What property is used to determine cage degree of polarity between two bonded atoms

Answer:

Model C has more double the oxygen than A. I think it is B

Explanation:

According to the Le Chatlier's Principle, an equilibrium system will adapt to a change in temperature, volume, or the quantity of molecules in a reactant or product in order to reestablish balance.

The smallest unit of a substance that keeps its content and properties is a molecule, which is made up of two or more atoms linked together by chemical bonds. The building blocks of chemistry are molecules. A subscript with the atom count is placed after the element symbol to identify molecules.

When two or more molecules interact to create a brand-new product, a chemical reaction takes place. Reacting substances are referred to as reactants, whilst newly created substances are referred to as products.

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Explanation:

using Newton second law of motion which states that the rate of change of Momentum is directly proportional to the applied force.

force ∝ change in Momentum/time taken

F∝Mv-Mu/t

F=M(v-u)/t

remember in the law of motion in which acceleration(a)=v-u/t so we will just substitute

F= M×A

f=ma

in ur question

m(mass)= 5.2kg

force(f)=100N

a(acceleration)=??

f=ma

a=f/m

a=100/5.2

a=19.2m/s²

2.) No

3.) Yes look at the explanation

Answer:

B) 2.85 ∘C

Explanation:

A) Kelvin

Answer:Ithink erosion cuz if we can tell how long ago it eroded we can see how old it is

Explanation:

If 35 ml 0f 5.5 M H₂SO₄ was spilled. the minimum mass of NaHCO₃ that must be added to neutralize the acid is 32.34 g.

according to the question the balance equation is given as :

H₂SO₄    +   2Na₂SO₄   ----->  Na₂SO₄    +   2CO₃    +   2H₂O

1 mol of H₂SO₄ react with 2 mol of NaHCO₃

molarity = 5.5 M

volume = 35 ml = 0.035 L

Molarity =  mass of solute / volume of solution in L

mol of H₂SO₄ in 35 ml of 5.5 M solution

mass of solute =  0.035 L × 5.5 mol / L

                        =   0.1925 mols

no. of moles of H₂SO₄ = 0.1925 mol

from the equation ,

0.1925 moles of H₂SO₄ will require = 2 × 0.1925 mol of NaHCO₃

                                                          =  0.385 mol of NaHCO₃

molar mass of NaHCO₃ = 84.00 g/mol

         mass of NaHCO₃  =  0.385 mol ×  84.00 g/mo                

                                        =  32.34 g

Thus, If 35 ml 0f 5.5 M H₂SO₄ was spilled. the minimum mass of NaHCO₃ that must be added to neutralize the acid is 32.34 g.

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Answer:

Magnesium

Explanation:

The answer is Magnesium

Answer:

a) 1,69 M

b)11.55%

Explanation:

a) To determine the [CH3CH2OH] in the wine, we can use the stoichiometry of the balanced equation provided. Since the ratio of CrO7^2- to CH3CH2OH is 2:3, for every 2 moles of CrO7^2- that are consumed, 3 moles of CH3CH2OH are produced. Therefore, we can use the volume and molarity of the CrO7^2- solution to determine the number of moles of CH3CH2OH present in the wine sample.

The number of moles of CrO7^2- used in the titration is (26.25 mL)(0.500 M) = 13.125 moles. Therefore, the number of moles of CH3CH2OH present in the wine sample is (3/2)(13.125 moles) = 19.69 moles

Since the original volume of wine sample was 10.0 mL, the [CH3CH2OH] in the wine is (19.69 moles) / (0.01 L) = 1.969 M

b) To convert the answer in part (a) into percent by volume, we can use the density of ethanol and the conversion factor of 100mL/1L.

The density of ethanol is 0.789 g/mL, so the mass of ethanol in the sample is (19.69 moles) x (46.07 g/mol) = 910.1 g

The mass of ethanol in 100ml is (910.1g) x (100mL/1L) = 91.01 g/100mL

The volume of ethanol in the sample is (91.01 g/100mL) / (0.789 g/mL) =115.5 mL/L or 11.55% by volume.

Steel is produced from pig iron through a process known as steelmaking or iron and steel production.

The pig iron obtained from the blast furnace contains high amounts of carbon, impurities, and other elements. To convert pig iron into steel, the carbon content needs to be reduced to desired levels, and impurities must be removed.One common method of steelmaking is the basic oxygen process (BOP). In this process, pig iron is placed in a vessel called a converter, where oxygen is blown through the molten metal. The oxygen reacts with the carbon and impurities, causing them to oxidize and form gases that are released. Alloying elements and desired additives can be added at this stage to achieve specific steel properties. Another method is the electric arc furnace (EAF), where an electric arc is used to heat and melt the pig iron, allowing impurities to be oxidized and removed.The advantages of using steel are numerous. Steel is strong, durable, and versatile, making it suitable for a wide range of applications. It has high tensile strength, which means it can withstand heavy loads and pressures. Steel is also resistant to corrosion, making it ideal for construction, infrastructure, and transportation projects. It is a recyclable material, contributing to sustainability and reducing environmental impact. Additionally, steel can be fabricated into various shapes and sizes, allowing for customization and flexibility in design.References:

A. Ghosh and A. Chatterjee, Ironmaking and Steelmaking: Theory and Practice, PHI Learning, 2008.

R.H. Tupkary and V.R. Tupkary, An Introduction to Modern Iron Making, Khanna Publishers, 2010.

J.R. Davis, ed., ASM Specialty Handbook: Carbon and Alloy Steels, ASM International, 1995.

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The volume of the given gas is 5.35 L.

Here we use the combined gas law viz. P1V1/T1 = P2V2/T2, which is  derived from the ideal gas equation PV = nRT, where

PV = nRT

where,

P = pressure

V = volume

n = no. of moles

R = gas constant = 0.0821 L atm/mol K

T = temperature.

Here,

\($P_1\) = 1.40 atm, \($P_ 2\)= 0.989 atm  

\($V_1\) = 3.70 L, \($V_2\) = ?

\($T_1\) = 12.20°C = (12.20 + 273) K = 285.2 K  

\($T_2\) = 20.80°C = (20.80 + 273) K = 293.8  K

substituting the values in the equation  P1V1/T1 = P2V2/T2, we get,

(1.40 x 3.70)/285.2 = 0.989 x \($V_2\)/293.8

\($V_2\) = (1.40 x 3.70 x 293.8) / (285.2 x 0.989)

\($V_2\) = 1521.884 / 284.211

\($V_2\) =5.35 L

Thus, the volume of the gas is 5.35 L.

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Potential energy depends on location to generate energy.

Potential energy is a type of stored energy that depends on how various system elements interact with one another. A spring's potential energy rises when it is compressed or expanded. A steel ball has more potential energy if it is raised above the ground as opposed to dropping to it. The more it is raised, the more work it is capable of. Instead of being a property of specific entities or particles, potential energy is a property of systems. For instance, the potential energy of the system composed of Earth and the raised ball increases as they move apart.

Systems with components whose configurations, or relative positions, affect the strength of the forces they apply to one another, create potential energy.

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Answer: A chemical change occurs when the substance's composition is changed. When bonds are broken and new ones are formed a chemical change occurs.

Answer:

They have the same number of valence electrons

Explanation:

The periodic table classifies elements into groups and periods. The groups are the vertical columns while the periods are the horizontal rows.

The elements in the same column are said to be in the same group. One similarity shared by all elements in the same group is that they all have the same number of valence electrons in their outermost shells.

The temperature changes for the water and the metal can be calculated by subtracting their initial temperatures from the final temperature.

AT (water) = √°C - °℃

AT (metal) = √°C - °℃

The above equations give the temperature changes for the water and the metal, respectively. The specific values of the temperatures and the final temperature are not provided, so the actual temperature changes cannot be determined without knowing these values.

In general, the temperature change of a substance is given by the difference between the final and initial temperatures. When a warmer object comes into contact with a cooler one, heat energy is transferred from the warmer object to the cooler one until they reach thermal equilibrium, where their temperatures become equal.

The magnitude of the temperature change depends on factors such as the specific heat capacity of the substances involved and the amount of heat exchanged between them.

To accurately calculate the temperature changes, the specific heat capacities of water and the metal would be needed. Additionally, the masses or quantities of the substances would be necessary to determine the amount of heat exchanged. Without these specific values, it is not possible to provide a precise numerical answer.

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Reagents used for making phenol from benzene are \(H_{2} SO_{4}\) and \(HNO_{3}\). Another reagent used is NaOH.

Due to the pi electrons on the oxygen atom providing electron density into the ring, phenol is very reactive to electrophilic aromatic substitution. By using this general strategy, other groups can be joined to the ring using techniques including acylation, halogenation, and sulfonation.

But because phenol's ring is second only to aniline so strongly activated, chlorination or bromination of phenol will result in replacement of the hydroxyl group on all carbon atoms, ortho and para, instead of just one.

The conc. is used to warm the ben. sulfuric acid to develop acid sulfonated with benzene. The sodium phenoxide is then produced by heating the sodium hydroxide. Phenol is produced through sulphuric acid hydrolysis. The above list contains the reaction order.

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Answer:

I think A it looks to be the answer

Explanation:

sorry if wrong

Answer:

-1

Explanation:

Proton +1

Neutron 0

Electron −1

Answer:

1.37 mol NaCl

Explanation:

Hi!

For this one, you are given a mass (in grams) of NaCl, 80.0.

To convert this to moles, you have to do a mass-to-mole calculation, where you use the molar mass of NaCl.

Na's m.m. is 22.99 g/mol

Cl's m.m. is 35.45 g/mol

1(22.99 g/mol) + 1(35.45 g/mol) = 58.44 g/mol => here is the molar mass of NaCl.

Here's the setup for the conversion:

g(mol/g) - we are flipping g/mol to mol/g to get mol on top (since we are looking for the # of mol) and g on the bottom to cancel out the g unit.

80.0 g NaCl(1 mol NaCl/58.44 g NaCl) = 80.0 / 58.44 = 1.37 mol NaCl.

I hope this helped!

The moles of carbon dioxide gas that are present in the sample is 1.36 mol. The ideal gas law should be applied to calculate the number of moles of CO₂.

According to ideal gas laws, the number of moles can be found by using the formula:

                    PV = nRT

Where P = Pressure of the gas = 1.30 atm (given)

            V = Volume of gas = 31  L

            T = Temperature = 87 °C = 360 K

            R = Gas constant = 0.0821 L atm mol⁻¹ K⁻¹

            n = number of moles

                           \(n = \frac{PV}{RT} \\\\n = \frac{(1.3) (31.0)}{(0.0821) (360)} \\\\n = 1.36\)

Hence, the moles of CO₂  gas in the sample = 1.36 mol

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For the chemical elements Cl, Am, Lu, Ca, Hg, I, Ti, and Mg, the final occupied sublevels are the 4s orbital for Cl, the 5f orbital for Am, the 7s orbital for Lu, the 3p orbital for Ca, the 6s orbital for Hg, the 5p orbital for I, the 4f orbital for Ti, and the 3s orbital for Mg.

The primary quantum number, n, of an element determines the sublevel of that element. greater numbers correspond to greater energy levels for the electron, which is indicated by this number.

The form of the orbital is determined by the angular momentum quantum number, l. The p orbital has a form, the d orbital has a clover shape, the f orbital is complicated, and the s orbital is spherical. the final level that was inhabited.

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4) The volume of the HCl used is 9.500 mL while the volume of the NaOH used is 3.800 mL.

5) Molarity of sodium hydroxide is obtained from; Molarity of HCl * 1/2

By reacting an unknown component with a known quantity of a different chemical known as a titrant, titration is a laboratory procedure used to measure the concentration of an unknown substance, often a solute dissolved in a liquid.

The endpoint of a titration can be detected in a number of ways, depending on the specific titration being performed.

4)

Volume of the Acid used = Initial reading - Final reading = 25.00 - 15.50 = 9.500 mL

Volume of the base used = 8.80 - 5.00 = 3.800 mL

5)

We know that the mole ratio is 1:2 and the implication of this is that the set up to obtain the molarity of the sodium hydroxide solution is Molarity of HCl * 1/2

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The pressure of benzene vapor in equilibrium with benzene liquid at 298 K is 1.97 atm.

Vaporization is the conversion of a substance from the liquid or solid phase into the gaseous (vapour) phase. If conditions allow the formation of vapour bubbles within a liquid, the vaporization process is called boiling.

Direct conversion from solid to vapour is called sublimation.

Given,

∆G° of vaporization for benzene = 4.883 KJ/mol = 4883 J/mol

Pressure in liquid state = 1 atm

Temperature = 298 K

We know that,

                                                ∆G° = - RT ln K

Benzene (vapour) ⇔ Benzene ( Liquid)

K = pressure in liquid ÷ pressure in vapour state

                                                    K = 1 / p

Substituting this in the formula above,

                      4883 = - 8.314 × 298 × ( 1 ÷ p )

                        p = 1.97 atm

Therefore, the pressure of benzene vapor in equilibrium with benzene liquid at 298 K is 1.97 atm.

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Answer:

Explanation:

balance

2 C2H6 + 7  O2  --> 4 CO2 + 6 H2O

given 360 g H20 (g)

required =586.67 g CO2

360 g H20 x (1mole/18 g H20) X (4 mole CO2/6 moles H20) X (44g CO2/1mole) =586.67 g CO2

Answer::

Explanation::

Answer:

Before we can sketch the Lewis structures of molecules, we must first understand the octet rule. The octet rule asserts that when atoms combine to create compounds, electrons are gained, lost, or shared among them, resulting in a stable electron configuration defined by eight valence electrons as a result. These rules are used in conjunction with the main-group components of the second period.

Explanation:

Hope it helps:)

Mainly, glucose such as monosaccharide give positive Benedict's test.

In Benedict's test, the sodium carbonate converts glucose into enediol and enediol is reduces cupric into cuprous forming cuprous hydroxide.

On boiling the solution which is kept in sodium citrate give red precipitate of cuprous oxide.The chemical reaction is shown below.

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The conversion of more than one substance reactant into one or more distinct substances, products, and subsequent discussion can be characterized as follows:

Calculating the Reaction 1:

\(NaOH\ (s) \rightarrow Na^+ \ (aq) + OH^- \ (aq) + X_1\ \ KJ ......................... (1)\)

\(NaOH\) mass = \(1\ g\)

\(H_2O\) mass = \(50 \ mL = 50\ g\)

water heat of \(s_p\) = \(4.186\ \frac{ J}{ g\ ^{\circ}C}\)

\(\Delta T\) = final temp - initial temp \(= 30.3 - 25 = 5.3^{\circ} \ C\\\)

Therefore

Calculating the releasing heat

= mass × sp heat × \(\Delta T\)

= 50 × 4.186 × 5.3 J

= 1109.3 J

Calculating the \(NaOH\) mass \(= 1\ g = \frac{1}{ 40}\ mole= 0.025 \ mole\)

Calculating the releasing heat per mole:

\(\to NaOH = \frac{1109.3}{ 0.025} = 44372\ J = 44.4\ KJ\)

Thus

\(\to X_1 = 44.4\ KJ\)

Calculating the Reaction 2:

\(NaOH \ (s) + H^+\ (aq) + Cl^- \ (aq) \rightarrow Na^+ \ (aq) + Cl^- \ (aq) + H_2O + X_2 \ KJ\\\)

Calculating the net ionic from the equation:

\(NaOH\ (s) + H^+\ (aq) \rightarrow Na^+ \ (aq) + H_2O \ (l) + X_2 \ KJ ................................... (2)\)

Calculating the \(NaOH\) mass:

\(= 1\ g = \frac{1 }{ 40} = 0.025\ mole\)

Calculating the \(HCl\) mass:

\(= 50\ mL = 50\ g\) [ density = 1 approx]

sp heat of the solution \(= 4.186 \frac{J}{g\ ^{\circ}C}\) [ assume the sp heat same as water]

\(\Delta T\) = final temp - initial temp \(= 36.97 - 25 = 11.97^{\circ} \ C\)

Calculating the releasing heat:

= mass × sp heat × \(\Delta T\)

= 50 ×  4.186 ×  11.97 J

= 2505.3 J

Calculating the releasing heat per mole in \(NaOH\):

\(= \frac{ 2505.3 }{ 0.025} = 100212\ J = 100.2 KJ\)

Thus

\(X_2 = 100.2 \ KJ\)

Calculating the Reaction 3:

\(Na^+ \ (aq) + OH^-\ (aq) + H^+ \ (aq) + Cl^- \ (aq) \rightarrow Na^+\ (aq) + Cl^-\ (aq) + H_2O + X_3\ KJ\)

Calculating the net ionic in the given equation

\(H^+ + OH\rightarrow H_2O\ (l) + X_3\ KJ .............................................................. (3)\)

Calculating the volume of \(NaOH\):

\(= 25 \ mL\ of\ 1.0\ M = 25 \times \frac{1 }{ 1000} \ mole = 0.025 \ mole\)

Calculating the volume of HCl:

\(= 25 \ mL\ of\ 1.0\ M = 25 \times \frac{1 }{ 1000} \ mole = 0.025 \ mole\)

Calculating the total volume

\(= 50 \ mL = 50\ g\) { density = 1]

Calculating the sp heat in the solution

\(= 4.186 \frac{J}{ g \ ^{\circ} C}\) [ assumed the sp heat is the same as water]

\(\Delta T\) = final temp - initial temp \(= 31.7- 25 = 6.7^{\circ}\ C\)

Calculating the releasing heat

= mass  ×  sp heat  ×  \(\Delta T\)

= 50  ×  4.186  ×  6.7 J

= 1402.3 J

Calculating the releasing heat per mole in \(NaOH\):

\(=\frac{1402.3 }{ 0.025} \ J\\\\= 56092\ J\\\\= 56,09\ KJ\)

Therefore

\(X_3 = 56.09 \ KJ\\\\X_1 = 44.4\ KJ\\\\X_2 = 100.2\ KJ\\\\X_3 = 56.09\ KJ\\\\X_2 - [ X_1+ X_3 ] = 100.2 - [44.4 + 56.09]\ = 100.2 - 100.49= -0.29\)

So, the difference is equal to zero.  

\(\to X_2 = X_1 + X_3\)

This is due to the fact that if we add the reaction (1) and (3) we get the reaction (2)

Calculating the difference percentage:

\(= [\frac{0.29 }{100.2} ] \times 100 = 0.29\%\)

The number of joules released in reaction 1 would be 4 times what is released in the calculation if we used 4 g of \(NaOH\).

\(\to 4 \times 1109.3\ J = 4437.2 \ J\\\\\)

Calculating the \(NaOH\) moles \(= \frac{4}{40} = 0.1\)

\(\to X_1 = \frac{4437.2}{ 0.1} = 44372 \ J = 44.4\ KJ\)

As a result, it has no bearing on the solution's molar heat.

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Answer:the answer is hypothesis

Explanation: that’s the answer