How do I find the mass in kg
To find the mass in kilograms, you need to know the object's weight in newtons and the acceleration due to gravity. The formula for finding mass is mass = weight / acceleration due to gravity. So if you have an object with a weight of 100 N and the acceleration due to gravity is 9.8 m/s^2, the mass would be 10.204 kg.
The mass of the block is 0.025 kg or 25 g, when the spring has k = 28 N/m, and compresses 0.11 m before bringing the block to rest.
When a block is dropped onto a spring with k=28 N/m, the block has a speed of 3.2 m/s just before it strikes the spring. If the spring compresses an amount of 0.11 m before bringing the block to rest, what is the mass of the block?The formula for the spring potential energy is given as follows; PE = (1/2) kx² where k is the spring constant and x is the amount of deformation of the spring. Substituting the values given;PE = (1/2) 28 (0.11)²PE = 0.16972 J. According to the law of conservation of energy, the potential energy stored in the spring at maximum compression is equal to the kinetic energy the block had before it struck the spring;KE = (1/2) mv²where m is the mass of the block and v is its velocity.Substituting the values;0.16972 = (1/2) m (3.2)²m = 0.025 kg or 25 gTherefore, the mass of the block is 0.025 kg or 25 g.For more questions on mass
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QUESTION 5 (Start on a new page.)
A roller-coaster car of mass 200 kg, with the engine switched off, travels along
track ABC which has a rough surface, as shown in the diagram below. At point A,
which is 10 m above the ground, the speed of the car is 4 m.s.
At point B, which is at a height h above the ground, the speed of the car is 2 m.st.
During the motion from point A to point B, 3,40 x 10 J of energy is used to overcome
friction.
Ignore rotational effects due to the wheels of the car.
4 m.s
2 m.s1
22 m
B
h
10 m
(2)
5.1
Define the term non-conservative force.
botravelled from
A seesaw is balanced on a pivot point. If a 20 kg child sits 1 meter from the pivot point, how far from the pivot point should a 40 kg child sit in order to balance the seesaw?
Okay, here are the steps to solve this problem:
1) The seesaw is balanced when the sum of moments is 0.
2) The moment created by a force depends on the force and the perpendicular distance from the pivot point.
3) The 20 kg child sits 1 meter from the pivot. So its moment is 20 * 1 = 20 kg*m.
4) We want to find the distance for the 40 kg child to create a moment that balances the 20 kg child's moment.
5) So the moment of the 40 kg child must be 20 kg*m.
6) The moment depends on force and distance. We know the force is 40 kg.
7) So we set: 40 kg * distance = 20 kg*m
8) And solve for the distance: distance = 20 / 40 = 0.5 meters
Therefore, for the seesaw to balance with a 20 kg child 1 meter from the pivot and a 40 kg child on the other side, the 40 kg child should sit 0.5 meters from the pivot point.
Let me know if you have any other questions!
1) As a result of a complex set of biochemical reactions, the cell membrane of a nerve cell pumps ions (Na+ and K+) back and forth across itself, thereby maintaining an electrostatic potential difference from the inside to the outside of the membrane. Modifications of the conditions can result in changes in those potentials. Part of the process can be modeled by treating the membrane as if it were a simple electric circuit consisting of batteries, resistors, and a switch. A simple model of the membrane of a nerve cell is shown in the figure at the right. It consists of two batteries (ion pumps) with voltages V1 = 100 mV and V2 = 50 mV. The resistance to flow across the membrane is represented by two resistors with resistances R1 = 10 kΩ and R2 = 90 kΩ. The variability is represented by a switch, SW1. Four points on the circuit are labelled by the letters a-d. The point b represents the outside of the membrane, and the point d the inside of the membrane. The lines coming off of points b and d have no effect on the circuit itself. A. What is the current flowing around the loop when the switch is closed? B. What is the voltage drop across the resistor R1 when the switch is open? Closed? C. What is the voltage drop across the resistor R2 when the switch is open? Closed? D. What is the voltage difference across the membrane (i.e., between d and b) when the switch is closed? E. If the locations of resistances R1 and R2 were reversed would the voltages across the cell membrane be different? How do you know?
The resistance to flow over the membrane is represented by two resistors with resistances R1 = 10 k and R2 = 90 k. SW1 is a switch that represents variability.
A. When the switch SW1 is closed, the current flowing around the loop can be found using Kirchhoff's loop rule. Thus, the total voltage drop around the loop is V1 - IR1 + V2 - IR2 = (V1 + V2) - I(R1 + R2). Since the loop is a closed circuit, the current I must be the same everywhere, so we have I = (V1 + V2)/(R1 + R2) = (100 mV + 50 mV)/(10 kΩ + 90 kΩ) = 1.0 μA (microampere).
B. When the switch SW1 is open, no current flows through the resistor R1, so the voltage drop across it is zero (0 V). When the switch is closed, the voltage drop across R1 can be found using Ohm's law: V1 - IR1 = (100 mV) - (1.0 μA)(10 kΩ) = 90 mV.
C. When the switch SW1 is open, no current flows through the resistor R2, so the voltage drop across it is zero (0 V). When the switch is closed, the voltage drop across R2 can be found using Ohm's law: V2 - IR2 = (50 mV) - (1.0 μA)(90 kΩ) = -35 mV.
D. Since we have defined point b as having a voltage of 0 V, the voltage at point d is simply the voltage drop across R2, which we found to be -35 mV. Thus, the voltage difference across the membrane is 0 V - (-35 mV) = 35 mV.
E. However, the current flowing around the loop would be different, since the resistance of the path between points a and d would be different. Specifically, when R1 and R2 are swapped, the current flowing around the loop when the switch is closed would be (V1 - V2)/(R2 + R1) = (100 mV - 50 mV)/(90 kΩ + 10 kΩ) = 0.5 μA, which is half the value we calculated earlier.
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Which of the following pieces of home-made equipment is appropriate for use?
O A brick, some rope and a stick that you found on the side of the road
O Some old bottles you found in the garage
O The welcome mat and your sister's jump rope
O Your neighbor's bicycle inner tubes
Answer:
your neighbors biycyle inner tubes
Explanation:
hope this helps :)
What type of wave does not need matter to carry energy?If y varies directly as x and y = 20 when x = 6, what is the value of y when x = 24?
a.
36
b.
80
c.
30
d.
4
Please select the best answer from the choices provided
A
B
C
D
Which statement describes a switch in an electrical circuit?
Answer:
An electrical component that can disconnect or connect the conducting path in an electrical circuit.
Which chart correctly describes the properties of magnets and electromagnets?
Answer:
The second chart seems to be correct
Explanation:
An object of mass 2kg moves in circles at radius 8m at uniform speed of 30m/s calculate. A_angular velocity B_ceritripetal force
The angular velocity is 3.75 m/s and the centripetal force is 225 N respectively.
The angular velocity of an object with respect to some extent is a degree of the way rapid that item actions through the point's view, within the feel of the way speedy the angular function of the item modifications. An instance of angular pace is a ceiling fan. One blade will whole a complete round in a certain amount of time T, so its angular speed with respect to the middle of the ceiling fan is twoπ/T.
Calculation:-
A. angular velocity ω = v/r
= 30 /8
= 3.75 m/s
B. Centripetal force = mv²/r
= 2×30²/8
= 225 N
There are 3 formulations we will use to find the angular velocity. the primary comes instantly from the definition. The angular pace is the rate of alternate of the position attitude of an object with respect to time, so w = theta / t, in which w = angular pace, theta = position attitude, and t = time.
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what is diffusion and osmosis
Answer:
In explanation
Explanation:
DIFFUSION:
The movement of particles from a region where they are in higher concentration to a region where they are in lower concentration until the equilibrium is achieved is known as the process of "Diffusion". It occurs in all three states of matter, that is solid, liquid and gas.
OSMOSIS:
When the particles of a solvent move from a region of higher concentration to a region of lower concentration through a semi-permeable membrane until the concentration of the solution is balanced, is known as "Osmosis". It occurs in liquids only.
Who delivers the classroom and hands-on training you need to become a CERT volunteer? A. A team of first responders and other qualified volunteers B. Your state’s emergency management office C. FEMA D. The CERT’s sponsoring organization
Answer:
C. FEMA
Explanation:
Community Emergency Response team, known as CERT, constitutes a team of volunteers in the United States who do so to provide emergency responses to disasters e.g fire outbreak, search and rescue etc.
This set of volunteers in the CERT program are trained for these emergency situations by a local management agency such as the Federal Emergency Management Agency (FEMA). FEMA provides classroom and hands-on training needed to become a CERT volunteer.
Elizabeth has always believed that people's thoughts can help heal them. She wants to help people use positive thinking to positively affect their
illnesses. What type of psychology would be MOST appropriate for Elizabeth to study?
Answer: Family
Explanation:
Joe went 4.2 km/h south and then went 4.1 kw/h west. From start to finish, joe went 5.9 kw/h southwest. 1. What are the instantaneous velocities? 2.what is the average velocity?
(1) The instantaneous velocities are 4.2 km/h south and 4.1 km/h west
(2) The average velocity of Joe is 5.9 km/h southwest.
What are the instantaneous velocities?
The instantaneous velocities are the velocities of Joe at any given time period and it is calculated as follows;
v (1 ) = 4.2 km/h south
v ( 2 ) = 4.1 km/h west
The average velocity of Joe is calculated from the ratio of the total displacement to total time of motion.
v (avg) = ( total displacement ) / ( total time of motion )
v (avg) = 5.9 km/h southwest
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Wire A X is fold back at p such that /AP/= 40cm and its parallel with px which is 60cm long to form parallel combination. Calculate the effective resistance of the parallel combination if the resistance per unit length of the material of tge wire
Answer: To find the total resistance of the wires, we need to use a formula that takes into account the length and cross-sectional area of the wires and the resistivity of the material they are made of. By plugging in the appropriate values for the length, cross-sectional area, and resistivity of the wires in the formula, we can find the individual resistances of the wires. Then, by using another formula for the total resistance of a parallel combination, we can find the effective resistance of the wires in parallel.
Explanation:R = ρ * (L / A)
where R is the resistance of the wire, ρ is the material's resistivity (resistance per unit length), L is the length of the wire, and A is the cross-sectional area of the wire.
according to the given data
AP= 40 cm
px=60cm
Next, we need to calculate the wire PX's length and cross-sectional area. The length is given as 60 cm, and we can assume the same diameter of 1 mm, giving a cross-sectional area of 0.785 mm^2.
Now we can calculate the resistance of each wire using the formula above:
R_AX = ρ * (80 cm / 0.785 mm^2) = 101.91 * ρ
R_PX = ρ * (60 cm / 0.785 mm^2) = 76.43 * ρ
The total resistance of the parallel combination is given by the formula:
1/R_total = 1/R_AX + 1/R_PX
Substituting the values of R_AX and R_PX, we get:
1/R_total = 1/(101.91 * ρ) + 1/(76.43 * ρ)
1/R_total = (1.55 / ρ)
R_total = ρ / 1.55
therefore, the effective resistance of the parallel combination is (ρ / 1.55) ohms
Consider the circuit in Figure 5 with e(t) = 12sin(120pit) V. When S1 and S2 are
open, i leads e by 30°. When SI is closed and S2 is open, i lags e by 30°. When S1 and S2 are closed, i has an amplitude 0.5A. What are R, L, and C?
Based on the information, it should be noted that the resistance R is 0.5 Ω.
How to calculate the resistanceWhen S1 and S2 are open, i leads e by 30°. In this case, the circuit consists of only the inductor (L) and the capacitor (C) in series. Therefore, the impedance of the circuit can be written as:
Z = jωL - 1/(jωC)
Since i leads e by 30°, we can express the phasor relationship as:
I = k * e^(j(ωt + θ))
Z = jωL - 1/(jωC) = j(120π)L - 1/(j(120π)C)
Re(Z) = 0
By equating the real parts, we get:
0 = 0 - 1/(120πC)
Let's assume that there is a resistance (R) in series with the inductor and capacitor. The impedance equation becomes:
Z = R + jωL - 1/(jωC)
Z = R + jωL
Im(Z) = ωL > 0
Substituting the angular frequency and rearranging the inequality, we have:
120πL > 0
L > 0
This condition implies that the inductance L must be greater than zero.
When S1 and S2 are closed, i has an amplitude of 0.5 A. In this case, the impedance is:
Z = R + jωL - 1/(jωC)
Since the amplitude of i is given as 0.5 A, we can express the phasor relationship as:
I = 0.5 * e^(j(ωt + θ))
By substituting this phasor relationship into the impedance equation, we can determine the value of R. The real part of the impedance must be equal to R:
Re(Z) = R
Since the amplitude of i is 0.5 A, the real part of the impedance must be equal to 0.5 A: 0.5 = R
Therefore, the resistance R is 0.5 Ω.
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with a mass if 74 kg, is a moving with a velocity of 11m/s, what is the kinetic energy ?
Answer:
4477 JExplanation:
The kinetic energy of an object can be found by using the formula
\(k = \frac{1}{2} m {v}^{2} \\ \)
m is the mass
v is the velocity
From the question we have
\(k = \frac{1}{2} \times 74 \times {11}^{2} \\ = 37 \times 121\)
We have the final answer as
4477 JHope this helps you
Hector stretches a spring with a spring constant of 3 N/m until it is extended by 50 cm. What is the elastic potential energy stored by the spring?
The elastic potential energy stored in the spring is 0.375 J.
The formula for elastic potential energy is:
E = 1/2 * k * x^2
where:
* E is the elastic potential energy in Joules
* k is the spring constant in N/m
* x is the distance the spring is stretched or compressed from its equilibrium position in meters
In this problem, we have:
* k = 3 N/m
* x = 0.5 m (50 cm)
Substituting these values into the formula, we get:
E = 1/2 * 3 * 0.5^2 = 0.375 J
Therefore, the elastic potential energy stored in the spring is 0.375 J.
How many significant figures are there in each of the following?
(a) 85.8 + 0.9
Answer:
86.7
Explanation:
sana makatulong yung answer ko
A racing car going a 20 m/s stops in a distance of 20 m.What is its acceleration?
step by step
formular v^2 = u^2+2as
stop v = 0
0 = 400+2a(20)
-400=40a
a = -10 m/s^2
ans affect acceleration is 10 m/s^2
An electron is accelerated from rest across the gap of a capacitor (two parallel plates charged -Q and +Q respectively). A hole in the top plate allows the electron to emerge with a constant velocity of v = 27 m/s. If the gap between the plates is d = 0.94 m, what is the magnitude of the electric field between the plates?
The magnitude of the electric field between the plates is 5.87 × 10^5 N/C.
The electron gains kinetic energy as it is accelerated across the gap of the capacitor. This energy is equal to the work done on the electron by the electric field between the plates of the capacitor. We can use this relationship to determine the magnitude of the electric field.
The kinetic energy gained by the electron can be expressed as:
K = (1/2)mv^2
where K is the kinetic energy, m is the mass of the electron, and v is its velocity. The work done on the electron by the electric field is given by:
W = qEd
where W is the work done, q is the charge of the electron, E is the electric field, and d is the distance between the plates.
Since the electron is negatively charged, it will be accelerated from the negative plate (-Q) to the positive plate (+Q) of the capacitor. The charge on an electron is -1.602 × 10^-19 C. Therefore, the work done on the electron is:
W = qEd = (-1.602 × 10^-19 C)(E)(0.94 m)
The kinetic energy gained by the electron is equal to the work done on it by the electric field, so:
K = W = (1/2)mv^2
Substituting the known values and solving for the electric field gives:
E = (2qK) / (md^2) = (2(-1.602 × 10^-19 C)(0.5m_e(27 m/s)^2)) / ((9.11 × 10^-31 kg)(0.94 m)^2)
where m_e is the mass of the electron.
E = 5.87 × 10^5 N/C
Therefore, the magnitude of the electric field between the plates is approximately 5.87 × 10^5 N/C.
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What happens to the body’s immune system when attacked by HIV ?
Answer:
HIV attacks a specific type of immune system cell in the body. It's known as the CD4 helper cell or T cell. When HIV destroys this cell, it becomes harder for the body to fight off other infections.
Explanation:
An AC generator consists of eight turns of wire, each having area A =9.0x 10-2 m2, with a total resistance of 12.0 V. The coil rotates in a magnetic field of 0.500 T at a constant frequency of 60.0 Hz, with axis of rotation perpendicular to the direction of the magnetic field. (a) Find the maximum induced emf. [3] (b) What is the maximum induced current? [1] (c) Determine the induced emf and current as functions of time. [2] (d) Wiat maximum torque must be applied to keep the coil turning? (3)
We have that the maximum induced emf,the maximum induced current, the induced emf and current as functions of time,The maximum torque must be applied to keep the coil turning are
a )\(E_{max}=135.6v\)
b) \(I_max=11A\)
c) \(I_i=11A sin(376.9rad/s t)\)
\(E_i=135.6v sin(376.9rad/s )\)
d) \(T=4.07Nm\)
From the Question we are told that
Area \(A =9.0x 10^{-2} m^2\)
Total resistance of \(R=12.0 V.\)
Magnetic field of \(B=0.500 T\)
Constant frequency \(F=60.0 Hz\)
Eight turns \(N=8N\)
A)
Generally the equation for the maximum induced emf is mathematically given as
\(E=NAB\omega\)
Where
\(\omega=2\pi f\)
\(\omega=2*3.142*60\)
\(\omega=376.9rad/s\)
\(E_max=8*(9.0x 10-2)*0.5*376.9\)
\(E_{max}=135.6v\)
B)
Generally the equation for the maximum induced Current is mathematically given as
\(I_m=\frac{E}{R}\\\\I_max=\frac{135.6}{12}\\\\I_max=11A\)
C)
Generally for the induced emf and current as functions of time we Substitute \(E_{max}\) and \(\omega\) into
\(E_i=E_{max} sin\omega t\)
\(E_i=135.6v sin(376.9rad/s t)\)
And Same for induces Current
\(I_i=I_{max} sin\omega t\)
\(I_i=11A sin(376.9rad/s t)\)
D)
Generally the equation for the maximum torque is mathematically given as
\(T = rB sin θ\)
Where
r= maximum magnetic moment
\(r=NIAr= 8*11.3*0.090r=8.14m^2\)
Therefore
\(T = 8,14*0.500 sin 90\)
\(T=4.07Nm\)
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25. Heat is supplied at the same rate to two metals at room temperature. Which metal will reach 20° above room temperature first?Select one:a. Iron will reach 20° above room temperature first because it has a lower specific heat.b. Silver will reach 20° above room temperature first because it has a higher specific heat.c. They will reach room temperature in the same amount of time.d. It depends on the room temperature.
The specific heat capacity is defined as the thermal energy required to raise the temperature of a specific mass of a material a specific amount. The one with the highest specific heat capacity would have the smallest rise in temperature.
Since:
\(\begin{gathered} ci=Specific_{\text{ }}heat_{\text{ }}of_{\text{ }}iron=0.1 \\ ca=Specific_{\text{ }}heat_{\text{ }}of_{\text{ }}aluminum=0.2 \\ ca>ci \end{gathered}\)We can conclude that the answer is:
a. Iron will reach 20° above room temperature first because it has a lower specific heat.
Question 1 of 10 Which of the following statements are true of liquids? Check all that apply. A. The particles have more kinetic energy than those of gases O B. The particles can move past each other within a fixed volume. C. The particles are in a fixed location. 0 D. There are intermolecular forces between the atoms or molecules. SUE
Answer:
B. The particles can move past each other within a fixed volume.
D. There are intermolecular forces between the atoms or molecules.
Explanation:
define the term work
Answer:
Work, in physics, measure of energy transfer that occurs when an object is moved over a distance by an external force
Explanation:
at least part of which is applied in the direction of the displacement. ... To express this concept mathematically, the work W is equal to the force f times the distance d, or W = fd.
How much gravitational force do two lead balls with a mass of 8 kilograms, the centers of mass of which are 17 cm apart, affect each other?
Answer:
1.48×10⁻⁷ Newtons
Explanation:
From the question,
According to newton's law of universal gravitation.
F = Gmm'/r²........................ Equation 1
F = gravitational force, G = gravitational constant, m = mass of the first ball, m' = mass of the second ball, r = distance between the balls.
Given: m = m' = 8 kg, r = 17 cm = 0.17 m,
Constant : G = 6.67×10⁻¹¹ Nm²/kg²
Substitute these values into equation 1
F = (6.67×10⁻¹¹×8×8)/(0.17²)
F = 1.48×10⁻⁷ N
the
four particles form a square of edge
length a 5.00 cm and have charges
q1 10.0 nC, q2 20.0 nC, q3
20.0 nC, and q4 10.0 nC. In unitvector notation, what net electric field
do the particles produce at the square’s
center
Answer:
500 in unitivector notion
27 1 point
A student has tested several types of wood for density. The best way of presenting this information graphically would be to use which item?
Scatterplot
Pie Chart
Line Graph
Bar Graph
Previous
Search
The best way of presenting the information on density graphically would be to use a D, bar graph.
What is a bar graph?A bar graph is a type of chart that uses rectangular bars to represent data. The bars are typically arranged in columns, with the independent variable (in this case, the type of wood) on the x-axis and the dependent variable (in this case, the density) on the y-axis.
A bar graph is the best choice for this data because it allows for easy comparison of density of different types of wood. We can see at a glance which type of wood is the densest and which type of wood is the least dense.
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list the 8 types of waves found on the electromagnetic spectrum from longest to shortest wavelength.
The 8 types of waves found on the electromagnetic spectrum, from longest to shortest wavelength, are: Radio waves , Microwaves , Infrared radiation, Visible light, Ultraviolet radiation, X-rays, Gamma rays.
The electromagnetic spectrum is a range of electromagnetic waves that includes radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays.
The wavelength of an electromagnetic wave is the distance between consecutive points of equal phase in the wave. The shorter the wavelength, the higher the frequency of the wave.
Radio waves have the longest wavelength and the lowest frequency of the electromagnetic waves. Gamma rays have the shortest wavelength and the highest frequency.
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A Ping-Pong ball is shot into a circular tube that is lying flat (horizontal) on a table-top.
Figure attached.
When the Ping-Pong ball exits the tube, which path will it follow in the figure?
d
a
c
b
e
Answer:
e
Explanation: