 3

s2 | -1 2 1 0 1 6

Z | 3 2 1 0 0 0

Step 3: Perform the simplex method iterations:

Iteration 1:

Pivot column: x1 (lowest ratio = 3/1 = 3)

Pivot row: s2 (lowest ratio = 6/2 = 3)

Perform row operations to make the pivot element equal to 1 and other elements in the pivot column equal to 0:

s2 = -s2/3

x2 = x2 + (2/3)s2

x3 = x3 - (1/3)s2

s1 = s1 - (1/3)s2

Z = Z - (3/3)s2

New tableau:

x1 x2 x3 s1 s2 RHS

x1 | 1 -2/3 -1/3 0 1/3 2

s2 | 0 7/3 4/3 1 -1/3 2

Z | 0 2/3 2/3 0 -1/3 2

Iteration 2:

Pivot column: x2 (lowest ratio = 2/7)

Pivot row: x1 (lowest ratio = 2/(-2/3) = -3)

Perform row operations to make the pivot element equal to 1 and other elements in the pivot column equal to 0:

x1 = -3x1/2

x2 = x2/2 + (1/7)x1

x3 = x3/2 + (4/7)x1

s1 = s1/2 - (1/7)x1

Z = Z/2 - (2/7)x1

New tableau:

x1 x2 x3 s1 s2 RHS

x2 | 0 1 4/7 3/14 -1/14 1/2

s2 | 1 0 3/7 -1/14 3/14 3/2

Z | 0

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A horizontal parabola with a right-facing opening and a vertex at (1,1) is we have positive direction.

In order to make the coefficients of either the variable x or the variable y numerically equal, first multiply both of the following equations by any suitable non-zero constants.

Finding the single equation of a curve in standard form with only the variables xs and ys constitutes the cartesian equation of that curve. You must simultaneously solve the parametric equations in order to arrive to this equation.

X and Y both

are t-related functions.

We have t=y1 after solving y=t+1 to get t as a function of y.

Thus, given x=t2+1, we have x=(y1)2+1x1=(y1) by substituting t=(y1).

A horizontal parabola with a right-facing opening and a vertex at (1,1) is what we have positive direction.

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The graph as an inequality expression is y < -2x - 3

From the question, we have the following parameters that can be used in our computation:

The graph of the inequality

A linear equation is represented as

y = mx + c

Where

c = y when x = 0

So, we have

c = -3 from the graph

The equation becomes

y = mx - 3

Using the other points, we have

-3m - 3 = 3

So, we have

-3m = 6

This gives

m = -2

Recall that

y = mx - 3

So, we have

y = -2x - 3

The bottom part is the shaded region

So, we have

y < -2x - 3

Hence, the graph as an inequality is y < -2x - 3

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The test used to determine whether or not first-order autocorrelation is present is the Durbin-Watson test.

1. Fit a regression model to the data.

2. Obtain the residuals, which represent the differences between the observed values and the predicted values from the regression model.

3. Calculate the Durbin-Watson statistic, which is a ratio of the sum of squared differences between adjacent residuals to the sum of squared residuals.

4. Compare the calculated Durbin-Watson statistic to critical values from a Durbin-Watson table or use statistical software to determine if there is significant autocorrelation.

5. The Durbin-Watson statistic ranges from 0 to 4, where a value around 2 suggests no autocorrelation, a value below 2 indicates positive autocorrelation, and a value above 2 indicates negative autocorrelation.

6. By analyzing the Durbin-Watson statistic, researchers can make conclusions about the presence or absence of first-order autocorrelation in the regression model.

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Answer:

A

Step-by-step explanation:

180⁰= a+b+81⁰

a=180⁰-117⁰=63⁰

b=180⁰-63⁰-81⁰=36⁰

find dy/dx

x= t sin(t); (Given in the question)

y= t²+8t; (Given in the question)

then, x= t sin(t)

dx/dt = sin t + t cos t ;

y= t²+8t

dy/dt = 2t + 8;

then, dy/dx = dy/dt x dx/dt

dy/dx = (2t+8)/(sin t + t cos t)

dy/dx = 2(t+4)/(sin t + t cos t)

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Answer:

C

Step-by-step explanation:

A and c are parallel

B and d are parallel

A and c are intersecting

9514 1404 393

Answer:

  see below

Step-by-step explanation:

The "solution" is the doubly-shaded area on the graph. Here, the dashed lines cross in a sort of X pattern, and the doubly-shaded area is the quadrant at the bottom (below both lines).

__

The "solution" involves graphing the boundary lines, and identifying the shaded area associated with each.

When equations are in standard form, there are a couple of different ways you can graph them. (I like to use a graphing calculator.) One way is to rewrite the equations to slope-intercept form:

  y < 2x -4 . . . . . . slope of 2, y-intercept of -4, shading below the dashed line

  y < -x -1 . . . . . . . slope of -1, y-intercept of -1, shading below the dashed line

__

Comment on multiple choice questions

You need to identify what makes each answer choice different from the others. It might be the slopes of the lines, the y-intercepts, the side that is shaded, the nature of the line (dashed, solid). You can usually eliminate the answer choices that don't make any sense, and concentrate on the subtleties of the remaining viable candidates.

The "solution" is the doubly-shaded area on the graph. Here, the dashed lines cross in a sort of X pattern, and the doubly-shaded area is the quadrant at the bottom (below both lines).

A graph is the representation of the data on the vertical and horizontal coordinates so we can see the trend of the data.

The "solution" involves graphing the boundary lines and identifying the shaded area associated with each.

When equations are in standard form, there are a couple of different ways you can graph them. (I like to use a graphing calculator.) One way is to rewrite the equations to slope-intercept form:

y < 2x -4 . . . . . . slope of 2, y-intercept of -4, shading below the dashed line

y < -x -1 . . . . . . . slope of -1, y-intercept of -1, shading below the dashed line

Therefore "solution" is the doubly-shaded area on the graph. Here, the dashed lines cross in a sort of X pattern, and the doubly-shaded area is the quadrant at the bottom (below both lines).

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