When determining a safe amount of each nutrient to consume we can remember the following rule: ___ % or less is low and ___% or more is high for a given nutrient on the label. (5 points) a 2% and 30% b 10% and 50% c 10% and 30% d 5% and 20%

By knowing how intensity relates to distance, we will see that at 4 meters of the engine the intensity is 80.

The sound spreads in a solid angle like all waves, so the intensity of the sound will decrease with the distance squared, this means that:

\(I = \frac{P}{4*pi*r^2}\)

Where P is the sound power, we know that when the student is at 8m from the engine, the intensity measured is 20 (it does not tell the units) so we have:

\(20 = \frac{P}{4*3.14*(8m)^2} \\\\P = 20*4*3.14*(8m)^2 = 16,078.8 m^2\)

Now, if you move 4 meters closer to the engine, your new position will be:

r = 4m

Then we have:

\(I = \frac{16,078.8 m^2}{4*3.14*(4m)^2} = 80\)

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Answer:

80 is the answer! 100% CORRECT!

Explanation:

~Hope this helps! :)

Answer: 272.82 drop/tile

Explanation:

Given that the Rain drops fall on a tile surface at a density of 4638 drops/ft2. There are 17 tiles/ft2. How many drops fall on each tile?

Tiles/ft^2 × drop/tiles = drop/ft^2

Tiles will cancel out. Leaving the answer to be drop/ ft^2

Substitutes all the magnitude of the above units.

17 × drop/tiles = 4638

Make drop/tiles the subject of formula

Drop/tiles = 4638/17

Drop/tiles = 272.82

Therefore, 272.82 drop/tile drops fall on each tile? 

Answer:

Speed of sound ways in railroad = 6,135.8 m/s

Explanation:

Given:

Distance cover by sound wave = 2,350 meter

Time taken by sound wave to cover distance = 0.383 seconds

Find:

Speed of sound ways in railroad

Computation:

Speed = Distance / Time

Speed of sound ways in railroad = Distance cover by sound wave / Time taken by sound wave to cover distance

Speed of sound ways in railroad = 2,350 / 0.383

Speed of sound ways in railroad = 6,135.77

Speed of sound ways in railroad = 6,135.8 m/s

The mass of a dog that weighs 382N is 38.94kg

Weight of a substance refers to the force on an object due to the gravitational attraction between it and the Earth (or whatever astronomical object it is primarily influenced by).

The mass can be calculated from the weight using the following formula:

Weight = mass × acceleration due to gravity.

Acceleration due to gravity on Earth is 9.81 m/s²

382N = m × 9.81m/s²

m = 38.94kg

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The anion radius is approximately 0.092 nm

To find the anion radius, we can use Coulomb's law, which states that the force of attraction between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them. In this case, the force of attraction between the divalent cation and divalent anion is given as 1.50 x 10^-8 N.

The charge of a divalent cation is 2+, and the charge of a divalent anion is 2-. Therefore, the product of their charges is (2)(2) = 4.

Now, we can use Coulomb's law to calculate the anion radius:

Force of attraction = (k * (charge of cation) * (charge of anion)) / (distance^2)

1.50 x 10^-8 N = (k * 4) / (distance^2)

Now, we need to find the value of the constant k. It is equal to 8.99 x 10^9 Nm^2/C^2.

1.50 x 10^-8 N = (8.99 x 10^9 Nm^2/C^2 * 4) / (distance^2)

To find the anion radius, we need to rearrange the equation to solve for distance:

distance^2 = (8.99 x 10^9 Nm^2/C^2 * 4) / (1.50 x 10^-8 N)

distance^2 = (35.96 x 10^9 Nm^2/C^2) / (1.50 x 10^-8 N)

distance^2 = 2397.33 x 10^17 m^2/C^2/N

Now, we can solve for the anion radius by taking the square root of both sides:

distance = √(2397.33 x 10^17 m^2/C^2/N)

Plugging in the given values, we get:

distance = √(2397.33 x 10^17 m^2/C^2/N)

distance ≈ √(23.97 x 10^18 m^2/C^2/N)

distance ≈ √(2.397 x 10^19 m^2/C^2/N)

distance ≈ √(2.397) x √(10^19) m/C√N

distance ≈ √2.397 x 10^9 m/C√N

Finally, we convert the distance from meters to nanometers:

distance ≈ √2.397 x 10^9 m/C√N

distance ≈ √2.397 x 10^9 m/C√N x (10^9 nm/1 m)

distance ≈ (√2.397 x 10^9 x 10^9) nm/C√N

distance ≈ √(2.397 x 10^18) nm/C√N

distance ≈ √2.397 x 10^9 nm/C√N

Therefore, the anion radius is approximately 0.092 nm.

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Taking the square root of both sides, we find that the anion radius, r, is equal to the square root of (599.33 × \((q^2)\)).

The force of attraction between a divalent cation and a divalent anion is given as 1.50 x\(10^{-8\) N. We can use Coulomb's Law to solve for the anion radius. Coulomb's Law states that the force of attraction between two charged particles is directly proportional to the product of their charges and inversely proportional to the square of the distance between them.

The equation for Coulomb's Law is F = k × (q1 × q2) /\(r^2\), where F is the force of attraction, k is the electrostatic constant, q1 and q2 are the charges of the two particles, and r is the distance between them.

In this case, since the charges of the cation and anion are equal in magnitude, their product can be written as \(q^2\). Also, we can substitute the given force value of 1.50 x \(10^{-8\) N.

Therefore, the equation becomes 1.50 x \(10^{-8\) N = k × \((q^2) / r^2\).

To find the anion radius, we need to rearrange the equation to solve for r. Rearranging, we get \(r^2\) = k × (q^2) / (1.50 x\(10^{-8\) N).

Now, we can substitute the known values into the equation. The electrostatic constant, k, is approximately 8.99 x\(10^9 Nm^2/C^2.\)
Let's assume the radius of the cation is 0.092 nm, which is equal to 0.092 x \(10^{-9\) m.

Substituting the values, we have \(r^2\) = (8.99 x \(10^9 Nm^2/C^2\)) * (\(q^2\)) / (1.50 x\(10^{-8\)N).

Simplifying the equation further, we get \(r^2\) = 599.33 × (\(q^2\)).

Finally, taking the square root of both sides, we find that the anion radius, r, is equal to the square root of (599.33 × (\(q^2\))).

Therefore, the anion radius is dependent on the charge of the ion, q. To calculate the specific value, we need additional information about the charge of the ion.

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Answer:

The amount of gravitational force INCREASES as the distance between two objects increases; thus, an astronauts weight DECREASES as she or he moves away from earth into space.

hope this helped.

Answer:

most likely just 1

Explanation:

I sucked at sig figs in middle school, in fact it was the lowest test grade i ever received, but it is relatively simple.

because there is only one sig fig involved in each number, there can't be multiple sig figs here. 3000/500=6

500/3000=2(round up from 1.66666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666666) you get the point.

As per the given scenario, Ram will cross the river first.

Ram chooses the quickest route and crosses the river without turning. Ram and Hari can both swim in still water at the same speed, hence their respective speeds when crossing the river will be equivalent. Ram will be able to get to the opposing bank the fastest as a result.

Hari, on the other hand, is swimming upstream at an angle and is being dragged downstream by the water.

Hari's overall travel distance will increase due to the downstream current, however his effective speed will drop in comparison to the other bank. Hari will therefore take longer than Ram to get to the opposing bank.

Thus, Ram will cross the river first in this scenario.

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Answer:

Huh is there options?

Explanation:

XD I dont understand have a good day tho a better person and smarter person will answer this for u

Answer: Metal ions tend to lose their electrons and form positive ions. Both iron and zinc are metals, so they both form ions that are positively charged. However, ions with the same charge repel each other. That is why an iron ion is not attracted to a zinc ion.

Answer:

68.8 N

Explanation:

From the question given above, the following data were obtained:

Mass (m) of box = 18 Kg

Coefficient of friction (μ) = 0.39

Force of friction (F) =?

Next, we shall determine the normal force of the box. This is illustrated below:

Mass (m) of object = 18 Kg

Acceleration due to gravity (g) = 9.8 m/s²

Normal force (N) =?

N = mg

N = 18 × 9.8

N = 176.4 N

Finally, we shall determine the force of friction experienced by the object. This is illustrated below:

Coefficient of friction (μ) = 0.39

Normal force (N) = 176.4 N

Force of friction (F) =?

F = μN

F = 0.39 × 176.4

F = 68.796 ≈ 68.8 N

Thus, the box experience a frictional force of 68.8 N.

Frictional forces between a liquid and the walls of a pipe can convert kinetic energy into thermal energy, leading to a drop in pressure within the pipe due to the decrease in force being applied to the walls.

Frictional forces between the liquid and the walls of a pipe can lead to the conversion of kinetic energy into thermal energy. This can have an effect on the pressure of the liquid within the pipe. Specifically, when the liquid loses kinetic energy due to friction, the pressure within the pipe drops. This drop in pressure can be attributed to the fact that as the liquid loses kinetic energy, its molecules move more slowly, thus decreasing the amount of force that is being applied to the walls of the pipe. As a result, the pressure within the pipe decreases.

In summary, frictional forces between a liquid and the walls of a pipe can convert kinetic energy into thermal energy, leading to a drop in pressure within the pipe due to the decrease in force being applied to the walls.

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Answer:

Explanation:

Considering the fact that we ave been given an angle of inclination here, we best use it! That means that the velocity of 23 m/s is actually NOT the velocity we need; I tell my students that it is a "blanket" velocity but is not accurate in either the x or the y dimension of parabolic motion. In order to find the actual velocity in the dimension in which we are working, which is the y-dimension, we use the formula:

\(v_{0y}=v_0sin\theta\) and filling in:

\(v_{0y}=23sin(25)\) which gives us an upwards velocity of 9.7 m/s. So here's what we have to work with in its entirety:

\(v_{0y}=9.7m/s\)

a = -9.8 m/s/s

t = 2.8 seconds

Δx = ?? m

The one-dimensional motion equation that utilizes all of these variables is

Δx = \(v_0t+\frac{1}{2}at^2\) and filling in:

Δx = \(9.7(2.8)+\frac{1}{2}(-9.8)(2.8)^2\) I am going to do the math according to the correct rules of significant digits, so to the left of the + sign and to 2 sig fig, we have

Δx = 27 + \(\frac{1}{2}(-9.8)(2.8)^2\) and then to the right of the + sign and to 2 significant digits we have

Δx = 27 - 38 so

Δx = -11 meters. Now, we all know that distance is not a negative value, but what this negative number tells us is that the ball fell 11 meters BELOW the point from which it was kicked, which is the same thing as being kicked from a building that is 11 meters high.

Even if the submarine's mass rises while its volume stays constant, the buoyant force on it doesn't change. As a result, the buoyant force on the submarine has changed by around 9,434.53 N.

The air in the ballast tanks is evacuated out of the submarine as it dives, and the ballast tanks are flooded with water until the submarine's overall density is greater than the surrounding water, at which point the submarine starts to sink. (negative buoyancy).

Identify the buoyant force change:

The weight of the displaced water changes in proportion to the change in buoyant force. As a result, the buoyant force has changed as follows:

change in buoyant force = change in weight of displaced water

change in buoyant force = 9,434.53 N

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Answer:

Explanation:

The force acting on an object given it's mass and acceleration can be found by using the formula

From the question we have

force = 4 × 13

We have the final answer as

Hope this helps you

The second option is the correct answer to the question. The complete question is attached

In the beginning, the cart started from rest and moved to the right. The movement represents positive acceleration

In the middle, there is no change in velocity hence no acceleration. This means that the value of acceleration is zero

A the end, the cart had a negative acceleration which brings the cart to rest.

Acceleration refers to the change in velocity with time. Usually when there is no change in velocity acceleration is zero. The value can also be positive or negative depending on the velocity.

When there is an increase in velocity, the result is positive acceleration but in a situation when there is a decrease in velocity the result is negative acceleration. At the peak pf negative acceleration the result is to put the object accelerating to a stop.

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Answer:

-10 m/s²

Explanion:

(0 m/s - 50 m/s) ÷ 5 seconds

You subtract the original speed from the final speed, (to get negative 50), then divide that by 5 seconds.

Hope this helps! :)

Answer:

distance =2km

time =1/2hour

speed =distance /time =2/1/2=4km/h

The average speed of the gazelle is equal to 4 Km/h. Therefore, option (C) is correct.

The average speed can be defined as the total distance traveled in a fixed interval of time. It can be determined by dividing the total distance traveled by the total time.

The average velocity of the object is a single value if the object moves uniformly, it will travel the same distance in the same interval of time.

The mathematical expression for the average speed is as follows:

The average speed = Total distance covered/Total time taken

Given, the distance traveled by gazelle = 2 Km

The time taken by the gazelle to travel this distance = 1/2 hr = 0.5 hr

The average speed = 2Km/ 0.5 hr = 4 Km/hr

Therefore, the gazelle's average speed is equal to 4 Km/hr.

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Answer:

c) The spoon temporarily gets charged with static electricity.

Explanation:

Static electricity is the electric charge that arises on the material's surface. This is caused when the two positive and the negative charges come in contact with each other. The electricity generated finds an escape from the object's surface.  

Rubbing the spoon makes it negatively charged while the sat and pepper have positive charge.

Between salt and pepper, it is the pepper that jumps to the spoon because it is lighter than salt.

The arrow leaves the bow at a speed of 40.47 m/s.

When the arrow is released from its bow, the arrow will move and accelerate. Newton's second law of motion applies to the arrow. The formula F = ma

\(a \:=\: \frac{F}{m}\)

\(a \:=\: \frac{89.0}{0.0850}\)

a = 1,047.059 m/s²

When the object has acceleration, the object will move in a non-uniform motion. The formula

v² = u² + 2ad

v² = 0² + (2×1,047.059×0.782)

v² = 1,637.6

\(v_t \:=\: \sqrt{1,637.6}\)

\(v_t\) = 40.47 m/s

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The daytime temperature on the moon can reach 266 degrees Fahrenheit, and the nighttime temperature can get as low as -292 degrees Fahrenheit. To find the difference between these extremes is as follow:

We need to subtract the lower temperature from the higher temperature.

Mathematically, we can represent the problem as follows:

266°F - (-292°F)

= 266°F + 292°F

= 558°F

Therefore, the difference between the extremes of daytime and nighttime temperatures on the moon is 558 degrees Fahrenheit.

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The magnification of the image formed by the lens is -0.982.

To determine the magnification of the image formed by the lens, we can use the lens formula:

1/f = (n - 1) * (1/r1 - 1/r2)

Where f is the focal length of the lens, n is the refractive index of the lens material, r1 is the radius of curvature of the front surface, and r2 is the radius of curvature of the back surface.

Given that the radii of curvature are 34.5 cm and -26.9 cm, and the refractive index is 1.66, we can substitute these values into the lens formula to calculate the focal length.

Using the lens formula, we find that the focal length of the lens is approximately 13.54 cm.

The magnification of the image formed by the lens can be determined using the magnification formula:

m = -v/u

Where m is the magnification, v is the image distance, and u is the object distance.

Given that the object is placed 42.6 cm from the lens, we can substitute this value and the focal length into the magnification formula to calculate the magnification.

Substituting the values, we find that the magnification of the image formed by the lens is approximately -0.982.

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Explanation:

Gravity

Gravity is one major force that creates tides. In 1687, Sir Isaac Newton explained that ocean tides result from the gravitational attraction of the sun and moon on the oceans of the earth (Sumich, J.L., 1996).

Answer:408

Explanation:

Answer:

  382.2 N

Explanation:

You want the normal force on an object weighing 437 N situated on an inclined plane 29° from the horizontal.

The vector 437 N straight down can be decomposed to vectors parallel to the plane and perpendicular to the plane. That decomposition looks like ...

  (perpendicular, parallel) = 437 N · (cos(29°), sin(29°)) ≈ (382.2, 211.9) N

The normal force on the object is about 382.2 N.

For a distant astronomical object (a quasar) is moving away from us at half the speed of light, the speed of the light we receive from this quasar  is mathematically given as c = 3x108 m/s

Generally, the equation for the   is mathematically given as

The speed of light can be said to be measured to be approximately the value c = 3x108 m/s

.

In conclusion, An will not influence  3x108 m/s unless both are inertia and frames refrences where newtons laws are valid, so the speed of light measured from the earth frame is equal to  3x108 m/s

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Answer:

La ecuación de onda lineal para una función f(x, t) se escribe como:

\(\frac{d^2f}{dt^2} = c^2*\frac{d^2f}{dx^2}\)

Donde c es una constante que depende de la velocidad de propagación de la onda.

En este caso, tenemos:

\(f(x) = A*e^{-i*(k*x - w*t + \phi)}\)

Recordar que la derivada de la exponente es tal que:

\(k(x,y) = A*e^{c*x + n*y}\\dk/dx = c*A*e^{c*x + n*y}\)

Entonces las derivadas de f van a ser:

\(\frac{df}{dt} = (i*w)*f(x)\)

\(\frac{d^2f}{dt^2} = (i*w)^2*f(x) = -(w)^2*f(x)\)

\(\frac{df}{dx} = (-i*k)*f(x)\)

\(\frac{d^2f}{dx^2} = (-i*k)^2*f(x) = -k^2*f(x)\)

Entonces podemos reescribir la ecuación de onda como:

\(\frac{d^2f}{dt^2} = c^2*\frac{d^2f}{dx^2}\)

\(-(w)^2*f(x) = c^2*(-k^2*f(x))\)

Ahora podemos simplemente definir c^2 = (w/k)^2 y vemos que la ecuación de onda se cumple.

Answer:

you can't go ice skating on it because if it just reached the temp then you need to wait for about 2 hours

Explanation:

This is due to the fact that occluded fronts combine two cold air masses, which causes one of the cold air masses to go downward.

When a warm air mass is sandwiched between two cold air masses, an occluded front occurs. In an occlusion, the warm front passes over the cold front, which dives beneath it.

In a front is obscured, the warm front is fully supplanted by the cold front, in which the warm air masses have completely disappeared. Furthermore, there are frequent shifts in the various weather producing circumstances because of the cold front's relatively low temperature.

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