What was the instantaneous speed of Bear A at 5 seconds in meters/min? (No unit conversions necessary, no units required for answer. Type your answer.)

Answer:

Stars are the light bulbs of the universe.

Answer:

Stars are the recycling centers of the universe

Explanation:

I just did on edge C

The two pointy tapes repel. This shows they have the same type of charge.

The attraction of two charges occurs when the two charges have opposite charges.

The repulsion of two charges occurs when the two charges have similar charges.

Thus, since the two pointy tapes will have the same charge, we can conclude that they will repel each other when brought near each other.

The complete question is below:

How did the pointy tapes behave when brought near each other, and what does this demonstrate about their charges?

Two pointy tapes repel. This shows they have opposite types of charge.

Two pointy tapes attract. This shows they have opposite types of charge.    

Two pointy tapes repel. This shows they have the same type of charge.

Two pointy tapes attract. This shows they have the same type of charge.

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Electricity is just the flow of electrons or charges from a point of production through a conductor, to another point where it can be utilized or converted to another form of energy.

Magnetism is the force exerted by magnets when they attract or repel each other. Magnetism is caused by the motion of electric charges from two or more magnetic substances.

Answer:

By Electricity.. We mean the Flow of electrical power or Charge.

While Magnetism is a phenomenon that occurs from or by the Motion of Charges

The value of the inductance, in , microhenrys of Tarik's solenoid is approximately 1.6239 microhenrys.

To calculate the inductance of a solenoid, we can use the formula:

L = (μ₀ * N² * A) / l

where L is the inductance, μ₀ is the permeability of free space (4π × 10⁻⁷ T·m/A), N is the number of turns, A is the cross-sectional area of the solenoid, and l is the length of the solenoid.

In this case, we have:

N = 175 turns

Diameter = 8.05 mm = 0.00805 m (converted to meters)

Radius = Diameter / 2 = 0.00805 m / 2 = 0.004025 m

Length (l) = 2.37 cm = 0.0237 m (converted to meters)

First, let's find the cross-sectional area (A) using the formula for the area of a circle:

A = π * r² = π * (0.004025 m)² ≈ 5.08398 × 10⁻⁵ m²

Now we can plug in the values into the formula for inductance:

L = (4π × 10⁻⁷ T·m/A * (175)² * 5.08398 × 10⁻⁵ m²) / 0.0237 m

L ≈ (1.2566 × 10⁻⁶ * 30625 * 5.08398 × 10⁻⁵) / 0.0237

L ≈ (38.5086 × 10⁻⁶) / 0.0237

L ≈ 1.6239 × 10⁻⁶ H

Now, let's convert the inductance from henrys to microhenrys:

L ≈ 1.6239 × 10⁻⁶ H * 10⁶ μH/H ≈ 1.6239 μH

So the inductance of Tarik's solenoid is approximately 1.6239 microhenrys.

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The velocity of car 2, from the frame of reference of car 1, is 20 m/s west. (Answer: B)

When considering the frame of reference of car 1, we need to subtract the velocity of car 1 from the velocity of car 2 to determine the relative velocity. Since car 1 is moving at 45 m/s west and car 2 is moving at 25 m/s east, we can subtract these velocities to find the relative velocity of car 2 with respect to car 1.

45 m/s (west) - 25 m/s (east) = 20 m/s (west)

Therefore, car 2 has a velocity of 20 m/s west when observed from the frame of reference of car 1. It is important to note that velocities are vector quantities, which means they have both magnitude and direction. In this case, the direction is west because car 2 is moving in the opposite direction of car 1. (Answer: B)

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Answer

The ocean liner has greater kinetic energy.

Energy bullet = 116.5248 J

Energy ocean liner = 4248000000 J

Explanation:

The kinetic energy of an object can be calculated as:

Where m is the mass and v is the velocity.

Then, replacing m = 0.0014 kg and v = 408 m/s we get that the kinetic energy of the bullet is:

In the same way, we can replace m = 5.9 x 10^7 kg and v = 12 m/s to find the kinetic energy of the ocean liner as:

Therefore, the ocean liner has greater kinetic energy.

So, the answers are:

The ocean liner has greater kinetic energy.

Energy bullet = 116.5248 J

Energy ocean liner = 4248000000 J

The angular velocity in radians per second, given that Microwave ovens rotate at a rate of about 5 revolutions per minute (rpm) is 0.50 radians per second

The angular velocity (in radians per second) can be obtained by simply converting 0.08 revolution per second to radians per second. This is obtained as illustrated below:

1 revolution per second = 2π radians per second

Therefore,

0.08 revolution per second = 0.08 × 2π

Recall

Pi (π) = 3.14

Thus,

0.08 revolution per second = 0.08 × 2 × 3.14

0.08 revolution per second = 0.50 radians per second

Thus, we can conclude that the angular velocity (in radians per second) is 0.50 radians per second

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Answer:

The answer will be #3 and #4

Explanation:

Because the more the organisms live in the topsoil the weaker the soil would get and most likely that would happen and planting trees stop soil erosion because when the trees absorb water underground it makes the soil firm and tight just like the (abnormal) soil you would see near few feet near most trees.

We have that the tension in rope 2 is mathematically given as

the tension in rope 2 is

From the question we are told

A crate hangs from a rope that is attached to a metal ring.

The metal ring is suspended by a second rope that is attached overhead at two points, as shown.

What is the angle if the tension in rope 1 is 0.640 times the tension in rope 2?

Generally the equation for the Tension  is mathematically given as

\(Tcos\theta+0.640\theta-T_1=0\\\\Therefore\\\\ZTcos \theta-0.640T=0\\\\Cos=0.32\\\\\theta=71.3\\\\\)

Therefore

the tension in rope 2 is

\(\theta=71.3\)

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Answer:

His gravitational potential energy will increase as well.

Explanation:

Let gpe represent gravitational potential energy.

gpe = mass × gravitational field strength × height

From the formula above, we can conclude that as the mass of a body increases, it's gpe increases too.

Easy the answer to your question is Obviously "A"

The Magnus effect can not be observed in skiing.

Magnus' effect: When there is relative motion between the spinning body and the fluid, a sideways force is generated on a rotating cylindrical or spherical solid immersed in the fluid (liquid or gas). The effect, bears the name H.G. Magnus Phenomenon, after the German scientist and chemist who first experimentally explored the effect in 1853.

The ball is pushed higher into the air by the Magnus Effect, which has an equal-and-opposite effect to the friction between the air and the ball.

A deflection in the direction perpendicular to the spinning axis and the velocity vector results from the spinning. Tennis players frequently use top or backspin when striking the ball.

When a fastball has a backspin, the upward Magnus Effect works against gravity to keep the ball in the air longer. When a curveball has topspin, however, the downward Magnus Effect works in favor of gravity to shorten the baseball's flight.

In skiing, there is no Magnus effect

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In which of these sports can one not observe the Magnus effect?

a) Baseball

b) Tennis

c) Basketball

d) Skiing

Answer:

Explanation:

Wavelength = 100m. Speed = V. 2.) Frequency = 20 Hz. Wavelength = 200 m. Speed = ... 2=1.7m. F=Y/2 f=2×10. 5.) Wavelength = 502 km. Speed= 100 m/s.

v = s/t

44 m/s = 3.5 m/t

t = 3.5 m : 44 m/s

t = 0.08 s

a = v/t

a = 44 m/s/0.08 s

a = 550 m/s²

a : g = 550 m/s² : 10 m/s²

a : g = 55 : 1

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Answer:

Solar energy is renewable.

Explanation:

If something is renewable, it is generated faster than it can be reasonably used or won't run out for longer than it would be used. Solar falls into the latter category. Using solar panels won't deplete the sun and the sun will likely be around for much longer than we will.

Answer:

I dont understand...٩(●˙—˙●)۶

Explanation:

Sorry...

According to the question the mass of remaining ice in the jar is 90.3 g.

Mass is a fundamental physical property of matter that is measured in kilograms (kg). It is the amount of matter an object contains and is often used to measure the weight of an object. Mass is different from weight, which is a measure of the force of gravity acting on an object. Mass is the same no matter where it is located, while weight is different due to the varying gravitational forces in different locations. Mass is an inherent property of matter and is conserved, meaning it cannot be created or destroyed, it can only be changed from one form to another. Mass is an important concept in physics and is used in a variety of calculations.

The equation for heat transfer can be written as
Q = mcΔT
Where Q is the heat transfer, m is the mass, c is the specific heat capacity, and ΔT is the temperature change.
We can use this equation to solve for the remaining mass of ice:
Q = mcΔT
m = Q / (cΔT)
m = (185 x 4186 x (33.1-26.3)) / (4186 x (0 - 26.3))
m = 90.3 g
Therefore, the mass of remaining ice in the jar is 90.3 g.

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The distance of your hometown from school is 318.64 km.

Given data

Distance S = 190 km

Speed v = 97 km / h

Now, the time taken to travel S distance is calculated as,

t = S / v

t = 180 / 95

t = 1.958 hrs

Now, the total time is given as

Total time T = 4.0 h

So, remaining time t ' = T - t = 4 hrs - 1.958 hrs = 2.042 hrs

Now, the velocity after travel 190 km is v ' = 63 km/ h

Distance travel in this velocity S ' = v ' t '

= 128.6 km

Now, the distance of your hometown from school , S " = S + S '

= 190 km + 128.6 km = 318.64 km

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Changing the green sum of forces arrow involves manipulating applied forces, frictional forces, and normal forces, allowing for adjustments in magnitude and direction through various means.

To change the green sum of forces arrow, you can employ the following three strategies:

Adjusting Applied Forces: By modifying the magnitude or direction of the applied forces, you can alter the green sum of forces arrow. If the applied forces are increased or directed in a different way, the green sum of forces arrow will change accordingly. For instance, increasing the magnitude of a pushing force will result in a larger green sum of forces arrow in that direction.

Modifying Frictional Forces: Frictional forces play a crucial role in determining the green sum of forces. By changing the coefficient of friction or applying lubricants, you can affect the magnitude of frictional forces acting on an object. Reducing friction will decrease the green sum of forces arrow, while increasing friction will have the opposite effect.

Varying Normal Forces: The green sum of forces arrow can be influenced by adjusting the normal forces acting on an object. Normal forces are perpendicular to the surface and counteract the weight of an object. By changing the angle or surface on which an object rests, you can modify the normal forces. This alteration will subsequently impact the green sum of forces arrow.

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Answer:

it is double the temperature change of iron

Answer:

\(8.16\ \text{m/s}\)

Explanation:

\(d_1\) = Initial diameter = 4 cm

\(v_1\) = Initial velocity = 1 m/s

\(d_2\) = Final diameter = 7.8 m

\(v_2\) = Final velocity

\(A\) = Area = \(\pi\dfrac{d^2}{4}\)

From the continuity equation we get

\(A_1v_1=A_2v_2\\\Rightarrow \pi\dfrac{d_1^2}{4}v_1=\pi\dfrac{d_2^2}{4}v_2\\\Rightarrow v_2=\dfrac{d_1^2}{d_2^2}v_1\\\Rightarrow v_2=\dfrac{4^2}{1.4^2}\times 1\\\Rightarrow v_2=8.16\ \text{m/s}\)

The speed of water at the second floor is \(8.16\ \text{m/s}\).

Answer:  Choice A) 2 meters per second

=======================================================

Explanation:

The smaller ball has momentum of

p = m*v

p = (1 kg)*(4 m/s)

p = 4 kg*m/s

All of this momentum transfers into the larger ball because the smaller ball comes to a complete stop.

For the larger ball, we have p = 4 and m = 2. Let's find v.

p = m*v

4 = 2*v

4/2 = v

2 = v

v = 2 m/s which is why the answer is choice A

The larger ball moves at a speed of 2 meters per second. The speed is cut in half compared to the smaller ball because the larger ball has more inertia (aka more mass), and therefore it takes more energy to move it. If you apply the same energy to each, then the smaller object moves faster.

Answer:

B. For a gas in a closed container at a constant temperature, the product of the pressure and the volume remains constant.

Explanation:

The rest are societal laws, as they are telling you something you should avoid or follow.

Hope this helps :)

Answer:

   y = - (½ g / v₀²)   x²

Explanation:

This is a projectile launch exercise where there is no acceleration on the x-axis so

        x = v₀ₓ t

        v₀ₓ = v₀ cos tea

        y = \(v_{oy}\) t - ½ g t2

        v_{oy} = v₀ sin θ

as the sphere is thrown horizontally, the angle is tea = 0º, so the initial velocity remains

          v₀ₓ = v₀

           v_{oy} = 0

we substitute in our equations

          x = v₀ t

          y = - ½ g t²

we eliminate the time from these equations, we substitute the first in the second

      y = - ½ g (x / v₀)²

      y = - (½ g / v₀²)   x²

this is the equation of a parabola

When the overcurrent protection for a conductor is located on the load end rather than the supply side of a conductor it is considered to be a tap conductor.

The National Electrical Code (NEC), the benchmark for safe electrical design, installation, and inspection to protect people and property from electrical hazards, defines a tap conductor as a conductor, other than a service conductor, that has overcurrent protection rated more than the ampacity of a conductor. A tap conductor has overcurrent protection ahead of its point of supply that exceeds the value permitted for similar conductors that are protected as described in NEC 240.4. Hence, when the overcurrent protection for a conductor is located on the load end rather than the supply side of a conductor it is considered to be a tap conductor.

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Answer:Lesson Objectives

Describe how the action of waves produces different shoreline features.

Discuss how areas of quiet water produce deposits of sand and sediment.

Discuss some of the structures humans build to help defend against wave erosion.

Vocabulary

arch

barrier island

beach

breakwater

groin

refraction

sea stack

sea wall

spit

wave-cut cliff

wave-cut platform

Introduction

Waves are important for building up and breaking down shorelines. Waves transport sand onto and off of beaches. They transport sand along beaches. Waves carve structures at the shore.

Wave Action and Erosion

All waves are energy traveling through some type of material, such as water (Figure below). Ocean waves form from wind blowing over the water.

Ocean waves are energy traveling through water.

The largest waves form when the wind is very strong, blows steadily for a long time, and blows over a long distance.

The wind could be strong, but if it gusts for just a short time, large waves won’t form. Wave energy does the work of erosion at the shore. Waves approach the shore at some angle so the inshore part of the wave reaches shallow water sooner than the part that is further out. The shallow part of the wave ‘feels’ the bottom first. This slows down the inshore part of the wave and makes the wave ‘bend.’ This bending is called refraction.

Wave refraction either concentrates wave energy or disperses it. In quiet water areas, such as bays, wave energy is dispersed, so sand is deposited. Areas that stick out into the water are eroded by the strong wave energy that concentrates its power on the wave-cut cliff (Figure below).

The wave erodes the bottom of the cliff, eventually causing the cliff to collapse.

Other features of wave erosion are pictured and named in Figure below. A wave-cut platform is the level area formed by wave erosion as the waves undercut a cliff. An arch is produced when waves erode through a cliff. When a sea arch collapses, the isolated towers of rocks that remain are known as sea stacks.

(a) The high ground is a large wave-cut platform formed from years of wave erosion. (b) A cliff eroded from two sides produces an arch. (c) The top of an arch erodes away, leaving behind a tall sea stack.

Wave Deposition

Rivers carry sediments from the land to the sea. If wave action is high, a delta will not form. Waves will spread the sediments along the coastline to create a beach (Figure below). Waves also erode sediments from cliffs and shorelines and transport them onto beaches.

Sand deposits in quiet areas along a shoreline to form a beach.

Beaches can be made of mineral grains, like quartz, rock fragments, and also pieces of shell or coral (Figure below).

Quartz, rock fragments, and shell make up the sand along a beach.

Waves continually move sand along the shore. Waves also move sand from the beaches on shore to bars of sand offshore as the seasons change. In the summer, waves have lower energy so they bring sand up onto the beach. In the winter, higher energy waves bring the sand back offshore.

Some of the features formed by wave-deposited sand are in Figure below. These features include barrier islands and spits. A spit is sand connected to land and extending into the water. A spit may hook to form a tombolo.

Examples of features formed by wave-deposited sand.

Shores that are relatively flat and gently sloping may be lined with long narrow barrier islands (Figure below). Most barrier islands are a few kilometers wide and tens of kilometers long.

(a) Barrier islands off of Alabama. A lagoon lies on the inland side. (b) Barrier islands, such as Padre Island off the coast of Texas, are made entirely of sand. (c) Barrier islands are some of the most urbanized areas of our coastlines, such as Miami Beach.

In its natural state, a barrier island acts as the first line of defense against storms such as hurricanes. When barrier islands are urbanized (Figure above), hurricanes damage houses and businesses rather than vegetated sandy areas in which sand can move. A large hurricane brings massive problems to the urbanized area.

Protecting Shorelines

Intact shore areas protect inland areas from storms that come off the ocean (Figure below).

Dunes and mangroves along Baja California protect the villages that are found inland.

Explanation:

Answer: Below

Explanation: Correct on Edmentum

The acceleration of the body is 4.5 m/s^2.

First, let's convert the initial velocity and final velocity from m/s to km/h:

Initial velocity = 30 m/s = (30/1000) * 3600 = 108 km/h

Final velocity = 80 m/s = (80/1000) * 3600 = 288 km/h

Let the time taken to accelerate to 288 km/h be t1, and the time taken to decelerate from 288 km/h to rest be t2. Since the time spent at constant velocity is twice the time spent accelerating, it is 2t1.

The distance covered during acceleration and deceleration can be calculated using the formula:

distance = (initial velocity * time) + (0.5 * acceleration * time^2)

For acceleration:

distance1 = (108 * t1) + (0.5 * a * t1^2)

For deceleration:

distance2 = (288 * t2) + (0.5 * (-a) * t2^2)

Since the total time taken for the journey is 40, we have:

t1 + 2t1 + t2 = 40

3t1 + t2 = 40

Also, the total distance traveled is given as 2550 km:

distance1 + distance2 = 2550

Substituting the expressions for distance1 and distance2, we get:

(108 * t1) + (0.5 * a * t1^2) + (288 * t2) - (0.5 * a * t2^2) = 2550

Simplifying the above equation:

108t1 + 144t1^2/a + 288t2 - 0.5t2^2a = 2550

Now, we have three equations with three variables (a, t1, t2). We can solve these equations to obtain the value of acceleration (a).

From the first equation, we have:

t2 = 40 - 3t1

Substituting this value of t2 in the equation for distance2, we get:

distance2 = 288(40 - 3t1) - 0.5*a(40 - 3t1)^2

Substituting the values of distance1 and distance2 in the equation for total distance, we get:

(108 * t1) + (0.5 * a * t1^2) + 288(40 - 3t1) - 0.5*a(40 - 3t1)^2 = 2550

Simplifying the above equation and solving for a, we get:

a = 4.5 m/s^2
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Answer:

the answer is ambivert have a good fourth of July

Answer:

i believe the answer is ambivert

Displacement is equal to the area under a velocity-time graph.