what period of oscillation would you expect if the mass of the glider were doubled? assume no damping

The answer to the digits rounded to one significant figure is 100.

Significant figures are the most important figures in a number of digits.

The closer a digit is to the beginning of a number, the more important  or significant  it is.

But, the rule for rounding up a set of numbers to the first significant or to one significant figure is that:

From the numbers 98.907, 9 is the most significant digit followed by 8.

8 is greater than 5 so we should round up by adding one to 9 making the number 100.

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Explanation:

Density=mass/volume

density= 3.5 g ÷ 5.5cm

density=0.63

The potential energy associated with the conservative force is +40 j. As the particle moves from a to b, the force does +25 j of work on the particle, all of which results in an increase in the kinetic energy only. Hence, the value of the potential energy at point b is -25J.

Given:

Mass of the particle= 0. 40 kg

Speed=10m/s

Initial workdone =+25J

Initial Potential enrgy=+40J

Now to find the value of the potential energy at point b use the following statement i.e.

∴ The change in potential energy of the given system is the -ve of the internal work done by the conservative force on the particle.

Hence,

ΔU=−W int

ΔU=-(+25J)

ΔU=-25J

Hence, -25Jis the value of the potential energy at point b.

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F = 20 N

m = 250 g = 0.25 Kg

a = ?

Using Newton's 2nd Law

a = F/m

a = 20/0.25

a = 80 m/s²

The acceleration of an object with a mass of 250 grams or 0.250 kg and force applied of 20N is 80m/s².

Acceleration is the rate of change of velocity of an object. Acceleration means the speed of the object is changing, but not always. When an object moves in a circular path at a constant speed rather than variable, it is still accelerating, because the direction of its velocity is changing. It is a vector quantity as it has both the magnitude and direction. The SI unit of acceleration is meter per second (m/s²).

According to the formula,

f = m × a

f = force,

m = mass of the body,

a = acceleration of the body

f = 20N

m = 250 grams = 0.250kg (1kg = 1000grams)

f = m × a

a = f/ m

a = 20N/ 0.250kg

a = 80m/s²

The acceleration of the body is 80m/s².

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The range of magnetic field strengths on the Earth's surface varies depending on the location and geological features of the area.

The magnetic field of the Earth is not uniform and varies in strength, direction, and intensity over time and location.

At the equator, the magnetic field strength is about 30,000 to 60,000 nanotesla (nT), while at the poles, the strength can be as high as 60,000 to 80,000 nT. In general, the magnetic field strength at the Earth's surface is typically between 25,000 to 65,000 nT.

However, the magnetic field of the Earth is subject to fluctuations and changes due to various factors, such as solar activity, geological changes, and other natural phenomena. These fluctuations can cause variations in the strength and direction of the magnetic field, which can have significant implications for a variety of fields, including navigation, geology, and space weather forecasting.

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The total surface area of one slice will be 64 π cm².

The total surface area includes the base as well as the curving component. It is the whole area covered by the object's surface.

The total area of a form with a curved surface and base is equal to the sum of the two areas.

The total surface area of the sphere will be;

\(\rm A=4 \pi r^2 \\\\ \rm A=4 \times \pi (4)^2 \\\\ \rm A=64 \pi \ cm^2\)

Hence the total surface area of one slice will be 64 π cm².

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Answer:

32

Explanation:

The angular width of the central peak when monochromatic light of wavelength 600 nm is incident on a slit with a width of 6 micrometers is 0.1 radian.

The angular width is the angle between the two points at which the intensity of the light has dropped to 1/2 the maximum value. This angle is known as the full width at half maximum (FWHM).

The angular width of the central peak for a monochromatic light of wavelength 600 nm incident on a slit with a width of 6 micrometers can be calculated using the equation:

θ = (λ/a)

where λ is the wavelength of the incident monochromatic light and a is the width of the slit.

Therefore, the angular width of the central peak of a diffraction grating with monochromatic light of wavelength 600 nm and a slit width of 6 micrometers can be calculated as follows:

θ = λ/a

θ = 600 x 10⁻⁹ / 6 x 10⁻⁶

θ = 100 x 10⁻³ radians

θ = 0.1 radian

Therefore, the angular width of the central peak is 0.1 radian.

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Answer:

1. The horizontal component of the velocity is approximately 271.89 m/s

The vertical component of the velocity is approximately 126.79 m/s

2. The time the bullet spends in the air is approximately 25.85 seconds

3. The maximum height reached by the bullet is approximately 819.35 meters

4. The horizontal distance is approximately 7028.36 meters

Explanation:

The initial velocity of the bullet = 300 m/s

The angle at which the bullet was fired, θ = 25° from the horizontal

1. The horizontal component of the velocity vₓ = The component of the velocity in the x-direction

vₓ = v × cos(θ)

Substituting gives;

vₓ = 300 × cos(25°) ≈ 271.89 m/s

The vertical component of the velocity \(u_y\) = The component of the velocity in the y-direction

\(v_y\) = v × sin(θ)

Substituting gives;

\(u_y\) = 300 × sin(25°) ≈ 126.79 m/s

2. The time the bullet takes to maximum height, t = 1/2 × The time the bullet spends in the air

The following is the relevant kinematic equation for the vertical motion of the bullet;

v = u - g × t

Where;

\(v_y\) = The final velocity vertical velocity = (0 at maximum height)

\(u_y\) = The initial vertical velocity ≈ 126.79 m/s

g = The acceleration due to gravity = 9.81 m/s²

t = The time in flight of the bullet

Substituting gives;

0 = 126.79 - 9.81 × t

t ≈ 126.79/9.81 ≈ 12.924 s

The time the bullet spends in the air = 2 × The time the bullet takes to maximum height

∴ The time the bullet spends in the air ≈ 2 × 12.924 ≈ 25.85

The time the bullet spends in the air ≈ 25.85 seconds

3. The maximum height reached is given from the following kinematic equation;

\(u_y\)² = 2 × g × h

Where;

h = The maximum height reached by the bullet

∴ h = \(u_y\)²/(2 × g)

h = 126.79²/(2 × 9.81) = 819.35

The maximum height reached by the bullet = h = 819.35 meters

4. The horizontal distance travelled by the bullet = Horizontal component of the velocity of the bullet × The time the bullet spends in the air

∴ The horizontal distance travelled by the bullet = 271.89 × 25.85 ≈ 7028.36

The horizontal distance travelled by the bullet ≈ 7028.36 meters.

Answer: They change the shape of the lens

Explanation: It enables the lens to change its shape to focus on objects at various distances

Answer:

4.(615384)Hz

Explanation:

Firstly, let's take a note that the speed of light is much higher than 30m/s, on the other hand visible light has wavelengths measured in nanometers, so I assume we're just supposed to assume the values in the question for the purpose of solving it.

If a wave moves through a point with speed v and has wavelength l, In each second we observe v/l cycles - and cycles per second is the frequency!

F = 30m/s / 6.5m = 4.(615384)/s = 4.(615384)Hz

Explanation:

v=fh, where v is velocity

f is frequency

h is wavelength

hence the frequency=velocity/wavelength

=30/6.5

=4.61Hz

It was easier to determine the sequence of colored threads with the higher magnification objective. This is because the higher magnification objective allows for a clearer and more detailed view of the threads, making it easier to differentiate between the different colors and determine their sequence.

For example, if you were using a 10x objective, you would be able to see the threads more clearly than if you were using a 4x objective. This would make it easier to determine the sequence of the colored threads, as you would be able to see the individual colors more clearly and differentiate between them more easily.

In conclusion, the higher magnification objective makes it easier to determine the sequence of colored threads because it provides a clearer and more detailed view of the threads.

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Answer:

Gravity.

Rocket ships.

Ball.

Basketball.

Explanation:

Gravity has to do a lot with air. It puts the planets in there area.

Rocket Ship has to do a lot with air. If i'm right, they calculate the area, weather, about the air.

A ball gets throwed in the air, which gravity comes into place.

Basketball is also a similar example to a ball.

The surface temperature of our Sun, a class G star, is 5800 K. Since it is hotter than a type M star, we can infer that it is cooler than a type O star. Williamina Fleming developed a system to categorize stars in the 1880s based on the potency of hydrogen absorption lines.

The stars with the strongest hydrogen lines were designated as "A" stars, followed by "B" stars with the second-strongest hydrogen lines, and so on until "O" stars with the weakest hydrogen lines.

However, as we saw above, hydrogen lines by themselves are not a very reliable indicator for classifying stars since they vanish from the visible light spectrum when stars get too hot or too cool.

A, B, F, G, K, M, and O were the only letters from the old system that Annie Jump Cannon focused on when she redesigned this classification system in the 1890s.

Instead of beginning over, Cannon also rearranged the existing classes into the order we are familiar with: O, B, A, F, G, K, M, in decreasing order of temperature.

In her lifetime, she classified over 500,000 stars, classifying up to three stars each minute by examining the stellar spectra, as you can read in the piece on Annie Cannon: Classifier of the Stars later in this section.

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Our Sun is a class G star with a surface temperature of 5800 K. We may conclude that it is colder than a type O star since it is hotter than a type M star.

In the 1880s, Williamina Fleming created a classification system for stars based on the strength of hydrogen absorption lines.

The stars were categorized as "A" stars, "B" stars with the second-strongest hydrogen lines, "C" stars with the strongest hydrogen lines, and so on until "O" stars with the weakest hydrogen lines.

Since they disappear from the visible light spectrum when stars get too hot or too cold, hydrogen lines by themselves are not a particularly accurate signal for categorizing stars, as we have shown above.

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Answer:

An interval is a distinct measure of time or the physical or temporal distance between two things.

Explanation:

Now our wavelength is getting longer because the waves are stretching out. This makes the 1. Frequency is lower as well as the pitch we hear.

Wavelength is the gap among equal factors (adjacent crests) in the adjacent cycles of a waveform sign propagated in the area or alongside a twine. In wi-fi systems, this duration is generally laid out in meters (m), centimeters (cm), or millimeters (mm).

Equation of the wavelength, we will tell that the wavelength of a wave is inversely proportional to its frequency, i.e., because the frequency of a wave increases, its wavelength decreases.

A better-frequency sound has a better pitch, and a decreased-frequency sound has a lower pitch. In discern 10.2 sound A has a better pitch than sound B. for example, the chirp of a bird would have an excessive pitch, but the roar of a lion could have a low pitch. The human ear can discover a huge variety of frequencies.

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Disclaimer:- your question is incomplete, please see below for the complete question.

Now our wavelength is getting longer because the waves are stretching out. This makes the _________ lower as well as the pitch we hear.

1. Frequency

2. Loudness

3. Amplitude

Answer:

C. C

Explanation:

A wave can be defined as a disturbance in a medium that progressively transports energy from a source location to another location without the transportation of matter.

In Science, there are two (2) types of wave and these include;

I. Electromagnetic waves: it doesn't require a medium for its propagation and as such can travel through an empty space or vacuum. An example of an electromagnetic wave is light.

II. Mechanical waves: it requires a medium for its propagation and as such can't travel through an empty space or vacuum. An example of a mechanical wave is sound.

A crest can be defined as the highest (vertically) point on a waveform.

On a related note, a trough is the lowest (vertically) on a waveform.

An amplitude can be defined as a waveform that's measured from the center line (its origin or equilibrium position) to the bottom of a trough or top of a crest. Thus, the vertical axis (y-axis) is the amplitude of a waveform i.e it's measured vertically.

In this scenario, waveform C which is represented by a blue curvy line has the smallest amplitude in comparison with the other waveforms because it has the minimum height when measured from the origin.

In contrast, waveform A represented by a purple line has the highest amplitude because it has the maximum height when measured from the origin.

Mathematically, the amplitude of a wave is given by the formula;

x = Asin(ωt + ϕ)

Where;

Answer:

The answer is indeed D as the comment above suggests.

Explanation:

Simply put, wave D's highest point is closer to the line than all of the other high points of A, B and C

The nurse's duty in avoiding polypharmacy is to keep a thorough record of all medications you take, including their brand and generic names, dosages, and intended uses.

Polypharmacy includes the usage of many drugs as well as possibly unsuitable pharmaceuticals.

Assist patients and families close to getting a complete list of drugs. Rearrange the patient's electronic health record prescription list.

Look out for unsuitable and inaccurate medications. When rescribing drugs, use caution.

Keeping a complete record of all drugs you take, including their brand and generic names, doses, and intended use is the nurse’s role in preventing polypharmacy.

Hence, nurses play an important role in preventing polypharmacy.

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The average product of capital when 10 units of capital and 10 units of labor are employed in the production function q = 3k 4l is 3.

The average product of capital (APK) is calculated by dividing the total product of capital (TPK) by the number of units of capital employed (k). In this case, the production function is given by q = 3k^4l, where q represents the output, k represents the units of capital, and l represents the units of labor.

To find the APK, we first need to calculate the total product of capital (TPK) when 10 units of capital and 10 units of labor are employed. Substituting the given values into the production function, we have q = 3(10)^4(10) = 3(10,000)(10) = 300,000.

Next, we divide the TPK by the number of units of capital employed (k). Since 10 units of capital are employed, the APK is calculated as follows: APK = TPK/k = 300,000/10 = 30,000/1,000 = 3.

Therefore, the average product of capital when 10 units of capital and 10 units of labor are employed in the production function q = 3k^4l is 3.

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A rocket with 200kgs is loaded extra 100kgs then the  Rocket maximum altitude is 93005 m and total Time-of-Flight is 294 s

The Time-of-Flight concept (ToF) is a technique for determining distances between sensors and objects based on the amount of time that passes between a signal being sent and returning to the sensor after being reflected by an object. The Time-of-Flight principle can be employed with a variety of signals (also known as carriers), with sound and light being the most popular ones. The time it takes for photons to travel between two points—from the sensor's emitter to a target and back—in order to calculate distance for all Time-of-Flight (ToF) sensors.

Direct and indirect ToF both have unique advantages in particular situations. Each pixel in a scene can be simultaneously measured for distance and intensity.

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Answer:

Newton's first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force

Answer:

An object in motion will stay in motion unless acted on by an unbalanced force.

An object at rest will stay at rest unless acted on by an unbalanced force.

An object in motion will stay in motion, and an object at rest will stay at rest unless acted on by an unbalanced force

(There are three parts to Newton’s First Law of Motion)

Answer:

12500W

Explanation:

Given parameters:

Work done  = 250000J

Time taken  = 20s

Unknown:

Power of the crane = ?

Solution:

Power is the defined as the rate at which work is being done;

  Mathematically;

        Power = \(\frac{work done}{time }\)

 insert the parameters and solve;

      Power  = \(\frac{250000}{20}\)   = 12500W

The uncertainty in the emitted wavelength is approximately: 0.013 nm.

The mean lifetime of an electronically excited state in a molecule is 5 ns. If this state emits at 500 nm, calculate the uncertainty in the emitted wavelength.

The uncertainty in the emitted wavelength can be calculated using the relation given below,Δλ = h/(4πmc)τ
Here, Δλ is the uncertainty in the emitted wavelength is Planck’s constant
m is the mass of an electron
c is the speed of light in vacuum
t is the lifetime of the excited state

Therefore, substituting the given values we have,Δλ = (6.626 × 10^-34)/(4π × 9.1 × 10^-31 × 3 × 10^8 × 5 × 10^-9)≈ 0.013 nm (approximately)

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1) push down on the end of the lever, and 2) 3/4 of the way from the fulcrum

Answer:

5N NORTH

Explanation:right on edge

The process of cellular respiration releases energy because the energy that is released when the bonds are formed in CO₂ and water is equal to the energy required to break the bonds of sugar and oxygen. So, option A.

Through a sequence of chemical processes called cellular respiration, glucose is broken down to create ATP, which may then be used as an energy source for a variety of bodily functions. The citric acid cycle, oxidative phosphorylation, and glycolysis are the three primary phases of cellular respiration.

Carbon dioxide and water are created during cellular respiration when glucose is broken down in the presence of oxygen. The energy-carrying molecule ATP (adenosine triphosphate) absorbs the energy generated during the process.

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Answer:

8.803 s

(but this is only if it's a free fall, which we assume since we didn't get the mass of the hulk)

Answer:

Length - meter (m)

Time - second (s)

Amount of substance - mole (mole)

Electric current - ampere (A)

Temperature - kelvin (K)

Luminous intensity - candela (cd)

Mass - kilogram (kg)

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Light will reflect at the same angle off a smooth surface as when it first touches it. The direction of reflected light beams for a flat surface is the same. Specular reflection is what is happening here.

When light reflects off of a surface, it happens. Light will reflect at the same angle it was incident upon if the surface is glossy and smooth.

A smooth polished surface is what is referred to as a reflection when a light ray strikes it and bounces back. Surface reflection occurs when a light beam hits it and then leaves it.

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Answer: The part of color that's reflected is the red that bounces off the paper.

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26.0898 rad/s is the angular velocity of a rotor in a blender.

Given

Initial velocity (ω₁) = 55.0 rad/s

Deceleration (α) = -40.7 rad/s²

Angle (θ) = 28.8 rad

Final angular velocity (ω₂) =?

According to the angular kinematic equation

ω₂² = ω₁² + 2αθ

Put the values of ω₁, α, and θ in the equation

We get,
ω₂² = (55)² + 2(₋40.7)(28.8)

ω₂² = √680.68

ω₂ = 26.0898 rad/s

Hence, 26.0898 rad/s is the angular velocity of a rotor in a blender after turning 28.8 rad.

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The capacitance across the motor must be 86.87 f to increase the power factor to 0.9 lagging.

An electric rotating machine with the capacity to transform electrical energy into mechanical energy is known as a single-phase motor. It functions using a single-phase power source. They have hot and neutral wiring, respectively. Their supply voltages fluctuate in unison and their power can exceed 3Kw.

I1 = 20A, f = 50 Hz

cosϕ1 = 0.75 ⇒ ϕ1 = 41.41∘ ⇒ tanϕ1 = 0.88

cosϕ2 = 0.9 ⇒ ϕ2 = 25.84∘ ⇒ tanϕ2 = 0.48

Ic = I1 cosϕ1 (tanϕ1 − tanϕ2)

= (20) (0.75) (0.88 – 0.48) = 6 A

C = Ie/2πfv

C = 6/2π × 20 × 220

C = 86.87∪f

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