What make race condition bad? name and briefly desribe two distince factors needed for a race

Answer:

Is safe to use the bag.

Explanation:

To solve this problem we must use Newton's second law which tells us that the resulting force is equal to the product of mass by acceleration.

F = m*a

where:

F = force [N] (units of Newtons)

m = mass = 15 [kg]

a = acceleration = 7 [m/s²]

Now replacing these values in the previous equation:

F = 15*7

F = 105 [N]

F < 230 [N]

The force of 105 [N] is lesser than the maximum resistance force, therefore is safe to use the bag.

The squared quantity is 4(2L/π)².

To calculate the quantity you're asking for, we'll first determine the distance of each star from the center of rotation. Let's assume the stars are labeled as A, B, C, and D.

The center of the square is equidistant from all four stars. Let's denote this distance as R.

Since the stars are arranged at the corners of a square, the diagonal of the square is twice the distance from a corner to the center. Therefore, the diagonal of the square has a length of 2R.

Now, let's consider the diagonal of the square as the diameter of the circle in which the stars move. The circumference of a circle is given by the formula:

C = 2πr

where C is the circumference and r is the radius of the circle.

In this case, the circumference of the circle is equal to the perimeter of the square, which is 4L. Therefore:

2πR = 4L

R = 2L/π

Now, to calculate the squared quantity you're interested in, we can find the sum of the squares of the distances of the stars from the center:

Sum = (Distance of star A)² + (Distance of star B)² + (Distance of star C)² + (Distance of star D)²

Since all four stars are equidistant from the center, we can calculate the sum as:

Sum = 4R²

Substituting the value of R we found earlier:

Sum = 4(2L/π)²

Therefore, the squared quantity you're looking for is 4(2L/π)².

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Answer:

20N

Explanation:

w over h is 600 divided by 300

Answer:

20 000 pascals

Explanation:

PRESSURE in the metric system is measured in Pascals

   the units are   N / m^2

300 cm^2 = .03 m^2

600N / .03 m^2 =20 000 pascals

A force of 40 pounds must be applied to roll the 120-pound barrel up the inclined plane to a height of 3 feet, disregarding friction.

To calculate the force required to roll a 120-pound barrel up an inclined plane disregarding friction, we can use the concept of mechanical advantage. The force required can be determined using the formula:

Force = Weight * (Vertical distance / Inclined distance)

In this case, the weight of the barrel is 120 pounds, the vertical distance is 3 feet, and the inclined distance is 9 feet.

Force = 120 pounds * (3 feet / 9 feet)

Simplifying the equation, we have:

Force = 120 pounds * (1/3)

Force = 40 pounds

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You decide to hike up Mt. Everest so you can experience what it is like to be above roughly 75% of the air in the atmosphere,  the pressure at the summit is mathematically given as

P= 250mb

Generally, the equation for pressure at the summit is mathematically given as

P= (100-75) * pressure at the surface

Therefore

P= (25/100) x 1000

P= (0.25 x 1000)mb

P= 250mb

In conclusion, the pressure at the summit

P= 250mb

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The average acceleration of the race - car driver would be 3.78 m/s².

Average acceleration is the rate of change of velocity per unit time. Mathematically -

a = dv/dt              [instantaneous acceleration]

dv = adt

∫dv = ∫adt

∫dv = a ∫dt

v₂ - v₁ = a(t₂ - t₁)Δv = aΔt

a = Δv/Δt

Given is a race-car driver who achieved a velocity of 53 m/s in 14 seconds after taking off from rest at the starting line.

We can write -

Initial velocity of the race-car driver [u] = 0 m/s

Final velocity of the race-car driver  [v] = 53 m/s

Time taken by the race-car driver [Δt] = 14 seconds

Using the formula for acceleration, we get -

a = Δv/Δt = (v - u)/Δt

Substituting the values -

a = (53 - 0)/14

a = 3.78 m/s²

The acceleration will be 3.78 m/s²

Therefore, the average acceleration of the race - car driver would be 3.78 m/s².

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10 pounds of weight is equivalent to 44.48 newtons of force.

The pound (lb) is a unit of mass commonly used in the United States and a few other countries. However, in the International System of Units (SI), the unit of force is the newton (N). Therefore, to convert pounds to newtons, we need to use the following equivalency:

1 lb = 4.448 N

This means that 1 pound is equal to 4.448 newtons of force. To convert a weight in pounds to a force in newtons, we can simply multiply the weight by 4.448. For example, if we have a weight of 10 pounds, we can convert it to newtons as follows:

10 lb x 4.448 N/lb = 44.48 N

Therefore, 10 pounds of weight is equivalent to 44.48 newtons of force.

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The wavelength of the radio waves emitted by the radio station is approximately 3.38 meters. This means that the radio waves have a relatively long wavelength and can travel long distances, which is why radio waves are commonly used for broadcasting signals.

To determine the wavelength of the radio waves emitted by the radio station, we can use the formula:

wavelength = speed of light / frequency

The speed of light is approximately 299,792,458 meters per second. However, the frequency of the radio station is given in megahertz, which is a unit of frequency equal to one million hertz. To convert megahertz to hertz, we need to multiply by one million.

Therefore, the frequency of the radio station in hertz is:

88.7 MHz x 1,000,000 = 88,700,000 Hz

Now, we can substitute the values into the formula:

wavelength = 299,792,458 m/s / 88,700,000 Hz = 3.38 meters

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Explanation:

1 For a sound wave, the pitch is determined by which wave characteristic?

A - Frequency

2 Which of the following waves cannot be transmitted through a vacuum?

C - Sound waves

3 Which of the following could be the value of a wavelength that is found in the visible region of the electromagnetic spectrum?

B - 5 × 10^-7 m

4 Sophie is trying to measure the speed of sound. She stands 24.0 m away from a wall and claps repeatedly, changing the frequency until the echo synchronized with her claps. If she calculates the speed of sound as 325 m • s-1 how long did she wait between claps?

The time between her claps and the echo is twice the time it takes for the sound to travel from her to the wall. Therefore, the time between her claps is:

time = distance/speed = 2 x 24.0 m/325 m/s = 0.148 seconds (to three significant figures).

So the answer is 0.148, without units and correct to three significant figures

Answer:

D)evaluating a solution

Explanation:

In this scenario, the next logical step would be evaluating a solution. This is because Jasper and Samantha have already identified the problem/need which is that the robot needs to be able to move a 10-gram weight at least 2 meters and turn in a circle. They also designed and implemented a solution because they have already built the robot. Therefore the only step missing is to evaluate and make sure that the robot they built is able to complete the requirements.

Answer:

To calculate the linear expansion of a brass rod due to a temperature change of 100K, we can use the formula:

ΔL = α * L * ΔT

where:

α = linear expansivity of brass (1.8 x 10^-5K^-1)

L = original length of the rod (2m)

ΔT = change in temperature (100K)

Plugging in the values:

ΔL = 1.8 x 10^-5K^-1 * 2m * 100K = 0.036m

So the linear expansion of the brass rod due to a temperature change of 100K is 0.036 meters.

Answer:

32.32857

Explanation:

Searched on the web

Answer:

The force of gravitational will decreases by a factor of 4

Explanation:

The given parameters are;

The symbol that represents the given mass = m

The mass of the circular ring = M

The initial distance of the mass "m" located at the point P from the center O = h

The final distance of the mass "m" when moved further away from point O = 2·h

Given that h = r, we have;

\(The \ initial \ gravitational \ force, F_1 =G \cdot \dfrac{M \cdot m}{r^{2}}\)

Therefore, when OP = 2·h, we have;

OP = 2·r and the new gravitational force, F₂, is given as follows;

\(F_2 =G \cdot \dfrac{M \cdot m}{(2\cdot r)^{2}} = G \cdot \dfrac{M \cdot m}{4\cdot r^{2}} = \dfrac{1}{4} \times G \cdot \dfrac{M \cdot m}{r^2} = \dfrac{1}{4} \times F_1\)

\(\therefore F_2 = \dfrac{1}{4} \times F_1\)

Therefore, when the mass, m, is removed such that OP = 2h, the value of the gravitational force decreases by a factor of 4.

When an engineering team reaches the stage of iterating to improve the solution in the engineering design process, there are various activities that the team might be doing. One of the most crucial activities at this stage of the design process is testing. Here are a few things that an engineering team might do to test and improve the solution:

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The displacement of the object is 831.6 meters.

displacement = (final velocity - initial velocity) x time

displacement = (60.7 m/s - 5.26 m/s) x 15.0 s

displacement = 55.44 m/s x 15.0 s

displacement = 831.6 m

Displacement refers to the change in position of an object, typically measured as the distance and direction between an object's starting point and its ending point. Displacement is a vector quantity, which means that it has both magnitude (size) and direction.

Displacement can be calculated using mathematical formulas that take into account an object's velocity, time, and acceleration. It is an important concept in physics because it allows us to measure and understand an object's motion, including how far it has moved and in what direction. Displacement is also related to other important physical quantities such as velocity, acceleration, and momentum.

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The highest point of the cat's trajectory is 0.43 m.

In projectile motion, the vertical motion can be analyzed independently of the horizontal motion. The vertical motion is influenced by the acceleration due to gravity. As the cat jumps, it experiences a vertical acceleration of -9.8 m/s² (negative due to gravity pulling the cat downwards).
Using the kinematic equation for vertical motion:
vf² = vi² + 2ad

where:
vf = final velocity (0 m/s at the highest point)
vi = initial velocity (3.34 m/s)
a = acceleration (-9.8 m/s²)
d = displacement (highest point of the trajectory, which we are trying to find)

Substituting the known values into the equation:
0 = (3.34)² + 2(-9.8)d

Simplifying the equation:
0 = 11.1556 - 19.6d

Rearranging the equation:
19.6d = 11.1556

Solving for d:
d = 11.1556 / 19.6
d = 0.5689 m

Since the displacement is measured from the ground level, the highest point of the trajectory would be at a height of 0.5689 m.
However, in the given options, 0.5689 m is not listed. The closest option is 0.43 m.

Thus, the highest point of the cat's trajectory is 0.43 m.

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The magnetic force allows to find the result for the question about the characteristics of the material is:

Ampere's law explains the formation of the magnetic field due to the movement of the charges in the solenoid wire.

For the switch to move it must be a metal that is attracted by the magnetic field, to increase the force to the maximum possible it must be a metal that has many electrons with unpaired spin and these can feel the force of the magnetic field.

One of the most used metals is iron, which has 5 unpaired electrons and is the one that most feels the forces of the magnetic field.

In conclusion using the magnetic force we can find the result for the question is:

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Answer:

Increase height

Increase mass

Feet per minute (ft/min) and meters per second (m/s) are units of speed or velocity, with the former being more commonly used in some industries such as HVAC (heating, ventilation, and air conditioning).

To convert from ft/min to m/s, you can use the following conversion factor:

1 ft/min = 0.00508 m/s

Velocity is a measure of the rate at which an object changes its position with respect to time. It is a vector quantity, which means it has both magnitude and direction. Velocity is different from speed because speed only takes into account the magnitude of the change in position, while velocity also considers the direction of the change.

In physics, velocity is denoted by the symbol ‘v’ and is measured in meters per second (m/s) or other units such as miles per hour (mph), feet per second (ft/s), or kilometers per hour (km/h). It is calculated by dividing the displacement (change in position) of an object by the time taken for that displacement to occur.

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A 25.5 kg video cart is rolled down a hallway. It is accelerated at 0.12 m/s2. If a force of 30 N is applied to move the cart . The wheels have 26.4 N  force of friction against the floor

Force of friction is that force  that resists the sliding or rolling of one solid object over another

F(applied) - friction = F net

30 - fr = mass * acceleration

30 - fr  = 25.5  *  0.12  

fr = 30 - 3.06

  = 26.4 N

The wheels have 26.4 N  force of friction against the floor

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Answer:

c 0.10

Explanation:

V=IR

12.0V=I x 120.12ohms

I=0.099

I= 0.10

Answer:

\(\huge\boxed{\sf F= 350 \ N}\)

Explanation:

Considering pivot as the central point,

Key:

\(F_1r_1=F_2r_2\)

Here,

Substitute the givens in the above formula.

\(F(1.2)=600(0.7)\\\\F(1.2)=420\\\\Divide \ 1.2 \ to \ both \ sides\\\\F=420/1.2\\\\F= 350 \ N\\\\\rule[225]{225}{2}\)

Explanation:

GIVEN DATA

since P(momentum)=Mass×Velocity

F = P2 -P1

t

F= Mv2-Mv1

t

F=M( v2-v1) ,(a=v2-v1)

t t

ANSWER EXPLANATION IN WORDS

That question is related to Newton's second law of motion, the question ask you to find the force it gives you a mass and a acceleration As we know that the SI unit of acceleration is newton per kilogram or metre per second square It is correct to write metre per second square instead of Newton Per kilogram because because all of them are the SI unit of acceleration so that is the answer we get 686 Newton by Force .

Answer:

they a giant ball of gases, so the answer is they have very large gas masses

Explanation:

Answer:

get G OA S S E d

Explanation:

d gasses are large

Hello!

Δv = 0.1 m/s

Use the equation F = m · a to solve for the acceleration:

5 = 15 · a

a = 1/3

The equation to solve for acceleration can be rewritten to solve for the change in velocity:

Δv / t = a

Δv = at

We are given the acceleration and time, therefore:

Δv = (1/3)(0.3)

Δv = 0.1 m/s

By resolving forces into their components and adding them together, you can determine the resultant force in the x and y directions without knowing the actual variables involved.

To find the summation of Fx and summation of Fy without knowing the specific variables, you need to have information about the forces acting on an object in the x and y directions. If you have the magnitudes and directions of individual forces, you can use vector addition to determine the resultant force in each direction.

Here's a general approach to finding the summation of Fx and Fy:

Identify the forces: Start by identifying all the forces acting on the object and their directions. Each force can be represented as a vector with a magnitude and direction.

Resolve forces: If the forces are not already given in the x and y directions, you need to resolve them into their x and y components. Use trigonometry (sine and cosine) to determine the components of each force along the x-axis (Fx) and the y-axis (Fy).

Sum the components: Add up all the individual components of forces acting in the x-direction to find the summation of Fx. Similarly, add up all the individual components of forces acting in the y-direction to find the summation of Fy.

Summation of Fx = F1x + F2x + F3x + ...

Summation of Fy = F1y + F2y + F3y + ...

Combine components: If there are forces acting at an angle to the x and y axes, you can use the Pythagorean theorem and trigonometry to find the resultant force in each direction.

Summation of Fx = √(F1x^2 + F2x^2 + F3x^2 + ...) (taking into account both magnitudes and directions)

Summation of Fy = √(F1y^2 + F2y^2 + F3y^2 + ...) (taking into account both magnitudes and directions)

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sectors are the amount of resources

Concave mirrors form both real and virtual images.

A concave mirror has an inward-curving reflective surface that faces away from the light source. Light is reflected inward by concave mirrors to a single focus point. Unlike convex mirrors, a concave mirror's created image exhibits a variety of picture types based on the object's distance from the mirror.

A virtual, magnified image of the object is produced when the concave mirror is placed very close to it. As the distance between the object and the mirror increases, the size of the image decreases and real images are produced.

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