The fundamental frequency, which is also known as the instrument's first harmonic, is the lowest pitch that every instrument can play.
Is the lowest frequency the first harmonic?The fundamental frequency is the lowest frequency that can be produced by a certain instrument.A first harmonic of a instrument is another name for the fundamental frequency.
What frequency is the first harmonic?The fundamental frequency is another name for the first harmonic.It is the frequency's lowest attainable value.Simply said, the term "first harmonic" refers to a wave that consists of simply two nodes and an antinode.
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How can the motion of two objects be described relative to each other
Answer:
Explanation:
The force on an object causes an a object to move
Dos resistencias de 30 y 20 Ω se conectan en seria a un generador que tiene una diferencia de potencial de 20 V entre sus bornes. a. Determina la resistencia equivalente de la asociación b. Dibuja el circuito y coloca un amperímetro que indique el valor de la intensidad de la corriente y unos voltímetros que muestren la diferencia de potencial entre los extremos de las resistencias ¿Qué valores muestran estos aparatos?
Answer:
V = 12V, V = 8V
Explanation:
a) In this series circuit the equivalent resistance is
Req - R1 + R2
Req = 30 + 20
Eeq = 50 Ω
b) see attached
c) the circuit current is
i = V / Req
i = 20/50
i = 0.4 A
voltages are>
V = 0.4 30
V = 12V
V = 0.4 20
V = 8V
How many cups of water should you drink in a day?
Answer:
about 2.7liters for women and 3.7liters for men
Explanation:
True or false question scientists can predict when an earthquake will occur
Answer:
False
Explanation:
Neither the USGS nor any other scientists have ever predicted a major earthquake. USGS scientists can only calculate the probability that a significant earthquake will occur in a specific area within a certain number of years.
can someone help me in that plz ??!
Answer: These forces are an example of newtons third law every action has equal and opposite reaction
Explanation:UwU
a charged particle of mass 0.0020 kg is subjected to a magnetic field which acts at a right angle to its motion. if the particle moves in a circle of radius at a speed of what is the magnitude of the charge on the particle? a) 0.0083 c b) 120 c c) 0.00040 c d) 2500 c
The magnitude of the charge on the particle of mass 0.0020 kg that is subjected to a magnetic field of 6 T which acts at a right angle to its motion is 0.0083 C ( a )
Fm = q v B
Fc = m v² / r
Fm = Magnetic force
q = Charge of the particle
v = Velocity of the particle
B = Magnetic field strength
Fc = Centripetal force
m = Mass
v = Velocity
r = Radius
m = 0.002 kg
v = 5 m / s
r = 0.2 m
B = 6 T
Since the magnetic force causes the centripetal motion,
q v B = m v² / r
q = m v / B r
q = 0.002 * 5 / 6 * 0.2
q = 0.01 / 1.2
q = 0.0083 C
Therefore, the magnitude of the charge on the particle is 0.0083 C ( a )
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The wavelengths in the hydrogen spectrum with m = 1 form a series of spectral lines called the Lyman series. Calculate the wavelengths of the first four members of the series.
the wavelengths in the hydrogen spectrum of the first four members of the series where m=1, the first four members have the wavelength of \(1.464 * 10^7 m,\) \(1.231 * 10^7 m,\) \(1.164 * 10^7 m,\) and \(1.097 * 10^7 m.\)
The wavelengths of the spectral lines in the Lyman series of the hydrogen spectrum can be calculated using the Rydberg formula:
1/λ = \(R * (1/n1^2 - 1/n2^2)\)
Where λ is the wavelength of the spectral line, R is the Rydberg constant (approximately \(1.097 * 10^7 m^-^1)\), and n1 and n2 are positive integers representing the energy levels of the electron in the hydrogen atom.
For the Lyman series, we have m = 1, which means the electron transitions from higher energy levels (n2) to the first energy level (n1 = 1).
Let's calculate the wavelengths for the first four members of the Lyman series:
For n2 = 2:
1/λ = \(R * (1/1^2 - 1/2^2)\)
1/λ = \(R * (1 - 1/4)\)
1/λ = \(R * (3/4)\)
λ = \(4/3R\)
Substituting the value of the Rydberg constant:
λ = \((4/3) * (1.097 × 10^7 m^-^1)\)
λ ≈ \(1.464 * 10^7 m\)
For n2 = 3:
1/λ = \(R * (1/1^2 - 1/3^2)\)
1/λ = \(R * (1 - 1/9)\)
1/λ = \(R * (8/9)\)
λ = \(9/8R\)
Substituting the value of the Rydberg constant:
λ = \((9/8) * (1.097 * 10^7 m^-1)\)
λ ≈ \(1.231 * 10^7 m\)
For n2 = 4:
1/λ = \(R * (1/1^2 - 1/4^2)\)
1/λ = \(R * (1 - 1/16)\)
1/λ = \(R * (15/16)\)
λ = \(16/15R\)
Substituting the value of the Rydberg constant:
λ = \((16/15) * (1.097 * 10^7 m^-^1)\)
λ ≈ \(1.164 * 10^7 m\)
For n2 = 5:
1/λ = \(R * (1/1^2 - 1/5^2)\)
1/λ = \(R * (1 - 1/25)\)
1/λ = \(R * (24/25)\)
λ = \(25/24R\)
Substituting the value of the Rydberg constant:
λ = \((25/24) * (1.097 * 10^7 m^-^1)\)
λ ≈ \(1.097 * 10^7 m\)
Therefore, the wavelengths of the first four members of the Lyman series are approximately:
\(1.464 * 10^7 m,\)
\(1.231 * 10^7 m,\)
\(1.164 * 10^7 m,\)
and \(1.097 * 10^7 m.\)
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The record number of boat lifts, including the boat and its ten crew members, was achieved by Sami Heinonen and Juha Räsänen of Sweden in 2000 . They lifted a total mass of 653.2 kg approximately 4 in. off the ground a total of 24 times. Estimate the total work done by the two men on the boat in this record lift, ignoring the negative work done by the men when they lowered the boat back to the ground.
The estimated total work done by Sami Heinonen and Juha Räsänen on the boat in this record lift is approximately 1292.17 Joules.To estimate the total work done by Sami Heinonen and Juha Räsänen on the boat in this record lift, we can use the formula:
Work = Force × Distance
First, let's find the force. The total mass lifted is 653.2 kg, and we need to account for the boat and its ten crew members. So, the mass lifted by each person is 653.2 kg ÷ 12 = 54.43 kg (rounded to two decimal places).
The force exerted by each person can be found using the formula:
Force = mass × gravity
Assuming the acceleration due to gravity is approximately 9.8 m/s², the force exerted by each person is:
Force = 54.43 kg × 9.8 m/s² = 533.83 N (rounded to two decimal places).
Now, let's calculate the distance lifted. The boat was lifted approximately 4 inches off the ground, which is approximately 0.1016 meters.
To find the total work done by the two men, we need to multiply the force exerted by each person by the distance lifted, and then multiply that by the number of lifts:
Work = (Force × Distance) × Number of lifts
= (533.83 N × 0.1016 m) × 24
= 1292.17 Joules (rounded to two decimal places).
Therefore, the estimated total work done by Sami Heinonen and Juha Räsänen on the boat in this record lift is approximately 1292.17 Joules.
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an embedded deicing unit of the resistance type shall not exceed ? of heated area.
According to the National Electric Code (NEC) section 426.20(A), an embedded deicing unit of the resistance type shall not exceed 120 watts/ft2 of the heated area.
This limits the amount of power that an embedded deicing unit of the resistance type can use to melt snow and ice on a surface. This ensures that the unit does not overheat or create a fire hazard.
It's important to note that this limit applies to the total power used by the embedded deicing unit and not just the heating element. Other factors like the type of material, the environment, and the design can also affect the performance and safety of the deicing unit.
It's recommended to consult with local code officials or a licensed professional to determine the specific requirements and limitations that apply to your project.
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Lora (of mass 54 kg) is an expert skier. She
starts at 2.6 m/s at the top of the lynx run,
which is 51 m above the bottom.
What is her final kinetic energy at the bottom of the ski run?
The mechanical energy at top =Mechanical energy at bottom
Mass=m=54kgHeight=h=51mAcceleration due to gravity=g=10m/s^2Velocity=v=2.6m/s\(\\ \tt\longmapsto M_{initial}=M_{Final}\)
Final energy at bottom=The kinetic energy\(\\ \tt\longmapsto KE=M_{initial}\)
\(\\ \tt\longmapsto KE=P.E_{(Top)}+K.E_{(Top)}\)
\(\\ \tt\longmapsto K.E=mgh+\dfrac{1}{2}mv^2\)
\(\\ \tt\longmapsto K.E=m\left(gh+\dfrac{v^2}{2}\right)\)
\(\\ \tt\longmapsto K.E=54\left((10)(51)+\dfrac{2.6^2}{2}\right)\)
\(\\ \tt\longmapsto K.E=54\left(510+\dfrac{6.76}{2}\right)\)
\(\\ \tt\longmapsto K .E=54(510+3.38)\)
\(\\ \tt\longmapsto K.E=54(513.38)\)
\(\\ \tt\longmapsto K.E=27722.52J\)
\(\\ \tt\longmapsto K.E=27.7KJ\)
a ball of mass 100g falls from a height of 5m and rebounds to a height of 3m . calculate the energy lost . (g=10ms-2)
Explanation:
use the explanation above
Hope it's clear
The coldest clouds in the ISM are molecular clouds, so named because their temperatures are low enough and their densities high enough for atoms to join together into molecules. These clouds are capable of collapsing to form new stars, in a stellar nursery like the one in the left image. The Pleiades (right image) is an example of stars that formed recently within such a nursery.
Molecular clouds range in mass from a few times the mass of our Sun (solar masses) to 10 million solar masses. Individual stars range from 0.08 to about 150 solar masses.
What does all of this imply about how stars form from molecular clouds?
Stars form from molecular clouds through a process known as stellar formation.
These clouds, characterized by low temperatures and high densities, provide the ideal conditions for atoms to combine and form molecules. With a mass range spanning from a few solar masses to millions of solar masses, molecular clouds serve as the birthplaces of new stars. The Pleiades cluster serves as a notable example of stars that have recently formed within such a stellar nursery.
The formation of stars from molecular clouds involves several key steps. Firstly, gravitational forces acting on regions of higher density within the cloud cause them to collapse under their own gravity. As the cloud collapses, it begins to fragment into smaller, denser clumps called protostellar cores. These cores continue to collapse, and their central regions become increasingly dense and hot. At this stage, they are known as protostars.
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A rocket weighing 560,000 N is taking off from Earth with a total thrust of
700,000 N at an angle of 20 degrees, as shown in the image below. What is
the approximate vertical component of the net force that is moving the rocket
away from Earth?
A. 76,000 N
B. 112,000 N
C. 132,000 N
D. 98,000 N
Answer:
D
Explanation:
LA FUERZA NETA ES LA FUERZA TOTAL DE EMPUJE MENOS EL PESO DEL
COHETE.
\(F_{y}\) = 700000 N(sen 90° - 20°) - 560000 N = 97785 N
The approximate vertical component of the net force that is propelling the rocket away from Earth is 112,000 N. Option B is correct.
The net force acting on the rocket is the sum of the thrust force and the weight of the rocket. The thrust force is pointing upwards at an angle of 20 degrees, and the weight of the rocket is pointing downwards. The thrust force is the force that is generated by the rocket engine. It is the force that propels the rocket upwards.
The weight of the rocket is the force of gravity acting on the rocket. It is the force that pulls the rocket downwards. The net force acting on the rocket is the sum of the thrust force and the weight of the rocket. If the net force is positive, the rocket will accelerate upwards. If the net force is negative, the rocket will accelerate downwards. If the net force is zero, the rocket will remain at rest.
net force = thrust force + weight
vertical component of net force = thrust force * cos(angle)
vertical component of net force = 700,000 N * cos(20 degrees) = 112,000 N. Option B is correct.
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Why is it easier to cut meat with a sharp knife than with a blunt knife
Answer:
because the knife is sharp
Answer:
Pressure is inversely proportional to the area of the surface. While a blunt knife has more area coming in contact than a sharp knife and the pressure exerted by the blunt knife will be less as compared to that of a sharp knife. Therefore it is easier to cut with a sharp knife.
Explanation:
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A person weighing 645 N climbs up a ladder to a height of 4.55 m. What is the
increase in gravitational potential energy?
Answer:
P.E = 2934.75
Explanation:
Potential energy can be defined as an energy possessed by an object or body due to its position.
Mathematically, potential energy is given by the formula;
\( P.E = mgh\)
Where, P.E represents potential energy measured in Joules.
m represents the mass of an object.
g represents acceleration due to gravity measured in meters per seconds square.
h represents the height measured in meters.
Given the following data;
Weight =645
Height = 4.55
\( P.E = mgh\)
But we know that weight = mg = 645N
Substituting into the equation, we have;
\( P.E = 645 * 4.55 \)
\( P.E = 2934.75 J\)
Potential energy, P.E = 2934.75 Joules.
Ms. Howard's science class looked at the group of stars called the Big Dipper, They watched it in the early evening during fall and spring. This is what
they saw:
Fall- upright and low in the sky
Spring - upside down and high in sky
Why does the position of the Big Dipper change during the year?
O A Earth revolves around the Sun,
OB. The position of the Moon is different in the fall than in the spring.
O C. The Big Dipper is made of different stars in the fall than in the spring.
OD. The Big Dipper moves toward Earth in the fall and away in the spring.
You are gardening in the peak of summer, it hasn't rained in a week, and your plants are looking rough. You decide to water the plants for an hour. The next day you come back to the garden, and the plants look in worse shape than they did previously, as if none of that water made it to the plant. With what you know from class, please try and explain what is happening to your plants.
In the peak of summer, it hasn't rained in a week, and the plants are looking rough, so watering the plants for an hour is a good idea.
However, the next day, you come back to the garden, and the plants look in worse shape than they did previously, as if none of that water made it to the plant. Plants absorb water through their roots. The root system of a plant is responsible for drawing water and nutrients from the soil. A plant's root system must be able to absorb water quickly in order for the plant to grow and thrive. When the soil around the root system is dry, the roots will stop growing and will not be able to absorb water.
It may even start to die. Watering plants during the peak of summer is important because it will help keep the soil moist and prevent the roots from drying out. However, watering a plant too much can be harmful. If a plant is overwatered, the water may not be able to penetrate the soil and reach the roots. Instead, it may just sit on top of the soil, causing the roots to rot and die. This can cause the plant to wilt and die.To summarize, if the soil around the plant is too dry, the roots may not be able to absorb the water you gave them, causing the plant to look worse than before. Conversely, overwatering can also be harmful because the water may not be able to penetrate the soil and reach the roots, causing the roots to rot and die.
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Can someone please help me with this project??? (Due tmrw afternoon)
Waves are periodic disturbances through a medium. How fast a wave can move through a medium only depends on a couple of things. One thing that determines the speed of a wave, is what type of wave it is. Sound travels at 340 m/sec in air, while light travels at nearly 3x108 m/sec in air. This experiment is going to look at what other factors determine the speed of a wave in a medium. To determine the speed of a wave pulse, record the time it takes for a pulse to travel then length to the clamp and back. Use the ruler to determine the distance between the pulse generator and the clamp, then double that for the total distance. If we can assume the wave travels at a constant speed, then v = d/t (total)
The assignment:
Part I: Amplitude versus Wave Speed
To determine the relationship between amplitude and wave speed, change the amplitude of the pulse and measure the speed of the wave.
Amplitude Distance Time Average Speed
1.
2.
3.
4.
5.
6.
Part II: Period versus Wave Speed
To determine the relationship between period and wave speed, change the pulse width and measure the speed of the wave. In this simulation, the pulse width is measured in seconds, which is the period of the pulse generator.
Pulse Width Distance Time Average Speed
1.
2.
3.
4.
5.
6.
Part III: Tension versus Wave Speed
To determine the relationship between tension in the chain and wave speed, change the tension and measure the speed of the wave. This time there is not numerical value for the tension so you will just use approximate descriptions.
Tension Distance Time Average Speed
High
Mid-point
Low
Questions
1. From your data, what factor(s) affect the speed of a wave? Explain your reasoning.
2. The pitch made by a musical instrument is dependent on the frequency of the wave. Frequency is the inverse of period. What impact do you think the frequency of a wave has on the wave speed?
3. What happens to wave speed as it moves from a medium of low density to one of high density? Explain your response with respect to this lab.
4. When a stringed instrument is out of tune, the player with tighten or loosen the string. If the instrument is initially flat, should they tighten or loosen the string? In the context of this experiment, explain your reasoning.
1. The data shows that amplitude, period, and tension all affect the speed of a wave. As amplitude and tension increase, the speed of the wave increases, while an increase in period results in a decrease in speed.
What is an amplitude?
Amplitude is the maximum displacement or distance moved by a wave from its resting position. In other words, it is the magnitude of the oscillation in a wave, or the height of a wave from its equilibrium position. In general, the greater the amplitude of a wave, the more energy it carries. In the context of sound waves, amplitude is associated with the loudness of the sound, while in the context of electromagnetic waves (such as light), it is associated with the brightness or intensity of the light.
2. The frequency of a wave has a direct relationship with the wave speed. As the frequency of a wave increases, the speed of the wave also increases.
3. Wave speed decreases as it moves from a medium of low density to one of high density. This is because a denser medium causes more resistance to the wave, resulting in a slower wave speed.
4. If the instrument is initially flat, the player should tighten the string. This is because tightening the string increases the tension, which in turn increases the speed of the wave, resulting in a higher pitch.
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A car's bumper is designed to withstand a 5.04-km/h (1.4-m/s) collision with an immovable object without damage to the body of the car. The bumper cushions the shock by absorbing the force over a distance. Calculate the magnitude of the average force on a bumper that collapses 0.255 m while bringing a 890-kg car to rest from an initial speed of 1.4 m/s.
Answer:
3420.39 N
Explanation:
Applying,
Fd = 1/2(mv²-mu²)................. Equation 1
Where F = force on the bumber, d = distance, m = mass of the car, v = final velocity, u = initial velocity.
make F the subject of the equation
F = (mv²-mu²)/2d............... Equation 2
From the question,
Given: m = 890 kg, v = 0 m/s (to rest), u = 1.4 m/s, d = 0.255 m
Substitute these values into equation 2
F = [(890×0²)-(890×1.4²)]/(2×0.255)
F = -1744.4/0.51
F = -3420.39 N
The negative sign denotes that the force in opposite direction to the motion of the car.
the higher an object is raised compared to the ground
The higher an object is raised compared to the ground, the greater its gravitational potential energy.
Gravitational potential energy is the energy possessed by an object due to its position in a gravitational field. It is directly related to the height or elevation of the object above a reference point, such as the ground. The higher the object is raised, the farther it is from the source of gravity (typically the Earth), and thus the greater its potential energy.
The increase in gravitational potential energy occurs because when an object is raised, work is done against the force of gravity. Energy is transferred to the object, increasing its potential energy. This energy can be converted into other forms, such as kinetic energy when the object falls back to a lower position.
The relationship between gravitational potential energy (PE), mass (m), acceleration due to gravity (g), and height (h) can be expressed by the equation:
PE = m * g * h
Where "m" is the mass of the object, "g" is the acceleration due to gravity (approximately 9.8 m/s² on Earth), and "h" is the height or elevation above the reference point.
Therefore, the higher an object is raised compared to the ground, the greater its gravitational potential energy, indicating an increase in the potential for doing work or being converted into other forms of energy.
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Complete Question:
The higher an object is raised compared to the ground, the greater its ___________.
larger gases diffuse and effuse slower. true or false.also describe the difference between diffusion and effusion
The rate of effusion depends on the molecular weight of the gas, with lighter gases effusing more rapidly than heavier gases
False. Larger gases diffuse and effuse slower than smaller gases. This is because the rate of diffusion and effusion depends on the molecular weight of the gas. Smaller molecules have a higher velocity than larger molecules due to their lower mass, which allows them to move more quickly and diffuse and effuse more rapidly.
Diffusion refers to the process by which gas molecules move from an area of high concentration to an area of low concentration. This process occurs spontaneously due to the random motion of the gas molecules. Diffusion is responsible for the mixing of gases and is a key factor in many chemical reactions.
Effusion, on the other hand, refers to the process by which gas molecules escape from a container through a small hole or opening. This occurs because the gas molecules are in constant motion and collide with the walls of the container. If there is a small opening, some of the gas molecules will escape through it, leading to a decrease in pressure inside the container. The rate of effusion depends on the molecular weight of the gas, with lighter gases effusing more rapidly than heavier gases.
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A spring with a spring constant of 245 N/m is attached to a 1. 5 kg mass and then set in motion. What is the period of the mass-spring system?
Answer in units of s and round to two decimal place
The period of the mass-spring system is 0.39 seconds.
It is given that a spring with a spring constant of 245 N/m is attached to a 1. 5 kg mass and then set in motion. To calculate the period of the mass-spring system, you can use the formula:
T = 2π√(m/k)
where T is the period, m is the mass, and k is the spring constant.
Given the mass (m) as 1.5 kg and the spring constant (k) as 245 N/m, plug in these values:
T = 2π√(1.5 kg / 245 N/m)
T ≈ 0.39 s
So, the period of the mass-spring system is approximately 0.39 seconds when rounded to two decimal places.
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the distance to the north star, polaris, is approximately 6.44 1018 m. (a) if polaris were to burn out today, how many years from now would we see it disappear?
2,042.1 years time from now will we see it disappear.
d = 6.44. 3.10¹⁸ m,
v = 3.10⁸ m/s,
t = 6.44.3. 10¹⁸ / 3. 10⁸ s = 6.44 . 10¹⁰ sec.
Converting seconds to years:
6.44. 10¹⁰ sec . (1min/60 sec).(1h/60 min). (1d/24h)(1y/365d) = 2,042.1 years.
Physicists define time as the progression of events from the past through the present, and into the future. If a system doesn't change, it is effectively timeless. When describing events that take place in three-dimensional space, time may be seen as the fourth dimension of reality. We are unable to see, touch, or taste time, yet we can compute how much time has passed.
Everywhere in classical mechanics, time is constant. The timekeeping systems are still in sync. But as Einstein's special and general theories of relativity show, time is relative. It depends on the observer's perspective of view. The theory of time dilation states that when one approaches the speed of light, the intervals between events grow longer (dilates).
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7
What was the dependant variable? * is it 1,2 or 3?
(1 Point)
1. Type and weight of the block
2. increase in energy transferred
3. Thermometer used
Answer:
Increase is energy transferred
Explanation:
Increase in energy or ∆E depends upon the mass or type of the blockIt also depends upon the surface area etc The thermometer used is useless in this case .Option B is correct
A 80 N horizontal force is applied to a 20.0 kg block at rest on a horizontal surface where µS = 0.6.? What is the magnitude of the force of friction on the block?
Answer:
The frictional force on the block is 118 N.
Explanation:
Given;
horizontal force applied on the block, f = 80 N
mass of the block, m = 20.0 kg
coefficient of friction, μ = 0.6
The frictional force on the block is calculated as;
F = μR
F = μ(mg)
F = 0.6(20 x 9.81)
F = 117.7 N
F = 118 N.
Therefore, the frictional force on the block is 118 N.
find the magnitude of force f2, such that the resultant moment about point c due to both forces is zero, given: f1 = 300 n, l1 = 3 m, l2 = 7 m, θ = 35°, x,y,h = 12,5,13, respectively
The magnitude of force F₂ required for the resultant moment about point C to be zero is approximately 643.92 N.
Determine the magnitude of force?To find the magnitude of force F₂, we need to balance the moments created by both forces. The moment of a force is given by the equation:
M = F * d * sin(θ),
where M is the moment, F is the force, d is the perpendicular distance from the point of rotation to the line of action of the force, and θ is the angle between the force and the line connecting the point of rotation to the force.
Given:
F₁ = 300 N,
l₁ = 3 m,
l₂ = 7 m,
θ = 35°.
First, we calculate the moment created by force F₁ about point C:
M₁ = F₁ * l₁ * sin(θ).
To balance the moments, we need a force F₂ with a moment equal in magnitude but opposite in direction:
M₂ = -M₁.
Substituting the values and solving for F₂:
F₂ * l₂ * sin(θ) = -F₁ * l₁ * sin(θ),
F₂ = -F₁ * l₁ / l₂,
F₂ = -(300 N * 3 m) / 7 m,
F₂ ≈ -128.57 N.
Since the magnitude of the force is required, we take the absolute value:
|F₂| ≈ 128.57 N.
Therefore, the magnitude of force F₂ required for the resultant moment about point C to be zero is approximately 128.57 N.
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HELP PLZZZZZZZZ
3. Which of these does not have potential energy?
a. A book resting on the floor
b. A roller coaster at its maximum height
c. A bird flying in the sky
d. A basketball shot in the air
Answer:
a. A book resting on the floor
Explanation:
Potential energy is the energy stored in a object due to its position relative to some zero position. An object possesses gravitational potential energy if it is positioned at a height above/below the zero height.
A race car travelling with an initial velocity of 90 km/h accelerates at a uniform
rate of 5.0 m/s2 for 2.0 s. What is the final velocity of the race car in m/s?
The final velocity of the race car in m/s calculated with the help Newton's first equation of motion is 35 m/s.
What is Newton's first equation of motion?
The first equation of motion given by Newton is v = u + at. This equation is also referred as the velocity-time relation.
According to Newton's first equation of motion,
v = u + at
where, v = final velocity, u = initial velocity, a = acceleration, t = time taken.
As given in question,
u = 90 km/h = 90 km/h / 3.6 = 25 m/s,
a = 5 m/s^2,
t = 2 seconds,
So, putting the values given in question the the Newton's first equation of motion.
v = u + at
v = 25+(5x2)
v = 25+10
v = 35 m/s
Hence, the final velocity is 35 m/s.
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In which of the following is a skater NOT accelerating?
A-going straight while speeding up
B-going straight at constant speed
C-making circles at constant speed
D-going straight while slowing down
The tip of second's hand of a clock take 60 seconds to to move once on the circular dial of the clock. If the radius of the dial of the clock be 10.5 cm, calculate the speed of the tip of the second's hand of the clock.
Answer:
( About ) 1.1 cm / s
Explanation:
We know that the time it takes the clock's second hand to move is 60 seconds. Respectively the radius of this clock is given to be 10.5 centimeters.
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Let us apply the formula speed = distance traveled / time. Here the " distance traveled " is the circumference of the clock, or 2πr - where we can pose π as 3.14. In other words, Speed = 2πr / time. Substitute known values to solve for the Speed,
S = 2 * 3.14 * 10.5 / 60,
Speed = ( About ) 1.1 cm / s
Hope that helps!