When converted to a household measurement, 9 kilograms is approximately equal to a

Answer:

Explanation: POTENTIAL ENERGY is stored energy, energy ready to go. A race car at the starting line of a race, a bicycle on top of a hill, and students waiting to go home from school are all examples of potential energy.

A moving bicycle has mechanical energy. When you apply the brakes, the bicycle's mechanical energy is not destroyed. The mechanical energy is transformed into thermal energy. Friction between the brake pad of a car and the moving wheel transforms mechanical energy into thermal energy (heat).

During braking, 60% of the kinetic energy of the bicycle and rider is converted to thermal energy in the brake blocks.

Answer:

Speed: 3, 4, 5, 6. Distance: 1, 2, 3, 4, 5

Answer:

Speed: 3, 4, 5, 6. Distance: 1, 2, 3, 4, 5

Explanation:

The reduction in the potential energy of the water is approximately 7.5 J.

option 1

We can use the principle of conservation of energy to determine the reduction in potential energy of the water.

Initially, the water in vessel A has a certain amount of potential energy due to its height above the bottom of the vessel. When the water flows through the tube and reaches vessel B, its height above the bottom of vessel B is lower than that of vessel A, which means that its potential energy has decreased.

The potential energy of the water in vessel A is given by:

PE_A = mgh_A

The mass of the water in vessel A is given by:

m = density x volume

volume = A x h_A

Substituting for m and simplifying, we get:

PE_A = density x A x h_A x g

Similarly, the potential energy of the water in vessel B is:

PE_B = density x A_B x h_B x g

At equilibrium, the height of the water in the two vessels will be the same, so we can set h_A = h_B = h.

Also, since the water is in equilibrium, the pressure at the bottom of both vessels must be the same. This means that the pressure difference between the top and bottom of the water column in vessel A (due to the weight of the water) must be balanced by the pressure difference between the top and bottom of the water column in vessel B.

The pressure difference in vessel A is:

P_A = density x g x h_A

and the pressure difference in vessel B is:

P_B = density x g x h_B

Since the pressure difference must be balanced, we have:

P_A - P_B = density x g x h_A - density x g x h_B = 0

which simplifies to:

h_A = h_B x A_B / A

Substituting for h_A and h_B in the expressions for PE_A and PE_B, we get:

PE_A = density x A x h x g

PE_B = density x A_B x h x g x A / A_B

The reduction in potential energy of the water is:

ΔPE = PE_A - PE_B = density x g x h x (A - A_B x A / A_B)

which simplifies to:

ΔPE = density x g x h x (A - A_B)

Substituting the given values, we get:

ΔPE = 1000 kg/m³ x 9.8 m/s² x 0.3 m x (50 cm² - 25 cm²)

Converting the area units to m², we get:

ΔPE = 1000 kg/m³ x 9.8 m/s² x 0.3 m x (0.005 m² - 0.0025 m²)

Simplifying, we get:

ΔPE = 7.4 J

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Weight is best defined as C) the force of gravity on an object.

The distance which the sled which is weighing 32 kg and has a speed of 5.5 m/s will travel before stopping is 15.1 meters.

Friction is the force which resists the sliding or rolling of one solid object over the another object. Frictional forces, such as the one traction needed to walk without slipping, may be beneficial, however they also present a great measure of opposition to the motion of object.

In this problem, we are to utilize the kinematic equation in the form;

Vf² = Vi² + 2aD

where, Vi is the initial velocity, Vf is the final velocity, a is the acceleration and D is the distance traveled.

Given,

Mass of boy and sled (m) = 32 kg

Speed of boy and sled (Vi) = 5.5 m/s

Average force (F) = 32 N

Using the equation for Newton's Second Law of Motion with the friction force opposing the motion:

Fs = ma

a = Fs/ m

a = -32/ 32

a = -1m/s²

Plugging the values in the obtained acceleration into the kinematic equation, we get:

(0)² = (5.5)² + 2(-1)D

D = (5.5)²/ 2

D = 30.25/ 2

D = 15.1 meters

The distance which the sled will travel before stopping is 15.1 meters.

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Answer:

In a material, the magnetic behavior depends on the alignment of magnetic moments of the atoms. Magnetic moments are generated by the motion of the electrons in the atoms. When the magnetic moments of atoms in a material are aligned in a specific pattern, it creates a magnetic field which results in the material being magnetic.

In many materials, the magnetic behavior arises due to the alignment of magnetic domains, which are regions of atoms with magnetic moments aligned in the same direction. When many domains with aligned magnetic moments are present in a material, the material becomes magnetic.

The magnetic behavior of a material depends on the number of electrons and the arrangement of those electrons in the atoms. In particular, for an atom to have a magnetic moment, it must have unpaired electrons, meaning electrons that are not paired with another electron with the opposite spin. When these unpaired electrons in the atoms are aligned, they generate a magnetic moment. If all electrons are paired, there will not be a net magnetic moment, so the material will not be magnetic.

So, in summary, the magnetic behavior of a material is determined by the alignment of magnetic moments of atoms. When the magnetic moments of many atoms in a material align in the same direction, it creates a magnetic field, leading to a material being magnetic. This alignment is usually present in magnetic domains consisting of atoms with unpaired electrons.

1. The maximum height above its launch level is 1.45 m

2. The time of flight of the ball is 1.1 s

1. How do I determine the maximum height?

From the question given above, the following data were obtained:

The maximum height can be obatianed as follow:

H = u²Sine²θ / 2g

H = [5.5² × (Sine 76)²] / (2 × 9.8)

Maximum height = 1.45 m

How do I determine the time of flight?

The time of flight of the ball can be obtained as follow:

T = 2uSineθ / g

T = [2 × 5.5 × Sine 76] / 9.8

Time of flight = 1.1 s

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Answer:

The answer is below

Explanation:

We are to check if the statement is true of false. If it is false, we correct the statement.

Solution:

Acceleration is the time rate of change of velocity. It is the ratio of the change in velocity to the change in time. The acceleration can be gotten from a velocity time graph by finding the slope of the graph.

The x coordinate represent the time and the y coordinate velocity.

5) Graph A passes through the point (0, 0) and (4, 24). Therefore the acceleration (slope) is:

Acceleration = \(\frac{24-0}{4-0}=6\ m/s^2\)

This is correct.

6) Graph B is a straight line of 12 m/s. It passes through (0, 12) and (4, 12). Hence:

Acceleration = \(\frac{12-12}{4-0}=0\ m/s^2\)

This is false.

Therefore the acceleration of graph B is 0 m/s².

The name and strength of the force holding the block up is 50 N upward - Normal force.

The given parameters:

The weight of the block acting downwards due to gravity is calculated as follows;

W = mg

where;

W = 5 x 10

W = 50 N (downwards)

Since the block is at rest, an a force equal to the weight of the block must be acting upwards. This force is known as normal reaction.

Fₙ = 50 N (upwards)

Thus, the name and strength of the force holding the block up is 50 N upward - Normal force.

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The block will remain on the table because the normal force balances with the weight of the block. The correct answer is  50 N upward normal force

From the diagram shown a 5.00-kilogram block at rest on a horizontal, frictionless table. The weight of the block will act downward which will be

Weight W = mg

let g = 10 m/\(s^{2}\)

W = 5 x 10

W = 50 N

The block will also produce an equal but in opposite direction of a normal force which is equal to the weight of the block. That is,

Normal force N = 50 N

The block will remain on the table because the normal force balances with the weight of the block.    

Therefore, the correct name and strength of the force holding the block up is 50 N upward normal force.

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Answer:

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In the circuit shown in Figure, initially K

1

is closed and K

2

is open. What are the charges on each capacitor. Then K

1

was opened and K

2

was closed (order is important), What will be the charge on each capacitor now? [C=1μF]

1796057

expand

Medium

Solution

verified

Verified by Toppr

When K

2

is open and K

1

is closed the capacitors C

1

and C

2

will charge and potential develops across them i.e., V

1

and V

2

respectively which will be equal to the potential of battery 9V

∴V

1

+V

2

=9……..I

∵V=

C

q

=orVα

C

1

Or

V

2

V

1

=

C

1

C

2

V

2

V

1

=

6C

3C

3V

2

=6V

1

V

2

=2V

1

…II

From Eqns. I and II

V

1

+2V

1

=9

3V

1

=9

V

1

=3

Volt

V

2

=2×3Volt=6Volt

∴q

1

=C

1

V

1

=6C×3=18C[(from II C=1μF)

=18×1μF=18μc

q

2

=C

2

V

2

=3C×6

=3×1μF×6=18μC

So, charges on each capacitor i.e., q

1

=q

2

=18μc

When k

1

is open and k

2

is closed then charge q

2

will be distributed among

C

2

and C

3

. Let it be q

2

and q

3

∴q

2

=q

2

+q

3

As C

2

and C

3

are now in parallel combination so their potentials

remain same (V)

∴q

2

=C

2

V+C

3

V

18μC=3×1μFxV+3×1μF×V

18=6V

V=3Volt

So potential on C

2

and C

3

capacitors are 3 Volt each

q

2

′

=C

2

V−3×1μF×3Volt=9μC

q

3

=C

3

V=3×1μF×3Volt=9μC

The magnitude of force acting on the bumper is 3760 N.

It states that the Work done in moving a body is equal to the change in kinetic energy of the body

Kinetic energy = 1/2 mv²

Given is a car's bumper designed to withstand 4.32 km/h or 1.2 m/s collision with an immovable object without damage to the body of the car. The bumper cushions the shock by absorbing the force over a distance.

The cushion collapses 0.180 m while bringing 940 kg car to rest from a initial speed of 1.2 m/s

Work done = Force x displacement

As the displacement of the bumper and force acted on it is in same direction, so the work done is

W = Fxcos0° = Fx

The body is coming to rest, so, final velocity is zero. Then, change in kinetic energy will be

ΔK.E = K.Ef - K.Ei

ΔK.E = m/2 (v² - u²)

According to work energy theorem, work done is

W = Fx  = m/2 (v² - u²)

Substitute the value and calculate the force,

F  = [940 x (0² - 1.2²)] / 2x0.180

F = 3760 N

Thus, the magnitude of force is 3760 N.

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Answer:

Explanation:

Area of a circle = pi x r x r = 3.14 x 28.77 x 28.77 = 2600.33677 ~ 2600 (using 4 significant figures)

The resistance of the copper wire at 80°C is r = 5.952 ohms

Given copper cable length is 1.2 km

The area of cross section given is 5 mm^2

Thus the equation for resistivity is:

p (t) = p (0) × ( 1 + a × ( change in temperature )

p(t) = 0.02 × 10^-6 × ( 1 + 0.004 × 60 )

p (t) = 2.48 × \(10^-^8\) ohm m

r = ( p × l ) ÷ a

r = (  2.48 × \(10^-^8\) × 1200 ) ÷ 5 × \(10^-^6\)

r = 5.952 ohms

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Answer:

c

Explanation:

efficiency is measured in % hence 0.02% is smaller than 20%

Answer:

Charging by contact is when the charged object is brought near but never contacted to the object being charged

Explanation:

So, the initial altitude of the parachuter is approximately (C). 123 m.

Hi ! In this question, I will help you. In this question, you will learn about the fall time of the free fall motion. Free fall is a downward vertical motion without being preceded by an initial velocity. When moving in free fall, the following equations apply:

\( \boxed{\sf{\bold{h = \frac{1}{2} \cdot g \cdot t^2}}} \)

\( \boxed{\sf{\bold{t = \sqrt{\frac{2 \cdot h}{g}}}}} \)

\( \boxed{\sf{\bold{v = \sqrt{2 \times g \times h}}}} \)

With the following condition :

We know that :

What was asked :

Step by Step :

\( \sf{h = \frac{1}{2} \cdot g \cdot t^2} \)

\( \sf{h = \frac{1}{2} \cdot 9.81 \cdot 5^2} \)

\( \sf{h = \frac{245.25}{2}} \)

\( \boxed{\sf{h = 122.625 \: m \approx 123 \: m}} \)

So, the initial altitude of the parachuter is approximately 123 m (C.)

The altitude of the parachuter is 122.625 meters. From the given options, the closest value is 123m. The correct option is (C).

Given:

Time (t) = 5 seconds

Acceleration due to gravity (g) = 9.81 m/s²

Using the formula for free fall:

Altitude (h) = (1/2) × g × t²

Substitute the values in the above formula:

Altitude (h) = (1/2) × 9.81 × (5)²

Altitude (h) = (1/2) × 9.81  × 25

Altitude (h) = 122.625 meters

Therefore, the altitude of the parachuter is  122.625 meters. Among the given options, the closest value is 123m. The correct option is (C).

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A  0.32 kg toy mouse was on a couch that is 0.35 m high, a car picks up the mouse and puts it in a nearby bookcase that is 2.85 m high, and the car did 7.84 J of work.

The work done by the car is calculated by ΔPE = mgh ,

(here the m=mass(0.32 kg)

g = acceleration(9.8 \(m/s^2\))

h= change in height  (2.85 m - 0.35 m = 2.50 m)

ΔPE = 0.32 kg x 9.8 \(m/s^2\) x 2.50 m = 7.84 J

Hence, a 0.32 kg toy mouse was on a couch that is 0.35 m high, a car picks up the mouse and puts it in a nearby bookcase that is 2.85 m high, and the car did 7.84 J of work.

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Answer:

\(\Delta T=38.95^{\circ} C\)

Explanation:

Given that,

Heat measured, Q = 81500 J

Mass of water, m = 0.5 kg

The specific heat of water is 4,184 J/kg °C

We need to find the change in temperature. The heat measured is given by :

\(Q=mc\Delta T\)

Where

\(\Delta T\) is the change in temperature

\(\Delat T=\dfrac{Q}{mc}\\\\\Delat T=\dfrac{81500}{0.5\times 4184 }\\\\\Delta T=38.95^{\circ} C\)

So, the change in temperature is \(38.95^{\circ} C\).

Answer:

4.6 option d

Explanation:

from second Newton law of motion

F=ma

to find acceleration

a= F/m

a= 1.15/0.25

a = 4.6

The work required to move the crate vertically at a constant speed of 5.0 m is approximately 7000 Joules (J).

To determine the work required to move the crate vertically, we need to calculate the gravitational potential energy change. The work done is equal to the change in potential energy.

The formula for gravitational potential energy is given by:

Potential energy = mass * acceleration due to gravity * height

In this case, the mass of the crate is not provided, but we can use the given weight of the crate to find the mass. Weight is equal to mass multiplied by the acceleration due to gravity (W = mg).

Given:

Weight of crate (W) = 1400 N

Acceleration due to gravity (g) = 9.8 m/s^2

Vertical distance (height) = 5.0 m

First, calculate the mass of the crate:

1400 N = m * 9.8 m/s^2

m = 1400 N / 9.8 m/s^2 ≈ 143 kg

Now we can calculate the work:

Work = Potential energy = mass * g * height

Work = 143 kg * 9.8 m/s^2 * 5.0 m ≈ 7000 J

Therefore, the work required to move the crate vertically at a constant speed of 5.0 m is approximately 7000 Joules (J).

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Answer:

The answer is 5×10‐⁵

Step-by-step Explanation:

\( \alpha = \frac{l2 - l1}{l1( \beta 2 - \beta 1)} \)

let ß be ø

\( \alpha = \frac{40.05 - 40}{40(45 - 20)} \)

\( \alpha = \frac{0.05}{40 \times 25} \)

\( \alpha = \frac{0.05}{1000}\)

\( \alpha = \frac{0.05}{1000}\)\( \alpha = 5.0 \times {10}^{ - 5} \)

Answer:

oc

Explanation:

year 10 .May be this is the answer.

Answer:

what graph ??

Explanation:

To model the discovery of electromagnetic induction, Tonya should use the procedure of moving a magnet into a coil of wire in a closed circuit.

Tonya should use the procedure of moving a magnet into a coil of wire in a closed circuit.

Electromagnetic induction refers to the phenomenon of generating an electric current in a conductor by varying the magnetic field passing through it. This concept was discovered by Michael Faraday in the early 19th century. To model this discovery, Tonya needs to recreate the conditions that led to this breakthrough.

In Faraday's experiment, he observed that when a magnet is moved into or out of a coil of wire, it induces an electric current in the wire. This occurs when the magnetic field passing through the coil changes. Therefore, Tonya should use a similar setup to replicate this process.

Out of the given options, the most appropriate procedure for Tonya would be to move a magnet into a coil of wire in a closed circuit. By having a closed circuit, it means that the ends of the wire are connected to form a complete loop. When the magnet is moved into the coil, the changing magnetic field induces an electric current to flow through the wire.

This procedure demonstrates the principle of electromagnetic induction and shows how a changing magnetic field can produce an electric current. It allows Tonya to visually observe the effects of the induced current, which is essential in modeling the discovery of electromagnetic induction.

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The stones needed to be dropped from the same height. The light stone is moving quicker than the hefty stone just as it touches the ground. The light stone is taller when it is first placed than the heavy stone is.

Energy is the ability to carry out work. Potential, kinetic, thermal, electrical, chemical, nuclear, and other forms may all exist for it.

There are numerous types of energy. Examples of these include: electromagnetic energy, chemical energy, nuclear or atomic energy, mechanical energy, gravitational energy, electrical energy, sound energy, and so on. Each form can be changed or transformed into the others.

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Answer:

the nucleus is the size of an apple, approximately 5 cm of radius e, the atom has a radius of R = 5 cm 104 = 50000 cm = 50 km

Explanation:

In the Rutherford experiments it was proved that the atomic nucleus has the volume 10-4 the volume of the atom.

If we make a scale design in which the nucleus is the size of an apple, approximately 5 cm of radius e, the atom has a radius of R = 5 cm 104 = 50000 cm = 50 km

This shows that almost the entire volume of the atom is empty.

Answer:

;

Explanation:

;

Answer:

you can see the factorial as many different ways, i will only show you two

you can see  \(n!=\frac{(n+1)!}{n+1}\)

so 0! would mean that

\(0!=\frac{(0+1)!}{0+1}=\frac{1!}{1} =1/1=1\)

the other way you can see factorial is as the number of ways to order n things

let's say we have

a   b and c and we want to arrange them in all possible ways so those are

abc

acb

bac

bca

cab

cba

and no more

for just a and b

we have

ab

ba

and no more

for just a

we have only

a

for no objects we have

that way, the one that it's upward, it's a bit philosophical but i hope you understand it