What volume of 0. 256 m sodium bromide contains 18. 7 grams of sodium bromide?.

ANSWER

the volume of the solution is 2.05 liters

EXPLANATION

Given that;

The concentration of Ca(OH)2 is 0.420M

The grams of Ca(OH)2 is 64.0 grams

Follow the steps below to find the volume of the solution

Step 1; Calculate the number of moles of Ca(OH)2 using the below formula

Recall, that the molar mass of Ca(OH)2 is 74.093 g/mol

Step 2; Find the volume of the solution in liters using the below formula

Therefore, the volume of the solution is 2.05 liters

Answer- better

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You would need to give approximately 18.8 ml of the ABC 8% solution to administer a 150 mg dose.

To calculate the required amount in milliliters, we need to use the following formula:

(required amount in ml) = (required dose in mg) / (concentration of stock solution in mg/ml)

Here, the required dose is 150 mg, and the concentration of the stock solution is 8% or 8 mg/ml.

So, putting the values in the formula, we get:

(required amount in ml) = 150 mg / 8 mg/ml

(required amount in ml) = 18.75 ml

Rounding off the answer to the nearest tenth, we get:

(required amount in ml) ≈ 18.8 ml

Therefore, you would need to give approximately 18.8 ml of the ABC 8% solution to administer a 150 mg dose.

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Answer:

1/32

Explanation:

When hydrochloric acid (HCl) is added to a carbonate salt, a chemical reaction occurs, producing carbon dioxide (CO2) gas, water (H2O), and a chloride salt. This reaction is called an acid-carbonate reaction. The key observation during this reaction is the effervescence or bubbling due to the release of carbon dioxide gas.

In this process, the HCl donates a hydrogen ion (H+) that reacts with the carbonate ion (CO3 2-) present in the carbonate salt. The reaction results in the formation of carbonic acid (H2CO3), which then breaks down into water and carbon dioxide gas.

The remaining part of the carbonate salt combines with the chloride ion (Cl-) from the hydrochloric acid to form the corresponding chloride salt.

The general equation for this reaction can be written as:

2HCl(aq) + M2CO3(s) → 2MCl(aq) + H2O(l) + CO2(g)

Here, M represents the metal cation of the carbonate salt, such as sodium (Na), calcium (Ca), or potassium (K).

An observable sign of this reaction is the effervescence or bubbling due to the release of carbon dioxide gas. The solution may also become clearer as the carbonate salt dissolves and reacts with the acid.

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Running a blank solution is crucial in spectrophotometry experiments to establish the zero %T and account for background absorbance. Without running a blank, the results can be affected by systematic errors.

It is important to run a blank solution to set the zero %T in both Parts 1 and 2 of the experiment because it helps to account for any background absorbance or interference from the solvent or other components in the sample. Running a blank solution allows us to establish a baseline measurement of the solvent or the solution without the analyte, which helps in accurately measuring the absorbance caused by the analyte of interest.

If a blank solution is not run, the results can be affected in several ways:

Systematic Error: The absence of a blank solution can introduce a systematic error, causing a constant offset in the measured absorbance values. This offset can lead to incorrect calculations and interpretations.

Overestimation or Underestimation: Without running a blank, the measured absorbance may include contributions from the solvent or other interfering substances. This can lead to overestimation or underestimation of the analyte concentration, affecting the accuracy of the results.

Distorted Beer's Law Plot: In the absence of a blank, the plot obtained may not accurately represent the linear relationship between concentration and absorbance according to Beer's Law. This can lead to incorrect calculations of the slope (molar absorptivity) and affect the accuracy of future concentration determinations.

In spectrophotometry, the blank solution serves as a reference for setting the zero %T (transmittance) or absorbance value. By measuring the blank, we can account for any absorbance caused by the solvent, impurities, or other components in the sample. The blank solution typically contains all the components except the analyte of interest. It is measured under the same conditions as the sample solutions.

The blank measurement allows us to subtract any background absorbance from the sample measurements, providing a more accurate representation of the absorbance caused solely by the analyte. This helps in obtaining reliable and precise measurements for concentration determination using Beer's Law.

Running a blank solution is crucial in spectrophotometry experiments to establish the zero %T and account for background absorbance. Without running a blank, the results can be affected by systematic errors, inaccurate concentration determinations, and distorted Beer's Law plots. It is important to always include a blank solution to ensure accurate and reliable measurements.

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Answer:

(6.02214179×1023) / one mole of substance. How many atoms are in a 3.0 g sample of sodium (Na)?

Explanation:

Answer:

Explanation:

Mass is 1.000

The amount of water that melts when 100.0 grams of pure ice are combined with 100.0 grams uniform temperature   of water heated to 60.0 degrees Celsius is 50.3 grams. To 0 degrees Celsius, the water has been cooled.

The term "temperature uniformity" refers to the ability of an oven to keep the desired temperature consistently throughout all of its operating duration, not only in one area.

1. Evenly distributed heat flow at the ground. If the grooves are deep or if the macroscopic constriction resist in the tube walls is high compared to the interfacial contact resistance there at joint between the outer and inner tubes, the heat flux over the land would be roughly uniform.

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Answer:

D

Explanation:

Just that. The atomic number is equal to the atomic mass.

Answer:

CH4 + 2O2 --> CO2 + 2H2O

Explanation:

"CO2" can be written as carbon dioxide

Answer: Yes, sulfuric acid is highly soluble in water.

Explanation:

Answer:

Protons = 89

Neutrons = 142

Electrons = 89

Option C

Explanation:

Hello,

Were required to find the proton, neutron and electron of an element Y

The atomic mass of element Y is composed of the protons and neutrons while the atomic number is the exact amount of protons present in the element.

Element = ₈₉²³¹Y

Atomic number = 89

Number of protons = 89

Number of electrons = 89

Atomic mass = 231

Atomic mass = protons + neutrons

231 = 89 + neutrons

Neutrons = 231 - 89

Neutrons = 142

Therefore the number of protons is 89, number of neutrons is 142 and number of electrons is 89.

Note: for an electrically neutral atom, the number of protons must be equal to the number of electrons

The correct option is (A) - This Bohr Model of atom describes that there are a total of 6 electrons in the given figure.

The electrons are positioned in circular orbitals at particular distances from the central nucleus in the Bohr model of the atom. These orbits create electron shells or energy levels, which allow us to see how many electrons are present in each shell. The number and the letter "n" are used to identify these energy levels. The first energy level nearest to the nucleus, for instance, is represented by the 1n shell. Normally, an electron resides in the shell with the lowest energy, which is the one closest to the nucleus. A photon of light's energy can raise it to a higher energy shell, but this is an unstable position, and the electron quickly returns to the ground state.

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Answer:

Global warming stresses ecosystems through temperature rises, water shortages, increased fire threats, drought, weed and pest invasions, intense storm damage and salt invasion, just to name a few.

Explanation:

Global warming stresses ecosystems through temperature rises, water shortages, increased fire threats, drought, weed and pest invasions, intense storm damage and salt invasion, just to name a few.

Answer:

B.  Na

Explanation:

To identify an atom, you simply need to look at the number of protons.  This atom has 11 protons.  On the periodic table, you can see that the element with 11 protons is sodium (Na).

Answer:

Explanation:

SODIUM ATOM;

SODIUM ATOM IS NEUTRAL

SODIUM ION;

IT IS A CHARGED SPECIE WITH A CHARGE OF +1

SODIUM ATOM:

THE NUMBER OF PROTONS AND ELECTRONS ARE SAME ie:11

SODIUM ION:

NUMBER OF PROTONS AND ELECTRONS ARE NOT SAME ie. ELETRON: 10, PROTONS:11

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Answer:

See explanation

Explanation:

If I am running my country, I will go for biomass as an energy resource. Biomass is cheap and readily available. The use of biomass in electricity generation is largely safe and reliable; it even ensures a clearer environment!

Biopower plants burn biomass directly to produce high-pressure steam which is now used to drive a turbine generator to generate electricity. Biomass will always be available at almost no cost hence it offers an inexpensive energy resource for electricity generation.

Answer: Carbon Dioxide, Methane, Nitrous Oxide and Fuorinated Gases

Explanation:Carbon dioxide (CO2): Carbon dioxide enters the atmosphere through burning fossil fuels (coal, natural gas, and oil), solid waste, trees and other biological materials, and also as a result of certain chemical reactions (e.g., manufacture of cement). Carbon dioxide is removed from the atmosphere (or "sequestered") when it is absorbed by plants as part of the biological carbon cycle.

Methane (CH4): Methane is emitted during the production and transport of coal, natural gas, and oil. Methane emissions also result from livestock and other agricultural practices and by the decay of organic waste in municipal solid waste landfills.

Nitrous oxide (N2O): Nitrous oxide is emitted during agricultural and industrial activities, combustion of fossil fuels and solid waste, as well as during treatment of wastewater.

Fluorinated gases: Hydrofluorocarbons, perfluorocarbons, sulfur hexafluoride, and nitrogen trifluoride are synthetic, powerful greenhouse gases that are emitted from a variety of industrial processes. Fluorinated gases are sometimes used as substitutes for stratospheric ozone-depleting substances (e.g., chlorofluorocarbons, hydrochlorofluorocarbons, and halons). These gases are typically emitted in smaller quantities, but because they are potent greenhouse gases, they are sometimes referred to as High Global Warming Potential gases ("High GWP gases").

Answer:

Here are the finishes for each equation, respectively:

Mg + 4 HNO3 → Mg(NO3)2 + 2 NO + 2 H2O

2 Al + 6 HBr → 2 AlBr3 + 3 H2

K2O + 2 HNO3 → 2 KNO3 + H2O

Ba + H3PO4 → Ba3(PO4)2 + 3 H2

Ca + 2 HBr → CaBr2 + H2

3 NaOH + H3PO4 → Na3PO4 + 3 H2O

Fe2O3 + 6 HNO3 → 2 Fe(NO3)3 + 3 H2O

Mg + 2 HCl → MgCl2 + H2

FeO + 2 HCl → FeCl2 + H2O

Fe3O4 + 8 H2SO4 → 3 Fe2(SO4)3 + 8 H2O

Ba + 4 HNO3 → Ba(NO3)2 + 2 NO2 + 2 H2O

2 Na + 2 HNO3 → 2 NaNO3 + H2

MgO + 2 HBr → MgBr2 + H2O

2 KOH + H2SO4 → K2SO4 + 2 H2O

FeO + HNO3 → Fe(NO3)2 + NO + H2O

NaOH + HCl → NaCl + H2O

Oxidation and reduction are important concepts in chemistry, and they often go hand in hand with redox reactions. Metals that can be oxidized are referred to as reducing agents, whereas those that can be reduced are referred to as oxidizing agents.

The metal that has the greatest tendency to be oxidized is the strongest reducing agent, while the one with the least tendency to be oxidized is the weakest reducing agent. Copper (Cu), cadmium (Cd), and nickel (Ni) are three metals that will be considered. The oxidations and their equilibrium constants are given below:

Cu → Cu2+ + 2 e− [Cu2+] / [Cu]2Cd

→ Cd2+ + 2 e− [Cd2+] / [Cd]2Ni

→ Ni2+ + 2 e− [Ni2+] / [Ni]2

Using the above given equations, equilibrium constants can be determined for these metals:

Cu:  Kc = [Cu2+] / [Cu]2

Cd: Kc = [Cd2+] / [Cd]2

Ni: Kc = [Ni2+] / [Ni]2

The smaller the value of Kc, the more spontaneous the reaction. Hence, the metal with the smallest Kc would be the strongest reducing agent, and the metal with the largest Kc would be the weakest reducing agent. According to the above equations, the metals in order of strength from the strongest to the weakest reducing agent are as follows: Cu, Cd, Ni. Therefore, copper is the strongest reducing agent, cadmium is the second strongest reducing agent, and nickel is the weakest reducing agent.

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Every a-module homomorphism aₑ → aₑ is of the form x → xb for some b = εbε ∈ εaε.

What is an a-module homomorphism?

An a-module homomorphism is a map between two a-modules that preserves the module structure, i.e., it respects the module addition and scalar multiplication.

To show that every a-module homomorphism aₑ → aₑ is of the form x → xb for some b = εbε ∈ εaε, let φ be an a-module homomorphism from aₑ to aₑ. For any x ∈ aₑ, we can express x as x = εa for some a ∈ a.

Then, φ(x) = φ(εa) = εφ(a). Let b = φ(a), so φ(x) = εb. Therefore, every a-module homomorphism aₑ → aₑ is of the form x → xb for some b = εbε ∈ εaε.

Therefore, the answer is that every a-module homomorphism aₑ → aₑ is of the form x → xb for some b = εbε ∈ εaε.

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Answer:

CaCO3... Answerrrr.....

Answer:

\(CaCO_{3}\)

Explanation:

This is because calcium is a metal that forms ions with a 2+ charge (as it has 2 electrons on its outer shell).

Carbonate ions are complex ions with a 2- charge, so with one carbonate and one calcium, the 2+ and 2- charges will cancel out.

Answer:

Evolution is the process by which populations of organisms change over generations. Genetic variations underlie these changes

Explanation:

If a trait is advantageous and helps the individual survive and reproduce, the genetic variation is more likely to be passed to the next generation.

Brain-List?

Answer:

A metalloid is a type of chemical element which has a preponderance of properties in between, or that are a mixture of, those of metals and nonmetals. There is no standard definition of a metalloid and no complete agreement on which elements are metalloids. Despite the lack of specificity, the term remains in use in the literature of chemistry.

A series of six elements called the metalloids separate the metals from the nonmetals in the periodic table. The metalloids are boron, silicon, germanium, arsenic, antimony, and tellurium. These elements look metallic; however, they do not conduct electricity as well as metals so they are semiconductors. They are semiconductors because their electrons are more tightly bound to their nuclei than are those of metallic conductors. Their chemical behavior falls between that of metals and nonmetals. For example, the pure metalloids form covalent crystals like the nonmetals, but like the metals, they generally do not form monatomic anions. This intermediate behavior is in part due to their intermediate electronegativity values. In this section, we will briefly discuss the chemical behavior of metalloids and deal with two of these elements—boron and silicon—in more detail.

Explanation:

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The liquid described, containing 60% sugar and 40% water throughout its composition, is called a homogeneous mixture.

A homogeneous mixture is a type of mixture where the components are uniformly distributed throughout the mixture, resulting in a uniform composition and appearance. In a homogeneous mixture, the components are not visibly distinct and cannot be easily separated by physical means, such as filtering or settling.

Homogeneous mixtures can be either single-phase or multi-phase, depending on the number of components present and the nature of their interactions. Examples of homogeneous mixtures include solutions (such as saltwater), alloys (such as brass), and some types of gels and emulsions.

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The empirical formula for the compound containing 42.88% carbon and 57.1% oxygen by mass is Carbon Monoxide (CO).

To find the empirical formula for 42.8% carbon (C) and 57.1% oxygen (O)

First, find the molar mass of each component-

    C = 12.010, O = 15.999

Converting to the moles :

    C = 3.563, O = 3.568

Finding smallest mole value :

    C = 3.563

Dividing all components by smallest value :

    C = 1, O = 1.001

By rounding off -

    C = 1, O = 1

Combining to get empirical formula : CO

Now, multiplying all by 1 ( molar mass of empirical formula/molar mass of sample = 28.01 / 28.034 ) to get molecular formula : CO

Since multiplied by 1, Therefore, the empirical formula and molecular formula are same.

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The blending of one s atomic orbital and two p atomic orbitals produces three sp hybrid orbitals.

When an s orbital and two p orbitals combine, they undergo hybridization to form three sp hybrid orbitals. This hybridization occurs when an atom is bonded to three other atoms in a trigonal planar arrangement. The process involves mixing one s orbital and two p orbitals to form three equivalent hybrid orbitals.

These sp hybrid orbitals have a linear shape with an angle of 180 degrees between them. The term "sp" indicates that the hybrid orbitals are a combination of one s orbital and one p orbital. This type of hybridization is commonly observed in molecules with triple bonds or in the central atom of trigonal planar molecules.

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