When an atom is neutral the...?
A.the number of neutrons and protons are the same
B.the number of neutrons and electrons are the same
C.the number of protons and electrons are the same
D.all atoms are neutral regardless of the number of protons, neutrons, and electrons

Answers

Answer 1

Answer:

c

Explanation:

if numbers of protons and electrons are equal, the atom is neutral

Answer 2

Answer:

C.the number of protons and electrons are the same.

Explanation:

Protons have a positive charge, while electrons have a negative charge.

So, if there are more electrons (-) than protons (+), the atom will have a negative charge.

If the atom has more protons (+) than electrons (-), it will have a positive charge.

If they have the same number of negative and positive, they "cancel" out, making it neutral.


Related Questions

Non examples of convert

Answers

Answer:

another. persist. continue. last. remain.

Explanation:

What is sound waves

Answers

Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.

Characteristics of sound waves

Frequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).

Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.

Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.

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A pipe drips at 155 mL/min.
Express this is units of gallons/day.
1. 2.34 gal/day
2. 15.7 gal/day
3. 942 gal/day
4. 58.9 gal/day
5. 223 gal/day
6. 377 gal/day
7. 0.223 gal/day

Answers

We have that the total pipe drip of \(X=155 mL/min.\) expressed in gallons/day is

\(X=58.96gal/day\)

From the Question we are told that

Pipe Drip\(=155 mL/min.\)

Generally

We have that for mL to gallons conversion

\(1mL=0.000264172\)

And

A minute to day con version is

\(1min=0.000694444\)

Therefore

\(X=155 mL/min.\)

\(X=155(\frac{0.000264172}{0.000694444})\)

\(X=58.96gal/day\)

In conclusion

The total pipe drip of \(X=155 mL/min.\) expressed in gallons/day is \(X=58.96gal/day\)

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The half-life of a radioactive isotope is 210 d. How many days would it take for the decay rate of a sample of this isotope to fall to 0.58 of its initial rate?

Answers

It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.

2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.

3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.

4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.

5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.

6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".

7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).

8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).

9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.

10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.

11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).

12. Evaluating the expression, we find: t ≈ 546.

13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.

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Which statement best compares gamma rays to the other components of the electromagnetic spectrum?

Am I correct ???

Which statement best compares gamma rays to the other components of the electromagnetic spectrum?Am I

Answers

Answer:

no

Explanation:

gamma rays do have the most frequency, but they also have the highest amount of energy because they happen the most often.

two forces f1=(8i+3j)N and f2=(4i+6j) are acting on 5kg object then what is the magnitude and the direction of the resultant force
what is its acceleration of x and y component
what is the magnitude of acceleration of the object

Answers

Two forces f1=(8i+3j)N and f2=(4i+6j) are acting on 5kg object then  the magnitude of the resultant force is 15 N and the direction of the resultant force is approximately 36.87 degrees from the positive x-axis.

The acceleration of the object in the x-component (\(a_x\)) is 2.4  \(m/s^{2}\), and the acceleration in the y-component (\(a_y\)) is 1.8  \(m/s^{2}\).

The magnitude of the acceleration of the object is 3  \(m/s^{2}\).

To find the magnitude and direction of the resultant force, we need to add the two given forces together.

Given:

f1 = (8i + 3j) N

f2 = (4i + 6j) N

To find the resultant force (\(F_res\)), we simply add the corresponding components:

\(F_res\) = f1 + f2

= (8i + 3j) + (4i + 6j)

= (8 + 4)i + (3 + 6)j

= 12i + 9j

The magnitude of the resultant force (\(|F_res|\)) can be found using the Pythagorean theorem:

\(|F_res|\)= \(\sqrt{(12^2) + (9^2)}\)

= \(\sqrt{144 + 81}\)

= \(\sqrt{225}\)

= 15 N

So, the magnitude of the resultant force is 15 N.

To find the direction of the resultant force, we can use trigonometry. The direction can be represented by the angle θ between the positive x-axis and the resultant force vector. We can calculate θ using the inverse tangent function:

θ = arctan(9/12)

= arctan(3/4)

≈ 36.87 degrees

Therefore, the direction of the resultant force is approximately 36.87 degrees from the positive x-axis.

Now let's calculate the acceleration of the object in the x and y components. We know that force (F) is related to acceleration (a) through Newton's second law:

F = ma

For the x-component:

\(F_x\)= 12 N

m = 5 kg

Using  \(F_x\)= \(ma_x\), we can solve for \(a_x\):

12 N = 5 kg * \(a_x\)

\(a_x\)= 12 N / 5 kg

\(a_x\) = 2.4 \(m/s^{2}\)

For the y-component:

\(F_y\) = 9 N

m = 5 kg

Using \(F_y\) = \(ma_y\), we can solve for \(a_y\):

9 N = 5 kg * \(a_y\)

\(a_y\) = 9 N / 5 kg

\(a_y\)= 1.8  \(m/s^{2}\)

So, the acceleration of the object in the x-component (\(a_x\)) is 2.4  \(m/s^{2}\), and the acceleration in the y-component (\(a_y\)) is 1.8  \(m/s^{2}\).

To find the magnitude of the acceleration (|a|), we can use the Pythagorean theorem:

|a| = \(\sqrt{(a_x^2) + (a_y^2)}\)

= \(\sqrt{(2.4^2) + (1.8^2}\)

= \(\sqrt{5.76 + 3.24}\)

= \(\sqrt{9}\)

= 3  \(m/s^{2}\)

Therefore, the magnitude of the acceleration of the object is 3  \(m/s^{2}\)

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name a substance which will undergo change E​

name a substance which will undergo change E

Answers

Answer:

Water

Explanation:

At 0 degrees it's solid...Then it melts into a liquid and at 100 degrees it's gas Simple

Please help, will mark brainliest

(a) A freezer maintains an interior temperature inside of −12.0°C and has a coefficient of performance of 3.00. The freezer sits in a room with a temperature of 19.0°C. The freezer is able to completely convert 26.0 g of liquid water at 19.0°C to ice at −12.0°C in one minute. What input power (in watts) does the freezer require? (The specific heat of liquid water is 4.186 J/(g · °C), the specific heat of ice is 2.090 J/(g · °C), and the latent heat of fusion of water is 334 J/g.)

(b) What If? In reality, only part of the power consumption of a freezer is used to make ice. The remainder is used to maintain the temperature of the rest of the freezer. Suppose, however, that 100% of a freezer's typical power consumption of 160 W is available to make ice. The freezer has the same coefficient of performance as given above. How many grams per minute of water at 19.0°C could this freezer convert to ice at −12.0°C? g/min

Answers

Answer:

A.55.49W, B. 25g

Explanation:

The heat required to free the water at 17°c is that required to reduce it to water at 0°c plus that to convert it to ice at 0°c plus that required to get it to ice at -12°c.

Note that in the conversion process mass is constant.

Hence the heat extracted is defined as mass ×specific heat capacity × temperature change.

But on conversion from water to ice at 0°c the heat extracted is mass × latent heat of fusion.

Putting all together we have :

26 ×4.186 ×(0-19) -26 ×334 + 26 × 2.090× (-12-0)

=2067.884+8684+652.08=9988.16J

This is the output power

From performance formula;

Coefficient of performance=output power /input power

Input power = output power / coefficient of performance

Input power=9988.16J/3 =3329.39j

In watt we divide by 60

3329.39/60= 55.49W

Note the negative sign is just an indication that heat is been lost from the system.

B. Let's calculate Energy per unit mass of the process

9988.16J/26 =384.16J/g

Power consumption is 160w

This is the input power of the system

160 W is available to make ice.

This means 160 ×60 J is the energy available to make ice since the whole process takes 60s.

That energy =9600J

But the output energy per unit mass is 384.16J/g.

Hence the required mass for 9600J is

9600/384.16= 24.99g

Approximately 25g

Freezer requires 55,49 W of input of energy and the 25 g/ min of water at 19.0°C, this freezer convert to ice at −12.0°C.

(A)

Since, mass is constant.

Thus,

\(\bold {Q = mc\Delta T}\)...........1

But on conversion from water to ice at 0°c

Q  = m x Lf...........2

From equation 1 and 2,

26 ×4.186 ×(0-19) -26 ×334 + 26 × 2.090× (-12-0)

=2067.884 + 8684 + 652.08 = 9988.16 J

From performance formula;

\(\bold {Pi = \dfrac {Po} {CoP}}\)

Where,

Pi - power input

Po - Power output

CoP - Coefficient of power

\(\bold { Pi =\dfrac {9988.16\ J}{3} = 3329.39 J = 55.49 W}\)

(B)

Since, the negative sign indicate the lost of heat from the system.

Calculate Energy per unit mass of the given process

9988.16J/26 =384.16 J/g

Power consumption =  160 W

Since, the whole process takes 60s.

160 ×60 J = 9600 J

But the output energy per unit mass is 384.16J/g.

Hence the required mass for 9600J,

9600/384.16= 24.99g = 25 g/min

Therefore, freezer requires 55,49 W of input of energy and the 25 g/ min of water at 19.0°C, this freezer convert to ice at −12.0°C.

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Only Part B(a) Calculate the minimum frequency of ultrasound (in Hz) that will allow you to see details as small as 0.175 mm in human tissue. (Assume the speed of sound through human tissue is 1540 m/s.) a = 8.8e6 (b) What is the effective depth (in cm) to which this sound is effective as a diagnostic probe? cm

Answers

To determine the maximum depth we will use the following rule:

\(d_{max}=500\lambda\)

Where:

\(\begin{gathered} d_{max}=\text{ maximum depth} \\ \lambda=\text{ wavelength} \end{gathered}\)

Now, we substitute the values:

\(\begin{gathered} d_{max}=500(0.175mm) \\ d_{max}=87.5mm \end{gathered}\)

Now, we convert to centimeters by dividing the result by 10:

\(d_{max}=87.5mm\times\frac{1cm}{10mm}=8.75cm\)

Therefore, the maximum depth is 8.75 cm.

a uniform ladder of mass 100kg leans at 60° to the horizontal against a frictionless wall, calculate the reaction on the wall.​

Answers

Answer:

\(500\text{N} (490\text{N}) (490.5\text{N})\)

Explanation:

The reaction force is the force that is in the perpendicular direction to the wall.

We have an angle and a hypotenuse, we need to find the adjacent angle - so we can just use cos:

\(cos(\theta)=\frac{\text{adj}}{\text{hyp}}\\\text{hyp}*cos(\theta)=\text{adj}\\100*cos(60)=100*0.5=50\text{kg}\)

However, we would like a force and not a mass.

\(W=mg\\W=50g\\W=500\text{N} (490\text{N}) (490.5\text{N})\)

Answer 1 if you use g as 10, answer 2 if you're studying mechanics in maths, answer 3 if you're studying mechanics in physics.

Monochromatic light passes through two narrow slits 0.36 mm apart and forms an interference pattern on a screen 2.65 m away. If light of wavelength 632.69 nm is used, what is the distance from the center of the central maximum to the center of the third order bright fringe in centimeters?

Answers

Let's name some variables:

d: slit distance (in m); d = 0.00036 m

D: distance to the screen where the interference pattern is shown; D = 2.65 m

λ: wavelength of light; λ = 632.69 nm

y: distance from the center of the central maximum to the center of the third order bright fringe; we are solving for this

Given these known and unknown variables, we can use the following equation to solve for the unknown:

y = 3λD/d

Now, we just need to plug in the known variables:

y = 3*632.69*2.65/0.00036

y = 13971904.2 nm = 13.9719042 mm = 1.397 cm

An object has a mass of 120 kg on the moon what is the force of gravity acting on the object on the moon

Answers

Answer: i think it is An object has a mass of 120 kg on the Moon. The force of gravity acting on the object on the Moon is 196 N. Sol'n: force = mass * gravity; gravity on the moon is 1/6 that on the Earth = 9.807*(1/6)=1.6345; f = m*g; f = 120*1.6345 =196.14.

Explanation:

Answer:

Hey there!

W=mg, where m is the mass and g is the acceleration of gravity.

The acceleration of g on the moon is about 1.622 m/s^2, so plugging that in as a value gives us W, the force is equal to approximately 197 Newtons.

Let me know if this helps :)

If you speed through a construction zone while workers are present, your fines could be:.

Answers

If you speed through a construction zone while workers are present, your fines could be as much as one thousand dollars.

What is a Fine?

This is referred to as the amount which is instructed by a court or authority to be paid as a result of it being a penalty for various types of offences. each crime has its specific fine which helps to serve as deterrent for unlawful behavior in the community.

it is always best not to speed when within a construction zone which has workers present in the area. This is ideal as it helps to prevent incidences of accidents or death.

it is therefore the reason why a fine of 1000 dollars is to be paid so that people can think of such high amount before performing certain types of activities when driving and makes it the most appropriate choice.

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two waves that pass through the same medium at the same time produce:
a. diffraction
b. interference
c. refraction
d. resonance

Answers

The correct answer is

B. Interference

What is the final temperature if I mix 20 liters of water at 80 degrees with another 20 liters of water at 20 degrees?

Answers

The final temperature of the mixture is 50°C.

Temperature of the hot water, T₁ = 80°C

Temperature of the cold water, T₂ = 20°C

According to the principle of calorimetry, the heat lost by the hot body is equal to the heat gained by the cold body.

So,

Heat lost by the hot water = Heat gained by the cold water

mC(T₁ - T) = mC(T - T₂)

Since, both are water and the amount of water is the same for both,

T₁ - T = T - T₂

Applying the values of T₁ and T₂,

80 - T = T - 20

2T = 100

Therefore, the final temperature of the mixture is,

T = 100/2

T = 50°C

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Cs-124 has a half-life of 30.8 s

A) If we have 7.5 μg initially, how many Cs nuclei are present?

B) How many nuclei are present 2.6 min later?

Answers

A) There are 3.70 x 10¹⁶ Cs nuclei present initially and B) There are 2.27 x 10¹⁵ Cs nuclei present 2.6 min later.

A) To solve this problem, we can use the following equation,

\(N = N'2^{\frac{-t}{T_{1/2}}}\)), number of Cs nuclei present is N, initial number of Cs nuclei present is N', elapsed time is t, half-life of Cs-124 is T½. First, we need to convert the initial mass of Cs-124 to the number of nuclei present,

7.5 μg Cs-124(1g/10⁶μg)(6.022x10²³nuclei/1g)

= 4.52 x 10¹⁵ Cs-124 nuclei.

Using the equation above, we can find the number of Cs-124 nuclei present after 0 s,

\(N = 4.52 * 10^{15} * 2^{\frac{-0}{30.8}}}\)

= 4.52 x 10¹⁵ Cs-124 nuclei

Therefore, initially, there are 4.52 x 10¹⁵ Cs-124 nuclei present.

B) After 2.6 min (156 s), we can again use the same radioactivity equation to find the number of Cs-124 nuclei present,

\(N = 4.52 * 10^{15} * 2^{\frac{-156}{30.8}}}\)

N = 1.60 x 10¹⁴ Cs-124 nuclei

Therefore, 2.6 min later, there are 1.60 x 10¹⁴ Cs-124 nuclei present.

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x
X
Number of Paper Clips Picked up
Electromagnet Strength
25
4x D
20
15
10
s
5
This chart measures how many paper clips were picked up by an electromagnet based on its number of coils.
Based on the graph, which statement is true?
A
The more coils of wire on an electromagnet, the more paperclips that it is likely to pick up.
10
15
Number of Coils of Wire
B At least one electromagnet in this study did not pick up any paperclips at all.
20
C
The less coils of wire wrapped around an electromagnet, the more magnetic it becomes.
The most paperclips picked up by an electromagnet in this study is 20.

Answers

Answer:

Explanation:

X

Number of Paper Clips Picked up

Electromagnet Strength

25

4x D

20

15

10

s

5

This chart measures how many paper clips were picked up by an electromagnet based on its number of coils.

Based on the graph, which statement is true?

A

The more coils of wire on an electromagnet, the more paperclips that it is likely to pick up.

10

15

Number of Coils of Wire

B At least one electromagnet in this study did not pick up any paperclips at all.

20

C

The less coils of wire wrapped around an electromagnet, the more magnetic it becomes.

The most paperclips picked up by an electromagnet in this study is 20.

Two point charges are separated by 12cm what is the force between them

Answers

Answer:

Coulomb's law calculates the magnitude of the force F between two point charges, q1 and q2, separated by a distance r. F=k|q1q2|r2.

Explanation:

math
Determine if the function below is continuous.

graph of a piecewise function, with 2 pieces. The first piece is a line that starts at negative infinity and goes through point (-4,5) and ends with an open dot at (1,0). The second piece is a line that starts with a closed dot at (1,-1), goes through point (2,1) and continues to infinity.

A. not continuous at x = 1
B. not continuous at x = 0
C. not continuous at x = -1
D. continuous

mathDetermine if the function below is continuous. graph of a piecewise function, with 2 pieces. The

Answers

The function is not continuous at x=1, so the answer is A.

At x=1, the two pieces of the function meet. The first piece ends with an open dot at (1,0), meaning that the function is not defined at $x=1$. The second piece starts with a closed dot at (1,-1), meaning that the function is defined at x=1 and takes the value -1 there.

Since the function is not defined at x=1, it cannot be continuous at that point. Therefore, the function is not continuous overall.

A. Uranus

B. Mars

C. Mercury

D. Earth

HELPPPP PLEASE

A. Uranus B. MarsC. Mercury D. EarthHELPPPP PLEASE

Answers

Answer:

C. Mercury

Explanation:

Need help on this question I’d really appreciate it thanks!

Need help on this question Id really appreciate it thanks!

Answers

Answer:radiation

Explanation:

radiation is the only one that makes sense

A Michelson interferometer uses light from a sodium lamp. Sodium atoms emit light having wavelengths 589.0 nm and 589.6 nm. The interferometer is initially set up with both arms of equal length (L1=L2), producing a bright spot at the center of the interference pattern. How far must mirror M2 be moved so that one wavelength has produced one more new maxima than the other wavelength?

Answers

The distance mirror M2 must be moved so that one wavelength has produced one more new maxima than the other wavelength is;

L = 57.88 mm

We are given;

Wavelength 1; λ₁ = 589 nm = 589 × 10⁻⁹ m

Wavelength 2; λ₂ = 589.6 nm = 589.6 × 10⁻⁹ m

We are told that L₁ = L₂. Thus, we will adopt L.

Formula for the number of bright fringe shift is;

m = 2L/λ

Thus;

For Wavelength 1;

m₁ = 2L/(589 × 10⁻⁹)

For wavelength 2;

m₂ = 2L/(589.6)

Now, we are told that one wavelength must have produced one more new maxima than the other wavelength. Thus;

m₁ - m₂ = 2

Plugging in the values of m₁ and m₂ gives;

(2L/589) - (2L/589.6) = 2

divide through by 2 to get;

L[(1/589) - (1/589.6)] = 1

L(1.728 × 10⁻⁶) = 1

L = 1/(1.728 × 10⁻⁶)

L = 578790.67 nm

L = 57.88 mm

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what is canadas offical winter sport​

Answers

Answer:

Ice hockeyyyyyy

Explanation:

Ice Hockey
Good luck

the answer for this pls

the answer for this pls

Answers

The solubility of a substance in a solvent is affected by many factors, including temperature. In general, increasing the temperature of a solvent increases the solubility of a solute in that solvent. This relationship is known as the temperature-solubility relationship.

How to explain the relationship

There are a few different ways in which temperature can affect solubility, depending on the specific solute and solvent in question. For example:

For most solid solutes in liquid solvents, increasing the temperature of the solvent will increase the solubility of the solute. This is because increasing the temperature generally increases the kinetic energy of the solvent molecules, which in turn makes it easier for them to break apart the intermolecular forces holding the solute together and form new solute-solvent interactions.

In some cases, however, the opposite may be true: the solubility of a solute in a solvent may decrease with increasing temperature. This is often observed for gases dissolved in liquids, where increasing the temperature decreases the solubility of the gas. This is because increasing the temperature of the liquid also increases the kinetic energy of the gas molecules, making them more likely to escape from the liquid and form a gas phase.

In rare cases, the temperature-solubility relationship may be more complex and exhibit unusual behavior. For example, for some solutes, the solubility may initially increase with temperature but then decrease at higher temperatures.

Overall, the relationship between temperature and solubility is an important consideration in many chemical processes, including crystallization, precipitation, and dissolution. Understanding this relationship can help scientists and engineers optimize their processes and achieve their desired outcomes.

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what is the magnitude of its velocity just before it strikes the ground, if the bottle was thrown straight out horizontally from the tower with a speed of 11.8 m/s?

Answers

There's not enough given information to find the answer.

The horizontal velocity has no effect on anything that happens vertically. To find the object's vertical speed when it hits the ground, we need to know what height it was dropped from, and that's not given in the question.

Since the bottle is falling vertically, the vertical displacement s is the height of the tower from which it was thrown.

If a bottle is thrown horizontally from a tower, its initial vertical velocity is 0 m/s since there is no vertical component to its initial velocity. The only force acting on the bottle in the vertical direction is gravity, which causes it to accelerate downward at a rate of approximately 9.81 m/s² (assuming Earth's gravity).

Since the initial vertical velocity is 0 m/s and the acceleration is 9.81 m/s², you can use the following kinematic equation to find the magnitude of its velocity just before it strikes the ground:

v2=u2+2as

Where:

v is the final vertical velocity (which we're trying to find)

u is the initial vertical velocity (0 m/s)

a is the acceleration due to gravity (-9.81 m/s², negative because it's acting downward)

s is the vertical displacement (which is the height of the tower)

Since the bottle is falling vertically, the vertical displacement

s is the height of the tower from which it was thrown.

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Car A rounds a curve of 150-m radius at a constant speed of 54 km/h. At the instant represented, car B is moving at 81 km/h but is slowing down at the rate of 3m / (s ^ 2) Determine the velocity and accelera- tion of car A as observed from car B.

Answers

The velocity of the car A as observed from car B is (15i - 22.5j) m/s

The acceleration of car A as observed from car B is 4.5j m/s²

The velocity of car A and car B in m/s is equal:

VA = 54 km/h * 5/18 = 15 im/s

VB = 81 km/h * 5/18 = 22.5 jm/s

The relative velocity is:

\(v_{AB} = v_{A} - v_{B} =\) (15 i -22.5 j ) m/s

The acceleration of the cars are:

\(a_{A} = v^{2}_{A} = 15^{2} /150 =1.5 jm /s^{2}\)

The relative acceleration is:

\(a_{AB} = a_{A} - a_{B} =\) 1.5- (-3), negative - because - the - car - is- slowly - down

\(a_{AB\) = 4.5 jm/ \(s^{2}\)

The relative velocity is defined as the velocity of an object with respect to another observer. It is the time pace of change of relative position of one object with respect to another object.

The relative acceleration (also or ) is the acceleration of an object or observer B in the rest casing of another object or observer A. Acceleration of B relative to An is =ab−aa.

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Give the SI base unit of each of these quantities Enter the abbreviation rather than the name of the unit: time: mass: Kg length:m

Answers

Time: s (second)

Mass: kg (kilogram)

Length: m (meter)

What are the SI units?

The SI units (International System of Units) are a standard system of measurement used in science, engineering, and many other fields. They provide a universal language for expressing and comparing measurements. The SI units are based on seven fundamental physical quantities, and each of these quantities is associated with a specific base unit, which is defined independently of any other unit.

Seven base units of the SI system are:

Length: meter (m)

Mass: kilogram (kg)

Time: second (s)

Electric current: ampere (A)

Temperature: kelvin (K)

Amount of substance: mole (mol)

Luminous intensity: candela (cd)

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A cannonball is fired straight up at a speed of 25 m/s. What is the maximum altitude that it will reach?

Answers

Answer:

When the projectile is launched straight up, there isn't a horizontal ... The initial acceleration was 9.8 m/s2 pointing up, so the acceleration at any other point should be the same.

Explanation:

Hope it helped =)

The maximum altitude that the cannonball will reach if fired straight up at a speed of 25 m/s is; 31.86 m

According to the question;

The cannonball is fired straight up at a speed of 25 m/s

Additionally, the cannonball is fired against the force of gravity.

Consequently, the motion is in the opposite direction of the acceleration due to gravity.

From the equation of motion;

V² = U² - 2gH

At the maximum altitude, V = 0.

0² = 25² - (2× 9.81) H

19.62H = 625

H = 625/19.62

H = 31.86m

The maximum altitude that it will reach is;

H = 31.86m

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Would it be easier to pull the tablecloth out from under a glass of water or an
empty paper cup (leaving the cup or glass in place)? Explain why.

Answers

Glass as it is heavier and by newtons first law and inertia the greater the mass = more inertia(resistance to chabge in motion) thus the glass has a greater mass than an empty paper cup and thus has greater inertia. So it would be easier to leave it in place

The gravitational field at the Moon in N/kg due to the Earth is approximately (G = 6.67 × 10-11 N m2/kg2, the mass of the Earth is 5.98 × 1024 kg, and the distance to the Moon is 3.85 × 108 m)

Answers

Answer:

F = 2.69 10⁻³ m   [ N]

Explanation:

This exercise asks to calculate the gravitational field of the Earth on the lunar surface, let's use the universal gravitation law

          F = G m M / r²

where m is the mass of the body, M the mass of the Earth and r the distance between the Earth and the Moon

         F = (G M / r²) m

         F = (6.67 10⁻¹¹ 5.98 10²⁴ / (3.85 10⁸)² ) m

         F = 2.69 10⁻³ m   [ N]

This force is directed from the Moon towards the Earth, therefore it reduces the weight of the body

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