What part of the Milky Way allows for determination of its rotational direction? A. Celestial body B. Galactic body C. Galactic disk D. Two long tails

There are lots more but these are the best

Explanation:

First, we need to calculate the gravitational field strength g on Planet Y. So, we will use the following e

Answer:

Ok, first is important that you understand how the heat radiation works.

All the objects that have some heat energy in them, radiate some of that energy in the form of electromagnetic waves.

Particularly, the Sun radiates a lot of energy (at the point that if you step under the sunlight, you can feel on your skin the heat that comes from the sun, this is due to radiation).

Now, suppose that you have a thin coat of water over you, then the material that gets impacted by that radiation will be the water and not you, and then the energy is dissipated (some of the energy goes to your body and some go to the air)

This is one way in which spraying water over themselves helps the elephants to keep them cool.

Another way in which heat can be transferred is by conduction.

When you have a hot object and a cool object, and you put them together (so the objects touch each other), the heat will flow from the hotter object to the cooler object until both objects have the same temperature.

Then if the elephant body temperature is larger than the temperature of the water that the elephant sprays over his body, when the water touches the body some of the heat in the elephant body will be transferred to the coat of water, and in this way, the temperature of the elephant's body decreases.

These are the two ways we wanted to find.

The center of mass of the system is located at 107.5 cm from the reference point.

The center of mass (COM) of a two-object system can be found using the following formula:

COM = (m1x1 + m2x2) / (m1 + m2)

where

m1 and m2 are the masses of the two objects,

x1 and x2 are their respective positions.

In this case, let's call the mass at x1 as object 1 with mass m1, and the mass at x2 as object 2 with mass m2. We are given that m2 = m1/6.

Using the formula, the position of the center of mass is:

COM = (m1x1 + m2x2) / (m1 + m2)

COM = (m1 * 70 cm + (m1/6) * 223 cm) / (m1 + (m1/6))

COM = (70 + 37.1667) / (1 + 1/6)

COM = 107.5 cm

Therefore, the center of mass of the system is located at 107.5 cm from the reference point.

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The Law of Inertia is a part of Newton's First Law. According to this, an item at rest or in motion will remain such until it is affected by an unbalanced force (s). Law of Inertia governs roller coasters.

Product of force mass equals acceleration, according to Newton's Second Law (f x m = a). As a result, the roller coaster alters its velocity, accelerates, or travels up the hill whenever the chain pulley system is pulling it. The acceleration increases as the chain pulley pulls more forcefully.

A rollercoaster ride is a device that propels a train of vehicles over a twisting track using gravity and inertia. When the coaster rolls up, down, and around its track, the body experiences distinct sensations as a result of gravity, inertia, g-forces, and centripetal acceleration.

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Answer:

del mundo

Explanation:

The charge on the sphere is found to be 1.5 x 10⁻¹⁵ C.

The proton is orbiting the surface of the charged sphere of radius 4.43 cm and the speed of the proton is 3.22 x 10⁵m/s. The charge on proton is 1.6 x 10⁻¹⁹ C and the mass of the proton is 1.67 x 10⁻²⁷ kg.

Now,

For revolving,

Electrostatic forces = Centripetal force

KQq/r² = Mv²/r

Here,

R is the radius of the orbit,

Q and q are the charges of the sphere and the proton,

M is the mass of the proton.

Putting values,

9 x 10⁹ x Q x 1.6 x 10⁻¹⁹/0.0443 = 1.67 x 10⁻²⁷ x 3.22 x 10⁵

Q = 1.5 x 10⁻¹⁵ C

So, the charge on the sphere is 1.5 x 10⁻¹⁵ C.

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Among the given expressions, the correct one to find the angle in the drawing is option C) ? = tan(⁻¹)(⁵).

The expression tan^(-1)(5) represents the inverse tangent function, also known as arctan or atan. It is commonly used to find the angle when the ratio of the opposite side to the adjacent side is known. In this case, the expression suggests that the angle can be determined by taking the inverse tangent of 5. By plugging in the appropriate values and evaluating the expression, the angle can be obtained. It's important to note that without further context or information about the specific problem or drawing, it's challenging to provide a definitive answer. However, based on the given options, option C) ? = tan(⁻¹)(⁵) is the expression that can be used to find the angle.

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Close to your chest, with both hands. Make sure to keep your elbows slightly bent and your back straight.

When carrying an object, it is important to hold it close to the body's center of gravity in order to maintain balance and reduce strain on the body. The body's center of gravity is the point at which the body's mass is evenly distributed, usually around the hips. By holding the object close to this point, the body's weight is more evenly distributed and the person is able to maintain balance and reduce the strain on the body from carrying the object. Additionally, holding the object close to the center of gravity helps to reduce the risk of injury from dropping the object.

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Close to your chest, with both hands. Make sure to keep your elbows slightly bent and your back straight.

When carrying an object, it is important to hold it close to the body's center of gravity in order to maintain balance and reduce strain on the body. The body's center of gravity is the point at which the body's mass is evenly distributed, usually around the hips. By holding the object close to this point, the body's weight is more evenly distributed and the person is able to maintain balance and reduce the strain on the body from carrying the object. Additionally, holding the object close to the center of gravity helps to reduce the risk of injury from dropping the object.

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Answer:

B. 24.2 m/s

Explanation:

Given;

mass of the roller coaster, m = 450 kg

height of the roller coaster, h = 30 m

The maximum potential energy of the roller coaster  due to its height is given by;

\(P.E_{max} = mgh\\\\PE_{max} = 450 *9.8*30\\\\PE_{max} = 132,300 \ J\)

\(P.E_{max} = K.E_{max} \ (law \ of \ conservation\ of \ energy)\)

\(K.E_{max} = \frac{1}{2}mv_{max}^2\\\\ v_{max}^2 = \frac{2K.E_{max}}{m}\\\\ v_{max}^2 = \frac{2*132300}{450}\\\\ v_{max}^2 =588\\\\v_{max} = \sqrt{588}\\\\ v_{max} = 24.2 \ m/s\)

Therefore, the maximum speed of the roller coaster is 24.2 m/s.

Answer:

1. 24.2 m/s

2. 20.4 m

3. 22.5 m/s

4. 109,375 J

5. It is easy to calculate new scenarios.

Explanation:

5/5 on the Maximum Energy Quick Check

Answer:

electron is the correct answer

Explanation:

pls mark me as brainlist

The velocity of the cart after 10 baseballs have been thrown at it is 5.075 m/s.

To solve this problem, apply the principle of conservation of momentum.

The initial momentum of the cart is zero since it is at rest, and the final momentum is determined by the momentum of the baseballs caught by the sail.

Since the cart catches the baseballs, the momentum of each baseball is transferred to the cart.

Given:

Mass of the cart, m_cart = 10 kg

Mass of each baseball, m_baseball = 145 grams = 0.145 kg

Velocity of each baseball, v_baseball = 35 m/s

Number of baseballs caught, n = 10

The total momentum of the system after the baseballs are caught is the sum of the momenta of the individual baseballs:

Total momentum = (mass of first baseball × velocity of first baseball) + (mass of second baseball × velocity of second baseball) + ...

Total momentum = (m_baseball × v_baseball) + (m_baseball × v_baseball) + ... (for n baseballs)

Substituting the given values:

Total momentum = (0.145 kg × 35 m/s) + (0.145 kg × 35 m/s) + ... (for 10 baseballs)

Total momentum = 10 × (0.145 kg × 35 m/s)

Now, calculate the velocity of the cart using the total momentum and the mass of the cart:

Total momentum = m_cart × v_cart

v_cart = Total momentum / m_cart

v_cart = (10 × 0.145 kg × 35 m/s) / 10 kg

v_cart = 5.075 m/s

Therefore, the velocity of the cart after 10 baseballs have been thrown at it is 5.075 m/s.

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Answer:

1. b

2. e

3. a

4. c

5. d

hope dis helps ^-^

Answer:

papi sus

Explanation:

Explanation:

the rate at which someone or something moves or operates or is able to move or operate.

Answer:

a) \( \Delta U = 7.5 kJ \)

b) \(T_{f} = 900 K \)

Explanation:

a) To find the change in its internal energy (U) we need to use the following equation:

\( \Delta U = W + Q \)

Where:

W: is the work done on the system

Q: is the energy transferred into the system by heat = 12.5 kJ

Since we have an isobaric expansion, the work is:

\( W = - P\Delta V = - P(V_{f} - V_{i}) \)

Where:

\(V_{f}\): is the final volume = 3.00 m³

\(V_{i}\): is the initial volume = 1.00 m³

P: is the pressure = 2.50 kPa

\( W = -P(V_{f} - V_{i}) = -2.5 \cdot 10^{3} Pa(3.00 m^{3} - 1.00 m^{3}) = -5.00 \cdot 10^{3} J \)

Now, we can find the change in its internal energy:

\( \Delta U = W + Q = -5.00 \cdot 10^{3} J + 12.5 \cdot 10^{3} J = 7.5 \cdot 10^{3} J \)

b) The final temperature can be found as follows:

\( \frac{V_{i}}{V_{f}} = \frac{T_{i}}{T_{f}} \)

\( T_{f} = \frac{T_{i}*V_{f}}{V_{i}} = \frac{300 K*3.00 m^{3}}{1.00 m^{3}} = 900 K \)

Hence, the final temperature is 900 K.

I hope it helps you!

Answer:

c

Explanation:

Initially the capacitor just acts as a short circuit...or piece of wire ...just like it is not there....   so initially current =  V/R = 9/10 = .9 amps

as the capacitor charges to full capacity the current gradually decreases to

0 amps

Answer:

Copper isn't ferromagnetic,

Aluminum isn't ferromagnetic,

String has a ferromagnetic property

So in conclusion:

The answer is strings :)

Answer:

d. distance travelled

Explanation:

answer

A hydrogen atom is in its ground state (nᵢ = 1) when a photon impinges upon it. The atom absorbs the photon, which has precisely the energy required to raise the atom to the nf = 3 state. (a) The photon's energy that was absorbed is approximately 1.51 eV (negative sign indicates absorption).(b)option B and C are correct.

To determine the photon's energy and the energies of photons that might be emitted when the hydrogen atom returns to the ground state, we can use the energy level formula for hydrogen atoms:

E = -13.6 eV / n^2

where E is the energy of the electron in the atom, and n is the principal quantum number.

(a) To find the energy of the photon that was absorbed by the hydrogen atom to raise it from the ground state (nᵢ = 1) to the nf = 3 state, we need to calculate the energy difference between the two states:

ΔE = Ef - Ei = (-13.6 eV / 3^2) - (-13.6 eV / 1^2)

Calculating the value of ΔE:

ΔE = -13.6 eV / 9 + 13.6 eV

= -1.51 eV

Therefore, the photon's energy that was absorbed is approximately 1.51 eV (negative sign indicates absorption).

(b) When the hydrogen atom returns to the ground state, it can emit photons with energies corresponding to the energy differences between the excited states and the ground state. We need to calculate these energy differences and check which values are present among the given options.

ΔE1 = (-13.6 eV / 1^2) - (-13.6 eV / 3^2) = 10.20 eV

ΔE2 = (-13.6 eV / 1^2) - (-13.6 eV / 4^2) = 10.20 eV

ΔE3 = (-13.6 eV / 1^2) - (-13.6 eV / 5^2) = 12.10 eV

ΔE4 = (-13.6 eV / 1^2) - (-13.6 eV / 6^2) = 12.10 eV

ΔE5 = (-13.6 eV / 1^2) - (-13.6 eV / 7^2) = 13.55 eV

ΔE6 = (-13.6 eV / 1^2) - (-13.6 eV / 8^2) = 13.55 eV

ΔE7 = (-13.6 eV / 1^2) - (-13.6 eV / 9^2) = 13.55 eV

Comparing the calculated energy differences with the given options:

(A) 1.89 eV: This energy difference does not match any of the calculated values.

(B) 12.1 eV: This energy difference matches ΔE3 and ΔE4.

(C) 10.2 eV: This energy difference matches ΔE1 and ΔE2.

(D) 13.6 eV: This energy difference does not match any of the calculated values.

Therefore option B and C are correct.

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A rocket ship has several engines and thrusters. While the solid rocket booster (srb) and main engines only work together during the first 2 minutes of flight, the main engines operate for a total of 8. 5 minutes after the launch. Once the srbs are released, the main engines alone accelerate the rocket from about 1341 m/s to 7600 m/s. During the first two minutes of flight, the SRB and main engine accelerate at a rate of 52.16 m/s2.

Acceleration is the rate at which a moving object's speed and direction change over time. When something moves faster or slower, it is considered to be accelerating. The engine's initial velocity (u), final velocity (v), and time of motion (t), which is equivalent to two minutes, are the parameters given (2 x 60 s).

The calculations for the main engine's and SRB's acceleration are listed below.

a= Δv / Δt

a=7600-1341 /2*60s

a=52.16 m/s²

As a result, during the first two minutes of flight, the main engine and SRB accelerate at a rate of 52.16 m/s2.

Your question is incomplete but most probably your full question is

A rocket ship has several engines and thrusters. While the Solid Rocket Booster (SRB) and main engines only work together during the first 2 minutes of flight, the main engines operate for a total of 8.5 minutes after the launch. Once the SRBS are released, the main engines alone accelerate the rocket from about 1341 m/s to 7600 m/s.

What is the height of the rocket when the rocket reaches the speed of 7600 m/s? Show your work.

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During a tennis volley, the force pair involved is the action-reaction forces.

When playing tennis and returning a volley, the force pair involved is the action and reaction forces. In the process of hitting the ball, the tennis racket exerts a force on the ball, which is the action force.

The ball, in turn, exerts an equal and opposite force on the racket, which is the reaction force.Both the racket and the ball experience the force of impact during the volley.

The force applied by the racket causes the ball to move forward, while the equal and opposite force applied by the ball pushes the racket back.

These two forces are referred to as action-reaction forces or force pairs. A force pair refers to a pair of forces that are equal in magnitude but opposite in direction.

These forces always act on different objects and occur simultaneously. In this scenario, the action force was exerted by the tennis racket while the reaction force was exerted by the ball.

Therefore, during a tennis volley, the force pair involved is the action-reaction forces.

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q = ne

100 = n × 1.6 ×10^-19

Answer:

h = 4.25 m

Explanation:

\(gravitational \space\ potential \space\ energy \space\ (gpe)= m g h\\\) ,

where m is the mass, g is acceleration of gravity, and h is height of object.

In our case, m = 1.2 kg, g = 9.8m/s², and gpe = 50 J.

50 = 1.2 x 9.8 x h

h = 50 / (1.2 x 9.8)

h = 4.25 m

Answer:

4.25m

Explanation:

Joules is a "derived unit", meaning it is really composed of other units, and it is just abbreviated as a single letter.

\(1[J]=1 [\frac{kg \cdot m^2}{s^2}]\)

This comes from the formula for potential energy, often denoted "U"

\(U=mgh\), where m is the mass of the object (measured in kilograms,  \(kg\)), g is the acceleration due to gravity at that spot (measured in meters per second squared,  \(\frac {m}{s^2}\)), and h is the height of the object (measured in meters, \(m\)).

Note:  The object itself may or may not have an acceleration of "g" at the given point because it may be supported (like on a bookshelf).  However, the "g" is representative of its gravitational acceleration at that point if gravity could accelerate it unimpeded.

Rearranging the potential energy equation to isolate the unknown "h", dividing both sides by "m" and "g", we get the following:

\(\dfrac{U}{mg}=h\)

Substituting known values (and rewriting Joules as its SI units so we can ensure units cancel the way we need them to):

\(\dfrac{\left (50 [\frac{kg \cdot m^2}{s^2}] \right)}{(1.2 [kg])(9.8 [\frac{m}{s^2}])}=h\\\dfrac{\left (50 [\frac{kg \!\!\!\!\!\!\!{--} \cdot m^{2 \!\!\!{-}}}{s^2\!\!\!\!\!\!\!{--} }] \right)}{(1.2 [kg \!\!\!\!\!\!\!{--} ])(9.8 [\frac{m\!\!\!\!\!\!\!{--} }{s^2\!\!\!\!\!\!\!{--} }])}=h\\\dfrac{(50)}{(1.2)(9.8)}[m]=h\\\\4.2517[m] \approx h\)

Thus, the height of the book would be approximately 4.25meters high.

Answer:

Conflict resolution is the process by which two or more parties reach a peaceful resolution to a dispute. In the workplace, there can be a variety of types of conflict: Conflict may occur between co-workers, or between supervisors and subordinates, or between service providers and their clients or customers.

The term conflict resolution implies the process of seeking effective and plausible settlement in conflict situations between aggrieved parties.

The term conflict in itself refers to a disagreement between two or more parties. Conflicts are common in human parlance. An example is the current conflict between Russia and Ukraine in recent times.

The term conflict resolution implies the process of seeking effective and plausible settlement in conflict situations between aggrieved parties.

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A weight of 140 pounds will stretch the spring 11.2 inches.

Let's use Hooke's law, distance, stretch, and the given information. Hooke's law states that the distance (d) a spring stretches varies directly as the weight (w) on the spring. We can represent this relationship as:
d = kw

We are given that a weight of 50 pounds stretches a spring 4 inches:
4 = k(50)

Now, let's solve for the constant of proportionality (k):
k = 4/50 = 1/12.5

Now that we have the value of k, we can use the equation to find how far a weight of 140 pounds will stretch the spring:
d = (1/12.5)(140)
d = 11.2 inches

So, the spring will be stretched 11.2 inches.

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The graph shown in the first option nicely plots the lion's and gazelle's velocities as a function of time, so option A is the correct answer.

Velocity is the rate of change of displacement over time.

As mentioned in the problem of running at a constant speed towards a gazelle with a standing lion as shown above.

So option A is correct.

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Answer:

1.81 m

Explanation:

m = 2000 / 0.5 = 4000 times 0.8 = 3200

0.4 times 3200 = 1280 / (72)(9.8) = 1.814 m

The momentum during the collision is conserved. Hence, the total initial momentum is equal to the total final momentum. Therefore, the initial velocity of the car with a mass of 3250 Kg was, 2.05 m/s.

Momentum of a body is the product of its mass and velocity. Momentum is a vector quantity having both magnitude and direction.

The momentum during a collision is conserved. Thus,the sum of initial momentum of the colliding  bodies is equal to the final momentum of the combined mass.

Given that, mass of car 1 = 2150 Kg

velocity = 10 m/s

Momentum = mass × velocity.

= 10 m/s × 2150 Kg = 21500 kg m/s.

Mass of car 2 = 3250 kg

the combined mass = 3250  + 2150 = 5400 Kg

final velocity = 5.22 m/s

final velocity = 5400 Kg × 5.22 = 28188 kg m/s .

momentum of car 1 + momentum of car 2 = 281888 kg m/s

21500 kg m/s + (3400 Kg × V) = 281888 kg m/s

v = 2.05 m/s.

Therefore, the initial velocity of the car with a mass of 3250 Kg is 2.05 kg m/s.

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Your question is incomplete. But your complete question probably was:

A 2150 kg car, moving east at 10.0 m/s, collides and joins with a 3250 kg car. The cars move east together at 5.22 m/s. What was the initial speed of car with 3250 kg mass.