when a -2 c charge is moved from point a to b the potential energy of the system increases by 12 j. what is the voltage vba?

Answer: 3.60 grams are needed to make 220 ML of 0.040 m solution

Explanation:

This is due to the fact that the hoop's greater moment of inertia requires more rotating kinetic energy to be transformed into gravitational potential energy, which requires longer time. Option 4 is correct.

We may observe that the hoop takes longer to descend than the cylinder does. In Example 12.12, we applied the idea of energy conservation to determine how long it would take a uniform cylinder to fall a specific distance while still being tied to a rope.

The time to reach the ground would change if a cylindrical-hoop with the same mass and radius were used in place of the uniform cylinder. For a cylindrical hoop with mass M and radius R, the moment of inertia is:

I = M\(R^{2}\)

I = (1/2 )M\(R^{2}\)      

t = \(\sqrt{((4h)/(3g))}\)

t = \(\sqrt{((2h)/(3g))}\)

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Correct Question:

In Example 12.12 (lowering a bucket), if the uniform cylinder were replaced with a cylindrical hoop of the same mass and radius (i.e., most of the mass on of the cylinder is now on the outer rim) the time to reach the ground would: For diagram refer below image:

1. stay the same

2. increase

3. decrease

4. it is not possible to tell without knowing the mass of the bucket.

Agatha requires (c) 10 hours of sleep each night.

Children in middle school ideally require average 9-12 hours of sleep each night. If the number of hours of sleep each night is compromised, it will show effect on the concentration and health of the child.

Because sleep is crucial to your physical health, it is crucial that you receive enough of it every night. For instance, your heart and blood arteries are able to recover and repair themselves as you sleep. An increased risk of heart disease, renal disease, high blood pressure, diabetes, and stroke has been related to chronic sleep deprivation. For the brain and body to operate properly the following day, doctors and specialists advise children to receive at least 9 to 12 hours of sleep each night.

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Answer:

\(5,480\:\text{N}\)

Explanation:

The formula for work is given by \(W=F\Delta x\), where \(F\) is the force applied over a distance of \(\Delta x\).

Plugging in given values, we get:

\(16,700=F\cdot 3.05,\\F=\frac{16,700}{3.05},\\F\approx \boxed{5,480\:\text{N}}\)(three significant figures).

Sure! Here are the steps for calculating the velocity and distance traveled by the car after 50 seconds :

Step 1: Calculate the velocity using the equation:

\(v = u + at\)

where:

- \(v\) is the final velocity

- \(u\) is the initial velocity (0 m/s, as the car starts from rest)

- \(a\) is the acceleration (3 m/s²)

- \(t\) is the time (50 seconds)

Substituting the values into the equation:

\(v = 0 + (3 \, \text{m/s²}) \times (50 \, \text{s})\)

Step 2: Calculate the distance traveled using the equation:

\(s = ut + \frac{1}{2}at^2\)

where:

- \(s\) is the distance traveled

- \(u\) is the initial velocity (0 m/s)

- \(a\) is the acceleration (3 m/s²)

- \(t\) is the time (50 seconds)

Substituting the values into the equation:

\(s = 0 \times (50 \, \text{s}) + \frac{1}{2} \times (3 \, \text{m/s²}) \times (50 \, \text{s})^2\)

Now, let's simplify these equations:

\(v = 3 \times 50\)

\(s = \frac{1}{2} \times 3 \times 50^2\)

Calculating the results:

\(v = 150\) m/s

\(s = 3750\) meters

Therefore, after 50 seconds, the car will have a velocity of 150 m/s and would have traveled a distance of 3750 meters.

Answer:

E) 5100 m.

Explanation:

La persona observa el rayo en el tiempo ty luego escucha el trueno 15 segundos después, el tiempo t + 15.

El observador está a la misma distancia cuando ocurren ambos eventos.

Sabemos que la velocidad se da como la distancia dividida por el tiempo:

s = d / t

=> t = d / s

Para el rayo:

La velocidad de la luz es 3 * 10 ^ 8 m / s. Por lo tanto, el tiempo que tardó el rayo en recorrer una distancia d hasta el observador es:

t = d / 300000000000 _____ (1)

Para el trueno:

La velocidad del sonido en el aire es de 341 m / s. Por lo tanto, el tiempo que tardó el trueno en viajar al observador es:

t + 15 = d / 341

=> t = d / 341 - 15 _____ (2)

Por lo tanto, igualando (1) y (2):

d / 300000000 = d / 341 - 15

=> d / 341 - d / 300000000 = 15

d (1/341 - 1/300000000) = 15

d (0.002933) = 15

d = 15 / 0.002933

d = 5114 m ≅ 5100 m (a la centena más cercana)

Por lo tanto, el observador está a 5100 m.

Answer:Physical

Explanation:

Answer:

physical change

Explanation:

Making a fruit salad, with raw fruits is considered as physical change because in this process chemical composition of fruits is not changed. It is simply changing the shape of the substance.

Answer:

4.5V

Explanation:

In a arrangement of cells, the cells could be joined end to end(series) or to a common junction (parallel).

When cells are joined in series, the total emf of the cell is the sum of the individual emf of all the cells.

Hence;

Total emf = 1.5V + 1.5V + 1.5 V = 4.5 Volts

Answer:

50% of the lunar surface is always illuminated by Sun

Answer:

10m/s

Explanation:

Data

mass=55kg, Maximum height (h1) =10m

Height reached when going down (h2)= 5m

final velocity (v)=?

At Maximum height the velocity is zero

hence intial velocity is 0m/s

The change in Potential energy = change in kinetic energy

mgh1-mgh2=1/2mv²-1/2mu²

But (u)= 0m/s

mgh2-mgh1=1/2mv²

mg(h1-h2)=1/2mv²

2g(h1-h2)=v²

v²=2(10m/s²)(10m-5m)

v²=100m²/s³

v=10m/s

The heat of vaporization at 25°C. The percentage error can be calculated as (|Estimated Value - Actual Value| / Actual Value) * 100.

To estimate the heat of vaporization of benzene at 25°C, we can use different correlations and data:

a) The heat of vaporization at the normal boiling point and Watson's correlation:

The normal boiling point of benzene is approximately 80.1°C. We can assume that the heat of vaporization at the normal boiling point is equal to the heat of vaporization at 25°C. Watson's correlation is a linear approximation that relates the heat of vaporization to the normal boiling point. We can use the equation: ΔHvap = ΔHvap(NBP) * (1 - T/T(NBP)), where ΔHvap(NBP) is the heat of vaporization at the normal boiling point and T(NBP) is the normal boiling point temperature. By substituting the values, we can estimate the heat of vaporization at 25°C.

b) The Clausius-Clapeyron equation and boiling points at 50 mmHg and 150 mmHg:

The Clausius-Clapeyron equation relates the heat of vaporization to the boiling points at different pressures. By using the boiling points of benzene at 50 mmHg and 150 mmHg, we can calculate the heat of vaporization at those pressures using the equation: ln(P1/P2) = ΔHvap/R * (1/T2 - 1/T1), where P1 and P2 are the given pressures, T1 and T2 are the corresponding temperatures, ΔHvap is the heat of vaporization, and R is the ideal gas constant. By rearranging the equation, we can solve for ΔHvap at 25°C.

c) Tables B.1 and B.2 of the text:

Table B.1 provides the heat of vaporization at the normal boiling point, while Table B.2 provides the boiling point at 25°C for different pressures. By using the values from these tables, we can estimate the heat of vaporization at 25°C.

d) Find a tabulated value of the heat of vaporization of benzene at 25°C:

This involves referring to a reliable reference or database that provides tabulated values of the heat of vaporization for benzene at 25°C.

After obtaining the estimated values of the heat of vaporization using each method, we can calculate the percentage errors by comparing them to the tabulated value or a more accurate reference value. The percentage error can be calculated as (|Estimated Value - Actual Value| / Actual Value) * 100.

By using these approaches, we can estimate the heat of vaporization of benzene at 25°C and evaluate the accuracy of the different methods by comparing the calculated percentage errors.

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The measurement of body temperature is an example of a variable that uses option A, interval scale.

A scale with an interval has order and a meaningful difference between two values. Temperature (Fahrenheit), temperature (Celsius), pH, SAT score (200-800), and credit score are a few examples of interval variables (300-850).

One variable that uses interval scale is the measurement of body temperature.

Only ratio scales have a genuine zero, even though interval and ratio data can both be categorized, sorted, and spaced equally apart between consecutive values. As 0 is not the lowest attainable temperature, temperature in Celsius or Fahrenheit, for instance, is measured on an interval scale.

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Answer:

read this it might help some

When a moving object collides with a stationary object of identical mass, the stationary object encounters the greater collision force. When a moving object collides with a stationary object of identical mass, the stationary object encounters the greater momentum change.

Explanation:

\( \underline {\huge \boxed{ \sf \color{skyblue}Answer : }}\)

Given :

\( \tt \large {\color{purple} ↬ } \: \: \: \: \: I_{D} = 5mA\)

\( \: \: \)

\( \tt \large {\color{purple} ↬ } \: \: \: \: \: I_{DSS} = 10mA\)

\( \: \: \)

\( \tt \large {\color{purple} ↬ } \: \: \: \: \: V_{GS(off)} = -6V\)

\( \: \: \)

\( \tt \large {\color{purple} ↬ } \: \: \: \: \: V_{GS} = {?}\)

\( \: \: \: \)

Let's Slove :

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In this lab, the weight of water in a cylinder will be measured using a digital balance while an object is submerged in the water using a string, ensuring it remains suspended without contacting the sides or bottom of the cylinder.

This laboratory experiment aims to investigate the concept of buoyancy and apply Archimedes' principle. By placing a cylinder of water on a digital balance, we can obtain an accurate measurement of the water's weight, which is equivalent to its mass. The digital balance provides precise readings, allowing for accurate calculations.

To study the buoyant force, an object is submerged in the water using a string. It is crucial to ensure that the object remains suspended and does not touch the sides or bottom of the cylinder. By doing so, we eliminate any additional factors that could influence the experiment's outcome and focus solely on the buoyant force acting on the object.

The difference in weight between the water alone and the water with the submerged object represents the buoyant force exerted by the water on the object. This disparity arises because the object displaces a volume of water equal to its own volume, leading to an upward force known as buoyancy. Archimedes' principle states that the buoyant force is equal to the weight of the displaced fluid.

By analyzing the weight difference and understanding the relationship between the weight of the displaced water and the buoyant force, we can gain insights into the principles of buoyancy. This experiment helps reinforce the fundamental concepts of fluid mechanics and demonstrates the practical applications of Archimedes' principle.

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We can solve for A and B by substituting suitable values of s.

\((s * x(0) + dx(0)/dt) = A * (s - r_2) + B * (s - r_1).\)

Once we have the values of A and B, we can apply the inverse Laplace transform to obtain x(t).

To solve a simple harmonic oscillator equation using Laplace inversion, let's consider the following second-order differential equation:

\(m * d^{2} x(t)/dt^{2} + k * x(t) = 0,\)

We can solve this equation using the Laplace transform. The Laplace transform of x(t) is given by X(s), where s is the complex frequency variable.

Applying the Laplace transform to the equation, we get:

\(m * (s^{2} * X(s) - s * x(0) - dx(0)/dt) + k * X(s) = 0.\)

Rearranging the equation, we have:

\(s^{2} * X(s) + (k/m) * X(s) = (s * x(0) + dx(0)/dt).\)

Now, we can solve for X(s):

X(s) = (s * x(0) + dx(0)/dt) / (s² + k/m).

To find the inverse Laplace transform of X(s), we need to decompose it into partial fractions.

Let's assume the roots of the denominator s² + k/m are \(r_1\) and \(r_2\):

\(X(s) = A / (s - r_1) + B / (s - r_2),\)

where A and B are constants.

By equating the numerators, we have:

\((s * x(0) + dx(0)/dt) = A * (s - r_2) + B * (s - r_1).\)

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--The complete Question is, Solve a simple harmonic oscillator equation using  Laplace inversion ?--

Answer:

d.weather conditions

Explanation:

Climate is the sum of weather conditions in a given area,averaged over a long period of time.

1. The data shows that amplitude, period, and tension all affect the speed of a wave. As amplitude and tension increase, the speed of the wave increases, while an increase in period results in a decrease in speed.

What is an amplitude?

Amplitude is the maximum displacement or distance moved by a wave from its resting position. In other words, it is the magnitude of the oscillation in a wave, or the height of a wave from its equilibrium position. In general, the greater the amplitude of a wave, the more energy it carries. In the context of sound waves, amplitude is associated with the loudness of the sound, while in the context of electromagnetic waves (such as light), it is associated with the brightness or intensity of the light.

2. The frequency of a wave has a direct relationship with the wave speed. As the frequency of a wave increases, the speed of the wave also increases.

3. Wave speed decreases as it moves from a medium of low density to one of high density. This is because a denser medium causes more resistance to the wave, resulting in a slower wave speed.

4. If the instrument is initially flat, the player should tighten the string. This is because tightening the string increases the tension, which in turn increases the speed of the wave, resulting in a higher pitch.

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The speed or the tangential velocity of the satellite to keep it in its orbit is  3,073.5 meters per second.

The gravitational force between two objects is given by:

F = GMm/r²

Where:

G = constant of gravity = 6.674 x 10⁻¹¹ N.m²/kg²

M, m = mass of each object

r = distance between objects

Parameters given in the problem:

M = 5.972 x 10²⁴ kg

m = 750 kg

r = 6371 + 35,800 = 42,171 km = 42,171,000 m

Hence,

F = 6.674 x 10⁻¹¹ x 5.972 x 10²⁴ x 750 / 42,171,000²

   = 168.1 N

This is equal to centripetal force:

F = m  . v² / r

168.1  = 750 .  v² /  42,171,000

v² = 9,446,304

v = 3,073.5 m/s

Hence, the tangential velocity of the satellite to keep it in its orbit is  3,073.5 m/s

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From Task 2 data, a general rule for sinking and floating can be described as follows: An object will float in a liquid if its density is less than the density of the liquid. Conversely, an object will sink in a liquid if its density is greater than the density of the liquid.

Density is a fundamental physical quantity that describes the amount of mass per unit volume of a substance. In other words, it is a measure of how tightly packed the particles in a material are. The SI unit of density is kilograms per cubic meter (kg/m³), but other units such as grams per cubic centimeter (g/cm³) and pounds per cubic inch (lb/in³) are also commonly used.

This means that the density of a substance is equal to the amount of mass it contains divided by its volume. For example, if two objects have the same mass but different volumes, the object with the smaller volume will have a higher density because its particles are packed more tightly together.

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A. the change in volume of the cube is approximately 0.120601 cm^3. B. the average rate of change of volume of the cube with respect to an edge length is approximately 12.0601 cm^3/cm. C. the equation of the line that passes through the point (1, 5) and is parallel to the tangent line to f(x) = 1/x at x = 3 is y = (-1/9)x + 14/9.

(a) To find the change in volume of the cube as x increases from 2.00 to 2.01 centimeters, we need to calculate the difference in volume between these two values.

The volume of a cube is given by V = x^3, where x is the edge length.

For x = 2.00 cm, the volume V1 = (2.00 cm)^3 = 8.00 cm^3.

For x = 2.01 cm, the volume V2 = (2.01 cm)^3 = 8.120601 cm^3.

The change in volume is ΔV = V2 - V1 = 8.120601 cm^3 - 8.00 cm^3 ≈ 0.120601 cm^3.

Therefore, the change in volume of the cube is approximately 0.120601 cm^3.

(b) The average rate of change of volume of the cube with respect to an edge length as x increases from 2.00 to 2.01 centimeters can be calculated by dividing the change in volume by the change in edge length.

ΔV = 0.120601 cm^3 (from part a)

Δx = 2.01 cm - 2.00 cm = 0.01 cm

The average rate of change of volume is ΔV/Δx = 0.120601 cm^3 / 0.01 cm ≈ 12.0601 cm^3/cm.

Therefore, the average rate of change of volume of the cube with respect to an edge length is approximately 12.0601 cm^3/cm.

(c) The instantaneous rate of change of volume of the cube with respect to an edge length at the instant when x = 2 centimeters can be found by taking the derivative of the volume function V = x^3 with respect to x and evaluating it at x = 2.

dV/dx = 3x^2

At x = 2 cm, the instantaneous rate of change of volume is dV/dx evaluated at x = 2:

dV/dx = 3(2 cm)^2 = 12 cm^2.

Therefore, the instantaneous rate of change of volume of the cube with respect to an edge length at x = 2 centimeters is 12 cm^2.

To find the equation of the line that passes through the point (1, 5) and is parallel to the tangent line to f(x) = 1/x at x = 3, we need to determine the slope of the tangent line.

The derivative of f(x) = 1/x is given by f'(x) = -1/x^2.

At x = 3, the slope of the tangent line is f'(3) = -1/(3^2) = -1/9.

Since the line we want to find is parallel to the tangent line, it will have the same slope. So the slope of the line is -1/9.

Using the point-slope form of a linear equation, we can write the equation of the line as:

y - y1 = m(x - x1),

where (x1, y1) is the given point (1, 5) and m is the slope.

Substituting the values, we have:

y - 5 = (-1/9)(x - 1).

Expanding and rearranging the equation, we get:

y = (-1/9)x + 14/9.

Therefore, the equation of the line that passes through the point (1, 5) and is parallel to the tangent line to f(x) = 1/x at x = 3 is y = (-1/9)x + 14/9.

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The transfer of energy causes atoms and molecules to vibrate more rapidly, which in turn causes matter to heat up.

All electromagnetic waves, including microwaves, are forms of energy that oscillate at specific frequency. When waves interact with matter, they  transfer their energy to atoms and molecules within that matter. This transfer of energy causes atoms and molecules to vibrate more rapidly, which causes the matter to heat up.

Microwaves are particularly efficient at heating water because frequency is in the range that matches natural resonance frequency of water molecules. This means that they transfer energy more efficiently to water molecules, which results in faster heating as compared to other forms of electromagnetic waves.

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Answer: The conditions would probably exist the drew point and dry bulb temperatures to be the same at the ground because When the dew point temperature and air temperature are equal, the air is said to be saturated. Dew point temperature is NEVER GREATER than the air temperature. Therefore, if the air cools, moisture must be removed from the air and this is accomplished through condensation.

Explanation:

Since the air is said to be saturated when the dew point temperature and air temperatures are equal, the circumstances are likely present for the dew point and dry bulb temperatures to be equal at the ground. NEVER is the dew point temperature higher than that of the air temperature. As a result, condensation is used to remove moisture from the air when it cools.

The dew point, under the assumption of constant air pressure and water content, is the temperature at which air must be chilled to become water vapor condenses. Airborne vapor will condense to create liquid water, known as dew, when it is cooled below the dew point, thereby moisture capacity.  If this occurs via coming into contact with a cooler surface, dew will grow there.

Humidity influences the dew point. The dew point rises as the amount of moisture in the atmosphere increases.

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The current flowing when the charge is transfered at different rates are:

A. 4.5 A4.5 A

B. 3.2 A

C. 4.6 A

D. 3 A

E. 2 A

F. 13 A

G. 6.4 A

H. 8.8 A

I. 0.5 A

We know that charge, current and time are related by the following formula:

Charge (Q) = Electric current (I) × time (t)

Q = It

Divide by t

I = Q / t

With the above formula, we can obtain the current. Details below:

A. How do I determine the current?

I = Q / t

I = 4.5 / 1

I = 4.5 A

B. How do I determine the current?

I = Q / t

I = 192 / 60

I = 3.2 A

C. How do I determine the current?

I = Q / t

I = 16560 / 3600

I = 4.6 A

D. How do I determine the current?

I = Q / t

I = 1.8 / 0.6

I = 3 A

E. How do I determine the current?

I = Q / t

I = 3.2 / 1.6

I = 2 A

F. How do I determine the current?

I = Q / t

I = 33.8 / 2.6

I = 13 A

G. How do I determine the current?

I = Q / t

I = 147.2 / 23

I = 6.4 A

H. How do I determine the current?

I = Q / t

I = 7920 / 900

I = 8.8 A

I. How do I determine the current?

Charge (Q) = 7920 C

Time (t) = half hour = 30 mins = 30 × 60 = 1800 s

Current (I) = ?

I = Q / t

I = 900 / 1800

I = 0.5 A

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answer:

click on the picture, hope it helps

The magnitude of the electric field at that location is is 40  N.C⁻¹.

The force per unit charge exerted on a positive test charge that is at rest at a given position is the force per unit charge that is used to define the electric field analytically.

Electric charge or magnetic fields with variable amplitudes can produce an electric field.

Given parameters:

Charge of the positive test charge, q =  5.0x10⁻⁶ C.

Electric force exerted by the electric field, F = 2.0x10⁻⁴ N.

Then, electric field at the position, E = F/q

= 2.0x10⁻⁴ / 5.0x10⁻⁶ N.C⁻¹.

= 40  N.C⁻¹.

Hence,  the magnitude of the electric field at the location of the test charge is 40  N.C⁻¹.

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Answer:

B seismic wave

Answer:

d= 1.5 g/cm3

Explanation:

datos

m= 30g

v= 20cm3

d=?

formula

d= m / v

solución

d= 30g / 20cm3 = 1.5g/cm3