when a kid drops a rock off the edge of a cliff, it takes 4.0 seconds to reach the ground below. when she throws the rock down, it strikes the ground in 3.0 seconds. what initial speed did she give the rock?

Answers

Answer 1

the initial speed that the kid gave the rock when throwing it downward is approximately 5.75 m/s.

To determine the initial speed that the kid gave the rock when throwing it down, we can use the equations of motion for free fall.

When the rock is dropped:

The time taken (t) is 4.0 seconds, and we assume the initial velocity (u) is 0 (since the rock was dropped without an initial upward or downward velocity). We can use the equation:

s = ut + (1/2)gt^2

where s is the distance fallen, u is the initial velocity, t is the time taken, and g is the acceleration due to gravity.

When the rock is thrown:

The time taken (t) is 3.0 seconds, and we need to find the initial velocity (u). We can use the same equation as above:

s = ut + (1/2)gt^2

Since the rock was thrown downward, the initial velocity (u) will be negative.

Now, we can set up the equations:

For dropping the rock:

0 = 0 + (1/2)g(4.0)^2

For throwing the rock:

s = ut + (1/2)gt^2

Substituting the given values:

s = ut + (1/2)gt^2

0 = u(3.0) + (1/2)g(3.0)^2

Simplifying the equations:

(1/2)g(4.0)^2 = (3.0)u + (1/2)g(3.0)^2

8g = 6u + 4.5g

Rearranging the equation:

6u = 8g - 4.5g

6u = 3.5g

Dividing both sides by 6:

u = (3.5g) / 6

Substituting the approximate value for the acceleration due to gravity (g ≈ 9.8 m/s^2):

u ≈ (3.5 * 9.8) / 6

Calculating the value:

u ≈ 5.75 m/s

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Related Questions

A
heat engine is measured to have 30% efficiency. Is the theoretical
efficiency going to be greater or less than that? Why?

Answers

The theoretical efficiency is greater than that of the actual efficiency of the engine. This is because heat engine always produces some waste heat.

The Second Law of Thermodynamics states that a heat engine cannot be 100% efficient. In practice, a heat engine is only 100% efficient when it is operating at about 30-50% efficiency.

If we were to multiply this by 100, we would get the efficiency as a percent: 49%. This is the theoretical maximum efficiency. If we were to actually build an engine, it would be less efficient than the theoretical engine. The theoretical engine that can achieve this theoretical maximum efficiency is called the Carnot Engine.

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8\%) Problem 9: The maximum horizontal distance that Jean can throw a baseball is 58.2 m : D Assuming she can throw with the same initial speed at all launch angles, to what maximum height (measured in meters above the release point) will the ball rise if she throws it straight upward?

Answers

The maximum height the ball will rise if Jean throws it straight upward is 0 meters above the release point.

To find the maximum height the ball will rise if Jean throws it straight upward, we can use the concept of projectile motion. The key idea is that the vertical component of the initial velocity is zero at the highest point of the trajectory.
Given that the maximum horizontal distance is 58.2 m, we can assume that the initial speed (also known as the magnitude of the initial velocity) is constant for all launch angles.  

Let's denote the maximum height as "h" (measured in meters above the release point). At the highest point of the trajectory, the vertical velocity component will be zero.
Using the equation for the vertical displacement in projectile motion, we have:

Vertical displacement = (Initial vertical velocity * time) + (0.5 * acceleration due to gravity * time^2)

Since the ball is thrown straight upward, the initial vertical velocity is positive (upward). The acceleration due to gravity is negative (downward). Therefore, the equation becomes:
h = (0 * t) + (0.5 * (-9.8 m/s^2) * t^2)

Simplifying the equation, we have:
h = -4.9t^2

To find the time it takes for the ball to reach its highest point, we need to use the equation for the vertical component of the velocity:

Vertical velocity = Initial vertical velocity + (acceleration due to gravity * time)
Since the vertical velocity is zero at the highest point, we have:
0 = 0 + (-9.8 m/s^2) * t

Solving for t, we find:
t = 0

This means that at the highest point of the trajectory, the ball has been in the air for 0 seconds.
Substituting t = 0 into the equation for h, we find:
h = -4.9(0)^2
h = 0

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When Jean throws the ball straight upward, it will not rise to any height above the release point. It will only reach the same level as the release point. To determine the maximum height the ball will reach when thrown straight upward, we need to use the concept of projectile motion. When the ball is thrown straight upward, it experiences a vertical motion under the influence of gravity.

First, we need to find the initial vertical velocity of the ball. Since the ball is thrown straight upward, the initial vertical velocity is equal to zero.

Next, we need to find the time it takes for the ball to reach its maximum height. We can use the equation:

    t = (final velocity - initial velocity) / acceleration

The final velocity is zero, the initial velocity is zero, and the acceleration due to gravity is -9.8 m/s^2 (taking downward as negative). Therefore, the time taken to reach the maximum height is zero.

Now, we can use the equation for vertical displacement:

    Δy = (initial velocity * t) + (0.5 * acceleration * t^2)

Substituting the values, we get:

    Δy = (0 * 0) + (0.5 * -9.8 * 0^2)
=> Δy = 0

This means that the maximum height the ball will rise is 0 meters above the release point. The ball will reach the same level from where it was thrown, but not higher.

In conclusion, when Jean throws the ball straight upward, it will not rise to any height above the release point. It will only reach the same level as the release point.

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Hydrogen can be prepared by suitable electrolysis of aqueous magnesium salts. True or false?
Answer is true.
Hydrogen can be prepared by suitable electrolysis of aqueous silver salts. True or false?
Answer is false.
How do you solve both of these and what is the difference between the two?

Answers

Hydrogen can be prepared by suitable electrolysis of aqueous magnesium salts is true.

This is because,

Hydrogen is produced from water when a direct current is passed through the water. Hydrogen ions are generated at the anode by oxidation of water. Magnesium salts are electrolyzed in the presence of a little sulfuric acid to produce hydrogen gas at the cathode and oxygen gas at the anode. Magnesium hydroxide and magnesium oxide are formed in the anode compartment.2H2O → O2 + 2H2

The statement Hydrogen can be prepared by suitable electrolysis of aqueous silver salts is false.

This is because,

This is because silver is an extremely noble metal that is resistant to chemical attack; thus, it is a poor conductor of electricity. As a result, silver is not used in the production of electrolytes. Silver is also used in the purification of electrolyte solutions due to its chemical and physical properties.

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You want to lift a heavy box with a mass L = 64.0 kg using the two-ideal pulley system as shown. With what minimum force do you have to pull down on the rope in order to lift the box at a constant velocity? One pulley is attached to the ceiling and one to the box.

You want to lift a heavy box with a mass L = 64.0 kg using the two-ideal pulley system as shown. With

Answers

The given problem can be solved using the following free-body diagram:

The diagram is the free-body diagram for the pulley that is holding the weight. Where:

\(\begin{gathered} T=\text{ tension} \\ m=\text{ mass} \\ g=\text{ acceleration of gravity} \end{gathered}\)

Now we add the forces in the vertical direction:

\(\Sigma F_v=T+T-mg\)

Adding like terms:

\(\Sigma F_v=2T-mg\)

Now, since the velocity is constant this means that the acceleration is zero and therefore the sum of forces is zero:

\(2T-mg=0\)

Now we solve for "T" by adding "mg" from both sides:

\(2T=mg\)

Now we divide both sides by 2:

\(T=\frac{mg}{2}\)

Now we substitute the values and we get:

\(T=\frac{(64\operatorname{kg})(9.8\frac{m}{s^2})}{2}\)

Solving the operations:

\(T=313.6N\)

Now we use the free body diagram for the second pulley:

Now we add the forces in the vertical direction:

\(\Sigma F_v=T-F\)

The forces add up to zero because the velocity is constant and the acceleration is zero:

\(T-F=0\)

Solving for the force:

\(T=F\)

Therefore, the pulling force is equal to the tension we determined previously and therefore is:

\(F=313.6N\)

You want to lift a heavy box with a mass L = 64.0 kg using the two-ideal pulley system as shown. With
You want to lift a heavy box with a mass L = 64.0 kg using the two-ideal pulley system as shown. With

John has a utility function of the following: UL, C) = L ^BC ^(1-ẞ), where L is leisure and C is consumption. If he works, he receives a real wage w. Outside of the labor market, he has nonlabor market income V. And his endowment of time T is normalized to 1. And the price of goods p is also normalized to 1.
(a) Please write down his budget constraint.
(b) Assuming ẞ = 1/2, V = 100, w = 200, what is his optimal supply of labor?
(c) How much total income does he have?
(d) How much consumption will he make?
(e) Now, consider the case where John is subject to a 10% income tax on labor income only. What is his new optimal supply of labor?

Answers

(a) The budget constraint can be written as: C = wL + V, where C is consumption, w is the real wage, L is leisure, and V is non-labor market income.

(b) With ẞ = 1/2, V = 100, and w = 200, John's optimal supply of labor cannot be determined without information about his preferences for leisure and consumption. The utility function only represents his preferences, but we need additional information to determine the specific amount of labor he would choose to supply.

(c) John's total income is the sum of his labor income and non-labor market income: Total income = Labor income + Non-labor income = wL + V. Without knowing the specific value of L, we cannot calculate the total income.

(d) Similarly, without knowing John's preferences for leisure and consumption, we cannot determine the specific level of consumption he would choose.

(e) In the case where John is subject to a 10% income tax on labor income only, his new optimal supply of labor would depend on the tax rate's impact on his preferences and the trade-off between leisure and consumption. Without further information on his preferences and the specific tax structure, we cannot determine the new optimal supply of labor.

Additional information about John's preferences for leisure and consumption, as well as the specific tax structure, is necessary to calculate his optimal labor supply, total income, consumption, and the impact of the income tax on his labor supply.

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About how many half-lives have elapsed when a radioactive substance has decayed to less than 1% of its original amount? 05 O 50 07 O 10 32 99

Answers

About 7 half-lives have elapsed when a radioactive substance has decayed to less than 1% of its original amount.

Radioactive decay is a process where a nucleus of an unstable atom loses energy by emitting radiation. The amount of time it takes for half of a sample to decay is called the half-life of the substance. If we want to know the amount of time it takes for a radioactive substance to decay to less than 1% of its original amount, then it would require a minimum of 7 half-lives to pass by.

This is because, after each half-life, the amount of radioactive substance will be reduced by 50%. So, if we take 50% for 7 times (7 half-lives), it will give us a value that is less than 1%. Therefore, about 7 half-lives have elapsed when a radioactive substance has decayed to less than 1% of its original amount.

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What is the element, atomic number, mass number, and charge of the image?

What is the element, atomic number, mass number, and charge of the image?

Answers

Answer:

1. Beryllium

2. 4

3. 9

4. 0

Explanation:

• The element shown in the image is beryllium because the atom shown contains four protons and the only element with four protons is beryllium.

• The atom's atomic number is 4, because atomic number is the number of protons of an element, and the atom shown contains 4 protons.

• The mass number of the atom is 9. Mass number is the sum of the number of protons and neutrons in the nucleus of an atom, and the atom shown contains 4 protons and 5 neutrons; therefore its mass number is (4 + 5 =) 9.

• The charge of the atom is 0. This is because it has 4 protons which give it a +4 charge, but it also has 4 electrons which give it a -4 charge. Therefore its net charge is: 4 + (-4) = 0.

The spring mass system shown in Figure 2 is released from rest. The mass m slides vertically on the smooth rod. If the spring has a spring constant k and is unstretched at the position shown in the figure, determine the equations of motion for the mass.

Answers

Since I don't have access to the specific Figure 2 you mentioned, I won't be able to provide you with the exact equations of motion for the mass in the given system. However, I can provide you with a general framework for determining the equations of motion for a spring-mass system.

In a spring-mass system, the forces acting on the mass include the gravitational force (mg) and the spring force (kx), where m is the mass of the object, g is the acceleration due to gravity, k is the spring constant, and x is the displacement of the mass from its equilibrium position.

Using Newton's second law (F = ma), we can set up the equation of motion for the mass:

m * (d^2x/dt^2) = -kx - mg

This is a second-order linear differential equation, where (d^2x/dt^2) represents the acceleration of the mass with respect to time.

To solve this equation and obtain the equations of motion for the mass, you would need to apply appropriate initial conditions, such as the initial position and velocity of the mass.

If you can provide more specific information or a detailed description of the system in Figure 2, I can assist you further in determining the equations of motion.

About Velocity

Velocity is a vector quantity that indicates how fast an object is moving. The magnitude of this vector is called speed and is expressed in meters per second. Velocity or speed: the quotient between the distance traveled and the time interval. Velocity or speed is a scalar quantity. Speed ​​or velocity is the quotient of the displacement with the time interval. Speed ​​or velocity is a vector quantity.

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The lift reaches a steady upward speed.
State the value of the force exerted on the woman by the floor at this steady
speed.
please quick

Answers

The value of force exerted on the women will be normal of the lift in positive x direction .

Acceleration is defined as change of velocity divided by time.

Since lift is moving upward at a steady speed , that means no change of speed has been taken place . hence no acceleration.

There is no external acceleration acting on the lift . Hence there will be  two forces, one is the force of gravity and the other is upward normal force from the elevator.

N = mg if the elevator is at rest or moving at constant velocity

The value of force exerted on the women will be normal of the lift in positive x direction

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a person throws a ball from shoulder height and parallel to ground with an initial horizontal velocity of 4 m/s. it hits the ground at exactly 5 seconds. what horizontal distance has the ball traveled?

Answers

The ball has traveled 20 meters in a horizontal direction. The outcome is achieved by using the idea of projectile motion.

What is speed and what is its SI equivalent?

Just as for speed, "m/s" is the SI unit for velocity. (a) While mobility is just the rate at which a body's displacement changes, speed refers to the pace at which a body's distance traveled changes. While velocities is a vector field and requires both magnitude and orientation to really be described, speed is a rudderless quantity.

Briefing:

dx = dVx × t

dx = 4 m/s × 5 s

dx = 20 m

Hence, the ball has travelled 20 m at the horizontal distance.

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When a 9.00 V voltage is applied to a resistor, it drives 0.325 A of current through the resistor. How much power does the resistor use? (Unit = W)

Can someone please explain how to do this question.

Answers

Answer: 2.925

Explanation: :)

Answer:

2.925

Explanation:

Express 48 m/s in terms of
1.km/h
2.m/min
3.km/s
4.km/minutes

Answers

48 m/s in terms of km/h is 720.8 km/h. In terms of m/min is 2880 m/min, in terms of km/s is 0.048 km/s and in terms of km/min is 2.88 km/min.

To solve this question, we need to understand some terms. The unit of velocity is measured in m/s. It can be expressed in different units of velocity.

1 km (kilometer) = 1000 meter

1 h (hour) = 3600 seconds

1 minutes = 60 seconds

To convert m/s into km/h,

48 m/s * 3600/1000 =  172.8 km/h

To convert m/s into m/min,

48 m/s * 60 = 2880 m/min

To convert m/s into km/s,

48 m/s ÷ 1000 = 0.048 km/s

To convert m/s into km/minutes,

48 m/s * 60 / 1000 = 2.88 km/min

Therefore, the 48 m/s expressed is 172.8 km/h, 2880 m/min, 0.048 km/s and 2.88 km/min.

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48 m/s is equivalent to  172.8 km/h, 2880 m/min, 0.048 km/s, and 2.88 km/minute.

To express 48 m/s in different units of velocity:

km/h (kilometers per hour):

To convert m/s to km/h, we can use the conversion factor of 3.6 since 1 m/s is equal to 3.6 km/h.

48 m/s * (3.6 km/h / 1 m/s) = 172.8 km/h

Therefore, 48 m/s is equivalent to 172.8 km/h.

m/min (meters per minute):

To convert m/s to m/min, we can use the conversion factor of 60 since there are 60 seconds in a minute.

48 m/s * (60 m/min / 1 s) = 2880 m/min

Therefore, 48 m/s is equivalent to 2880 m/min.

km/s (kilometers per second):

Since 1 kilometer is equal to 1000 meters, to convert m/s to km/s, we divide the value by 1000.

48 m/s / 1000 = 0.048 km/s

Therefore, 48 m/s is equivalent to 0.048 km/s.

km/minute (kilometers per minute):

To convert m/s to km/minute, we first need to convert m/s to km/s (as calculated in the previous step) and then multiply by 60 to convert seconds to minutes.

0.048 km/s * 60 = 2.88 km/minute

So, 48 m/s is equivalent to 2.88 km/minute.

Hence, 48 m/s is equivalent to approximately 172.8 km/h, 2880 m/min, 0.048 km/s, and 2.88 km/minute.

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How far does a freely falling apple drop in 7.0 s after being released from rest?

Answers

Answer:

The distance traveled by the apply after being released is 127.45 m.

Explanation:

The given parameters;

time of motion of the apple, t = 5.1 s

initial velocity of the apple, u = 0

The distance traveled by the apply is calculated by applying second kinematic equation as shown below.

Assuming downward motion to be positive.

ok oh if i need any answers just asking i'll help you

A student shakes a rope such that 36 complete vibrations are
made in 9.00 seconds. determine the vibrational period of
the rope, along with the corresponding unit.

Answers

The vibrational period of the rope, when a student shakes it is 0.25 s.

What is the frequency?

Frequency is the number of oscillations per second.

Given is the number of vibrations =36 in time t = 9s, then frequency will be

f = 36/9 =4Hz

The time period is the reciprocal of the frequency.

T = 1/f

Plug the frequency value, we get

T = 1/4 Hz = 0.25 seconds

Thus, the vibrational time period is 0.25s.

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What would be the effect of adding a proton to a nucleus?A. It would increase the strong nuclear force and increase theelectrostatic force.B. It would decrease the strong nuclear force and decrease theelectrostatic force.C. It would increase the strong nuclear force and decrease theelectrostatic force.D. It would decrease the strong nuclear force and increase theelectrostatic force.

Answers

Adding protons to the nucleus would increase the electrostatic repulsion and increase the strong nuclear force.

Correct option : A

To practice Problem-Solving Strategy 27. 2 Motion in Magnetic Fields. An electron inside of a television tube moves with a speed of 2. 74×107 m/s. It encounters a region with a uniform magnetic field oriented perpendicular to its trajectory. The electron begins to move along a circular arc of radius 0. 190 m. What is the magnitude of the magnetic field?Part CCalculate the magnitude F of the force exerted on the electron by a magnetic field of magnitude 8. 21×10−4 T oriented as described in the problem introduction. Express your answer in newtons

Answers

Answer:

Magnetic field strength: approximately \(8.20 \times 10^{-4}\; {\rm T}\).

Force on the electron: approximately \(3.60 \times 10^{-15}\; {\rm N}\).

Explanation:

Look up the charge and mass of an electron:

The magnitude of charge on an electron is the same as the elementary charge: \(q_{e} \approx 1.602 \times 10^{-19}\; {\rm C}\).Electron rest mass: \(m_{e} \approx 9.109 \times 10^{-31}\; {\rm kg}\).

Since the electron is moving perpendicularly across a magnetic field, magnitude of the magnetic force on this electron would be:

\(F = q\, v\, B\),

Where:

\(q\) is the magnitude of the electric charge on this electron,\(v\) is the speed of the electron, and\(B\) is the magnitude of the magnetic field.

At the same time, because the electron is in a centripetal motion, magnitude of the net force on the electron should satisfy:

\(\displaystyle F_{\text{net}} = \frac{m\, v^{2}}{r}\),

Where:

\(m\) is the mass of the electron, \(v\) is the speed of the electron, and\(r\) is the radius of the circular orbit.

Assuming that magnetic force from the field is the only force on this point charge. Net force on the charge would be equal to the magnetic force. In other words:
\(\displaystyle \frac{m\, v^{2}}{r} = q\, v\, B\).

Rearrange this equation and solve for the magnetic field strength:

\(\begin{aligned}B &= \frac{m\, v}{q\, r} \\ &\approx \frac{(9.109 \times 10^{-31})\, (2.74 \times 10^{7})}{(1.602 \times 10^{-19})\, (0.190)}\; {\rm T} \\ &\approx 8.20 \times 10^{-4}\; {\rm T}\end{aligned}\).

Substitute \(B \approx 8.20 \times 10^{-4}\; {\rm T}\) back into the equation \(F = q\, v\, B\) to find the magnetic force on this electron:

\(\begin{aligned}F &= q\, v\, B \\ &\approx (1.602 \times 10^{-19})\, (2.74 \times 10^{7})\, (8.20 \times 10^{-4})\; {\rm N}\\ &\approx 3.60 \times 10^{-15}\; {\rm N}\end{aligned}\).

The gas in a balloon has T=280K and V=0.0279m^3. If the temperature increases to 320K at constant pressure, what is the new volume of the balloon? (Hint: n and P are constant) (Unit= m^3)

Answers

Answer:

\(\boxed{ V_{2}= 0.03189 m^3}\)

Explanation:

According to Charles Law

=> \(\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\)

Where \(V_{1}\) = 0.0279 m³, \(T_{1}\) = 280 K and \(T_{2}\) = 320 K

=> \(\frac{0.0279}{280} = \frac{V_{2}}{320}\)

=> \(V_{2}\) = 0.03189 m³

For the following questions, please provide a complete step by step solution. You do notneed interaction, but you are required force diagrams.

For the following questions, please provide a complete step by step solution. You do notneed interaction,

Answers

Tennsion 1= horizontal = 484.94 N

Tension 2 = slanted string = 560 N

Explanation

Step 1

Free body diagram

Newton's first law says that if the net force on an object is zero, like in this case the mass is in rest,then that object will have zero acceleration

so

Step 1

set the equations:

a) for x-axis

\(\begin{gathered} \sum ^{}_{}F_x=0 \\ so \\ T_{2x}-T_1=0 \\ T_2\cos 30-T_1=0\rightarrow equation(1) \end{gathered}\)

b) for y -axis

\(\begin{gathered} \sum ^{}_{}F_y=0 \\ so \\ T_{2y}-w=0 \\ T_2\sin 30-280N=0\rightarrow equation(2) \end{gathered}\)

Step 2

Solve the equations

\(\begin{gathered} T_2\cos 30-T_1=0\rightarrow equation(1) \\ T_2\sin 30-280N=0\rightarrow equation(2) \end{gathered}\)

a) solve for T2in equation (2)

\(\begin{gathered} T_2\sin 30-280N=0\rightarrow equation(2 \\ \text{add 280 N in both sides} \\ T_2\sin 30-280N+280N=0+280\text{ N} \\ T_2\sin 30=280\text{ N} \\ \text{divide both sides by sin 30} \\ \frac{T_2\sin30}{\sin30}=\frac{280\text{ N}}{\sin30} \\ T_2=560\text{ N} \end{gathered}\)

b) replace the T2 value in equation (1) to find T1

\(\begin{gathered} T_2\cos 30-T_1=0\rightarrow equation(1) \\ 560\cos 30-T_1=0\rightarrow equation(1) \\ 484.97-T_1=0 \\ 484.97=T_1 \end{gathered}\)

therefore

Tennsion 1= horizontal = 484.94 N

Tension 2 = slanted string = 560 N

I hope this helps you

For the following questions, please provide a complete step by step solution. You do notneed interaction,

i single and thiccccc hmu

Answers

Answer:

wtfffff

Explanation:

wtffffff

The chemical reactivity of an atom is determined by the number of _____ present.a) protonb) neutronc) electronThere can be multiple answers.

Answers

The chemical reactivity of an atom is determined by the number of electrons present in its outermost shell, also known as the valence electrons.

These electrons play a key role in determining the chemical properties of an atom, such as its reactivity and bonding behavior. An atom with a full or nearly full valence shell is less likely to engage in chemical reactions, while an atom with a partially filled valence shell is more reactive and readily participates in chemical reactions. Thus, the number of electrons in the valence shell is a critical factor in determining the chemical reactivity of an atom. Chemical reactivity refers to the ability of a substance to participate in chemical reactions and form new compounds. It is determined by various factors, including the arrangement of electrons in the outermost shell (valence electrons), the stability of the electronic configuration, and the energy required to break or form chemical bonds.

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please help I got no time!!

please help I got no time!!

Answers

Answer:

42a. Ammeter 2 = 0.20 A

42b. Ammeter 3 = 0.20 A

42c. The current will remain the same i.e unchanged.

43. Equivalent resistance is 11780 Ω

46a. 11 V

46b. 7.5 V

46c. 18.5 V

47. 1.70 A

Explanation:

42a. Determination of ammeter 2

Ammeter 1 = 0.20 A

Ammeter 2 =?

Since the resistors are in series connection, the same current will pass through them. Thus, ammeter 2 will read 0.20 A.

Ammeter 2 = ammeter 1 = 0.20 A

42b. Determination of ammeter 3

Ammeter 1 = 0.20 A

Ammeter 3 =?

Since the resistors are in series connection, the same current will pass through them. Thus, ammeter 3 will read 0.20 A.

Ammeter 3 = ammeter 1 = 0.20 A

42c. Since the resistors are in series connection, the same current will pass through them. Therefore, the current will remain the same.

43. Determination of the equivalent resistance.

We'll begin by converting 1.1 KΩ and 10 KΩ to Ω. This can be obtained as follow:

1 KΩ = 1000 Ω

Therefore,

1.1 KΩ = 1.1 KΩ × 1000 Ω / 1 KΩ

1.1 KΩ = 1100 Ω

1 KΩ = 1000 Ω

Therefore,

10 KΩ = 10 KΩ × 1000 Ω / 1 KΩ

10 KΩ = 10000 Ω

Finally, we shall determine determine the equivalent. This can be obtained as follow:

Resistor 1 (R₁) = 680 Ω

Resistor 2 (R₂) = 1100 Ω

Resistor 3 (R₃) = 10000 Ω

Equivalent Resistance (Rₑq) =?

Rₑq = R₁ + R₂ + R₃

Rₑq = 680 + 1100 + 10000

Rₑq = 11780 Ω

Thus, the equivalent resistance is 11780 Ω

46a. Determination of the voltage across 22 Ω

Current (I) = 0.50 A

Resistor (R₁) = 22 Ω

Voltage (V₁) =?

NOTE: the current is the same since the resistor are in series connection.

V₁ = IR₁

V₁ = 0.5 × 22

V₁ = 11 V

46b. Determination of the voltage across 15 Ω

Current (I) = 0.50 A

Resistor (R₂) = 15 Ω

Voltage (V₂) =?

NOTE: the current is the same since the resistor are in series connection.

V₂ = IR₂

V₂ = 0.5 × 15

V₂ = 7.5 V

46c. Determination of the voltage of the battery.

Voltage 1 (V₁) = 11 V

Voltage 2 (V₂) = 7.5 V

Battery voltage (V) =?

V = V₁ + V₂

V = 11 + 7.5

V = 18.5 V

47. Determination of the current.

We'll begin by calculating the equivalent resistance. This can be obtained as follow:

Resistor 1 (R₁) = 22 Ω

Resistor 2 (R₂) = 4.5 Ω

Equivalent Resistance (R) =?

R = R₁ + R₂

R = 22 + 4.5

R = 26.5 Ω

Finally, we shall determine the current.

Voltage (V) = 45 V

Resistance (R) = 26.5 Ω

Current (I) =?

V = IR

45 = I × 26.5

Divide both side by 26.5

I = 45 / 26.5

I = 1.70 A

can u find the . in this?
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Answers

Answer:

Yeah it's right there from the one next to the exclamation point

Answer:

its not there

Explanation:

its literally not there

8. What current flows through a 1.15 kW electric fire at a potential difference of
230 V? (Remember that 1.15 kW is 1,150 W)
9. Would it be best to use a 3A, 5A or a 13A fuse for the fire above? Explain
why.

Answers

Answer:

I = 5[amp]

Explanation:

Electrical power is defined as the product of voltage by current.

\(P=V*I\)

where:

P = power = 1150 [W]

V = voltage = 230 [V]

I = current [amp]

Now replacing:

\(1150=230*I\\I=1150/230\\I=5[amp]\)

A 15 [amp] fuse must be used. Always the fuse must be larger than the operating current, to protect the equipment from very high currents. above 15 [amp]

rank the order in which the following substances would condense out the solar nebula: argon, iron, methane, water ice.

Answers

The order of condensation from the solar nebula is: Iron, Water Ice, Methane, and Argon.

1. Iron: Iron has the highest condensation temperature, so it would be the first substance to condense out of the solar nebula.
2. Water ice: Water ice has a lower condensation temperature than iron, but higher than methane and argon, making it the second substance to condense.
3. Methane: Methane has a lower condensation temperature compared to water ice and iron, but higher than argon, making it the third substance to condense.
4. Argon: Argon has the lowest condensation temperature of the four substances, so it would be the last to condense out of the solar nebula.

So, the order of condensation from the solar nebula is: Iron, Water Ice, Methane, and Argon.

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A top sprinter reached his maximum instantaneous velocity of 12.28 meters per second 7.17 seconds after leaving the blocks. Calculate his acceleration. All key steps must be shown.
I am very confused will you please help me!!

Answers

Answer:

Here we will assume two things.

His acceleration is constant until he reaches his maximum velocity and then he stops accelerating.

When he leaves the blocks, his velocity is "zero", meaning that the initial velocity is zero.

Then:

For the acceleration of the sprinter we will have a constant, A:

a(t) = A.

for the velocity we need to integrate over time, we will get

v(t) = A*t + v0

Where v0 is a constant of integration, and this is the initial velocity, as we already said, this will be zero, so the velocity equation is:

v(t) = A*t

We know that at t = 7.17 seconds, his velocity is 12.28m/s

then:

v(7.17s) = 12.28m/s = A*7.17s

               12.28m/s/7.17s = 1.71 m/s^2 = A.

The acceleration is: 1.71 m/s^2  for 0 < t < 7.17s

                                  0 m/s^2  for  7.17s < t.

This is because that was his maximum velocity, then after that time he can not accelerate more.

Two boxes are connected by a light string that passes over a light, frictionless pulley. One box rests on a frictionless ramp that rises at 30.0 degrees above the horizontal (see Figure 5.50), and the system is released from rest. (a) Make a free-body diagram of each box. (b) Which way will the 50.0 kg box move, up the pane or down the plane? Or will it even move at all? Show why or why not. (c) Find the acceleration of each box.

Answers

(a) To make a free-body diagram of each box, we need to consider the forces acting on each box.

The box on the ramp will have the force of gravity acting downward, which can be resolved into components parallel and perpendicular to the ramp. The parallel component will act down the ramp, while the perpendicular component will act normal to the ramp. The box will also experience a force of friction acting up the ramp, which will be equal and opposite to the component of the force of gravity acting down the ramp. The box on the other side of the pulley will have only the force of gravity acting downward.

(b) The direction in which the 50.0 kg box moves will depend on the net force acting on it. If the force down the ramp due to the component of the force of gravity is greater than the force up the ramp due to friction, then the box will move down the ramp. If the force up the ramp due to friction is greater than the force down the ramp due to gravity, then the box will move up the ramp. If the forces are balanced, then the box will not move at all.

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Calculate the power per square meter (in kW/m2) reaching Earth's upper atmosphere from the Sun. (Take the power output of the Sun to be 4.00 ✕ 1026 W.)

Answers

The power from the sun reaching Earth's upper atmosphere is 1.42 x 10³ kW/m².

To calculate the power per square meter reaching Earth's upper atmosphere from the Sun, we need to use the inverse square law.

The power output of the Sun is given as 4.00 x 10²⁶ W.

The distance between the Sun and the Earth varies throughout the year, but on average, it is about 149.6 million kilometers (9.3 x 10⁷ miles).

Using the formula for the surface area of a sphere, we can find the total surface area of the imaginary sphere with a radius equal to the distance between the Sun and the Earth.

The surface area of a sphere = 4πr²

The surface area of the sphere with a radius of 149.6 million km:

A = 4 x 3.1416 x (149.6 x 10⁹)²

A = 2.827 x 10²³ m²

Now, we can calculate the power per square meter reaching Earth's upper atmosphere by dividing the total power output of the Sun by the total surface area of the sphere.

Power per square meter = Power output of the Sun / Total surface area of the sphere

= (4.00 x 10²⁶ W) / (2.827 x 10²³ m²)

= 1.42 x 10³ kW/m²

Therefore, the power per square meter reaching Earth's upper atmosphere from the Sun is 1.42 x 10³ kW/m².

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a(n) 6 kg object moving with a speed of 6.3 m/s collides with a(n) 17 kg object moving with a velocity of 7.2 m/s in a direction 19◦ from the initial direction of motion of the 6 kg object. What is the speed of the two objects after the collision if they remain stuck together?

Answers

The final speed of the two objects after the collision is 4.27 m/s.

First, let's find the initial momentum of the system:

p_i = m1v1 + m2v2 = (6 kg)(6.3 m/s) + (17 kg)(7.2 m/s * cos(19°))

p_i = 100.82 kg m/s

Next, let's find the initial kinetic energy of the system:

\(KE_i = (1/2)m_1v_1^2 + (1/2)m_2v_2^2 = (1/2)(6 kg)(6.3 m/s)^2 + (1/2)(17 kg)(7.2 m/s * cos(19\textdegree))^2\\\\KE_i = 929.07 J\)

The final velocity of the two items will be the same since they remain attached to one another after colliding. Let's call this velocity v_f.

Conservation of momentum gives:

p_f = (m1 + m2)*v_f

v_f = p_f / (m1 + m2)

Conservation of kinetic energy gives:

KE_i = KE_f

\((1/2)m1v1^2 + (1/2)m2v2^2 = (1/2)*(m1 + m2)*v_f^2\)

Substituting in our values and solving for v_f gives:

\(v_f = \sqrt{(m_1v_1^2 + m_2v_2^2)/(m_1 + m_2)}\\\\v_f = \sqrt{(6 kg)(6.3 m/s)^2 + (17 kg)(7.2 m/s * cos(19\textdegree))^2)/(6 kg + 17 kg)}\\\\v_f = 4.27 m/s\)

Collision refers to a physical impact or clash between two or more objects that results in damage, destruction, or a change in motion. Collisions can occur in a wide variety of contexts, from everyday situations such as car crashes and sports collisions to more complex phenomena in physics and engineering.

In physics, collisions are studied in terms of momentum, energy, and conservation laws, as they can provide valuable insights into the behavior of particles and systems. Elastic collisions involve a transfer of kinetic energy between objects, while inelastic collisions result in a loss of energy due to deformation or other factors.

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What are theoretical questions transformed into through operational definitions?

a. Testable hypotheses.

b. Proven theories.

c. Ethical guidelines.

d. Conclusive statements.

Answers

Testable hypotheses are the theoretical problems that operational definitions have converted into.

Scientific observation is an empirical research designed to systematically address issues about the world. Through the use of operational definitions, theoretical questions are converted into. a provable theory. The measurement process for measuring external, observable behaviour is specified in Operational Definitions. The measurements that are obtained are utilised to define and quantify the construct. A measurement process (a collection of operations) is specified in an operational definition for the purpose of measuring an external, observable behaviour, and the definition and measurement of the hypothetical construct are then based on the results of the measurement procedure. No matter how solid your conceptual definition may be, you cannot measure anything without an operational definition.

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2. A roller coaster is at the top of a 72 m hill and weighs 150 kg. The coaster (at this moment) has
energy
anarov

Answers

Answer:

it is going down down down down the hill it goes so the roller coaster will then be down to a 0 m

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