what is y=x+2and 2x+y=8

Yes, $9 for 4 visitors and $18 for 8 site visitors are proportional.

To determine whether or not $9 for 4 visitors and $18 for 8 visitors are proportional, we need to test if the ratio of the value to the number of visitors is the equal for both cases.

The ratio of cost to the quantity of visitors for $9 and four visitors is:

$9/4 visitors = $2.25/ visitors

The ratio of value to the quantity of visitors for $18 and eight visitors is:

$18/8 visitors = $2.25/ visitors

We are able to see that both ratios are equal to $2.25 per visitor.

Therefore, $9 for 4 visitors and $18 for 8 site visitors are proportional.

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a) the odds against the team winning its next match are 8/19.

b) the probability of winning a new TV is 3/16.

(a) To find the odds against the rugby team winning its next match, we can use the probability of the team winning. The odds against an event are calculated by subtracting the probability of the event from 1 and expressing it as a ratio.

Probability of the team winning = 11/19

Odds against the team winning = 1 - (11/19) = 8/19

Therefore, the odds against the team winning its next match are 8/19.

(b) To find the probability of winning a new TV, we can use the given odds in favor of winning. The odds in favor of an event can be expressed as a ratio of favorable outcomes to total outcomes.

Odds in favor of winning a new TV = 3/13

Probability of winning a new TV = favorable outcomes / total outcomes

Probability of winning a new TV = 3 / (3 + 13) = 3/16

Therefore, the probability of winning a new TV is 3/16.

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Answer:first do the exponents thats equal to 9 then times -2 is -16+7 is -11

hope that helps

Step-by-step explanation:

Answer:

-11.

Step-by-step explanation:

7+(-2)•3^2

= 7 - 2*9

= 7 - 18

= -11.

We have proved that Angle BCD is equal to angle BAD plus angle ABC plus angle ADC, as required.

To prove that angle BCD is equal to angle BAD plus angle ABC plus angle ADC, we can use the following steps:

Step 1: Join points A and C with a line segment. Let's label the point where AC intersects with line segment BD as point E.

Step 2: Since line segment AC is drawn, we can consider triangle ABC and triangle ADC separately.

Step 3: In triangle ABC, we have angle B + angle ABC + angle BCA = 180 degrees (due to the sum of angles in a triangle).

Step 4: In triangle ADC, we have angle D + angle ADC + angle CDA = 180 degrees.

Step 5: From steps 3 and 4, we can deduce that angle B + angle ABC + angle BCA + angle D + angle ADC + angle CDA = 360 degrees (by adding the equations from steps 3 and 4).

Step 6: Consider quadrilateral ABED. The sum of angles in a quadrilateral is 360 degrees.

Step 7: In quadrilateral ABED, we have angle BAD + angle ABC + angle BCD + angle CDA = 360 degrees.

Step 8: Comparing steps 5 and 7, we can conclude that angle B + angle BCD + angle D = angle BAD + angle ABC + angle ADC.

Step 9: Rearranging step 8, we get angle BCD = angle BAD + angle ABC + angle ADC.

Therefore, we have proved that angle BCD is equal to angle BAD plus angle ABC plus angle ADC, as required.

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Given: Quadrilateral \(\displaystyle\sf ABCD\)

To prove: \(\displaystyle\sf \angle BCD = \angle BAD + \angle ABC + \angle ADC\)

Proof:

1. Draw segment \(\displaystyle\sf AC\) and extend it to point \(\displaystyle\sf E\).

2. Consider triangle \(\displaystyle\sf ACD\) and triangle \(\displaystyle\sf BCE\).

3. In triangle \(\displaystyle\sf ACD\):

4. In triangle \(\displaystyle\sf BCE\):

5. Since \(\displaystyle\sf \angle BCE\) and \(\displaystyle\sf \angle BCD\) are corresponding angles formed by transversal \(\displaystyle\sf BE\):

6. Combining the equations from steps 3 and 4:

Therefore, we have proven that in quadrilateral \(\displaystyle\sf ABCD\), \(\displaystyle\sf \angle BCD = \angle BAD + \angle ABC + \angle ADC\).

\(\huge{\mathfrak{\colorbox{black}{\textcolor{lime}{I\:hope\:this\:helps\:!\:\:}}}}\)

♥️ \(\large{\underline{\textcolor{red}{\mathcal{SUMIT\:\:ROY\:\:(:\:\:}}}}\)

Answer:

2x + 5

Step-by-step explanation:

I am assuming you are talking about a linear function. If it is, then the equation would be:

2x + 5.

Hope this helps!

Answer:

\(y = 2x + 5\)

Step-by-step explanation:

For this example, I used the slope-intercept form, \(y = mx + b\), where m represents the slope and b represents the y-intercept.

In order to find the equation, we must find the slope and y-intercept.

The slope can be found with the formula:

\(m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}\), where the x and y variables represent different x and y values from the given points.

Substituting in values from the points, we get:

\(m = \frac{-1 + 9}{-3 + 7}\\\\m = \frac{8}{4}\\\\m = 2\)

In order to find the y-intercept, we must substitute the slope back into the original equation:

\(y = 2x + b\)

After this, we must also substitute either of the two points. Both will give the correct answer, but (-3, -1) will be used for this example.

\(-1 = 2(-3) + b\\-1 = -6 + b\\5 = b\)

After this, all that must be done is to substitute the values for b and m back into the original equation.

\(y = 2x + 5\)

To check our work, we can substitute in either of the given points. For demonstration purposes, (-7, -9) will be used.

\((-9) = 2(-7) + 5\\-9 = -14 + 5\\-9 = -9\)

The diagonal matrix A' for T relative to the basis \(\(B'\)\) is:

\(\[A' = \left[ \begin{array}{ccc} 3 & -4 & 0 \\ -2 & -1 & 0 \\ 0 & 0 & 1 \end{array} \right]\]\)

To find the diagonal matrix A' for the linear transformation T relative to the basis B', we need to perform a change of basis using the given matrix A and basis B'.

Let's denote the standard basis as \(\(B = \{(1, 0, 0), (0, 1, 0), (0, 0, 1)\}\).\)

To perform the change of basis, we need to find the matrix P such that P[B'] = B.

We can write the vectors in B' as column vectors:

\(\[B' = \left[ \begin{array}{ccc} -1 & 2 & 0 \\ 1 & 1 & 0 \\ 0 & 0 & 1 \end{array} \right]\]\)

To find \(P\), we solve the equation P[B'] = B for P:

\(\[P \cdot B' = B\]\\\\\P = B \cdot (B')^{-1}\]\)

Calculating the inverse of \(\(B'\)\):

\(\[B'^{-1} = \left[ \begin{array}{ccc} -1 & 2 & 0 \\ 1 & 1 & 0 \\ 0 & 0 & 1 \end{array} \right]^{-1} = \left[ \begin{array}{ccc} -1 & 1 & 0 \\ \frac{1}{2} & \frac{1}{2} & 0 \\ 0 & 0 & 1 \end{array} \right]\]\)

Now we can calculate \(\(P\)\):

\(\[P = B \cdot B'^{-1} = \left[ \begin{array}{ccc} 1 & 0 & 0 \\ 0 & 1 & 0 \\ 0 & 0 & 1 \end{array} \right] \cdot \left[ \begin{array}{ccc} -1 & 1 & 0 \\ \frac{1}{2} & \frac{1}{2} & 0 \\ 0 & 0 & 1 \end{array} \right] = \left[ \begin{array}{ccc} -1 & 1 & 0 \\ \frac{1}{2} & \frac{1}{2} & 0 \\ 0 & 0 & 1 \end{array} \right]\]\)

Now, the diagonal matrix A' for T relative to the basis B' can be calculated as:

\(\[A' = P^{-1} \cdot A \cdot P\]\)

Calculating\(\(P^{-1}\):\)

\(\[P^{-1} = \left[ \begin{array}{ccc} -1 & 1 & 0 \\ \frac{1}{2} & \frac{1}{2} & 0 \\ 0 & 0 & 1 \end{array} \right]^{-1} = \left[ \begin{array}{ccc} -1 & 2 & 0 \\ 1 & 1 & 0 \\ 0 & 0 & 1 \end{array} \right]\]\)

Substituting the values into the equation for \(\(A'\)\):

\(\[A' = \left[ \begin{array}{ccc} -1 & 2 & 0 \\ 1 & 1 & 0 \\ 0 & 0 & 1 \end{array} \right]^{-1} \cdot \left[ \begin{array}{ccc} -1 & -2 & 0 \\ -1 & 0 & 0 \\ 0 & 0 & 1 \end{array} \right] \cdot \left[ \begin{array}{ccc} -1 & 2 & 0 \\ 1 & 1 & 0 \\ 0 & 0 & 1 \end{array} \right]\]\)

Performing the matrix multiplication:

\(\[A' = \left[ \begin{array}{ccc} -1 & 2 & 0 \\ 1 & 1 & 0 \\ 0 & 0 & 1 \end{array} \right] \cdot \left[ \begin{array}{ccc} -1 & -2 & 0 \\ -1 & 0 & 0 \\ 0 & 0 & 1 \end{array} \right] \cdot \left[ \begin{array}{ccc} -1 & 2 & 0 \\ 1 & 1 & 0 \\ 0 & 0 & 1 \end{array} \right]\]\)

Calculating the matrix multiplication, we get:

\(\[A' = \left[ \begin{array}{ccc} 3 & -4 & 0 \\ -2 & -1 & 0 \\ 0 & 0 & 1 \end{array} \right]\]\)

Therefore, the diagonal matrix A' for T relative to the basis B' is:

\(\[A' = \left[ \begin{array}{ccc} 3 & -4 & 0 \\ -2 & -1 & 0 \\ 0 & 0 & 1 \end{array} \right]\]\)

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Answer:

1) 2002

2) 92

Step-by-step explanation:

1)

First, you need to find the area of the triangular base. The height of the triangle is 7, and the base is 26, meaning that the area is 7*26/2=91. Multiplying this by the length of the prism, you get 2002 cubic meters.

2)

First, you need to find the area of the trapezoidal base. The two bases of the trapezoid have lengths 12 and 11, while the height is 8, meaning that the area is 8*(12+11)/2=92 cubic centimeters.

Hope this helps!

Answer: -15a+20c

multiply by -5

The distance between the tips of the minute and hour hands of a large clock is changing at a rate of approximately 0.0084 feet per minute at 6:20 pm.

To find the rate at which the distance between the tips of the two hands is changing, we can use the concept of related rates. Let's consider the minute hand and the hour hand as they move on the clock face.

At 6:20 pm, the minute hand is pointing at the 4 on the clock, and the hour hand is pointing between the 6 and 7 on the clock. We can calculate the angle between the two hands by taking the difference in their positions. The minute hand has moved 20 minutes past the 6, which corresponds to 1/3 of the clock's circumference, or 2π/3 radians. The hour hand has moved 1/3 of the way between the 6 and 7, which corresponds to 1/12 of the clock's circumference, or π/6 radians.

The distance between the tips of the hands can be found using the law of cosines. Considering the minute hand as the side a (length 1 foot), the hour hand as the side b (length 1/2 feet), and the angle between them as θ (π/6 - 2π/3), we can use the formula: c^2 = a^2 + b^2 - 2ab*cos(θ).

By substituting the given values, we have c^2 = (1)^2 + (1/2)^2 - 2(1)(1/2)*cos(π/6 - 2π/3).

Simplifying, c^2 = 5/4 - √3/2.

Differentiating both sides with respect to time, we have 2c(dc/dt) = 0 - (-√3/2)(dθ/dt).

Since the minute hand moves at a constant rate of 2π radians per hour, dθ/dt = 2π/60 = π/30 radians per minute.

Substituting the values, we get 2c(dc/dt) = (√3/2)(π/30).

Simplifying, dc/dt = (√3/4π) feet per minute.

Therefore, at 6:20 pm, the distance between the tips of the minute and hour hands is changing at a rate of approximately 0.0084 feet per minute.

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Answer:

5 units

Step-by-step explanation:

Points:

The distance:

Sides of the triangle are 5

Answer:

(5 , 0)

Step-by-step explanation:

Answer:

.80

Step-by-step explanation:

P(1) = .20, so P(2 < x < 4) = 1 - P(1)

= 1 - .20 = .80

The values of μ and σ after converting the pulse rates of women to z-scores are: μ = 0 (since the mean of z-scores is always 0). σ = 1 (since the standard deviation of z-scores is always 1). Correct option is D.

To convert pulse rates of women to z-scores using the formula z = (x - μ) / σ, we can use the given values:

μ (mean) = 77.5 beats per minute

σ (standard deviation) = 11.6 beats per minute

To calculate the z-scores, we subtract the mean from each individual pulse rate and divide it by the standard deviation.

The units of the original pulse rates are "beats per minute." When we convert the pulse rates to z-scores, the resulting z-scores are numbers without units of measurement (choice D). Z-scores represent the number of standard deviations an observation is from the mean, and they do not have the same units as the original data.

Therefore, the values of μ and σ after converting the pulse rates of women to z-scores are:

μ = 0 (since the mean of z-scores is always 0)

σ = 1 (since the standard deviation of z-scores is always 1)

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Pulse rates of women are normally distributed with a mean of 77.5 beats per minute and a standard deviation of 11.6 beats per minute. Answer the following questions.

What are the values of the mean and standard deviation after converting all pulse rates of women to z scores using z=(x−μ)σ​?

μ=σ=

The original pulse rates are measure with units of​ "beats per​ minute". What are the units of the corresponding z​ scores? Choose the correct choice below.

A. The z scores are measured with units of​ "beats per​ minute."

B. The z scores are measured with units of​ "minutes per​ beat."

C. The z scores are measured with units of​ "beats."

D. The z scores are numbers without units of measurement.

Answer:4

Step-by-step explanation:

Answer:

c) The vertical asymptotes are x = (-5 + √(13))/4 and x = (-5 - √(13))/4. To find them, set the denominator equal to zero and solve for x.

d) There are no holes in the function.

e) The zeros are x = 0, x = 2, and x = -3. To find them, set the numerator equal to zero and solve for x.

f) The slant asymptote is y = x + 2 - (3.5x + 1.5)/(2x^2 + 5x + 3). To find it, use long division to divide the numerator by the denominator. To find the slant asymptote of the given rational function, we use long division to divide the numerator by the denominator. The quotient of the division gives the equation of the slant asymptote.

g) The domain is (-∞, (-5 - √(13))/4) U ((-5 + √(13))/4, ∞). To find it, set the denominator not equal to zero and solve for x. To find the domain of the given rational function, we set the denominator not equal to zero and solve for x. The domain is all real numbers except the values of x that make the denominator equal to zero.

I hope this helps you! I'm sorry if it's wrong! If you need more help, ask me! :]

True

A triangle with all the three sides equal equilateral

Hope this helped you- have a good day bro cya)

the energy use for each quarter beginning with winter in year 26 is as follows:

Winter: 121.91

Spring: 149.49

Summer: 170.44

Fall: 129.96

To determine the energy use for each quarter beginning with winter in year 26, we need to multiply the base value D = 80.0 + 0.45Q by the corresponding seasonal factors. Here are the calculations:

Winter (Q = 101): D = (80.0 + 0.45 * 101) * 0.9 = 135.45 * 0.9 = 121.91

Spring (Q = 102): D = (80.0 + 0.45 * 102) * 1.1 = 135.9 * 1.1 = 149.49

Summer (Q = 103): D = (80.0 + 0.45 * 103) * 1.25 = 136.35 * 1.25 = 170.44

Fall (Q = 104): D = (80.0 + 0.45 * 104) * 0.95 = 136.8 * 0.95 = 129.96

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The probability that the mean length of a sample of four krill is more than 49 mm is approximately 1 - 0.0106 = 0.9894 or 98.94%.

The distribution of the mean length of a sample of four krill follows a normal distribution with mean µ = 50.5 mm and standard deviation σ = 1.3 mm.

We can use the central limit theorem to approximate the probability that the mean length of a sample of four krill is more than 49 mm. This theorem states that, for a large sample size, the distribution of sample means will be approximately normal regardless of the distribution of the population. The sample size of 4 is relatively small, but we can still use the normal approximation since the population standard deviation is known. The standard error of the mean can be calculated as follows: SE = σ/√n = 1.3/√4

= 0.65 mm

We can use a z-table to find the probability that a standard normal variable is less than -2.31:P(z < -2.31) ≈ 0.0106.

Then, the z-score can be calculated as follows :z = (49 - 50.5)/0.65

= -2.31

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When balloons filled to capacity outdoors at a temperature of 25∘F are brought indoors where the temperature is 70∘F, they will expand and increase in size as they warm up. The increase in temperature causes the air molecules inside the balloons to gain energy and move more rapidly.

When the balloons are brought indoors where the temperature is 70∘F, the air inside the balloons will begin to warm up. As the temperature increases, the air molecules inside the balloons gain energy and start to move more rapidly. This increased movement of the air molecules causes them to collide with the walls of the balloons more frequently and with greater force.

The collision of the air molecules with the walls of the balloons creates pressure inside the balloons. As the pressure increases, the balloons will start to expand and stretch. This expansion occurs because the rubber material of the balloons is flexible and can accommodate the increased volume of air.

As the balloons continue to warm up, the expansion will become more noticeable. The balloons will increase in size and become tauter. This happens because the air molecules inside the balloons are now occupying a larger space due to the increase in temperature. The rubber material of the balloons stretches to accommodate the greater volume of air.

It's important to note that if the temperature difference is significant, the expanding balloons may eventually reach their limits and could potentially burst if they are unable to withstand the internal pressure. Therefore, it's crucial to consider the temperature conditions when filling balloons to avoid overinflation.

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Answer:

x > 11

Step-by-step explanation:

15 < 4 + x

Subtracting 4 from both sides (to get rid of the 4 on the right side) gives us:

15 - 4 < 4 + x - 4

11 < x

Answer:

x>11

Step-by-step explanation:

15<4+x

Simplify both sides of the inequality.

15<x+4

Flip the equation.

x+4>15

Subtract 4 from both sides.

x+4−4>15−4

x>11

Answer:

34.54 in

Step-by-step explanation:

The approximate circumference of a plate with a diameter of 11 inches can be calculated using the formula C = πd, where C is the circumference and d is the diameter .

So, substituting the given value of diameter d = 11 inches and taking π to be approximately 3.14, we get:

C = πd = 3.14 x 11 = 34.54 inches (approx.)

Therefore, the approximate circumference of the plate is 34.54 inches.

Since it is required to round the answer to the nearest hundredth, we get the rounded answer as 34.54 rounded off to two decimal places, which is 34.54 (no rounding needed).

Answer: For circumference, you simply multiply the diameter by pi, so the answer you are looking for is 34.54

Step-by-step explanation:

Considering the forecasted demand of 30,000 units, the best site would be Comilla as it yields the highest profit among all locations for that particular volume.

To determine the best site for the new manufacturing plant based on volume and pricing factors, we need to calculate the total costs and revenues for each location. The location with the highest profit will be considered the best site. Let's calculate the profits for each location based on the given information:

Location: Rajshahi

Fixed cost per year: $30,000

Variable cost per product: $45

Price per product: $150

Forecast demand per year: 20,000

Total Cost = Fixed Cost + (Variable Cost per Product * Forecast Demand per Year)

Total Revenue = Price per Product * Forecast Demand per Year

Profit = Total Revenue - Total Cost

Total Cost = $30,000 + ($45 * 20,000) = $1,050,000

Total Revenue = $150 * 20,000 = $3,000,000

Profit = $3,000,000 - $1,050,000 = $1,950,000

Performing similar calculations for the other locations, we get:

Location: Dhaka

Total Cost = $100,000 + ($75 * 50,000) = $4,850,000

Total Revenue = $120 * 50,000 = $6,000,000

Profit = $6,000,000 - $4,850,000 = $1,150,000

Location: Comilla

Total Cost = $60,000 + ($35 * 30,000) = $1,110,000

Total Revenue = $100 * 30,000 = $3,000,000

Profit = $3,000,000 - $1,110,000 = $1,890,000

Location: Chittagong

Total Cost = $110,000 + ($60 * 40,000) = $2,510,000

Total Revenue = $90 * 40,000 = $3,600,000

Profit = $3,600,000 - $2,510,000 = $1,090,000

Based on the calculated profits, we can determine the range in volume over which each location would be best:

Rajshahi: The best site for a volume range up to 20,000 units.

Dhaka: The best site for a volume range between 20,001 and 50,000 units.

Comilla: The best site for a volume range between 50,001 and 30,000 units.

Chittagong: The best site for a volume range above 30,000 units.

Therefore, considering the forecasted demand of 30,000 units, the best site would be Comilla as it yields the highest profit among all locations for that particular volume.

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Answer:

B

Step-by-step explanation:

money would she have at the end of vacation = 377,789,318,629,571,617,095.67 dollars.

When interest is applied to a principal amount together with the interest that has already been paid, this process is known as compounding. This means that compounding, sometimes known as the "wonder of compounding," can be thought of as interest on the compound, which has the effect of increasing returns from interest over time.

Current good compounding practices refer to the minimal requirements for the procedures, facilities, and controls used to compound medicine to ensure that it has the identity, and strength, and satisfies the quality and purity requirements it is claimed to have.

She puts in one penny the first day, 2 pennies the second, 4 pennies the third...and so on.

The total sum is thus,

(1, 3, 7, 15, 31, 63, 127)

Which translate to

(2^1-1, 2^2-1, 2^3-1, 2^4-1, 2^5-1, 2^6-1, 2^7-1,..)

So at the end of the 75th day, the total amount is 2^75-1

or

37778931862957161709567 pennies

or

377,789,318,629,571,617,095.67 dollars.

money would she have at the end of vacation =  377,789,318,629,571,617,095.67 dollars.

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I understand that the question you are looking for is:

Your friend is saving pennies. She puts one penny into her piggy bank the first day, two pennies the second day, four the third day, and so on, doubling the number of pennies added. How many much money would she have at the end of vacation, if she could keep saving at this rate? Vacation lasts 75 days.

The total length, in inches, of the four cut boards is 130 inches.

Addition is one of the basic mathematical operations where two or more numbers is added to get a bigger number.

The process of doing addition is also called as finding the sum.

Given that, the length of each of the cut pieces of the board are 7½ inches, 10½ inches, 9 inches, and 5½ inches.

We have to find the total length of the board.

Total length of the board is found by adding each length.

Total length = 7½ + 10½ + 9 + 5½

Mixed fraction can be converted to improper fraction by cross multiplication.

7½ = (7 * 2 + 1) / 2, 10½ = (10 * 2 + 1) / 2 and 5½ = (5 * 2 + 1) / 2

Total length = 15/2 + 21/2 + 9 + 11/2

                    = (15/2 + 21/2 + 11/2) + 9

                     = 47/2 + 9

                     = 65/2

Again improper fraction can be converted to mixed fraction.

Total length of a board = 32 1/2 inches

But there are 4 boards.

Total length of the 4 boards = 4 × 65/2 = 130 inches

Hence the total length is 130 inches.

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The lexicographic preferences on apricots and bananas are transitive. They cannot be represented by a continuous utility function u(a, b).

1. To prove that the lexicographic preferences on apricots and bananas are transitive, let's assume the following:
(x1, y1)≻(x2, y2) (x2, y2)≻(x3, y3)

That implies the following:
1. x1 > x2 or (x1 = x2 and y1 > y2)
2. x2 > x3 or (x2 = x3 and y2 > y3)

Therefore, we have two cases:

Case 1: x1 > x2 > x3

If this is true, then we have

(x1, y1) > (x3, y3),

and the lexicographic preferences are transitive.

Case 2: x1 = x2 > x3

If this is true, then

y1 > y2, and x2 = x3,

which means

y2 > y3.

Therefore, (x1, y1) > (x3, y3), and the lexicographic preferences are transitive.

2. Now we need to prove that the lexicographic preferences on apricots and bananas cannot be represented by a continuous utility function u(a,b).

Suppose that there exists a continuous utility function u(a,b) that represents the lexicographic preferences on apricots and bananas.

Therefore, (a1, b1) ≻ (a2, b2) if and only if u(a1, b1) > u(a2, b2).

Let's consider two cases:

Case 1: a1 > a2.

Since

u(a1, b1) > u(a2, b2),

we have:

u(a1, b1) - u(a2, b2) > 0,

which means that

Δu = u(a1, b1) - u(a2, b2) > 0

Case 2: a1 = a2 and b1 > b2.

Since

u(a1, b1) > u(a2, b2),

we have:

u(a1, b1) - u(a2, b2) > 0,

which means that

Δu = u(a1, b1) - u(a2, b2) > 0

Therefore, we have Δu > 0 in both cases, which contradicts the fact that the lexicographic preferences on apricots and bananas are non-continuous.

Hence, they cannot be represented by a continuous utility function u(a,b).

In conclusion, the lexicographic preferences on apricots and bananas are transitive but cannot be represented by a continuous utility function.

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Answer:

12

Step-by-step explanation:

We are finding the discriminant

b^2 -4ac

2x^2 - 2x - 1 = 0​

a =2  b = -2  c = -1

(-2)^2 - 4(2)(-1)

4 +8

12

Answer:

\(b^2 - 4ac= 12\)

Step-by-step explanation:

Standard quadratic equation :

                   \(ax^2 + bx + c = 0\)

Given equation :

                  \(2x^2 - 2x - 1 = 0\)

From the given equation , a = 2, b = -2 , c = -1

Therefore,

              \(b^2 - 4ac= ( -2)^2 - ( 4 \times 2 \times (-1))\)

                          \(=4 + 8 = 12\)

Answer:

The number 3.99 as a fraction in its simplest form is 3 and 99/100. In its simplest form of a mixed fraction is 399/100.

Step-by-step explanation:

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Answer:

- 3 99/100

= - 399/100

Step-by-step explanation: