Answer:
D) 19.8 lbs
Explanation:
1kg in household measurement is equal to 35.274 ounces. 35.274*9=317.466 ounces.
1kg is also equal to 2.205 lbs. 9*2.205=19.8416
9 kg is also equal to 9000 grams, but grams are not a part of the household measurement system
a) 9000 grams. b) 9000 ounces. c) 19.8 ounces. d) 19.8 pounds.
This leaves us with 19.8 lbs
The wiring in a house must be thick enough so it does not become so hot as to start a fire.part aWhat diameter must a copper wire be if it is to carry a maximum current of 34 A and produce no more than 1.6 W of heat per meter of length?
Given:
The maximum current in the circuit is,
\(i=34\text{ A}\)The power per length is,
\(\frac{P}{l}=1.6\text{ W/m}\)To find:
The diameter of the copper wire
Explanation:
The power (P) produced by current i, through a copper wire of resistance R and length l is given by,
\(\begin{gathered} Pl=i^2R \\ \frac{R}{l}=\frac{P}{i^2} \\ \frac{R}{l}=\frac{1.6}{34\times34} \end{gathered}\)Now,
\(\begin{gathered} R=\frac{\rho l}{A} \\ R=\frac{\rho l}{\pi r^2} \end{gathered}\)The resistivity of copper is,
\(\rho=1.72\times10^{-8}\text{ ohm.m}\)So, we can write,
\(\begin{gathered} \frac{R}{l}=\frac{\rho}{\pi r^2} \\ \frac{1.6}{34\times34}=\frac{1.72\times10^{-8}}{\pi r^2} \\ r^2=\frac{1.72\times10^{-8}\times34\times34}{1.6} \\ r=3.5\times10^{-3}\text{ m} \\ diamer\text{ is,} \\ 2r=7.0\times10^{-3}\text{ m} \end{gathered}\)Hence, the diameter is,
\(7.0\times10^{-3}\text{ m}\)Calculate the energy in electron volts of (a) an electron that has de Broglie wavelength 400 nm and (b) a photon that has wave. length 400 nm
Answer:
(a) To calculate the energy in electron volts of an electron with a de Broglie wavelength of 400 nm, we can use the de Broglie wavelength equation:
λ = h / p
where λ is the de Broglie wavelength, h is Planck's constant (6.626 x 10^-34 J s), and p is the momentum of the particle. We can rearrange this equation to solve for the momentum:
p = h / λ
Plugging in the given de Broglie wavelength, we get:
p = (6.626 x 10^-34 J s) / (400 x 10^-9 m)
= 1.6565 x 10^-24 kg m/s
To calculate the kinetic energy of the electron, we can use the formula:
KE = p^2 / (2m)
where m is the mass of the electron (9.109 x 10^-31 kg). Plugging in the momentum we just calculated, we get:
KE = (1.6565 x 10^-24 kg m/s)^2 / (2 x 9.109 x 10^-31 kg)
= 1.423 x 10^-17 J
Finally, we can convert this energy from joules to electron volts (eV) using the conversion factor 1 eV = 1.602 x 10^-19 J:
KE = 1.423 x 10^-17 J / (1.602 x 10^-19 J/eV)
= 88.8 eV
Therefore, the energy in electron volts of an electron with a de Broglie wavelength of 400 nm is 88.8 eV.
(b) To calculate the energy in electron volts of a photon with a wavelength of 400 nm, we can use the formula:
E = hc / λ
where E is the energy of the photon, h is Planck's constant, c is the speed of light (299,792,458 m/s), and λ is the wavelength of the photon. Plugging in the given wavelength, we get:
E = (6.626 x 10^-34 J s) x (299,792,458 m/s) / (400 x 10^-9 m)
= 4.965 x 10^-19 J
Finally, we can convert this energy from joules to electron volts using the conversion factor 1 eV = 1.602 x 10^-19 J:
E = 4.965 x 10^-19 J / (1.602 x 10^-19 J/eV)
= 3.10 eV
Therefore, the energy in electron volts of a photon with a wavelength of 400 nm is 3.10 eV.
Explanation:
How does the lens from which you view the world shape your approach to research inquiry?
Why is it important as a scholar-practitioner engaged in research to acknowledge your worldview ?
LEARNING RESOURCES Required Readings
Babbie, E. (2017). Basics of social research (7th ed.). Boston, MA: Cengage Learning.
Chapter 1, “Human Inquiry and Science”
Burkholder, G. J., Cox, K. A., Crawford, L. M., & Hitchcock, J. H. (Eds.). (2020). Research designs and methods: An applied guide for the scholar-practitioner. Thousand Oaks, CA: Sage.
Chapter 1, "Introduction to Research"
Chapter 2, “Philosophical Foundations and the Role of Theory in Research”
Acknowledging one's worldview as a scholar-practitioner is crucial as it influences research inquiry. It shapes research questions, methods, and interpretations. Recognizing biases and being open to diverse perspectives ensures reliable and valid research.
As a scholar-practitioner engaged in research, it is important to acknowledge your worldview because your worldview affects the approach you take to research inquiry. It shapes your research questions, methods, and interpretations. The lens through which you view the world is informed by your background, culture, experiences, and beliefs. Therefore, two scholars may approach the same research question differently based on their worldviews. For instance, a scholar from an individualistic culture may approach a research question on teamwork differently from a scholar from a collectivistic culture. The individualistic scholar may focus on the individual's contribution to the team, while the collectivistic scholar may focus on the team's contribution to the individual.To conduct research that is reliable and valid, it is crucial for the scholar-practitioner to acknowledge their worldview and recognize that it shapes their approach to research inquiry. By acknowledging their worldview, the scholar-practitioner can identify and manage their biases and take steps to minimize them. They can also be open to multiple perspectives and incorporate them into their research to enhance its credibility. In conclusion, acknowledging your worldview as a scholar-practitioner is essential for conducting research that is reliable and valid. It helps you identify and manage your biases and be open to multiple perspectives.For more questions on interpretations
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1- Show that the equation d=vt2
dimensionally correct or not?
Is the answer clockwise (CW) or counter clockwise (CCW) ?
Why do you think the pylon in Figure 24 is designed the way it is, and not in the way shown in Figure 25?
They are specifically made tο be ideal fοr cοnducting live electrical lines because οf their electrical insulatiοn and mechanical tοughness. A structure called an electric pylοn οf hοt-rοlled steel bevels οr gusset plates.
What kinds οf patterns are used tο create electrical pylοns?Other materials, such as cοncrete and wοοd, may alsο be utilised in additiοn tο steel. Transmissiοn tοwers can be divided intο fοur main categοries: suspensiοn, terminal, tensiοn, οr transpοsitiοn.
Whο was the electrical pylοn's designer?This Central Electricity Bοard held a cοmpetitiοn in 1927, and the winning entry was chοsen by the classical designer Sir Reginald Blοοmfield. He settled οn an A-frame structure with latticewοrk that was οffered by the American cοmpany Milliken Brοthers and is still in use tοday.
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Complete question:
In the United States, household electric power is provided at a frequency of 60 HzHz, so electromagnetic radiation at that frequency is of particular interest. On the basis of the ICNIRP guidelines, what is the maximum intensity of an electromagnetic wave at this frequency to which the general public should be exposed
Answer:
the maximum intensity of an electromagnetic wave at the given frequency is 45 kW/m²
Explanation:
Given the data in the question;
To determine the maximum intensity of an electromagnetic wave, we use the formula;
\(I\) = \(\frac{1}{2}\)ε₀cE\(_{max\)²
where ε₀ is permittivity of free space ( 8.85 × 10⁻¹² C²/N.m² )
c is the speed of light ( 3 × 10⁸ m/s )
E\(_{max\) is the maximum magnitude of the electric field
first we calculate the maximum magnitude of the electric field ( E\(_{max\) )
E\(_{max\) = 350/f kV/m
given that frequency of 60 Hz, we substitute
E\(_{max\) = 350/60 kV/m
E\(_{max\) = 5.83333 kV/m
E\(_{max\) = 5.83333 kV/m × ( \(\frac{1000 V/m}{1 kV/m}\) )
E\(_{max\) = 5833.33 N/C
so we substitute all our values into the formula for intensity of an electromagnetic wave;
\(I\) = \(\frac{1}{2}\)ε₀cE\(_{max\)²
\(I\) = \(\frac{1}{2}\) × ( 8.85 × 10⁻¹² C²/N.m² ) × ( 3 × 10⁸ m/s ) × ( 5833.33 N/C )²
\(I\) = 45 × 10³ W/m²
\(I\) = 45 × 10³ W/m² × ( \(\frac{1 kW/m^2}{10^3W/m^2}\) )
\(I\) = 45 kW/m²
Therefore, the maximum intensity of an electromagnetic wave at the given frequency is 45 kW/m²
Captain Picard beams down to a previously unexplored planet. The planet has four times the mass of Earth, and twice the radius. If the force of gravity on the surface of Earth is represented by "g," what is the force of gravity on the surface of the new planet?
A. g
B. 2g
C. 4g
D. 8g
The force of gravity on the surface of the new planet is g
Option A is correct
The force of gravity on the surface of the new planetForce of gravity: the force of gravity speaks to the force that acts on every body that exists under a given space or planet.
The force of gravity acts on masses to create weight.
W=mg
Generally the equation for the Force of gravity is mathematically given as
\(g=\frac{Gme}{Re^2}\\\\Therefore\\\\g'=\frac{G*4Me}{2Re^2}\\\\g=4/4\frac{GMe}{Re^2}\\\\\)
g=1g
Therefore, the force of gravity on the surface of the new planet is g
Option A is correct
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A circle loop of radius 2 m is positioned in a uniform magnetic field of magnitude 1.5 N/C so that the plane of the loop makes an angle of 65° with the magnetic field. Find the flux passing through the circle loop.
The flux through the circle loop of wire is determined as 7.96 N/C.m².
What is the flux passing through the circle loop?The flux through the circle loop of wire is calculated by applying the following formula.
Ф = EA cosθ
where;
B is the magnitude of the electric fieldA is the area of the circular loopθ is the direction of the loopThe area of the wire is calculated as follows;
A = πr²
A = π (2 m)²
A = 12.57 m²
The flux through the circle loop of wire is calculated as;
Ф = EA cosθ
Ф = 1.5 x 12.57 x cos (65)
Ф = 7.96 N/C.m²
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I need helpp! This is urgent tomorrow is the duedate
Answer:
The Force that resists the motion of one object moving relative to another is Friction. Kinetic Friction Resists the motion of Moving objects, while Static friction keeps the objects from moving.
find the rms speed of a sample of oxygen at 30° C and having a molar mass of 16 g/mol.
At 30°C, the rms speed of a sample of oxygen with a molar mass of 16 g/mol is approximately 482.34 m/s.
The root mean square (rms) speed of a gas molecule is a measure of the average speed of the gas particles in a sample. It can be calculated using the formula:
vrms = √(3kT/m)
Where:
vrms is the rms speed
k is the Boltzmann constant (1.38 x 10^-23 J/K)
T is the temperature in Kelvin
m is the molar mass of the gas in kilograms
To calculate the rms speed of oxygen at 30°C (303 Kelvin) with a molar mass of 16 g/mol, we need to convert the molar mass to kilograms by dividing it by 1000:
m = 16 g/mol = 0.016 kg/mol
Substituting the values into the formula, we have:
vrms = √((3 * 1.38 x 10^-23 J/K * 303 K) / (0.016 kg/mol))
Calculating this expression yields the rms speed of the oxygen sample:
vrms ≈ 482.34 m/s
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Hi please help on question! . If answer is correct I'll rate you five stars a thanks and maybe even brainliest! You will even get 54 pts!!
Here is a function machine.
Input : multiply by 6. Subtract 80: output
The input is the same as the output. Find the input.
Also can you please show me an easy to work out these type of questions
Answer:
Explanation:
Sure, I'd be happy to help you with the question!
Let's denote the input as x. According to the function machine, the input is multiplied by 6 and then 80 is subtracted from the result to obtain the output.
So, the function can be written as:
Output = (6 * x) - 80
Now, the problem states that the input is the same as the output. Therefore, we can set up the equation:
x = (6 * x) - 80
Let's solve this equation to find the value of x:
x = 6x - 80
Subtracting 6x from both sides, we get:
x - 6x = -80
Combining like terms, we have:
-5x = -80
Dividing both sides by -5, we find:
x = (-80) / (-5)
Simplifying the expression, we have:
x = 16
Therefore, the input (x) that results in the input being the same as the output is 16.
To work out these types of questions, it's important to carefully read the instructions and understand the operations being performed in the function machine. Then, you can set up an equation with the input and output, and solve for the unknown value. Always double-check your solution to ensure it satisfies the given conditions of the problem.
Answer:
16
Explanation:
(x*6) - 80 = x
Multiply the parentheses
6x - 80 = x
Add 80 to each side to get
6x = x + 80
Subtract x from both sides to get
5x = 80
Divide both sides by 5
x = 16
The half-life of a radioactive isotope is 210 d. How many days would it take for the decay rate of a sample of this isotope to fall to 0.58 of its initial rate?
It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.
2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.
3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.
4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.
5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.
6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".
7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).
8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).
9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.
10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.
11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).
12. Evaluating the expression, we find: t ≈ 546.
13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
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Help me please
What is the shape of the velocity vs time graph for an object going at constant speed?
A- A curve that rises gradually to the right
B- A curve that decreases gradually to the right
C- A straight line that rises gradually to the right
D- A strait line that decreases gradually to the right
E- A straight line that is level and neither increases or decreases going to the right
Answer: a or b can u pls give me brainlest
Explanation:A straight line is a curve with constant slope. Since slope is acceleration on a velocity-time graph, each of the objects represented on this graph is moving with a constant acceleration.
8. An airplane of mass 8500 kg dives has an altitude of 15,000 m. It then dives steeply to an
altitude of 11,000 m. What was the change in potential energy?
Answer:
333.5 MJ
Explanation:
ΔV = m·g·Δh
= 8500 · 9.81 · (15000-11000)
= 8500 · 9.81 · 4000
= 333 540 000
≈ 333.5 ·10⁶J = 333.5 MJ
The change in potential energy is 333.5 MJ
What is Potential Energy?
Potential energy is defined as the energy possessed by an object because of its position relative to other objects, tension within itself, its electric charge, or other factors. Any object that is raised above its rest position has energy stored in it, so it is called potential energy because it has the potential to do work when released.
It can be expressed as:
P.E.= mgh
where, m is the mass of an object measured in grams 'g'
g is the acceleration due to gravity which is \(9.8 m/s^2\)
h is the height measured in meter 'm'
Here,
the given information is
m= 8500kg
Δh= \(h_2 - h_1\) = 15000-11000 = 4,000m
So, P.E. = 850 x 9.8 x 4000 = 333 540 000= 333.5 ·10⁶J = 333.5 MJ
Thus, the change in potential energy is 333.5 MJ
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A 10 KVA, 380 V, 50 Hz, 3-phas, star-connected salient pole alternator has direct axis and quadrature axis reactances of 12 ohms and 8 ohms respectively. The armature has resistance of 1 ohin per phase, The generator delivers rated load at 0.8 p,f lagging with the terminal voltage being maintained at rated value. If the load angle is 16.15, determine (i) the direct axis and quadrature axis components of armature current, (b) excitation voltage of the generator.
Direct axis and quadrature axis components of armature current are 30.28 A and 46.92 A respectively, and the excitation voltage of the generator is 765.36 V.
Given:
Apparent power (S) = 10 KVA = 10,000 VA
Line voltage (V) = 380 V
Frequency (f) = 50 Hz
Xd = 12 ohms
Xq = 8 ohms
Ra = 1 ohm
Power factor (pf) = 0.8 lagging
Load angle (δ) = 16.15 degrees
(i) Armature current's direct axis and quadrature axis components
We know that the apparent power is given by S = 3VLILcos(φ), where VL is the line voltage, IL is the line current, and φ is the angle between them. For a star-connected alternator, line voltage is equal to phase voltage, so we can write:
S = 3Vphase Iphase cos(φ)
Iphase = S / (3Vphase cos(φ))
For a lagging power factor, cos(φ) = 0.8, so
Iphase = 10,000 / (3 x 380 x 0.8) = 10.46 A
The direct axis component (Id) and the quadrature axis component (Iq) make up the armature current. Using the given values of Xd, Xq, and Ra, we can calculate these components as follows:
Id = (VL - IaRa) / Xd
Iq = (VL - IaRa) / Xq
where Ia is the magnitude of the armature current, which is equal to the magnitude of the line current divided by √3. Thus,
Ia = Iphase / √3 = 10.46 / √3 = 6.03 A
Substituting the given values:
Id = (380 - 6.03 x 1) / 12 = 30.28 A
Iq = (380 - 6.03 x 1) / 8 = 46.92 A
(ii) Excitation voltage of the generator:
The excitation voltage (E) of the generator is given by:
E = Vphase + IqXq
Substituting the given values:
E = 380 + 46.92 x 8 = 765.36 V
Therefore, the direct axis and quadrature axis components of armature current are 30.28 A and 46.92 A respectively, and the excitation voltage of the generator is 765.36 V.
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the radiation that is least damaging to humans is
The radiation that is least damaging to humans is non-ionizing radiation.
What is non ionizing radiationNon-ionizing radiation refers to the type of radiation that does not have enough energy to remove tightly bound electrons from atoms or molecules, thus not causing significant damage to biological tissues.
Examples of non ionizing radiation include radio waves, microwaves, visible light and low energy ultraviolet (UV) radiation. while excessive exposure to any form of radiation can have adverse effects, non-ionizing radiation is generally considered to be less harmful compared to ionizing radiation, which includes X-rays and gamma rays.
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Taking care of yourself can sometimes be hard work and can even lead to feelings of
Answer:
deception
Explanation:
A bullet is shot straight up with an initial speed of 180 m/s. How long is the bullet in the air and how high does the bullet go? (neglect air resistance)
Answer:
Explanation:
Time of flight is the time taken by the bulet in air. Time of flight is expressed as T = Usinθ/g where;
U is the initial velocity = 180m/s
θ is the angle of launch = 90° (Since the bullet is shot upwards)
g is the acceleration due to gravity = 9.81m/s²
T = 180sin90/9.81
T = 180/9.81
T = 18.35s
Hence the bullet will spend 18.35s in air
The height covered by the bullet is the maximum height. Maximum height is expressed as;
H = u²sin²θ/2g
H = 180²sin²90/2(9.81)
H = 180/19.62
H = 9.17m
Hence the bullet will go 9.17m high
HELP PLEASE USE KINEMATIC EQUATIONS!!!
A runner accelerates from rest to their top speed in 3 seconds. If they travel 18 m in that time, how
long does it take for the runner to run the entire 100 m race?
Answer:
ans is 16.66sec time is taken by runner
Hellooooooooooopooooooo
Answer:
Hi ??? what is your question
can an object have kinetic energy if there is no motion.
No. The object has to have motion for it to have kinetic energy.
A particule accelerates uniformly from rest at 6.0m/s for 8seconds determine the magnitude of its velocity
The particle has a 48 m/s maximum velocity.
How can I calculate the speed of an object?The equation for uniformly accelerated motion, which states that an object's final velocity, v, is equal to its beginning velocity, u, plus the product of its acceleration, a, and the time taken, t, serves as the theoretical foundation
As v = u + at, this formula can be used.
Following are the procedures to determine a particle's velocity:
Use the equation v = u + at in step one, where v is the end velocity, u is the beginning velocity, an is the acceleration, and t is the duration.
Substitute the values into the formula in step 2 to complete. Here, u = 0 (since the particle is initially at rest),
a = 6 m/s2 and t = 8 s
v = 0 + (6 m/s2) × (8 s) (8 s)
v = 48 m/s
The particle's speed is therefore 48 m/s on average.
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I will mark Brainlyest for the CORRECT ANSWER in % how are apes like humans
Explanation:
Chimpanzees are genetically closest to humans, and in fact, chimpanzees share about 98.6% of our DNA. We share more of our DNA with chimpanzees than with monkeys or other groups, or even with other great apes! We also both play, have complex emotions and intelligence, and a very similar physical makeup.
(I hope that's good) :)
Explain how the energy from the sun is transferred to fossil fuel?
Answer:
Fossil fuels are energy sources that come directly from nature. First, the sun's radiant energy is stored as chemical energy in plants by photosynthesis. When the plants die, they start decaying. After many years, the plants are turned into fossil fuels.
Explanation:
Fossil fuels rely on the Sun's energy because the energy in fossil fuels came from plants and algae as they performed photosynthesis, which requires sunlight.
When sunlight strikes a plant, some of the energy is trapped through photosynthesis and is stored in chemical bonds as the plant grows.
(u should paraphrase it)
The 10/90 principle can help you take control of your situation in taking responsibility of what you can change rather than in being victim of what you cannot change. Give an example of a situation that can change for you in applying this principle.
The 10/90 principle can be a powerful tool for taking control of your situation and improving your life. By taking responsibility for what you can change and focusing on your reaction to the situation, you can make positive changes in your life and become the master of your own destiny.
The 10/90 principle refers to the idea that life is made up of 10% of what happens to you and 90% of how you respond to it. In other words, you may not be able to control what happens to you, but you can control your reaction to it. By taking responsibility for what you can change rather than being a victim of what you cannot change, you can take control of your situation and improve your life.One example of a situation where the 10/90 principle could be applied is losing a job. Losing a job can be a devastating experience, and it can be easy to feel like a victim in this situation. However, by applying the 10/90 principle, you can take control of your situation and make positive changes in your life.The first step in applying the 10/90 principle in this situation would be to take responsibility for what you can change. This could mean updating your resume, networking with others in your field, and applying for new jobs. By taking action and doing what you can to find a new job, you are taking control of your situation and improving your chances of finding a new job.
The second step would be to focus on your reaction to the situation. Instead of dwelling on the negative aspects of losing your job, try to focus on the positive aspects. This could mean using the extra time to pursue a new hobby or spend more time with family and friends. By focusing on the positive aspects of the situation, you are taking control of your reaction and improving your overall well-being.
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We intend to measure the open-loop gain (LaTeX: A_{open}A o p e n ) of an actual operational amplifier. The magnitude of LaTeX: A_{open}A o p e n is in the range of 106 V/V. However, the signal generator in measurement setup can supply minimal voltage of 1 mV, and the oscilloscope used at amplifier output can measure maximal voltage level of 10 V. Can you design a simple measurement setup using this signal generator and oscilloscope, and accurately measure the LaTeX: A_{open}A o p e n
Answer:
voltage divider, R₂ = 1000 R₁
measuring the output in the resistance R₁
Explanation:
Let's analyze the situation, in an op amp in open gain loop, the gain is maximum G = 10⁶ V / V
in this case the signal generator gives a minimum wave of 1 10⁻³ V, after passing through the amplified it becomes 10³ V which saturates the oscilloscope.
To solve this problem we must use a simple voltage divider, for this we use the fact that in a series circuit the voltage is the sum of the voltages of each element.
If we use two resistors whose relationship is
R₂ / R₁ = 10³
R₂ = 1000 R₁
When measuring the output in the resistance R₁ we have the desired divider, with a tolerance range, for the minimum output of the generator (1 10⁻³V) we have a reading of V = 1 V in the oscilloscope, for which we can use voltage up to 10V on the generator
a hydraulic lift requires a minimum effort force force of 14.4N to lift a patient of mass 82kg .How much is the effort piston area if the resistance piston has an area of 1.2m2, assuming the piston are circular
Answer:
0.022 m²
Explanation:
By Pascal's law, we have the following relationship
\(\frac{F_1}{A_1}=\frac{F_2}{A_2}\)Where F1 is the effort force, A1 is the effort piston area, F2 is the resistance force and A2 is the resistance piston area.
Since the resistance force is the weight of a patient, we get:
F2 = 82kg (9.8 m/s²) = 803.6 N
Now, we can replace F1 = 14.4 N, F2 = 803.6N, and A2 = 1.2 m²
\(\frac{14.4N}{A_1}=\frac{803.6N}{1.2m^2}\)Solving for A1, we get:
\(\begin{gathered} 14.4(1.2)=803.6(A_1) \\ 17.28=803.6A_1 \\ \frac{17.28}{803.6}=A_1 \\ 0.022=A_1 \end{gathered}\)Therefore, the area of the effort piston area should be 0.022 m²
A catcher catches a 145 g baseball traveling horizontally at 36 m/s. How large an impulse does the ball give to the catcher?
A cannonball is fired horizontally from the top of a cliff. The cannon is at height H = 55.5 m above ground level, and the ball is fired with initial horizontal speed . The projectile lands at a distance D = 140 m from the cliff. Assume that the cannon is fired at time t = 0 and that the cannonball hits the ground at time . a. What is the value of ? b. What is the y position of the cannonball at the time c. Find the initial speed of the projectile.
a) The value of t u = 140/t`b.
b) The y position of the cannonball at the time t is 55.5 mc.
c) The initial speed of the projectile is 52.4 m/s.
Given that a cannonball is fired horizontally from the top of a cliff. The cannon is at height H = 55.5 m above ground level, and the ball is fired with initial horizontal speed u. The projectile lands at a distance D = 140 m from the cliff. Assume that the cannon is fired at time t = 0 and that the cannonball hits the ground at time t.Now,We have to find the value of t, y position of the cannonball at the time t and the initial speed of the projectile.
a. To find the value of t:Here, we have to use the formula of distance
i.e.,S = ut + (1/2)gt², Where S = 140 m, u = u and g = 9.8 m/s².Hence,140 = u×t ………..(1)We know that, time taken by the cannonball to hit the ground can be calculated as,`(2H)/g`
Since the height of the cannon from the ground is 55.5m, the total height of the cannonball from the ground is
(2H) = 2 × 55.5
= 111 m`2H/g
= 111/9.8`
= 11.32653 s
From equation (1),u×t = 140u = 140/t
Therefore, `u = 140/t`b.
b)To find the y position of the cannonball at the time t:
Here, we have to use the formula of height i.e.,y = u×t – (1/2)gt²,
Where, y = height of the cannonball at time t, u = 140/t, t = time taken by the cannonball to hit the ground and g = 9.8 m/s².
We have already calculated the time taken by the cannonball to hit the ground in the previous step.`
y = 140 - (1/2) × 9.8 × t²`
On substituting the value of t as `t = 11.32653`,
we get,y = 140 - (1/2) × 9.8 × (11.32653)²= 55.5 mc.
c) To find the initial speed of the projectile:
To calculate the initial speed of the projectile, we need to use the formula of range of projectile
.i.e.,R = u²sin2θ/g
Where R = 140 m, g = 9.8 m/s², θ = 0° (horizontal)
u² = R × g/sin2θ
= 140 × 9.8/sin0°
= 2744m²/s²u
= \(\sqrt(2744m^2/s^2)\)
= 52.4 m/s
Hence, the initial speed of the projectile is 52.4 m/s.
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