When an allele has a frequency of 1.0 in a population, it is _____ in the population. lost dominant

A study conducted in 2004 examined the usage of cable television and radio among 10 individuals to determine if there was a significant difference in the average hours spent on each medium. Using a significance level of 0.05, statistical analysis was performed to test for a disparity between the population mean usage of cable television and radio.

The researchers collected data on the number of hours per week spent watching cable television and listening to the radio from a sample of 10 individuals. The objective was to determine if there was a significant difference in the average usage between cable television and radio, considering the increasing competition among various entertainment options.

To test for a difference between the population mean usage for cable television and radio, a statistical hypothesis test was conducted. The significance level (α) of 0.05 was chosen, which means that the results would be considered statistically significant if the probability of obtaining such extreme results by chance alone was less than 5%.

The test compared the means of the two samples, namely the average hours spent watching cable television and listening to the radio. By analyzing the data using appropriate statistical techniques, such as a two-sample t-test, the researchers determined whether the observed difference in means was statistically significant or could be attributed to random variation.

After conducting the hypothesis test, if the p-value associated with the test statistic was less than 0.05, it would indicate that there was a significant difference between the population mean usage of cable television and radio. Conversely, if the p-value was greater than 0.05, there would be insufficient evidence to conclude a significant disparity.

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The value of y in the given coordinate points is 5.

The value of y in the given coordinate points is calculated as follows;

Point (5,1) is equidistant from (1,y) and (10, -3).

The value of y is calculated as follows;

(x₁ + x₂)/2, (y₁ + y₂)/2 = (5, 1)

(y - 3)/2 = 1

y - 3 = 2

y = 5

The coordinates points are (1, 5) and (10, - 3)

Thus, the value of y in the given coordinate points is 5.

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The position vector of the particle, denoted as r(t), can be calculated using the given acceleration, initial velocity, and initial position. The equation for r(t) is obtained by integrating the acceleration function with respect to time.

The acceleration vector a(t) is given as a(t) = 18t i + sin(t) j + cos(2t) k, where i, j, and k are the standard basis vectors in three-dimensional space. The initial velocity v(0) is given as i, and the initial position r(0) is given as j.

To find the position vector r(t), we need to integrate the acceleration function a(t) with respect to time. Integrating each component of a(t) separately, we get:

∫(18t) dt = 9t^2 + C1,

∫sin(t) dt = -cos(t) + C2,

∫cos(2t) dt = (1/2)sin(2t) + C3,

where C1, C2, and C3 are integration constants.

Now, integrating the components and incorporating the initial conditions, we have:

r(t) = (9t^2 + C1)i - (cos(t) + C2)j + (1/2)sin(2t) + C3)k,

Substituting the initial conditions r(0) = j, we can find the integration constants:

r(0) = (9(0)^2 + C1)i - (cos(0) + C2)j + (1/2)sin(2(0)) + C3)k = j,

which implies C1 = 0, C2 = 1, and C3 = 0.

Therefore, the position vector r(t) is:

r(t) = 9t^2i - (cos(t) + 1)j + (1/2)sin(2t)k.

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Answer:

x ≥ 20

Step-by-step explanation:

First, we want to isolate x. We can start to do that by subtracting 6 to both sides.

x/10≥2

Now, we multiply each side by 10.

x ≥ 20

That's the answer, all values above or equal to 20 are solutions.

Answer:

The answer is x_> 20

Step-by-step explanation:

Answer:

y=-2x^2+10x-12

Step-by-step explanation:

graph is shown in image below

The estimated δf for f(x) = 112 * x^2 when a = 2 and δx = -1/2 is approximately -224.

To estimate δf using linear approximation, we will use the formula: δf ≈ f'(a) * δx
Here, f(x) = 112 * x^2, a = 2, and δx = -1/2. First, we need to find the derivative of f(x) with respect to x: f'(x) = d(112 * x^2) / dx = 224 * x

Now, we will find the derivative at the point a: f'(a) = f'(2) = 224 * 2 = 448
Finally, we'll use the linear approximation formula to estimate δf: δf ≈ f'(a) * δx = 448 * (-1/2) = -224

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Answer:

y intercept: (0,-13)

x intercept: (13/5, 0)

Step-by-step explanation:

To find the y intercept, x has to equal zero. So, plug it in. The equation becomes y=-13.

Since x is zero, the point becomes (0,-13)

To find the x intercpet, y has to equal zero. So, plug it in. The equation becomes 0=5x-13.

move 13 to the other side

13=5x

divide by 5

13/5=x

Since y is zero, the point becomes (13/5,0)

hope this helps!

The given line is 5x - 3y = 0. It is required to write the equation of a line that is perpendicular to this line and passes through the point (-2,-1).We know that if two lines are perpendicular, then the product of their slopes is equal to -1.Therefore, the slope of the line 5x - 3y = 0 is given by:5x - 3y = 0-3y = -5x + 03y = 5x y = (5/3) x

The slope of the required line is negative reciprocal of the slope of this line: m = -3/5The point (-2,-1) lies on the required line and the slope of the line is -3/5.Therefore, the equation of the line in the slope-intercept form is given by:

y - y1 = m(x - x1),

where (x1,y1) = (-2,-1)

Substituting the values, we get:

y - (-1) = -3/5(x - (-2))y + 1 = -3/5(x + 2)y + 1 = (-3/5)x - 6/5y = (-3/5)x - 6/5 - 1y = (-3/5)x - 11/5

Thus, the equation of the required line in slope-intercept form is y = (-3/5)x - 11/5. The slope-intercept form of a linear equation is y = mx + b where m represents the slope and b represents the y-intercept. To find the equation of a line that passes through a given point and is perpendicular to a given line, we need to use the properties of perpendicular lines.In order for two lines to be perpendicular, their slopes must have opposite signs and be reciprocals of each other. We can find the slope of the given line by rearranging it in slope-intercept form as follows:

5x - 3y = 0-3y = -5x + 0y = (5/3)x

So the slope of the given line is 5/3. Since the slope of the perpendicular line must be the negative reciprocal of 5/3, we have:m = -1/(5/3) = -3/5Now we can use the point-slope form of the equation of a line to find the equation of the line passing through the point (-2,-1) with slope -3/5:

y - y1 = m(x - x1)y - (-1) = (-3/5)(x - (-2))y + 1 = (-3/5)(x + 2)y + 1 = (-3/5)x - 6/5y = (-3/5)x - 6/5 - 1y = (-3/5)x - 11/5

So the equation of the line that passes through (-2,-1) and is perpendicular to 5x - 3y = 0 is y = (-3/5)x - 11/5.

Therefore, the equation of the required line in slope-intercept form is y = (-3/5)x - 11/5.

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Answer:

C

Step-by-step explanation:

6 is the smallest so the first one would be c because it is the smallest

The set S does not span the vector space M_n×n.

To determine if the vector space of square matrices, denoted as M_n×n, is spanned by the set S, we need to check if every matrix in M_n×n can be expressed as a linear combination of matrices formed by the commutator operation.

The set S consists of matrices of the form m = ab − ba, where a and b are matrices in M_n×n. The commutator operation produces a new matrix by taking the difference between the matrix product ab and ba.

To show that S spans M_n×n, we need to demonstrate that any matrix M in M_n×n can be expressed as a linear combination of matrices from S. In other words, we need to find matrices a and b such that M = ab − ba.

However, it is not possible to express every matrix in M_n×n as a commutator of two matrices. This is because not all matrices have a well-defined commutator representation. Therefore, the set S does not span the vector space M_n×n.

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(a) The probability that a call selected at random lasts 4 minutes or less is 0.5(1 - \(e^(^-^e^s^4^)\)), where s is the rate parameter of the probability density function.

(b) The probability that a call selected at random lasts between 7 and 10 minutes is ∫[7,10] 0.5\(e^(^-^e^s^t^)\) dt.

(c) The probability that a call selected at random lasts 4 minutes or less, given that it lasts 7 minutes or less, is P(t ≤ 4 | t ≤ 7).

(a) To find the probability that a call lasts 4 minutes or less, we can integrate the probability density function from 0 to 4. The probability density function is given as f(t) = 0.5\(e^(^-^e^s^t^)\), where t represents the duration of the call and s is the rate parameter. Plugging in the values, we have P(t ≤ 4) = ∫[0,4] 0.5\(e^(^-^e^s^t^)\) dt. Integrating this expression will give us the desired probability.

(b) To find the probability that a call lasts between 7 and 10 minutes, we need to integrate the probability density function from 7 to 10. Using the same probability density function as before, we have P(7 ≤ t ≤ 10) = ∫[7,10] 0.5\(e^(^-^e^s^t^)\) dt. Evaluating this integral will give us the probability.

(c) To find the probability that a call lasts 4 minutes or less, given that it lasts 7 minutes or less, we can use conditional probability. The probability is given by P(t ≤ 4 | t ≤ 7) = P(t ≤ 4 and t ≤ 7) / P(t ≤ 7). The numerator represents the joint probability of a call lasting 4 minutes or less and 7 minutes or less, while the denominator represents the probability of a call lasting 7 minutes or less. By calculating these probabilities separately and dividing them, we can find the desired conditional probability.

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Answer:

I don't know what prism. once you see this put it in the description of this

Step-by-step explanation:

Answer:

5 5/7 liters of 5%

4 2/7 of the 40 %

Step-by-step explanation:

we need 10 liter of a 20 %  solution

We have x liters of 5%  and  since there is a total of 10 liters we have 10-x of the 40 % solutions

10 * .20  = .05 x + .40 ( 10-x)

2 = .05x +4 - .4x

Combine like terms

2 = 4- .35x

Subtract 4 from each side

2-4 = -.35x

-2 = -.35x

Divide by -.35

-2/.-35 =x

40/7 =x

5 5/7 =x

10 -5 5/7 = 4 2/7

4 2/7 of the 40 %

We can write an equation for this problem.

10 * 0.20 = 0.05x + 0.40(10 - x)

~Simplify

2 = 0.05x + 4 - 0.40x

~Combine like terms

2 = 4 - 0.35x

~Subtract 4 to both sides

-2 = 0.35x

~Divide 0.35 to both sides

40/7 = x

~Subtract by 10

10 - 40/7 = 30/7

30/7 of 40%

Best of Luck!

Answer: Circle = 5    Triangle = 2     Square = 6

Step-by-step explanation:  5 + 2 = 7          2 + 6 = 8              6+2 =8, 8 + 5 =13

The equation for the temperature, D, in terms of t, with the minimum positive phase shift possible, is: D = 65 + 13 sin[(t - 4) * (2π / 24)].

The given information suggests that the temperature variation throughout the day follows a sinusoidal pattern. To find the equation for temperature, we need to consider the amplitude, period, and phase shift. The high temperature is 78 degrees, which corresponds to the midpoint of the sinusoidal function. The low temperature of 52 degrees occurs at 4 AM, which implies a phase shift to the right by four hours.

The general form of a sinusoidal function is D = A + B sin[(t - C) * (2π / P)], where A represents the midline (average temperature), B denotes the amplitude (half the difference between the high and low temperatures), C signifies the phase shift, and P is the period.

In this case, the midline temperature is (78 + 52) / 2 = 65 degrees. The amplitude is (78 - 52) / 2 = 13 degrees, as it is half the difference between the high and low temperatures. The phase shift, determined by the time at which the low temperature occurs, is 4 hours. The period, in this case, is 24 hours.

Substituting these values into the general equation, we obtain D = 65 + 13 sin[(t - 4) * (2π / 24)], which represents the temperature, D, as a function of time, t, with the minimum positive phase shift possible.

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Answer:

the answer is inspection

Step-by-step explanation:

The area of a circle is changing at a rate of 576π cm²/sec when the radius of the circle is 32 cm.

For the given question;

Express the circle's area as a function of the its radius.

A = πr²

Determine the area's derivative with respect towards its radius.

dA/dr = 2πr

Using the chain rule, calculate the derivative of a area with respect to time.

dA/dt =  dA/dr . dr/dt

dA/dt = 2πr(9)

dA/dt = 18πr

When the radius is 32 cm, find the derivative of a area with respect to time.

dA/dt = 18π(32)

dA/dt = 576π

As a result, the area of a circle is changing at a rate of 576π cm²/sec when the radius of the circle is 32 cm.

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Answer: 21

Step-by-step explanation:

This means we can substitute x=5 into f(x), so f(5)=6+3(5)=21.

P

OQ = 4S - 10

OP = 23

PQ = 1

Equation

OQ = OP + PQ

Substitution

4S - 10 = 23 - 1

Simplification

4S = 22 + 10

4S = 32

S = 32/4

S = 8

Determine OP

OQ = 4(8) - 10

OQ = 32 - 10

OQ = 22

Three examples of groups of order 120 that are not isomorphic are the symmetric group S5, the direct product of Z2 and A5, and the semi-direct product of Z3 and S4.

The symmetric group S5 consists of all the permutations of five elements, which has order 5! = 120. This group is not isomorphic to the other two examples because it is non-abelian, meaning the order in which the elements are composed affects the result. The other two examples, on the other hand, are abelian.

The direct product of Z2 and A5, denoted Z2 × A5, is formed by taking the Cartesian product of the cyclic group Z2 (which has order 2) and the alternating group A5 (which has order 60). The resulting group has order 2 × 60 = 120. This group is not isomorphic to S5 because it contains an element of order 2, whereas S5 does not.

The semi-direct product of Z3 and S4, denoted Z3 ⋊ S4, is formed by taking the Cartesian product of the cyclic group Z3 (which has order 3) and the symmetric group S4 (which has order 24), and then introducing a non-trivial group homomorphism from Z3 to Aut(S4), the group of automorphisms of S4. The resulting group also has order 3 × 24 = 72. However, there are exactly five groups of order 120 that have a normal subgroup of order 3, and Z3 ⋊ S4 is one of them. These five groups can be distinguished by their non-isomorphic normal subgroups of order 3, making Z3 ⋊ S4 non-isomorphic to S5 and Z2 × A5.

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The longer worm was ( 3)/(10) of an inch longer than the shorter worm.

To find out how much longer the longer worm was, we need to subtract the length of the shorter worm from the length of the longer worm.

Length of shorter worm = ( 1)/(2) inch

Length of longer worm = ( 1)/(5) inch

To subtract fractions with different denominators, we need to find a common denominator. The least common multiple of 2 and 5 is 10.

So,

( 1)/(2) inch = ( 5)/(10) inch

( 1)/(5) inch = ( 2)/(10) inch

Now we can subtract:

( 2)/(10) inch - ( 5)/(10) inch = ( -3)/(10) inch

The longer worm was ( 3)/(10) of an inch longer than the shorter worm.

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This type of account is commonly referred to as a flat-fee or all-inclusive trading account. It simplifies the fee calculation and allows the client to have better visibility and control over their trading costs.

A flat-fee trading account is an account where clients pay a single, predetermined fee that covers all the trades executed within the account, regardless of the number of transactions made. This approach is different from traditional transaction-based accounts where clients pay a separate fee for each individual trade.

By offering a flat-fee account, your firm aims to provide cost-saving benefits to the active investor client who frequently engages in numerous transactions. Instead of incurring transaction fees for each trade, the client can pay a single flat fee that covers all the trades made within the account. This can potentially lead to significant cost savings for the client, especially if they regularly execute a high volume of trades.

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A digital camera is used that takes pictures with a resolution of 2536×1902 pixels with a colour depth of 24 bits, the file size, rounded to the nearest tenth, is approximately 13.1 MB.

To calculate the file size in megabytes, we need to consider the resolution and color depth of the image.

Resolution: 2536 × 1902 pixels

Color depth: 24 bits (8 bits per color)

The file size can be calculated using the formula:

File Size = (Resolution Width × Resolution Height × Color Depth) / (8 × 1024 × 1024)

File Size = (2536 × 1902 × 24) / (8 × 1024 × 1024) ≈ 13.1 MB

Therefore, the file size, is approximately 13.1 MB.

To calculate the file size when reducing the resolution to 845×634 pixels:

Resolution: 845 × 634 pixels

Color depth: 24 bits (8 bits per color)

File Size = (Resolution Width × Resolution Height × Color Depth) / (8 × 1024 × 1024)

File Size = (845 × 634 × 24) / (8 × 1024 × 1024) ≈ 1.3 MB

Therefore, the size of the reduced file is approximately 1.3 MB.

The reduction factor obtained is the ratio of the original file size to the reduced file size:

Reduction Factor = Original File Size / Reduced File Size

Reduction Factor = 13.1 MB / 1.3 MB = 10

Therefore, the file size has been divided by a factor of 10.

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Answer:

slope = 1

Step-by-step explanation:

A standard linear function is

y = mx + b

where m = slope, b = initial value

Given y = x + 6

slope m = 1, b = 6

Slope of a line parallel to the given line should have the same slope, therefore slope required is m = 1.

Answer:

  see below for the meaning of a, b, c, k, p, q.

Step-by-step explanation:

You want the minimum value of a quadratic function.

The extreme will be a minimum if the sign of the leading term is positive. It will be a maximum if the sign of the leading term is negative.

The standard form equation of a parabola is ...

  f(x) = ax² +bx +c

The x-coordinate of the extreme value (maximum or minimum) is ...

  x = -b/(2a)

The y-coordinate of the extreme value, the maximum or minimum, is ...

  y = -b²/(4a) +c

The extreme point is (-b/(2a), -b²/(4a) +c).

The vertex form equation of a parabola is ...

  f(x) = a(x -h)² +k

The coordinates of the vertex (extreme point) are (h, k).

The factored form of the equation of a parabola is ...

  f(x) = a(x -p)(x -q)

where p and q are the x-intercepts.

The coordinates of the extreme point are ((p+q)/2, -a/4(p-q)²).

__

Additional comment

As you can see, the way you find the minimum (or maximum) value depends on what you're starting with. In general that value is the y-value of the vertex. We have also shown the x-value of the vertex, because you may be asked for the coordinates of the minimum (or maximum) point.

You may see the quadratic function in other forms. Generally, those forms can be rearranged to one of these forms. Obviously, if you're looking for the vertex, the "vertex form" is the easiest place to start.

The value of 'a' is the leading coefficient in every case.

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To find the minimum value of a quadratic equation, you can use either the vertex formula or completing the square method. The minimum value occurs at the vertex of the parabola.

To find the minimum value of a quadratic equation, you can use either the vertex formula or completing the square method.

Vertex Formula:

Completing the Square:

By using either of these methods, you can find the minimum value of a quadratic equation.

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Cosine distance is used in the k-means clustering algorithm to remove outliers. It is a metric used to determine the similarity between two documents. In k-means clustering, cosine distance is used to calculate the distance between data points.

Cosine distance is used to normalize the data so that it is not affected by the length of the data vectors or the scale of the data. The cosine distance is calculated as follows:

Cosine distance = 1 - Cosine similarity,

where Cosine similarity = dot product of two vectors/ product of the magnitude of two vectors.

To remove the outliers from the k-means clustering algorithm, we can set a threshold value for the cosine distance. If the cosine distance between two data points is greater than the threshold value, then those data points are considered outliers and they are not included in the cluster. This helps to ensure that the clustering algorithm only groups together data points that are similar and ignores the outliers.

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