What’s the answers pls

Based on the net present value profile, Project H has a higher NPV than Project E.

To compare the net present value (NPV) of Project E and Project H, we need to calculate the present value of cash flows for each project and determine which one has a higher NPV. The cash flow patterns for the two projects are as follows:

Project E:

Initial investment: -$100,000

Cash flows for Year 1: $40,000

Cash flows for Year 2: $50,000

Cash flows for Year 3: $60,000

Project H:

Initial investment: -$120,000

Cash flows for Year 1: $60,000

Cash flows for Year 2: $50,000

Cash flows for Year 3: $40,000

To calculate the present value of cash flows, we need to discount them using an appropriate discount rate. The discount rate represents the required rate of return or the cost of capital for the company. Let's assume a discount rate of 10%.

Using the formula method, we can calculate the present value (PV) of each cash flow and sum them up to obtain the NPV for each project:

For Project E:

PV = $40,000/(1 + 0.10)^1 + $50,000/(1 + 0.10)^2 + $60,000/(1 + 0.10)^3

PV = $36,363.64 + $41,322.31 + $45,454.55

PV = $123,140.50

For Project H:

PV = $60,000/(1 + 0.10)^1 + $50,000/(1 + 0.10)^2 + $40,000/(1 + 0.10)^3

PV = $54,545.45 + $41,322.31 + $30,251.14

PV = $126,118.90

Using the financial calculator method, we can input the cash flows and the discount rate to calculate the NPV directly. By entering the cash flows for each project and the discount rate of 10%, we find that the NPV for Project E is approximately $123,140.50 and the NPV for Project H is approximately $126,118.90.

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Answer:

3 hours and 18 minutes.

Step-by-step explanation:

5/6 x 4 = 10/3 = 3.33 hours or 3 hours and 18 minutes.

Answer:

the volume of the square pyramid is 2430 cubic cm

Answer:

1296 cm³

Step-by-step explanation:

V = a² x [√s²- (a/2)²] / 3

a = 18 cm

s = 15 cm

V = 18² x [√15²-(18/2)²] / 3 = 18² x [√225-81] / 3

V = 324 x (√144/3) = 1296 cm³

Answer:

Proof in explanation

Step-by-step explanation:

Trigonometric Identities

The basic trigonometric identity is:

\(\sin^2\theta+\cos^2\theta=1\)

We'll use it and some basic algebra to prove that, given:

\(a sin^3\theta+b cos^3\theta=sin\theta cos\theta\)

And

\(a\sin\theta-b\cos\theta=0\)

Then

\(a^2+b^2=1\)

From the equation:

\(a\sin\theta-b\cos\theta=0\)

We have:

\(a\sin\theta=b\cos\theta\qquad [1]\)

The equation

\(a sin^3\theta+b cos^3\theta=sin\theta cos\theta\)

Can be rewritten as

\(a\sin\theta \sin^2\theta+b \cos^3\theta=\sin\theta \cos\theta\)

Replacing [1]:

\(b\cos\theta \sin^2\theta+b \cos^3\theta=\sin\theta \cos\theta\)

Taking the common factor:

\(b\cos\theta (\sin^2\theta+ \cos^2\theta)=\sin\theta \cos\theta\)

The expression in parentheses is 1, thus:

\(b\cos\theta =\sin\theta \cos\theta\)

Dividing by \(\cos\theta\)

\(b=\sin\theta\)

Replacing in

\(a\sin\theta=b\cos\theta\)

We have

\(a\sin\theta=\sin\theta\cos\theta\)

Dividing by \(\sin\theta\)

\(a=\cos\theta\)

Now:

\(a^2+b^2=(\cos\theta)^2+(\sin\theta)^2\)

This expression is 1, thus it's proven:

\(\boxed{a^2+b^2=1}\)

Answer:

1)\(625^-\frac{1}{4}\)

=> \((5^4)^-^\frac{1}{4}\)

=> (4 and 4 get simplified so we are left with 5 raised to the power-1)

=> \(5^-^1\)

=>\((a^m)^n =a^m^n\)

=> \(a^-^n=\frac{1}{a} ^n\)

=>\(\frac{1}{5}\)

​

Step-by-step explanation:

Answer:

20/18

Step-by-step explanation:

Answer:10/9 exact form mixed # 1 1/9

Step-by-step explanation:reduce the expression, if possible, by cancelling the common factors.

The joint relative frequency for school children who plan to attend camp and have swimming lesson is 44%.

The correct option to the given question is option d.

We are required to find the joint relative frequency for school children who plan to attend camp and have swimming lessons, rounded to the nearest percent.

To find the joint relative frequency, we use the formula as follows:

Joint relative frequency = frequency of interest / total frequency

Joint relative frequency for school children who plan to attend camp and have swimming lessons = 42 / 96

(As we are looking for the students who plan to attend camp and have swimming lessons, we are interested in the first column of the table and the entry at the intersection of the first row and second column.)

Joint relative frequency for school children who plan to attend camp and have swimming lessons = 0.4375

Joint relative frequency for school children who plan to attend camp and have swimming lessons (rounded to the nearest percent) = 44%(option d).

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9514 1404 393

Answer:

Step-by-step explanation:

Let Q represent the number of quarters. Then (Q-4) is the number of dimes, and the total amount of money is ...

  25Q +10(Q -4) = 520

  35Q = 560 . . . . . add 40

  Q = 560/35 = 16

Ngo has 16 quarters and 12 dimes.

*see attachment showing the 2 boxes

Answer:

3 ft²

Step-by-step explanation:

==>Given:

Box J with the following dimensions:

L = 4.5ft

W = 3ft

H = 2ft

Box F:

L = 3ft

W = 3ft

H = 3ft

==>Required:

Difference between the surface area of box J and box F

==>Solution:

Surface area = 2(WL + HL + HW)

=>S.A of box J = 2(3*4.5 + 2*4.5 + 2*3)

= 2(13.5 + 9 + 6)

= 2(28.5)

S.A of box J = 57 ft²

=>S.A of box F = 2(3*3 + 3*3 + 3*3)

= 2(9 + 9 + 9)

= 2(27)

S.A of box F = 54 ft²

Difference between box J and box F = 57 - 54 = 3 ft²

Based on equations, Angus worked 6 hours on Saturday and 10 hours at his after-school job last week earning a total of $127.80.

The hourly rate at Angus' Saturday job = $8.80

The hourly rate at Angus' after-school job = $7.50

The total earnings last week = $127.80

Let the hours Angus worked at Saturday job = x

Let the hours Angus worked after-school = 4 + x

The total hours worked = x + x + 4

2x + 4

The total earnings last week 127.80 = 8.8x + 7.5x + 4 (7.5)

127.80 = 8.8x + 7.5x + 30

127.8 - 30 = 16.3x

x = 6 hours

x + 4 = 10 hours

2x + 4 = 16 (12 + 4)

Check:

Earnings at Saturday job = $52.80 ($8.80 x 6)

Earnings at after-school job = $75.00 ($7.50 x 10)

Total earnings = $127.80

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The mean of the test is 20.

To determine the mean of the test, we need to use the information provided about the scores falling above the mean in terms of standard deviations.

Let's denote the mean of the test as μ, and the standard deviation as σ.

We are given that a score of 29 falls three standard deviations above the mean, so we can write this as:

29 = μ + 3σ

Similarly, we are told that a score of 23 falls one standard deviation above the mean, which can be expressed as:

23 = μ + σ

Now we have a system of two equations with two variables (μ and σ). We can solve this system of equations to find the values of μ and σ.

From the second equation, we can isolate μ:

μ = 23 - σ

Substituting this value into the first equation, we have:

29 = (23 - σ) + 3σ

Simplifying the equation, we get:

29 = 23 + 2σ

2σ = 29 - 23

2σ = 6

σ = 3

Substituting the value of σ back into the second equation, we find:

μ = 23 - 3

μ = 20

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Answer:

can u add a picture cause i dont understand what ur saying at all

Step-by-step explanation:

a) The customs duty on the car would be $1,350,000.

b) The imported price of the bus would be $858,000.

(a) To calculate the customs duty on a car with an imported price of $3,000,000, we can multiply the imported price by the duty rate of 45%:

Customs duty = $3,000,000 * 0.45 = $1,350,000.

(b) To calculate the imported price of a bus if the amount paid, including customs duty, is $1,560,000, we need to determine the portion of the total amount that represents the customs duty. Since the customs duty is 45% of the imported price, we can set up the following equation:

Customs duty = $1,560,000 * 0.45.

Solving for the customs duty:

Customs duty = $702,000.

Now, we can subtract the customs duty from the total amount to find the imported price:

Imported price = $1,560,000 - $702,000 = $858,000.

In summary, the customs duty on a car with an imported price of $3,000,000 would be $1,350,000. On the other hand, if the amount paid for a bus, including customs duty, is $1,560,000, the imported price of the bus would be $858,000.

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The distance of a rock after three seconds will be 144 feet.

A function is an assertion, concept, or principle that establishes an association between two variables.

Let's use the formula for direct variation, which is:

d = kt²

64 = k(2²)

64 = 4k

k = 16

Now we can use this value of k to find the distance when t = 3:

d = 16 × (3²)

d = 16(9)

d = 144

Therefore, the rock will fall 144 feet in 3 seconds.

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The complete question is given below.

The distance, d, that a rock falls when dropped from a cliff varies directly as the square of time, t, the rock is falling. If a rock falls 64 feet in 2 seconds, how far will it fall in 3 seconds?

Answer: A: Greater than the whole number

Step-by-step explanation:

5/2 x 9 = 45/2 = 22.5

Answer:

what i would do is if you are in real school not online ask you teacher to give extra stuff like:

Step-by-step explanation:

extra like: missing assinments, extra credit work, retake any tests etc. but if your online you can retake tests and go ahead of work. hope this helps!

Answer: 11

Step-by-step explanation:

4x+3

4(2)+3

8+3

11

Answer:

J)  \(\frac{17}{24}\)

Step-by-step explanation:

\(\frac{3}{8} +\frac{1}{3} \\\\\frac{9}{24} +\frac{8}{24} = \frac{17}{24}\)

Find the common denominator ^^

Answer:

17/24

Step-by-step explanation:

3/8× 3/3=9/24

1/3×8/8=8/24

8/24 +9/24= 17/24

Answer:

3f = s

Step-by-step explanation:

f = tickets sold friday

s = tickets sold saturday

The Equation is  x+ 3x = 360.

90 tickets sold on Friday and 270 Tickets sold on Saturday.

A branch of mathematics known as algebra deals with symbols and the mathematical operations performed on them.

Variables are the name given to these symbols because they lack set values.

In order to determine the values, these symbols are also subjected to various addition, subtraction, multiplication, and division arithmetic operations.

Given:

The drama department sold a total of 360 tickets to their Friday and Saturday night shows.

So, Friday ticket sold = 3 x Saturday ticket sold.

let the tickets sold on Friday be x.

So, x+ 3x = 360

4x= 360

x= 360/ 4

x= 90

Hence, 90 tickets sold on Friday and 270 Tickets sold on Saturday.

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Answer:

1 3 5 15 and its a composite

Step-by-step explanation:

i went online

Step-by-step explanation:

15 can be factorised as ,

1 × 15

3 × 5

5 × 3

15 × 1

so all the factors of 15 are 1 , 3 , 5 and 15

since 15 has more than 2 factors that is more than 1 and itself, so it is composite number.

And we are done!

- Rishabh

Answer: One way to measure 3 1/6 teaspoons of salt using 1/3 -teaspoon and 1/2 -teaspoon measuring spoon is to use:

the 1/2 teaspoon measuring spoon 3 times to measure 3/2 = 1 1/2 teaspoons

and use the 1/3 teaspoon measuring spoon 6 times to measure 6 * 1/3 = 2/3 teaspoons

3 1/2 + 2/3 = 3 1/6

Another way to measure 3 1/6 teaspoons of salt using 1/3 -teaspoon and 1/2 -teaspoon measuring spoon is to use:

the 1/3 teaspoon measuring spoon 6 times to measure 6 * 1/3 = 2/3 teaspoons

and use the 1/2 teaspoon measuring spoon 6 times to measure 6 * 1/2 = 3 teaspoons

3 + 2/3 = 3 1/6

So, there are two ways to measure 3 1/6 teaspoons of salt using 1/3 -teaspoon and 1/2-teaspoon measuring spoon, one is by using 3 times 1/2 teaspoon measuring spoon and 6 times 1/3 teaspoon measuring spoon and the second one is by using 6 times 1/3 teaspoon measuring spoon and 3 times 1/2 teaspoon measuring spoon.

Step-by-step explanation:

\(~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ E(\stackrel{x_1}{2}~,~\stackrel{y_1}{3})\qquad F(\stackrel{x_2}{3}~,~\stackrel{y_2}{1}) ~\hfill EF=\sqrt{(~~ 3- 2~~)^2 + (~~ 1- 3~~)^2} \\\\\\ ~\hfill EF=\sqrt{( 1)^2 + ( -2)^2} \implies \boxed{EF=\sqrt{ 5 }}\)

\(F(\stackrel{x_1}{3}~,~\stackrel{y_1}{1})\qquad D(\stackrel{x_2}{-1}~,~\stackrel{y_2}{-1}) ~\hfill FD=\sqrt{(~~ -1- 3~~)^2 + (~~ -1- 1~~)^2} \\\\\\ ~\hfill FD=\sqrt{( -4)^2 + ( -2)^2} \implies \boxed{FD=\sqrt{ 20 }} \\\\\\ D(\stackrel{x_1}{-1}~,~\stackrel{y_1}{-1})\qquad E(\stackrel{x_2}{2}~,~\stackrel{y_2}{3}) ~\hfill DE=\sqrt{(~~ 2- (-1)~~)^2 + (~~ 3- (-1)~~)^2} \\\\\\ ~\hfill DE=\sqrt{( 3)^2 + (4)^2} \implies DE=\sqrt{ 25 }\implies \boxed{DE=5} \\\\[-0.35em] \rule{34em}{0.25pt}\)

\(E(\stackrel{x_1}{2}~,~\stackrel{y_1}{3})\qquad F(\stackrel{x_2}{3}~,~\stackrel{y_2}{1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{1}-\stackrel{y1}{3}}}{\underset{run} {\underset{x_2}{3}-\underset{x_1}{2}}} \implies \cfrac{ -2 }{ 1 } \implies - 2 \\\\[-0.35em] ~\dotfill\)

\(F(\stackrel{x_1}{3}~,~\stackrel{y_1}{1})\qquad D(\stackrel{x_2}{-1}~,~\stackrel{y_2}{-1}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-1}-\stackrel{y1}{1}}}{\underset{run} {\underset{x_2}{-1}-\underset{x_1}{3}}} \implies \cfrac{ -2 }{ -4 } \implies \cfrac{1 }{ 2 } \\\\[-0.35em] ~\dotfill\)

\(D(\stackrel{x_1}{-1}~,~\stackrel{y_1}{-1})\qquad E(\stackrel{x_2}{2}~,~\stackrel{y_2}{3}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{3}-\stackrel{y1}{(-1)}}}{\underset{run} {\underset{x_2}{2}-\underset{x_1}{(-1)}}} \implies \cfrac{3 +1}{2 +1} \implies \cfrac{4 }{ 3 }\)

Answer:

Step-by-step explanation:

Answer: 10.5/6 - 6.5/6 = 2/3

Step-by-step explanation:

The answer is 10.5/6 - 6.5/6 = 2/3

The density of the unknown metal exists 8.9 g/mL.

The mass of an object divided by its volume is how dense it is. The gram per cubic centimeter (g/cm³) unit of density is frequently used. How much mass is present in a given area is referred to as density. Try to picture a drawer full of socks. Its density is particular. Consider that when you remove a sock, the drawer's density changes. This is due to the socks' shifting mass while the drawer's remaining constant volume.

The definition of density is the mass of a substance per unit volume. The degree to which matter is packed together is fundamentally measured by density. It is a specific physical quality of a specific object. Greek scientist Archimedes is credited with discovering the density principle.

The density (D) is equal to mass (m) divided by volume (V): D = m/V

To find the mass of the object:

m = 156 g - 105.5 g = 50.5 g

To find the volume of the volume:

V = 30.7 mL - 25 mL = 5.7 mL

The density is:

D = m/V = 50.5 g  / 5.7 mL = 8.9 g/mL

Therefore, the density exists 8.9 g/mL.

The complete question is:

A graduated cylinder was filled with water to the 25.0 mL mark and weighed. Its mass was 105.5g. An object made of an unknown metal was placed in the cylinder and completely submerged in the water. The water level rose to 30.7 mL. When reweighed, the cylinder, water and metal object had a total mass of 156.0g. Based on these measurement, what is the density of the unknown metal?

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The value of the y is 18 when x = 5.

Given,

In the question:

If y varies inversely as x

and, y=9 when x =10

To find the value of y when x = 5

Now, According to the question:

Based on the given conditions:

Formulate:

y = k/x

Calculate and substitute y = 9 , x = 10 into y = k/x

9 = k/10

k = 90

To find the equation of the function:

y = 90/x

Calculate and substitution x = 5 into y = 90/x

y = 18

Hence, The value of the y is 18 when x = 5.

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Answer: it’s 3/4

Step-by-step explanation: you have to make the Denominator equal for all of them In order to be able to compare. So if you make the denominator equal to 36 you then have to multiply the numerator by the same number you did for the denominator. Once doing that you will find that 24/36 < 27/36 < 28/36

Plz brainliest.

Given

To find

we know that

Inserting the value of radius