When 0.157 mol NH3 is reacted with excess HCl, 6.91 kJ of energy is released asheat. What is ΔH for this reaction per mole of NH3 consumed

Answer:

Beta emission measn -1e0

Here reactant is phosphorus-32.

phosphorus-32 --- >    product + -1e^0

product = 16 S^32

P-32 beta decays to S-32. On the beta emission the product is formed which has same number of mass but the atomic number more than 1 of the reactant.

Answer:

The edge of the length is \(\mathbf{L = 8.54 \times 10^{-10} \ m}\)

Explanation:

From the given information:

The associated energy for a particle in three - dimensional box can be expressed as:

\(E_n = \dfrac{h^2}{8mL^2}(n_x^2+n_y^2+n_z^2)\)

here;

h = planck's constant = \(6.626 \times 10^{-34} \ Js\)

\(n_i\) = the quantum no in a specified direction

m = mass (of particle)

L = length of the box

At the ground state \(n_x = n_y = n_z=1\)

The energy at the ground state can be calculated by using the formula:

\(E_1 =\dfrac{3h^2}{8mL^2}\)

At first excited energy level, one of the quantum values will be 2 and the others will be 1.

Thus, the first excited energy will be: 2,1,1

∴

\(E_2 =\dfrac{(2^2+1^2+1^2)h^2}{8mL^2}\)

\(E_2 =\dfrac{(4+1+1)h^2}{8mL^2}\)

\(E_2 =\dfrac{(6)h^2}{8mL^2}\)

The transition energy needed to move from the ground to the excited state is:

\(\Delta E= E_2 - E_1\)

\(\Delta E= \dfrac{6h^2}{8mL^2}- \dfrac{3h^2}{8mL^2}\)

\(\Delta E= \dfrac{3h^2}{8mL^2}}\) ----- (1)

Recall that:

the  wavelength identified with the electronic transition is: 800 nm

800 nm = 8.0  × 10⁻⁷ m

However, the energy-related with the electronic transition is:

\(\Delta E =\dfrac{hc}{\lambda}\)

\(\Delta E =\dfrac{6.626 \times 10^{-34} \times 2.99 \times 10^8}{8.0 \times 10^{-7} }\)

\(\Delta E =2.48 \times 10^{-19} \ J\)

Replacing the value of \(\Delta E\) in (1); then:

\(2.48 \times 10^{-19}= \dfrac{3h^2}{8mL^2}}\)

Making the edge length L the subject of the formula; we have:

\(L = \sqrt{\dfrac{3h^2}{8m \times2.48 \times 10^{-19}} }\)

\(L = \sqrt{\dfrac{3\times (6.626 \times 10^{-34})^2}{8(9.1 \times 10^{-31} ) \times2.48 \times 10^{-19}} }\)

\(\mathbf{L = 8.54 \times 10^{-10} \ m}\)

Thus, the edge of the length is \(\mathbf{L = 8.54 \times 10^{-10} \ m}\)

1. The reaction mixture with the largest amount of product(s) when at equilibrium is the one with the largest Keq value.

2. The reaction mixture with the largest amount of reactants when at equilibrium is the one with the smallest Keq value

3. The reactions in the table that have concentrations that represent the systems at equilibrium are Reactions 1 and 3.

4. For each reaction that is not at equilibrium, change the concentration of only one of the reactants or products so that the ratio represents the system at equilibrium.

1. In this case, the reaction mixture with the largest Keq value is Reaction 2. This is because the equilibrium constant, Keq, is a measure of the relative concentrations of the products and reactants at equilibrium. A large Keq value indicates that the equilibrium lies far to the right, meaning that there are more products than reactants at equilibrium.

2. The reaction mixture with the largest amount of reactants when at equilibrium is the one with the smallest Keq value. In this case, the reaction mixture with the smallest Keq value is Reaction 4. This is because a small Keq value indicates that the equilibrium lies far to the left, meaning that there are more reactants than products at equilibrium.

3. The reactions in the table that have concentrations that represent the systems at equilibrium are Reactions 1 and 3. This is because the concentrations of the products and reactants in these reactions are equal, which is the definition of equilibrium.

4. For each reaction that is not at equilibrium, change the concentration of only one of the reactants or products so that the ratio represents the system at equilibrium. For example, to bring Reaction 2 to equilibrium, we could increase the concentration of H2O or decrease the concentration of CO2.

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Reaction Keq Concentrations at Equilibrium

1 1000 H2O:CO2 = 1:1

2 10 H2O:CO2 = 10:1

3 0.01 H2O:CO2 = 100:1

4 0.001 H2O:CO2 = 1000:1

On the basis of the Keq values given in the table, which reaction mixture contains the largest amount of product(s) when at equilibrium? Explain.

2. Which reaction mixture contains the largest amount of reactants when at equilibrium?

3. Which reactions in the table have concentrations that represent the systems at equilibrium?

4. For each reaction that is not at equilibrium, change the concentration of only one of the reactants or

products so that the ratio represents the system at equilibrium

The correct answer is cation Ni +2 and anion S 2-.

Nickel sulfide

It is discovered that the bonding in NiS is remarkably similar to that in NiO, with a covalent component resulting from bonds between the Ni 3d and the S 3p atom and an ionic contribution resulting from the donation of the Ni 4s electron to the S atom.

With heated concentrated nitric acid or aqua regia, NiS can be easily reactively dissolved, which is followed by sulphur precipitation.

F belongs to Group 7A, while Ni is in Group 5A. (EN: N=3.0, F=4.0) The NF3 molecule and each N-F bond are both polar. F possesses a partial positive charge in the N-F bond. The NF3 molecule and each N-F bond are both non-polar.

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Answer: is a substance that accepts hydrogen ions.

Scientific knowledge be used to solve a practical problem through all of the above which are:

This is defined as the movement of air and other gases on the surface on the earth. Wind intensity varies according to various factors and it's best to study it as helps to prepare for unforeseen circumstances.

Its knowledge helps in the building of windmills so as to ensure efficient capture of winds.

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Answer:

false statements because they are all nonrenewable resources

Answer:

BLACK

Explanation:

the color is black

Answer: 1st one is black second one is also black

Explanation:

By -320 pM, we need to increase the source power. A fluorescent material begins to produce visible light when energy is absorbed as a result of the incidence of X-rays, light waves, and electrons.

When a substance generates electromagnetic waves inside the longer wavelength range and makes them visible to the human eye, it is a fascinating occurrence. Let's first define fluorescence in order to comprehend this. This allows the substance to gently transition from the partly excited state to the ground state. Fluorescence is the term for this phenomena.

Detection limit = 3 × noise / signal to noise ratio

Detection limit  = 3× 75 pM / 5 = 15 pM

Source power = (noise / desired detection limit)² × current source power

Source power = (15 pM / 75 pM)² ×500 pM

                      = 0.36 ×500 pM

                       = 180 pM

Source power= 180 pM - 500 pM =

                       =-320 pM

Therefore, -320 pM, we need to increase the source power.

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The maximum electron capacity at energy level 1 is 2. The maximum electron capacity at energy level 2 is 8. Maximum electron capacity at energy level 3 is 18. The maximum number of electrons at energy level 4 is 32.

Having a negative electric charge, an electron is a subatomic particle. Together with protons and neutrons, it is one of the basic building blocks of atoms.

The chemical characteristics of elements are determined by electrons, which are found in the valence shell, the outermost shell of an atom. In addition, they have a role in the production of magnetism, electrical conduction, and chemical processes. Additionally, as in an electron beam, electrons can also exist freely and independently.

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This problem is providing information about a chemical reaction between sodium carbonate and hydrochloric acid. Thus, the mass of evolved carbon dioxide is required and found to be 0.0922 g according to:

In chemistry, stoichiometry is a tool that allows us to perform mole-mass calculations based on proportional factors involving the balanced chemical equation, molar masses and mole ratios. In such a way, for the reaction in this problem, we write:

\(2HCl+Na_2CO_3\rightarrow 2NaCl+H_2O+CO_2\)

In such a way, since both HCl and Na2CO3 are given, we calculate the grams of CO2 produced by each one, to identify the limiting reactant, according to the 2:1 and 1:1 mole ratios the reactants have with CO2 respectively:

\(0.2220gNa_2CO_3*\frac{1molNa_2CO_3}{106gNa_2CO_3} *\frac{1molCO_2}{1molNa_2CO_3}*\frac{44.01 gCO_2}{1molCO_2}= 0.0922gCO_2\\ \\ 0.1000L*0.0731\frac{molHCl}{L} *\frac{1molCO_2}{2molHCl}*\frac{44.01 gCO_2}{1molCO_2}=0.161gCO_2\)

Thus, since Na2CO3 produce the smallest amount of CO2, we infer it is the limiting reactant and therefore the correct produced amount is 0.0922 g.

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The changes to the atmosphere that caused temperatures to increase, making the Eocene such a warm time in Earth’s history was the increase in concentrations of greenhouse gases, primarily carbon dioxide (CO2) and methane (CH4).

The Eocene period was a geological epoch that lasted from approximately 56 to 34 million years ago, occurring between the Paleocene and Oligocene epochs.

During this epoch, the Earth experienced a greenhouse climate, with higher global temperatures and high levels of carbon dioxide in the atmosphere.

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Answer:

what??? Is this the complete quetion??

Answer:

No and Yes

Explanation:

This is both possible and impossible. When you put your mind to what you believe, you can achieve it through patience and minded values. Your mind can either be your Greatest enemy or your Best Ally.

Taking into account the reaction stoichiometry, 128.4 grams of C are required to produce 10.7 moles of methane.

In first place, the balanced reaction is:

C + 2 H₂ → CH₄

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The following rule of three can be applied: If by reaction stoichiometry 1 mole of CH₄ is produced by 12 grams of C, 10.7 moles of CH₄ are produced by how much mass of C?

mass of C= (10.7 moles of CH₄×12 grams of C)÷1 mole of CH₄

mass of C= 128.4 grams

Finally, 128.4 grams of C are required.

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Explanation:

Pure subsance is a substance that is made up of only one type of particle - each piece is the same throughout.

Being present before the reaction but not after means it's no the same (it couldve evaporated)

A 30-kg iron block and a 40-kg copper block, both initially at 80∘C, are dropped into a large lake at 15 °C. The total entropy change for this process is 0.64kJ/ K.

given that :

mass of iron block , mFe = 30 kg

mass of copper block mCu = 40 kg

temperature T1 = 80 °C = 353 K

temperature T2 = 15 °C = 288 K

the entropy change for iron block is given as :

ΔS fe = mc ln(T2/T1)

ΔS fe = 30 × 0.45 × ln ( 288/ 353)

ΔS fe = - 2.74 kJ/ K

The entropy change for copper :

ΔS Cu = 40 × 0.386 ln ( T2 / T1)

ΔS Cu = - 3.14 kJ/ K

the heat transfer to the lake :

Q out = - mFe cFe ( T2 - T1 ) - mCu cCu ( T2 - T1 )

          = - 30 × 0.45 ( 15 - 80 ) - 40 × 0.386 ( 15 - 80 )

          = 1881.1 kJ

the entropy change for the lake :

ΔS lake = Q out / T2

            = 1881.1 / 288

            = 6.53 kJ/K

the total entropy change is given as follows :

ΔS  = - 2.747 - 3.142 + 6.53

      = 0.64 kJ/ K

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Ammonia (\(NH_3\)) and ammonium chloride (\(NH_4Cl\)) mixture could be a useful buffer in a solution. Option C

A buffer is a solution that can resist changes in pH when small amounts of acid or base are added. It consists of a weak acid and its conjugate base or a weak base and its conjugate acid. The buffer system works by the principle of Le Chatelier's principle, where the equilibrium is shifted to counteract the changes caused by the addition of an acid or a base.

In option A, acetic acid (\(CH_3CO_2H\)) is a weak acid, but hydrochloric acid (HCl) is a strong acid. This combination does not form a buffer because HCl is completely dissociated in water and cannot provide a significant concentration of its conjugate base.

Option B consists of sodium hydroxide (NaOH), which is a strong base, and elemental sodium (Na), which is a metal. This combination does not form a buffer as there is no weak acid-base pair involved.

Option D contains acetic acid (\(CH_3CO_2H\)), a weak acid, and ammonia (\(NH_3\)), a weak base. Although they are weak acid and base, they do not form a buffer system together as they are both weak acids or bases and lack the required conjugate acid-base pair.

Option C, ammonia (\(NH_3\)), is a weak base, and ammonium chloride (\(NH_4Cl\)) is its conjugate acid. This combination can form a buffer system. When ammonia reacts with water, it forms ammonium ions (NH4+) and hydroxide ions (OH-).

The ammonium ions act as the weak acid, while the ammonia acts as the weak base. The addition of a small amount of acid will be counteracted by the ammonium ions, and the addition of a small amount of base will be counteracted by the ammonia, thus maintaining the pH of the solution relatively stable.

Therefore, option C, consisting of ammonia (\(NH_3\)) and ammonium chloride (\(NH_4Cl\)), is the suitable mixture that could be a useful buffer in a solution.

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Answer:

0.147 mol

Explanation:

Step 1: Calculate the volumetric concentration (Cv)

We will use the following expression.

Cv = Cg × ρ

Cv = 98.0 g%g × 1.84 g/mL = 180 g%mL

Step 2: Calculate the molarity of sulfuric acid

We will use the following expression.

M = mass solute / molar mass solute × liters of solution

M = 180 g / 98.08 g/mol × 0.100 L = 18.4 M

Step 3: Calculate the moles of solute in 8.00 mL of solution

8.00 × 10⁻³ L × 18.4 mol/L = 0.147 mol

Explanation:

Functional groups containing nitrogen are amines and amides.

The general formula for amines is:

RNH₂, where R = longer hydrocarbon chain.

The general formula for amides is:

RCONH₂, where R = longer hydrocarbon chain.

See attached diagram for general structural formula.

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Answer: arterioles

Explanation:

All the element have their own unique color because the every element have their own set of energy levels.

According to the bohr model of atoms : electrons exist at certain energy levels. when we give heat to electron , it gets excited and moves from lower energy level to higher energy level. the electron is less stable in higher energy level. when an electron returns from higher energy level to lower energy level it emits some energy in form of radiation. The wavelength of light depends upon energy level . and every elements have their own unique energy levels.  The color for different element is different.

Thus, All the element have their own unique color because the every element have their own set of energy levels.

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Amobarbital (like all barbiturates) works by being incontestible to the GABAA receptor at either the alpha or the beta subunit.

Amobarbital (like all barbiturates) works by binding to the GABAA receptor at either the alpha or the beta subunit. These are compulsory sites that are distinct from GABA itself and also distinct from the benzodiazepine binding site.

Amobarbital is a barbiturate classified as having a halfway duration of action, meaning that the effects of the drug can last from 4-6 amobarbital increases the effects of benazepril by apparatus: pharmacodynamic synergism.

So we can conclude that Amobarbital, 5-ethyl-5-isoamyl barbituric acid like all barbiturates.

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Answer:

D

Explanation:

Answer:

I know i'm late but here the answer Heat is considered "lost" energy because it cannot be used for work.

Explanation:

Answer:

If H = 15.88%

Then C = 100.00 – 15.88 = 84.12%

Divide each % value by respective atomic mass

H = 15.88/1 = 15.88

C = 84.12/12 = 7.01

Divide through by smaller value

H = 15.88/7.01 = 2.26

C = 7.01/7.01 = 1

Remove fraction , multiply by 4

H = 9

C = 4

Empirical formula = C4H9

The hydrocarbon could be ( C4H9)2 = C8H18 = octane.