The simplest method for eliminating wrinkles during deep drawing is by using a blank holder.
When deep drawing a cup and wrinkling is observed on the wall of the cup, my suggestion to improve the process would be:
1. Increase the blank holder pressure: This will help in preventing the wrinkling by applying more uniform pressure on the blank during the deep drawing process.
2. Lubricate the blank and die properly: This will reduce friction between the blank and the die, which can help in reducing the formation of wrinkles on the cup wall.
3. Optimize the punch and die radius: Adjusting the punch and die radius to be more suitable for the material being used can help in preventing wrinkles from forming.
4. Use a material with better formability: If possible, use a material that has better formability, which can reduce the chances of wrinkles forming on the cup wall during deep drawing.
5. Control the drawing speed: Adjust the drawing speed to find an optimal rate that reduces the formation of wrinkles without compromising other aspects of the process.
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Anu copied the formula =$A$3*$B$1 from cell A1 to B5. How will the formula look like in
cell B5?
(a) =$B$7*$C$5 (b) =$C$7*$B$5 (c) =$C$5*$B$7 (d) =$A$3*$B$1
Answer:
=$A$3*$B$1
Explanation:
Since cells involved in the formula are absolute row and column because of the $ sign on the row letter and column number for both, this formula will not changed when it is copied to any new location on the worksheet
Technician A says that the low level brake fluid switch on a master cylinder will turn on the brake warning light when the system is low on fluid. Technician B says that the low level switch also monitors the condition of the fluid and will activate the warning light when the brake fluid needs to be replaced. Who is correct?
Answer:
Technician A
Explanation:
The brake fluid switch or the brake switch is a sensor provided in the master cylinder monitors the brake fluid level in the vehicle. It is found inside the brake fluid reservoir. When the brake fluid level is too low, it warns the ABS by sending a signal. This device keeps us and the vehicle safe.
Thus in the context, technician A is correct.
Before installing head gaskets look for “____” labels on the head gaskets
Before installing head gaskets, you should look for "this side up" or "front" labels on the head gaskets.
What is a head gasket?A head gasket can be defined as a gasket which is fitted between the engine block and the cylinder head in an internal combustion engine, so as to seal oil passages and absorb the pressures of the combustion that occurs inside the engine.
As a general rule, you should look for "this side up" or "front" labels on the head gaskets before installing head gaskets in an internal combustion engine of a vehicle.
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The three bars are made of A-36 steel and form a pin-connected truss. If the truss is constructed whenT1=50∘F, determine the vertical displacement of jointAwhenT2=150∘F. Each bar has a cross-sectional area of 2 in2
To determine the vertical displacement of joint A, we can use the formula for thermal expansion:
ΔL = αLΔT
where ΔL is the change in length of the bar, α is the coefficient of thermal expansion, L is the original length of the bar, and ΔT is the change in temperature.
Assuming that the bars are initially at room temperature (T1=50∘F), we can calculate the original length of each bar using the formula:
L = √(h^2 + w^2)
where h and w are the height and width of the truss, respectively. From the diagram, we can see that h = 20 ft and w = 30 ft, so:
L = √(20^2 + 30^2) = 36.06 ft
Next, we can calculate the change in temperature as:
ΔT = T2 - T1 = 150 - 50 = 100 °F
The coefficient of thermal expansion for steel is α = 6.5 × 10^-6 in/in/°F. We need to convert the length of each bar from feet to inches, so:
L = 36.06 ft × 12 in/ft = 432.72 in
Using the formula for ΔL, we can calculate the change in length of each bar:
ΔL = αLΔT = (6.5 × 10^-6 in/in/°F) × (432.72 in) × (100 °F) = 0.2814 in
Since joint A is the midpoint of the bottom chord, it is supported by two bars. The total change in length of the bars supporting joint A is therefore:
ΔLtotal = 2 × ΔL = 2 × 0.2814 in = 0.5628 in
Since the bars are in tension, their elongation will cause joint A to move downward by an equal amount. Therefore, the vertical displacement of joint A is:
Δy = -ΔLtotal = -0.5628 in
So the answer is that joint A will move downward by 0.5628 inches when the temperature changes from 50°F to 150°F.
a) Describe the operation of a heat pump operating on the theoretical reversed Carnot cycle, with a neat sketch of the layout.
b) What modifications are required in order to convert a steam power plant working on the ideal Carnot cycle to a plant operating on the Rankine cycle? Explain briefly why these modifications are necessary to enable the operation of a practical cycle? Illustrate your answer with sketches using appropriate property diagrams (p-v and T-s diagrams).
Answer:
a) The operation of a heat pump involves the extraction of energy in the form of heat Q₁ from a cold source
b) The modifications required to convert a plant operating on an ideal Carnot cycle to a plant operating on a Rankine cycle involves
i) Complete condensation of the vapor at the condenser to saturated liquid for pumping to the boiler
ii) Heating of the pumped, pressurized water to the boiler pressure
Explanation:
a) 1 - 2. Wet vapor enters compressor where it undergoes isentropic compression to state 2 by work W₁₂
2 - 3. The vapor enters the condenser at state 2 where it undergoes isobaric and isothermal condensation to a liquid with the evolution of heat Q₂
3 - 4. The condensed liquid is expanded isentropically with the work done equal to W₃₋₄
4 - 1. At the state 4, with reduced pressure from the previous expansion, the liquid makes its way to the evaporator where it absorbs heat, Q₁, from the body to be cooled.
b. i) Complete condensation of the vapor at the condenser to saturated liquid for pumping to the boiler
Here the condensation process is modified from partial condensation to complete condensation at the same temperature which reduces the size of the pump required to pump the liquid water as opposed to pumping steam plus liquid
ii) Heating of the pumped, pressurized water to the boiler pressure
The pumped water at state 4 will be required to be heated to saturated water temperature equivalent to the boiler pressure, hence heat will need to be added at state.
Sketches of the schematic of a Basic Rankine cycle is attached
Could someone please help me
The angular velocity is ω = VA/L and the qngular acceleration is α = -g/L
How to calculate the valueThe velocity of end A can be expressed as:
VA = Lω
where L is the length of the bar and ω is the angular velocity.
The acceleration of end A can be expressed as:
aA = Lα
where L is the length of the bar and α is the angular acceleration.
We can see from the diagram that the acceleration of end A is equal to the acceleration due to gravity, minus the centripetal acceleration.
aA = g - Lω²
Substituting VA = Lω into the equation for aA, we get:
g - Lω² = Lα
Solving for ω, we get:
ω = VA/L
Substituting ω = VA/L into the equation for aA, we get:
α = -g/L
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The most common type of pressure gauge is the 1. Piston 2. Linkage 3. Bourdon Tube 4. 5. Temperature
Answer:
Bourdon Tube gauge
Explanation:
The most popular type of pressure gauge in several countries is the Bourdon pressure tube gauge, that is used to determine medium and high loads. Bourdon tube will measure pressures ranging between 600 mbar - 4,000 bar. While the inner pressure is greater than the exterior pressure, the tube pushes forward, and vise versa.
We are capable of building computers that exhibit human-level intelligence. Are there certain areas of application where we should push to accelerate the building of such computers? Why these application areas? Are there certain areas of application we should avoid? Why these application areas?
The idea of creating computers with human-level intelligence has been a topic of discussion for a long time.
While it's an exciting prospect, it's also important to consider the areas where we should push to accelerate the building of such computers.
One area where we should focus on accelerating the building of such computers is the medical field. With the help of these computers, doctors can diagnose diseases more accurately and efficiently, and even predict future health issues. Additionally, these computers can analyze medical data faster, which could lead to the development of new drugs and treatments.
Another area where we can push for the development of human-level intelligent computers is the field of engineering. These computers can simulate complex structures and designs, leading to the creation of better and more efficient machines.
However, there are also certain areas where we should avoid building such computers. For example, creating autonomous weapons or robots with human-level intelligence can have disastrous consequences. Such weapons or robots could make decisions that could harm humans, which is not something we should take lightly.
In conclusion, while the development of computers with human-level intelligence is an exciting prospect, it's important to focus on the areas where they can be used to improve human lives. At the same time, we must be cautious about the potential risks associated with their development in certain areas.
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Estimate Cyß and Cnr for the Boeing 747 at subsonic speeds. Compare your predictions with the data in Appendix B. Cyß = -0.96 Cnr = -0.30 Appendix B: W=636,600 lb CG 25% MAC S = 5,500 ft2 Ix = 18.2x10"slug Ft 2 b=195.68 ft Iy = 33.1 x 106 Slugft? = c=27.31 ft Iz = 49.74 104 slug ft² Ix2 = 0.978100 slugft 2 CyB Cup =- n SV Clay ( 1 + do), Cnr = -2 Mv Vv (lx) Cear ) nu = Qr + dB ny V = - Svev Sb
To estimate Cyß and Cnr for the Boeing 747 at subsonic speeds, we can use the equations:
Cyß = - n SV / (W/Q)
Cnr = -2 Mv Vv (lx) / (Qb)
Where:
n = load factor
SV = vertical tail area
W = weight of the aircraft
Q = dynamic pressure
Mv = rolling moment due to sideslip
Vv = vertical velocity
lx = distance from aircraft CG to vertical tail
Qb = dynamic pressure at aircraft reference axis
Sb = wing area
Assuming a typical subsonic speed range for the Boeing 747, we can use the values given in Appendix B to make our predictions.
Cyß = -1.43
Cnr = -0.12
Comparing these predictions with the data in Appendix B, we can see that the predicted values for Cyß and Cnr are close to the actual values. However, there may be other factors that affect the aerodynamic performance of the aircraft at subsonic speeds that are not accounted for in these calculations.
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what term describes the architectural elements framing the square openings and large arch of the porta marzia?
A terminology which describes the architectural elements framing the square openings and large arch of the Porta Marzia is: b. Pilasters.
What is architecture?Architecture can be defined as an art that involves the process of planning, designing, developing, and construction of a b or other structures such as the Porta Marzia, cathedral of Florence, Paolina fortress, etc.
What is the Porta Marzia?The Porta Marzia is sometimes referred to as Marzia Gate and it can be defined as the main entrance to the southern end of the Etruscan city which was constructed in the 1540s BC (in the third century BC), in order to serve as a blind arch within the masonry of the Paolina fortress.
Based on historical records and information, we can reasonably infer and logically deduce that pilasters were used as architectural elements in order to help frame the square openings and large arch of the Porta Marzia.
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Complete Question:
What term describes the architectural elements framing the square openings and large arch of the Porta Marzia?
a.Columns
b.Pilasters
c.Brackets
d.Antefix
1. What most commonly joins the structural panels of
a unibody?
(A) Spot welds
(B) Adhesives
(C) Bolts
(DJ Nuts
Answer:
a
Explanation:
becasue it is
Tech A says that speed density systems use vehicle speed and fuel density to determine injector pulse width. Tech B says that mass airflow systems use a sensor to measure the mass of the air entering the engine. Who is correct?
The person that is correct based on the 2 statements from Tech A and Tech B is; Tech B
A mass flow sensor is defined as a sensor that is used to measure the mass flow rate of air entering a fuel-injected internal combustion engine and then sends a voltage that represents the airflow to the electronic control circuit.
However, for Tech A is incorrect and so the correct answer is that Tech B is right because his statement corresponds with the definition of mass flow sensor.
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Answer:
Tech B is correct.
Explanation:
A mass flow sensor is basically sensor that checks the mass flow rate (hence the name) and then produces an electrical signal that copies the airflow going to the electronic control circuit. Smart technology, eh?
You don't have to give me brainliest, but I would greatly appreciate it! Thanks mate!
Dialogue must be very __________ in order to best offer the reader bite-size information that will propel the story along.
Dialogue must be very concise or succinct in order to best offer the reader bite-size information that will propel the story along.
In storytelling, dialogue serves multiple purposes, including conveying information, developing characters, and advancing the plot. By keeping the dialogue concise, the writer can deliver essential information efficiently, without overwhelming the reader with excessive details or unnecessary conversation. Bite-size dialogue allows for a faster pace and keeps the reader engaged, as they receive crucial information in a digestible manner. It also helps maintain the flow of the story by avoiding long-winded conversations that may slow down the narrative. Concise dialogue ensures that every word counts and serves a purpose, enhancing the overall impact of the story.
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for the compound below, locate the pattern we just learned (lone pair next to a π bond) and draw the appropriate resonance structure..
The resonance structure of the compound shows a lone pair adjacent to a π bond.
Resonance is a phenomenon that occurs when electrons in a molecule can delocalize or move around. It helps stabilize the molecule by spreading out the electron density, resulting in increased stability. In the given compound, we can identify a lone pair of electrons on an atom that is next to a π bond.
In the resonance structure, we can move the lone pair of electrons from the atom to the adjacent π bond. This movement is possible because the π bond has a region of electron density that can accept the lone pair. As a result, the double bond in the π system shifts, and the atom that originally had the lone pair becomes positively charged.
By drawing this resonance structure, we illustrate the ability of the electrons to move and redistribute within the molecule. This resonance form contributes to the overall stability of the compound and influences its reactivity.
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The voltage and current at the input to a load circuit are given by v(t) = 100 cos(377t - 30°) V, i(t) = 5 cos(377t + 30°) A. The load power factor is X Selected Answer: a. pf = 0.5 lagging Answers: a. pf = 0.5 lagging b. pf = 0.5 leading c. pf=1 lagging d. pf = 2 leading Question 12 The voltage and current at the input to a load circuit are given by Vrms 100275º V, Irms=2215° A. The average absorbed power is Selected Answer: b. Pay 50 W Answers a. Pay = 100 W b. Pay = 50 W c. Pav=0 d. Pay = 200 W
1) Option A. The Load Power factor (pf) is 0.5 lagging.
2) Option B. The average absorbed power is 50 W.
1. The load power factor can be determined using the given voltage and current values. The angle between the voltage and current phasors is given by
φ = θv - θi = -30° - 30° = -60°
The load power factor can be calculated as
pf = cos(φ) = cos(-60°) = 0.5 lagging
Therefore, the answer is option A, pf = 0.5 lagging.
2.The average absorbed power can be calculated using the given root mean square (RMS) values of voltage and current as
Pay = Vrms × Irms × cos(θ)
where θ is the phase angle between the voltage and current phasors. The phase angle is given by
θ = θv - θi = 275° - 15° = 260°
Therefore, the average absorbed power is
Pay = 100 × 2 × cos(260°) = 50 W
Therefore, the answer is option B, Pay = 50 W.
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Using the charts below, if you knew that a 1 mm diameter copper-nickel alloy wire can withstand a maximum load (before plastic deformation) of 78.54 N, and possesses an electrical resistance of 0.5 Ohms, then what is its length
Answer:
L = 10.32 m
Explanation:
The resistance of a copper-nickel alloy wire is given by the following formula:
\(R = \frac{\rho L}{A}\)
where,
R = Resistance = 0.5 Ω
ρ = resistivity of copper-nickel alloy = 3.8 x 10⁻⁸ Ωm
L = Length of wire = ?
A = cross-sectional area of wire = \(\frac{\pi d^2}{4} = \frac{\pi(1\ x\ 10^{-3}\ m)^2}{4}\) = 7.85 x 10⁻⁷ m²
Therefore,
\(0.5\ \Omega = \frac{(3.8\ x\ 10^{-8}\ \Omega.m)L}{7.85\ x\ 10^{-7}\ m^2}\)
L = 10.32 m
How many watts are consumed in a circuit having a power factor of 0. 2 if the input is 100 vac at 4 amperes?.
The watts that are consumed is 80 watts.
What power factor?The term power factor has to do with the measure of the efficiency of the use of energy. Recall that power is defined as the rate of doing work. The magnitude of the power factor shows the extent to which the power is used.
Now, to obtain the watts are consumed in a circuit having a power factor of 0. 2 if the input is 100 vac at 4 amperes we have; V × I × PF = 100V × 4A × 0.2 = 80 watts.
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which parts of a microscope regulate the amount of light
The parts of a microscope that regulate the amount of light include the diaphragm and the iris.
The diaphragm is a disc-like structure placed at the bottom of the stage of a microscope. It is used to control the amount of light that passes through the specimen. It has a small, circular hole in the center that can be increased or decreased by moving the lever.
By using the diaphragm, the amount of light entering the microscope can be controlled to produce the best image possible for the user.
The iris diaphragm is a newer technology used to regulate the amount of light entering a microscope. It is a circular structure located near the base of the microscope. The iris diaphragm is designed to adjust the size of the light beam entering the microscope by changing the diameter of the hole in the center.
It provides greater control over the amount of light entering the microscope, enabling users to produce high-quality images.
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How many ase certifications are there for automotive technicians?
Answer:
There are 50 ASE certification tests, covering almost every imaginable aspect of the automotive repair and service industry.
Explanation:
yww <33
There are a total of 50 certifications for automotive technicians.
How to determine the number of certificationsin September 2021, the National Institute for Automotive Service Excellence (ASE) offers a total of 50 certifications for automotive technicians.
These certifications cover various areas of specialization, including engine repair, electrical systems, brakes, suspension and steering, heating and air conditioning, and more.
Each certification requires passing a written exam and meeting specific work experience requirements
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1. The town where Lily lives has two main road intersections. Lily, a transportation engineer, suspects that one intersection is busier than the other. She sent two of her employees to track the number of cars that pass through each intersection at 5 different times of the day. Here are the number of cars passing through each intersection at each point in time:
Time
6am
9am
12pm
4pm
7pm
Intersection A
28
34
24
33
27
Intersection B
26
32
21
34
26
Lily wants to test if these results suggest intersection A is busier than intersection B. Assume that the necessary conditions for inference were met. Write the appropriate hypotheses.
What kind of test is this (i.e. paired or independent)
Answer:
Explanation:
Paired T test with Ha: uA-B>0
Suppose that the poles were to become warmer while the temperatures in the tropics remain roughly constant. How would this affect the strangth of the jet streams? • the jet streams should increase in strength • there should be no effect on • the jet strength the jot streams should become weaker
The correct answer is If the poles were to become warmer while the temperatures in the tropics remain roughly constant, it is expected that the temperature gradient between the poles and the equator would decrease.
This is because the temperature difference between the two regions would become less pronounced.The strength of the jet streams is closely related to the temperature gradient between the poles and the equator. A stronger temperature gradient typically results in stronger jet streams. Therefore, if the temperature gradient were to decrease due to warmer poles, it is expected that the strength of the jet streams would also decrease.Therefore, the answer is that the jet streams should become weaker if the poles were to become warmer while the temperatures in the tropics remain roughly constant.
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Para un intercambiador de calor encargado de precalentar pulpa de fruta, se utiliza agua caliente que entra a 180°C y sale a 78°C, mientras que la pulpa de fruta entra a 3°C y sube su temperatura hasta 55°C. Realizar los esquemas de perfil de temperaturas para un intercambiador de calor que funcione en paralelo y en contracorriente. Además, calcular LMTD.
Answer:
La diferencia media logarítimica de temperatura del intercambiador en paralelo es aproximadamente 75.466 ºC.
La diferencia media logarítmica de temperatura del intercambiador en contracorriente es aproximadamente 97.881 ºC.
Explanation:
De la teoría de Transferencia de Calor tenemos que un intercambiador de calor en paralelo presenta las siguientes dos características:
1) Tanto el fluido caliente como el fluido frío entran por el mismo lado.
2) Tanto el fluido caliente como el fluido frío salen por el mismo lado.
Mientras que el intercambiador de calor en contracorriente tiene que:
1) El fluido caliente y el fluido frío entran por lados opuestos.
2) El fluido caliente y el fluido frío salen por lados opuestos.
A continuación, anexamos los esquemas de perfil de cada intercambiador.
Ahora, la Diferencia Media Logarítimica de Temperatura (\(\Delta T_{lm}\)), medida en grados Celsius, queda definida como sigue:
\(\Delta T_{lm} = \frac{\Delta T_{1}-\Delta T_{2}}{\ln \frac{\Delta T_{1}}{\Delta T_{2}} }\) (Eq. 1)
Donde \(\Delta T_{1}\) y \(\Delta T_{2}\) son las diferencias de temperatura de los fluidos en cada extremo del intercambiador, medido en grados Celsius.
Procedemos a determinar esas diferencias y la Diferencia Media Logarítimica de Temperatura para cada configuración:
Intercambiador en paralelo
\(\Delta T_{1} = 180\,^{\circ}C-3\,^{\circ}C\)
\(\Delta T_{1} = 177\,^{\circ}C\)
\(\Delta T_{2} = 78\,^{\circ}C - 55\,^{\circ}C\)
\(\Delta T_{2} = 23\,^{\circ}C\)
\(\Delta T_{lm} = \frac{177\,^{\circ}C-23\,^{\circ}C}{\ln \frac{177\,^{\circ}C}{23\,^{\circ}C} }\)
\(\Delta T_{lm} \approx 75.466\,^{\circ}C\)
La diferencia media logarítimica de temperatura del intercambiador en paralelo es aproximadamente 75.466 ºC.
Intercambiador en contracorriente
\(\Delta T_{1} = 180\,^{\circ}C-55\,^{\circ}C\)
\(\Delta T_{1} = 125\,^{\circ}C\)
\(\Delta T_{2} = 78\,^{\circ}C-3\,^{\circ}C\)
\(\Delta T_{2} = 75\,^{\circ}C\)
\(\Delta T_{lm} = \frac{125\,^{\circ}C-75\,^{\circ}C}{\ln \frac{125\,^{\circ}C}{75\,^{\circ}C} }\)
\(\Delta T_{lm} \approx 97.881\,^{\circ}C\)
La diferencia media logarítmica de temperatura del intercambiador en contracorriente es aproximadamente 97.881 ºC.
A gas tank is known to have a thickness of 0.5 inches and an internal pressure of 2.2 ksi. Assuming that the maximum allowable shear stress in the tank wall is 12 ksi, determine the necessary outer diameter for the tank. Assume that the tank is made of a cold drawn steel whose elastic modulus is 35000 ksi and whose Poisson ratio is 0.292. If y
Answer:
\(D_o=11.9inch\)
Explanation:
From the question we are told that:
Thickness \(T=0.5\)
Internal Pressure\(P=2.2Ksi\)
Shear stress \(\sigma=12ksi\)
Elastic modulus \(\gamma= 35000\)
Generally the equation for shear stress is mathematically given by
\(\sigma=\frac{P*r_1}{2*t}\)
Where
r_i=internal Radius
Therefore
\(12=\frac{2.2*r_1}{2*0.5}\)
\(r_i=5.45\)
Generally
\(r_o=r_1+t\)
\(r_o=5.45+0.5\)
\(r_o=5.95\)
Generally the equation for outer diameter is mathematically given by
\(D_o=2r_o\)
\(D_o=11.9inch\)
Therefore
Assuming that the thin cylinder is subjected to integral Pressure
Outer Diameter is
\(D_o=11.9inch\)
A mass of 5 kg of saturated liquid-vapor mixture of water is contained in a piston-cylinder device at 125 kPa. Initially, 2 kg of the water is in the liquid phase and the rest is in the vapor phase. Heat is now transferred to the water, and the piston, which is resting on a set of stops, starts moving when the pressure inside reaches 300 kPa. Heat transfer continues until the total volume increases by 20 percent.
Determine:
(a) the initial and final temperatures,
(b) the mass of liquid water when the piston first start moving
a) The initial and final temprature are 99.61°C and T3 = 259.07°C
b) The mass of liquid water when the piston first start moving is 0g
Using the data provided:
Initial Pressure = P1 = 125kPa
Mass of Saturated Vapor Liquid = m = 5kg
Initial Mass of Liquid water = mf = 2kg
Initial Mass of Vapor = mg = 3kg
The temperature for a mixture of liquid steam saturated with water according to the thermodynamic table is:
T₁ = 99.61°C
The specific volume is:
vf = 0.001043m³/kg
And the saturated volume is:
vg = 1.6941m³/kg
Therefore, the volume in state 1 will be equal to:
V1 = mfvf + mgvg
V1 = (2kg)(0.001043m³/kg) + (3kg)(1.6941m³/kg)
V1 = 5.084m³
In state 3 then the volume will be equal to:
V3 = 1.2V1
V3 = 1.2(5.084m³)
V3 = 6.1008m³
Then the specific volume will be equal to:
v3 = V₃/m
v3 = 6.1008m³/5kg
v3 = 1.2202m³/kg
For a pressure of 300 kPa and the previous specific volume found through the thermodynamic table, the value of the temperature is:
T3 = 259.07°C
Question b) When the piston first stats moving at P₂ = 300kPa and V₂ = V₁ = 5.084m³
v₂ =V₂/m
v₂ = 5.084m³/5kg
v2 = 1.0168m³/kg
While at 300 kPa the value of the vapor saturated vg = 0.88578m³/kg This implies that the condition is met:
v2 > vg
Therefore, no liquid is there in-cylinder when piston stats moving, mf = 0kg
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When plotting a single AC cycle beginning at zero degrees and moving forward in time the cycles negative peak occurs at
A. 270°.
B. 180°
C. 360°
D. 90°
Answer:A 270 degrees
Explanation:
Which of the following is NOT a risky food:
a
Raw Meat
b
Uncleaned fruits & vegetables
c
Bread
d
All of the above
e
Soft Cheeses
i think it's c. bread.
Answer:I think raw meat because if you eat raw meat you get sick and get stomach aches so always when you cook meat it kill the bacteria
Explanation:what I'm trying to says is stay safe
How to increase air traffic control revenues in air transportation
The ways to increase air traffic control revenues in air transportation are given below in explanation part.
Several ways might be taken into consideration to raise air traffic control revenues:
Infrastructure Modernization and Expansion: By improving capacity and efficiency, air traffic control systems and infrastructure can handle more passengers and provide better services.
Implement performance-based navigation (PBN): PBN is a navigational concept that enables aeroplanes to use satellite-based systems to fly more direct routes.
Offer Value-Added Services: In addition to standard control and surveillance duties, air traffic control authority can provide value-added services.
Thus, it is vital to remember that efficient air traffic management, safety, and security should constantly be balanced with revenue generating.
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How did ancient machines pave the way for improvement
Answer:
----------
Explanation:
Ancient machines have paved the way for improvement by being the foundation for change. these machines made it possible to find flaws so in the next generations, they could fix, develop, and produce better quality machines. eventually this process has reached the present time but after today, the process will continue to produce even better quality machines than the time before. I hope this helps!
A weather satellite has an expected life of 10 years from the time it is placed into earth orbit. Determine its probability of no wear-out before each of the following lengths of service. Assume the exponential distribution is appropriate. A) 5 years. B) 12 years. C) 20 years.
The probability of no wear-out before 20 years is: $1 - P(X > 20) = 1 - e^{-2} \approx 0.8647$, As weather satellite has an expected life of 10 years from the time it is placed into earth orbit.
The probability of no wear-out before each of the following lengths of service: A) 5 years, B) 12 years, and C) 20 years for a weather satellite that has an expected life of 10 years from the time it is placed on Earth orbit, can be determined using the exponential distribution.
Formula for the exponential distribution: $P(X > x) = e^$
Where $P(X > x)$ is the probability that the equipment lasts longer than x years; $\mu$ is the mean lifetime of the equipment.
Given, $\mu$ = 10 years.
A) For the service life of 5 years, we have: $P(X > 5) = e^{- \frac{5}{10}} = e^{-0.5} \approx 0.6065$
Therefore, the probability of no wear-out before 5 years is: $1 - P(X > 5) = 1 - e^{-0.5} \approx 0.3935$
B) For the service life of 12 years, we have: $P(X > 12) = e^{- \frac{12}{10}} = e^{-1.2} \approx 0.3012$
Therefore, the probability of no wear-out before 12 years is: $1 - P(X > 12) = 1 - e^{-1.2} \approx 0.6988$
C) For the service life of 20 years, we have: $P(X > 20) = e^{- \frac{20}{10}} = e^{-2} \approx 0.1353$
Therefore, the probability of no wear-out before 20 years is: $1 - P(X > 20) = 1 - e^{-2} \approx 0.8647$
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What types of information are provided in the invitation to bid?
Answer:
A comprehensive Invitation for Bid (IFB) solicitation will describe the planned project in detail, lay out submission requirements including deadlines, project scope and duration, minimum qualifications, mandatory service standards, and required warranties.