What is the value of x?


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Answer:

30 square meters

Answer:

How many square meters is a 7 meter by 8 meter rectangle? Use this easy and mobile-friendly calculator to compute the area of a rectangle given the length of ...

Step-by-step explanation:

Carlos has 13 pennies, 13 dimes, and 8 quarters in his box of coins.

Let's denote the number of pennies as "p", the number of dimes as "d", and the number of quarters as "q". Since the number of pennies is equal to the number of dimes, we can set up the following equation:

p = d

The total number of coins is given as 34, so we can write another equation:

p + d + q = 34

The value of the pennies can be represented as 0.01p, the value of the dimes as 0.10d, and the value of the quarters as 0.25q. The total value of the coins is $3.43, so we can set up another equation:

0.01p + 0.10d + 0.25q = 3.43

Now, substitute p = d into the second equation:

0.01(d) + 0.10d + 0.25q = 3.43

0.11d + 0.25q = 3.43

We have three equations:

p = d

p + d + q = 34

0.11d + 0.25q = 3.43

Substituting p = d into the second equation gives:

d + d + q = 34

2d + q = 34

We can rewrite the third equation as:

11d + 25q = 343

Now we have a system of two equations:

2d + q = 34

11d + 25q = 343

By solving these equations, we can find the values of d and q.

Using the substitution method, we can express q in terms of d from the first equation:

q = 34 - 2d

Substituting this value into the second equation:

11d + 25(34 - 2d) = 343

11d + 850 - 50d = 343

-39d + 850 = 343

-39d = 343 - 850

-39d = -507

d = -507 / -39

d = 13

Substituting the value of d back into the first equation:

p = d

p = 13

Finally, substituting the values of p and d into the equation for the total number of coins:

p + d + q = 34

13 + 13 + q = 34

q = 34 - 26

q = 8

Therefore, Carlos has 13 pennies, 13 dimes, and 8 quarters in his box of coins.

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Pepe Rodriquez works 42.5 hours at $6.20 per hour. The first 40 hours would be paid at the standard rate of $6.20 per hour, equaling $248.

The correct answer is B. $263.50, which is calculated by taking the standard pay of 40 hours at $6.20 per hour ($248) and adding the time-and-a-half pay of 2.5 hours at $9.30 per hour ($23.25).

Pepe Rodriquez works 42.5 hours at $6.20 per hour. The first 40 hours would be paid at the standard rate of $6.20 per hour, equaling $248. The remaining 2.5 hours would be paid at time-and-a-half, which is 1.5 times the hourly rate of $6.20, equaling $9.30 per hour. The total pay for the 2.5 hours is therefore $9.30 x 2.5 hours = $23.25. Adding the standard pay of $248 to the time-and-a-half pay of $23.25 yields a total of $263.50. Therefore, the correct answer is B. $263.50.

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The sign that goes in the circle to make the sentence true is >• 4/5+5/8= >1

Let us compare 4/5 and 5/8.

To compare the numbers, we have to get the lowest common multiple (LCM). We can derive the LCM by multiplying the denominators which are 5 and 8. 5×8 = 40

LCM = 40.

Converting 4/5 and 5/8 to fractions with a denominator of 40:

4/5 = 32/40

5/8 = 25/40

= 32/40 + 25/40

= 57/40

= 1.42.

4/5+5/8 = >1

1.42>1

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We cannot determine the percentage of pegilar grade gasoline sales between 3.27 and 53.63 per gallon or the percentage of regular gasoline sale price > 3.33/gallon as the total sales for both are not provided.

Given data:Pegilar grade gasoline sales between 3.27 and 53.63 per gallon.

Percentage of pegilar grade gasoline sale between 3.27 and 53.63 per gallon can be calculated as:X %.

Therefore,X% = (Sale between 3.27 and 53.63 per gallon) / Total sales * 100.

However, the total sales are not provided so we cannot calculate the percentage.

Further information is required.Similarly, for the second part, given data is:Regular gasoline sale price > 3.33/gallon.

Percentage of regular gasoline sale price > $3.33/gallon can be calculated as:Y %.

Therefore,Y % = (Regular sale price > $3.33/gallon) / Total sales * 100.

However, the total sales are not provided so we cannot calculate the percentage. Further information is required.

To summarize, we cannot determine the percentage of pegilar grade gasoline sales between 3.27 and 53.63 per gallon or the percentage of regular gasoline sale price > 3.33/gallon as the total sales for both are not provided.

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Since they need to find the weight of their suitcases to make sure they meet airline regulations. the units that they should use Kg.

Airport passengers are often needed to put only at least a single baggage any time in the check-in self-service so that the baggage can be checked and identified.

Note that the Maximum Weight per piece is said to be 50 lb/23 kg and the Maximum Dimensions is said to be 45 linear inches or 115 cm (including the length + width + height)

Therefore, Since they need to find the weight of their suitcases to make sure they meet airline regulations. the units that they should use Kg.

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See full question below

Maria and Jose, students at Mississippi Valley State University, are going to study abroad in Spain. They need to find the weight of their suitcases to make sure they meet airline regulations. What units should they use?

Answer:

well you want to set it up in a way that it shows how many days she mowed a lawn and then multiply by 10 and after add 12

Step-by-step explanation:

hope this makes sense :)

Answer:

well you want to set it up in a way that it shows how many days she mowed a lawn and then multiply by 10 and after add 12

Step-by-step explanation: good luck

Answer:

N1356

Step-by-step explanation: I hope it helps :)

\(Profit \% = 15\%\\Selling -Price = N1560.00\\C.P = ?\\\\CP = ( SP \times 100 ) / ( 100 + percentage \: profit).\\C.P =\frac{Selling \:price \times 100}{100+ Profit \%} \\\\C.P = \frac{1560\times 100}{100+15} \\\\C .P = \frac{156000}{115} \\\\C.P =N1356.5\)

Answer:

1/4

Step-by-step explanation:

Fractions have two parts, the numerator and the denominator. The denominator is the bottom number and it tells us what unit of fraction we are working with (ie: it denotes fourths, halves, etc.)

Hope it helps! :D

The term is called an identity element. In multiplication, the identity element is one because any number multiplied by one results in the same number. In addition, the identity element is zero because any number added to zero results in the same number.

The term in mathematics for the operation or number that leaves others unchanged when combined with them is called the identity element.

It is also known by the name of neutral element.

In multiplication, the identity element is one (1) because when you multiply a number by one the result remains the same as the original number. For any number a,

a1=1a=a.

While in addition, the identity element is zero (0) because when you add zero to a number, the result remains the same as the original number. For any number a,

a+0=0+a=a.

There is no identity element for subtraction, and division only has an identity element for certain sets.

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Answer:

1. 15

2. 45

3. There is a missing digit.

Step-by-step explanation:

Given:  y=3 and x= 1/2

4(6-4/2)-1

4(6-2)-1

4*4-1

16-1

15

4/2²2*27-10

4/2²+54-10

45: Numerical factors in this term have been multiplied.

Since he walks 96 meters per minute Frank will take 2400/96=25 minutes to complete the walk, then he will end by 7:10 a.m

Answer:

because

Step-by-step explanation:

when you make 16-2 it equals= 14

Answer: Therefore, the length of a blue bead is 2.5 cm, and the length of a green bead is 1.2 cm. And the length of the bracelet is:

10 × (2.5 + 1.2) = 37 cm.

Step-by-step explanation:

To represent the length of the bracelet, we need to determine the length of each repetition of the basic pattern and then multiply it by the number of times the pattern is repeated.

The length of each repetition of the basic pattern is the sum of the length of one blue bead and one green bead, which is:

B + 1.2 cm

Since the basic pattern is repeated 10 times, the total length of the bracelet is:

10 × (B + 1.2) cm

And we know that the total length of the bracelet is 37 cm, so we can set up an equation:

10 × (B + 1.2) = 37

Simplifying the equation, we can divide both sides by 10:

B + 1.2 = 3.7

Subtracting 1.2 from both sides, we get:

B = 2.5

Therefore, the length of a blue bead is 2.5 cm, and the length of a green bead is 1.2 cm. And the length of the bracelet is:

10 × (2.5 + 1.2) = 37 cm.

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Answer:

The equation that is graphed is y = one-half cosine (2 x) minus 1.

Answer:

\(x^2 = 16\)

\(x = \pm 4\)

Thus the answer is (b)

The solutions to the given quadratic equation are +4 and -4. Therefore, the option B is the correct answer.

The solutions to the quadratic equation are the values of the unknown variable x, which satisfy the equation. These solutions are called roots or zeros of quadratic equations. The roots of any polynomial are the solutions for the given equation.

The given quadratic equation is x²-16=0.

Now, x²=16

x=±√16

x=±4

x=+4 or x=-4

Therefore, the option B is the correct answer.

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Answer:

50

Step-by-step explanation:

A full circle is 360. The half circle you're looking at is 180.

So 180-65-65

Answer:

36 back

Step-by-step explanation:

100 - 64 = 36

Answer:

36¢

Step-by-step explanation:

1.00-0.64=0.36

Given:

Total number of students = 238

Let the number of passing students be x

We're given that 6 times the number of students passed as failed. Hence, the number of students:

Hence, we can write:

Solving for x:

Hence the number of passing students is 204 students

We can find the number of failing students by subtraction:

Answer:

Passing students: 204

Failing students: 34

Answer:

400

Step-by-step explanation:

6/8 = 0.75 or 75% expected to respond favorably.

Margin of error 2.5%:

  Lower bound: 0.75 - .025 = 0.725

  Upper bound: 0.75 + .025 = 0.775

Range:

  Lower bound: 8000 * 0.725 = 5800

  Upper bound: 8000 * 0.775 = 6200

  6200 - 5800 = 400

The ending dollar balance in inventory, using the FIFO method, is $973.

The cost of each sold unit must be tracked according to the sequence of the unit's purchase if we are to use the FIFO (First-In, First-Out) approach to calculate the ending dollar balance in inventory.

Let's begin by utilizing the FIFO approach to get COGS or the cost of goods sold. In order to attain the total number of units sold, we first sell the units from the earliest purchase (First Purchase) before moving on to the units from the second purchase (Second Purchase).

First Purchase:

Number of Units: 130

Cost per unit: $3.1

Second Purchase:

Number of Units: 451

Cost per unit: $3.5

We compute the cost based on the cost per unit from the First Purchase until we reach the total amount sold to estimate the cost of goods sold (COGS) for the 303 units sold:

Units sold from First Purchase: 130 units

COGS from First Purchase: 130 units × $3.1 = $403

Units remaining to be sold: 303 - 130 = 173 units

Units sold from Second Purchase: 173 units

COGS from Second Purchase: 173 units × $3.5 = $605.5

Total COGS = COGS from First Purchase + COGS from Second Purchase

Total COGS = $403 + $605.5 = $1,008.5

To calculate the ending dollar balance in inventory, we need to subtract the COGS from the total cost of inventory.

Total cost of inventory = (Quantity of First Purchase × Cost per unit) + (Quantity of Second Purchase × Cost per unit)

Total cost of inventory = (130 units × $3.1) + (451 units × $3.5)

Total cost of inventory = $403 + $1,578.5 = $1,981.5

Ending dollar balance in inventory = Total cost of inventory - COGS

Ending dollar balance in inventory = $1,981.5 - $1,008.5 = $973

Therefore, the ending dollar balance in inventory, using the FIFO method, is $973.

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Answer:

For a cylinder there is 2 kinds of formulas the lateral and the total. the lateral surface area is just the sides the formula for that is 2(pi)radius(height). the formula for the total surface area is 2(pi)radius(height) + 2(pi)radius squared.

Step-by-step explanation:

Answer:

\(h=\frac{1}{3} \pi r^{2} v\)

Step-by-step explanation:

height is equal to one third times pi times radius squared times volume

The expression of the volume of the cone in terms of height H will be as H = 3V/(πR²).

A mixture of variables, numbers, addition, subtraction, multiplication, and division are called expressions.

An expression is a mathematical proof of the equality of two mathematical expressions.

As per the given volume of the cone,

V=(1/3)πR²H

Manipulate the above formula as,

[V (3/1)]/(πR²) = H

H = 3V/(πR²)

Hence "The expression of the volume of the cone in terms of height H will be as H = 3V/(πR²)".

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Step-by-step explanation:

Break it up into two trapezoids as shown

area = trap1 + trap2

      = 2 *   (7+3) / 2   + 3 *  ( 7 + 3) / 2 = 10 + 15 = 25 units^2

The linear demand function for DVDs is q(p) = 391.47 - (49/17) p, where q is the quantity demanded and p is the price.

To find the linear demand function, we can use the two data points given:

Let's assume that the demand function takes the form:

q = a - bp

where q is the quantity demanded, p is the price, a is the intercept, and b is the slope of the demand function.

Using the first data point (15 dollars, 132 units per week), we have:

132 = a - 15b

Using the second data point (32 dollars, 83 units per week), we have:

83 = a - 32b

Now we have two equations with two unknowns, a and b. Solving for a and b, we get:

b = (132 - 83) / (15 - 32) = 49/17

Substituting b in the first equation, we get:

132 = a - 15(49/17)

a = 132 + 15(49/17) = 391.47

Therefore, the demand function is:

q = 391.47 - (49/17) p

So, the demand for DVDs as a function of price is:

q(p) = 391.47 - (49/17) p

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The expression 19(\(\sqrt[5]{8}\))^4 in rational exponent form is (152)^(4/5) and the expression (-4)^(2/7) in radical form is     \(\sqrt[7]{(-4)^{2} }\).

What is rational exponent form?

In the formula a^(p/q), where a is the base and p/q is the rational exponent and q≠0, rational exponents are exponents of numbers that are expressed as rational numbers.

The first expression is -

19(\(\sqrt[5]{8}\))^4

Solve it to get rational exponent form -

Apply the rule n√x^m=x^(m/n) to rewrite the expression as a rational exponent.

= 19(\(\sqrt[5]{8}\))^4

= 19 × (\(\sqrt[5]{8}\))^4

= 19 × (8)^(4/5)

= (152)^(4/5)

The second expression is -

(-4)^(2/7)

Solve it to get the radical form -

Apply the rule x^(m/n)=n√x^m to rewrite the expression as a radical.

= (-4)^(2/7)

= \(\sqrt[7]{(-4)^{2} }\)

Therefore, the values are obtained as (152)^(4/5) and \(\sqrt[7]{(-4)^{2} }\).

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The area of the triangle UVW is approximately \(48.020 \ mm^2\), and the height (perpendicular) WX is approximately \(5.339 \ mm\).

To find the area of a triangle, we can use the formula:

\(\[ \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} \]\)

In this case, the \(18\) mm side can be considered as the base, and we need to find the height of the triangle. To find the height, we can use trigonometry.

Side UV is \(18 \ mm\), side VW is \(7 \ mm\), and angle UVW is \(48\)°.

To find the height of the triangle, we need to determine the length of the perpendicular from point W to side UV.

Using trigonometry, we can determine the height \((\( h \))\) using the formula:

\(\[ h = BC \times \sin(\text{angle UVW}) \]\)

Let's calculate it:

\(\[ h = 7 \, \text{mm} \times \sin(48^\circ) \approx 5.339 \, \text{mm} \]\)

Now, we can calculate the area of the triangle:

\(\[ \text{Area} = \frac{1}{2} \times \text{base} \times \text{height} = \frac{1}{2} \times 18 \, \text{mm} \times 5.339 \, \text{mm} \approx 48.020 \, \text{mm}^2 \]\)

Therefore, the area of the triangle is approximately \(48.020 \ mm^2\), and the height (perpendicular) just opposite the \(48\)° angle is approximately \(5.339 \ mm\).

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The National Oceanic and Atmospheric Administration (NOAA) is a scientific agency within the United States Department of Commerce, and is responsible for conducting hydrographic surveys. The agency has a preferred tow height for side scan sonar at different ranges scales.

NOAA has a preferred tow height of 50 meters for Side Scan Sonar using a 50 m range scale. As per the agency, when conducting side scan sonar at 50 meters range scale, the sonar system should be towed at a height of 0.12H to 0.25H, where H is the total height of the side scan sonar from the transducer face to the towing bridle.

It is recommended by NOAA that the side scan sonar should be towed at a height of 0.12H to 0.25H above the seafloor while conducting the side scan sonar survey. By doing so, the sonar system will be able to transmit the sound waves at an appropriate angle to get a clear image of the seafloor. Additionally, it will avoid the shadow effect, which occurs due to the high side lobe levels of the side scan sonar.

If the range scale decreases to 25 meters, the towing height should be reduced to 0.08H to 0.12H. The shadow effect is more prominent at the 25-meter range scale because the sound waves are more directional at this range scale.

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