What would top speed up the hill be for a Professor's Experimental Electric Vehicle given the following motor, powertrain, and road load data? 3000 lb total weight for the EV 8% Grade Gear Ratio 3.5:1 (Motor Speed: Axle Speed Ratio) note motor faster as given here 27" Diameter Tire Rolling Diameter Motor see dynamometer

The driver of the van will hear a higher pitch due to his higher relative velocity.

The relative velocity of an object is the velocity of the object with respect to a stationary observer.

If a fire engine is moving at 40 m/s and sounding its horn. Also if  A car in front of the fire engine is moving at 30 m/s, and a van in front of the car is stationary.

The relative velocity of the stationary van is calculated as;

Vv = -40m/s - 30 m/s = - 70 m/s

The driver of the van will hear a higher pitch since his combined relative velocity of both cars is 70 m/s.

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If the clock input to a 4-bit ripple counter is 2KHz, then the frequency of the MSB of the counter is 1000Hz. So, option A is correct.

A ripple counter is a type of digital counter that sequentially counts from one state to the next. In a 4-bit ripple counter, there are four flip-flops connected in a cascaded manner, where the output of each flip-flop serves as the clock input for the next flip-flop.

The frequency of the counter is determined by the clock input. In this case, the clock input is given as 2 kHz (2000 Hz). Since the counter is 4-bit, it means it will have 2⁴ = 16 states.

Each state transition occurs on the rising edge of the clock signal, so the frequency of the MSB (most significant bit) of the counter will be half of the clock frequency.

This is because the MSB changes state only after all the lower-order bits have gone through their respective state transitions.

Therefore, the frequency of the MSB of the counter will be:

2000 Hz / 2 = 1000 Hz

It is important to note that in a ripple counter, the frequency of the MSB is always half the clock frequency, regardless of the number of bits in the counter.

Hence, the correct answer is A) 1000 Hz.

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Answer:if i know ill tell u

Explanation:

The scale will read 290.6 N when the piece of copper is submerged in water.

The Force exerted by the mass of the copper piece is 320 N according the scale reading, We know that Weight = mg where m is the mass of the object and g is the acceleration due to gravity (9.8 m/s²). Therefore the mass of the copper piece is :

⇒Weight = mg

⇒m = Weight/g

⇒m = 320/9.8

⇒32.65 kg

Now , we know that density = mass/volume. The density of copper is 8830 kgm⁻³.

∴ Volume = mass/density

⇒ 32.65/8830

⇒ 0.003 m³

Now, Apparent weight = (Weight of the object) - (Weight of the volume of liquid displaced by the object)

Formula for buoyant force = (volume displaced) x (acceleration due to gravity) x (density of the liquid). Density of water is approximately 1000kg/m³

Therefore, Apparent weight of the copper piece :

⇒ Actual weight - Buoyant force

⇒ 320N - [1000 x 0.003 x 9.8]

⇒ 320N - 29.40N

⇒ 290.6 N

Therefore, the scale will read 290.6 N when the copper piece is submerged in water.

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Answer:

The answer to this question can be defined as follows:

Explanation:

Advantage:

Answer:

please find attached pdf

Explanation:

Answer:

The answer to the following question is given below.

Explanation:

This means a mixture of interconnected, interlinked, or interactive elements that establish the collaborative entity or entities.  

Scalar quantities have magnitude only, while vector quantities have magnitude and direction. Scalars can be added algebraically, while vectors follow specific rules. Scalars have a single value, while vectors require representation with magnitude and direction.

Scalar quantities and vector quantities are two fundamental types of physical quantities used in physics. Here are five key differences between scalar and vector quantities:

1. Definition: Scalar quantities are defined by magnitude only, meaning they have a numerical value but no specific direction. Examples of scalars include time, temperature, mass, and speed. In contrast, vector quantities have both magnitude and direction. Examples of vectors include displacement, velocity, force, and acceleration.

2. Representation: Scalar quantities are represented by a single numerical value or variable, often accompanied by appropriate units. For instance, temperature can be represented by a value like 25 degrees Celsius. Vector quantities, on the other hand, require a representation that includes both magnitude and direction. This can be achieved using vectors or by using a combination of numerical values and angles.

3. Addition and Subtraction: Scalar quantities can be added or subtracted algebraically by simply considering their numerical values. For example, adding two temperatures of 10 degrees Celsius and 15 degrees Celsius gives a result of 25 degrees Celsius. In contrast, vector quantities follow different rules for addition and subtraction. Vector addition involves considering both the magnitude and direction of the vectors, using methods such as the parallelogram law or the triangle law.

4. Algebraic Operations: Scalar quantities can undergo all basic algebraic operations, such as multiplication, division, addition, and subtraction. These operations apply only to the numerical values of the scalars. Vector quantities, however, have additional operations specific to vectors, including dot product and cross product, which involve both the magnitude and direction of the vectors.

5. Physical Interpretation: Scalar quantities represent quantities that can be fully described by a single value, such as the magnitude of a quantity. For example, the speed of an object is a scalar that represents the magnitude of its velocity. Vector quantities, on the other hand, have physical interpretations that involve both magnitude and direction. For instance, displacement represents both the distance and the direction from the starting point to the endpoint.

In summary, scalar quantities have magnitude only, while vector quantities have both magnitude and direction. Scalars are represented by single numerical values, while vectors require representation with both magnitude and direction. Scalar quantities can be algebraically added or subtracted, whereas vector quantities follow specific rules for vector addition and subtraction. Scalars can undergo all basic algebraic operations, while vectors have additional vector-specific operations. Scalar quantities represent fully describable quantities, while vector quantities require consideration of both magnitude and direction for a complete description.

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It's important for the sonographer to employ a combination of these techniques while considering patient factors, gallstone characteristics, and equipment capabilities to effectively demonstrate acoustic shadowing with small gallstones during the ultrasound examination.

The sonographer can utilize several techniques to demonstrate acoustic shadowing with small gallstones during an ultrasound examination. Acoustic shadowing occurs when the sound waves encounter a highly reflective or attenuating structure, such as a gallstone, causing a shadow to appear behind it. Here are some techniques commonly used:

Adjusting imaging angle: Changing the angle of the ultrasound beam relative to the gallstone can help accentuate the shadowing effect. By angling the transducer appropriately, the sonographer can optimize the visualization of the gallstone and the resulting shadow.

Utilizing higher-frequency transducers: Higher-frequency transducers provide better resolution and are more sensitive to small structures like gallstones. Using a high-frequency transducer can enhance the ability to visualize and demonstrate acoustic shadowing from small gallstones.

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Answer:

Work done = 80 gm/s

Explanation:

Given:

Final velocity (v) = 4 m/s

Initial velocity (u) = 0 m/s

Mass of ball (m) = 40 g

Find:

Work done.

Computation:

Using work energy rule

Work done = Change in kinetic energy

Work done = 1/2[mv-mu]

Work done = 1/2[(40)(4) - (40)(0)]

Work done = 1/2[(40)(4)]

Work done = 80 gm/s

Answer:

Equation for general relativity

Explanation:

Answer:

  cue ball final: 0.85 m/s at N65°W

  8-ball final: 1.27 m/s at N12°E

Explanation:

In a perfectly elastic collision, both momentum and energy are conserved. The momentum is the sum of products of mass and velocity. The energy is half the product of mass and the square of velocity. The difference of "particle" velocities changes sign as a consequence of the collision.

__

If we let the masses be m1 and m2, the corresponding initial velocities be v1 and v2, and the final velocities be u1 and u2, we have ...

  m1·u1 +m2·u2 = m1·v1 +m2·v2 . . . . . . . conservation of momentum

  u1 -u2 = v2 -v1 . . . . . . . . . . . . . . . relative velocity sign changes

This pair of linear equations can be solved for u1 and u2 in any of the usual ways to give ...

  u1 = v1(m1 -m2)/(m1 +m2) + v2(2·m2)/(m1 +m2)

  u2 = v2(m2 -m1)/(m1 +m2) +v1(2·m1)/(m1 +m2)

__

Using angle measures as clockwise from north, we are given ...

  cue ball: m1 = 0.17 kg, v1 = 1.2∠10° m/s

  eight ball: m2 = 0.15 kg, v2 = 0.89∠-70° m/s

A suitable calculator can find the final velocities using the above equations.

The first attachment shows the calculations using a TI-84 work-alike calculator.

  cue ball final: 0.85 m/s at N65°W

  8-ball final: 1.27 m/s at N12°E

The second attachment shows a vector diagram of the velocities.

The measurement of 32.3 kJ is equivalent to approximately 7,726.94 calories.

Energy can be measured in different units, such as calories and joules. To convert between these units, we need to know the conversion factor.

One joule (J) is equivalent to 0.239005736 calories (cal). Therefore, to convert kilojoules (kJ) to calories, we need to multiply the value in kilojoules by the conversion factor.

In this case, we have 32.3 kJ. To convert it to calories, we multiply 32.3 by the conversion factor:

32.3 kJ * 0.239005736 cal/J ≈ 7,726.94 calories

Hence, the measurement of 32.3 kJ is approximately equivalent to 7,726.94 calories. It's important to note that the conversion factor used here is an approximate value, and the exact conversion factor may vary slightly depending on the specific definitions and standards used for calories and joules.

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The hill must be at least 30 meters high for the riders to experience weightlessness at the top of the loop.

Let h be the height of the hill, and let v be the velocity of the roller coaster at the top of the loop. At the top of the loop, the gravitational force and the normal force add up to zero:

mg + N = 0

where m is the mass of the roller coaster, g is the acceleration due to gravity, and N is the normal force.

The centripetal force required to keep the roller coaster moving in a circle of radius R is, Fc = mv²/R, where Fc is the centripetal force.

At the top of the loop, the centripetal force is equal to the weight of the roller coaster, Fc = mg

Setting these two expressions for Fc equal to each other,

mv²/R = mg

Solving for v,

v = sqrt(gR)

Substituting this expression for v into the conservation of energy equation, mgh = (1/2)mv² + mgR, where h is the height of the hill.

Substituting the expression for v,

mgh = (1/2)mgR + mgR

Solving for h,

h = 3R/2

Substituting the given value of R = 20 m, h = 30 m.

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Aceleration = change in speed / time for the change

Change in speed = (later speed) minus (earlier speed)                                

Change in speed = (1 m/s) - (3 m/s)  =  -2 m/s

Time for the change = 2 seconds

Acceleration = (-2 m/s) / (2 seconds)

Acceleration = -1 m/s²

Answer:

The answer should be 100 if not try 200

Explanation:

d=v x t

400m=4m/s x t

/4           /4

100=t

Answer:

Rheostat, adjustable resistor used in applications that require the adjustment of current or the varying of resistance in an electric circuit. The rheostat can adjust generator characteristics, dim lights, and start or control the speed of motors.

Explanation:

Alumunium has an atomic number  (Z) of 13 So, its electronic configuration is [Ne] 3s2 3p1 Hence, it needs to lose 3 electrons to attain stable configuration, hence its valency is three. Oxygen has an atomic number (Z) of 18 So, its electronic configuration is [He]2s23p1.

This formula's subscripts (2 and 3) indicate how so many atoms will make up each unit of a compound.The 2 denotes the presence of two aluminum atoms and the 3 denotes the presence of three oxygen atoms.

So there's also aluminum, plus carbon now and nine oxygens.Therefore, the sum of the atoms is two + three plus nine, which equals 14.In the formula given after the molecule, there are therefore 14 atoms.The issue has now been resolved.

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Answer:

24.5 m/s

Explanation:

Since the work done by the electric field on the charge equals the kinetic energy of the ball, then

qV = 1/2mv²

and v = √(2qV/m)

where q = charge = + 0.05 C, V = potential difference = 12.0 V, m = mass of ball = 2.0 g = 0.002 kg

Substituting the values into v, we have

v = √(2 × + 0.05 C × 12.0 V/0.002 kg)

= √(1.2 CV/.002 kg)

= √(600 CV/kg)

= 24.5 m/s

Answer:

Jethro Wood is the one who designed the one-piece wrought iron plow.

Answer:

70m/s2

Explanation:

acceleration is equal to force over mass,

a=4200/60

= 70m/s2

The converse of the statement "No pilots are mechanics" is No mechanics are pilots.

Hence, the correct option is A.

The converse of a statement switches the subject and the predicate and negates both. In the original statement, the subject is "pilots" and the predicate is "mechanics."

The original statement states that there is no overlap between pilots and mechanics. In the converse statement, the subject becomes "mechanics" and the predicate becomes "pilots," and it still states that there is no overlap between the two groups.

Therefore, The converse of the statement "No pilots are mechanics" is No mechanics are pilots.

Hence, the correct option is A.

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Answer: Rob's father does love him unconditionally but he also just wants rob to have a successful future and be able to have money for his own car and other necessities needed for when he is on his own.

Explanation:

Thermal insulation reduces unwanted heat loss and also reduces unwanted heat gain.

Insulation creates a barrier between the hot and the cold object by reducing heat transfer by either reflecting light radiation.

Insulating materials are bad conductors of electricity and heat. So, insulating reduces the heat loss via conduction.

Thermal energy is prevented to increase the temperature of building in summers and decrease in winters. The thermal energy transfer plays vital role in insulating a building.

Thus Thermal insulation reduces unwanted heat loss and also reduces unwanted heat gain.

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