Your correct answers are:
B. A field that is perpendicular to the flow of charges
C. A magnetic field
When electric charges move through a conductor, two fields are formed: a magnetic field and an electric field. The correct answer is C. a magnetic field and D. an electric field.
A magnetic field is formed around the conductor when electric charges flow through it. This is due to the interaction between the moving charges and the magnetic field lines. The magnetic field is perpendicular to the flow of charges and its strength depends on the magnitude of the current flowing through the conductor.
An electric field is also formed around the conductor. This electric field is established due to the presence of charges and their interaction with each other. The electric field lines are typically radial, originating from the charged particles or the source of the electric field. The electric field exists both inside and outside the conductor.
So, the correct answer is C. a magnetic field and D. an electric field.
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What is the length of the y-component of the vector plotted below?
A. 1
B. 4
C. 2
D.3
Answer:
um .... D. D D D D D this should be it
What can you infer about the changes in the environment over time at the mystery fossil dig site? Record your inferences in the spaces provided.
Describe the environment in Egypt before the mystery fossil organism emerged.
the fossil informed us about the climatic and geographical changes that occurs in the environment over time.
What the mystery fossil dig site informed us about environment?We can infer about the climate and geographical changes in the environment over time at the mystery fossil dig site because the fossil provides us information about the climatic condition as well as the geography of land when this fossil organism were alive.
So we can conclude that the fossil informed us about the climatic and geographical changes that occurs in the environment over time.
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An old light bulb draws only 52.3 W, rather than its original 60.0 W, due to evaporative thinning of its filament. By what factor is the diameter of the filament reduced, assuming uniform thinning along its length
The filament's diameter will be reduced by 9.1% when an old light bulb draws only 52.3 W instead of its original 60.0 W due to evaporative thinning of its filament.
When an old light bulb draws only 52.3 W instead of its original 60.0 W, the reason behind it is due to evaporative thinning of its filament. To calculate the factor by which the diameter of the filament is reduced, we will use the following formula; W α (diameter)2Lwhere, W = Power, L = Length, and α is a constant.The constant α is independent of the diameter of the filament. Therefore, \frac{W 1}{ W 2} =\frac{ (\frac{diameter 1 }{ diameter 2} )2L1 }{ L2}. Here, W1 = 60.0 W (original power of the light bulb), W2 = 52.3 W (new power), and L1 = L2 (uniform thinning of the filament).Now, we can find the diameter of the filament using the following formula;diameter 2 = diameter 1 sqrt{(\frac{W1 }{ W2} )}= diameter 1 sqrt{(\frac{60.0 }{ 52.3})}.This formula helps to find the diameter of the filament when the power of the light bulb is reduced due to evaporative thinning of its filament.The new diameter of the filament will be; Diameter 2 = 0.909 Diameter 1Therefore, the diameter of the filament has been reduced by 9.1% (approximately 0.909 times of its original diameter).
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REALLY NEED HELP, DUE TODAY!!!
1. How will an object at rest be affected if multiple forces working on it are opposed but unbalanced?
Motion will either be created, stopped, or changed.
The acceleration of the object will increase
The unbalanced forces will cause the object to produce a humming sound
The mass of the object will decrease.
2. A blue car weighing 1,302 kg is accelerating forward at a rate of 4 m/s2. What is the forward force of the car?
325.5 N
1,298 N
1,306 N
5,208 N
3. Two people collide on a busy city street. What information is needed to calculate the force one of the people exerts on the other person?
The velocity of each person
The speed of each person
The mass and acceleration of each person
The location of the collision
4. (don't need)
5. Two bowling balls of different masses collide while accelerating at 1.875 m/s2. The first ball, rolling to the right, weighs 7 kg. The second ball, rolling to the left, weighs 4 kg. What force does the bowling ball weighing 7 kg exert on the bowling ball weighing 4 kg?
8.875 N to the right
3.73 N to the left
7.5 N to the left
13.125 N to the right
Answer:
1.An object at rest has zero velocity - and (in the absence of an unbalanced force) will remain with a zero velocity. Such an object will not change its state of motion (i.e., velocity) unless acted upon by an unbalanced force.
3.Let speed of balls are v
1
and v
2
.
There is no external force acting, momentum will be conserved.
m
1
u
1
+m
2
u
2
=m
1
v
1
+m
2
v
2
⇒m×6−m×6=mv
1
+mv
2
⇒v
1
=−v
2
Coefficient , e=−
u
1
−u
2
v
1
−v
2
⇒
3
1
=−
6+6
v
1
−v
2
⇒v
1
=−2m/sWhen two objects with the same mass collide, Newton's laws tell us that they will accelerate the same amount but in opposite directions.
Collision Forces - 5/5
1. A) Motion will be either created, stopped or changed.
2. D) 5,208 N
3. B) the mass and acceleration of each person
4. C) balanced forces
5. B) 13.125 N to the right
Hope this helps ya out peeps!
select all that apply select all the stars that would have the same luminosity. (use the stefan-boltzmann law.) presented are the radii and temperatures of five stars compared to the sun.
According to the Stefan-Boltzmann law, the luminosity of a star is directly proportional to the fourth power of its temperature and its radius squared.
The formula for luminosity is:L = 4πR²σT⁴where L is the luminosity, R is the radius, T is the temperature, and σ is the Stefan-Boltzmann constant (5.67 × 10⁻⁸ W/m²K⁴).To determine which stars would have the same luminosity as the sun, we need to compare their luminosity values using the given data. The radii and temperatures of five stars compared to the sun are as follows:Star A: R = 2R⊙, T = 6000 KStar B: R = R⊙, T = 3000 KStar C: R = 0.1R⊙, T = 6000 KStar D: R = 10R⊙, T = 3000 KStar E: R = 2R⊙, T = 15000 KSubstituting the values in the formula, we get:L⊙ = 4π(1²)(5.67 × 10⁻⁸)(5778⁴) ≈ 3.828 × 10²⁶ Wm¹²Star A: L = 4π(2²)(5.67 × 10⁻⁸)(6000⁴) ≈ 1.84 × 10³³ Wm¹²Star B: L = 4π(1²)(5.67 × 10⁻⁸)(3000⁴) ≈ 6.86 × 10²⁹ Wm¹²Star C: L = 4π(0.1²)(5.67 × 10⁻⁸)(6000⁴) ≈ 6.95 × 10²³ Wm¹²Star D: L = 4π(10²)(5.67 × 10⁻⁸)(3000⁴) ≈ 5.48 × 10³⁴ Wm¹²Star E: L = 4π(2²)(5.67 × 10⁻⁸)(15000⁴) ≈ 5.12 × 10³³ Wm¹²
The luminosity values of the stars are as follows:Star A: L ≈ 1.84 × 10³³ Wm¹²Star B: L ≈ 6.86 × 10²⁹ Wm¹²Star C: L ≈ 6.95 × 10²³ Wm¹²Star D: L ≈ 5.48 × 10³⁴ Wm¹²Star E: L ≈ 5.12 × 10³³ Wm¹²Comparing the luminosity values with that of the sun, we can see that stars A and E would have the same luminosity as the sun.
Therefore, the correct answer is: Stars A and E
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Identify the type of reaction (combustion, synthesis, decomposition, single replacement, or double replacement) this equation represents.
CH4 + O2 CO2 + H2O
Answer:
Combustion
Explanation:
Given: Rocket motor equation: " Ve + (Pe – Pa) AC Rocket weight (no propellant): 300 kg Propellant weight: 800 kg Acceleration at burnout: 10 18 G ur. First things first – the contribution of the pressure differential, (Pe - Pa)Ae is typically very small. Its contribution will be ignored for this problem. Compute the Isp required to develop a rocket with a burnout velocity of 1000 m/s. Compute the exit velocity (Ve or Vj) required for this rocket. Plot the rocket acceleration (in terms of G) and rocket weight as a function of time. What is the burn time of the rocket? Finally, plot the speed of the rocket, assuming a flight path angle of 45 degrees assuming no gravity. Plot the speed of the rocket considering gravity.
To develop a rocket with a burnout velocity of 1000 m/s, the specific impulse (Isp) required needs to be calculated. The exit velocity (Ve or Vj) required for the rocket can be determined using the rocket motor equation. The burn time of the rocket can be found by considering the rocket's weight and acceleration over time.
Additionally, the speed of the rocket, assuming a flight path angle of 45 degrees and considering gravity, can be plotted.
1. Calculating Required Isp:
To calculate the required Isp, we use the rocket motor equation: Ve + (Pe - Pa)AC = (m0 / mf) * g0 * Isp, where Ve is the exit velocity, Pe is the pressure at the exit, Pa is the ambient pressure, AC is the throat cross-sectional area, m0 is the initial total mass (rocket weight + propellant weight), mf is the final total mass (rocket weight), g0 is the acceleration due to gravity, and Isp is the specific impulse.
Since the contribution of the pressure differential is ignored, the equation simplifies to Ve = (m0 / mf) * g0 * Isp.
Given the burnout velocity of 1000 m/s, we can substitute the values and solve for Isp.
2. Determining Exit Velocity:
Using the rocket motor equation and the burnout velocity, we can solve for the exit velocity (Ve). This value represents the speed at which exhaust gases leave the rocket nozzle.
3. Plotting Rocket Acceleration and Weight:
To plot the rocket acceleration as a function of time, we need to consider the mass of the rocket over time. Initially, the rocket weight is the sum of the rocket weight (300 kg) and propellant weight (800 kg). As the propellant burns, the rocket weight decreases, resulting in a changing acceleration.
4. Calculating Burn Time:
The burn time of the rocket can be determined by dividing the propellant weight (800 kg) by the propellant consumption rate, which is the mass flow rate of the propellant.
5. Plotting Rocket Speed:
Assuming a flight path angle of 45 degrees and neglecting gravity, the rocket's speed can be plotted over time. This plot represents the rocket's horizontal velocity.
6. Considering Gravity:
To plot the rocket's speed while considering gravity, we need to account for the vertical acceleration due to gravity. By considering the rocket's horizontal and vertical velocities, we can determine the overall speed of the rocket.
By following these steps, the required Isp, exit velocity, burn time, and velocity plots can be determined for the given rocket scenario.
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What is the frequency of a raido wave with a wavelength of 1.0 mm?
Answer:
3×10^6
Explanation:
frequency is the speed of light ( c) which is a constant number divided the wavelength
f = 3×10^6 / 1.0
Magnets are a mystery to scientists because scientists.
Magnetism is a mysterious force in this universe. Scientists don't fully understand why it occurs in the first place. They aren't sure why these particles have a north and south direction either, according to Live Science, and there are many different forms of magnetism.
What are magnets ?Anything that creates a magnetic field is considered to be a magnet. The most notable characteristic of a magnet is a force that pulls on other ferromagnetic materials, such as iron, steel, nickel, cobalt, etc., and attracts or repels other magnets. This invisible magnetic field is responsible for this property.
A substance or object that generates a magnetic field that has the potential to impact objects nearby. Magnetic materials, such as iron, are drawn to a magnet. A magnetic field is always present in permanent magnets. One of a magnet's two poles is its centre of the magnetic field.
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Which characteristics might make some moons of jupiter suitable for life?.
There are several characteristics that might make some moons of Jupiter suitable for life. Firstly, the presence of liquid water is crucial for life, and it is believed that some of the moons of Jupiter have subsurface oceans of liquid water.
These include Europa, Ganymede, and Callisto. Secondly, these moons have a source of heat from Jupiter's strong gravitational pull, which could potentially provide the energy needed to support life. Additionally, some of these moons have been found to have organic molecules, which are building blocks of life. Finally, the lack of a thick atmosphere on these moons could make it easier for life to develop and survive.
Overall, these characteristics make some moons of Jupiter intriguing targets for future exploration and the search for extraterrestrial life.
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A wooden block of 16N is placed on a rough surface. If the coefficient of friction between both surface is 0.25,the least horizontal force required to move the block is?
The least horizontal force required to move the block is 4.0 N.
What is static friction?A force that holds an object at rest is called static friction.
The definition of static friction is: The resistance people feel when they attempt to move a stationary object across a surface without actually causing any relative motion between their body and the surface they are moving the object across.
Weight of the block = 16 N
The coefficient of friction between both surface is 0.25,
Hence, the least horizontal force required to move the block is = frictional resistance force
= 0.25 × 16 N
= 4 N.
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A plane flies 408 mi with the wind in 3 hr. The return trip takes 4 hr. What is the speed of the wind and the speed of the plane in still air? Part 1 of 2 The speed of the plane in still air is Part 2
The speed of the wind is 17 mph and the speed of the plane in still air is 119 mph.
Let the speed of the plane be x and the speed of the wind be y. Then, the speed of the plane with the wind becomes x + y, while the speed of the plane against the wind is x - y.
The distance traveled with the wind in 3 hours is 408 miles.
Therefore, we can write the equation as:
3(x + y) = 408
Divide both sides by 3:
x + y = 136 .... (1)
The distance traveled against the wind in 4 hours is also 408 miles.
Therefore, the equation can be written as:
4(x - y) = 408
Divide both sides by 4:
x - y = 102 .... (2)
Now we can solve these two equations using the elimination method.
Add equations (1) and (2):
x + y + x - y = 136 + 1022x = 238x = 119 mph
Therefore, the speed of the plane in still air is 119 mph.
Now, substitute this value of x in equation (1):
119 + y = 136y = 17 mph
Therefore, the speed of the wind is 17 mph.
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The correct question is:
A plane flies 408 mi with the wind in 3 hr. The return trip takes 4 hr. What is the speed of the wind and the speed of the plane in still air?
A force is acting on a 3-kg object during 5 seconds. If the object initially has a speed of 1.5m/s and after applying the force its speed is 4 m/s
Answer:
1.5 N
Explanation:
You've left us to guess what the question is. I will Assume it is what's the force?
Givens
m = 3 kg
vi = 1.5 m/s
vf = 4 m/s
t = 5 seconds
Formula
F = m * (vf - vi)/t
Solution
F = 3 * (4 - 1.5) / 5
F = 1.5 N
When electrons are accelerated by 2450v in an electron microscope they will have wavelengths of
a)8.113nm
b)0.622nm
c)0.811nm
A B-52 bomber jet flies at a horizontal velocity of 286.2 m/s and at an altitude of 7500 m above the ground. How far away horizontally should a payload be dropped to land on a target?
Answer:
11196.14 m
Explanation:
From the question given above, the following data were obtained:
Horizontal velocity (u) = 286.2 m/s
Height (h) = 7500 m
Horizontal distance (s) =?
Next, we shall determine the time taken for the payload to get to the target. This can be obtained as follow:
Height (h) = 7500 m
Acceleration due to gravity (g) = 9.8 m/s²
Time (t) =?
h = ½gt²
7500 = ½ × 9.8 × t²
7500 = 4.9 × t²
Divide both side by 4.9
t² = 7500 / 4.9
Take the square root of both side
t = √(7500 / 4.9)
t = 39.12 s
Finally, we shall determine the horizontal distance as follow:
Horizontal velocity (u) = 286.2 m/s
Time (t) = 39.12 s
Horizontal distance (s) =.?
s = ut
s = 286.2 × 39.12
s = 11196.14 m
Thus the payload will travel 11196.14 m horizontally in order to hit the target
t/-15=-3. what is t?
Answer:
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What is the frequency of a mechanical wave that has a
velocity of 1.70 m/s and a wavelength æf 12.05 m?
Explanation:
v= (f) x ( lambda)
1.7 ms^-1/12.05 m = f =o.14 hz
A boy pushes a cart with a constant velocity of 0.5m/s by applying a force of 60 N. What is the total frictional force acting on the cart?
Answer:
The total frictional force equals 60 N
Explanation:
We know that F - f = ma where F is the applied force, f is the frictional force, m the mass of the object and a its acceleration.
Now, since the cart moves with constant velocity, its acceleration is zero. So, a = 0.
So F - f = ma
F - f = m(0) = 0
F - f = 0
So, F = f
From the above, we see that the frictional force equals the applied force which is equal to 60 N.
So, f the total frictional force equals 60 N
A positive charge of 1 µC is taken from points A & B such that VA-VB = 100 V. Then the
energy of charge increases by 10-3 J
energy of charge decreases by 10-3 J
energy of charge remains unchanged
energy of charge decreases by 103
Explanation:
It is given that,
Let Charge of \(1\ \mu C\) is taken from points A & B such that \(V_A-V_B=1000\ V\).
We need to find the energy of charge. Electric potential is defined as the work done per unit of electric charge. So,
\(W=(V_B-V_A)q\\\\W=-1000\times 10^{-6}\\\\W=E=-10^{-3}\ J\)
So, the energy of charge decreases by \(10^{-3}\ J\). Hence, the correct option is (a).
What are the five types of contact forces?
Answer:
Applied force
Normal force
Frictional force
Tension force
Wind force
Answer: Reaction force. An object at rest on a surface experiences reaction force .
Tension. An object that is being stretched experiences a tension force.
Friction. Two objects sliding past each other experience friction forces. ...
Air resistance. An object moving through the air experiences air resistance .
Gravitational Force.
Explanation:
How many electrons fill the outer shell of the smallest four elements ( H, He, Li, & Be)?
Just one electrons fill the outer shell of the smallest four elements( H, He, Li, & Be).
What is an element?A chemical element is a described as chemical substance that cannot be broken down into other substances.
The elements Hydrogen (H), lithium (Li), and sodium (Na), are group 1 elements and are called inert gases or noble gases because of their non-reactivity, hence have just one electron in their outermost shells.
Elements has properties and the properties include, but are not limited to, conductivity, magnetism, melting point, boiling point, color, state of matter, and others.
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How can red giants be so bright when they are so cool
Answer:
The star's luminosity rises above its previous level. Because it is so cool, the surface will be red, and it will be much farther away from the center than it was during the earlier stages of star evolution. Despite its lower surface temperature, the red giant has a large surface area, which makes it very luminous.
The wine poured in the pot_______ heat,. Increasing in its molecular collisions that overcome the intermolecular attraction forces. Almost immediately, part of the wine_______. You cover the pot with a lid, to let the beef cook slowly and become tasty
Heat the saucepan after the wine has been added. Growing molecular collisions that defeat the forces of intermolecular attraction. A portion of the wine starts to boil away almost instantly.
What's a good illustration of molecular attraction?Example: The polar H2O molecules are drawn to the sodium and chloride ions in the beaker when NaCl and water are combined there. This interaction's potency is determined by: how big the dipole moment is.
What draws molecules together?
Polar molecules line up so that their positive ends interact with each other's negative ends. Unlike the atoms' covalent bonds in a molecule (intramolecular bonding)
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it is currently believed that superclusters lie on the surfaces of "bubbles" in space. (True or False)
True. It is currently believed that superclusters of galaxies lie on the surfaces of vast cosmic voids or "bubbles" in space. These voids are regions of space that are largely empty of matter, with the galaxies and galaxy clusters tending to cluster around the edges of these voids.
The largest known of these voids is the Boötes void, which is approximately 250 million light-years in diameter and contains very few galaxies. The idea that superclusters are located on the surfaces of these voids is supported by observations of the large-scale structure of the universe, including the distribution of galaxies and cosmic microwave background radiation.
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What type of energy is thermal energy? A. Sound energy B. Chemical energy C. Kinetic energy D. Nuclear energy
Answer:
kinetic energy
Explanation:
gas expands when 591 J of energy is added to it as heat. The expanding gas does 431 J of work on its surroundings.
(a) What is the overall change in the internal energy of the gas?
J
(b) If the work done by the gas were equal to 1102 J (rather than 431) J), how much energy would need to be added as heat in order for the change in internal energy to equal the change in internal energy in part (a)?
Let us cut the work done on gas as we move along the direct path
W=-(-area undercurve),=-[(1.00atm)(4.l-2)+1/2(4-1)(4-2)],W=-5atm
The change in internal energy=-88.5J
What does physics mean by internal energy?
In thermodynamics, internal energy is a property or state functional that characterises a substance's energy in the absence of capillary effects and the impacts of external magnetic, electric, and other fields.
What makes it internal energy?
Internal Energy is the energy in a thermodynamics that is NOT either the system's total kinetic energy or the gravitational potential energy. The system's internal freedom levels are connected to the internal energy.
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how far does an object move in 1 second
It accelerates at about 32 feet per second every second, so it starts falling at zero feet per second and, one second later it is traveling at 32 feet per second. That means that its average speed is 16 feet per second, so it will fall 16 feet in the first second.
. as outlined below, a 2-kg bob is compressed 60-cm against a 50 n/m spring while on the other side a 3-kg block is placed 4-m up along a 30 degree incline. both objects are then released from rest. assuming all surfaces are frictionless: a. what will be the velocity of each object before they collide? (10pts) b. if the collision between the objects is elastic, what will be the velocity of each object after the collision? (10pts) c. if either (or both) of the objects moves toward the spring after the collision, determine how much the spring will be compressed by the object(s) (10pts) d. if either (or both) of the objects moves toward the incline after the collision, determine how far up the incline the object(s) will travel (10pts)
a. To determine the velocity of each object before they collide, we can apply conservation of mechanical energy.
For the 2-kg bob compressed against the spring, the potential energy stored in the spring when compressed is given by:
PE_spring = 0.5 * k * x^2,
where k is the spring constant (50 N/m) and x is the compression distance (0.6 m).
PE_spring = 0.5 * 50 N/m * (0.6 m)^2 = 9 J
The potential energy is converted entirely into kinetic energy before the collision:
KE_bob = PE_spring = 9 J
Using the formula for kinetic energy:
KE = 0.5 * m * v^2,
where m is the mass and v is the velocity, we can solve for the velocity of the 2-kg bob:
9 J = 0.5 * 2 kg * v^2
v^2 = 9 J / 1 kg
v = √(9 m^2/s^2) = 3 m/s
Therefore, the velocity of the 2-kg bob before the collision is 3 m/s.
For the 3-kg block on the incline, we can determine its velocity using the conservation of potential and kinetic energy.
The potential energy at the top of the incline is given by:
PE_top = m * g * h,
where m is the mass (3 kg), g is the acceleration due to gravity (9.8 m/s^2), and h is the height (4 m).
PE_top = 3 kg * 9.8 m/s^2 * 4 m = 117.6 J
The potential energy is converted into kinetic energy:
KE_block = PE_top = 117.6 J
Using the formula for kinetic energy, we can solve for the velocity of the 3-kg block:
117.6 J = 0.5 * 3 kg * v^2
v^2 = 117.6 J / 1.5 kg
v = √(78.4 m^2/s^2) ≈ 8.85 m/s
Therefore, the velocity of the 3-kg block before the collision is approximately 8.85 m/s.
b. If the collision between the objects is elastic, the total momentum before the collision is equal to the total momentum after the collision.
Total momentum before the collision:
P_before = m1 * v1 + m2 * v2,
where m1 and m2 are the masses, and v1 and v2 are the velocities.
P_before = (2 kg * 3 m/s) + (3 kg * 8.85 m/s)
P_before ≈ 36.55 kg·m/s
Since the collision is elastic, the total momentum after the collision remains the same.
Total momentum after the collision:
P_after = (2 kg * v1') + (3 kg * v2'),
where v1' and v2' are the velocities after the collision.
We need to solve this equation for v1' and v2'. More information is required about the nature of the collision (head-on or at an angle) to determine the specific velocities after the collision.
c. To determine how much the spring will be compressed by the object(s) after the collision, we need to consider the conservation of mechanical energy.
The total mechanical energy after the collision is equal to the sum of potential and kinetic energy:
Total Energy_after = PE_spring + KE_bob,
where PE_spring is the potential energy stored in the spring and KE_bob is the kinetic energy of the 2-kg
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3. In order to follow proper golf etiquette there should be no more than
players in your party.
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calculate how long tt takes for tennis ball to reach the ground and the tennis ball is droped height 3m and bounce book to a height of 7m
Answer:
0.59 seconds
Explanation:
To find the time it takes for a tennis ball to reach the ground and bounce back to a height of 7 meters, we need to use the formula for the time it takes an object to fall to the ground.
The formula for the time it takes an object to fall to the ground is given by:
t = sqrt(2 * d / g)
where t is the time it takes the object to fall, d is the distance the object falls, and g is the acceleration due to gravity.
In this case, we are given that the height from which the tennis ball is dropped is 3 meters, the height to which the ball bounces is 7 meters, and the acceleration due to gravity is 9.8 m/s^2. We can use these values to solve for the time it takes for the ball to reach the ground and bounce back to a height of 7 meters.
First, we need to calculate the distance the ball falls. The distance the ball falls is equal to the difference between the height from which the ball is dropped and the height to which the ball bounces:
d = H1 - H2
d = 3 - 7
d = -4
Next, we can use the formula for the time it takes an object to fall to the ground to solve for the time it takes for the ball to reach the ground and bounce back to a height of 7 meters:
t = sqrt(2 * d / g)
t = sqrt(2 * -4 / 9.8)
t = 0.59 seconds
Therefore, it takes 0.59 seconds for the tennis ball to reach the ground and bounce back to a height of 7 meters.