The meaning of Referential Orientation vs. Expressive Orientation refers to two different ways of using language.
Referential Orientation focuses on conveying factual information and objective meaning, while Expressive Orientation emphasizes the speaker's emotions, personal feelings, and subjective experiences. In summary, Referential Orientation is centred around providing accurate information, and Expressive Orientation prioritizes expressing emotions and personal experiences.Referential orientation focuses on conveying information objectively, while expressive orientation emphasizes the expression of emotions and personal experiences through vivid language and metaphors.
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Determine the equivalent capacitance in μF.
The equivalent capacitance is 21 μF.
We are given that,
capacitance =c₁ =9 μF
capacitance = c₂ =6 μF
capacitance = c₃ = 3 μF
capacitance = c₄ =2 μF
capacitance = c₅ = 1 μF
Thus, If the capacitor is connected in parallel the equivalent capacitance, cₐ can be calculated by the equation,
cₐ= c₁+c₂+c₃+c₄+c₅
cₐ = 9 +6 +3 +2+1 μF
cₐ = 21 μF
Therefore , The equivalent capacitance would be 21 μF.
What is equivalent capacitance?In the electrical engineering, the equivalent capacitance just often abbreviated as the C eq has the measurement of the total combined electric charge that held in two or more capacitors connected in series or the parallel.
A capacitor has an electrical device that stores electrical energy into the electric field. Typically, a capacitor has two electrical leads that are separated by a dielectric or other insulating substance.
Therefore, If the capacitor is connected in parallel the equivalent capacitance, cₐ can be calculated by the equation,
cₐ= c₁+c₂+c₃+c₄+c₅
cₐ = 9 +6 +3 +2+1 μF
cₐ = 21 μF
Therefore , The equivalent capacitance would be 21 μF.
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The yield stress of a steel is 250Mpa. A steel rod used for implant in a femurneeds to withstand 29KN. What should the diameter of the rod be not to deform
Answer:
r = 1.922 mm
Explanation:
We are given;
Yield stress; σ = 250 MPa = 250 N/mm²
Force; F = 29 KN = 29000 N
Now, formula for yield stress is;
σ = F/A
A = F/σ
Where A is area = πr²
Thus;
r² = 2900/250π
r² = 3.6924
r = √3.6924
r = 1.922 mm
Which of these is not a good rule to follow when caring for an injured person at an accident scene?
When caring for an injured person at an accident scene, it is important to follow certain rules to ensure their safety and wellbeing.
However, not all rules are good to follow, and some may even be harmful. For example, one rule that is not good to follow is to move an injured person without proper training or equipment.
This can cause further injury and even paralysis. It is important to wait for medical professionals to arrive and assess the situation before attempting to move the injured person.
Another rule that is not good to follow is to administer medication without proper knowledge or training. This can lead to adverse reactions and further harm to the injured person.
It is best to leave medication administration to medical professionals. Following these rules will help ensure the safety and wellbeing of the injured person.
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(viii) A capacitor of0.02 4F is larger than
(a 0.000020 F
(b) 200,000 pF
(c) 2,000 pF
(d) all of the above
Answer:
Answer is. (d) all of the above
Answer:
my answer is D
Explanation:
all of the above
how can an airplane fly in math form? maybe physics...
Answer:
the aeroplane can fly throw the petrol and
There is a 8 bit binary counter, based on 74LS16x family.It presents on the output the next sequence periodically :32,33,...66 -> 85,86,....130 ->173,174,...199 -> 32,33,..
1. Design the block- diagram of the network! 2. Specify the input and output signals of the blocks of the block-diagram, and the tasks of the boxes (what happens between the input and output signals of the block)! 3. Design the logical network of the boxes (you have to apply the signal-names of the block-diagram! You may apply any MSI circuits, which we studied (4 bit parallel adder, 4 bit cascadable comparator, 4 bit 7416x binary uo-counter,...) and the neccessary number of NAND/NOR/AND/OR/EXCLUSIVE OR/INCLUSIVE OR gates and SR/JK/DG/D/T flip-flops.
The block diagram of the network consists of various components and connections that enable the functioning of the 8-bit binary counter based on the 74LS16x family.
What are the input and output signals of the blocks in the block diagram, and what are the tasks of each box in terms of signal processing?The logical network of the boxes in the block diagram involves the use of MSI circuits, such as the 4-bit parallel adder, 4-bit cascadable comparator, and 4-bit 7416x binary up-counter, along with the necessary number of logic gates and flip-flops. The input signals of the blocks in the block diagram include the clock signal, control signals, and data signals. The clock signal is used to synchronize the operations of the counter, while the control signals determine the specific sequence and timing of the output values. The data signals represent the binary values that are processed and propagated through the counter.
The tasks of the boxes in the block diagram involve performing specific operations on the input signals to generate the desired output sequence. For example, the 4-bit parallel adder can be used to increment the binary count by one, while the cascadable comparator can be utilized to compare the current count with predefined values to trigger specific actions. The 7416x binary up-counter can be employed to maintain the count and propagate it to subsequent stages.
In addition to these MSI circuits, logic gates such as NAND, NOR, AND, OR, XOR, and XNOR, as well as flip-flops like SR, JK, D, and T, are used to implement the necessary logic operations and sequential behavior within the counter.
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Suppose, you are cleaning your reading table and keeping your books one upon another. Your
books are numbered are as 1,2,3,4,5. But you want your books to be ordered in such a way so
that when you pick up the first book and last book, those should be always 3 and 1, respectively.
The rest three books (2, 4 and 5) can be in any order.
Which collection is suitable here? Show its adding and removing methods in operation.
Answer:
it's answer B. I took the test
When data are produced and stored as numeric, textual, or visual information, it varies in
structure
access
scope
format
When data analysis is produced and stored as numeric, textual, or visual information, it varies in format. There are different formats in which data can be stored, such as spreadsheets, databases, or plain text files. Each format has its own advantages and disadvantage.
The structure of data refers to how it is organized and arranged. This can include the type of data, such as numbers, text, or dates, as well as the way it is grouped and categorized. The structure of data can have a significant impact on its analysis, as different structures require different methods of analysis.
In conclusion, when data is produced and stored as numeric, textual, or visual information, it varies in format, structure, access, and scope. Understanding these factors is important for effective data analysis and management. and the choice of format depends on the nature of the data and the purpose of the analysis.
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Which way do you turn the wrench to tighten the insert on this cam type holder?
Answer:
right !
Explanation:
Help this is very hard and I don't get it
Answer:
yes it is very hard you should find a reccomended doctor to aid in your situation. But in the meantime how about you give me that lil brainliest thingy :p
assuming complementary inputs are available, the minimum number of transistors needed to realize a two input xor gate is:
Assuming complementary inputs are available, the minimum number of transistors needed to realize a two input xor gate is 4.
If two inputs work well together in the production process, they are said to be complements. Since the inputs are used in fixed proportions, if the price of one input lowers, more of it will be sought after, increasing the demand for the other input.
In this study, a model of anticompetitive exclusive contracts with complimentary inputs is built. A downstream company converts a variety of complementary inputs into finished goods. When complementary input providers hold a dominant position in a specific input market, upstream competition price within that market benefits both the downstream firm and the complementary inputs providers by driving up complementary input prices.
Thus, even when entry that is socially optimal is permitted, the downstream firm is unable to generate higher profits. Therefore, even in the absence of scale economies, downstream competition, and relationship-specific investment, the inefficient incumbent provider can prevent socially efficient entrance by employing exclusive contracts.
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1.3. If the surface tension coefficient of a fluid is 0,07 N/m and the radius
of the droplet is 2,5 mm. calculate:
1.3.1 surface tension force
(2)
1.3.2 difference in pressure of the droplet
(1)
Answer:
A) F = 0.011 N
B) ΔP = 5.6 N/m²
Explanation:
We are given;
surface tension coefficient; S = 0.07 N/m
Radius; r = 2.5 mm = 0.025 m
A) Formula to find the surface tension force(F) is given by;
F = SL
Where L is effective length = 2πr
F = 0.07 × 2π × 0.025
F = 0.011 N
B) Formula for difference in pressure droplet is;
ΔP = 2S/r
Thus;
ΔP = (2 × 0.07)/0.025
ΔP = 5.6 N/m²
Hi. Help me guyz.
Read the resistance below indicated by the letters.
Answer:
2/4
7/2
92/1
83/1
9/1
93/0
Explanation:
R
K
K
R
K
R
I don't really know the answer
Determine an expression for the vorticity of the flow field described by V=−xy3^+y4^j Is the flow irrotational?
This problem can be solved using the pascal principle, which is applied for both pressures and volumes. In this case we use the definition of volumes, which says that the volume displaced fluid on one side of the Pistons should be equal to the volume displaced on the other side of the piston.
What is force?The force exerted at the large piston will be double in magnitude in comparison with the force applied at the smaller piston.
We know, according to the pascal's law,
The pressure applied at any point in the incompressible fluid is equal in magnitude at each and every point.
So,
P = Force/Area
Where P is pressure,
If pressure is same, then we can write,
F₁/A₁ = F₂/A₂
Where,
F₁ is the force applied at the small piston,
A₁ is the area of the smaller piston,
F₂ is the force at the larger piston,
A₂ is the area of the larger piston,
It is also given that, area if the larger piston is two times the area of the smaller piston so,
A₂ = 2A₁
So, putting the values we get,
F₂/F₁ = 2
So, F₂ = 2F₁
It means that the force exerted by the larger piston will be double in magnitude.
Therefore, In this case we use the definition of volumes, which says that the volume displaced fluid on one side of the Pistons should be equal to the volume displaced on the other side of the piston.
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A spherical tank with a radius of 0.25 m is filled with water (ρ = 1000 kg/m3). Calculate the mass and weight of the water in SI units.
The mass of the water is 65.5 kg. The weight of the water is 641.9 kgm/s²
What is the mass of a spherical tank?The mass of a spherical tank is the space contained in the tank. The mass of the spherical tank can be determined by first finding the volume of the tank, then using the relation of density, mass, and volume to find the mass.
From the given parameter:
The radius of the tank = 0.25 mThe density of the water = 1000 kg/m³The volume of the tank can be determined by using the formula:
\(\mathbf{V = \dfrac{4}{3}\pi r^3}\)
\(\mathbf{V = \dfrac{4}{3}\pi (0.25)^3}\)
V = 0.0655 m³
Using the relation that:
\(\mathbf{Density = \dfrac{mass}{volume}}\)
\(\mathbf{1000 \ kg/m^3= \dfrac{mass}{0.0655 \ m^3}}\)
mass = 1000 kg/m³ × 0.0655 m³
mass = 65.5 kg
The weight of the water can be determined by using the formula:
Weight = mass × gravity (i.e. acceleration due to gravity)
Weight = 65.5 kg × 9.8 m/s²
Weight = 641.9 kgm/s²
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The mass of the water in spherical tank is 65.4kg.
The weight of the water in spherical tank is 640.8 Newtons.
Given the data in the question:
Radius of the spherical tank; \(r = 0.25m\)Density of water; \(p = 1000kg/m^3\)Mass of water; \(m_w = \ ?\)
Weight of water; \(Ww = \ ?\)
DensityDensity \(p\) is simply the measure of the compactness of the mass of a substance. It is expressed as;
\(Density = \frac{Mass}{Volume}\)
To determine the mass and weight of the water in spherical tank,
we calculate the Volume of the spherical tank.
\(V = \frac{4}{3}\pi r^3\)
We substitute in our given values
\(V = \frac{4}{3} * \pi * (0.25m)^3\\ \\V = \frac{4}{3} * \pi * 0.015625m^3\\\\V = 0.0654 m^3\)
Now, we calculate the mass of the water; using the expression above.
\(Density = \frac{Mass}{Volume}\\Mass = Density * Volume\\\)
We substitute in our values
\(Mass = 1000kg/m^3 \ *\ 0.0654m^3\\\\Mass = 65.4kg\)
Hence, the mass of the water in spherical tank is 65.4kg.
Next we calculate the Weight which is expressed as;
\(Weight = mass\ *\ Acceleration\ of\ gravity\)
Where acceleration of gravity \(g = 9.8m/s^2\)
We substitute in our values
\(Weight = 65.4kg * 9.8m/s^2\\\\Weight = 640.8kgm/s^2\\\\Weight = 640.8N\)
Therefore, the weight of the water in spherical tank is 640.8 Newtons.
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5. For what purpose do we employ the "double-truck live load model"?
6. Why do we employ dynamic impact factor to the live load model?
5.The "double-truck live load model" is employed for the purpose of determining the maximum load that a bridge or structure can sustain. It is a method used in structural engineering to analyze the stress and deflection caused by the passage of a double-truck vehicle on a bridge.
By considering the weight distribution, axle spacing, and dynamic effects of the double-truck vehicle, engineers can assess the structural integrity and ensure that the bridge or structure is designed to withstand the anticipated loads and remain safe for public use.
6.The dynamic impact factor is employed in the live load model to account for the additional dynamic effects that occur when a moving load traverses a structure.
As a vehicle or load moves across a bridge or structure, it causes dynamic vibrations and oscillations due to its motion and interaction with the structure.
The dynamic impact factor takes into consideration these dynamic effects and amplifies the live load to ensure the structural design can withstand the combined static and dynamic loads imposed by moving vehicles or loads.
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Questions: 1. How can this motherboard support 8 GB of RAM with only fout 2. CHAPT Memory What memory features, if any, are used? (Select a ply) I parity non-parity IECCI registered fully bulleredbultered I SVD What memory modules are needed the customer was 3 of dualche RAM ties and how many of each capacity are required) 3. What memory slots will be used to install the memory, based on the information provided 5. Using the Internet, a computer parts magazine, or a list of memory modules, determine the cast per numbers and quantities of memory modules you would buy. List them, along with the location when you obtained the information. 6. Will it matter if the motherboard has tin contacts in the memory slots? Why or why not? 7. Can DDR memory modules be used with this motherboard? How can you tell? 8. If this motherboard already has 1 GB of RAM installed in the DIMMO_ChanA slot and the customer would like to upgrade to 2 GB of dual-channel RAM, what memory modules are needed? (What ca pacities and how many of each capacity are required) . What suggestions, if any, would you make to the customer before researching prices? 0. What memory slots will be used to install the memory, based on the information provided? Using the Internet, a computer parts magazine, or a list of memory modules, determine the exact part numbers and quantities of memory modules that you would buy. List them, along with the location where you obtained the information. To be able to determine the correct amount and type of memory to imalna Refer to Figure 6.24 and Table 6.11 to answer the questions. This motherboard The desktop board supports either single-ordual-channel memory configuration. The board has four 240-pin DDR2 SDRAM DIMM connectors with gold-plated con provides support for unbuffered, non-registered single or double-sided Most Install a matched pair of DIMMs equal in speed and size in Follow the directions for two DIMMs and add another matched Install a matched pair of DIMMs equal in speed and size in and DIMM1 of Channel A. Install a DIMM equal in speed and total size of the DIMMs installed in Channel A in either DOM All other memory configurations result in single-channel menu Exercise 6.2 Configuring Memory on Paper Objective: Parts: Internet access or access to magazines or ads that show memory prices Procedure: the following memory configurations • Up to 2 GB utilizing 256 MB technology • Up to 4 GB utilizing 512 MB or 1 GB technology • Up to 8GB utilizing 1 GB technology DDR2 533/667/800 MHz memory, and (SPD) memory only. Motherboard with four memory slots DIMMO_Chana DIMM1_Chana DIMMO ChanB DIMM1_ChanB FIGURE 6.24 Motherboard with four memory slots and two channels TABLE 6.11 Motherboard single-/dual-channel guidelines Installed memory Guidelines 2 DIMMs dual-channel of both Channel A and Channel B. 4 DIMMs dual-channel of DIMMs in DIMM1 of both Channels A and B. 3 DIMMs dual-channel DIMM1 of Channel B. Single-channel operation.
1. The memory support capacity of the motherboard can be determined by the capacity of each individual RAM slot on the motherboard. In this case, the motherboard has four 240-pin DDR2 SDRAM DIMM connectors, which can accommodate up to 8GB of RAM. This means that each RAM slot can support up to 2GB of memory.
2. The memory features used in this motherboard are unbuffered, non-registered single or double-sided DDR2 533/667/800 MHz memory, and (SPD) memory only. The motherboard supports parity, non-parity, ECC, registered, and fully buffered memory.
3. The customer needs 3 dual-channel RAM kits, and each kit should consist of a matched pair of DIMMs equal in speed and size. Therefore, the customer needs a total of 6 DIMMs.
4. Based on the information provided, the memory slots that will be used to install the memory are DIMM0 and DIMM1 of Channel A, and DIMM0 and DIMM1 of Channel B.
5. The cost, part numbers, and quantities of the memory modules depend on the customer's requirements and budget. The information can be obtained from computer parts magazines or online stores that sell memory modules.
6. Tin contacts in the memory slots can cause connectivity issues and affect the performance of the memory modules. Therefore, it is important to ensure that the memory modules have proper connectivity with the motherboard.
7. Yes, DDR memory modules can be used with this motherboard. The motherboard supports DDR2 SDRAM memory, which is backward compatible with DDR SDRAM memory.
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Coal containing 21% ash is completely combusted, and the ash is 100% removed in a water contact scrubber. If 10,000 kg of coal is burned per hour with a scrubber flow rate of 1.0 m3/min, the weight percentage of the ash in the water/ash stream leaving the scrubber is most nearly:_______.
a. 3.4
b. 14.3
c. 25.9
d. 67.7
Answer:
Weight Percentage of Ash = 3.4
Explanation:
Given - Coal containing 21% ash is completely combusted, and the ash is 100% removed in a water contact scrubber. If 10,000 kg of coal is burned per hour with a scrubber flow rate of 1.0 m3/min.
To find - the weight percentage of the ash in the water/ash stream leaving the scrubber is most nearly ?
Solution -
Given that,
Coal Burned Rate = 10,000 kg/hr
= \(\frac{10,000}{60 min} * 1 hr *\frac{kg}{hr}\)
= 166.6666 kg/min
⇒Coal Burned Rate = 166.6666 kg/min
Now,
Given that,
Ash content in coal = 21 %
⇒Ash in (coal that burned) = 166.6666 × \(\frac{21}{100}\) kg/min
= 34.9999 ≈ 35 kg/min
⇒Ash in (coal that burned) = 35 kg/min
Now,
We know,
Density of water = 1000 kg/m³
Now,
Water flow Rate = \(1\frac{m^{3} }{min} * density\)
= 1000 kg/min
⇒Water flow Rate = 1000 kg/min
Now,
Total Mass flow Rate of (Water + Ash stream) = ( 1000 + 35) kg/min
= 1035 kg/min
⇒Total Mass flow Rate of (Water + Ash stream) = 1035 kg/min
So,
Weight Percentage of Ash = (Weight of Ash ÷ Total weight of Stream) × 100
= (35 ÷ 1035) × 100
= 3.38 ≈ 3.4
∴ we get
Weight Percentage of Ash = 3.4
Technician A says lever action pushes a rod into the brake booster and master cylinder
when the driver pushes on the brake pedal. Technician B says the produces hydraulic
pressure in the master cylinder. Who is correct?
Three of the following techniques are used in mass production:
a. Assembly line production
b. Automation
c. Division of labor
d. All of the above
By combining these techniques, manufacturers can produce large quantities of goods quickly and efficiently.
Mass production is a method of manufacturing goods on a large scale, which is characterized by standardized designs and assembly-line processes. Three of the techniques used in mass production are assembly line production, automation, and division of labor.Assembly line production is a technique where work is divided into individual tasks, and each worker performs a specific task repeatedly on each product as it moves down the assembly line. This technique can reduce manufacturing costs, increase productivity, and improve product quality.Automation is the use of technology to perform tasks that were previously done by humans.
Automation has the potential to increase efficiency and reduce costs. It can also improve product quality and reduce the risk of errors.Division of labor is the process of dividing a complex task into smaller, more manageable tasks that are assigned to different workers. This technique can increase efficiency and productivity, as each worker can focus on their assigned task, rather than trying to complete the entire task on their own.All three of these techniques are used in mass production. By combining these techniques, manufacturers can produce large quantities of goods quickly and efficiently. These techniques help to streamline the manufacturing process, reduce costs, and increase productivity. Overall, mass production has played a significant role in the development of modern manufacturing and has led to significant advances in technology and productivity.
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Plastic deformation is characterized by permanent _________, that is, the material (like a compressed snowball) doesn't return to its original shape.
Plastic deformation is characterized by permanent strain , that is, the material (like a compressed snowball) doesn't return to its original shape.
What is plastic deformation?When a material experiences tensile, compressive, bending, or torsion loads that are greater than its yield strength, causing it to stretch, compress, buckle, bend, or twist, this irreversible distortion is known as plastic deformation.The bonds are stretched during this sort of deformation, but the atoms do not slide past one another. It is referred to as plastic deformation when the metal is sufficiently stressed to permanently distort it.The capacity of a solid material to undergo persistent deformation, or an irreversible change of shape in response to applied pressures, is known as plasticity in physics and materials science.Plastic deformation is distinguished by permanent strain, which means that the material (such as a compressed snowball) does not return to its original shape.
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__ strength is a measure of the maximum stress that a material can resist under tensile stress
Tensile strength is a measure of the maximum stress that a material can resist under tensile stress.
The strength of a material is a measure of its ability to withstand external forces without breaking or deforming. It is usually expressed as the maximum stress that a material can withstand before it fails. In the case of tensile strength, this refers to the maximum stress that a material can resist under tension, which is when a force is applied to pull it apart.
Tensile strength is an important property to consider when selecting materials for engineering applications. The tensile strength of a material can be determined through a variety of tests, including the tensile test, where a sample of the material is subjected to tension until it breaks.
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Is a 10 foot ladder long enough to safely reach a landing that is 9 feet above the adjacent floor
Answer:
Definitely not
Explanation:
You should have 1-2 feet of extra ladder on a flat surface so 1 foot on an adjacent floor is a no no
Describe each stage, utilizing 50-75 words, including the generally accepted economic activities that occur during and between the stages.
Economic activities can occur during and between different stages of various processes.
How to explain the informationHere are some examples:
Production Stage: During the production stage, economic activities can include the purchase of raw materials, labor costs, and the use of machinery and equipment.
Distribution Stage: During the distribution stage, economic activities can include transportation costs, warehousing costs, and marketing costs.
Consumption Stage: During the consumption stage, economic activities can include the purchase of goods and services by consumers.
Recycling Stage: During the recycling stage, economic activities can include the collection and processing of waste materials, the production of recycled materials, and the sale of these materials to manufacturers.
Innovation Stage: Economic activities during the innovation stage can include research and development expenses, patents, and intellectual property rights.
Service Stage: During the service stage, economic activities can include the provision of services to customers, such as consulting, repair, and maintenance services.
Investment Stage: During the investment stage, economic activities can include the purchase of securities, property, and other assets.
Overall, economic activities occur throughout various stages of a process, from the production of goods and services to their consumption and beyond.
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6.03 Discussion: Then & Now - Safety
Discussion Topic
I'm Done
In this unit, you have learned about the evolution of the industry’s machines, through both technology and innovation. These improvements have reduced risk and injury to the Operating Engineers.
Choose one innovation or device.
Explain why you think that technology is the most important advancement in Operating Engineers’ safety.
Answer:
Information technology is important in our lives because it helps to deal with every day's dynamic things. Technology offers various tools to boost development and to exchange information. Both these things are the objective of IT to make tasks easier and to solve many problems.
Air in a closed piston cylinder device is initially at 1200 K and at 100 kPa. The air undergoes a process until its pressure is 2.3 MPa. The final air temperature is 1800 K. In your assessment of the following do not assume constant specific heats. What is the change in the air's specific enthalpy during this process (kJ/kg)? Chose the correct answer from the list below. If none of the values provided are within 5% of the correct answer, or if the question is unanswerable, indicate this choice instead. O a. unanswerable/ missing information O b. 760 kJ/kg O c. 1570 kJ/kg O d. -760 kJ/kg O e. -685 kJ/kg O f. 725 kJ/kg O g. -1570 kJ/kg O h. 685 kJ/kg O i. -725 kJ/kg O j. none of these are within 5% Indicate from the choices provided, a correct statement regarding the heat transfer involved in this process. O a. No, there was definitely no heat transfer involved in this process O b. It is very likely that there was heat transfer involved in this process, but this cannot be stated with certainty О с. It is impossible to answer this question based on the information given Yes, there was definitely heat transfer involved in this process O d. O e. It is very unlikely that there was heat transfer involved in this process, but this cannot be stated with certainty
The change in the air's specific enthalpy during this process (kJ/kg) is -725 kJ/kg and there was definitely heat transfer involved in this process.
The initial temperature of air,
T1 = 1200 K
The final temperature of air,
T2 = 1800 K
The initial pressure of air
P1 = 100 kPa
The final pressure of air,
P2 = 2.3 MPa
We know that the change in the specific enthalpy is given by
:Δh = Cp ΔT + V(ΔP)
Where,Cp is the specific heat at constant pressureΔT is the change in temperatureV is the specific volume of airΔP is the change in pressureSince there is no information provided for the specific heats, let us assume them to be variable and evaluate the enthalpy changes by integration of Cp with respect to temperature..Therefore, option i. -725 kJ/kg is the correct answer to the first question. For the second question, it is very likely that there was heat transfer involved in this process, but this cannot be stated with certainty. Therefore, option b. It is very likely that there was heat transfer involved in this process, but this cannot be stated with certainty is the correct answer to the second question.
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using the what-if function in excel to make a decision is considered a type of __________.
A forecast as well as scenario model is a form of decision-making tool that uses the what-if Excel function.
What purposes does Excel serve?Users of Microsoft Excel may format, arrange, and compute data together in spreadsheet. Data analysts or other customers can make data simpler to examine when data is added as well as altered by arranging the data using tools like Excel. The boxes in Excel are referred to as cells, and they are arranged in columns or rows.
What is a formula in Excel?In Microsoft Excel, an formula seems to be an expression that changes the values of a group of cells. These equations nevertheless provide a result, even if it's erroneous. Using Excel formulas, you may do operations like addition, subtraction, multiplication, as well as division.
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you cant mix conventional and synthetic oil fact or myth
Answer:
Explanation:
myth
a load of 12tonnes is put along a horizontal plane by a force at 30°to and above the flat. if the coefficient of sliding friction is 0.2 find the frictional force
Answer:
20368.917N
Explanation:
Frictional force (F) is the product of the Coefficient of friction and the normal reaction.
F = μN
Coefficient of friction, μ = 0.2
Normal reaction = MgCosθ
Mass, m = 12 tonnes = 12 * 1000 = 12000 kg
N = 12000 * 9.8 * cos30
N = 101844.58
F = 0.2 * 101844.58
F = 20368.917N
1. An asbestos pad is square in cross section, measuring 5 cm on a side at its small end, increasing linearly to 10 cm on a side at the large end. The pad is 15 cm high. If the small end is held at 600 K and the large end at 300 K, what heat‐flow rate will be obtained if the four sides are insulated?2. Solve Problem for the case of the larger cross section exposed to the higher temperature and the smaller end held at 300 K.