when a charged ruler attracts small pieces of paper, somtimes a piece jumps quickly away after touching the ruler. explain

The white dwarf would explode completely as a white dwarf supernova if it gained enough mass to reach the 1.4 solar-mass white dwarf limit.

This is referred to as an occurrence which is characterized by the shattering or blowing apart of something and is usually accompanied with the release of a certain amount of energy.

In a situation whereby a white dwarf gains mass to reach the 1.4 solar-mass white dwarf limit then there will be an explosion as a result of the white dwarf undergoing a collapse and expelling the excess mass thereby making it the correct choice.

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Answer:

engaging in more exercise

Explanation:

Maladaptive means not providing an adequate or appropriate adjustment to the environment or situation. Therefore the question is asking which is Not a bad way to respond to stress.

Answer: letter B

Explanation:

As you can see the battery only has one wire connected to it thus not a complete loop

its b trust me man ;oih wrio'weioa'yher

A beam of blue light causes photoelectrons to be emitted from a photoemissive surface. An increase in the intensity of the blue light will cause an increase in the number of photoelectrons emitted. Therefore, an increase in the intensity of blue light will cause an increase in the light intensity.

What is light? Light is a type of electromagnetic radiation that travels in waves at a velocity of 299,792 kilometers per second (km/s) in a vacuum. It is a form of energy and, like all forms of energy, can be transferred. Light, like other electromagnetic waves, has both electric and magnetic fields that oscillate perpendicularly to one another at right angles.Light has a very important property, which is its intensity. The amount of light that passes through a given area or space per unit time is known as light intensity. It is the amount of light energy that falls on a unit area in a given time. The energy of light, like all energy, can be described in terms of photons.

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The activity that is not part of sustainable development is option 3, where forests are cut down and new trees regrow to replace them. This is because it takes several years for new trees to grow, and the rate at which they are being cut down is much higher than the rate at which they are being replaced.

This can lead to deforestation, which can cause soil erosion, water pollution, and loss of biodiversity.
On the other hand, options 1, 2, and 4 are sustainable activities as they focus on conserving resources and reducing environmental impact.

Limited harvesting of fish ensures that their populations are not depleted, while replacing water in the Great Lakes ensures that the ecosystem remains balanced. Solar energy is a renewable source of energy that does not produce harmful emissions and reduces the dependence on non-renewable sources like coal and oil.

In conclusion, sustainable activities focus on using resources in a responsible and efficient manner, ensuring that they are not depleted and do not cause harm to the environment. It is essential to adopt sustainable practices to ensure the long-term health and well-being of our planet.

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So here, we use the equation:

W = ΔKE + ΔPE

Recall that: KE = 0.5mv^2, and PE = qdΔV/D

ΔKE = 0.5m(v2)^2 - 0.5m(v1)^2, where v2 and v1 are Initial and final velocity respectively.

ΔPE = PE2 - PE1

PE2 = 0, since all energy is converted to other forms, mainly kinetic energy.

PE1 = q(d1)ΔV/D

Here, W = 0.

0 = 0.5m(v2)^2 - 0.5m(v1)^2 + 0 - q(d1)ΔV/D

Simplifying a bit, and knowing that d1 = D,

0 = 0.5m((v2)^2 - (v1)^2) - qΔV

Moving qΔV to the other side,

qΔV = 0.5m((v2)^2 - (v1)^2)

Dividing by q and isolating ΔV,

ΔV = 0.5m * ((v2)^2 - (v1)^2) / q

Now, we have ΔV, which is the electric potential difference, in terms of all the variables we know.

m = 9.1 * 10^-31

v2 = 1 * 10^6

v1 = 5 * 10^6

q = 1.602 * 10^-19 (this is a well known constant)

ΔV = 0.5*9.1*10^-31 * ((5*10^6)^2 - (1*10^6)^2) / 1.602*10^-19

Solving and simplifying all of this, we get that

ΔV = 68.25 V

Answer:

See below

Explanation:

1.  Measure and record the length of the nichrome wire (in cm)

2.  Measure and record the voltage of the DC power supply with the voltmeter (in volts).

3.  Assemble a circuit:

4,  Measure and record the current (in amps).

Use the equation V = IR, where V is volts, I is amps, and R is the resistance, in ohms.  Solve for R (R = V/I)

5.  Divide the value of R by the length on the nichrome wire.  This will produce a number with units of ohms/cm, the desired "resistance per unit length​."

The acceleration of a particle is a= (-1.6 v1/2) m/s². The initial velocity of the particle is u = 8 m/s.

Now, let's use the formula: 2as = v² - u², where a = (-1.6v^(1/2)) m/s², u = 8 m/s, and v = 0 m/s 2 × (-1.6v^(1/2)) × s = 0 - 8²s = 64 / (2 × 1.6v^(1/2)) = 20v^(1/2)/4 = 5v^(1/2) meters.

This is the distance travelled by the particle before it stops.

We know that the final velocity of the particle is 0 m/s. The initial velocity of the particle is 8 m/s.

The acceleration of the particle is a = (-1.6v^(1/2)) m/s².

Let's use the formula to calculate the time it takes to stop the particle. It is:v = u + at 0 = 8 + (-1.6v^(1/2)) × t t = 8 / (1.6v^(1/2)) t = 5 / v^(1/2) seconds.

This is the time taken by the particle to come to rest.

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The particle travels approximately 12.5 meters before it comes to a stop. It takes approximately 5 seconds for the particle to reach zero velocity.

To determine the distance traveled before the particle comes to a stop, we need to integrate the velocity function over time. The given deceleration is expressed as a = -1.6√v , where v is the velocity in m/s. Since the initial velocity is 8 m/s, we can write the deceleration as a = -1.6√8. Integrating the acceleration with respect to velocity gives us the equation: ∫dv/(-1.6√v ) = ∫dt. Simplifying the integral and solving for t gives us t = 5 seconds.

To find the distance traveled, we integrate the velocity function with respect to time. The velocity function is given by dv/dt = -1.6√v. Separating variables and integrating, we get ∫dv/√v  = ∫-1.6dt. Evaluating the integral and substituting the limits (from v = 8 m/s to v = 0), we find √v = -1.6t + C. Applying the initial condition v(0) = 8, we can solve for C and obtain C = √8. Plugging in the values for t and C, we get √v = -1.6t + √8. Squaring both sides and solving for v, we find v = \((1.6t - \sqrt{8} )^{2}\). Integrating the velocity function again with respect to time, we get ∫\((1.6t - \sqrt{8} )^{2}\) dt = ∫ds. Evaluating the integral and substituting the limits, we find s = 12.5 meters.

Therefore, the particle travels approximately 12.5 meters before coming to a stop.

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When a light source is turned on, it emits photons that scatter in different directions and hit every object that is present around it.

This is referred to as the path in which electric current can flow around and comprises of some components such as resistors, bulb etc. There are two types which include open and closed circuit.

When the light source is turned on, the circuit is closed and there is complete flow of electrons which powers up the bulb and gives rise to the emission of the photons which hits objects around it thereby giving rise to the illumination of the area.

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Answer:

D: D= m/v

Explanation:

That is the right formula. I like to remember that finding density takes a lot of HEART because it is shaped like a heart

The field strength E at a distance of 3 meters from the charge is 1 V/m. Hence E= 1 V/m

To find the field strength E at a distance of 3 meters from the charge, we can use the inverse square law for electric fields, which states that the field strength is inversely proportional to the square of the distance from the charge.

Step 1: Write down the given values.
E1 = 9 V/m (field strength at 1 meter)
d1 = 1 m (distance 1)

Step 2: Determine the desired values.
E2 = ? (field strength at 3 meters)
d2 = 3 m (distance 2)

Step 3: Apply the inverse square law.
\(E1/E2 = (d2/d1)^2\)

Step 4: Solve for E2.
\(E2 = E1 * (d1/d2)^2\)

Step 5: Plug in the given values and calculate.
\(E2 = 9 V/m * (1 m/3 m)^2 = 9 V/m * (1/3)^2 = 9 V/m * (1/9) = 1 V/m\)

So, the field strength E at a distance of 3 meters from the charge is 1 V/m.

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Answer:

A  75.1 N and a direction of 152° to the vertical.

B 85.0 N at 0° to the vertical.

Explanation:

A) The interaction partner of this normal force has what magnitude and direction?

The interaction partner of this normal force is the component of the weight of the crate perpendicular to the ramp. It has a magnitude of 85cos28° = 75.1 N and a direction of 180° - 28° = 152° to the vertical(since it is directed downwards perpendicular to the ramp).

B) The normal and frictional forces are perpendicular components of the contact force exerted on the crate by the ramp. What is the magnitude and direction of the contact force?

Since this force has to balance the weight of the crate, its magnitude is 85.0 N. Its direction has to be vertically opposite to that of the weight.

Since the weight is 180° to the vertical (since it is directed downwards), this force is 0° to the vertical.

So, this force has a magnitude of 85.0 N and a direction of 0° to the vertical.

Answer:

The correct option is;

Technician A only

Explanation:

Leaks in the cooling system parts such as the radiator cap can be tested with a pressure operated hand pump by attaching the pump cap to the pump with an adaptor and apply pressure enough for there to be a release of pressure at the cap.

The pressure added to the system should be maintained for up to two minutes. If the pressure drops quicker, then there is likely to be leaks in the system

The freezing and boiling point of the coolant is measured with an antifreeze tester which carries the appropriate apparatus to measure the coolants freezing and boiling points.

Answer:Caloric theory, explanation, widely accepted in the 18th century, of the phenomena of heat and combustion in terms of the flow of a hypothetical weightless fluid known as caloric. ... The idea of an imaginary fluid to represent heat helped explain many but not all aspects of heat phenomena.

Explanation:

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A displacement of 14.14 m, connecting the identical beginning and finishing points, is larger than a distance of 20 m.

The sequence's displacement is computed as follows;

Δx = √[(x₂ - x₁)² + (y₂ - y₁)²]

Δx = √[(-5 - 5)² + (-5 - 5)²]

Δx = 14.14 m

This leads us to the conclusion that a displacement of 14.14 m, which links the identical beginning and finishing points, is more than a distance of 20 m.

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a. The final pressure is 1.39 atm.

b. The final temperature is 80.4 °C.

The final pressure can be calculated using the adiabatic expansion equation:

P₂/P₁ = (V₁/V₂)^(γ)

where P₁, V₁, and P₂, V₂ are the initial and final pressures and volumes, respectively, and γ is the adiabatic index, which is 1.4 for diatomic gases like O2.

Substituting the given values, we get:

P₂/2.5 atm = (1/2)^(1.4)

P₂ = 1.39 atm

Therefore, the final pressure is 1.39 atm.

The final temperature can be calculated using the adiabatic expansion equation:

T₂/T₁ = (V₁/V₂)^(γ-1)

Substituting the given values, we get:

T₂/443.15 K = (1/2)^(0.4)

T₂ = 353.4 K

Therefore, the final temperature is 80.4 °C.

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At the 39.7 cm mark on the meter stick, the electric potential (relative to infinity) is -140.74 x 106 V.

Electric potential is the effort required to transport an units charge from one place to another in the presence of an electric field. Earth is typically chosen as the reference point, but any location outside the range of the applied electric charge can be used. potential electricity.

Let the negative charge be located at the left end of the meter stick and the positive charge at the right end. E = kq / x2, where k is the Coulomb constant (8.99 x 109 Nm2/C2) and q seems to be the charge at the left end of the meter stick, can be used to calculate the electric field at a location x cm from the left end of the meter stick (4.02 C).

The following equation can be applied to compute the electrical potential difference seen between left end of the meter stick & infinity:

ΔV left = -kq / d = -kq / 100 cm = -kq / 0.01 m = -8.99 x 10^9 Nm^2/C^2 * 4.02 C / 0.01 m = -359.57 x 10^6 V

Similarly, the electric potential difference between the right end of the meter stick and infinity can be calculated as:

ΔV right = kq / d = kq / 100 cm = kq / 0.01 m = 8.99 x 10^9 Nm^2/C^2 * 4.02 C / 0.01 m = 359.57 x 10^6 V

The total electric potential difference between the 39.7 cm mark and infinity can then be calculated as:

ΔV_total = ΔV_left + ΔV_right * (100 cm - 39.7 cm) / 100 cm = -359.57 x 10^6 V + 359.57 x 10^6 V * (100 cm - 39.7 cm) / 100 cm = -359.57 x 10^6 V + 218.83 x 10^6 V = -140.74 x 10^6 V

Therefore, the electric potential (V) at the 39.7 cm mark relative to infinity can be calculated as:

V = ΔV_total = -140.74 x 10^6 V

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To create a spark between two plates, electrons must be transferred from one plate to the other. The number of electrons required depends on the charge carried by each electron and the total charge needed to create the spark.

The charge carried by each electron is 1.6 x 10^-19 coulombs. Let's assume that the total charge needed to create the spark is Q coulombs. To determine the number of electrons required, we can use the formula:

Number of electrons = Total charge / Charge carried by each electron

So, the number of electrons (N) can be calculated as:

\(N = Q / (1.6 \times 10^-19)\)

For example, if the total charge needed is 1.6 x 10^-5 coulombs, then the number of electrons required would be:

\(N = (1.6 \times 10^-{5}) / (1.6 \times 10^{-19}) = 1 \times 10^{14} electrons.\)

Therefore, in this example, 1 x 10^14 electrons must be transferred from one plate to the other to create a spark between the plates.

In summary, the number of electrons required to create a spark between two plates depends on the total charge needed and the charge carried by each electron.

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Answer: True

Explanation: got it right

Answer:

0.5A

Explanation:

Using \(R = \frac{V}{I}\),

R is the resistance (in Ohms)

V is the voltage (in V)

I is the current (in A)

\(240=\frac{120}{I}\)

I = 0.5A

Answer:

1. Cellular respiration is the process in which cells break down glucose, release the stored energy, and use it to make ATP. The process begins in the cytoplasm and is completed in a mitochondrion. Cellular respiration occurs in three stages: glycolysis, the Krebs cycle, and electron transport.

2. How much ATP is produced in all three stages combined? Glycolysis produces 2 ATP molecules, and the Krebs cycle produces 2 more. Electron transport from the molecules of NADH and FADH2 made from glycolysis, the transformation of pyruvate, and the Krebs cycle creates as many as 32 more ATP molecules.

3. Photosynthesis converts carbon dioxide and water into oxygen and glucose. ... Cellular respiration converts oxygen and glucose into water and carbon dioxide. Water and carbon dioxide are by- products and ATP is energy that is transformed from the process.

4. Aerobic respiration takes place in presence of oxygen; whereas anaerobic respiration takes place in absence of oxygen. Carbon dioxide and water are the end products of aerobic respiration, while alcohol is the end product of anaerobic respiration. Aerobic respiration releases more energy than anaerobic respiration.

Answer:

KE = 1/2 M V^2

V = (2 KE / M)^1/2 = (2 * 40 / .1)^1/2 = 28.3 m/s

ANSWER

T₂ = 10.19N

EXPLANATION

Given:

• The mass of the ball, m = 1.8kg

First, we draw the forces acting on the ball, adding the vertical and horizontal components of each one,

In this position, the ball is at rest, so, by Newton's second law of motion, for each direction we have,

The components of the tension of the first string can be found considering that they form a right triangle, where the vector of the tension is the hypotenuse,

We have to find the tension in the horizontal string, T₂, but first, we have to find the tension 1 using the first equation,

Solve for T₁,

Now, we use the second equation to find the tension in the horizontal string,

Solve for T₂,

Hence, the tension in the horizontal string is 10.19N, rounded to the nearest hundredth.

Answer: won’t let me not put something down

Explanation:

Answer:

the momentum is 50 kg m/s

Explanation:

The computation of the momentum is shown below;

As we know that

Momentum = mass × velocity

where

mass = 5 kg

And, the velocity is 10 m/s

So, the momentum is

= 5 × 10

= 50 kg m/s

Hence, the momentum is 50 kg m/s

The current sensitivity of the first coil is  0.5 times that of the second coil. The voltage sensitivity of the first coil is 2.5 times that of the second coil.

Current sensitivity can be determined as how much a galvanometer will deflect on flowing some current through it. Voltage sensitivity can be determined by how much the galvanometer will show deflection when a potential difference is developed across its ends.

Current sensitivity is directly proportional to the number of turns while voltage sensitivity is the ratio of the number of turns of the coil to the resistance.

The number of turns in the first coil, n₁ = 50

The number of turns in the second coil, n₂= 100

The current sensitivity:

\(\frac{CS_1}{CS_2}= \frac{50}{100}\)

C.S₁ = 0.5 C.S₂

The current sensitivity of the first coil is  0.5 times that of the second coil.

Given the resistance of the first coil = 10 ohm

The resistance of the second coil = 50 ohm

The voltage sensitivity of coils:

\(\frac{V.S_1}{V.S_2} =\frac{50/10}{100/50}\)

V.S₁ = 2.5 V.S₂

The voltage sensitivity of the first coil is 2.5 times that of the second coil.

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When heating this reaction mixture at reflux, the reaction temperature will be maintained approximately at 100C. Thus, C is the correct option.

Heating the chemical reaction for a specific amount of time, while continually cooling the vapour produced back into liquid form, using a condenser is called Reflux. The vapours produced during the reaction above continually undergo condensation, returning to the flask as a condensate.

In general, the temperature of a reflux reaction will depend on the boiling point of the solvent used. If the solvent has a boiling point of 100°C, for example, then the reaction temperature will be maintained at approximately 100°C when the reaction mixture is heated at reflux.

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Answer:m=42kg

Explanation:

wieght = mass × gram

420 = mass × 10

therefore , answer is 42

Answer:

\(\huge \boxed{\mathrm{42 \ kg} }\)

Explanation:

\(\sf Weight \ (N) = mass \ (kg) \times acceleration \ of \ gravity \ (m/s^2)\)

\(\sf W=m \times g\)

We know that the acceleration of gravity on the Earth is approximately 10 m/s.

The weight of the body is given 420 N.

\(\sf 420=m \times 10\)

Solve for the mass. Divide both sides by 10.

\(\sf m = 42\)

The mass of the body is 42 kg.

Most of the ten million tonnes of particles known as solar wind that leave the sun each year do so through places known as coronal holes.

The corona is the name given to the outermost part of the Sun's atmosphere. Usually, the Sun's bright surface light makes the corona invisible. It gets difficult to see without using certain instruments.

A halo is a ring or light that develops around the sun or moon as a result of light from the sun or moon reflecting off ice crystals found in a thin layer of cirrus clouds. The halo is typically perceived as a dazzling, white ring, however it occasionally has colour.

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work is done by the force F on the two block system is 31.59 J.

The work done by a force on an object is given by the formula W = Fd cosθ where F is the force, d is the displacement, and θ is the angle between the force and the displacement vectors.

When the force and the displacement are in the same direction, theta is 0 degrees, and the work done is positive, meaning energy is transferred to the object. When the force and the displacement are in opposite directions, theta is 180 degrees, and the work done is negative, meaning energy is transferred away from the object.

In this case, the force F is pulling to the left and the displacement d is also to the left, so the angle between them is 0 degrees (cos 0 = 1).

Therefore, the work done by the force on the two-block system is:

W = Fd cosθ = (39.0 N)(0.81 m)(1) = 31.59 J

So the work done by the force is 31.59 J.

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