When solid NH4NO3 is added to water, the pH ____.
a. remains at 7
b. becomes greater than 7
c. becomes less than 7
d. is independent of the amount dissolved
e. Can not be determined

Explanation:

Regions of the Electromagnetic Spectrum

Listed below are the approximate wavelength, frequency, and energy limits

of the various regions of the electromagnetic spectrum.

Wavelength (m) Frequency (Hz) Energy (J)

Radio > 1 x 10-1 < 3 x 109 < 2 x 10-24

Microwave 1 x 10-3 - 1 x 10-1 3 x 109 - 3 x 1011 2 x 10-24- 2 x 10-22

Infrared 7 x 10-7 - 1 x 10-3 3 x 1011 - 4 x 1014 2 x 10-22 - 3 x 10-19

Optical 4 x 10-7 - 7 x 10-7 4 x 1014 - 7.5 x 1014 3 x 10-19 - 5 x 10-19

UV 1 x 10-8 - 4 x 10-7 7.5 x 1014 - 3 x 1016 5 x 10-19 - 2 x 10-17

X-ray 1 x 10-11 - 1 x 10-8 3 x 1016 - 3 x 1019 2 x 10-17 - 2 x 10-14

Gamma-ray < 1 x 10-11 > 3 x 1019 > 2 x 10-14

The structures of two isomeric alkyl magnesium bromides that would react with water to give propane are:

Isopropylmagnesium bromide (CH3)2CHMgBr:

H H

| |

H3C - C - Mg - Br

n-Propylmagnesium bromide CH3CH2CH2MgBr:

H H H

| | |

H3C - C - C - Mg - Br

In both cases, when these alkyl magnesium bromides react with water, they will undergo a hydrolysis reaction, resulting in the formation of propane.

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The pH of a 0.25 M solution of NaNO2= 6.65.

Given the concentration of NaNO2, we can find the concentration of NaOH and HNO2 as follows:

NaNO2 = 0.25 MNaOH = HNO2 = x

(since they have equal concentrations due to the stoichiometry of the reaction)

Thus, we can write the equilibrium constant expression as:

Ka = x^2/0.25

Now, let's solve for x:

x^2 = 0.25 x 4.5 x 10^-4x = √(0.25 x 4.5 x 10^-4) = 0.015

This value represents the concentration of both HNO2 and NaOH. Since we are interested in pH, we need to find the concentration of H+ ions using the following equation:

Kw = [H+][OH-]

Since we have found the concentration of OH- (which is the same as the concentration of NaOH),

we can solve for H+:

Kw = 1.0 x 10^-14[H+][0.015] = 1.0 x 10^-14[H+] = 6.7 x 10^-13

Finally, we can find pH:

pH = -log[H+]pH = -log(6.7 x 10^-13)pH = 6.65

Therefore, the correct option is d) pH = 6.65.

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There are a number of experimental findings that show 1-bromobutane to be the major product over 2-bromobutane like kinetics of reaction, stereochemistry of the reaction and quantitative comparison of the reaction rates.

First, the kinetics of the reaction. Because the SN2 mechanism requires the nucleophile to attack the primary carbon at a 180 degree angle, 2-bromobutane will be a bit slower to react than 1-bromobutane. As a result, when the reaction is allowed to run for a certain amount of time, more 1-bromobutane is formed. Second, a quantitative comparison of the reaction rates of the two substrates.

Because the SN2 reaction mechanism is so sensitive to steric hindrance, a quantitative comparison of the reaction rates of the two substrates could be carried out to determine which one is the better substrate. This would be a direct experimental measurement of the relative reactivity of the two substrates, and would show that 1-bromobutane is more reactive than 2-bromobutane.

Finally, the stereochemistry of the reaction products. When a stereocenter is created during an SN2 reaction, the resulting product is always an enantiomeric pair of molecules. Because the SN2 reaction requires the nucleophile to attack the primary carbon from the back side, the product will be a pair of enantiomers with opposite stereochemistry.

If 1-bromobutane is the major product, then the product will be a pair of enantiomers with opposite stereochemistry. If 2-bromobutane is the major product, then the product will be a pair of enantiomers with the same stereochemistry. So, by analyzing the stereochemistry of the product, we can determine which substrate is the better SN2 substrate.

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Answer:

None of the above

Explanation:

Erikson's was a student of freud's and expanded of his theory of psychosexual development by emphasizing the importance of culture in parenting practices and motivations and adding three stages of adult development.

The magnification of the magnifying glass is approximately 1.44.

To calculate the magnification of the magnifying glass, we can use the formula:

Magnification = (image distance) / (object distance)

In this case, the magnifying glass is held 10.4 cm from the mole, so the object distance (d₀) is 10.4 cm. The focal length (f) of the magnifying glass is given as 15.0 cm.

Using the formula, we can calculate the magnification (M):

M = (image distance) / (10.4 cm)

The magnification of a magnifying glass is typically assumed to be the ratio of the image distance to the least distance of distinct vision (25 cm for a relaxed eye). Therefore, we need to find the image distance (dᵢ) in terms of the least distance of distinct vision.

Using the lens formula: 1/f = 1/d₀ + 1/dᵢ

We can rearrange the formula to solve for the image distance (dᵢ):

1/dᵢ = 1/f - 1/d₀

Substituting the given values:

1/dᵢ = 1/15 cm - 1/10.4 cm

Calculating the result:

1/dᵢ ≈ 0.0667 cm⁻¹

dᵢ ≈ 15 cm

Now we can substitute the values for image distance (dᵢ) and object distance (d₀) into the magnification formula:

M = 15 cm / 10.4 cm

Simplifying the calculation:

M ≈ 1.44

Therefore, the magnification of the magnifying glass in this scenario is approximately 1.44.

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Answer:

Number of protons - number of electrons = charge on ion.

Explanation:

To solve this problem, we will use the formula:q = m × c × ΔTwhereq is the amount of heat absorbed or released, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature of the substance.

In this case, we are trying to find the amount of heat absorbed by 75 grams of water when its temperature increases from 20°C to 35°C. The specific heat capacity of water is 4.18 J/g°C. So, let's substitute the given values into the formula:q = m × c × ΔTq = 75 g × 4.18 J/g°C × (35°C - 20°C)q = 75 g × 4.18 J/g°C × 15°Cq = 4693.5 J

So the amount of heat absorbed when the temperature of 75 grams of water increases from 20°C to 35°C is 4693.5 J. Therefore, the answer is 4700J.

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Answer:

true

no explanation

The total equation is C2H4 + C2H5 + H2 → C2H5 + C2H6 when these equations are combined together.

By placing all of the reactants on the left side of the equation and all of the products on the right side, you can integrate numerous reactions into a single equation. Chemical species that are present on both sides of the equation will be eliminated without change if the overall equation is simplified.

Only chemical compounds with numerous bonds—such as molecules with carbon-carbon double bonds (alkenes), carbon-carbon triple bonds (alkynes), or molecules with carbonyl (C=O) groups—can conduct addition reactions. Consider the formula CH2=CH2 + Cl2 CH2Cl → CH2Cl.

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Answer:

When the frozen popsicle sitting outside in the Sun is exposed to warm air, energy will travel between the popsicle and the warm air as follows;

1) Convection current

Heat will be gained by the frozen popsicle by coming into contact with fresh warm air as the air flows around the popsicle while the cooling of the warm air will cause the water vapor in the air to condense and form the visible mist

In turn the popsicle will gain heat resulting in melting of the ice

2) Conduction

As the some of the mist from the air settles on the popsicle, they share their heat resulting further melting of the popsicle

3) Radiation

Radiated heat energy from the Sun is absorbed by the popsicle resulting in the melting of the popsicle

Explanation:

The heat gained by copper when 51.8 g of copper is warmed from 15.5°C to 76.4°C is 1,090.97 J.

To calculate the heat gained, you can use the formula q = mcΔT, where q is the heat gained, m is the mass of copper, c is the specific heat of copper, and ΔT is the change in temperature.

1. Determine the mass (m): 51.8 g
2. Identify the specific heat (c): 0.385 J/(g·°C)
3. Calculate the change in temperature (ΔT): 76.4°C - 15.5°C = 60.9°C
4. Plug the values into the formula: q = (51.8 g) x (0.385 J/(g·°C)) x (60.9°C)
5. Calculate the heat gained (q): 1,090.97 J

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Answer:

B. electric energy then chemical energy

Explanation:

Answer:

See the explanation

Explanation:

In this question we have to take into account that we have to get the same amount of atoms on both sides, so:

Reaction 1

\(BaCl_2~+~H_2SO_4~=>~BaSO_4~+~2HCl\)

We have 1 Ba, 2 Cl, 2 H and 4 O on both sides

Reaction 2

\(Ca(OH)_2~+~CO_2~=>~CaCO_3~+~H_2O\)

We have 1 Ca, 2O, 2 H and 1 C on both sides

Reaction 3

\(2Al~+~3CuCl_2~=>~2 AlCl_3~+~3Cu\)

We have 2 Al, 3 Cu, and 3 Cl on both sides

Reaction 4

\(2SO_2~+~O_2~=>~2SO_3\)

We have 2 A and 6O on both sides

Reaction 5

\(2NH_3~+~3CuO~=>~3Cu~+~N_2~+~3H_2O\)

We have 2 N, 3 H, 3 Cu and 3O on both sides.

I hope it helps

Answer:

what do you need help with?

Explanation:

Answer:

B, trees, they use photosynthesis to do so.

Answer: B

Explanation:

Answer:

Difference in temperature.

Explanation:

Conduction is the movement of heat energy through a substance or from one substance to another by direct contact of atoms and molecules. Heat moves directly from one molecule to another. The heat energy speeds up the movement of the atoms and they collide with other molecules setting them into faster motion.

The reaction between glucose and yeast hexokinase is diffusion-limited because of its high rate coefficient.

Yes, the reaction is diffusion limited. Diffusion-limited reaction is a chemical reaction between two reactants that is restricted by diffusion.

In other words, molecules need to collide in order to react, and the rate of this collision is influenced by the amount of space the molecules can diffuse through.

The rate coefficient k of glucose binding to yeast hexokinase is 3.7 × 106 M−1 s−1. The rate coefficient is an indication of how efficient the diffusion of reactants is. If the rate coefficient is high, the diffusion is efficient, and the reaction is diffusion-limited.

The high rate coefficient of glucose binding to yeast hexokinase indicates that the reaction is diffusion-limited.

Therefore, the reaction between glucose and yeast hexokinase is diffusion-limited because of its high rate coefficient.

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Answer:

4.73 mol NH

Explanation:

What we're doing here is calculating basic mole-mole relationships, something that you'll be doing quite a bit!

The steps to solving mole-mole problems like this are

write the balanced chemical equation for the reaction (this is given)

divide the number of moles of the given known substance (3.55) by that substance's coefficient in the chemical equation (3)

multiply that number by the coefficient of the substance you're trying to find (4)

Using simple dimensional analysis, it looks like this:

Answer:

4.68 H2O is needed to make 3.12 moles of NH3

Explanation:

Using stoichiometry, we can convert Moles of NH3 into Moles of H20

since we're converting moles to moles, we take the given mole of NH3

3.12, and multiply it by the Mole ratio, which in this case is (H20/NH3) or (6/4)

so then: 3.12 * 6/4 = 4.68 mols of H2O

Answer:

D 2.8.6 is the electron configuration

Answer:

You need 0.5 moles of oxygen to burn one mole of Mg.

Explanation:

The balanced reaction is:

2 Mg + O₂ → 2 MgO

When chemical changes occur, the chemical elements are conserved, so the number of atoms is the same before and after the change. To represent this equality of the number of atoms, the expression is "balanced" or "equalized". That's why you put a two in front of the magnesium formula and a two in front of the magnesium oxide to equal the number of atoms involved in the change. These numbers used are called stoichiometric coefficients. The stoichiometric coefficients allow to establish the molar ratio in which the reactants combine and the products are formed.

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction) the following amounts of each compound participate in the reaction:

Then you can apply the following rule of three: if by reaction stoichiometry 2 moles of magnesium reacts with , 1 mole of magnesium reacts with how many moles of oxygen?

\(amount of moles of oxygen=\frac{ 1 mole of magnesium*1 mole of oxygen}{ 2 moles of magnesium}\)

amount of moles of oxygen= 0.5 moles

You need 0.5 moles of oxygen to burn one mole of Mg.

The balanced version of the half-reaction that occurs in acidic solution for the reduction of NO3 to NO2 is:

NO3^-(aq) + 2H^+(aq) + 2e^- → NO2(g) + H2O(l)

In this reaction, NO3^- is reduced to NO2, and electrons (e^-) are gained. To balance the equation, we need to ensure that the number of atoms and charges are equal on both sides.

To balance the oxygen atoms, we add water (H2O) on the right side:

NO3^-(aq) + 2H^+(aq) + 2e^- → NO2(g) + H2O(l)

Next, we balance the hydrogen atoms by adding protons (H^+) to the left side:

NO3^-(aq) + 2H^+(aq) + 2e^- → NO2(g) + H2O(l)

Finally, we balance the charges by adding electrons (e^-) to the left side:

NO3^-(aq) + 2H^+(aq) + 2e^- → NO2(g) + H2O(l)

Now, the equation is balanced, with an equal number of atoms and charges on both sides. Therefore, the balanced version of the half-reaction for the reduction of NO3 to NO2 in acidic solution is given by the equation above.

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Answer:

Sodium Chloride is salt

Explanation:

Basically, its used to help absorb and transport nutrients, its also used to help blood pressure along with maintaining the right balance of fluid. These will all be helpful to our bodies and environment.

Answer:

Sodium chloride (NaCl), also known as salt, is an essential compound our body uses to: absorb and transport nutrients. maintain blood pressure. maintain the right balance of fluid.

After considering all the given data we conclude that A)  the ratios of the balanced chemical equation is 2:1, 2:2, 1:2, B) the number of moles of hydrogen needed is 0.5 mol H₂,  C) moles of oxygen are required for the combustion is 15.8, the balanced chemical equation is N₂(g) + O₂(g) → 2NO(g), D) a)552 g NO₂ will be formed when NO reacts, b) NO reacts with 384 g O₂, c)360 g NO are required to react with 384 g O₂.

Here are the mole ratios for the balanced chemical equation below:

2Ca + O₂ → 2CaO

A) The mole ratio between Ca and O₂ is 2:1 since 2 moles of Ca were needed to produce 1 mole of O₂. The mole ratio between Ca and CaO is 2:2 since 2 moles of Ca were needed to produce 2 moles of CaO. The mole ratio between O₂ and CaO is 1:2 since 1 mole of O₂ was needed to produce 2 moles of CaO.

B)The balanced equation for the reaction between hydrogen and oxygen to produce water is:

2H2 + O₂ → 2H₂O

From this equation, we can see that 2 moles of hydrogen react with 1 mole of oxygen to produce 2 moles of water. Therefore, to produce 5.0 mol of water, we would need:

5.0 mol H₂O × (2 mol H₂ / 2 mol H₂O)

= 5.0 mol H₂

So we would need 5.0 moles of hydrogen to produce 5.0 moles of water.

C) The balanced equation for the combustion of ethane is:

2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O

According to this equation, 7 molecules of oxygen are required for the complete combustion of 2 molecules of ethane1. Therefore, we can calculate how many moles of oxygen are required for the combustion of 4.50 mol of ethane as follows:

(7 mol O₂ / 2 mol C₂H₆) x (4.50 mol C₂H₆) = 15.8 mol O₂

Therefore, 15.8 moles of oxygen are required for the combustion of 4.50 mol of ethane.

D) a) The balanced equation for this reaction is:

N₂(g) + O₂(g) → 2NO(g)

b) To find out how much NO₂ is formed when NO reacts with 384 g O₂, we first need to find out how many moles of O₂ are present in that amount. We can use the molar mass of O₂ (32 g/mol) to convert grams to moles:

384 g O₂ × (1 mol / 32 g) = 12 mol O₂

From the balanced chemical equation above, we know that one mole of NO reacts with one mole of O₂ to form one mole of NO₂. Therefore, if we have 12 molO₂ present, then we will also form 12 mol NO₂.

To find out how much mass that corresponds to, we can use the molar mass of NO₂ (46 g/mol):

12 mol NO₂ × (46 g / mol) = 552 g NO₂

Therefore, 552 g NO₂ will be formed when NO reacts with 384 g O₂.

c) To find out how many grams of NO are required to react with this amount of O₂, we first need to find out how many moles of NO are required. From the balanced equation above, we know that one mole of NO reacts with one mole of O₂.

Since we have 12 mol O₂ present (as calculated in part b), then we will also need 12 mol NO.

To convert from moles to grams, we can use the molar mass of NO (30 g/mol):

12 mol NO × (30 g / mol) = 360 g NO

Therefore, 360 g NO are required to react with 384 g O₂.

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The principle of option D. Uniformitarianism states that the physical, chemical, and biological processes at work shaping the Earth today have also operated in the

Option D. Uniformitarianism is the principle stating that the physical, chemical, and biological processes at work shaping the Earth today have also operated in the geologic past. It is based on the idea that the present is the key to the past. In other words, the same natural laws that operate in the universe today have been operating since the beginning of time.

James Hutton was the first to propose this principle in the late 18th century. He suggested that the Earth was shaped by slow-acting geological forces such as erosion, sedimentation, and uplift over long periods of time. He believed that the same processes were still happening today and that they had operated in the past.

This principle is an important concept in geology because it allows scientists to interpret the Earth's history based on the processes that they observe today. By understanding how these processes work and how they have changed over time, scientists can reconstruct the history of the Earth and its environments.

Uniformitarianism has been tested and proven through many observations and experiments. For example, the study of sedimentary rocks has shown that they were formed in the past through the same processes that are observed today, such as deposition of sediment by water, wind, or ice.

Similarly, the study of volcanoes has shown that they are formed by the same processes as today, such as the movement of magma from deep within the Earth.

In conclusion, Uniformitarianism is the principle that allows us to interpret the Earth's history by observing the processes that shape it today. It is a fundamental concept in geology and has been tested and proven through many observations and experiments.

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Answer:

78° C.

Explanation:

The final temperature of water is 81℃ , if it is allowed to cool from a temperature of 95  and  it releases heat of 1200J.

In the following question we will apply specific heat Capacity equation

q=mct Δt

q= 1200J   m= 20 g c= 4.186  T₁= 95 ℃

1200= 20 ✕4.186(95-T₂)

T₂=81℃

Hence, The water cools to 81℃ temperature

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The 1H NMR signal for an OH or NH proton usually does not exhibit spin-spin splitting because these protons exchange rapidly with other protons in solution.

This exchange leads to broadening of the NMR signal, making it difficult to observe spin-spin splitting. However, if the exchange rate is slowed down, spin-spin splitting may be observed.

                            Additionally, if the OH or NH proton is part of a larger molecule or functional group, the surrounding atoms and chemical environment can affect the NMR signal and potentially lead to spin-spin splitting.
The statement is true. The 1H NMR signal for an OH or NH proton typically does not exhibit spin-spin splitting due to the rapid exchange of these protons with the surrounding solvent, which effectively averages out the spin-spin interactions. This results in a broad, singlet peak for these types of protons in the NMR spectrum.

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