When silver crystallizes, it forms face-centered cubic cells. The unit cell edge is 4. 087 å. Calculate the density of silver.

Answer:

A- evaporates

Answer:

Condenses

Explanation:

Clouds are created when water vapor, an invisible gas, turns into liquid water droplets. These water droplets form on tiny particles, like dust, that are floating in the air.

Answer:

I'm sorry didn't understand

To calculate the Gibbs energy of 2 kg of liquid water at 600 kPa and 150°C relative to the reference state at 150°C and 50 kPa, we can use the following formula:

ΔG = ΔH - TΔS

Where ΔH is the enthalpy change, T is the temperature in Kelvin, and ΔS is the entropy change.

Assuming the water is incompressible, we can use the following equation to calculate the enthalpy change:

ΔH = CpΔT

Where Cp is the specific heat capacity of water and ΔT is the temperature change. At constant pressure, Cp is approximately 75.3 J/mol·K.

Thus, ΔH = CpΔT = 75.3 J/mol·K × 2 kg × (150 - 150) = 0 J

Since the process is isothermal, the entropy change can be calculated using the following equation:

ΔS = Qrev / T

Where Qrev is the heat transferred reversibly. Since the process is reversible, the heat transferred is equal to the enthalpy change, so ΔS = ΔH / T.

Therefore, ΔS = 0 J / (423 K) = 0 J/K

Now we can calculate the Gibbs energy change:

ΔG = ΔH - TΔS = 0 J - (423 K)(0 J/K) = 0 J

Thus, the Gibbs energy of 2 kg of liquid water at 600 kPa and 150°C relative to the reference state at 150°C and 50 kPa is zero, indicating that there is no free energy available to do work.

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The statement that describes the particles that make up the rigid structure of a three-dimensional crystalline solid is:

Solids are one of the three states in which matter exists.

Solids are characterized by their having definite shapes and volumes.

Solids have definite shapes and volumes because of the arrangement of the particles in a solid.

The intermolecular forces of the particles in a solid are very strong such that the particles are not free to move but  vibrate about a fixed position.

Thus, they are arranged in rigid continuous patterns as seen in solid crystals.

In conclusion, the particles in a crystalline solid are arranged in regular repeating patterns forming a three-dimensional structure.

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The enzyme used in ethanol metabolism that converts acetaldehyde into acetyl-CoA is called as aldehyde dehydrogenase.

Acetaldehyde dehydrogenase is an enzyme involved in the conversion of acetaldehyde into acetic acid. Acetic acid is then converted into acetic-CoA (acetyl-Coa synthase) and enters the citric acid cycle.

The term “dehydrogenase” is derived from the fact that it aids in the de-hydrogenation (-hydrogen-) of hydrogen and is a (-ase) reaction.

Dehydrogenase reactions typically take two forms: a hydride transfer and a proton transfer (usually with water as a secondary reactant), and a hydrogen transfer.

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Answer:

The chemicals differ depending on what the surrounding area is like.

Answer:

D.) All of the above

Explanation:

Anxiety can cause sweating, chaky hands, headaches etc

The concentration of H+ and OH- ions in a neutral solution is 1.0 × 10−7M

At 25°C, Kw = [H+][OH−] = 1.0 × 10−14.

For a neutral solution, the concentration of H+ and OH− ions is equal.

To find their concentrations, we'll use the formula Kw = [H+][OH−].

Since it is a neutral solution, H+ ion concentration equals OH- ion concentration.

[H+]= xM[OH-]=xMx²

=Kw = 1.0 × 10−14x

=sqrt(Kw) = 1.0 × 10−7[H+]

=[OH-]=1.0 × 10−7M

Note: The square root of Kw is called the ion product constant of water, and it equals 1.0 × 10−7 M.

So, the concentration of H+ and OH- ions in a neutral solution is 1.0 × 10−7 M. However, we can also express this using scientific notation as [H+]=1.0 × 10−7M and [OH−]=1.0 × 10−7M respectively.

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Explanation:

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Answer:

all of the above

Explanation:

all of this is in the solar system

A non-covalent interactions between  molecules are van der Waal's forces and hydrogen bonds.

Non-covalent interaction is an interaction which does not involve sharing of electrons and in this aspect it differs from covalent bond.It rather involves dispersed variations  of electromagnetic interactions  which are present between the molecules or within the molecule.

The energy released during the formation of these interactions  is of the order of 1-5 kcal .They are classified as electrostatic, pi effects , van der waals forces  and hydrophobic effects.

They are important in maintaining the three dimensional structure of large molecules such as proteins ,nucleic acids ,etc.They are also involved in biological processes . They heavily influence drug design process and design of materials.

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Given that the volume and molarity of barium acetate are 38.2 ml and 5.0 M, respectively. We need to find the theoretical mass in grams of the precipitate. Let's first write the balanced chemical equation for the reaction taking place: Rubidium Carbonate + Barium Acetate → Barium Carbonate + Rubidium AcetateRb2CO3(aq) + Ba(C2H3O2)2(aq) → BaCO3(s) + 2 RbC2H3O2(aq).

We can see that 1 mole of barium acetate reacts with 1 mole of barium carbonate. Hence, the molar ratio of barium acetate and barium carbonate is 1:1.Using the molarity and volume of barium acetate, we can find the moles of barium acetate as: Moles of barium acetate = Molarity × Volume in litres= 5.0 mol/L × (38.2/1000) L= 0.191 moles. Now, from the balanced chemical equation, we can see that 1 mole of barium carbonate is formed from 1 mole of barium acetate.

Therefore, the number of moles of barium carbonate formed will also be 0.191 moles. Now, let's calculate the mass of barium carbonate using its molar mass. Molar mass of BaCO3= (1 × atomic mass of Ba) + (1 × atomic mass of C) + (3 × atomic mass of O)= (1 × 137.33 g/mol) + (1 × 12.01 g/mol) + (3 × 16.00 g/mol)= 197.33 g/mol. Theoretical mass of BaCO3= Number of moles of BaCO3 × Molar mass of BaCO3= 0.191 mol × 197.33 g/mol= 37.7 g. Therefore, the theoretical mass of the precipitate is 37.7 g (approx) when only the volume and molarity of the barium acetate are taken into account. Note: In order to find the limiting reagent and the actual mass of the precipitate formed, we need to consider the volume and molarity of both the reactants.

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Three experiments that would accomplish the students' goal are:

Intermolecular force is the electromagnetic forces of attraction or repulsion between atoms and other particles nearby. It is dependent on the melting point, state, and viscosity of the substances. If the melting point of a substance is very high, it means the intermolecular forces between its particles are very high. The higher the substances' viscosity, the higher the intermolecular force between its particles. At room temperature, the state of a substance is defined as the state of matter.

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The anion As²⁻ is paramagnetic because it has one unpaired electron in its electron configuration and the correct option is option A.

To determine if an anion is paramagnetic, we need to examine the electron configuration and look for unpaired electrons.

A. As²⁻: The neutral atom arsenic (As) has the electron configuration [Ar] 3d¹⁰ 4s² 4p³. When it gains two electrons to form As²⁻, it becomes [Ar] 3d¹⁰ 4s² 4p⁵. There is one unpaired electron in the p subshell, so it is paramagnetic.

B. S²⁻: The neutral atom sulfur (S) has the electron configuration [Ne] 3s² 3p⁴. When it gains two electrons to form S²⁻, it becomes [Ne] 3s² 3p⁶. There are no unpaired electrons, so it is diamagnetic.

C. P³⁻: The neutral atom phosphorus (P) has the electron configuration [Ne] 3s² 3p³. When it gains three electrons to form P³⁻, it becomes [Ne] 3s² 3p⁶. There are no unpaired electrons, so it is diamagnetic.

D. N³⁻: The neutral atom nitrogen (N) has the electron configuration [He] 2s² 2p³. When it gains three electrons to form N³⁻, it becomes [He] 2s² 2p⁶. There is no unpaired electrons, so it is diamagnetic.

E. Si⁴⁻: The neutral atom silicon (Si) has the electron configuration [Ne] 3s² 3p². When it gains four electrons to form Si⁴⁻, it becomes [Ne] 3s² 3p⁶. There are no unpaired electrons, so it is diamagnetic.

Thus, the ideal selection is option A.

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The molecular weight of cerium(IV) nitrate hexahydrate is 446.24 g/mol. Therefore, one mole of cerium(IV) nitrate hexahydrate contains one mole of cerium(IV) ions, which will combine with four moles of nitrate ions to form one mole of cerium(IV) nitrate hexahydrate.

The formula for the concentration of ions in a solution is C = n/V where C is the concentration of ions, n is the number of moles of ions, and V is the volume of the solution in liters. The first step in solving this problem is to calculate the number of moles of cerium(IV) nitrate hexahydrate in 150.0 mL of a 0.565 M solution. This can be done using the following formula:n = M x V n = 0.565 mol/L x 0.150 L= 0.08475 mol of cerium(IV) nitrate hexahydrate This amount contains four times as many moles of nitrate ions as cerium(IV) ions.

Therefore, the number of moles of nitrate ions is: nitrate ions = 4 x 0.08475 militate ions = 0.339 molThe volume of the solution is 150.0 mL, which is equal to 0.150 L. Using the formula given above, we can calculate the concentration of nitrate ions :C = n/V= 0.339 mol/0.150 LC = 2.26 M Therefore, the concentration of nitrate ions in the solution is 2.26 M.

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Answer:

The cation is written first in the name; the anion is written second in the name. Rule 2. When the formula unit contains two or more of the same polyatomic ion, that ion is written in parentheses with the subscript written outside the parentheses.

When writing the formula of a compound that contains polyatomic ion, the metal is written first followed by the central atom in the ion and then other atoms that surround the central atom.

A poly atomic ion refers to an ion that comprises of more than one atom. Such ions are common in chemistry. Examples of polyatomic ions include; PO4^3-, BH4^- etc.

When writing the formula of a compound that contains a polyatomic ion, the metal is written first then the central atom in the ion follows before other atoms that surround the central atom in the ion.

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Answer:

C

Explanation:

Q and R forms a nitrate. When dissolved in water it will form a solution with a pH greater than 7 because the solution is alkaline.

Answer: When the enthalpy of this overall chemical equation is calculated, the enthalpy of the second intermediate equation is halved and has its sign changed.

Explanation:

Hess’s law of constant heat summation states that the amount of heat absorbed or evolved in a given chemical equation remains the same whether the process occurs in one step or several steps.

According to this law, the chemical equation is treated as ordinary algebraic expressions and can be added or subtracted to yield the required equation. This means that the enthalpy change of the overall reaction is equal to the sum of the enthalpy changes of the intermediate reactions.

The overall chemical reaction follows:

\(CaO(s)+CO_2\rightarrow CaCO_3(s)\)     \(\Delta H^o_{rxn}=?\)

The intermediate balanced chemical reaction are:

(1) \(Ca(s)+CO_2(g)+\frac{1}{2}O_2(g)\rightarrow CaCO_3(s)\)    \(\Delta H_1=-812.8kJ\)  

(2) \(2Ca(s)+O_2(g)\rightarrow 2CaO(s)\)     \(\Delta H_2=-1269kJ\)

The expression for enthalpy of the reaction follows:

\(\Delta H^o_{rxn}=[1\times (\Delta H_1)]+[\frac{1}{2}\times (-\Delta H_2)]\)

Hence, when the enthalpy of this overall chemical equation is calculated, the enthalpy of the second intermediate equation is halved and has its sign changed.

Answer:

A. is halved and has its sign changed.

Explanation:

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Option E IR absorptions are caused by electron excitation  isn't true about IR spectroscopy.

IR absorptions are caused by changes in the vibrational energy of bonds in a molecule, not by electron excitation. This means that IR spectroscopy is based on the measurement of the absorption of infrared light by a sample, not on the excitation of electrons.

IR spectroscopy, or Infrared spectroscopy, is a type of vibrational spectroscopy that measures the vibrations of bonds between atoms in a molecule, it is used to identify and quantify the composition of a sample by analyzing the absorption or transmission of infrared light through the sample.

By analyzing the pattern of IR absorptions, it is possible to identify the functional groups and the chemical composition of a sample, which can provide valuable information about its structure and properties.

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Answer:

0

Explanation:

The number of unpaired electrons in  is 0

Answer:

4 unpaired electrons

Explanation:

becausd it have 4 unpaired electros it is paramagnetic

To make a 20.0 mL solution with a density of 1.10 g/mL, you would mix water with a liquid substance from the materials list that has a density greater than 1.10 g/mL.

To determine the liquid substance to mix with water, we need to find a substance with a higher density than 1.10 g/mL. Since water has a density of approximately 1 g/mL, we need to select a substance that will increase the overall density of the solution.

Let's consider a few examples of liquid substances that have higher densities:

Ethanol (density ≈ 0.789 g/mL): Mixing ethanol with water would not increase the density, as ethanol has a lower density than water.

Glycerol (density ≈ 1.26 g/mL): Mixing glycerol with water would increase the density of the solution. Glycerol has a higher density than water and would contribute to an overall higher density of the solution.

Chloroform (density ≈ 1.49 g/mL): Mixing chloroform with water would also increase the density of the solution. Chloroform has a higher density than water and would result in a solution with a higher overall density.

There are various other substances with higher densities that could be considered depending on the specific materials available.

To make a 20.0 mL solution with a density of 1.10 g/mL, you would need to mix water with a liquid substance from the materials list that has a density higher than 1.10 g/mL. Examples of substances that could be used are glycerol or chloroform, among others. It is important to select a substance with a higher density to increase the overall density of the solution.

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Answer:

Methane

Explanation:

It is methane because, it comes from natural sources.

Yes, it is true a molecule with a central atom that has four electron groups and two bonded atoms. A molecule with only two of its four electron groups connected to neighboring atoms is H2O, which has four electron groups on its core atom.

When the center atom possesses one or more lone pairs of electrons, the molecular geometries of the molecules alter. What is referred to as the electron domain geometry is determined by the overall number of electron pairs, including bonded pairs and lone pairs. The molecular geometry (real shape) of the molecule is changed when one or more of the bonding pairs of electrons are swapped out for a lone pair.

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Answer:

H₃P phosphidic acid

Explanation:

The Trihydrogen monophosphide, as stated in the exercise, can act as an acid. This is pretty similar to the case of hydrogen chloride, which is a gas but it can also be an acid, in this case, chloridic acid.

In the case of trihydrogen phosphide, we can write it molecular formula which is:

H₃P

Now, this is a binary compound because its composed of only two elements, in this case, hydrogen and phosphide. To name binary acid, we need to name the non metal with the sufije idic, and then, the word acid.

Following this simple rule, the trihydrogen phosphide would be, as acid:

H₃P: phosphidic acid

Hope this helps

a)  The volumetric flow rate of air entering the furnace is approximately 20.78 \(m^3/h.\)

b) the rate of heat transfer from the furnace is approximately 15,600 kJ/h.

To solve this problem, we need to apply the principles of stoichiometry and energy balance. Let's break it down step by step:

a.)  To determine the volumetric flow rate of air, we'll use the stoichiometry of the combustion reaction. Methane (\(CH_4\)) burns completely with air according to the following balanced equation:

\(CH_4\)+ 2 ( \(O_2\)+ 3.76 \(N_2\)) -> \(CO_2\)+ 2 \(H_2O\) + 7.52 \(N_2\)

Since we're given that the methane flow rate is 27 m^3/h, we can set up the equation:

27 \(m^3/h.\) \(CH_4\)* (2 + 3.76) = Air flow rate * 7.52

Simplifying, we find:

27 * 5.76 = Air flow rate * 7.52

Air flow rate = (27 * 5.76) / 7.52 ≈ 20.78 m^3/h

Therefore, the volumetric flow rate of air entering the furnace is approximately 20.78 \(m^3/h.\).

b. To determine the rate of heat transfer from the furnace, we'll use the energy balance equation. The energy balance can be expressed as follows:

Q = m_air * Cp_air * (T_exit_air - T_enter_air)

Where:

Q is the rate of heat transfer (in kW),

m_air is the mass flow rate of air (in kg/h),

Cp_air is the specific heat capacity of air (assumed constant at around 1.005 kJ/kg·°C),

T_exit_air is the exit temperature of air (427°C),

T_enter_air is the entering temperature of air (127°C).

To convert the volumetric flow rate of air to mass flow rate, we'll need to consider the density of air at the given conditions. At 127°C and 1 atm, the density of air is approximately 0.941 kg/m^3.

m_air = Air flow rate * Density_air = 20.78 m^3/h * 0.941 kg/m^3 = 19.53 kg/h

Now we can substitute the values into the energy balance equation:

Q = 19.53 kg/h * 1.005 kJ/kg·°C * (427°C - 127°C) = 15,600 kJ/h

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There is approximately 3.28 grams of NaCl contained in 450 mL of a 0.125 M solution of sodium chloride.

To calculate the grams of NaCl in the solution, we need to use the formula:

grams of NaCl = moles of NaCl * molar mass of NaCl

First, let's calculate the moles of NaCl using the formula:

moles of NaCl = concentration of NaCl * volume of solution

Given:

Concentration of NaCl = 0.125 M

Volume of solution = 450 mL = 450/1000 = 0.45 L

moles of NaCl = 0.125 M * 0.45 L

moles of NaCl = 0.05625 mol

The molar mass of NaCl is approximately 58.44 g/mol.

Now, let's calculate the grams of NaCl:

grams of NaCl = 0.05625 mol * 58.44 g/mol

grams of NaCl ≈ 3.28 g

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The molar mass of B(NO₃)₃ - Boron nitrate : 196.822 g/mol

In stochiometry therein includes  

Relative atomic mass (Ar) and relative molecular mass / molar mass (M)  

So the molar mass of a compound is given by the sum of the relative atomic mass of Ar  

M AxBy = (x.Ar A + y. Ar B)  

The molar mass of B(NO₃)₃ - Boron nitrate :

M B(NO₃)₃ = Ar B + 3. Ar N + 9.Ar O

M B(NO₃)₃ = 10.811 + 3. 14,0067 + 9. 15,999

M B(NO₃)₃ = 196.822 g/mol

Answer:

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Explanation:

Standards help avoid confusion and ambiguity when taking measurements. For example, a meter will always be the same length, no matter who is taking the measurement or where it is being taken.

The formula for density is given by:p= m/v Where p is the density,m is the mass and,v is the volume.We are given that the mass of the beaker and the fluid is 61.89 g. Subtracting the mass of the empty beaker (30.36 g) from the combined mass gives the mass of the fluid to be:61.89 g - 30.36 g = 31.53 g.

Converting the volume of the fluid to liters:25.0 mL = 0.025 L. The density of the fluid can now be calculated as follows:

p = 31.53 g / 0.025 L = 1261.2 g/L.

The first step when calculating density is to identify the mass and volume of the substance. In this problem, we are given the volume of the fluid in milliliters and the mass of the beaker and fluid in grams. To calculate the mass of the fluid, we simply subtract the mass of the empty beaker from the combined mass of the beaker and fluid. We then convert the volume to liters since density is expressed in units of mass/volume.To calculate the density of the fluid, we use the formula:p = m/vwhere p is the density, m is the mass, and v is the volume. Plugging in the values we have, we get:p = 31.53 g / 0.025 L = 1261.2 g/L

Therefore, the density of the fluid is 1261.2 g/L.

Given the mass of the beaker and fluid, and the volume of the fluid, we were able to calculate the density of the fluid using the formula: p = m/v. We found that the density of the fluid is 1261.2 g/L.

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Answer:

5g NaOH

Explanation: