Answers
Answer:
λ = 5.773 x 10⁻⁷ m = 577.3 nm
Explanation:
In order to solve this problem we will use the grating equation:
mλ = d Sin θ
where,
m = order = 3
λ = wavelength of light = ?
d = slit separation = 2 μm = 2 x 10⁻⁶ m
θ = angle = 60°
Therefore,
(3)λ = (2 x 10⁻⁶ m)Sin 60°
λ = 1.732 x 10⁻⁶ m/3
λ = 5.773 x 10⁻⁷ m = 577.3 nm
Related Questions
The three pieces of evidence that Alfred Wegener used to support his theory that the Earth's continents are what?
Answers
Cody hits up food king and uses a scale to weigh the mass of an apple. if the spring potential energy in the scale is .09 j and is spring is stretched 0.6 meters, calculate the spring constant
Answers
Answer:
oK so here's what you should do is add .09 and 0.6
Explanation:
what is calculator program
Answers
Answer:
software calculator is a calculator that has been implemented as a computer program, rather than as a physical hardware device. They are among the simpler interactive software tools, and, as such, they: Provide operations for the user to select one at a time.
Answer: The calculator is a compact portable device that performs mathematical calculations. Some calculators also allow easy text editing and programming. It's also a programming software that simulates a portable calculator. Calculator applications help you make basic math calculations without leaving your screen.
How do nutritional needs change when a person increases their activity level to gain muscle mass?
Answers
When a person increases their activity level to gain muscle mass, their nutritional needs change.
How utritional needs change when a person increases their activity level to gain muscle mass?The key changes include increasing protein intake to support muscle growth and repair, consuming a slight caloric surplus to provide energy for muscle development, ensuring sufficient carbohydrate intake for fuel, including healthy fats for overall health, staying hydrated, and considering essential micronutrients.
Individual variations exist, so seeking personalized guidance from a professional is recommended.
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The slope of a displacement time graph for a uniform motion represent what
Answers
Answer:
Velocity.
Explanation:
The slope of a displacement time graph for a uniform motion represent the gradient of the line i.e. the velocity of the object.
The velocity of an object is given by :
v = d/t
Where
d is displacement
t is time
Hence, the slope of the displacement-time graph gives the velocity of the object.
A 1. 20-gram sample of a hydrated salt is heated to a constant mass of 0. 80 gram. What was the percent by mass of water contained in the original sample?.
Answers
Water has a mass of 1.20 - 0.80 = 0.40 gram.
The water percentage is (0.40 / 1.20) * 100 = 33 1/3%
Evaporation is the physical process through which water transitions from a liquid to a gaseous state and then returns to the atmosphere as steam. Water in solid form (snow or ice) can also move straight to steam, a process known as sublimation. The word must be defined in a broad sense, including sublimation, to consequences of predicting evaporation losses in a region. Solar radiation supplies the energy required for water molecules to shift states.
Calculations:
Initial mass - ultimate mass of evaporated water
Evaporated water: 1.2 g - 0.8 g
0.4 g = evaporated H20
100% 1.2 g total mass
0.4 g of H20 --> 33.33 %
The initial sample has 33.33% of its mass in water.
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A rightward force of 4.0 N is exerted upon an object for a distance of 3.0 meters.
What is the work done on the object?
Answers
Answer:
W = 12 J
Explanation:
Given that,
Force, F = 4 N
The object moves in rightward direction for a distance of 3 m.
Work done on the object is given by :
\(W=F\times d\\\\=4\ N\times 3\ m\\\\=12\ J\)
So, the work done on the object is 12 J.
An ideal monatomic gas expands isothermally from 0.540 m3 to 1.25 m3 at a constant temperature of 720 K. If the initial pressure is 1.20e5 Pa.
a) Find the work done on the gas
b) Find the thermal energy transfer Q
c) Find the change in the internal energy
Answers
Answer:
a) The work done on the gas during an isothermal expansion is given by:
W = nRT ln(V2/V1)
where n is the number of moles of gas, R is the gas constant, T is the temperature, V1 is the initial volume, and V2 is the final volume.
Since the gas is monatomic, we can use the ideal gas law to find the number of moles:
PV = nRT
n = PV/RT
Substituting this expression for n into the equation for work, we get:
W = PV ln(V2/V1)
where we have cancelled out the R and T terms.
Substituting the given values, we get:
W = (1.20e5 Pa)(0.540 m^3) ln(1.25/0.540) = 1.38e4 J
b) The thermal energy transfer Q during an isothermal process is equal to the work done on the gas. Therefore, Q = 1.38e4 J.
c) The change in internal energy ΔU of a gas during an isothermal process is zero, since the temperature of the gas does not change. Therefore, ΔU = 0.
W = nRT ln(Vf/Vi)
where:
- n is the number of moles of gas
- R is the gas constant (8.31 J/mol*K)
- T is the temperature of the gas
- Vi and Vf are the initial and final volumes of the gas, respectively
Since the gas is monatomic, its molar specific heat at constant volume is Cv = (3/2)R, and its molar specific heat at constant pressure is Cp = (5/2)R. Since the process is isothermal, the temperature of the gas remains constant, so T = 720 K for both Vi and Vf. Therefore, we can simplify the equation for work to:
W = nRT ln(Vf/Vi) = nRT ln(1.25/0.540)
We can calculate the number of moles of gas using the ideal gas law:
PV = nRT
n = PV/RT
Substituting the given values, we get:
n = (1.20 x 10^5 Pa)(0.540 m^3)/(8.31 J/mol*K)(720 K) ≈ 9.86 mol
Therefore, the work done on the gas is:
W = nRT ln(1.25/0.540) ≈ 9.92 x 10^3 J
b) The thermal energy transfer Q during an isothermal process is equal to the work done on the gas:
Q = W ≈ 9.92 x 10^3 J
c) The change in internal energy ΔU of an ideal gas during an isothermal process is zero, since the temperature of the gas remains constant and internal energy is a function of temperature only. Therefore, ΔU = 0.
A boat sails for 24 km pointed in the direction [40° S of WI. A constant current moves the boat 8 km [30° W of N]. If the trip takes 3 hours, find the boats resultant velocity
Please brainliest, really need it!!!
Answers
The resultant velocity of the boat is 7.5 km/h.
What is the resultant displacement of the boat?The resultant displacement of the boat is calculated as follows;
Sum of the vertical displacement of the boat is calculated as;
∑Fy = -24 km sin(50) + 8 km sin(60)
∑Fy = -11.5 km
Sum of the horizontal displacement of the boat is calculated as;
∑Fx = -24 km cos(50) - 8 km cos(60)
∑Fx = -19.4 km
The resultant displacement is calculated as follows;
d = √ (-11.5² + 19.4²)
d = 22.55 km
The resultant velocity of the boat is calculated as follows;
v = ( 22.55 km ) / ( 3 hrs )
v = 7.5 km/h
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How much impulse is imparted on a 0.14 kg baseball initially traveling at 32 m/s when it is struck by a baseball bat and begins to travel in the opposite direction at 49 m/s
Answers
ANSWER AND EXPLAINATION:
To calculate the impulse imparted on the baseball, we can use the impulse-momentum principle, which states that the impulse experienced by an object is equal to the change in momentum of the object. Mathematically, it can be expressed as:
Impulse = Change in momentum
The momentum of an object is given by the product of its mass and velocity:
Momentum = mass × velocity
In this case, the baseball has an initial mass of 0.14 kg and an initial velocity of 32 m/s. After being struck by the bat, it travels in the opposite direction at a velocity of 49 m/s.
Therefore, the change in momentum is given by:
Change in momentum = (mass × final velocity) - (mass × initial velocity)
Change in momentum = mass × (final velocity - initial velocity)
Change in momentum = 0.14 kg × (49 m/s - (-32 m/s))
Change in momentum = 0.14 kg × (49 m/s + 32 m/s)
Change in momentum = 0.14 kg × 81 m/s
Change in momentum = 11.34 kg·m/s
So, the impulse imparted on the baseball is 11.34 kg·m/s.
long narrow uniform stick of length ! and mass m lies motionless on ice (assume the ice provides a frictionless surface). The center of mass of the stick is the same as the geometric center (at the midpoint of the stick). The moment of inertia of the stick about its center of mass is lcm . A puck (with putty on one side) has same mass m as the stick. The puck slides without spinning on the ice with a speed of v0 towards the stick, hits one end of the stick, and attaches to it. You may assume that the radius of the puck is much less than the length of the stick so that moment of inertia of the puck about its center of mass is negligible compared to Icm . (a) How far from the midpoint of the stick is the center of mass of the stick-puck combination after the collision?
Answers
Answer:
the answer would be 0 as known to the lengthExplanation:
0m x96 would put as an mass of 900 into 0 so there for your answer would be 0
2. For electric circuit shown in Figure find currents in each resistor.
Answers
The current flowing in the 2Ω and 1Ω is 1.14 A and the current flowing in the 3Ω and 4Ω is 0.286 A.
What is the current flowing in each resistor?The value of the current in each resistor is calculated by applying Kirchoff voltage law as follows;
The total voltage in loop 1 is calculated as;
2 + 4 - I₁R₁ - (I₁ - I₂)R₂ - I₁R₃ = 0
6 - 2I₁ - 3(I₁ - I₂) - 1₁ = 0
The current flowing in loop 2 is calculated as;
I = V/R
I₂ = ( 6 V - 4 V ) / (3 + 4)
I₂ = 0.286 A
The value of the current flowing in loop 1 is calculated as;
6 - 2I₁ - 3(I₁ - I₂) - 1₁ = 0
6 - 2I₁ - 3(I₁ - 0.286) - 1₁ = 0
6 - 3I₁ - 3₁ + 0.858 = 0
-6I₁ = -6.858
I₁ = 6.858 / 6
I₁ = 1.14 A
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The motion of a ball on an inclined plane is described by the equation Ax = 1/2a(At)^2. This statement implies which of the following quantities has a value of zero?
Answers
Answer: Initial Velocity
Explanation:
The formula is:
Δx = Vit + 1/2at^2
Therefore the initial velocity is zero
A river flows at a velocity of 3 km/h relative to the riverbank. A boat moves downstream at a velocity of 15 km/h relative to the river. What is the velocity of the boat relative to the riverbank?
Answers
Think about it like this. The boat is going 15 faster than the river, and the river is going 3 faster than the bank, so the boat is going 18 faster than the river bank
as seen from above, a 73.8 kg water skier is pulled by a 105 N force at a 22.5 angle, while the water creates a 74.8 N force pulling directly backward. What is the y-component of the total force on the skier?
Answers
Answer:
40.2 N
Explanation:
I'm an Acellus student who got it correct.
The magnitude of y-component of the total force on the skier is 40.18 N.
What is force?Force is an influence which tends to set a stationary body in motion or stop a moving body, or which tends to change the speed and direction of a moving body, or which tends to change the shape and size of body.
Given parameters:
Mass of the water: M = 73.8 kg.
Magnitude of force acting at 22.5° angle is: F₁ = 105 N.
Magnitude of force acting at directly backwards is: F₂ = 74.8 N.
We have to find: the y-component of the total force on the skier = ?
As F₂ acting directly backwards, this force has no y-component.
Hence, resultant y-component of the total force on the skier
= F₁ sin22.5°
= 105 ×sin22.5° N.
= 40.18 N.
Hence, magnitude of y-component of the total force on the skier is 40.18 N.
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Why does the force of gravity on Earth always pull things down?
a
The force of gravity on Earth is always pointing down
b
The force of gravity on Earth always points to the center of the planet
c
The force of gravity on Earth is a force that repulses
d
The force of gravity on Earth is a force that pulls objects away from each other
Answers
Explanation:
the answer is D because of inertia aka the force that pulls obejects downs
Mario places 10 mL of water in a test tube and heats the liquid over a Bunsen burner for 2 minutes. After removing the test tube from the Bunsen burner, there are 6 mL of water left in the test tube. This experiment is a good example of a
Answers
Answer:
water cycle your welcome
Answer:
This experiment is a good example of a water cycle
Explanation:
Two identical 0.25 kg balls are involved in a head-on collision. Ball A is initially travelling at 3.5 m/s, and ball B is initally at rest. Determine the velocity of each ball after the collision.
Answers
Answer:
a) mv(final):<0,0,0> minus mv(initial):<25,0,0> = <-25,0,0>
b) mv(final):<25,0,0> minus mv(initial):<0,0,0> = <25,0,0>
c) conservation of momentum makes it <0,0,0>
for a-b-c, momentum_system + momentum_surroundings = 0
Explanation:
Hope this helps
The velocity of each ball after the collision is 1.75 m/s
Law of conservation of momentum states that:
Total momentum before collision = Total momentum after collision
m₁u₁ + m₂u₂ = (m₁ + m₂)v
Where m₁, m₂ is the mass of object, u₁, u₂ is the initial velocity before collision and v is the final velocity after collision
Given that: m₁ = m₂ = 0.25 kg, u₁ = 3.5 m/s, u₂ = 0, hence:
0.25(3.5) + 0.25(0) = (0.25 + 0.25)v
v = 1.75 m/s
The velocity of each ball after the collision is 1.75 m/s
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Iu Metallic bonding is similar to iconic bonding because
Answers
Answer:
In an ionic bond the valence electrons are transferred from the metal
Explanation:
A crow is flying horizontally with a constant speed of 2.70m/s when it releases a claim from its beak. The clan lands on the rocky Beach 2.10s later. Just before the clam lands, what is (a) its horizontal component of velocity and (b) its vertical component of velocity? (c) How would your answers to parts (a) and (b) change if the speed of the crow were increased? Explain.
Answers
Given:
Speed = 2.70 m
Time, t = 2.10 seconds
Let's solve for the following:
• (a) The horizontal component of the velocity.
To find the horizontal component, apply the formula:
\(V_{ox}=V_o\cos \theta\)Where:
Vo is the initial speed = 2.70 m
θ = 0 degrees
Hence, we have:
\(\begin{gathered} V_{ox}=2.70\cos 0 \\ \\ V_{ox}=2.7\text{ m/s} \end{gathered}\)The horizontal component of the velocity just before it lands is 2.70 m/s.
• (b) The vertical component of the velocity.
To find the vertical component, apply the formula:
\(V_{oy}=V_{0y}-gt=\text{V}_{oy}\text{ sin}\Theta-gt\)Where:
g is the acceleration due to gravity = 9.8 m/s²
t is the time = 2.10 s
Hence, we have:
\(\begin{gathered} V_{oy}=V_{oy}\sin \theta-gt \\ \\ V_{oy}=2.70\sin 0-9.8(2.10) \\ \\ V_{oy}=0-20.58 \\ \\ V_{oy}=-20.58\text{ m/s} \end{gathered}\)The vertical component of the velocity just before it lands is -20.58 m/s.
(c) Here, the initial speed is equal to the constant horizontal speed.
Therefore, in part (a) the horizontal component will increase in the x-direction if the speed of the crow is increased.
The initial vertical velocity is 0 m/s in both cases.
Therefore, in part (b) the vertical component will remain constant.
ANSWER:
(a) 2.70 m/s
(b) -20.58
(c) In part (a) the horizontal component will increase, while in part (b) the vertical component will remain constant.
Robert Galstyan, from Armenia, pulled two coupled railway wagons a distance of 7 m using his teeth. The total mass of the wagons was about 2.20 X 10^5 kg. Of course, his job was made easier by the fact that the wheels were free to roll. Suppose the wheels are blocked and the coefficient of static friction between the rails and the sliding wheels is 0.220. What would be the magnitude of the minimum force needed to move the wagons from rest? Assume that the track is horizontal.
Answers
The magnitude of the minimum force needed to move the wagons from rest is 474320 N
How do I determine the force needed to move the wagons?We have come to know that the force and coefficient of friction have a simple relationship as shown by the equation below:
Frictional force (N) = coefficient of friction (μ) × normal reaction (N)
F = μN
Applying the above formula, we can determine the force needed to move the wagons from rest. Details below:
Mass of wagons (m) = 2.20×10⁵ KgAcceleration due to gravity (g) = 9.8 m/s²Normal reaction (N) = mg = 2.20×10⁵ × 9.8 = 2156000 NCoefficient of static friction (μ) = 0.220Force needed (F) = ?F = μN
F = 0.220 × 2156000
F = 474320 N
Thus, the force needed is 474320 N
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PLEASE ANSWER FASG I WILL MARK BRAINELIST PLEASEEEEE
The number of protons in the nucleus of an atom determines the species of the atom, i.e., the element to which the atom belongs. An atom has the same number of protons and neutrons. But the electron number cannot be used instead because (5 points)
a. electrons are not within the nucleus
b. electrons are negatively charged
c. electrons can be removed from or added to an atom
d. electrons are lighter than protons
Answers
The electron number cannot be used instead because electrons can be removed from or added to an atom (option C)
Why the electron number cannot be used instead?The element of an atom is determined by its proton count, while the electron count can exhibit variability. Take, for instance, a sodium atom, which encompasses 11 protons and 11 electrons. However, it has the capacity to relinquish one electron, transforming into a sodium ion housing only 10 electrons.
This occurs due to the relatively loose binding of electrons to the nucleus, enabling their removal through the influence of an electric field or alternative mechanisms.
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Select the correct answer from each drop-down menu. Because of location, the has become a center for transportation. The is also a center for transportation and home to the nation’s busiest airport.
Answers
Because of location, the Hartsfield Jackson international airport has become a center for transportation. The is also a center for transportation and home to the nation’s busiest airport.
What is transportation?It should be noted that transportation simply means the movement of people and animals from one location to another. It should be noted that there are different means of transportation such as rail, air, road, etc.
In this case, because of location, the Hartsfield Jackson international airport has become a center for transportation. The is also a center for transportation and home to the nation’s busiest airport. This is located in Atlanta Georgia.
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Select the correct answer from each drop-down menu. Because of location, the has become a center for transportation. The is also a center for transportation and home to the nation’s busiest airport.
a. Dallas International Airport.
b. Denver International Airport.
c. John Kennedy International Airport
d. Hartsfield Jackson international airport
-What is the wavelength of an X-ray photon with energy 9.0 keV (9000 eV )? (1 eV = 1.60 × 10 −19 joule.)
-What is its frequency?
Answers
wavelength = hc/E
= (6.63 x 10^-34 J*s) * (2.998 x 10^8 m/s) / (9000 eV * 1.60 x 10^-19 J/eV)
= 1.53 x 10^-11 m
To find the frequency of the photon, we can use the equation:
frequency = c/wavelength
Plugging in the values, we get:
frequency = (2.998 x 10^8 m/s) / (1.53 x 10^-11 m)
= 1.95 x 10^19 Hz
This is the frequency of the X-ray photon.
The back emf in a motor is 72 V when operating at 1800 rpm. What would be the back emf at 2500 rpm if the magnetic field is unchanged?
Answers
The back emf at 2500 rpm if the magnetic field is unchanged is 100 V for the back emf in a motor is 72 V when operating at 1800 rpm.
The back emf in a motor is proportional to the speed of the motor. Therefore, we can use the following formula to determine the back emf at 2500 rpm:
E2 = E1 × (N2 / N1)
where E1 is the back emf at 1800 rpm, N1 is the speed at which the back emf was measured, E2 is the back emf at 2500 rpm, and N2 is a new speed.
Plugging in the values we get:
E2 = 72 V × (2500 rpm / 1800 rpm)
E2 = 100 V
Therefore, the back emf at 2500 rpm of the motor would be 100 V if the magnetic field is unchanged.
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Two spheres have identical charges and are 0.75 m apart. The force between them is
+0.30 N. What is the magnitude of the charge on each sphere?
What can you tell about the charge signs on the spheres?
Answers
Like charges repel other like charges, and unlike charges attract, according to Coulomb's theory of the electric force for charges in a resting state.
What is Coulomb's law in simple terms?The characteristics of the electric force for charges in a resting state, according to Coulomb, are as follows: The opposite of a charge's attraction is the opposite of its repellency. Therefore, a positive charge attracts a negative charge, whereas two negative charges repel one another.
The charge on each sphere has a magnitude of 4.33 10(-6) C.
We receive;
r = 75 cm = 0.75 m, the distance between the centres of two spheres.
The force between the charges is F = 0.3 N.
The equation for the force between charges is F = (kq1q2)/r2.
Where;
k is a constant and equals 9 10(9) N.m2/C2.
The charges are equivalent, hence q1 = q2 = q.
Thus;
F = kq²/r²
q = √(Fr²/k)
q = √(0.3 × 0.75²/(9 × 10^(9))
q = 4.33 × 10^(-6) C
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A 1500-kg car goes around a flat 25-m-radius circular track at 10 m/s (approximately 22 mph). What is the maximum speed this car can go without sliding, in m/s? The coefficients of friction between the tire and the road on a dry day are µs = 1.0 and µk= 0.80. Use g = 10 m/s2.
Answers
The maximum speed that the car can gο arοund the circular track withοut sliding is apprοximately 27.39 m/s.
What is a fοrce?Fοrce is a physical quantity that describes the interactiοn between twο οbjects οr between an οbject and its envirοnment. A fοrce can cause an οbject tο accelerate, change directiοn, οr defοrm. Fοrce is a vectοr quantity, meaning it has bοth magnitude and directiοn. It is measured in units οf Newtοns (N).
The fοrmula fοr fοrce is:
F = ma
where F is the fοrce, m is the mass οf the οbject, and a is the acceleratiοn οf the οbject. This fοrmula is knοwn as Newtοn's Secοnd Law οf Mοtiοn. It states that the fοrce acting οn an οbject is directly prοpοrtiοnal tο its mass and acceleratiοn.
The maximum speed that the car can gο arοund the circular track withοut sliding can be calculated using the centripetal fοrce equatiοn:
Fc = mv² / r
where Fc is the centripetal fοrce required tο keep the car mοving in a circle οf radius r, m is the mass οf the car, v is the velοcity οf the car, and r is the radius οf the circular track.
Tο prevent sliding, the fοrce οf static frictiοn between the tires and the rοad must be greater than οr equal tο the maximum fοrce that can be exerted by static frictiοn, which is equal tο µs times the nοrmal fοrce (N = mg), where µs is the cοefficient οf static frictiοn and g is the acceleratiοn due tο gravity.
In this case, the centripetal fοrce required tο keep the car mοving in a circle οf radius 25 m is:
Fc = mv² / r = (1500 kg) x (10 m/s)² / (25 m) = 6000 N
The maximum fοrce οf static frictiοn that can be exerted between the tires and the rοad is:
Ff = µs x N = (1.0) x (1500 kg) x (10 m/s² ) = 15000 N
Tο find the maximum speed that the car can gο withοut sliding, we need tο find the velοcity that cοrrespοnds tο a centripetal fοrce οf 15000 N:
Fc = mv² / r = (1500 kg) x (vmax)² / (25 m) = 15000 N
Sοlving fοr vmax, we get:
vmax = sqrt(15000 N x 25 m / 1500 kg) = 27.39 m/s
Therefοre, the maximum speed that the car can gο arοund the circular track withοut sliding is apprοximately 27.39 m/s.
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A wire carrying 19.6 amps of current has a length of 29.5 centimeters within a magnetic field of strength 0.946 teslasa. What is the force on the wire if it makes an angle with the magnetic field of 90.0 degrees? b. What is the force on the wire if it makes an angle with the magnetic field of 29.6 degrees?
Answers
Given:
Length , L = 29.5 cm
Current, I = 19.6 A
B = 0.946
Let's find the following:
(a). Force on the wire if it makes an angle with the magnetic field of 90.0 degrees.
To find the force, apply the formula
\(F=BILsin\theta\)Where:
B is the magnetic field strength = 0.946 T
I is the current = 19.6 A
L is the length of the wire in meters.
Here, the length is in cm, let's convert from cm to m.
We have:
1 cm = 0.01 m
29.5 cm = 29.5 x 0.01 = 0.295 m
Plug in the values and solve for the force, F.
\(\begin{gathered} F=0.946*19.6*0.295sin90 \\ \\ F=5.47\text{ N} \end{gathered}\)Therefore, the force when the angle is 90 degrees is 5.47 N.
• (b). The force on the wire when the angle is 29.6 degrees.
\(\begin{gathered} F=0.946*19.6*0.295sin29.6 \\ \\ F=2.7\text{ N} \end{gathered}\)The force when it makes an angle of 29.6 degrees is 2.70 N.
ANSWER:
(a). 5.47 N
(b). 2.70 N
If the Earths atmosphere is air, then why doesn't the land fall? How is all the lava and water IN earth?
Answers
Answer:
Its stored in there
Explanation:
And air has little mass
A block has two strings attached to it on opposite ends. One string has a force of 5 N,
the other string a force of 15 N. The block is accelerating at 1 m/s2 on a horizontal surface.
A) What is the mass of the block if the friction force is 3 N?
B) What is the coefficient of friction?
Answers
Answer:
A) 7kg
B) 0.044
Explanation:
a) Accordimg to Newton's second law
\sum F = ma
Fm - Ff = ma
Fm is moving force =15-5 = 10N
Ff is fictional force = 3N
m is the mass = ?
a Is the acceleration = 1m/s²
Substitute
10-3 = 1m
7 = m
Hence the mass of the body is 7kg
b) coefficient of friction is expressed as;
n = Ff/R
R is the reaction = mg
n =Ff/mg
Substitute
n = 3/7(9.8)
n = 3/68.6
n = 0.044
Hence the coefficient of friction is 0.044