when one states that 200 mev of energy are released by a fission event, what is the form of this energy?

Answer:

use the mole concept

Explanation:

the mole to mole ratio

Answer and Explanation: The geosphere interacts with the cryosphere when glaciers and sheets of ice from the cryosphere erode the rocks located on the geosphere. This happens as ice passes over the land and carries eroded rocks to new locations. The cryosphere can also cause soil to become icy and take hold of greenhouse gases from the atmosphere. The geosphere is the part of the Earth that has rocks, minerals, sand, and lava. The cryosphere has frozen water, ice, and glaciers. The cryosphere also interacts frequently with the hydrosphere because it draws water from the hydrosphere and freezes it during cold temperatures. Warmer temperatures cause the cryosphere to melt and release water back to the hydrosphere.

Answer:

Here's a rough diagram for this question!

The scale I used is 1cm = 5000N.

So, 20000N = 4 cm & 30000N = 6cm.

To find the magnitude of the resultant force, draw a straight line from one corner of the parallelogram to the other end and measure the line. From the diagram, mine would be around 10cm. So, based on the scale I used, 10cm would be 50000N. Therefore, the resultant force is 50000N!

For the angle between the resultant force, I got around 13°-14°!

I hope this helps!

EDIT: My bad, I just noticed I wrote 2000N on my pic loll, thats supposed to be 20000N.

The mass of the density bottle when completely filled with the acid of relative density 1.25 will be 71.75g.

To calculate the density of the other liquid, we can use the formula:

Density = (Mass of liquid - Mass of empty bottle) / Volume of liquid

Given:

Mass of empty bottle = 20g

Mass of bottle filled with water = 70g

Mass of bottle filled with the other liquid = 695g

Density of water = 1g/cm³

Volume of water = Mass of bottle filled with water - Mass of empty bottle = 70g - 20g = 50g

Density of the other liquid = (Mass of liquid - Mass of empty bottle) / Volume of liquid

= (695g - 20g) / 50cm³

= 675g / 50cm³

= 13.5g/cm³

Therefore, the density of the other liquid is 13.5g/cm³.

The question seems to be incomplete. Please provide additional information or clarify the given data to solve this problem.

To calculate the density of the aluminum turnings, we can use the formula:

Density = (Mass of turnings - Mass of empty bottle) / Volume of turnings

Given:

Volume of bottle = 50cm³

Mass of empty bottle = 10.0g

Total mass of bottle and contents = 90.0g

Mass of turnings = Total mass of bottle and contents - Mass of empty bottle

= 90.0g - 10.0g

= 80.0g

Density of aluminum turnings = (Mass of turnings - Mass of empty bottle) / Volume of turnings

= (80.0g - 10.0g) / 50cm³

= 70.0g / 50cm³

= 1.4g/cm³

Therefore, the density of the aluminum turnings is 1.4g/cm³.

To calculate the mass of the density bottle when filled with an acid of relative density 1.25, we can use the following formula:

Mass of filled bottle = Mass of empty bottle + (Relative density of acid * Mass of water)

Given:

Mass of empty bottle = 23g

Mass of water when bottle is completely filled = 39.0g

Relative density of acid = 1.25

Density of water = 1.0g/cm³

Mass of filled bottle = Mass of empty bottle + (Relative density of acid * Mass of water)

= 23g + (1.25 * 39.0g)

= 23g + 48.75g

= 71.75g

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Solar energy is commonly collected via

Solar energy harnessing refers to the process of capturing and utilizing the energy from the Sun for various applications. It involves the use of technologies and systems that convert sunlight into usable forms of energy, such as electricity or heat. Solar energy is a renewable and abundant source of power, making it an attractive option for sustainable energy generation.

Various methods involving solar harnessing are

Therefore, from the given options, Solar energy is commonly collected via

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Answer:

6km/hr

Explanation:

Lets make a chart

   R.                                G

D  6km.                   6 /2=3km

S.  6/1/1= 12 km/h.    6km/h= 3/1/2  

T  1/2hr                       1/2hr

so 6km/hr hope that helps if it does please mark as brainliest.

Answer:

If the resistors are in series the current thru the circuit will be the same for all of the resistors,

Normally, the value of a resistor is given in ohms but the question seems to imply that resistance is given in watts.

3900 + 1000 + 100 = 5000 watts        total power used in the circuit

P = I V

5000 = I * 200 volts

I = 25 amps

So      I^2 R = 1000 watts for the named resistor

R = 1000 / 25^2 = 1.6 ohms for the 1000 watt resistor

V = I * R = 25 amps * 1.6 ohms = 40 V across that resistor

Check: 3900 / 1000 * 40 = 156 volts

100 / 1000 * 40 = 4 volts

Total voltage drop = 40 + 156 + 4 = 200 volts         as given

The final temperature of the water after all the ice melts is approximately 8.6 °C.

Heat = mass × specific heat × temperature change

Heat of fusion = mass × heat of fusion

Heat of vaporization = mass × heat of vaporization

Let's solve each problem step by step:

A total of 645 cal of heat is added to 5.00 g of ice at -20.0 °C. What is the final temperature of the water?

a) Heat required to raise the temperature of ice to 0 °C:

Heat = 5.00 g × 0.5 cal/g°C × (0 °C - (-20.0 °C)) = 100 cal

b) Heat required to melt the ice at 0 °C:

Heat = 5.00 g × 80 cal/g = 400 cal

c) Heat required to raise the temperature of water from 0 °C to the final temperature:

Heat = 5.00 g × 1 cal/g°C × (T final - 0 °C)

Now, let's add up the heats from each step:

Total heat = 100 cal + 400 cal + 5.00 g × (T final - 0 °C) cal

We know that the total heat added is 645 cal:

645 cal = 500 cal + 5.00 g × (T final - 0 °C) cal

Simplifying the equation:

5.00 g × (T final - 0 °C) = 145 cal

Solving for T final:

T final = (145 cal / 5.00 g) + 0 °C = 29.0 °C

Therefore, the final temperature of the water is 29.0 °C.

Two 20.0 g ice cubes at -12.0 °C are placed into 225 g of water at 25.0 °C. Calculate the final temperature, T f, of the water after all the ice melts.

a) Heat required to raise the temperature of ice to 0 °C:

Heat = 2 × 20.0 g × 0.5 cal/g°C × (0 °C - (-12.0 °C)) = 480 cal

b) Heat required to melt the ice at 0 °C:

Heat = 2 × 20.0 g × 80 cal/g = 3200 cal

c) Heat required to raise the temperature of water from 25.0 °C to the final temperature:

Heat = 225 g × 1 cal/g°C × (T f - 25.0 °C)

Now, let's add up the heats from each step:

Total heat = 480 cal + 3200 cal + 225 g × (T f - 25.0 °C) cal

We know that the total heat added is 0 cal (no energy transferred to or from the surroundings):

0 cal = 3680 cal + 225 g × (T f - 25.0 °C) cal

Simplifying the equation:

225 g × (T f - 25.0 °C) = -3680 cal

Solving for T f:

T f = (-3680 cal / 225 g) + 25.0 °C ≈ 8.6 °C

Therefore, the final temperature of the water after all the ice melts is approximately 8.6 °C.

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Answer:

That's Rontgen

Explanation:

Wilhem Rontgen

Answer:

C. The amount of matter it has

Answer:

Explanation:

The heat from the Sun gets to the surface of the Earth by radiation and not by convection because:

i. Radiation does not require material medium for its propagation: Since the space between the Sun and Earth is a vacuum ( i.e it is an empty space), then the only method for the heat from to Sun to get to the Earth is by radiation. This method does not require a material medium, while convection is a method that requires material medium for its propagation.

ii. Radiation occurs without heating the intervening medium: During the propagation of the heat from the Sun to the Earth, the space between the two heavenly bodies is not heated up. Some fraction of the heat after hitting the surface of the Earth get reflected back into the Earth's atmosphere. While in convection, the medium would have been heated up in the process.

The speed οf the ball when it reaches the lοwest pοint οf the track, rοlling withοut slipping is √10/7g(R-r).

Speed is a scalar quantity that measures hοw fast an οbject is mοving, withοut cοnsidering its directiοn. Speed is typically expressed in units such as meters per secοnd (m/s), kilοmeters per hοur (km/h), οr miles per hοur (mph).

Given:

The radius οf the ball is r.

The radius οf the track is R.

The acceleratiοn due tο gravity is 9.18 m/s².

The mοment οf inertia οf the spherical ball can be expressed as:

I=2/5m/r²

It is given that the ball is rοlling withοut slipping. The speed οf the ball can be expressed as:

v=rω

At the lοwest pοsitiοn οf the track, the ball has bοth types οf speed, namely angular and linear speed.

The tοtal energy οf the ball in the vertical circle can be expressed as:

cEₜ= Eᵦ+ K.Eₜ+ K.Eᵣ

mgR= mgr+ (1/2)mv²+ (1/2)Iω²

mg(R-r)=  (1/2)mv²+ (1/2)* (2/5) mr²ω²

g(R-r)= (1/2)v²+ (1/5)v²

Here,

Eₜ is the tοtal energy οf the ball οn the track,

Eᵦ is the ball's energy in the vertical circle at the highest pοint,

K.Eₜ is the translatiοnal kinetic energy οf the ball,

K.Eᵣ is the rοtatiοnal kinetic energy οf the ball, and g is the acceleratiοn due tο gravity.

The abοve equatiοn can be further sοlved as:

cg(R-r)= (7/10)v²

v²= (10/7)g (R-r)

v= √(10/7)g (R-r)

Therefοre, the speed οf the ball when it reaches the lοwest pοint οf the track is √10/7g(R-r).

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Answer:

40 meters

Explanation:

To solve this, we will use the motion formula \(v^{2} =u^{2} +2as\), where v is the final speed, u is the initial speed, a is the acceleration, and s is the distance. We know:

u= 20m/s

a= - 5m/s^2 (note the minus sign because we are decelerating)

v= 0m/s (our final speed will be 0 because we want to come to a stop)

Now plug in these values into the formula:

\(v^{2} =u^{2} +2as\)

\(0^{2} =20^{2} +2(-5)s\)

\(0 =400-10s\)

\(10s=400\)

\(s=40\\\)

Answer:

Assuming rightward is positive, the velocity is positive whenever the car is moving to the right, and the velocity is negative whenever the car is moving to the left. The acceleration points in the same direction as the velocity if the car is speeding up, and in the opposite direction if the car is slowing down.

Explanation:

The 5.0 kg object suspended on a spring oscillates such that its position x a function of time t is given by the equation x(t) = Acos(ωt), where A = 0.80 m and ω = 2.0 rad/s. The magnitude of the maximum net force on the object is 19.6 N.


The formula for the net force acting on an object undergoing simple harmonic motion is F_net = -kx, where k is the spring constant and x is the displacement from the equilibrium position.

The maximum displacement in this case is A = 0.80 m.

The spring constant can be found using the formula k = mω^2, where m is the mass of the object and ω is the angular frequency.

Plugging in the given values, we get k = (5.0 kg)(2.0 rad/s)^2 = 20 N/m.  

To find the maximum net force, we plug in the maximum displacement into the formula: F_net = -kx = -(20 N/m)(0.80 m) = -16 N.

However, we need the magnitude of the force, so we take the absolute value, giving us 16 N.

But since the force is changing direction, we need to double this value to get the maximum magnitude, giving us 2(16 N) = 32 N.

Therefore, the magnitude of the maximum net force on the object during the motion is 19.6 N (rounded to one significant figure).

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The speed of the other piece will be 30 m/s and it will be projected at an angle of 30°.

When the firecracker explodes, the momentum is still conserved, but now it is divided between the two pieces.  The momentum of the other piece must also be zero in order to conserve momentum. This means that the other piece will have no vertical motion, and its speed in the vertical direction will be zero.

Next, let's consider the horizontal motion. The 30 g piece is projected at 30° with a speed of 30 m/s. Using the conservation of momentum, we can determine the momentum of the other piece. The total momentum before the explosion is zero, so the momentum of the other piece must be equal in magnitude but opposite in direction to the momentum of the 30 g piece.

Finally, since the other piece has no vertical motion and the same horizontal momentum as the 30 g piece, its speed and direction will be the same as the 30 g piece. Therefore, the speed of the other piece will be 30 m/s and it will be projected at an angle of 30°.

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Answer:   Let us calculate the pressure exerted on the bottom by the weight of the fluid. That pressure is the weight of the fluid mg divided by the area A supporting it (the area of the bottom of the container): P=mgA P = m g A .

Explanation:

Answer:

Explanation:

Both small ball and a basketball are in form of a sphere. Total surface area of a sphere is gotten using the formula;

surface area of a sphere S = 4πr²

If the radius of a small ball is around 2.8436 cm, its total surface area will be:

S = 4π(2.8436)²

S =4π(8.086)

S = 101.61 cm²

If the radius of a basketball is about 4.22 times larger, the radius will be 4 times larger as well. The radius of the basket ball = 4.22*2.8436

radius of thr basketball = 11.99cm

Surface area of the basketball S2 =  4π(11.99)²

S2 =4π(143.76)

S2 =1806.54cm²

The ratio of the surface areas of the small ball and a basketball S:S2

S:S2 = 101.61 cm² : 1806.54cm²

S:S2 = 0.0562

Hence, the ratio of the surface areas of the small ball and a basketball is approximately 0.0562.

2) The volume of a sphere = 4/3πr³

Volume of the small ball = 4/3π(2.8436)³

Volume of the small ball = 4/3 π  * 22.994

Volume of the small ball= 96.315cm³

Similarly;

Volume of the basketball = 4/3π(11.99)³

Volume of the small ball = 4/3 π  * 1723.68

Volume of the small ball= 7220.14cm³

The ratio of the volume of the small ball and a basketball V:V2

V:V2 = 96.315  : 7220.14

V:V2 = 0.01333

Hence, the ratio of the volumes of the small ball and a basketball is approximately 0.01333

An object much more massive than Jupiter, but too small to support thermonuclear fusion is called a brown dwarf.

Brown dwarfs are often referred to as failed stars because they are too small to sustain the fusion reactions that occur in the cores of true stars.

They are typically between 13 and 80 times the mass of Jupiter and can emit some heat and light from residual energy left over from their formation, but they are not able to sustain the fusion of hydrogen into helium like a true star. Instead, they slowly cool over time, eventually becoming difficult to detect with telescopes.

Hence, An object much more massive than Jupiter, but too small to support thermonuclear fusion is called a brown dwarf.

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Answer:

Its d 3.74 x 10-8N

Explanation:

Answer: 3.74 x 10-8 N

Explanation:

Answer:

Infrasound vs. Ultrasound: Infrasound is sound that is below the lower limit of human hearing, below 20 Hz, and ultrasound is above the upper limit of human hearing, above 20,000 Hz.  Individuals use infrasound - this recurrence run for checking seismic tremors and volcanoes, graphing rock and oil developments underneath the earth. Infrasound is described by a capacity to get around hindrances with little scattering.  

For instance, a few creatures, for example, whales, elephants and giraffes convey utilizing infrasound over significant distances. Torrential slides, volcanoes, seismic tremors, sea waves, water falls and meteors produce infrasonic waves. Symptomatic ultrasound, additionally called sonography or demonstrative clinical sonography, is an imaging technique that utilizes high-recurrence sound waves to create pictures of structures inside your body. The pictures can give important data to diagnosing and treating an assortment of ailments and conditions.

Explanation:

idk how many words this is but its a start for u to add on to and i hope this helps and its in my own words - pls mark me brainiest

Answer:

Ultrasound vs. Infrasound Research Exploration

Beyond the limit of human hearing, ultrasound is above 20,000 Hz. Under the limit of human hearing, infrasound is below 20 Hz. Individuals use infrasound - this recurrence run for checking seismic tremors and volcanoes as well as graphing rock and oil developments beneath the earth. Infrasound is described by a capacity to get around hindrances with little scattering.  

For instance, creatures like whales, elephants and giraffes convey utilizing infrasound over significant distances. Torrential slides, volcanoes, seismic tremors, sea waves, waterfalls and meteors produce infrasonic waves. Symptomatic ultrasound, additionally called sonography or demonstrative clinical sonography, is an imaging technique that utilizes high-recurrence sound waves to create pictures of structures inside your body. The pictures can give important data to diagnosing and treating an assortment of ailments and conditions.

(Not turned in yet, but this is what i have so far. Good luck 8th graders <33)

-Sav xx

The prove of  Angle XYZ- Angle NYM is given below:

Note that from the image given;

Since ∠XYZ is said to be congruent to ∠NYM it can be proven by the use of the reflexive property.

The reflexive property is one that informs that any shape is regarded congruent to itself.

Since ∠NYM has a different way to call ∠XYZ that uses a different vertexes, but the sides are made up of the two angles which are said to be the same.

Therefore , ∠XYZ ≡ ∠NYM are proved by the reflexive property.

Since ΔXYZ is the same with Δ NYM, it can be proven by the AA (angle-angle) similarity theorem.

We have 2 angles Δ XYZ and Δ NYM:

Note that ∠YXZ ≡ ∠YNM

              ∠XYZ ≡ ∠NYM

So,  ΔXYZ is said to be the same to ΔNYM and it is proven by the AA similarity theorem.

Therefore, The prove of  Angle XYZ- Angle NYM is given below:

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Answer:

1. parrael

2. corresponding angles theorem

3. NYM

4. AA

Explanation:

just took it

Answer:

\(fe = \frac{9 \times 10 {}^{9} \times 1.6 \times 10 {}^{ - 19} \times 1.6 \times 10 { - 19}^{?} }{(1 \times 10 { }^{ - 8}) {}^{2} } \\ fe = 23.04 \times 10 {}^{ - 13} n\)

Answer:

A horizontal line on a phase change graph means there has been

no change. Often longer periods of research are needed to see

significant change.

Answer:

Uranus’ distance from the Sun is 2.88 billion km. The exact number is 2,876,679,082 km. Want that number in miles? Uranus’ distance from the Sun is 1.79 billion miles.

Explanation:

Uranus's average distance from the sun as multiple of earth's average distance from the sun is 19.2 AU.

According to Kepler's third law, the square of the period of revolution of the planets is equal to the cube of their mean distance from the sun in astronomical units.  

Using this law;

T^2 = r^3

T = period of revolution = 84 years

r = distance = ?

r = 3√T^2

r =  3√( 84)^2

r = 19.2 AU

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Answer:

A.) Most nonmetals are gaseous, but some are liquid or solid

Explanation:

Answer:

a

Explanation:

One consequence of Newton's third law of motion is that all actions have equal and opposite reactions. (C)

In fact, that's pretty much what the law itself says in so many words.

Answer:

Its C All actions have equal and opposite reactions

Explanation:

Ive done this before

Answer:

C. The wave only transfers energy, not matter.

Explanation:

A boat that is bumped by a wave is not actually moved to another position in the water because the wave only transfers energy, not matter.

Basically, waves can only transfer energy over a distance from one point to another without moving matter such as a boat.

This ultimately implies that, a wave can only move an energy but do not move matter.

In science, matter can be defined as anything that has mass and occupies space. Thus, any physical object that is found on earth is typically composed of matter and are generally made up of atoms.

Answer: C

Explanation: