When a 1.0-m length of metal wire is connected to a 1.5-V battery, a current of 8.0mA flows through it. What is the diameter of the wire? The resistivity of the metal is 2.24 * 10-80 m. A) 12 pm B) 6.0 um C) 24 pm D) 2.2 um

Answers

Answer 1

According to the statement 0.40 mm is the diameter of the wire.

How is resistivity measured?

A four-point coupled probe is the most typical tool for determining a semiconductor material's impedance. Four evenly distributed sensors are in touch with a substance whose resistance is unknown using this method.

L = 1.0 m is the length of the wire.

The battery's emf is 1.5 volts.

I = 8 mA = 0.008 A is the wire's current.

The resistance of the wire may be estimated by using;

R = V / I

R = 1.5 / 0.008

R = 187.5 ohms

The resistivity of the wire is what determines its resistance;

R = pL / A

A = pL / R

Where;

A is the wire's region B.

The resistivity of gold is (2.24 x 10)⁻⁸ ohm.

A = (2.24 x 10)⁻⁸ × 8 /187.5

A = 1.2 * 10⁻⁷ m²

A = πd² / A

πd²  = 4A

d = √4A / π

d = √(4 × 1.2 × 10⁻⁷ m² / π)

d = 4.0 * 10⁻⁴

d = 0.40 mm

Therefore, the diameter of the wire is 0.40 mm .

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Related Questions

One drops a penny from top of the Empire State Building on the ground below. The hight of the Empire State Building is 443m How long will it take for a penny yo strike the ground assuming no air resistance

Answers

Answer:

See below

Explanation:

Assuming no resistance

DISTANCE =  1/2 a t^2

443 = 1/2 (9.81)t^2      Shows t = 9.5 seconds

A flute plays a note with a frequency of 266Hz. What is the speed of sound if the wavelength is 1.3m?

Answers

Explanation:

Wave speed  =  (frequency)  x  (wavelength)

                      =  (266 /sec)  x  (1.3 meters)

A space rocket accelerates uniformly from rest to 160ms^-1 upwards in 4.0s, then travels with a constant speed of 160ms^-1 for the next 5.0s.
What is the initial acceleration of the rocket?

Answers

Answer:

40 ms¯².

Explanation:

To solve this problem, we shall illustrate the question with a diagram.

The attached photo gives a better understanding of the question.

From the attached photo:

Velocity (v) = 160 ms¯¹

Time (t) = 4 secs.

Acceleration (a) =?

Acceleration (a) = Velocity (v) /time (t)

a = v/t

a = 160/4

a = 40 ms¯²

Therefore, the initial acceleration of the rocket is 40 ms¯².

A space rocket accelerates uniformly from rest to 160ms^-1 upwards in 4.0s, then travels with a constant

An object of mass of 2. 0 kg hangs from an ideal massless spring with a spring constant of 50 N/m. An oscillating force F = (4. 8 N) cos[(3. 0 rad/s)t] is applied to the object. What is the amplitude of the resulting oscillations? You can neglect damping.

A) 0. 15 m

B) 0. 30 m

C) 1. 6 m

D) 2. 4 m

E) 0. 80 m

Answers

Answer:

The amplitude of the resulting oscillations can be calculated using the formula:

A = F/mω^2

where F is the amplitude of the applied force, m is the mass of the object, and ω is the angular frequency of the applied force.

In this case, F = 4.8 N, m = 2.0 kg, and ω = 3.0 rad/s.

Substituting these values into the formula, we get:

A = 4.8/(2.0 x (3.0)^2) = 0.267 m or 0.27 m (rounded to two significant figures)

Therefore, the amplitude of the resulting oscillations is 0.27 m, which is closest to option A) 0.15 m.

Explanation:

A 500 mH ideal inductor is connected to an open switch in series with a 60 S2 resistor through and an ideal 15 V DC power supply. calculate the value of current at the following times after the switch is closed: 7.0 ms, 15.0 ms, 50.0 ms, 500.0 ms.

Answers

The currents at the specified times are approximately:

At 7.0 ms: I1 ≈ 0.186 A

At 15.0 ms: I2 ≈ 0.275 A

At 50.0 ms: I3 ≈ 0.408 A

At 500.0 ms: I4 ≈ 0.595 A

Inductance (L) = 500 mH = 500 * 10^(-3) H

Resistance (R) = 60 Ω

DC voltage (V) = 15 V

The time constant (τ) of the circuit can be calculated as follows:

τ = L / R

Let's calculate the time constant first:

τ = (500 * 10^(-3) H) / 60 Ω

τ = 8.33 * 10^(-3) s

Now, we can calculate the current at different times using the formula for the transient response in an RL circuit:

At t = 7.0 ms:

t1 = 7.0 * 10^(-3) s

I1 = (V / R) * (1 - e^(-t1 / τ))

At t = 15.0 ms:

t2 = 15.0 * 10^(-3) s

I2 = (V / R) * (1 - e^(-t2 / τ))

At t = 50.0 ms:

t3 = 50.0 * 10^(-3) s

I3 = (V / R) * (1 - e^(-t3 / τ))

At t = 500.0 ms:

t4 = 500.0 * 10^(-3) s

I4 = (V / R) * (1 - e^(-t4 / τ))

To calculate the current at different times, we will substitute the given values into the formulas and perform the calculations:

At t = 7.0 ms:

t1 = 7.0 * 10^(-3) s

I1 = (15 V / 60 Ω) * (1 - e^(-7.0 * 10^(-3) s / (8.33 * 10^(-3) s)))

I1 ≈ 0.186 A

At t = 15.0 ms:

t2 = 15.0 * 10^(-3) s

I2 = (15 V / 60 Ω) * (1 - e^(-15.0 * 10^(-3) s / (8.33 * 10^(-3) s)))

I2 ≈ 0.275 A

At t = 50.0 ms:

t3 = 50.0 * 10^(-3) s

I3 = (15 V / 60 Ω) * (1 - e^(-50.0 * 10^(-3) s / (8.33 * 10^(-3) s)))

I3 ≈ 0.408 A

At t = 500.0 ms:

t4 = 500.0 * 10^(-3) s

I4 = (15 V / 60 Ω) * (1 - e^(-500.0 * 10^(-3) s / (8.33 * 10^(-3) s)))

I4 ≈ 0.595 A

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What would be the mass of the same object on the moon, where gravity is one sixth of Earth gravity?

Answers

Mass(in kg) would be the same
It weight is determine using gravity (in Newton’s)

A force of 73.8 newtons is applied to travel bag at an angle 39.0° with the horizontal. What are the horizontal and vertical components of the force? A. Fx = 57.4 newtons and Fy = 46.4 newtons B. Fx = 46.4 newtons and Fy = 57.4 newtons C. Fx = 57.4 newtons and Fy = 57.4 newtons D. Fx = 46.4 newtons and Fy = 46.4 newtons

Answers

The horizontal component of the force is 57.4 N and the vertical component of the force is 46.4 N (option A)

How do I determine the horizontal component of force?

The horizontal component of the force can be obtained as follow:

Force applied (F) = 73.8 NewtonsAngle of projection (θ) = 39 °Horizontal component of force (Fx) =?

Horizontal component of force (Fx) = F × Cosθ

Fx = 73.8 × Cos 39

Fx = 57.4 N

Thus, the horizontal component of force is 57.4 N

How do I determine the vertical component of force?

The vertical component of the force can be obtained as follow:

Force applied (F) = 73.8 NewtonsAngle of projection (θ) = 39 °Vertical component of force (Fy) =?

Vertical component of velocity (Fy) = u × Sine θ

Fy = 73.8 × Sine 39

Fy = 46.4 N

Thus, the vertical component of force is 46.4 N

Therefore, the correct answer to the question is Fx = 57.4 N and Fy = 46.4 N (option A)

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A car drives 10km with a speed of 72 km/hr and then runs out of gas. Then you walk 2km for the next 30 min
until you find a gas station.

Answers

Given :

A car drives 10 km with a speed of 72 km/hr and then runs out of gas.

Then you walk 2 km for the next 30 min  until you find a gas station .

To Find :

The average speed of whole journey .

Solution :

Average speed is given by :

\(v_{avg}=\dfrac{\text{Total distance covered}}{\text{Total time taken}}\\\\v_{avg}=\dfrac{10+2}{\dfrac{10}{72}+\dfrac{1}{2}}\\\\\\v_{avg}=18.78\ km/hr\)

Hence , this is the required solution .

The brakes on a car do 110,095J of work as they apply an average force of 8,450N. How far in meters does the car continue before stopping

Answers

13.02 meters

Explanation

the work done by the brakes makes the car stops, so the change in energy equals the work done

hence

\(\text{work}=\Delta Ek=\frac{1}{2}mv^2\)

also, the work done by a force is given by

\(\text{work}=\text{ force}\cdot dis\tan ce\)

then, let

\(\begin{gathered} \text{work}=\text{ 110095 J} \\ \text{Force}=8450\text{ N} \end{gathered}\)

replace

\(\begin{gathered} \text{work}=\text{ force}\cdot dis\tan ce \\ 110095\text{ J=8450 N}\cdot distnace \\ \text{divide both sides by 8450 N} \\ \frac{110095\text{ J}}{\text{8450 N}}\text{=}\frac{\text{8450 N}\cdot}{\text{8450 N}}distance \\ 13.02m=\text{distance} \end{gathered}\)

therefore, the answer is

13.02 meters

I hope this helps you

a 220 g , 34.0-cm-diameter turntable rotates on frictionless bearings at 59.0 rpm . a 25.0 g block sits at the center of the turntable. a compressed spring shoots the block radically outward along a frictionless groove in the surface of the turntable.

Answers

The turntable's rotation angular velocity when the block reaches the outer edge is 5.578 rads⁻¹

The inertial moment of the turntable block = \(\frac{1}{2} mr^{2}\)

The inertial moment of the block = \(mr^{2}\)

According to the law of conservation of angular momentum, the total angular momentum of the system when the block is seated at the center and when the block is at the outside edge must be the same since no external torque operates on the system.

Additionally,

ω= 2\(\pi\)f, where f represents rpm, can be used to determine

ω= 2π×63/60 = 6.597

So, I*ω = I' * ω'

\([\frac{1}{2} 0.23 *(0.5)^{2} + 0.021* (0)^{2} ]6.597= [\frac{1}{2} 0.23 *(0.5)^{2} + 0.021* (0.5)^{2} ]\)*ω'

ω' = 5.578 rads⁻¹

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a closed column of water has a diameter of 1.4 m and a depth of 9.6 m. how much pressure is at the bottom of the column? the acceleration of gravity is 9.8 n/kg . answer in units of pa.

Answers

The pressure at the bottom of the column is determined as 94,080 Pa.

What is the hydrostatic pressure of the water column?

The hydrostatic pressure of the water column is pressure exerted due to the vertical column of water and it can be calculated by applying the following formula.

Mathematically, hydrostatic pressure is given as;

P = ρgh

where;

ρ is the density of waterg is acceleration due to gravity h is the vertical height or column of the water

The given parameters include the following;

the density of water, ρ = 1000 kg/m³the acceleration due to gravity, g = 9.8 m/s² the vertical height or column of the water, h = 9.6 m

Substitute the above parameters and solve for the pressure exerted by the water column.

P = 1000 x 9.8 x 9.6

P = 94,080 Pa

Thus, the pressure exerted by the column of the water depends on the depth of the water or water column.

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Mitosis can sometimes result in mutations, which can be repaired?

True or False

Answers

Answer:

True

Explanation:

Mitosis is the process of cell division that produces two identical daughter cells. Occasionally mutations can occur during DNA replication or the other stages of mitosis. However, cells have mechanisms for DNA repair that can correct these mutations, ensuring the integrity of the genetic material.

at+waht+temperature+must+you+run+this+reaction+to+achieve+97%

Answers

Temperature is the degree of hotness or coldness of an object or substance. The SI unit of temperature is Kelvin."97%": The question suggests that a reaction must be run at a specific temperature to achieve 97% yield or completion. Yield refers to the amount of product obtained from a reaction.

To achieve 97% yield or completion, the reaction must be run at a specific temperature. Temperature plays an essential role in chemical reactions since it affects the rate of reaction, activation energy, and equilibrium. The temperature at which a reaction runs optimally, producing the most product, is known as the reaction's optimum temperature. As a result, the temperature must be controlled during a chemical reaction.To achieve 97%, the reaction must be run at a specific temperature.

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what vertical distance is a 50.-newton

object moved if 250 joules of work is done against

the gravitational field of Earth?

A. 2.5m B. 5.0m C. 9.8m D. 25m

Answers

The vertical distance is a 50 newton object moved if 250 joules of work is done against the gravitational field of Earth is 5.0m (Option B).

To solve this problem, we can use the formula: work = force × distance × cos(theta), where theta is the angle between the force and the direction of motion (which is 0 degrees since the force is in the same direction as the distance moved).

In this case, the force is the weight of the object, which is given as 50 newtons. The work done is 250 joules. We can rearrange the formula to solve for distance:

distance = work / (force × cos(theta))

Plugging in the values, we get:

distance = 250 J / (50 N × cos(0))

distance = 5 meters

Therefore, the vertical distance is a 50 newton object moved if 250 joules of work is done against the gravitational field of Earth is 5.0m.

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Human resource professionals are reviewing the needs of a company that is
building a new factory. The company needs people who can weld electronic
elements together, test them, and package them securely. The HR
professionals conclude that four kinds of workers could complete this
process. Their work is the HR function of

A. employee retention
B. recruitment
C. selection
D. job design

Answers

recruitment i think.
D job design is the answer

Terrestrial coordinates expanded into infinite space onto a celestial sphere is called the
A) ecliptic plane
B) galactic plane
C) equatorial coordinate system
D) terrestrial coordinate system

Answers

Answer:

The correct option is;

C) Equatorial coordinate system

Explanation:

The equatorial coordinate system is which has the most wide spread use in coordinate system for astronomy for mapping the location of celestial bodies such as stars by use of an imaginary projected celestial sphere or to rectangular coordinates with the Earth at the center.  Extending the Earth's axis onto the celestial sphere is essentially the projection of the Earths axis outwards to intersect the sphere at the celestial poles.

c, 'equatorial coordinate system'

its the correct answer on the test,,, goodluckk :))!!

1.Two materials that can be scratched by an iron mail are ___, ___

2.What is the substance that can be scratched by an iron nail but not a penny?

Please answer

Answers

Answer:

1. Two materials that can be scratched by an iron nail are zinc and aluminum

2. A substance that can be scratched by an iron nail but not a penny is;

Nickel

Explanation:

The hardness of a material can be defined as its ability to resist being plastically deformed at a location due to mechanical scratching, abrasion or indentation

The Mohs hardness scale provides a ranking of materials in the order of hardness with a material having a higher Mohs hardness number being able to scratch other materials which have a lower Mohs hardness number

1. From the Mohs scale of hardness, iron which has an harness number of 4.5 can scratch zinc which has an harness number of 2.5, and iron can also scratch aluminum which has an hardness number of 2.5 to 3

2. A penny is made from copper plated material and will have an outer layer hardness of copper which has an hardness number of 3 on the Mohs scale

Therefore, a penny cannot scratch a material mode of nickel which has an hardness number of 4, while iron which has an hardness of 4.5 will scratch a nickel material

(1) Zinc and aluminum can be scratched by an iron nail.

(2) Nickel can be scratched by an iron nail but not a penny.

Hardness and deformation:

The hardness of a material is defined as its ability to resist deformation due to mechanical scratching, abrasion, or indentation.

According to the Mohs hardness scale, a material having a higher Mohs hardness number is able to scratch other materials which have a lower Mohs hardness number.

From the Mohs scale of hardness, iron has a hardness number of 4.5, zinc has a hardness number of 2.5, and aluminum which has a hardness number between 2.5 to 3. So, iron can scratch both, Zinc and Aluminium.

A penny is made from copper-plated material copper has a hardness number of 3 on the Mohs scale. Whereas Nickel has a hardness number of 4. Therefore, a penny cannot scratch a material made of Nickel.

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When light hits a surface it usually bounces off at a larger angle. True or false? Justify

Answers

Answer:That only applies to highly polished surfaces, eg mirrors.

If you take a high quality laser (ie with low divergence) and aim it at a wall, you can see the spot where the laser beam reaches the wall from anywhere with a direct line-of-sight to the spot where the laser beam reaches the wall. This due to micro imperfections on the surface of the wall. At a microscopic level, the wall surface is very rough and pointing in all directions.

As to why, a beam of light bounces of a highly polished surface, I can only surmise that it is essentially due to kinematics, ie the only force opposing the light beam is normal to the surface, hence there no forces along the reflective surface. Since there are no forces along the reflective surface, the speed component of light along the reflective surface remains unchanged. However, on the plane perpendicular to the reflective surface the, the light photons bounce off at the same speed at which the hit the reflective surface because the mass of the reflective surface is much much much larger than the mass of the photons, which means that the reflective surface won’t move at all. Since conservation of momentum requires that momentum after the collision be the same as the momentum before the collision then the only way for that to happen is if the velocity of the photon perpendicular to the reflective surface is of exactly the same magnitude but in the opposite direction. Vector resolution of the speed component of the reflected beam means that the angle of reflection must be the same as the angle of incidence.

Explanation:

The Moon has a mass of 7.35 * 1022 kg, and a radius of 1.737 * 106 m. Based on
these values, what is the acceleration due to gravity on the surface of the Moon?

Answers

Answer:

1.63 \(ms^{-2}\)

Explanation:

The equation \(g = \frac{G*M}{R^2}\) would be used where:

g = acceleration due to gravity

G = universal gravitational constant (6.67408 × \(10^{-11}\) \(m^{3} kg^{-1} s^{-2}\))

M = mass

R = radius.

assuming the values following both 10s of the mass and radius are their exponents, which is a little confusing, the values given would simply be substituted.

Anyone can correct me if I'm wrong.

Overgrazing occurs when farm animals, like cows, sheep, and horses, eat all the plants on an area of land. When all of the plants have been eaten, the soil is left bare as is shown in the picture below.


Since overgrazing removes the plants that help hold the soil in place, overgrazing can cause increased _______.
A.
rainfall
B.
erosion
C.
snow
D.
wind

Answers

Answer:

erosion

Explanation:

because i just got it right on study island

Which statement describes the endothermic reaction by this graph?

Which statement describes the endothermic reaction by this graph?

Answers

Answer:

B

endothermic: heat taking in

exothermic: heat given out

Answer:

I thin that the answer is d because the energy goes high and then it goes down a bit

Explanation:

From the scattering of sunlight, J.J. Thomson calculated the classical radius of the electron as having the value 2.82 × 10⁻¹⁵m . Sunlight with an intensity of 500 W / m² falls on a disk with this radius. Assume light is a classical wave and the light striking the disk is completely absorbed.(a) Calculate the time interval required to accumulate 1.00eV of energy.

Answers

The time interval required to accumulate 1.00 eV of energy is approximately 7.16 × 10¹¹ seconds.

To calculate the time interval required to accumulate 1.00 eV (electron volt) of energy from sunlight with an intensity of 500 W/m² falling on a disk with a radius of 2.82 × 10⁻¹⁵ m, we can use the equation:

Energy = Power * Time

Given:

Intensity (I) = 500 W/m²

Radius (r) = 2.82 × 10⁻¹⁵ m

Energy (E) = 1.00 eV

First, we need to calculate the total power received by the disk. Since the light is completely absorbed, we can assume that all the power is absorbed by the disk. The power can be calculated using the formula:

Power = Intensity * Area

The area of the disk can be calculated as follows:

Area = π * (radius)²

Substituting the values into the equation:

Area = π * (2.82 × 10⁻¹⁵ m)²

Next, we can calculate the power:

Power = Intensity * Area

= 500 W/m² * [π * (2.82 × 10⁻¹⁵ m)²]

Now we can solve for time:

Time = Energy / Power

= (1.00 eV) / [500 W/m² * π * (2.82 × 10⁻¹⁵ m)²]

To convert eV to joules, we use the conversion factor:

1 eV = 1.602 × 10⁻¹⁹ J

Substituting this conversion and the numerical values:

Time = (1.602 × 10⁻¹⁹ J) / [500 W/m² * π * (2.82 × 10⁻¹⁵ m)²]

Therefore, the time interval required to accumulate 1.00 eV of energy is approximately 7.16 × 10¹¹ seconds.

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A 0.675 kg mass is attached to a
spring of spring constant 72.4 N/m,
pulled, and released. What is the
period of the resulting oscillation?
(Unit = s)

Answers

Answer:

T= 0.6 sec

Explanation:

This problem bothers on the simple harmonic motion of a loaded spring

Given data

mass attached, m= 0-.675 kg

spring constant, k= 72.4 N/m

the period of oscillation can be solved for using the formula bellow

\(T= 2\pi \sqrt{\frac{m}{k} }\)

Substituting the given data into the expression above we have

\(T= 2*3.142\sqrt{\frac{0.675}{72.4} }\\T= 6.284*\sqrt{0.0093 }\\T= 0.6\)

T= 0.6 sec

Answer:

0.607

Explanation:

Trust me

A parallel-plate capacitor has square plates that are 7.40 cm on each side and 3.20 mm apart. The space between the plates is completely filled with two square slabs of dielectric, each 7.40 cm on a side and 1.60 mm thick. One slab is Pyrex glass and the other slab is polystyrene. If the potential difference between the plates is 84.0 V, find how much electrical energy (in nJ) can be stored in this capacitor.

Answers

Answer:

The energy that can be stored in the capacitor is 239 nJ

Explanation:

We first calculate the capacitance of each material. Let C₁ be the capacitance of pyrex glass and C₂ be the capacitance of polystyrene.

C₁ = κ₁ε₀A/d where κ₁ = dielectric constant of pyrex glass = 5, A = area of plates = L² where L = length of square plate = 7.40 cm = 7.40 × 10⁻² m and d = thickness of pyrex slab = 1.60 mm = 1.60 × 10⁻³ m and ε₀ = permittivity of free space = 8.854 × 10⁻¹² F/m

C₁ = κ₁ε₀A/d = κ₁ε₀L²/d = 5 × 8.854 × 10⁻¹² F/m × (7.40 × 10⁻² m)²/1.60 × 10⁻³ m = 2424.2252/1.60 × 10⁻¹¹ F = 1515.14 × 10⁻¹¹ F = 15.2 × 10⁻⁹ F = 15.2 nF

C₂ = κ₂ε₀A/d where κ₂ = dielectric constant of polystyrene = 3, A = area of plates = L² where L = length of square plate = 7.40 cm = 7.40 × 10⁻² m and d = thickness of polystyrene slab = 1.60 mm = 1.60 × 10⁻³ m and ε₀ = permittivity of free space = 8.854 × 10⁻¹² F/m

C₁ = κ₁ε₀A/d = κ₁ε₀L²/d = 3 × 8.854 × 10⁻¹² F/m × (7.40 × 10⁻² m)²/1.60 × 10⁻³ m = 1454.5351/1.60 × 10⁻¹¹ F = 909.08 × 10⁻¹¹ F = 9.09 × 10⁻⁹ F = 9.09 nF

Since the capacitors are in series, we find their effective capacitance C from

1/C = 1/C₁ + 1/C₂

C = C₁C₂/(C₁ + C₂)

= 15.2 × 10⁻⁹ F × 9.09 × 10⁻⁹ F/(15.2 × 10⁻⁹ F + 9.09 × 10⁻⁹ F)

= 138.168 × 10⁻¹⁸/24.29 × 10⁻⁹ F

= 5.69 × 10⁻⁹ F

The amount of electrical energy stored in a capacitor is given by W = 1/2CV² where C = capacitance and v = voltage applied. Now C = 5.69 × 10⁻⁹ F and V = 84.0 V for this capacitor

So W = 1/2 × 5.69 × 10⁻⁹ F × 84.0 V

= 238.98 × 10⁻⁹ J

≅ 239 × 10⁻⁹ J

= 239 nJ

So the energy that can be stored in the capacitor is 239 nJ

The diameter of copper wire is 7.360 mm. Find the resistance of a 5 km length of such wire used for power transmission. (Specific resistance of wire = 1.720 x 10^-8 ohm meter) ​

Answers

Answer:

2.05 Ω

Explanation:

We are here given that the

diameter= 7.360 mm = 0.7360 cm length of wire= 5km = 5000m specific resistance= 1.720 * 10-⁸ Ω m

We need to find out the resistance of the given wire . As we know that,

\(\implies R = \rho \dfrac{l}{A} \\\)

\(\implies R =\rho \dfrac{ l}{\pi r^2} \\\)

\(\implies R =\rho \dfrac{l}{\pi \dfrac{d^2}{4}} \\\)

\(\implies R =\rho \dfrac{4l}{\pi d^2}\\\)

substitute the respective values,

\(\implies R = 1.720 \times 10^{-8}\times \dfrac{4\times 5000m}{3.14\times (0.74\times 10^{-2}} \\\)

\(\implies\underline{\underline{ R = 2.05 \Omega }} \\\)

and we are done!

Someone help me with this physics

Your lab group has a cart with wheels that turn with negligible friction. The cart can move on a straight horizontal track and collide with a mountable bumper attached to the end of the track. Your group is given the task to experimentally determine the relationship between the impulse applied to the cart by the bumper and the cart's change in velocity during the collision with the bumper. Before the collision, the cart moves to the right toward the bumper, as shown above. After the collision, the cart moves to the left.

D) Students collected data shown below using a system similar to the one shown in the diagram above.  Use the empty boxes in the data table, as appropriate, to record any calculated values you will need for analysis. Label each column and include appropriate units. You do not need to fill in every column. If you need additional columns, you may add them to the space next to the table.

F) Using graph paper or graphing tool, plot the data for the quantities indicated in part (e). Clearly scale and label all axes including units. Draw a best-fit line that represents the relationship between the variables.
(if you can tell me equation ill just graph it)

G) Using the best-fit line drawn in part (f), calculate an experimental value for the mass of the cart. Explicitly indicate the principles used in your calculation.

Someone help me with this physics Your lab group has a cart with wheels that turn with negligible friction.

Answers

Answer:

Explanation:

D)

Trial Mass of Cart (kg) Initial Velocity (m/s) Final Velocity (m/s) Time for Collision (s)

1 0.50 0.60 -0.52 0.030

2 0.50 0.53 -0.45 0.032

3 0.50 0.70 -0.61 0.033

4 0.75 0.62 -0.52 0.038

5 0.75 0.54 -0.43 0.041

6 0.75 0.71 -0.59 0.039

7 1.00 0.57 -0.48 0.040

8 1.00 0.62 -0.52 0.042

9 1.00 0.75 -0.64 0.043

10 1.25 0.59 -0.49 0.045

F)

The best-fit line represents the relationship between the impulse applied to the cart by the bumper and the cart's change in velocity during the collision with the bumper. The impulse is equal to the change in momentum, which can be calculated as:

Impulse = (Mass of Cart) x (Change in Velocity)

We can plot the impulse on the x-axis and the change in velocity on the y-axis, and the slope of the best-fit line will be equal to the mass of the cart.

Here is the graph:

The equation of the best-fit line is:

y = -1.054x + 0.052

where y represents the change in velocity (in m/s) and x represents the impulse (in Ns).

The slope of the best-fit line is -1.054, which represents the mass of the cart in kilograms. Therefore, the experimental value for the mass of the cart is:

Mass of Cart = -slope = -(-1.054) = 1.054 kg

G)

The principle used to calculate the mass of the cart is based on the conservation of momentum. During the collision, the impulse applied to the cart by the bumper is equal to the change in momentum of the cart. By plotting the impulse and the change in velocity on a graph, we can find the slope of the best-fit line, which is equal to the mass of the cart.

what is the likely cause of the haze seen in photographs of pluto's atmosphere taken by the new horizons spacecraft?

Answers

The likely cause of the haze seen in photographs of Pluto's atmosphere taken by the New Horizons spacecraft is the scattering of sunlight by small particles in the atmosphere.

What is haze?

Haze is a phenomenon in which dust, smoke, and other dry particles obscure the clarity of the sky. It causes visibility to be reduced, which makes distant objects appear blurry, and causes the sky to appear dull and gray. The same phenomenon can occur in space as well, where it is called a space haze.

What is Pluto?

Pluto is the smallest dwarf planet in the Solar System and was discovered in 1930. It is located in the Kuiper Belt, a region beyond the orbit of Neptune that contains many small icy bodies. Pluto is the largest object in the Kuiper Belt, with a diameter of 2377 km. In 2015, NASA's New Horizons spacecraft flew by Pluto and provided us with the first close-up images of the planet.

What is New Horizons?

New Horizons is a NASA spacecraft that was launched in 2006 with the goal of studying Pluto and the Kuiper Belt. It flew by Pluto in 2015 and took a number of photographs of the planet and its atmosphere. The spacecraft also studied the composition of the atmosphere, the geology of the surface, and the structure of Pluto's moons.


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A car is traveling at 100 km/h when the driver sees an accident 250 m ahead and slams on the brakes. What constant deceleration is required to stop the car in time to avoid a pileup

Answers

Deceleration required to stop car in time to avoid pileup is 8.16 m/\(s^2\).

To calculate the deceleration required, we need to use the formula: d = \(vi^2\)/2a, where d is the distance, vi is the initial velocity, and a is the acceleration.

Rearranging the formula to solve for a, we get a = \(vi^2\)/2d.

Substituting the values given, we get a = \(100^2\)/(2*250) = 8.16 m/\(s^2\).

This means that the car must decelerate at a constant rate of 8.16 m/\(s^2\)  to stop in time and avoid a pileup.

It is important for drivers to maintain a safe following distance to have enough time to react and avoid collisions.

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Question:Static friction percent error& trying to find the expected static friction value

Info: How do you calculate the static friction percent error for each?

Weight is 277.4g
Static force magnitude 1.1N
Experimented Static Coefficient .5

Weight is 799.8g
Static force magnitude 3.5N
Experimented Static Coefficient .45

Ik it’s ((experimented-expected)/expected)*100 to get the percent error but I don’t know how to calculate the expected

Q: What is the EXPECTED static coefficient for both weights and what is the percent error? How did you get to it?

Answers

Answer:  

The formula to calculate the static friction is given as: Static Friction = Normal Force x Static Friction coefficient. Static friction = 60 N.

Explanation: That's how you caculate it for each of them according to my knowledge sorry if it's wrong,

What came first, a chicken or an egg​

Answers

Answer:

a chicken

a chicken came first

Answer:

A Chicken

A chicken came first

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