When scientists are ready to publish the results of their experimentation, why is it important for them to include a description of the procedures they used?
To qualify for publication, scientists are required to submit lists of materials and procedures.
To be accepted by other scientists, results of experiments must be published in journals that require descriptions of procedures.
To be valid, experiments must be able to be repeated by other scientists.
Answers
Answer: To be valid, experiments must be able to be repeated by other scientists.
Answer:
Answer is C) To be valid, experiments must be able to be repeated by other scientists.
Explanation:
Related Questions
which has a higher melting point CH3CH2CH2CH2CH2CH3 or CH3CH2CH2CH2CH2CH2CH2CH3
Answers
Answer:
the second one
Explanation:because its higher
Answer:
CH3CH2CH2Ch2Ch2Ch3
Explanation:
That's the answer
20 POINTS!!!! HELP PLS IN A HURRY!!!!!!!!
Ionic compounds that dissolve in water conduct electricity because they break into ____ that move freely.
Answers
The equilibrium concentrations for the reaction between SO2 and O2 to form
SO3 at a certain temperature are given in the table below. Determine the
equilibrium constant and whether the reaction favors reactants, products, or
neither at this temperature.
O(g) +250 (9)
2250 (9)
[02]
[SO2)
[S03)
1.2 M
0.80 M
1.9 M
A. K = 4.7; product favored
B. K = 0.51; product favored
C. K = 0.51; reactant favored
o
D. K= 4.7; reactant favored
Answers
Answer:
A. K = 4.7; product favored
Explanation:
Step 1: Write the balanced reaction at equilibrium
O₂(g) + 2 SO₂(g) ⇄ 2 SO₃(g)
Step 2: Calculate the concentration equilibrium constant (Kc)
The equilibrium constant, Kc, is the ratio of the equilibrium concentrations of products over the equilibrium concentrations of reactants each raised to the power of their stoichiometric coefficients.
Kc = [SO₃]² / [SO₂]² × [O₂]
Kc = 1.9² / 0.80² × 1.2 = 4.7
When Kc > 1, the products are favored.
The mass of 0.550 mol of methanol, CH3OH, is _____ g (round to three significant figures)
Answers
The mass of 0.550 mol of methanol, CH3OH, is 17.6 g
To find the mass of 0.550 mol of methanol, CH3OH, we need to use the molar mass of CH3OH. The molar mass is the sum of the atomic masses of each element in the molecule, which can be found on the periodic table.
For CH3OH, we have:
- Carbon (C): 12.01 g/mol
- Hydrogen (H): 1.01 g/mol (there are 4 hydrogen atoms in CH3OH)
- Oxygen (O): 16.00 g/mol
So the molar mass of CH3OH is:
12.01 g/mol + (1.01 g/mol x 4) + 16.00 g/mol = 32.04 g/mol
This means that one mole of CH3OH weighs 32.04 grams.
To find the mass of 0.550 mol of CH3OH, we can use the following formula:
mass = number of moles x molar mass
So the mass of 0.550 mol of CH3OH is:
0.550 mol x 32.04 g/mol = 17.62 g
Rounding this to three significant figures gives us:
17.6 g
Therefore, the mass of 0.550 mol of methanol, CH3OH, is 17.6 g (rounded to three significant figures).
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Number of atoms in 2.56 moles of He
Answers
1.54 × 10²⁴ atoms He
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightChemistry
Atomic Structure
MolesAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.Stoichiometry
Using Dimensional AnalysisExplanation:Step 1: Define
[Given] 2.56 moles He
[Solve] atoms He
Step 2: Identify Conversions
Avogadro's Number
Step 3: Convert
[DA] Set up: \(\displaystyle 2.56 \ mol \ He(\frac{6.022 \cdot 10^{23} \ atoms \ He}{1 \ mol \ He})\)[DA] Multiply [Cancel out units]: \(\displaystyle 1.54163 \cdot 10^{24} \ atoms \ He\)Step 4: Check
Follow sig fig rules and round. We are given 3 sig figs.
1.54163 × 10²⁴ atoms He ≈ 1.54 × 10²⁴ atoms He
When using PCR to study DNA, primers attach to the exposed base pairs and begin to form double-stranded DNA. What stage of the process does this MOST accurately describe
Answers
The stage that this most accurately describes while using the PCR is the initiation of DNA synthesis, also known as the denaturation stage.
What occurs in the denaturation stage?In the denaturation stage of Polymerase Chain Reaction (PCR), the double-stranded DNA template is heated to a high temperature to separate the two complementary strands and create single-stranded DNA. The denaturation stage is the first step in the PCR cycle.
In this stage, the heat-stable DNA polymerase denatures the DNA and the primers anneal to the complementary single-stranded template. This marks the beginning of the extension stage, where the DNA polymerase synthesizes new complementary strands along the template DNA.
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Which form of energy increases in an object as you raise it higher off the ground?
A. Electrical
B. Kinetic
C. Mechanical
D. Potential
Answers
Answer:
D. Potential
Explanation:
Answer:
Potential
Explanation:
Gravitational potential is the energy the object has of it's position of the earth's surface. When the object is lifted, work is done. When work is done in raising the height of an object, energy is transferred as a gain in the gravitational potential energy of the object.
Question (1 point)
Given the model, answer the following questions regarding effusion. The orange spheres have a greater root-mean-square speed than the blue spheres. Assume the balloon has a tiny opening for gas molecules to escape.
1st attempt
Part 1 ( 0.5 point)
See Periodic Table See Hint
Which balloon, A or B, most accurately illustrates the effusion of a gas from the central balloon?
Calculate the relative rate of effusion for the orange to blue spheres. The root-mean-square speed for the orange spheres is 495.0m/s. The root-meah-5quare speed for the blue spheres is 380.0m/ s.
Answers
According to the claim, Balloon A, which has more blue and less orange, exhibits accurate effusion at a relative effusion rate of 1.303. (orange is 1.303 times more effused than blue).Relative rate of effusion for the orange to blue spheres = 1.531.
What is effusion ?The process of effusion is when a gas escapes from a container through a hole that is significantly smaller in diameter than the molecules' mean free path.
Gas molecules flow through a small opening in one container and into another by effusion. Graham's law allows rates of effusion to be compared at the same temperature. Diffusion is the random molecular motion-based movement of gas molecules through one or more other types of gas.
Rate of effusion of Orange / Rate of effusion of blue
= [Mblue / Morange]^1/2
Vrms = sqrt [(3RT/M)]
Vorange / Vblue = [ Mblue / Morange]^1/2
Rate of effusion of Orange / Rate of effusion of blue
= 565/ 369
= 1.531
Thus, Balloon A, which has more blue and less orange, exhibits accurate effusion at a relative effusion rate of 1.303.
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What can an author use to give the reader more information about a
character?
A. Information about the author's previous works
B. Information about how a story's central conflict will be resolved
C. Information about the character's social status
D. Information about events in a story that are true
SUBMIT
Answers
Answer:
the answer is C. Information about the character's social status
Calculate either [H3O+] or [OH−] for each of the solutions at 25 °C. Solution A: [OH−]=3.29×10−7 M; [H3O+]= _________M Solution B: [H3O+]=9.63×10−9 M; [OH−]= ____________M Solution C: [H3O+]=6.49×10−4 M; [OH−]= __________M Which of these solutions are basic at 25 °C? Solution A: [OH−]=3.29×10−7 M Solution C: [H3O+]=6.49×10−4 M Solution B: [H3O+]=9.63×10−9 M
Answers
Solution A and B are BASIC
\(\begin{gathered} solution\text{ A: }[H_3O^+]=3.039\times10^{-8}M \\ solution\text{ B: }[OH^-]=1.038\times10^{-6}M \\ solution\text{ C: }[OH^-]=1.54\times10^{-11}M \end{gathered}\)Explanations:Using the formula below to determine the concentration of the hydroxonium ion;
\(\begin{gathered} [H_3O^+][OH^-]=1\times10^{-14} \\ [H_3O^+]=\frac{1\times10^{-14}}{3.29\times10^{-7}} \\ [H_3O^+]=\frac{1}{3.29}\times10^{-14-(-7)} \\ [H_3O^+]=0.3039\times10^{^{-7}} \\ [H_3O^+]=3.039\times10^{-8}M \end{gathered}\)Determine the pH
\(\begin{gathered} pH=-log[H_3O] \\ pH=-log(3.039\times10^{-8}) \\ pH=-(-7.5) \\ pH=7.5 \end{gathered}\)This shows that the solution A is BASIC since the pH is greater than 7
For solution B
\(\begin{gathered} [OH^-]=\frac{1\times10^{-14}}{[H_3O^+]} \\ [OH^-]=\frac{1\times10^{-14}}{9.63\times10^{-9}} \\ [OH^-]=0.1038\times10^{-5}M \\ [OH^-]=1.038\times10^{-6}M \end{gathered}\)Determine the pH
\(\begin{gathered} pH=-log[H_3O^+] \\ pH=-log(9.63\times10^{-9}) \\ pH=-(-8.02) \\ pH=8.02 \end{gathered}\)This shows that the solution B is BASIC since the pH is greater than 7
For the solution C
\(\begin{gathered} [OH^-]=\frac{1\times10^{-14}}{[H_3O^+]} \\ [OH^-]=\frac{1\times10^{-14}}{6.49\times10^{-4}} \\ [OH^-]=0.1540\times10^{-10}M \\ [OH^-]=1.54\times10^{-11}M \end{gathered}\)Determine the pH of the solution C
\(\begin{gathered} pH=-log[H_3O^+] \\ pH=-log(6.49\times10^{-4}) \\ pH=-(-3.19) \\ pH=3.19 \end{gathered}\)Since the pH of the soution C is less than 7, hence the solution C is ACIDIC
1. Write a balanced chemical equation, including physical state symbols, for the combustion of methane in gaseous gaseous carbon dioxide.
Answers
Answer:
CH4(g)+2O2(g)→CO2(g)+2H2O(g)
Explanation:
For a complete combustion reaction of a hydrocarbon, oxygen is always one of the reactants, and the products are always carbon dioxide and water.
A 3.00- L flask is filled with gaseous ammonia, NH3 . The gas pressure measured at 25.0 ∘C is 2.55 atm . Assuming ideal gas behavior, how many grams of ammonia are in the flask?
Express your answer to three significant figures and include the appropriate units.
Answers
Considering the ideal gas law, the mass of ammonia is 5.321 grams.
Ideal gas lawAn ideal gas is a theoretical gas that is considered to be composed of randomly moving point particles that do not interact with each other. Gases in general are ideal when they are at high temperatures and low pressures.
An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of gases:
P×V = n×R×T
Mass of ammoniaIn this case, you know:
P= 2.55 atmV= 3 Ln= ?R= 0.082 \(\frac{atmL}{molK}\)T= 25 C= 298 KReplacing in the definion of ideal gas law:
2.55 arm× 3 L = n×0.082 \(\frac{atmL}{molK}\)× 298 K
Solving:
n= (2.55 arm× 3 L)÷ (0.082 \(\frac{atmL}{molK}\)× 298 K)
n= 0.313 moles
Being the molar mass of ammonia 17 g/mole, the mass can be calculated as:
mass of ammonia= 0.313 moles× 17 g/mole
Solving:
mass ammonia= 5.321 g
Finally, the mass of ammonia is 5.321 grams.
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You want to make a photo album for your friend. In three to five sentences, describe at least one advantage and one disadvantage of choosing a digital photo album rather than a physical one. Analyze a potential solution to the disadvantage
Answers
Because digital data can be lost so easily, Atomic Theory it is essential for photographers to have at least 1 backup of each shot they intend to save for the long term.
What are digital photography's drawbacks?Higher Initial Cost: Compared to roll film cameras, greater, fully-loaded digital cameras can be a little more expensive. Battery Consumption: With digital cameras, the battery runs out more quickly. This necessitates having a few spare batteries on hand, especially while taking numerous photos.
How do you recognise probable remedies?The process of finding solutions is iterative: Start by formulating theories for potential solutions to your problem. Create a how map by structuring these hypotheses. Next, prior to performing the actual testing, choose which hypothesis you wish to test first.
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MATCH THE NAMES OF THE MICROSCOPE PARTS WITH THEIR DECRIPTIONS
Answers
The Microscope part and their right descriptions are as follows
Iris Diaphragm: A. Increases or decreases the light intensity
Objective Lens System: B. After light passes through the specimen, it next enters this lens system
Stage: C. Platform that supports a microscope slide
Adjustment Knob: D. Causes stage (or objective lens) to move upward or downward
Condenser: E. Concentrates light onto the specimen
what other parts of microscope parts and their description should you know?Other parts of a microscope and their description that you should know about includes;
Eyepiece - The lens that you look through to see the image of the specimen.
Body tube - The tube that connects the eyepiece to the objective lenses.
Arm - The part of the microscope that supports the body tube and connects it to the base.
Base - The part of the microscope that supports the arm and provides stability.
Illuminator - The light source that provides light for the microscope.
Stage clips - The clips that hold the microscope slide in place on the stage.
Revolving nosepiece - The part of the microscope that holds the objective lenses and allows them to be rotated into place.
The above answer is in response to the full question below;
Match the names of the microscope parts in column A with the descriptions in column B. Place the letter of your choice in the space provided.
1. Iris diaphram
2. Objective lens system
3. Stage
4. Adjustment knob
5. Condenser
Increases or decreases the light intensity
2. After light passes through the specimen, it next enters this lens system
3. Platform that supports a microscope slide
4. Causes stage (or objective lens) to move upward or downward
5. Concentrates light onto the specimen
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What do these two changes have in common?
cellular respiration
a piece of avocado turning brown
Select all that apply.
Both are caused by heating.
Both are chemical changes.
Submit
Both are changes of state.
Both conserve mass.
Answers
The thing that cellular respiration and a piece of avocado turning brown is that both chemical changes.
Cellular respiration is a chemical process because there occurs the change of substances. The final byproducts of cellular respiration are ATP, water, and carbon dioxide which are result of chemical processes.
On the other hand, a piece of avocado oxidizing and turning brown is a chemical transformation that happens when the enzyme polyphenol oxidase in the fruit's cells combines with oxygen in the air. This irreversible process can be slowed down by preserving the avocado or using lemon juice.
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Please help I will mark you brainiest
Answers
Answer:
Ethylene glycol is a syrupy liquid at room temperature whereas polyethylene glycol is a solid material. The main difference between ethylene glycol and polyethylene glycol is that ethylene glycol has a fixed value for molecular weight whereas polyethylene glycol has no fixed value for molecular weight.
Predict the products and balance the equation
classify the reaction
Answers
Answer:
\(C_3H_8+5O_2\rightarrow 3CO_2+4H_2O\)
Explanation:
Hello there!
In this case, when coming across combustion reactions whereby hydrocarbons as fuels are burnt in the presence of oxygen, the main products are said to be carbon dioxide and water in agreement to the breaking and rearrangement of bonds due to the collisions among molecules. Thus, for the reaction between propane and oxygen we have the following balanced reaction:
\(C_3H_8+5O_2\rightarrow 3CO_2+4H_2O\)
Best regards!
3057 kJ is the energy required to break six carbon-carbon bonds in benzene. Calculate the average bond enthalpy
of one carbon-carbon bond in gaseous benzene, C6H6(g).
Answers
The average bond enthalpy of one carbon-carbon bond in gaseous benzene, C6H6(g) is 509.5 KJ.
The strength of a chemical bond is measured by bond energy, which is also known as mean bond enthalpy or average bond enthalpy. The average bond-dissociation energy for all bonds of the same type within a similar chemical species, as defined by IUPAC, is referred to as bond energy.The quantity of energy received by or released from a system under constant pressure is referred to as enthalpy. Bond enthalpy, also known as bond energy or bond dissociation (breakage) energy, is the quantity of thermal energy required to rupture a specific bond. Bond enthalpy provides a gauge and insight into the stability and strength of the bond. We are aware that chemical bonds are created by sharing or transferring electrons to finish their outermost shells in order to achieve stability.Energy required to break six C-C bonds in benzene = 3057 KJ
Average bond enthalpy for one C-C bond = 3057 / 6
= 509.5 KJ
Hence, the average bond enthalpy of one carbon-carbon bond in gaseous benzene, C6H6(g) is 509.5 KJ.
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What is the meaning of bezene
Answers
Answer:
Benzene is an organic chemical compound with the molecular formula C₆H₆. The benzene molecule is composed of six carbon atoms joined in a planar ring with one hydrogen atom attached to each. Because it contains only carbon and hydrogen atoms, benzene is classed as a hydrocarbon.
Create a double replacement reaction
3) CO(OH)3 + HNO3
4) FeBr3 + H2SO4
Answers
4) H2Br3 + FeSO4
Energy and Enthalpy Changes, Heat and Work -- Monatomic Ideal Gas dynamically generated plot 2.00-mol of a monatomic ideal gas goes from State A to State D via the path A→B→C→D: State A PA=11.0atm, VA=12.50L State B PB=11.0atm, VB=7.00L State C PC=25.0atm, VC=7.00L State D PD=25.0atm, VD=20.50L Assume that the external pressure is constant during each step and equals the final pressure of the gas for that step. Calculate q for this process. q = 1pts Tries 0/6 Calculate w for this process. w = -902 J Use w = -PΔV and sum over the individual steps. Check that you have the correct energy units and be sure you have the sign right (w is defined as the work done ON THE SYSTEM). 1pts Incorrect. Tries 4/6 Previous Tries Calculate ΔE for this process ΔE = 1pts Tries 0/6 Calculate ΔH for this process. ΔH = 1pts
Answers
(a) The heat generated in the process is 28 kJ.
(b) The work done in the process is determined as -28 kJ.
(c) The change in the internal energy is 0.
Heat of the isothermal compression
The heat generated in the process is negative done in the process.
W = -PΔV
W = -P(V₂ - V₁)
From A to BW = -P(VB - VA)
W = -11(7 - 12.5)
W = 60.5 L.atm = 60.5 x 101.325 J/L.atm = 6,130.16 J
From C to DW = -25(20.5 - 7)
W = -337.5 L.atm = -34,197.18 J
Total work , w = -34,197.18 J + 6,130.16 J = -28 kJ
q = - w
q = 28 kJ
Change in internal energyΔE = q + w
ΔE = 28 kJ - 28 kJ = 0
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At standard temperature and pressure. 0.500 mole of xenon gas occupies
Answers
Answer:
0.500 mole of Xe (g) occupies 11.2 L at STP.
General Formulas and Concepts:
Gas Laws
STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 KStoichiometry
Mole ratioDimensional AnalysisExplanation:
Step 1: Define
Identify.
0.500 mole Xe (g)
Step 2: Convert
[DA] Set up: \(\displaystyle 0.500 \ \text{mole Xe} \bigg( \frac{22.4 \ \text{L Xe}}{1 \ \text{mole Xe}} \bigg)\)[DA] Evaluate: \(\displaystyle 0.500 \ \text{mole Xe} \bigg( \frac{22.4 \ \text{L Xe}}{1 \ \text{mole Xe}} \bigg) = 11.2 \ \text{L Xe}\)Topic: AP Chemistry
Unit: Stoichiometry
Is the Swedish timber industry more likely a result of good resource availability or a lack of trees elsewhere on Earth?
Answers
Answer:
The forest products industry plays a major role in the Swedish economy, and accounts for between nine and 12 percent of Swedish industry's total employment, exports, sales and added value. It includes companies within the pulp and paper industry, as well as the wood-mechanical industry.
How do other factors shape earths surface
Answers
Answer:
Other factors shape earths surface are:
Factors that Shape Earth's Surface.
Unit Notes.
Plate Tectonics. Continental Drift. ...
Results of plate movement. ...
Weathering. ...
Erosion and Deposition.
when placed in an ice chest, dry ice will keep food cold. where does the heat go that is removed from the food and what change does it cause?
Answers
Answer:
Cold ice can absorb heat
When dry ice is used to keep food cold in an ice chest, the heat from the food immediately causes the phase shift of the dry ice from a solid to a gas. Sublimation is the name of this process.
At an extremely low temperature of about -78.5 degrees Celsius (-109.3 degrees Fahrenheit), solid carbon dioxide (CO₂) is known as dry ice. It absorbs heat from the environment, including the food, to reach its equilibrium temperature before being exposed to the warmer temperature within the ice chest. Dry ice starts to sublimate when it heat absorbed, going straight from a solid to a gaseous state without going through a liquid phase.
The CO₂ gas created during sublimation is discharged into the ice chest's air during sublimation. Because it is denser and colder than the air around it, this gas pushes the warmer air upward as it descends to the bottom of the chest. By eliminating heat energy from the ice chest's contents, including the food, as the CO₂ gas combines with the air, it aids in cooling. The meal is kept cold through this cooling procedure.
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HQ5.40
Homework Answered Due Today, 11:59 PM
The reaction 3H₂(g) + N₂(g) → 2NH3(g) has an enthalpy of reaction of -92.6 kJ/mol. If 1 g of hydrogen and 2 g of nitrogen are
reacted, how much heat is produced (kJ)?
Answers
The amount of heat energy produced when 1 g of hydrogen and 2 g of nitrogen are reacted, is -6.61 KJ
How do i determine the heat energy produced?First, we shall obtain the limiting reactant. Details below:
3H₂ + N₂ -> 2NH₃
Molar mass of N₂ = 28 g/molMass of N₂ from the balanced equation = 1 × 28 = 28 g Molar mass of H₂ = 2 g/molMass of H₂ from the balanced equation = 3 × 2 = 6 gFrom the balanced equation above,
28 g of N₂ reacted with 6 g of H₂
Therefore,
2 g of N₂ will react with = (2 × 6) / 28 = 0.43 g of H₂
We can see that only 0.43 g of H₂ is needed in the reaction.
Thus, the limiting reactant is N₂
Finally, we the amount of heat energy produced. Details below:
3H₂ + N₂ -> 2NH₃ ΔH = -92.6 KJ
Molar mass of N₂ = 28 g/molMass of N₂ from the balanced equation = 1 × 28 = 28 gFrom the balanced equation above,
When 28 grams of N₂ reacted, -92.6 KJ of heat energy were produced.
Therefore,
When 2 grams of N₂ will react to produce = (2 × -92.6) / 28 = -6.61 KJ
Thus the heat energy produced from the reaction is -6.61 KJ
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16) Select the best answer.
Round the answer to the correct number of significant figures.
10.05
2.8899 = 29.043495
29.0435
29.04
29.043
29
Answers
29 is not the best answer depends on the context and the rules for significant figures.
What is best answer?
The best answer depends on the context and the rules for significant figures. If we assume that we need to round to three significant figures:
10.05 has three significant figures, so it is already rounded correctly.2.8899 has four significant figures, so we need to round it to three significant figures. The third significant figure is 9, which is greater than 5, so we round up the second significant figure (which is 8) to 9. Therefore, 2.8899 rounded to three significant figures is 2.89.29.0435 has five significant figures, so we need to round it to three significant figures. The third significant figure is 0, which is less than 5, so we do not round up the second significant figure (which is 4). Therefore, 29.0435 rounded to three significant figures is 29.0.29.04 has four significant figures, so it is already rounded correctly.29.043 has four significant figures, so we need to round it to three significant figures. The third significant figure is 3, which is less than 5, so we do not round up the second significant figure (which is 4). Therefore, 29.043 rounded to three significant figures is 29.0.29 has one significant figure, so it is not rounded correctly to three significant figures.Therefore, 29 is not the best answer.
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To determine the mass of CO2 that forms from a given mass of CaCO3, which of the following must be known? Check all that apply.
Answers
To determine the mass of CO₂, the following must be known :
the molar mass of CaCO₃ the mole ratio of CaCO₃ to CO₂ the molar mass of CO₂Further explanationReaction
Decomposition of CaCO₃
CaCO₃ ⇒ CaO + CO₂
Given the mass of CaCO₃, so to determine the mass of CO₂ :
1. Find the mol of CaCO₃ from the molar mass of CaCO₃
\(\tt n_{CaCO_3}=\dfrac{mass~CaCO_3}{MW~CaCO_3}\)
2. Find the mole ratio of CaCO₃ : CO₂(from equation = 1 : 1)
\(\tt n_{CaCO_3}\div n_{CO_2}=1\div 1\)
3. Find the mass of CO₂ from the molar mass of CO₂
\(\tt mass_{CO_2}=n_{CO_2}\times MW_{CO_2}\)
Answer:
1 3 and 5
Explanation:
how to calculate molar extinction coefficient with wavelength and absorbance
Answers
The molar extinction coefficient is specific to the substance being measured and the wavelength of light used. Accurate and precise values for absorbance, concentration, and path length are necessary for an accurate calculation.
How to calculate molar extinction coefficient with wavelength and absorbanceTo calculate the molar extinction coefficient (ε) using wavelength (λ) and absorbance (A):
Apply the Beer-Lambert Law: A = εclA is the absorbance, ε is the molar extinction coefficient (in M^-1 cm^-1), c is the concentration of the substance (in M), and l is the path length of the sample (in cm).Rearrange the equation: ε = A / (cl)Ensure that concentration is in molar units (M) and path length is in centimeters (cm).Divide the absorbance by the product of the concentration and path length to obtain the molar extinction coefficient (ε).Learn more on molar extinction coefficient here https://brainly.com/question/31088826
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What did you include in your question? Check all that apply. examines the effect of mass examines the effect of different materials contains at least two variables
Answers
The sample response is : how do mass and the type of material affect thermal energy transfer?
So one need to have include the below factors in your answer:
Examines the effect of mass Examines the effect of different materialsContains at least two variablesWhat is the thermal energy transfer?The mass of an object influences allure thermal strength transfer traits. Generally, objects accompanying best public have greater warm strength depository volume.
They can absorb more heat strength before experience a meaningful change in hotness. If an equal amount of heat is used to both objects, the object accompanying better mass will demand more heat strength to raise allure temperature distinguished to the object accompanying tinier mass .
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. In this experiment, you need to examine the idea of the thermal energy transfer. Using a controlled experiment, what might a good question about the variables that affect thermal energy transfer be? Thermal energy transfer depends on many properties, be limit your question to only two. What did you include in your question?
