when an acid such as hcl reacts with a metal, such as zinc (shown here) the gas produced is
Answers
When an acid such as hydrochloric acid (HCl) reacts with a metal like zinc (Zn), the gas produced is hydrogen gas (H₂).
When hydrochloric acid (HCl) reacts with zinc (Zn), something interesting happens. The acid gives away its hydrogen atoms (H⁺) to the zinc. At the same time, the zinc gives away some of its electrons. As a result, hydrogen gas (H₂) is produced. The gas forms little bubbles that you might see during the reaction. The remaining zinc combines with the chlorine atoms (Cl⁻) from the acid to form zinc chloride (ZnCl₂). So, to sum it up, when acid (like HCl) and metal (like zinc) react, they create hydrogen gas and a compound called zinc chloride. The hydrogen gas bubbles out, and the zinc chloride dissolves in the remaining acid.
A single displacement reaction, also known as a metal-acid reaction, occurs when hydrochloric acid (HCl) and zinc (Zn) are in contact. This reaction results in the creation of zinc chloride (ZnCl₂) and hydrogen gas (H₂) as the zinc metal displaces the hydrogen in the hydrochloric acid. While the acid's hydrogen ions lose electrons and undergo oxidation, the zinc atoms acquire electrons and undergo reduction. It is a redox (reduction-oxidation) reaction because it includes both oxidation and reduction reactions.
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Related Questions
10. Make your own unique problem for your classmates to solve for the
independent, dependent, and controlled variables. Make sure to include the
answers.
Answers
Answer:
Explanation:
Problem:
In a gender based experiment, the blood pressure of different ages of men is been checked and recorded to determine if there is any correlation. What will be the independent, dependent and controlled variables?
Answer:
A controlled variable is the variable that is left constant throughout the course of an experiment. The controlled variable here is the gender.
A dependent variable is the variable that is been determined or measured during the course of an experiment. The dependent variable here is the blood pressure.
An independent variable is the variable that is intentionally or decidedly altered during the course of an experiment. The independent variable here is the age.
When the [CO2] and [H2CO3] are both horizontal lines, the rate of the forward reaction is
the rate of the reverse reaction
faster than
slower than
the same as
Answers
When \(CO_{2}\) and \(H_{2} CO_{3}\) are both horizontal lines, the rate of the forward reaction is the same as the rate of the reverse reaction. The reaction is occurring at equilibrium, with no net change in the concentrations of reactants and products over time.
When the concentration of carbon dioxide \(CO_{2}\) and the concentration of carbonic acid \(H_{2} CO_{3}\) are both horizontal lines, it indicates that their concentrations remain constant over time. In such a scenario, the rate of the forward reaction is the same as the rate of the reverse reaction. A horizontal line on a concentration-time graph suggests that the concentrations of the reactants and products are not changing, implying that the reaction has reached equilibrium. At equilibrium, the rate of the forward reaction equals the rate of the reverse reaction. This is a fundamental principle of chemical equilibrium, described by the principle of microscopic reversibility.
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What would be a correct unit of measurement for velocity?
Group of answer choices
Meters/second North
Meters/second
Answers
Answer:
Explanation:
Meter/ Second
Answer:
Meter/Second North!Brainliest pls :)
Explanation:
Which of these form an ionic bond
Answers
Answer:
the second 1
Explanation:
why can fluids flow but solids can’t?
Answers
Answer:
Fluids can flow because their molecular structure is different. Instead of being tightly packed, like a solid, there are fewer molecules per unit in a liquid than a solid. This gives the molecules of a liquid space to move around, and it flows because liquids take the shape of their container(s). These molecules usually tend to bump into each other and this causes the liquid to move as well
Answer:
Because the particles don't move, solids have a definite shape and volume, and can't flow. LIQUIDS - This means that liquid particles are further apart and can move about more easily. Since the particles can move, the liquid can flow and take the shape of its container.
Explanation:
hope this helps
How do you name ionic compounds with oxygen?
Answers
We use ite and ate when named ionic compounds with oxygen.
Ionic compound names applying -ite and -ate
When an element creates two oxyanions, the name of the one with less oxygen ends in -ite, and the name of the one with more oxygen ends in -ate. For illustration, KNO2 stands for potassium nitrite and KNO3 for potassium nitrate. Cations (positive ions) and anions(negative ions)make up ionic compounds.The names of the component ions serve as the basis for the nomenclature or naming of ionic compounds. Ionic compound names always place the positively charged cation before the negatively charged anion. names of ionic compounds ending in -ite and -ate. Some polyatomic anions contain oxygen. These anions are referred to as oxyanions. The names of the two oxyanions that an element forms end in -ite and -ate, respectively, depending on how much oxygen is present in each. An illustration of a nitrite is KNO2. Nitrite, NO2 nitrate (NO3) sulfite (SO32) sulphate (SO42) sulphate.
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Choose the pair of concentrations thatcannot be in a given aqueous solution at25°C.a. [H+] = 10-3 M, [OH-] = 10-11 Mb. [H+] = 10-7 M, [OH-] = 10-7 Mc. [H+] = 10-13 M, [OH-] = 1 Md. [H+] = 10 M, [OH-] = 10-15 Me. All of these can exist
Answers
All of these can exist as the pair of concentrations in a given aqueous solution at25°C.(E)
At 25°C, the product of the concentrations of hydrogen ions and hydroxide ions in water, known as the ion product constant (Kw), is equal to 1.0 x 10^-14. This means that for any aqueous solution at 25°C, the product of [H+] and [OH-] must equal 1.0 x 10^-14.
Using this information, we can calculate the [OH-] concentration for option A, B, C and D as follows:
A) [OH-] = Kw / [H+] = 1.0 x 10^-14 / 10^-3 = 1.0 x 10^-11 M
B) [OH-] = Kw / [H+] = 1.0 x 10^-14 / 10^-7 = 1.0 x 10^-7 M
C) [OH-] = Kw / [H+] = 1.0 x 10^-14 / 10^-13 = 1.0 x 10^-1 M
D) [OH-] = Kw / [H+] = 1.0 x 10^-14 / 10 = 1.0 x 10^-13 M
We can see that all of the given concentrations, except for option E, satisfy the condition that the product of [H+] and [OH-] must equal 1.0 x 10^-14. Option E violates this condition and therefore cannot exist in an aqueous solution at 25°C.
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If you were to do a 50% serial dilution, starting with a 10% concentration, how many dilutions would you have to make before getting to 2. 5% as your final concentration?.
Answers
Dilution Factor : It indicate what quantity of volume is there in your solution in comparison to the original solution. It is also known by the name of dilution ratio. The answer would be the 2% of the solution needed before having the final concentrations of the solution to the 50% of serial dilution with the initial concentration.
Now,
Here , 50 % serial dilution,
Initial concentration = 10 %
Final concentrations =2.5 %
v1*c1 = v2*c2
v2 = v1*c1/ c2
Starting concentration of solution = 10%
Final concentration of solution = 50 %
If we have to make 50% serial dilution to reach the final concentration of 2.5 % then first serial dilution will give 5% concentration and second dilution will give 2.5% concentration. Thus required times of serial dilution is 2%
In conclusion 2% dilution we have to make before having final concentration.
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How many degrees of freedom (translational + rotational) are needed to describe the following atoms/molecules: Ar, N2, H2O, CO, C60 (buckyball) ?
Answers
The number of degrees of freedom required to describe an atom or molecule depends on its complexity.
For a single atom such as Ar, there are only three degrees of freedom - translational in x, y, and z directions. For a diatomic molecule like N2 or H2O, there are five degrees of freedom - three translational and two rotational. CO also has five degrees of freedom due to its linear shape. C60, on the other hand, is a highly complex molecule with many possible ways of rotating and translating. It has a total of 174 degrees of freedom, including 3 translational, 9 rotational, and 162 vibrational.
These values represent the required degrees of freedom to describe the motion of each atom/molecule.
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One pound of sulfur combines with one pound of oxygen to produce gas. What is the percent by weight composition of this gas?
Answers
Therefore, the percent by weight composition of the gas formed from the combination of one pound of sulfur and one pound of oxygen is 50% sulfur and 50% oxygen.
To determine the percent by weight composition of the gas formed when one pound of sulfur combines with one pound of oxygen, we need to calculate the individual weights of sulfur and oxygen in the compound.
The atomic weight of sulfur (S) is approximately 32.06 g/mol, and the atomic weight of oxygen (O) is approximately 16.00 g/mol.
Since both sulfur and oxygen combine in a 1:1 ratio, one pound of sulfur is equal to one mole of sulfur, and one pound of oxygen is equal to one mole of oxygen.
The total weight of the compound is the sum of the weights of sulfur and oxygen, which is:
Weight of sulfur + Weight of oxygen = 1 pound + 1 pound = 2 pounds
To find the percent by weight composition of the gas, we calculate the weight percentage of each element in the compound:
Weight percentage of sulfur = (Weight of sulfur / Total weight) × 100
Weight percentage of oxygen = (Weight of oxygen / Total weight) × 100
Substituting the values:
Weight percentage of sulfur = (1 pound / 2 pounds) × 100 = 50%
Weight percentage of oxygen = (1 pound / 2 pounds) × 100 = 50%
Therefore, the percent by weight composition of the gas formed from the combination of one pound of sulfur and one pound of oxygen is 50% sulfur and 50% oxygen.
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Answer:suffer 66.7 percent oxygen 33.3 percent
Explanation:
The atomic weight of sulfur (S) is approximately 32.06 g/mol, and the atomic weight of oxygen (O) is approximately 16.00 g/mol. Add them together to get the total weight of 48.06. Then calculate the percent of each. Suffer is 32.06 divided by 48.06 times 100 equals 66.7. Oxygen is 16 divided by 48.06 times 100 equal 33.3.
50 POINTS AND BRAINLIEST. PLEASE HELP
How do scientists determine a nucleus' location within an atom?
A. by dividing the atomic radius by a factor of 2
B. by sending an electric current through the atom and measuring the amount of nucleus resistance
C. by measuring half the distance between the nuclei of two bonded atoms
D. by splitting the atom into an ion and measuring the nucleus' size
Answers
The location of the nucleus within an atom can be determined by measuring half the distance between the nuclei of two bonded atoms.
What are the Covalent radius and atomic number?The Covalent radius can be described as a value used to understand the covalently bonded atoms, while the atomic number can be described as the number of protons and neutrons that are present in the atomic nucleus, which permits us to get the relative distance between one atom and other atoms.
The atomic number is useful in order to determine different elements since they are made of a variable number of positively charged protons and neutrons, as well as the number of negatively charged electrons around the nucleus.
Therefore, the Covalent radius and atomic number are fundamental in order to determine the number of protons and neutrons. The covalent radius can be used to determine the location of the nucleus within an atom.
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Please help me out thank you so much
Answers
Answer:
a) 1.567 x 10^9
b) 2.36 x 10^(-5)
using cahn-ingold-prelog rules, identify the substituents that would have the highest priority. a) i b) ii c) iii d) iv
Answers
Using Cahn-Ingold-prelog rules, the substituents that would have the highest priority is a) i
According to the Cahn Ingold Prelog system, priorities are assigned as 1,2,3, or 4 to the atoms directly bonded to the stereo genic center in decreasing order of atomic number. The atom of highest atomic number has the highest priority 1.
A substituent with higher atomic number takes over a substituent with a lower atomic number. Hydrogen is the lowest priority substituent, as it has the lowest atomic number. But for isotopes, the atom with the higher atomic mass gets higher priority.
For assigning the priority, multiple bonds are seen as if each bond of the multiple bond is bonded to an unique atom.
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A gas occupies 710 cm at STP. A weather change reduces volume to 505 cm calculate the temperature.
Answers
The temperature of the gas after the volume change is approximately 294.62 Kelvin.
To calculate the temperature of the gas after the volume change, we can use the ideal gas law equation, which states that PV = nRT, where P is the pressure, V is the volume, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature in Kelvin.
At STP (Standard Temperature and Pressure), the pressure is 1 atmosphere (atm) and the temperature is 273.15 Kelvin (K).
Using the initial volume of 710 cm³ at STP, we can write:
(1 atm) * (710 cm³) = (n) * (0.0821 L·atm/(mol·K)) * (273.15 K)
Solving for n, the number of moles, we find n ≈ 0.0294 moles.
Now, with the new volume of 505 cm³, we can calculate the temperature (T2) as follows:
(1 atm) * (505 cm³) = (0.0294 moles) * (0.0821 L·atm/(mol·K)) * (T2)
Solving for T2, we find T2 ≈ 294.62 Kelvin.
Therefore, the temperature of the gas after the volume change is approximately 294.62 Kelvin.
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do equal volume of any gas under same temperature and pressure contain equal number of atoms? explain
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a sample contains 10.5 g of the radioisotope pb-212 and 157.5 g of its daughter isotope, bi-212. how many half-lives have passed since the sample originally formed?
Answers
Approximately 4 half-lives have passed since the sample originally formed.
How many half-lives have occurred since the sample's formation?The ratio between the radioisotope Pb-212 and its daughter isotope Bi-212 can be used to determine the number of half-lives that have passed since the sample was formed.
Radioactive decay follows an exponential decay model, where the amount of the parent isotope decreases by half with each half-life.
In this case, the sample contains 10.5 g of Pb-212 and 157.5 g of Bi-212. Since the daughter isotope is the result of the radioactive decay of the parent isotope, it can be inferred that 10.5 g of Pb-212 has decayed into 157.5 g of Bi-212.
Since each half-life reduces the parent isotope by half, the initial amount of Pb-212 would be 21 g (10.5 g × 2). Therefore, the number of half-lives can be calculated by dividing the initial amount of Pb-212 by the amount remaining, which is 21 g / 10.5 g = 2. Since each half-life takes the same amount of time, approximately 4 half-lives have passed since the sample originally formed.
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How much heat energy is required to heat a 100 g sample of liquid water from 30 °C to water vapor at 110 °C?The specific heat of liquid water is 4.184 J/(g K) and water vapor is 2.008 J/(g K). The heat of vaporization for water is 2259 J/g and the heat of fusion is 334.72 J/g
Answers
The total heat energy required is expressed according to the formula:
\(\begin{gathered} Q_T=Q_{\text{vap,w}}+Q_w \\ \end{gathered}\)where:
Qvap is the heat energy absorbed by the vapor
Qw is the heat energy absorbed by the water
Get the heat energy absorbed by the vapor at 100 degrees
\(\begin{gathered} Q_{\text{vap,w}}=n_w\times\triangle H_{vap,w} \\ Q_{\text{vap,w}}=\frac{mass}{molar\text{ mass}}\times\triangle H_{vap,w} \\ \end{gathered}\)Given the following parameters;
Mass of water = 100g
Molar mass of water (H2O) = 18.015g/mol
Hvap,w = 2259 J/g = 40.8 kJ/mol
Substitute the given parameters into the formula to have:
\(\begin{gathered} Q_{\text{vap,w}}=\frac{100\cancel{g}}{18.015\cancel{g}\cancel{\text{mol}^{-1}}^{}}\times\frac{40.8kJ}{\cancel{\text{mol}}} \\ Q_{\text{vap,w}}=226.48kJ \end{gathered}\)Get the heat absorbed by the water from 30 to 100 degrees and from 100 to 110 degrees using the formula below. Note that the water vapor is being heated without any phase changes, so we will be utilizing the specific heat capacity of water vapor.
\(\begin{gathered} Q_w=m_wc_w(\triangle\theta)_w+m_wc_w\triangle\theta \\ Q_w=(100\times4.184\times(100-30))+(100g\times2.008\frac{J}{g^oC}\times(110-100)^oC) \\ Q_w=(100\times4.184\times70)+(100\times2.008\times10) \\ Q_w=29,288+2008 \\ Q_w=31296\text{Joules} \\ Q_w=31.296kJ \\ \end{gathered}\)Get the total heat energy required;
\(\begin{gathered} Q_T=226.48kJ+31.296kJ \\ Q_T=257.776kJ \end{gathered}\)How many atoms of Chlorine would there be in 4.2 mol of Cl?
Answers
Answer:
4.2 moles Cl2 ( 2 Cl / 1 Cl2 ) = 8.4 mol Cl atoms.
Explanation:
Hope this helps.
does changes in state of matter indicate a chemical change.
Answers
Answer:
No, changes in matter are physical changes.
Explanation:
Ethanol fuel mixtures have "E" numbers that indicate the percentage of ethanol in the mixture by volume. For example, E10 is a mixture of 10% ethanol and 90% gasoline. How much E7 should be mixed with 3000 gal of E10 to make an E9 mixture? Part: 0 / 4 Part 1 of 4 Let x represent the amount of a mixture (in gal) containing 319. ethanol. 3000 gal is the amount of E10 mixture containing 10% ethanol. Therefore, is the amount of the resulting E9 mixture containing 906 ethanol
Answers
To make an E9 mixture 8657.14 gal of E7 should be mixed with 3000 gal of E10
Given to us is the amount of ethanol in the E10 mixture is 10% of 3000 gallons:
Ethanol in E10 = 10% × 3000 gal = 0.10 × 3000 gal = 300 gal
To solve this problem, we can set up an equation based on the amount of ethanol in each mixture.
Let x represent the amount of E7 mixture (in gallons) that needs to be added to the E10 mixture to obtain the desired E9 mixture.
The amount of ethanol in the E7 mixture is 7% of x gallons:
Ethanol in E7 = 7% × gal = 0.07 × gal
The resulting E9 mixture will contain 9% ethanol of the total volume of 3000 + x gallons:
Ethanol in E9 = 9% × (3000 + x) gal = 0.09 × (3000 + x) gal
According to the problem, the resulting E9 mixture contains 906 gallons of ethanol:
Ethanol in E9 = 906 gal
Now we can set up the equation:
Ethanol in E10 + Ethanol in E7 = Ethanol in E9
300 gal + 0.07x gal = 906 gal
Subtracting 300 gal from both sides:
0.07x gal = 606 gal
Dividing both sides by 0.07:
x = 606 gal / 0.07
x = 8657.14
Therefore, approximately 8657.14 gallons of E7 mixture should be mixed with 3000 gallons of E10 to make an E9 mixture.
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Complete question: Ethanol fuel mixtures have "E" numbers that indicate the percentage of ethanol in the mixture by volume. For example, E10 is a mixture of 10% ethanol and 90% gasoline. How much E7 should be mixed with 3000 gal of E10 to make an E9 mixture?
What is the mass of an object if its density is 12.3 g/ml and it has a volume of 25 ml?
Answers
\(density \: = \frac{mass}{volume} \)
mass = 12.3 × 25
= 307.5
approximately = 308 g
true or false: the process of combustion occurring without an open flame is called inconspicuous combustion.
Answers
The process of combustion occurring without an open flame is called inconspicuous combustion. This statement is False.
The process of combustion occurring without an open flame is not referred to as inconspicuous combustion. Inconspicuous combustion is not a recognized term in the context of combustion.
Spontaneous combustion, on the other hand, is the term used to describe the process of combustion that occurs without an external ignition source, such as an open flame. It typically happens when a material undergoes a self-sustaining exothermic chemical reaction, resulting in the release of heat and the ignition of the material itself.
Spontaneous combustion can occur in certain substances under specific conditions, such as high temperature, pressure, or exposure to oxidizing agents.
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You have been shipwrecked on a deserted island with no running water/fresh water, you have your clothes and a plastic bag containing your phone out of
charge and some sunscreen) How are you going to survive and escape?
Answers
Answer:
i have no clue
Explanation:
What volume will 2.0 moles of nitrogen occupy at 720 torr and 20.0°c? formula: pv = nrt (r = 62.396 l•torr/mol•k) 3.5 l 6.6 l 48 l 51 l
Answers
The ideal gas law is the state equation of a hypothetical ideal gas. The volume of the nitrogen gas is 51 I.
What is the ideal gas equation?The general gas equation, commonly known as the ideal gas law, is the state equation of a hypothetical ideal gas. The ideal gas equation is formulated as:
PV = nRT
In this equation, P refers to the pressure of the ideal gas, V is the volume of the ideal gas, n is the total amount of ideal gas that is measured in terms of moles, R is the universal gas constant, and T is the temperature.
As it is given that the pressure on the nitrogen is 720 torr, the temperature of the gas is 20°C(293 k), and the moles of nitrogen are 2.0 moles. Therefore, using the ideal gas equation the volume of the nitrogen can be written as,
\(pv=nRT\\\\v = \dfrac{nRT}{p}\\\\v = \dfrac{2 \times 62.396 \times 293}{720}\\\\v = 50.7834 \approx 51\)
Thus, the volume of the nitrogen gas is 51 I.
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Answer:
answer in picture
Explanation:
Help me
Do this for me ???
Answers
Answer:
I was just wondering if you want to be a good day at work and I don't know the answer sorry
Consider the intermediate equations: 3 equations.
C(s) + O2(g) --> CO2(g) Delta H1 = -393.5 kJ
2CO(g) + O2(g) --> 2CO2(g) Delta H2 = -566.0 kJ
2H2O(g) --> 2H2(g) + O2(g) Delta H3 = 483.6 kJ
With the overall reaction:
C(s) + H2O(g) --> CO(g) + H2(g) Delta Hrxn = ?
QUESTION 1:
What must be done to calculate the enthalpy of reaction?
The first must be halved.
The first must be reversed.
The second must be halved.
The second must be reversed.
The third must be halved.
The third must be reversed.
QUESTION 2:
What is the overall enthalpy of reaction?
Delta Hrxn = ____ kJ
Answers
Answer:
C. The second equation must be halved
D. The second equation must be reversed
E. The third equation must be halved.
Delta Hrxn= 131.3 kJ
Explanation:
The correct answer is -582 KJ.
What is the enthalpy of reaction?
Enthalpy is the heat content of a system.The enthalpy change of a reaction is roughly equivalent to the amount of energy lost or gained during the reaction.A reaction is favored if the enthalpy of the system decreases over the reaction.What is the overall enthalpy of the reaction?
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A gas with a volume of 650 mL and a pressure of 680 mm Hg is allowed to expand to a volume of 1200 mL. What is the new pressure of the gas in mm Hg?
Answers
Answer:
The new pressure will be
1000 L
Spring tides happen 2 times each month at the _and_phases
Neap tides happen 2 times each month at the _and_phases
Answers
Answer:
Spring tides happen 2 times each month at the New and Full phases
Neap tides happen 2 times each month at the First Quarter and Third Quarter phases
Given:
CH4 + 2O2 → CO2 + 2H2O, ΔH = -890 kJ/mol
How much energy is released when 59.7 grams of methane (CH4) reacts with oxygen?
The combustion of 59.7 grams of methane releases ___ kilojoules of energy
(I've seen two different answers both with goof reviews but I don't know which one is correct. This is for Edmentum btw)
Answers
Answer:
The combustion will release -3,321 KJ/mol of energy
Explanation:
What we need to do here is to first calculate the number of moles of methane burnt.
Mathematically, the number of moles of methane burnt = mass of methane/molar mass of methane
Molar mass of methane = 16g /mol
Thus the
number of moles will be ;
59.7/16 = 3.73 moles
Now, 1 mole of methane produces -890 KJ/mol if energy
Then the energy produced by by 3.73 moles of methane would be 3.73 * 890 = -3,320.8125
which is approximately -3,321 KJ/mol
Kindly note that the amount of heat is negative because it is an exothermic reaction
What is the molarity of 68.32g of h2so4 in 500ml of solution?
Answers
To determine the molarity of H2SO4 in the solution, we first need to calculate the number of moles of H2SO4 present in 68.32 g of the compound.
The molar mass of H2SO4 is:
2(1.008 g/mol) + 32.06 g/mol + 4(16.00 g/mol) = 98.08 g/mol
So, the number of moles of H2SO4 is:
68.32 g / 98.08 g/mol = 0.696 mol
Next, we need to convert the volume from mL to L:
500 mL = 0.5 L
Finally, we can calculate the molarity using the formula:
Molarity = moles of solute / volume of solution in liters
Molarity = 0.696 mol / 0.5 L = 1.392 M
Therefore, the molarity of 68.32 g of H2SO4 in 500 mL of solution is 1.392 M.
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