what skills and knowledge do you want to gain from electrical electronic engineering ? 1200 words
Answers
Details about the common knowledge and skills electrical and electronic engineering students look for.
Electrical and electronic engineers must possess a thorough understanding of circuit analysis and design. This includes understanding the interactions between various circuit components, such as resistors, capacitors, and inductors. Along with it, it entails knowing how to analyze and create electrical circuits using circuit theorems like Kirchhoff's, Ohm's, and Thevenin's laws.
Engineers who work with semiconductors, diodes, transistors, amplifiers, and other electronic components are required to have a strong foundation in electronics. Additionally, they must to be knowledgeable with many kinds of electrical circuits, including power supply, voltage regulators, and oscillators.
Electrical and electronic engineers require a strong background in electronics, including knowledge of semiconductors, diodes, transistors, and amplifiers. They should also be knowledgeable with other electronic circuit types, including power supplies, voltage regulators, and oscillators.
Electrical and electronic engineers need to be well-versed in digital systems, which include digital logic, binary integers, and Boolean algebra. They should also be knowledgeable with the various components of digital circuits, including gates, flip-flops, and multiplexers, and how to employ them when designing digital circuits.
Signals and Systems: Electrical and electronic engineers should be familiar with signals and systems since it helps them to comprehend how signals behave and how they can be processed. Understanding different signal kinds is part of this.
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Related Questions
A Maxwell-type element is constructed of the usual viscous dashpot but with an ‘ideal rubber’band in place of the usual Hookean spring. In a creep experiment with a constant load of 1,000pa, and at a temperature of 27oC, the total deformation in tensile strain units after 3 h is ε=2.00. When the load is removed (at 3 h), the resulting permanent set is 0.750 unit. Now the same element (with no starting deformation) is made to undergo stress relaxation at 127oC, with a fixed elongation of 1.5 strain units. What is the stress at time zero in the stress relaxation experiment?
Answers
The stress at time zero in the stress relaxation experiment is 1,000 pa.
What are Maxwell-type elements?
Maxwell-type elements are viscoelastic models that consist of a dashpot and a spring connected in series. The dashpot represents the viscous component of the material and the spring represents the elastic component. The Maxwell model is commonly used to describe the behavior of materials that exhibit both viscous and elastic properties, such as polymers and biological tissues.
For the creep experiment, we know that the total deformation in tensile strain units after 3 hours is ε=2.00, and the resulting permanent set is 0.750 unit. We can use the following equation to calculate the viscosity of the dashpot:
η = ε / σ
where η is the viscosity, ε is the strain, and σ is the stress. Rearranging this equation, we get:
σ = ε / η
We know that the load is constant at 1,000 pa, so the stress is also 1,000 pa. Therefore, we can plug in the values we have and solve for the viscosity:
1,000 = 2.00 / η
η = 0.002 Pa s
Now we can use the following equation to calculate the stress at time zero in the stress relaxation experiment:
σ = σ0 * e^(-t/τ)
where σ0 is the initial stress, t is the time, and τ is the relaxation time. We know that the fixed elongation is 1.5 strain units, so we can use the following equation to calculate the relaxation time:
τ = η / E
where E is the elastic modulus of the ideal rubber band. Since we don't know the value of E, we can't solve for τ. However, we do know that the element is undergoing stress relaxation at 127oC, which is well above room temperature. At this temperature, we can assume that the rubber band behaves as a purely viscous material, meaning that its elastic modulus is effectively zero. Therefore, we can assume that τ is very large (approaching infinity), and the stress at time zero is equal to the initial stress:
σ0 = σ = 1,000 pa
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different lever designs can be engineered to alter the brake pedal effort required of the driver by using different levels of ?
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Different lever designs can be engineered and developed to alter the brake pedal effort required of the driver by using different levels of mechanical advantage.
What is mechanical advantage?Mechanical advantage can be defined as a ratio of the output force of a lever to the force acting on it (input force or effort), assuming no losses due to wear, flexibility, tear or friction.
This ultimately implies that, different lever designs can be suitably engineered and developed to alter the brake pedal effort (input force) that is required of the driver, especially by using different levels of mechanical advantage.
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12. The new spark plug shown in the photograph above has been fouled. Which of the following is the most likely
cause?
esc
Answers
Answer:
Stuck open injector is the correct answer to this question.
Explanation:
The wet spark plug is the product of the injector stuck open. It can be observed in the exhaust system by the scent of petrol. It needs to be fixed quickly or the catalytic converter might be harmed.Another explanation may be that the engine is overloaded when you try to start the engine multiple times without firing it up. It happens frequently in winters.The signs of a fuel injector that is stuck-open or incompletely closed are very different from an injection system that is fully dead or moderately blocked up.Throughout this case, a scent of unburned fuel can be present in the passenger compartment, emanating through both the pipes, or out of the gas tank.
Technician A says that a standard grade 5 bolt is stronger than a standard grade 8 bolt. Technician B says that a metric grade 12.9 bolt is stronger than a metric grade 4.6 bolt. Who is correct?
Answers
Since Tech B says that a metric grade 12.9 bolt is stronger than a metric 4.6 bolt. the person that is correct is option b. Tech B.
What grade is a 12.9 bolt?The grade of 12.9 bolt is known to be 1220 (176,000 psi). The alloy carbon steel is said to be one that is often used to make Metric 12.9 Hex Cap Screws that is heat-treated, quenched, as well as tempered.
Their strength is one that is comparable to alloy sockets, and with a proof load of 970 MPa and a minimum tensile strength of 1220 MPa.
Therefore, Since Tech B says that a metric grade 12.9 bolt is stronger than a metric 4.6 bolt. the person that is correct is option b. Tech B.
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See full question below
Tech A says that a standard grade 5 bolt is stronger than a standard grade 8 bolt. Tech B says that a metric grade 12.9 bolt is stronger than a metric 4.6 bolt. Who is correct?
a. Tech A
b. Tech B
c. both
d. neither
FAULT LOCATION METHODS(input-output)
Answers
Fault location techniques are used in power systems for accurate pinpointing of the fault position.
This paper presents a comparative study between two fault location methods in distribution network with Distributed Generation (DG). Both methods are based on computing the impedance using fundamental voltage and current signals. The first method uses one-end information and the second uses both ends
to set pd2 as input the value of DDRD must be
Answers
To set PD2 as input the value of DDRD must be = 0x00. Note that DDRD is the direction register for Port D.
What is port D?
Port D is a bidirectional 8-bit I/O port with inbuilt pull-ups. The orientation of this pin is determined by the DDDn bit in the DDRD register; if DDDn is set (one), PDn is configured as an output pin. If DDDn is set to zero, PDn is set to be an input pin.
DDR makes use of the clock signal's falling and rising edges. The distinction from SDRAM and DDR is not one of speed, but rather of the number of times data is sent with each cycle. DDR transports data twice every clock cycle, whereas SDRAM sends signals only once. Both employ the same frequency.
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explain the difference in the importance of drafts in green-sand casting versus permanent-mold casting.
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In green-sand casting, drafts are essential because they provide a gradual slope in the molds that allows the casting to be released easily.
Drafts are not as important in permanent-mold casting because the mold is generally made of metal and can be more easily broken apart. Drafts can still be used in permanent-mold casting, but they are not as necessary.
Greensand is a mixture of quartz sand, water and bentonite. The sample product used is a 90o elbow measuring 0.5 inches with white cast iron material. The surface roughness was observed by visual observation of the casting results of the two green sand mold compositions.
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two technicians are describing how an air-conditioning system gets rid of the heat. Technician A says that heat always flows from the hotter to the colder object. Technician B says that as refrigerant evaporates, it absorbs heat as it changes from a liquid to a gas. which technician is correct?
Answers
Based on the information provided by these technicians, both of them are correct.
How does heat flow?According to heating, ventilation, and air conditioning (HVAC), heat in an air-conditioning system generally flows from the hotter object to the colder object.
As the refrigerant evaporates in a small radiator-type unit (evaporator), it absorbs heat as it changes phase from liquid to gas. Also, as the heat is being absorbed by the refrigerant, the small radiator-type unit (evaporator) becomes cold.
In conclusion, we can logically deduce that both of them are correct.
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3. Which of the following microstructures is the result of a diffusionless transformation? (a) (b) (c) (d) Martensite Bainite Tempered martensite Spheroidite 4. A steel contains 80% martensite and 20% ferrite at room temperature: (b) The steel is hypoeutectic and was slowly cooled to room temperature The steel is hypereutectic and was quickly cooled to room temperature The steel is hypereutectic and was slowly cooled to room temperature The steel is hypoeutectic and was quickly cooled to room temperature (d)
Answers
3. The following microstructures is the result of a diffusionless transformation: Martensite. The correct option is (a)
Martensite is a microstructure that is formed through a diffusionless transformation, meaning that it occurs without the diffusion of atoms. It is characterized by a highly distorted and supersaturated crystal structure.
4. A steel contains 80% martensite and 20% ferrite at room temperature: The steel is hypoeutectic and was quickly cooled to room temperature. The correct option is (d).
The given steel contains 80% martensite and 20% ferrite at room temperature. Martensite formation typically occurs when steel is rapidly cooled (quenched) from a high temperature to room temperature. This rapid cooling prevents sufficient diffusion of carbon atoms, resulting in the formation of martensite.
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The complete question might be:
3. Which of the following microstructures is the result of a diffusionless transformation?
(a) Martensite
(b) Bainite
(c) Tempered martensite
(d)Spheroidite
4. A steel contains 80% martensite and 20% ferrite at room temperature: (a) The steel is hypoeutectic and was slowly cooled to room temperature (b) The steel is hypereutectic and was quickly cooled to room temperature
(c) The steel is hypereutectic and was slowly cooled to room temperature (d) The steel is hypoeutectic and was quickly cooled to room temperature
How would you describe good communication? Why and when do we need it?
Answers
suppose we have tables students(name, major), taking(studentname, coursename), courses(name, dept), covers(coursename, topicname), topics(name, description), and likes(studentname, topicname). then this query is monotonic: find all students who are taking chem 101 and like at least two topics covered in that course. suppose we have tables students(name, major), taking(studentname, coursename), courses(name, dept), covers(coursename, topicname), topics(name, description), and likes(studentname, topicname). then this query is monotonic: find all students who are taking chem 101 and like at least two topics covered in that course. true false
Answers
The given query "find all students who are taking chem 101 and like at least two topics covered in that course" is not monotonic.
Monotonicity in database queries refers to the property that if a certain condition holds for a subset of the data, then it should also hold for any superset of that data. In other words, if we add more data to the tables, the query should still return the same or more results.
In the given query, the condition "like at least two topics covered in that course" introduces a non-monotonic condition. Adding more data to the tables may change the number of topics covered in the course, and therefore the result of the query may change. Hence, the query is not monotonic.
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The water in a tank is pressurized by air and the pressure is measured by a multifluid manometer. Determine the gage pressure of air in the tank id h1=.2m, h2=.3m and h3=.4m. Take the densities of water, oil, and mercury to be 1000kg/m^3, and 13,600 kg/m^3 respectively.
Answers
To determine the gauge pressure of air in the tank using the multifluid manometer, we need to consider the pressure difference between the air and the liquid columns in the manometer.
The gauge pressure can be calculated using the equation:
ΔP = ρgh
Where:
ΔP is the pressure difference
ρ is the density of the fluid
g is the acceleration due to gravity
h is the height of the fluid column
In this case, we have three different heights, h1 = 0.2 m, h2 = 0.3 m, and h3 = 0.4 m, representing the heights of the water, oil, and mercury columns, respectively.
First, we need to calculate the pressure difference between the air and water column:
ΔP1 = ρwater * g * h1
Next, we calculate the pressure difference between the oil and water columns:
ΔP2 = ρoil * g * h2
Finally, we calculate the pressure difference between the mercury and oil columns:
ΔP3 = ρmercury * g * h3
To obtain the gauge pressure of air in the tank, we sum up all the pressure differences:
Gauge pressure = ΔP1 + ΔP2 + ΔP3
Substituting the given values of densities and heights, and using the acceleration due to gravity (g = 9.8 m/s^2), we can calculate the gauge pressure of air in the tank.
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In which model of the system, the change in order is generated depending on the system activities. *
Static Model
Dynamic Model
Analytical Model
Numerical Model
Answers
Answer:
Static Model
Explanation:
Discuss on forced convection heat transfer with real examples.
Answers
Answer:
forced convection
Explanation:
When a fan, pump or suction device is used to facilitate convection, the result is forced convection. Everyday examples of this can be seen with air conditioning, central heating, a car radiator using fluid, or a convection oven.
A horizontal force P is applied to a 130 kN box resting on a 33 incline. The line of action of P passes through the center of gravity of the box. The box is 5m wide x 5m tall, and the coefficient of static friction between the box and the surface is u=0.15. Determine the smallest magnitude of the force P that will cause the box to slip or tip first. Specify what will happen first, slipping or tipping.
Answers
Answer:
SECTION LEARNING OBJECTIVES
By the end of this section, you will be able to do the following:
Distinguish between static friction and kinetic friction
Solve problems involving inclined planes
Section Key Terms
kinetic friction static friction
Static Friction and Kinetic Friction
Recall from the previous chapter that friction is a force that opposes motion, and is around us all the time. Friction allows us to move, which you have discovered if you have ever tried to walk on ice.
There are different types of friction—kinetic and static. Kinetic friction acts on an object in motion, while static friction acts on an object or system at rest. The maximum static friction is usually greater than the kinetic friction between the objects.
Imagine, for example, trying to slide a heavy crate across a concrete floor. You may push harder and harder on the crate and not move it at all. This means that the static friction responds to what you do—it increases to be equal to and in the opposite direction of your push. But if you finally push hard enough, the crate seems to slip suddenly and starts to move. Once in motion, it is easier to keep it in motion than it was to get it started because the kinetic friction force is less than the static friction force. If you were to add mass to the crate, (for example, by placing a box on top of it) you would need to push even harder to get it started and also to keep it moving. If, on the other hand, you oiled the concrete you would find it easier to get the crate started and keep it going.
Figure 5.33 shows how friction occurs at the interface between two objects. Magnifying these surfaces shows that they are rough on the microscopic level. So when you push to get an object moving (in this case, a crate), you must raise the object until it can skip along with just the tips of the surface hitting, break off the points, or do both. The harder the surfaces are pushed together (such as if another box is placed on the crate), the more force is needed to move them.
Members AB and BC of the truss shown are made of the same alloy. It is known that a 20-mm-square bar of the same alloy was tested to failure and that an ultimate load of 120 kN was recorded. If a factor of safety of 3.2 is to be achieved for both bars, determine the required cross-sectional area of (a) bar 1.4m AB, (b) bar AC.
Answers
The required cross-sectional area of both bars AB and AC is 125000 mm^2.
How did we get the value?To determine the required cross-sectional area of bars AB and AC, we need to calculate the maximum load that each bar can withstand with a factor of safety of 3.2, and then use the maximum load to calculate the cross-sectional area.
First, let's consider bar AB. We can analyze the forces acting on the truss to find the maximum load on bar AB. Since the truss is in static equilibrium, the sum of the forces in the x and y directions must be zero. In the y direction, we have:
F_AB + F_BC = W
where F_AB and F_BC are the forces acting on bars AB and BC, respectively, and W is the weight acting downwards at the joint C. Since the truss is symmetric, we can assume that F_AB = F_BC.
Therefore,
F_AB = W/2 = (1000 kg)(9.81 m/s^2)/2 = 4905 N
To find the maximum load that bar AB can withstand with a factor of safety of 3.2, we can use the formula:
maximum load = ultimate load / factor of safety
maximum load = 120 kN / 3.2 = 37.5 kN = 37500 N
Now we can use the maximum load to calculate the required cross-sectional area of bar AB:
maximum stress = maximum load / cross-sectional area
From the stress-strain curve of the alloy, we can assume that the ultimate stress is equal to the yield stress, since the bar will deform plastically beyond the yield stress. Let's assume that the yield stress of the alloy is 300 MPa.
maximum stress = 37500 N / cross-sectional area <= 300 MPa
cross-sectional area >= 37500 N / 300 MPa = 0.125 m^2
Therefore, the required cross-sectional area of bar AB is:
cross-sectional area = 0.125 m^2 = 125000 mm^2
For bar AC, we can repeat the same analysis to find the maximum load and then the required cross-sectional area. Since bar AC is inclined at an angle of 45 degrees, we need to resolve the forces into components in the x and y directions. We have:
F_AC = W/sin(45) = (1000 kg)(9.81 m/s^2)/sin(45) = 6945 N
maximum load = 120 kN / 3.2 = 37.5 kN = 37500 N
maximum stress = 37500 N / cross-sectional area <= 300 MPa
cross-sectional area >= 37500 N / 300 MPa = 0.125 m^2
Therefore, the required cross-sectional area of bar AC is:
cross-sectional area = 0.125 m^2 = 125000 mm^2
So the required cross-sectional area of both bars AB and AC is 125000 mm^2.
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Can space debris take out a whole state
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It has been observed that a cylindrical rod with a diameter of 93 mm and a length of 204 mm increases in volume by 202 mm3 under the effect of axial normal force. Knowing that E = 181 GPa, ν=1/3, how many kN is the applied force P?
Answers
The applied force P on the cylindrical rod is 299.27 kN.
Given, Diameter (d) of the cylindrical rod = 93 mm
Length (l) of cylindrical rod = 204 mm
Increase in volume (ΔV) of cylindrical rod = 202 mm³
Elasticity or Young's modulus (E) = 181 GPa
Poisson's ratio (ν) = 1/3
Formula to calculate the force applied on the cylindrical rod is:
F = ΔV x E / [1-ν²] x [(d/l)²]
Where,
F = Force applied on cylindrical rod
ΔV = Increase in volume
E = Elasticity or Young's modulus
ν = Poisson's ratio of the cylindrical rod
d = Diameter of the cylindrical rod
l = Length of the cylindrical rod
Put all the given values in the above formula:
F = 202 x 181 / [1 - (1/3)²] x [(93/204)²]
F = 299266.44 N
F = 299.27 kN
Therefore, the applied force P on the cylindrical rod is 299.27 kN.
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what is the principal difference between congruent and incongruent phase transformations?
Answers
Phase transformations are physical or chemical changes that occur in the structure and composition of materials. Congruent and incongruent transformations are two types of phase transformations.
The primary difference between congruent and incongruent phase transformations is that congruent transformations generate only one phase, whereas incongruent transformations create multiple phases.In congruent transformations, the initial phase transitions to the final phase in a balanced manner, resulting in only one phase. The final state is in equilibrium, and there is no excess or deficient phase.
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before conducting a discharge test for halon and clean agent extinguishing systems, what must be accomplished in order to determine the amount of leakage from the protected area?
Answers
Before conducting a discharge test for halon and clean agent extinguishing systems, it is necessary to accomplish a leakage integrity test.
This test is performed to determine the amount of leakage from the protected area. It involves pressurizing the system with an inert gas, such as nitrogen, and monitoring the pressure for a specified duration. If there is a significant drop in pressure during the test, it indicates the presence of leaks in the system, which can affect the effectiveness of the extinguishing agent during an actual fire event. By conducting the leakage integrity test, any leaks can be identified and repaired before proceeding with the discharge test, ensuring that the system is operating properly and effectively.
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A shrinkage limit test is performed on a soil. The initial mass and volume of the soil are: V1=20.2cm^3 , while the final mass and volume are M2=24g and V2=14.3cm^3 . Note that in the initial state the soil is saturated, whereas in the final state the soil is completely dry.
Calculate:
a. the shrinkage limit SL of the soil.
b. the void ratio at the SL.
c. Gs of the soil solids.
d. the initial void ratio.
Answers
the clausius-clapeyron equation cannot be used to determine
Answers
Answer: temperature and pressure of a system
Explanation: Good evening.
The Clausius-Claperyon equation is used to measure enthalpy of vaporization of a liquid. I'm sure I'm missing more, but i gave the direct answer. Sorry I did not indulge into the answer more.
A signal that cannot be faked and carries the most accurate information about a situation or individual is known as an ______ signal
Answers
Answer: Honest
Explanation: In other to establish communication between two or more species, the sender and receiver, It is required of the sender to showcase certain behavior, sound or other demonstrations which are capable of passing a message to the receiver. These demonstrations are often reffered to as signals. Signals could be honest or dishonest. Honest signals are characterized by it's usefulness to the receiver and the conveyance of the actual or true meaning of underlying signal being transmitted. This is the opposite of dishonest signals which are often used to trick the receiving party as the information being transmitted are inaccurate and unreliable.
1)How do you distinguish between positive and negative logic system? Prove that an OR gate in a positive logic System is an AND gate in a negative logic system.
2)Give a brief statement that would help one remember the truth table of AND ,NAND, OR, NOR, EX-OR and EX -NOR logic gate functions ,irrespective of the number of input used.
Answers
Answer:
Positive logic is defined as a high voltage level representing a logic 1 and a low voltage level representing a logic 0. Negative logic is the reverse, i.e., a low voltage level represents a logic 1 and a high voltage level represents a logic 0.
Explanation:
Thanks
Explain how the horsepower of a sports car can be improved.
Answers
Answer:
with turbo or nos
Explanation:
What is the hardest part of engineering?
Answers
ANSWER:
Aerospace Engineering. ...
Chemical Engineering. ...
Biomedical Engineering.
EXPLANATION:
This is all i know but ... I hope this helps~
Briefly explain the operating principles of a two-opening superimposed waveguide directional coupler
Answers
A two-opening superimposed waveguide directional coupler is a type of directional coupler that consists of two waveguides that are positioned parallel to each other.
The operating principle of a two-opening superimposed waveguide directional coupler is based on the interaction between the electromagnetic fields of the two waveguides.
When a signal is introduced into one waveguide, it creates an electromagnetic field that extends into the adjacent waveguide. The strength of the electromagnetic field in the adjacent waveguide depends on the separation distance between the two waveguides.
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Write one page summary about engineering.
Answers
Answer:
this is the answer
Explanation:
this the summery about engineering
Define water hammer. Give four effects of water hammer.
Answers
Answer:
Water Hammer is a knocking sound in an water pipe which occurs when the tap is turned off briskly
Explanation:
Vector A extends from the origin to a point having polar coordinates (7, 70ᵒ ) and vector B extends from the origin to a point having polar coordinates (4, 130ᵒ ). Find A · B.
Answers
Answer:
13.95
Explanation:
Given :
Vector A polar coordinates = ( 7, 70° )
Vector B polar coordinates = ( 4, 130° )
To find A . B we will
A ( r , ∅ ) = ( 7, 70 )
A = rcos∅ + rsin∅
therefore ; A = 2.394i + 6.57j
B ( r , ∅ ) = ( 4, 130° )
B = rcos∅ + rsin∅
therefore ; B = -2.57i + 3.06j
Hence ; A .B
( 2.394 i + 6.57j ) . ( -2.57 + 3.06j ) = 13.95