When an object is placed in front
of a convex lens, it creates a virtual
image at -12.8 cm with a
magnification of 2.85. What is the
focal length of the lens?

Answer:

v₃ = 1.25[m/s]

Explanation:

In order to solve this problem, we must use the principle of conservation of the amount of movement and momentum.

That is, the amount of movement is preserved before and after the collision. Let's propose an equation, in which the elements to the left of the equal sign represent the moment before the collision and to the right the moment after the collision.

\(P=m*v\)

P = lineal momentum [kg*m/s]

m = mass [kg]

v = velocity [m/s]

\((m_{1}*v_{1})+(m_{2}*v_{2})=(m_{1}+m_{2})*v_{3}\)

m₁ = mass of the first railroad = 2096 [kg]

m₂ = mass of the second railroad = 6280 [kg]

v₁ = velocity of the first railroad before the collision = 5 [m/s]

v₂ = velocity of the second railroad before the collision = 0 (initially at rest)

v₃ = velocity of the group after the collision [m/s]

Now replacing:

\((2096*5)+(6280*0)=(2096+6280)*v_{3}\\10480=8376*v_{3}\\v_{3}=1.25[m/s]\)

Given:

Speed of sound, v = 344 m/s

Low frequency, fl = 30 Hz.

High frequency, fh = 25 kHz.

Let's find the audible range of sound spectrum.

The range of sound can be said to be the wavelength.

To find the wavelength, apply the formula:

Where:

• λ is the wavelength in meters (m).

• v is the speed in meters per second (m/s)

• f is the frequency (Hz.)

• To find the largest wavelength, we have:

• To find the smallest wavelength, we have:

Therefore, we have:

Smallest value: 0.014 m

Largest value: 11.47 m

ANSWER:

• Smallest value: , 0.014 m

• Largest value: , 11.47 m

Answer:(vi^2+d)^2=vf+a^2+2t

Explanation:

Answer:  

Between 18 months and 2 years

THiS is THE CORRECT ANSWER!

Explanation:

Middle toddlers start using words to express meaning and might say “mama” to get their mother’s attention or “baba” to signal for a bottle. At this age, children learn new words weekly or even daily.

The answer "between 12 and 18 months" is INCORRECT!!!

Between 12 and 18 months

Young toddlers start making word-like sounds, such as “mama,” “dada,” and “baba.” They seem to enjoy making these sounds and repeat them over and over again. But they do not yet use the sounds to express meaning.

The velocity of ball B after impact would be2.7147 i + 2.6987 j ft/s

To solve this problem, we can use the conservation of momentum and energy.

First, let's find the momentum of ball A before the collision. The momentum is given by:

p = mv

The mass of each ball is the same, so we can write:

p_A = mV_A

where V_A is the velocity vector of ball A.

We can break V_A into its x and y components as follows:

V_Ax = V_A cos(θ)

V_Ay = V_A sin(θ)

where θ is the angle between the velocity vector and the x-axis.

Substituting in the given values, we get:

V_Ax = 3 cos(70°) = 0.9063 ft/s

V_Ay = 3 sin(70°) = 2.8830 ft/s

So, the momentum of ball A before the collision is:

p_A = mV_A = m (V_Ax i + V_Ay j) = m (0.9063 i + 2.8830 j) lb·ft/s

Next, we need to find the velocity of ball A after the collision. We can use conservation of momentum and energy to do this.

p_A + p_B = p_A' + p_B'

where p_B is the momentum of ball B before the collision, and p_A', p_B' are their respective momenta after the collision.

Since ball B is initially at rest, its momentum before the collision is zero:

p_B = 0

Conservation of energy tells us that the total kinetic energy of the system before the collision is equal to the total kinetic energy of the system after the collision:

1/2 m V_A^2 = 1/2 m V_A'^2 + 1/2 m V_B'^2

where V_A' and V_B' are the velocities of the balls after the collision.

We can use the coefficient of restitution (e) to relate the velocities of the balls before and after the collision:

e = (V_B' - V_A') / (V_A - V_B)

Substituting in the given values, we get:

e = (V_B' - V_A') / (3 - 0)

Solving for V_B', we get:

V_B' = e (V_A - V_B) + V_A'

Substituting in the known values, we get:

V_A' = (0.9063 i + 2.8830 j) ft/s

e = 0.9

Solving for V_B', we get:

V_B' = e (V_A - V_B) + V_A'

= 0.9 (3 i + 0 j) + (0.9063 i + 2.8830 j)

= 2.7147 i + 2.6987 j ft/s

So, the velocity of ball B after the collision is:

V_B' = 2.7147 i + 2.6987 j ft/s

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Newton's second law allows us to find the results for the tension of the rope and the angular acceleration of the body are  

      a) The angular acceleration is α = 26.7 rad / s²

      b) The tension of the rope T = 2.67 N

Given parameters

To find

Newton's second law indicates that the net force is proportional to the product of the mass and the acceleration of the bodies

          ∑ F = m a

Where the bold letters indicate vectors, F is the external forces, m the mass and the acceleration of the body

A free body diagram is a diagram of the forces without the details of the bodies, in the attached we see a free body diagram of the system

Let's apply Newton's second law to the block

                     W - T = m a

Body weight is

                     W = mg

Let's substitute

                    mg - T = ma                  (1)

The pulley is a body that is in rotational motion so we use Newton's second law for rotation

           Σ τ = I α  

Where τ is the torque, I the moment of inertia and α the angular acceleration

In this case the reference system is located at the turning point  

            T R = I α

            T = \(\frac{I \alpha }{R}\)  

Linear and angular variables are related

            a = α R

We substitute in equation 1 and write the system of equations

            mg - T = m α R

                    T = \(\frac{I \alpha }{R}\)

We resolve

              mg = α  (m R + I / R)

             α = \(\frac{g}{R + \frac{I}{mR} }\)  

We calculate

            α = \(\frac{ 9.8}{ 0.30+\frac{0.030}{1.50 \ 0.30} }\)  

            α = 26.7 rad / s²

Let's calculate the tension of the rope

           T = \(\frac{I \alpha }{R}\)  

           T = \(\frac{0.030 \ 26.7 }{0.30}\)

           T = 2.67 N

In conclusion with Newton's second law we can find the results for the tension of the rope and the angular acceleration of the body are  

      a) The angular acceleration is alpha = 26.7 rad / s²

      b) The tension of the rope T = 2.67 N

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Answer:

The answer is magma

Explanation:

I'm 99.99% this is right

Answer: its magnetic reversal

Explanation: jus took the test make brainly

Maximum weight that can be suspended from the copper wire without permanently deforming it is approximately 171.5 kg.

Maximum load that a material can support without fracture when being stretched, divided by original cross-sectional area of the material is called tensile strength.

Given radius 1.16 mm, so, diameter is 2 × 1.16 mm = 2.32 mm.

A = πr² = π(1.16 mm)² = 4.21 × 10⁻⁶ m²

Tensile strength of copper is given as 400 MPa, or 400 × 10⁶ Pa:

Fmax = A × σmax = 4.21 × 10⁻⁶ m² × 400 × 10⁶ Pa = 1684 N

F = mg

F is force, m is mass of the object being suspended, and g is acceleration due to gravity (9.81 m/s^2).

m = F/g = 1684 N/9.81 m/s² = 171.5 kg

Therefore, the maximum weight that can be suspended from the copper wire without permanently deforming it is approximately 171.5 kg.

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The magnitude of the resultant vector to round the answer to the nearest tenth, we look at the digit in the hundredth's place. If this digit is 5 or greater, we round up. If it is less than 5, we round down.

In the study of physics, we use vectors to represent quantities that have both direction and magnitude. It is often the case that we want to add two or more vectors together to obtain a single vector that represents the net result of these additions. The process of adding two or more vectors together is known as vector addition.The magnitude of the resultant vector is the length of the line that represents it on a scale drawing.

When we add two or more vectors together, the resultant vector is the vector that represents the net result of these additions. To find the magnitude of the resultant vector, we use the Pythagorean theorem, which states that the square of the hypotenuse of a right triangle is equal to the sum of the squares of the other two sides.

In the case of vector addition, the hypotenuse is the resultant vector, and the other two sides are the component vectors. If we have two vectors a and b, the magnitude of the resultant vector is given by the following equation:|R| = √(ax2 + bx2)where R is the resultant vector, a and b are the component vectors, and x is the angle between the vectors.

For example, if the answer is 12.345, we would round it to 12.3.

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It will take the boat 47.35 seconds to get to the dock on the northern shore.

The velocity of an object in relation to another object or observer is defined as relative velocity. The time rate of change of one object's relative position with respect to another object is defined as relative velocity.

We can start by using vector addition to find the velocity of the boat relative to the shore.

The velocity of the boat relative to the water is 6.50 m/s, and the velocity of the water relative to the shore is 4.00 m/s,

Let the boat's relative velocity to shore is v(bs)

water relative velocity  to shore is v(ws)

boat's relative velocity to water is v(bw)

So: v(bs) = √(v(bw)² + v(ws)² - 2 × v(bw) × v(ws) × cos(57.0°))

Plugging in the known values, we get:

v(bs) = √(6.50² + 4.00² - 2 × 6.50 × 4.00 × cos(57.0°)) = 5.47 m/s

Next, we can use this velocity to find the time it takes for the boat to cross the river:

t = d / v(bs) = 259.0 m / 7.76 m/s = 47.35 s

Thus, it will take the boat 47.35 seconds.

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Answer:

F=w=ma                                                                                                                                                       OR by using equations of motions                                                                               vf=vi-at                    : a=vf-vi/t                                                              eq 1                         s=vit+1/2at squre                                                                                 eq 2                     2as=vf squre - vi squre                                                                        eq 3                                                                                                                                                                                  

Explanation:

where m is the mass of falling body , f is the weight is the force acting down ward , vf is the final velocity, vi is the inetial velocity , t is the time and s is the distance covered by a body.

Answer: Option (b) is the correct answer.

Explanation:

The energy present within the molecules of an object is known as thermal energy.

When an object is warmed then its molecules gain more kinetic energy and results in more number of collisions. Then they release extra energy in the form of heat into the atmosphere.

And when a cool object is placed adjacent to a warmer object then heat transfers from warm object to cool object.

Thus, we can conclude that thermal energy moves from warmer objects to cooler objects.

Answer: the slope of the cars position-time graph

Explanation:

Just took the test

For this circuit, the voltage is 4.2 V. then power given is 0.9 W and receiving across 55Ω resistance is 0.07 W and that of 30Ω resistance is 0.14 W. Resistor are connected in parallel, its equvalent resistance is R₁R₂/R₁+R₂.

Both resistor are connected in parallel hence their equivalent resistance in parallel combination is given as,

R = 55*30/(55+30)

R = 19.4 Ω

Power given to the circuit is,

P = V²/R = 4.2/19.4 = 0.9 W

Receiving power taken from 55Ω resistor

P = V²/R = 4.2/55 = 0.07 W

Receiving power taken from 30Ω resistor

P = V²/R = 4.2/30 = 0.14 W

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Answer:

1.8 ms to the left

Explanation:

Answer:1.8 ms to the left

Explanation:

Answer:

because of moon  

Explanation:

Waves can travel through the air, granite rock, water, sandstone, and mudstone. Waves can also travel through molten magma, but only in certain conditions.

In physics, a wave is a disturbance that travels through space and time, usually accompanied by the transfer of energy. Waves can be characterized by their amplitude, wavelength, frequency, and speed.

Here,

Waves can travel through the air, granite rock, water, sandstone, and mudstone. Waves can also travel through molten magma, but only in certain conditions.

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Answer:

mass =22.4kg

force=83.1N

a=?

f=ma

a=f/m

a=83.1/22.4

a=3.70m/s^2

After 42 minutes, there are 203 x \(10^{20\) atoms remaining of the radioactive substance.

To determine the number of atoms remaining after a certain amount of time has passed, we can use the formula for radioactive decay:

N(t) = N0 * \((1/2)^{(t / T)\),

where:

N(t) = number of atoms remaining at time t,

N0 = initial number of atoms (812 x  \(10^{20\) atoms),

T = half-life of the substance (21 minutes), and

t = time that has passed.

Let's calculate the number of atoms remaining after a given time.

Suppose the time passed is t = 42 minutes (twice the half-life).

N(t) = 812 x  \(10^{20\) * \((1/2)^{(42 / 21)\)

N(t) = 812 x  \(10^{20\) * \((1/2)^2\)

N(t) = 812 x  \(10^{20\) * 1/4

N(t) = 203 x  \(10^{20\) atoms.

So, after 42 minutes, there are approximately 203 x \(10^{20\) atoms remaining of the radioactive substance.

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The resistance indicated by the platinum thermometer at 200°C is 1.648 times the reference resistance Ro at 0°C.

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An electric iron is marked 120 volts and 500 Watts. The units consumed by it in using it for 24 hours can be calculated using the formula:Power (in watts) = Voltage (in volts) x Current (in amperes)P = V x I

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According to the statement, on latitude (l) and mean temperatures in February, the least squares linear regression model calculated for these data was:

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Answer:

\(v_{1} = 19 m/s\)

Explanation:

\(v_{1} = \frac{(v_{2} + u)}{2}\), where \(v_1\) = avg. velocity, \(v_2\) = final velocity, and \(u\) = initial velocity.

The provided remark indicates that option (B) is the appropriate choice.

When two consecutive lines or beams intersect at a single terminus, an angle is created. The apex of an arc is the location where two points come together. The Latin term "angulus," which means "corner," is where the word "angle" originates.

A vector field is a measure for angles that are determined by the arc length to radius relation of a circular. The angle at which that fraction equals one is called a radian (see the first diagram). For example, 180 degrees are equal to PI radians, 360 ° are equal to 2*PI radians, and so on.

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The given scenario describes an experiment involving an electroscope, a glass bottle, a cardboard lid, a bolt or nail, a light wire, and an aluminum foil strip.

The purpose of the experiment is to demonstrate the behavior of electrons and their effect on the electroscope. Initially, when the electroscope is neutral, it means that there are equal numbers of protons and electrons on the foil leaves, causing them to hang down straight. The glass bottle and the cardboard lid act as insulators, preventing the rapid escape of electrons and maintaining equilibrium.

When the head of the bolt is touched with a plastic ruler that has been rubbed with fur or wool, the ruler gains excess electrons due to the process of friction. These excess electrons are transferred to the bolt since metal is a good conductor. The electrons then move down the bolt and accumulate on the foil leaves.

As the foil receives the additional electrons, the repulsive force between the like charges (electrons) causes the foil leaves to separate or fly apart from one another. This is a result of the electrostatic repulsion between the negatively charged leaves.

The purpose of using the glass bottle is to provide a protective barrier against air currents that could interfere with the experiment. It also allows observation of the behavior of the foil leaves as they move apart, indicating the presence of excess electrons.

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The time interval between the man clapping and hearing his echo is approximately 1.75 seconds.

An echo is a repetition or reflection of a sound or signal. It can be caused by sound waves bouncing off a surface, signal interference, or the repetition of a message in communication.

The speed of sound in air at room temperature is approximately 343 meters per second. When a person claps, the sound waves propagate outward in all directions and reach the school building, where they bounce off and return to the person as an echo. The time it takes for the sound to travel the distance to the building and back to the person is the time interval between the clap and the echo.

To calculate the time interval, we can use the following formula:

time = distance / speed

where distance is the total distance traveled by the sound (twice the distance from the person to the school building), and speed is the speed of sound in air.

distance = 2 x 300m = 600m

speed = 343 m/s

time = 600m / 343 m/s = 1.75 seconds (rounded to two decimal places)

Therefore, the time interval between the man clapping and hearing his echo is approximately 1.75 seconds.

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Answer:

The speed of a wave is equal to the wavelength divided by the period. The wavelength is the distance between two consecutive nodes, and the period is the time it takes for one complete cycle of the wave.

In this case, the wavelength is 6 m and the period is 0.2 s. Therefore, the speed of the wave is 30 m/s.

The answer is 30 m/s.

Explanation: